Search Results

Search found 31657 results on 1267 pages for 'too much php'.

Page 457/1267 | < Previous Page | 453 454 455 456 457 458 459 460 461 462 463 464  | Next Page >

  • Display label character by character using javascript

    - by Muhammad Sajid
    Hi, I am creating Hang a Man using PHP, MySQL & Javascript. Every thing is going perfect, I get a word randomly from DB show it as a label apply it a class where display = none. Now when I click on a Character that character become disable fine which i actually want but the label-character does not show. My code is: <link href="style.css" rel="stylesheet" type="text/css" media="screen" /> <?php include( 'config.php' ); $question = questions(); // Get question. $alpha = alphabats(); // Get alphabets. ?> <script language="javascript"> function clickMe( name ){ var question = '<?php echo $question; ?>'; var questionLen = <?php echo strlen($question); ?>; for ( var i = 0; i < questionLen; i++ ){ if ( question[i] == name ){ var link = document.getElementById( name ); link.style.display = 'none'; var label = document.getElementById( 'questionLabel' + i ); label.style.display = 'block'; } } } </script> <div> <table align="center" style="border:solid 1px"> <tr> <?php for ( $i = 0; $i < 26; $i++ ) { echo "<td><a href='#' id=$alpha[$i] name=$alpha[$i] onclick=clickMe('$alpha[$i]');>". $alpha[$i] ."</a>&nbsp;</td>"; } ?> </tr> </table> <br/> <table align="center" style="border:solid 1px"> <tr> <?php for ( $i = 0; $i < strlen($question); $i++ ) { echo "<td class='question'><label id=questionLabel$i >". $question[$i] ."</label></td>"; } ?> </tr> </table> </div>

    Read the article

  • How can give validation on custom registration form in drupal?

    - by Nitz
    Hey Friends, I have created custom registration form in drupal 6. i have used changed the behavior of the drupal registration page by adding this code in themes. template file function earthen_theme($existing, $type, $theme, $path) { return array( // tell Drupal what template to use for the user register form 'user_register' => array( 'arguments' => array('form' => NULL), 'template' => 'user_register', // this is the name of the template ), ); } and my user_register.tpl.php file is looking like this... //php tag starts from here $forms['access'] = array( '#type' = 'fieldset', '#title' = t('Access log settings'), ); $form['my_text_field']=array( '#type' = 'textfield', '#default_value' = $node-title, '#size' = 30, '#maxlength' = 50, '#required' = TRUE ); <div id="registration_form"><br> <div class="field"> <?php print drupal_render($form['my_text_field']); // prints the username field ?> </div> <div class="field"> <?php print drupal_render($form['account']['name']); // prints the username field ?> </div> <div class="field"> <?php print drupal_render($form['account']['pass']); // print the password field ?> </div> <div class="field"> <?php print drupal_render($form['account']['email']); // print the password field ?> </div> <div class="field"> <?php print drupal_render($form['submit']); // print the submit button ?> </div> </div> How to make validation on "my_text_field" which is custmized. and exactly i want that as soon as user click on my_text_field then datetime picker should be open and whichever date user select, that date should be value in my_text_field. so guys help. Thanks in advance, nitish Panchjanya Corporation

    Read the article

  • jQuery TypeError: example("input#autocomplete").autocomplete is not a function

    - by Ankush Kalia
    I have tried alot to remove this error but could not get success.When i am running this script on localhost its working fine but not working on Joomla frame work. The code is below: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <?php $viewFields=array('c++', 'java', 'php', 'coldfusion', 'javascript', 'asp', 'ruby'); ?> <link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5/jquery.min.js"></script> <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script> <script> var example=jQuery.noConflict(); var arrayFromPHP = <?php echo json_encode($viewFields) ?>; example(document).ready(function() { example("input#autocomplete").autocomplete({ source: arrayFromPHP }); }); </script> </head> <body> <center> <p><img src="<?php echo JURI::base(); ?>images/search_1.png" border="0" alt="" /> <img src="<?php echo JURI::base(); ?>images/business_2.png" border="0" alt="" /> <img src="<?php echo JURI::base(); ?>images/review_3.png" border="0" alt="" /> </p> </center> <input id="autocomplete" /> </body> </html> Its giving me this error:- -- [08:30:24.870] Use of getAttributeNode() is deprecated. Use getAttribute() instead. @ http://50.116.97.120/~amarhost/storage/media/system/js/mootools-core.js:343 [08:30:27.853] TypeError: example("input#autocomplete").autocomplete is not a function @ http://50.116.97.120/~amarhost/storage/index.php/component/storage/?action=war&Itemid=105:210

    Read the article

  • Display lable character by character using javascript

    - by Muhammad Sajid
    Hi, I am creating Hang a Man using PHP, MySQL & Javascript. Every thing is going perfect, I get a word randomly from DB show it as a label apply it a class where display = none. Now when I click on a Character that character become disable fine which i actually want but the label-character does not show. My code is: <link href="style.css" rel="stylesheet" type="text/css" media="screen" /> <?php include( 'config.php' ); $question = questions(); // Get question. $alpha = alphabats(); // Get alphabets. ?> <script language="javascript"> function clickMe( name ){ var question = '<?php echo $question; ?>'; var questionLen = <?php echo strlen($question); ?>; for ( var i = 0; i < questionLen; i++ ){ if ( question[i] == name ){ var link = document.getElementById( name ); link.style.display = 'none'; var label = document.getElementById( 'questionLabel' + i ); label.style.display = 'none'; } } } </script> <div> <table align="center" style="border:solid 1px"> <tr> <?php for ( $i = 0; $i < 26; $i++ ) { echo "<td><a href='#' id=$alpha[$i] name=$alpha[$i] onclick=clickMe('$alpha[$i]');>". $alpha[$i] ."</a>&nbsp;</td>"; } ?> </tr> </table> <br/> <table align="center" style="border:solid 1px"> <tr> <?php for ( $i = 0; $i < strlen($question); $i++ ) { echo "<td class='question'><label id=questionLabel$i >". $question[$i] ."</label></td>"; } ?> </tr> </table> </div>

    Read the article

  • Symfony : ajax call cause server to queue next queries

    - by Remiz
    Hello, I've a problem with my application when an ajax call on the server takes too much time : it queue all the others queries from the user until it's done server side (I realized that canceling the call client side has no effect and the user still have to wait). Here is my test case : <script type="text/javascript" src="jquery-1.4.1.min.js"></script> <a href="another-page.php">Go to another page on the same server</a> <script type="text/javascript"> url = 'http://localserver/some-very-long-complex-query'; $.get(url); </script> So when the get is fired and then after I click on the link, the server finish serving the first call before bringing me to the other page. My problem is that I want to avoid this behavior. I'm on a LAMP server and I'm looking in a way to inform the server that the user aborted the query with function like connection_aborted(), do you think that's the way to go ? Also, I know that the longest part of this PHP script is a MySQL query, so even if I know that connection_aborted() can detect that the user cancel the call, I still need to check this during the MySQL query... I'm not really sure that PHP can handle this kind of "event". So if you have any better idea, I can't wait to hear it. Thank you. Update : After further investigation, I found that the problem happen only with the Symfony framework (that I omitted to precise, my bad). It seems that an Ajax call lock any other future call. It maybe related to the controller or the routing system, I'm looking into it. Also for those interested by the problem here is my new test case : -new project with Symfony 1.4.3, default configuration, I just created an app and a default module. -jquery 1.4 for the ajax query. Here is my actions.class.php (in my unique module) : class defaultActions extends sfActions { public function executeIndex(sfWebRequest $request) { //Do nothing } public function executeNewpage() { //Do also nothing } public function executeWaitingaction(){ // Wait sleep(30); return false; } } Here is my indexSuccess.php template file : <script type="text/javascript" src="jquery-1.4.1.min.js"></script> <a href="<?php echo url_for('default/newpage');?>">Go to another symfony action</a> <script type="text/javascript"> url = '<?php echo url_for('default/waitingaction');?>'; $.get(url); </script> For the new page template, it's not very relevant... But with this, I'm able to reproduce the lock problem I've on my real application. Is somebody else having the same issue ? Thanks.

    Read the article

  • Matching array elements to get an array element at another index

    - by bccarlso
    I have a PHP array that I'm using to generate an HTML form. The PHP array is this: <?php $vdb = array ( array( "Alabama", 275), array( "Alaska", 197), array( "Arizona", 3322)); ?> The PHP to generate the HTML form is below. I need to have the value be the name of the state, because there is some AJAX I'm using to display which states a user has chosen. <?php echo "<table border='1'><thead><tr><th></th><th>State</th><th>Contacts</th><th>Email</th></tr></thead>"; for ($row = 0; $row < 42; $row++) { echo "<tr><td class='input_button'><input type='checkbox' name='vdb[]' value='".$vdb[$row][0]."' title='".$vdb[$row][1]."' /></td>"; echo "<td>".$vdb[$row][0]."</td>"; echo "<td>".$vdb[$row][1]."</td>"; } echo "</table>"; ?> What I'm trying to do is, on submission of the form, with the states the user selected, loop through the PHP array and total the numbers from the selected states. So if I checked Alabama and Alaska, I'd want to add 275 + 197. This is what I thought would have worked, but it's not: <?php $vendors = array(); if (isset($_POST["vdb"])) { $vendors = $_POST["vdb"]; } $ven_i = 0; $ven_j = 0; $ven_total = 0; foreach ($vendors as $value) { foreach ($vdb as $vdb_value) { if ($vendors[$ven_i] == $vdb[$ven_j][0]) { $ven_total += $vdb[$ven_j][1]; } $ven_j++; } $ven_i++; } ?> and then $ven_total should be the total I'm looking for. However, $ven_total just ends up being the first checkbox selected, and it ignores the rest. I am doing this correctly with the AJAX, displaying the total on the front end, but I don't know how to pass that on to the form submission. I'd rather not using GET and URL variables, because a user could type something into the URL and modify the count. Any idea what I'm doing wrong, or a better way to approach this that I would be able to understand? (Very much a novice programmer.)

    Read the article

  • Contact form problem - I do receive messages, but no contents (blank page).

    - by nitbuntu
    I have a contact form on site which used to work, but since last few months has stopped working properly. This could have been due to some coding error that I can't figure out. What happens is that I receive the messages sent, but they are completely blank, with no contents at all. What could be the problems? I'm attaching first the front-end page, and then the back-end. Sample of contact.php the front-end code:- <div id="content"> <h2 class="newitemsxl">Contact Us</h2> <div id="contactcontent"> <form method="post" action="contactus.php"> Name:<br /> <input type="text" name="Name" /><br /> Email:<br /> <input type="text" name="replyemail" /><br /> Your message:<br /> <textarea name="comments" cols="40" rows="4"></textarea><br /><br /> <?php require("ClassMathGuard.php"); MathGuard::insertQuestion(); ?><br /> <input type="submit" name="submit" value="Send" /> * Refresh browser for a different question. :-) </form> </div> </div> Sample of contactus.php (backend code):- <?php /* first we need to require our MathGuard class */ require ("ClassMathGuard.php"); /* this condition checks the user input. Don't change the condition, just the body within the curly braces */ if (MathGuard :: checkResult($_REQUEST['mathguard_answer'], $_REQUEST['mathguard_code'])) { $mailto="[email protected]"; $pcount=0; $gcount=0; $subject = "A Stylish Goods Enquiry"; $from="[email protected]"; echo ("Great, you're message has been sent !"); //insert your code that will be executed when user enters the correct answer } else { echo ("Sorry, wrong answer, please go back and try again !"); //insert your code which tells the user he is spamming your website } while (list($key,$val)=each($HTTP_POST_VARS)) { $pstr = $pstr."$key : $val \n "; ++$pcount; } while (list($key,$val)=each($HTTP_GET_VARS)) { $gstr = $gstr."$key : $val \n "; ++$gcount; } if ($pcount > $gcount) { $comments=$pstr; mail($mailto,$subject,$comments,"From:".$from); } else { $comments=$gstr; mail($mailto,$subject,$comments,"From:".$from); } ?>

    Read the article

  • Codeigniter not returning me to upload form after image upload.

    - by Drew
    I'm still very new to codeigniter. The issue i'm having is that the file uploads fine and it writes to the database without issue but it just doesn't return me to the upload form. Instead it stays in the do_upload and doesn't display anything. Even more bizarrely there is some source code behind the scenes. Can someone tell my what it is i'm doing wrong because I want to be returning to my upload form after submission. Thanks in advance. Below is my code: Controller: function do_upload() { if($this->Upload_model->do_upload()) { $this->load->view('home/upload_form'); }else{ $this->load->view('home/upload_success', $error); } } Model: function do_upload() { $config['upload_path'] = './uploads/'; $config['allowed_types'] = 'gif|jpg|png'; $config['max_size'] = '2000'; $this->load->library('upload', $config); if ( ! $this->upload->do_upload()) { $error = array('error' => $this->upload->display_errors()); return $error; } else { $data = $this->upload->data(); $full_path = 'uploads/' . $data['file_name']; $spam = array( 'image_url' => $full_path, 'url' => $this->input->post('url') ); $id = $this->input->post('id'); $this->db->where('id', $id); $this->db->update('NavItemData', $spam); return true; } } View (called upload_form): <html> <head> <title>Upload Form</title> </head> <body> <?php if(isset($buttons)) : foreach($buttons as $row) : ?> <h2><?php echo $row->image_url; ?></h2> <p><?php echo $row->url; ?></p> <p><?php echo $row->name; ?></p> <p><?php echo anchor("upload/update_nav/$row->id", 'edit'); ?></p> <?php endforeach; ?> <?php endif; ?> </body> </html>

    Read the article

  • How do I add a filter button to this pagination?

    - by ClarkSKent
    Hey, I want to add a button(link), that when clicked will filter the pagination results. I'm new to php (and programming in general) and would like to add a button like 'Automotive' and when clicked it updates the 2 mysql queries in my pagination script, seen here: As you can see, the category automotive is hardcoded in, I want it to be dynamic, so when a link is clicked it places whatever the id or class is in the category part of the query. 1: $record_count = mysql_num_rows(mysql_query("SELECT * FROM explore WHERE category='automotive'")); 2: $get = mysql_query("SELECT * FROM explore WHERE category='automotive' LIMIT $start, $per_page"); This is the entire current php pagination script that I am using: <?php //connecting to the database $error = "Could not connect to the database"; mysql_connect('localhost','root','root') or die($error); mysql_select_db('ajax_demo') or die($error); //max displayed per page $per_page = 2; //get start variable $start = $_GET['start']; //count records $record_count = mysql_num_rows(mysql_query("SELECT * FROM explore WHERE category='automotive'")); //count max pages $max_pages = $record_count / $per_page; //may come out as decimal if (!$start) $start = 0; //display data $get = mysql_query("SELECT * FROM explore WHERE category='automotive' LIMIT $start, $per_page"); while ($row = mysql_fetch_assoc($get)) { // get data $name = $row['id']; $age = $row['site_name']; echo $name." (".$age.")<br />"; } //setup prev and next variables $prev = $start - $per_page; $next = $start + $per_page; //show prev button if (!($start<=0)) echo "<a href='pagi_test.php?start=$prev'>Prev</a> "; //show page numbers //set variable for first page $i=1; for ($x=0;$x<$record_count;$x=$x+$per_page) { if ($start!=$x) echo " <a href='pagi_test.php?start=$x'>$i</a> "; else echo " <a href='pagi_test.php?start=$x'><b>$i</b></a> "; $i++; } //show next button if (!($start>=$record_count-$per_page)) echo " <a href='pagi_test.php?start=$next'>Next</a>"; ?>

    Read the article

  • Problems with MYSQL database

    - by shinjuo
    I have a database that worked fine until I decided to add a log onto the page. here is what I have now: <body> <?php if($_SERVER['REQUEST_METHOD'] == 'POST') { require("serverInfo.php"); mysql_query("UPDATE `cardLists` SET `AmountLeft` = `AmountLeft` + ".mysql_real_escape_string($_POST['Add'])." WHERE `cardID` = '".mysql_real_escape_string($_POST['Cards'])."'"); echo "\"" .$_POST['Add'] ."\" has been added to the inventory amount for the card \"". $_POST['Cards']. "\""; mysql_query("INSERT INTO `log` (`changes`, `amount`, `cardID`, `person`, Date)VALUES('ADDED','$_POST['Add']','$_POST['Cards']', '$_POST['Person']', NOW())"); mysql_close($link); } ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <?php require("serverInfo.php"); ?> <?php $res = mysql_query("SELECT * FROM cardLists order by cardID") or die(mysql_error()); echo "<select name = 'Cards'>"; while($row=mysql_fetch_assoc($res)) { echo "<option value=\"$row[cardID]\">$row[cardID]</option>"; } echo "</select>"; ?> Amount to Add: <input type="text" name="Add" maxlength="8" /> Changes Made By: <select name="Person"> <option value="justin">Justin</option> <option value="chris">Chris</option> <option value="matt">Matt</option> <option value="dan">Dan</option> <option value="tim">Tim</option> <option value="amanda">Amanda</option> </select> <input type="submit" name ="submit" onClick= "return confirm( 'Are you sure you want to add this amount?');"> </form> <br /> <input type="button" name="main" value="Return To Main" onclick="window.location.href='index.php';" /> </body> </html> it works fine until I added the: mysql_query("INSERT INTO `log` (`changes`, `amount`, `cardID`, `person`, Date)VALUES('ADDED','$_POST['Add']','$_POST['Cards']', '$_POST['Person']', NOW())"); mysql_close($link); Can anyone see what is going on?

    Read the article

  • How can I create a Searchstring for a Google AJAX Search API?

    - by elmaso
    Hello, i have this code to get the search resutls from the api: querygoogle.php: <?php session_start(); // Here's the Google AJAX Search API url for curl. It uses Google Search's site:www.yourdomain.com syntax to search in a specific site. I used $_SERVER['HTTP_HOST'] to find my domain automatically. Change $_POST['searchquery'] to your posted search query $url = 'http://ajax.googleapis.com/ajax/services/search/web?rsz=large&v=1.0&start=20&q=' . urlencode('' . $_POST['searchquery']); // use fopen and fread to pull Google's search results $handle = fopen($url, 'rb'); $body = ''; while (!feof($handle)) { $body .= fread($handle, 8192); } fclose($handle); // now $body is the JSON encoded results. We need to decode them. $json = json_decode($body); // now $json is an object of Google's search results and we need to iterate through it. foreach($json->responseData->results as $searchresult) { if($searchresult->GsearchResultClass == 'GwebSearch') { $formattedresults .= ' <div class="searchresult"> <h3><a href="' . $searchresult->unescapedUrl . '">' . $searchresult->titleNoFormatting . '</a></h3> <p class="resultdesc">' . $searchresult->content . '</p> <p class="resulturl">' . $searchresult->visibleUrl . '</p> </div>'; } } $_SESSION['googleresults'] = $formattedresults; header('Location: ' . $_SERVER['HTTP_REFERER']); exit; ?> search.php <?php session_start(); ?> <form method="post" action="querygoogle.php"> <label for="searchquery"><span class="caption">Search this site</span> <input type="text" size="20" maxlength="255" title="Enter your keywords and click the search button" name="searchquery" /></label> <input type="submit" value="Search" /> </form> <?php if(!empty($_SESSION['googleresults'])) { echo $_SESSION['googleresults']; unset($_SESSION['googleresults']); } ?> but with this code, I cant add a searchstring.. how can i add a search string like search.php?search=keyword ? thanks

    Read the article

  • How should I handle the case in which a username is already in use?

    - by idealmachine
    I'm a JavaScript programmer and new to PHP and MySQL (want to get into server-side coding). Because I'm trying to learn PHP by building a simple online game (more specifically, correspondence chess), I'm starting by implementing a simple user accounts system. Of course, user registration comes first. What are the best practices for: How I should handle the (likely) possibility that when a user tries to register, the username he has chosen is already in use, particularly when it comes to function return values?($result === true is rather ugly, and I'm not sure whether checking the MySQL error code is the best way to do it either) How to cleanly handle varying page titles?($gPageTitle = '...'; require_once 'bgsheader.php'; is also rather ugly) Anything else I'm doing wrong? In some ways, PHP is rather different from JavaScript... Here is a (rather large) excerpt of the code I have written so far. Note that this is a work in progress and is missing security checks that I will add as my next step. function addUser( $username, $password ) { global $gDB, $gPasswordSalt; $stmt = $gDB->prepare( 'INSERT INTO user(user_name, user_password, user_registration) VALUES(?, ?, NOW())' ); $stmt || trigger_error( 'Failed to prepare statement: ' . htmlspecialchars( $gDB->error ) ); $hashedPassword = hash_hmac( 'sha256', $password, $gPasswordSalt, true ); $stmt->bind_param( 'ss', $username, $hashedPassword ); if( $stmt->execute() ) { return true; } elseif( $stmt->errno == 1062) { return 'exists'; } else { trigger_error( 'Failed to execute statement: ' . htmlspecialchars( $stmt->error ) ); } } $username = $_REQUEST['username']; $password = $_REQUEST['password']; $result = addUser( $username, $password ); if( $result === true ) { $gPageTitle = 'Registration successful'; require_once 'bgsheader.php'; echo '<p>You have successfully registered as ' . htmlspecialchars( $username ) . ' on this site.</p>'; } elseif( $result == 'exists' ) { $gPageTitle = 'Username already taken'; require_once 'bgsheader.php'; echo '<p>Someone is already using the username you have chosen. Please try using another one instead.'; } else { trigger_error('This should never happen'); } require_once 'bgsfooter.php';

    Read the article

  • CodeIgniter Error Log Info + Errors

    - by fatnjazzy
    Hi, IS there a way to save in the log, Info + Errors without debug? Howcome debug level apears with info? If i want to log info "Account id 4345 was deleted by Admin", why do i need to see all of these: DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Config Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Hooks Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 URI Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Router Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Output Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Input Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Global POST and COOKIE data sanitized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Language Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Loader Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Config file loaded: config/safe_charge.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Config file loaded: config/web_fx.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Helper loaded: loadutils_helper DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Helper loaded: objectsutils_helper DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Helper loaded: logutils_helper DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Helper loaded: password_helper DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Database Driver Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 cURL Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Language Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Config Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Account MX_Controller Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 File loaded: ./modules/accounts/models/pending_account_model.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Model Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 File loaded: ./modules/accounts/models/proccess_accounts_model.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Model Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 File loaded: ./modules/accounts/models/web_fx_model.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Model Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 File loaded: ./modules/accounts/models/trader_account_type_spreads.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Model Class Initialized DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 File loaded: ./modules/accounts/models/trader_accounts.php DEBUG - 2010-12-27 08:39:13 --> 192.168.200.32 Model Class Initialized Thanks

    Read the article

  • Linking Post Title to Specific Page ID

    - by ThatMacLad
    I've created a form to update my websites homepage with content but I wanted to know how I could set it up so that a posts title links to a specific post ID. I'd also like to add a Read More link that directs anybody reading the blog to the correct post. Here is my PHP code: <html> <head> <title>Blog Name</title> </head> <body> <?php mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "SELECT * FROM php_blog ORDER BY timestamp DESC LIMIT 5"; $result = mysql_query($sql) or print ("Can't select entries from table php_blog.<br />" . $sql . "<br />" . mysql_error()); while($row = mysql_fetch_array($result)) { $date = date("l F d Y", $row['timestamp']); $title = stripslashes($row['title']); $entry = stripslashes($row['entry']); $password = $row['password']; $id = $row['id']; if ($password == 1) { echo "<p><strong>" . $title . "</strong></p>"; printf("<p>This is a password protected entry. If you have a password, log in below.</p>"); printf("<form method=\"post\" action=\"post.php?id=%s\"><p><strong><label for=\"username\">Username:</label></strong><br /><input type=\"text\" name=\"username\" id=\"username\" /></p><p><strong><label for=\"pass\">Password:</label></strong><br /><input type=\"password\" name=\"pass\" id=\"pass\" /></p><p><input type=\"submit\" name=\"submit\" id=\"submit\" value=\"submit\" /></p></form>",$id); print "<hr />"; } else { ?> <p><strong><?php echo $title; ?></strong><br /><br /> <?php echo $entry; ?><br /><br /> Posted on <?php echo $date; ?> <hr /></p> <?php } } ?> </body> </html> Thanks for any help. I really appreciate any input!

    Read the article

  • highlight search keywords on hover

    - by fusion
    i've a basic php search form which highlights the keywords using css. i was wondering if i could make the keywords in the results highlight only when the user hovers over the record. is this possible? this is the highlight code: function highlightWords($text, $words) { preg_match_all('~\w+~', $words, $m); if(!$m) return $text; $re = '~\\b(' . implode('|', $m[0]) . ')~i'; $string = preg_replace($re, '<span class="highlight">$0</span>', $text); return $string; } . . . <table class="result"> <?php while ($row= mysql_fetch_array($result, MYSQL_ASSOC)) { $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); ?> <tr> <td style="text-align:right; font-size:15px;"><?php h($row['cArabic']); ?></td> <td style="font-size:16px;"><?php echo $cQuote; ?></td> <td style="font-size:12px;"><?php h($row['vAuthor']); ?></td> <td style="font-size:12px; font-style:italic; text-align:right;"><?php h($row['vReference']); ?></td> </tr> <?php } ?> </table> css: table.result tr:hover { background:#F7F7F7; } .highlight { font-weight:bold; color: #DE2842; padding:5px; padding-right:2px; background: #FFFCDB; } i tried changing the color through highlight:hover, but this changed the color of the search keyword only when i hovered over the keyword itself, which is understandable since that's the way it is supposed to work, but i'd like the search keywords to be highlighted when i hover over the result as a whole.

    Read the article

  • Multiple Forms with Different Actions using Submit Buttons

    - by Adam Coulson
    I have Two forms in my index.php and am trying to get them to submit and POST their data seperatly Form 1 echo '<form action="process.php?type=news" method="post">'; echo '<table cellspacing="0"><tr><th>'; echo 'Add News to News Feed'; echo '</th></tr><tr><td>'; echo 'Title:<br /><input name="newstitle" type="text" id="add" style="height:16px;width:525px;" size="80" maxlength="186" /><br />'; echo 'Main Body Text:<br /><textarea name="newsfeed" id="add" style="width:525px;height:78px;" maxlength="2000" ></textarea>'; echo '<input style="float:right;margin-top:5px;" id="button" type="submit" value="Submit" />'; echo '</td></tr></table></from>'; And Form 2 echo '<form action="process.php?type=suggest" method="post">'; echo '<table cellspacing="0"><tr><th>'; echo 'Suggest Additions to the Intranet'; echo '</th></tr><tr><td>'; echo '<textarea name="suggest" id="add" style="width:330px;height:60px;" maxlength="800" ></textarea>'; echo '<input style="float:right;margin-top:5px;" id="button" type="submit" value="Submit" />'; echo '</td></tr></table></from>'; I want these both to post and do the action after pressing the submit button, but currently the second form submit to the first forms action How can i fix this??? EDIT: Also i am using .PHP for both the index and process page then using it to echo the forms onto the page Also here is the process.php data $type=$_REQUEST['type']; $suggest=$_POST['suggest']; $newstitle=$_POST['newstitle']; $news=mysql_real_escape_string($_POST['newsfeed']); if ($type == "news") { $sql=mysql_query("SELECT * FROM newsfeed WHERE title = ('$newstitle')"); $number_of_rows = mysql_num_rows($sql); if ($number_of_rows > 0) { echo 'This Title is Already Taken'; } else { $sql="INSERT INTO newsfeed (title, news) VALUES ('$newstitle','$news')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } header('Location: index.php'); exit; } } elseif ($type == "suggest") { $sql="INSERT INTO suggestions VALUES ('$suggest')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } header('Location: index.php'); exit; }

    Read the article

  • Codeigniter: Retrieving data on button click with Ajax

    - by OllyTenerife
    I have a simple webpage which generates a random quote from my database upon refreshing the page. I wish to implement some AJAX and JQuery in order to generate quotes via the button rather than having to refresh the page. I have done some research but I am not sure how to implement this in Codeigniter. My current code is below... Page controller: public function index() { $this->load->model('quote_model', '', TRUE); $data['quotes'] = $this->quote_model->getRandom(); $this->load->view('home', $data); } The view: <?php include ('layout/header.php'); ?> <div class="container-fluid"> <div class="row"> <div class="col-md-4 quote-holder"> <img src="application/assets/alan1.jpg" alt="..." class="img-circle img-responsive"> <br> <blockquote class="text-center"> <p><?php echo $quotes[0]['quote']; ?></p> <footer class="text-center"><?php echo $quotes[0]['character_name']; ?> in <cite title="Source Title"><?php echo $quotes[0]['series_name']; ?></cite></footer> </blockquote> <button type="button" class="btn btn-default center-block">Generate quote</button> </div> </div> <?php include ('layout/footer.php'); ?> Here is the function in the model I am retrieving the data from: function getRandom() { $query = $this->db->query(" SELECT * FROM quotes, characters, series WHERE quotes.series_id = series.series_id AND quotes.character_id = characters.character_id ORDER BY rand() LIMIT 1 "); return $query->result_array(); } Should I simply be using something like this? $("button").click(function(){ $.get( "Page/index", function( data ) { //output data to page element... } });

    Read the article

  • Apache ErrorDocument not working for PHP 500 error

    - by Jason
    I have a number of ErrorDocuments setup in my .htaccess file for errors such as 404, 401, 403 etc which all redirect to my error page but the ErrorDocument set for a 500 error is never displayed when PHP reports a 500. The 500 code is sent to the browser and the output is blank. Is there something special I need to do to enable 500 error documents for use with PHP? My directives look like this: ErrorDocument 401 /errorpage.php?error=401 ErrorDocument 403 /errorpage.php?error=403 ErrorDocument 404 /errorpage.php?error=404 ErrorDocument 500 /errorpage.php?error=500 I've looked through the php.ini and can't see anything that would obviously override the Apache settings and there are no ErrorDocument directives in my httpd.conf either. Anywhere else I should be looking? Thanks in advance.

    Read the article

  • RewriteRule and php download counter

    - by rcourtna
    (1) I have a site that serves up MP3 files: http://domain/files/1234567890.mp3 (2) I have a php script that tracks file download counts: http://domain/modules/download_counter.php?file=/files/1234567890.mp3 After download_counter.php records the download, it redirects to the original file: Header("Location: $FQDN_url"); (3) I'd like all my public links to be presented as the direct file urls from (1). I'm trying to use Apache to redirect the requests to download_counter.php: RewriteRule ^files/(.+\.mp3)$ /modules/download_counter.php?file=/files/$1 [L] I'm currently stuck on (3), as it results in a redirect loop, since download_counter.php simply redirects the request back to the original file (rather than streaming the file contents). I'm also motivated to use download_counter.php as is (without modifying it's redirect behaviour). This is because the script is part of a larger CMS module, and I'd like to avoid complicating my upgrade path. Perhaps there is no solution to my problem (other than modifying the download_counter script). WDYT?

    Read the article

  • Sending a variable from a processing page back to the original PHP page

    - by user1228907
    So on a PHP page (page 1) I have some HTML, including : <form action="create_subject.php" method="post" > Which goes to a processing page (page 2) containing MySQL which will be executed if there aren't any errors. If there are (checked by validation on the processing page (page 2)) or aren't, certain variables are set, including this one for if it's successful : if (mysql_affected_rows() == 1){ $success = 1; redirect_to("new_subject.php"); } However, how would I include $success into the URL without putting it in as : redirect_to("new_subject.php?success=1"); I can't do this as I need to do if statements, and it's only PHP on "page 2" so I can't do an if statement inside redirect_to("new_subject.php"); I know I could do ... } else { redirect_to("new_subject.php?success=1"); } But this would seem mundane and non-semantic especially as I have several variables to proccess.

    Read the article

  • IIS7.5 + Wordpress + Restrict Access to wp-login.php by client IP address

    - by JuanValdez
    I am moving from an Apache host to IIS. One of my sites in Wordpress (running Multi-site) which give me multiple blogs. I have moved all my rules from my .htaccess to the Microsoft URL ReWrite module. I have one section left that will not import. I want to restrict access to all instances of the file wp-login.php by Client IP address. In my .htaccess file I did the following: <Files wp-login.php> Order Deny,Allow Deny from all Allow from 192.168 </Files> Any smart ideas on how to accompish this in IIS7.5?

    Read the article

  • Configure clean URLs using Laravel using a rewrite rule to index.php

    - by yannis hristofakis
    Recently I've started learning Laravel , I have none experience with framework before. I'm encountering the following problem .I'm trying to configure the .htaccess file so I can have clean URLs but the only thing I get are 404 Not Found error pages. I have created a virtual host - you can see below the configuration file - and changed the .htaccesss file on the public directory. /etc/apache2/sites-available <VirtualHost *:80> ServerAdmin [email protected] ServerName laravel.lar DocumentRoot "/home/giannis/Desktop/laravel/public" <Directory "/home/giannis/Desktop/laravel/public"> Options Indexes FollowSymLinks MultiViews AllowOverride All </Directory> <Directory /var/www/> Options Indexes FollowSymLinks MultiViews AllowOverride None Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/ <Directory "/usr/lib/cgi-bin"> AllowOverride None Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch Order allow,deny Allow from all </Directory> ErrorLog ${APACHE_LOG_DIR}/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog ${APACHE_LOG_DIR}/access.log combined Alias /doc/ "/usr/share/doc/" <Directory "/usr/share/doc/"> Options Indexes MultiViews FollowSymLinks AllowOverride None Order deny,allow Deny from all Allow from 127.0.0.0/255.0.0.0 ::1/128 </Directory> </VirtualHost> .htaccesss file: laravel/public # Apache configuration file # http://httpd.apache.org/docs/current/mod/quickreference.html # Note: ".htaccess" files are an overhead for each request. This logic should # be placed in your Apache config whenever possible. # http://httpd.apache.org/docs/current/howto/htaccess.html # Turning on the rewrite engine is necessary for the following rules and # features. "+FollowSymLinks" must be enabled for this to work symbolically. <IfModule mod_rewrite.c> Options +FollowSymLinks RewriteEngine On </IfModule> # For all files not found in the file system, reroute the request to the # "index.php" front controller, keeping the query string intact <IfModule mod_rewrite.c> RewriteEngine On RewriteBase / RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ index.php?/$1 [L] </IfModule> In order to test it, I have created a view named about and made the proper routing. If I link to http://laravel.lar/index.php/about/ I'm routing to the about page instead if I link to http://laravel.lar/about/ I get a 404 Not Found error. I'm using a Debian based system.

    Read the article

< Previous Page | 453 454 455 456 457 458 459 460 461 462 463 464  | Next Page >