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• How do I make a view that groups nodes by taxonomy term?

  - by Andrew Weir

  Hello, I'm trying to bend views and drupal to my will. So far I've produced a view to display the titles of my nodes. Each node will be assigned exactly one taxonomy term from the set {X, Y and Z}. So for example, Node A has a title "Car drives into field, thousands don't care". Node A has a taxonomy term "Pointless". I'd like to group all the node titles by their taxonomy term. So.. Pointless - Car drives into field, thousands don't care - .... Next Taxonomy Term - ..... - ...... - ... You get the idea. Is it doable and how do I do it? I can't find the group by option in views. cheers SO.

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• Sharing Jinja2 templates between Pylons and Django applications

  - by Joe Holloway

  I'm writing a couple of Jinja2 templates that basically implement some common grid layouts. I'd like to be able to share this 'library' of templates between a Pylons app and Django app. I've hit a minor stumbling block in that Django's template context is accessible from the "top-level" of the template, whereas Pylons wraps your context inside the thread local c (or tmpl_context) variable. Here are some analogous examples that demonstrate this. Django from django.shortcuts import render_to_response ctx = {} ctx['name'] = 'John' return render_to_response('hello.html', ctx) hello.html: Hello {{ name }} Pylons from pylons import tmpl_context as c from myapp.lib.base import render c.name = 'John' return render('hello.html') hello.html: Hello {{ c.name }} What I'm trying to do is make it so that hello.html is the same across both frameworks. One way I see to do it is by wrapping the Django render_to_response and do something like this: ctx['c'] = ctx But that just doesn't feel right. Anybody see other alternatives to this? Thanks

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• How to implement Materialized View with MySQL?

  - by GregJohn

  How to implement Materialized Views? If not, how can I implement Materialized View with MySQL?

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• Nginx and Django on Dotcloud

  - by jmetz

  I currently have a dotcloud app that uses django to serve everything. It works great, however, we recently had our site redone in angular.js, and I don't want to use django to serve the actual html pages (I want to just use nginx for that), but I want django to serve some links for the API we built for the angular code to use. Is it possible for me, in the same app, to configure nginx to serve some static files for particular urls, and have it send other urls for django to serve? I want nginx to serve my index.html page is a request comes in to wwww.example.com, but if a request for example.com/api/login/ comes in, I want that to be handled by django. Is this possible?

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• Different behavior of reflected generic delegates with and without debugger

  - by Andrew_B

  Hello. We have encountered some strange things while calling reflected generic delegates. In some cases with attatched debuger we can make impossible call, while without debugger we cannot catch any exception and application fastfails. Here is the code: using System; using System.Windows.Forms; using System.Reflection; namespace GenericDelegate { public partial class Form1 : Form { public Form1() { InitializeComponent(); } private delegate Class2 Delegate1(); private void button1_Click(object sender, EventArgs e) { MethodInfo mi = typeof (Class1<>).GetMethod("GetClass", BindingFlags.NonPublic | BindingFlags.Static); if (mi != null) { Delegate1 del = (Delegate1) Delegate.CreateDelegate(typeof (Delegate1), mi); MessageBox.Show("1"); try { del(); } catch (Exception) { MessageBox.Show("No, I can`t catch it"); } MessageBox.Show("2"); mi.Invoke(null, new object[] {});//It's Ok, we'll get exception here MessageBox.Show("3"); } } class Class2 { } class Class1<T> : Class2 { internal static Class2 GetClass() { Type type = typeof(T); MessageBox.Show("Type name " + type.FullName +" Type: " + type + " Assembly " + type.Assembly); return new Class1<T>(); } } } } There are two problems: Behavior differs with debugger and without You cannot catch this error without debugger by clr tricks. It's just not the clr exception. There are memory acces vialation, reading zero pointer inside of internal code. Use case: You develop something like plugins system for your app. You read external assembly, find suitable method in some type, and execute it. And we just forgot about that we need to check up is the type generic or not. Under VS (and .net from 2.0 to 4.0) everything works fine. Called function does not uses static context of generic type and type parameters. But without VS application fails with no sound. We even cannot identify call stack attaching debuger. Tested with .net 4.0 The question is why VS catches but runtime do not?

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• Is there a 'hello world' website for django? OR (I've installed django, now what) ?

  - by morpheous

  I'm learning Python and decided to start familiarizing myself with the (defacto?) Python web framework - django. I have successfully installed the latest release of django. I want a simple 'hello world' website that will get me up and running quickly. I am already familiar with web frameworks (albeit for different languages) - so I just need a simple 'hello world' example website to help me get going. Ideally, I don't want to mess up with my Apache server settings (as I am still experimenting), so I want to use the lightweight web server that django bundles. I cant seem to find how to do this on the django website though - no doubt someone will post a link and shame me ... So, does anyone know of a link that shows how to get a simple 'hello world' django website up and running with minimal fuss?

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• How to transition from PHP to Python Django?

  - by ggfan

  Here's my background: Decent experience with PHP/MySql. Beginner's experience with OOP Why I want to learn Python Django? I gave in, based on many searches on SO and reading over some of the answers, Python is a great, clean, and structured language to learn. And with the framework Django, it's easier to write codes that are shorter than with PHP Questions Can i do everything in Django as in PHP? Is Django a "big" hit in web development as PHP? I know Python is a great general-purpose language but I'm focused on web development and would like to know how Django ranks in terms of web development.

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• Check something before django server starts

  - by Vijay Shankar Kalyanaraman

  I am running my api behind a django server and say I have a one time token that is needed by the django application and used through out its existence until the process quits. To check if I can proceed and serve requests (using the django server) I need to validate this token against a database entry. Now, I can have a script that hits the db, then issues the run server command if the token is valid. But if the db used by the django applications change, I will have to change the script also to point to the same db. Is there a way I can pass this token into the runserver command as an additional parameter (along with hostname:port) and validate this before django serves any requests? How can I access this parameter that is sent into ./manage.py runserver. Thanks.

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• Using generic type from other generic parameter

  - by DEHAAS

  Hi, I have a question about .net generics. Consider the following code: public class Test<TKey> { TKey Key { get; set; } } public class Wrapper<TValue, TKey> where TValue : Test<TKey> { public TValue Value { get; set; } } Now, when using this code, I could do something like this: Wrapper<Test<int>, int> wrapper = new Wrapper<Test<int>, int>(); The int type parameter has to be provided twice. Is it possible to modify the Wrapper definition, to require TValue to be a generic type, and use this 'nested' generic type parameter insted of the TKey type parameter?

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• Synchronize the position of two ScrollView views

  - by Billy

  I am trying to synchronize the positions of two ScrollViews. I'm trying to do this to display a tv guide listing. I have created a custom class that extends RelativeLayout to display the guide. This relative layout has four children: an imageview in the top left corner, a HorizontalScrollView to display the column headers in the top right, a ScrollView to display the row headers at the bottom left, and a ScrollView in the bottom right that contains the listings. This ScrollView then contains a HorizontalScrollView, which in turn contains a LinearLayout with multiple child views that display the data. I hope this explains it clearly, but here's a diagram to make it clearer: ____________ |__|___hsv___| | | | | | sv -> | | | hsv -> | |sv| ll -> | | | etc | | | | |__|_________| I set it up like this because I wanted the guide listings to scroll both horizontally and vertically, but there's no scroll view that does this. Also, I want the row and column headers to display no matter what position the guide listings are at, but I want them to be lined up properly. So I'm trying to find a way to synchronize the positions of the two hsv's, and to also synchronize the positions of the two sv's. I'm also trying to do it in a way that avoids just running a handler every few milliseconds to poll one view and call scrollTo on the other. I'm in no way sure that this is the best way to do it, but this is what I've come up with. If anybody has any other suggestions, please feel free!

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• Should onSaveInstanceState save the "enabledness" of the views?

  - by neutrino

  Hi there, I have a preferences activity where I can change the language and the theme of my application. From there I return to the previous activity via the Back key, and I want to recreate the activity. I've managed to do that by reinitializing the layout in onResume and also calling onRestoreInstanceState from there. All the views are restored properly, with checkboxes checked if needed, edittexts filled with texts I left there previously. But I also have a button which is initially disabled, and becomes enabled only when a radiobutton is checked. The problem with it is the following: I check the radiobutton, the button becomes enabled. Then I go to settings, change the theme there, and return to the first activity. When I arrive there, the radiobutton is still checked, but the button is disabled. So it seems that the enabled/disabled state isn't being saved into the bundle, which seems counterintuitive. And I haven't found any code in the Android source that does this, too. Am I missing something, or do I have to write my own code for that?

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• Passing additional data value to strongly typed partial views in ASP.NET MVC

  - by fearofawhackplanet

  I have an OrderForm domain class, which has property subclasses, something like: interface IOrderForm { int OrderId { get; } ICustomerDetails CustomerDetails { get; set; } IDeliveryDetails DeliveryDetails{ get; set; } IPaymentsDetails PaymentsDetails { get; set; } IOrderDetails OrderDetails { get; set; } } My "Details" view is strongly typed inheriting from IOrderForm. I then have a strongly type partial for rendering each section: <div id="CustomerDetails"> <% Html.RenderPartial("CustomerDetails", Model.CustomerDetails); %> </div> <div id="DeliveryDetails"> <% Html.RenderPartial("DeliveryDetails", Model.DeliveryDetails); %> </div> ... etc This works ok up to this point, but I'm trying to add some nice ajax bits for updating some parts of the order form, and I've realised that each of my partial views also needs access to the IOrderForm.OrderId. Whats the easiest way to give my partials access to this value?

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• Defining Views Based On Selection

  - by Wayne

  Well the title isn't very descriptive but I'm not exactly sure how to explain but here goes! I have a web application (can use either MVC or standard web forms) which a user signs in to. If the user has signed up for more than one product they will have the option to switch between them. For the sakes of this example lets say User1 signs in and has access to Product1, Product2 and Product3. Now, each product will be very different and offer different functionally. What I want is the main view to be focused around the product they have selected and not redirected to a sub domain. What I don't want to have to do is get them to go to www.mysite.com/product1 or www.mysite.com/product2 but simply www.mysite.com regardless of the product they have selected and have the site render the views etc for that product. Wow does any of that make any sense? I was thinking mabe the use of sessions or something and URL rewriting? Are there any sample apps out there that make use of the same kind of functionallity that I could take a look at? Thanks for any help I appreciate it!

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• Need access to views on the OnSeekBarChangeListener (which is in an own class)

  - by sandkasten

  first of all I hope you understand my english because I'am not a native speaker. Okay, I'am new to android development and try following: For my app I need a SeekBar, so I create a Seekbar via XML and implement an OnSeekBarChangeListener. In the compay I work for its forbidden (because of the styleguid) to create something like this: seekbar.setOnSeekBarChangeListener(new OnSeekBarChangeListener() { @Override public void onProgressChanged(SeekBar arg0, int arg1, boolean arg2) { /// Do something } ... }); So I need to create a own class for the OnSeekBarChangeListener. So far no problem. public class SeekBarChangeListener extends SeekBar implements SeekBar.OnSeekBarChangeListener { public SeekBarChangeListener(Context context) { super(context); } public void onProgressChanged(SeekBar seekBar, int progress, boolean fromUser) { } public void onStartTrackingTouch(SeekBar seekBar) { } public void onStopTrackingTouch(SeekBar seekBar) { /// Do something. Following Code wont work CheckBox RemeberUsername = (CheckBox)findViewById(R.id.RemeberUsername); /// Always gets NULL } } I need a way to get access to some controls. Normaly the findViewById works fine but not in this case (what I can totaly understand, because how should the listender know about the views?). Some good hints? Or is there no oter way like the first code snippet to get the controls? Hope someone can help me out.

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• Can I use Visual studio for Python and Django development?

  - by Pankaj Upadhyay

  I have been using Visual Studio for quite some time now, in fact from the VS 2005 version. Right now, I am not only comfortable but addict to using it(VS 2010) for all my development needs. Recently I have been learning Python and Django. In that getting the tutorial tasks up and running with IDLE seems very lame and outdated(I am following the Django Book). Therefore, I downloaded and configured Eclipse & PyDev. Eclipse seems good and fine but needs a bit of learning curve for itself. So, I am looking for a way to configure Visual Studio 2010 for Python and Django development if possible. Please tell me if that's possible and How ?

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• Reversing Django URLs With Extra Options

  - by Justin Voss

  Suppose I have a URLconf like below, and 'foo' and 'bar' are valid values for page_slug. urlpatterns = patterns('', (r'^page/(?P<page_slug>.*)/', 'myapp.views.someview'), ) Then, I could reconstruct the URLs using the below, right? >>> from django.core.urlresolvers import reverse >>> reverse('myapp.views.someview', kwargs={'page_slug': 'foo'}) '/page/foo/' >>> reverse('myapp.views.someview', kwargs={'page_slug': 'bar'}) '/page/bar/' But what if I change my URLconf to this? urlpatterns = patterns('', (r'^foo-direct/', 'myapp.views.someview', {'page_slug': 'foo'}), (r'^my-bar-page/', 'myapp.views.someview', {'page_slug': 'bar'}), ) I expected this result: >>> from django.core.urlresolvers import reverse >>> reverse('myapp.views.someview', kwargs={'page_slug': 'foo'}) '/foo-direct/' >>> reverse('myapp.views.someview', kwargs={'page_slug': 'bar'}) '/my-bar-page/' However, this throws a NoReverseMatch exception. I suspect I'm trying to do something impossible. Any suggestions on a saner way to accomplish what I want? Named URLs aren't an option, since I don't want other apps that link to these to need to know about the specifics of the URL structure (encapsulation and all that).

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• How should I organize complex SQL views in Rails?

  - by Benjamin Oakes

  I manage a research database with Ruby on Rails. The data that is entered is primarily used by scientists who prefer to have all the relevant information for a study in one single massive table for use in their statistics software of choice. I'm currently presenting it as CSV, as it's very straightforward to do and compatible with the tools people want to use. I've written many views (the SQL kind, not the Rails HTML/ERB kind) to make the output they expect a reality. Some of these views are quite large and have a fair amount of complexity behind them. I wrote them in SQL because there are many calculations and comparisons that are more easily done with SQL. They're currently loaded into the database straight from a file named views.sql. To get the requested data, I do a select * from my_view;. The views.sql file is getting quite large. Part of the problem is that we're still figuring out what the data we collect means, so there's a lot of changes being made to the views all the time -- and a ton of them are being created. Many of them need to be repeatable. I've recently run into issues organizing and testing these views. Rails works great for user interface stuff and business logic, but I'm not aware of much existing structure for handling the reporting we require. Some options I've thought of: Should I move them into the most relevant models somehow? Several of the views interact with each other, which makes this situation more complex than just doing a single find_by_sql, so I don't know if they should only be part of the model. Perhaps they should be treated as a "view" in the MVC sense? (That is, they could be moved into app/views/ and live alongside the HTML, perhaps as files named something like my_view.csv.sql which return CSV.) How would you deal with a complex reporting problem like this?

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• Re: How can Django/WSGI and PHP share / on Apache?

  - by Bogdan

  in response to: How can Django/WSGI and PHP share / on Apache? Hello, could you please post the complete config file from /sites-available I am having a problem seems like rewrite engine redirects all requests to django, so static and php files are not served and instead i see the django 404 page. If I get rid of rewrite rule then static files and php works. here is my apache config file from /sites-available <VirtualHost *:80> ServerAdmin webmaster@localhost DocumentRoot /home/www/django <Directory /> Options +FollowSymLinks ExecCGI Indexes AllowOverride None DirectoryIndex index.php AddHandler wsgi-script .wsgi </Directory> RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*)$ /mysite.wsgi/$1 [QSA,PT,L] ~ and my .wsgi file: import site site.addsitedir('/home/user/.virtualenvs/url.com/lib/python2.6/site-packages') import os, sys path = '/home/www/django' if path not in sys.path: sys.path.append(path) os.environ['DJANGO_SETTINGS_MODULE'] = 'mysite.settings' sys.path.append(path + '/mysite') import django.core.handlers.wsgi _application = django.core.handlers.wsgi.WSGIHandler() import posixpath def application(environ, start_response): # Wrapper to set SCRIPT_NAME to actual mount point. environ['SCRIPT_NAME'] = posixpath.dirname(environ['SCRIPT_NAME']) if environ['SCRIPT_NAME'] == '/': environ['SCRIPT_NAME'] = '' return _application(environ, start_response) the document root directory on disk (/home/www/django) contains php files, images, and the mysite.wsgi file.. thanks for your help

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• Forward Apache to Django dev server

  - by Alex Jillard

  I'm trying to get apache to forward all requests on port 80 to 127.0.0.1:8000, which is where the django dev server runs. I think I have it forwarding properly, but there must be an issue with 127.0.0.1:8000 not being run by apache? I'm running the django dev server in an ubuntu vmware instance, and I'd other people in the office to see the apps in development without having to promote anything to our actual dev/staging servers. Right now the virtual machine picks up an IP for itself, and when I point a browser to that url with the defualt apache config, I get the default apache page. I've since changed the httpd.conf file to the following to try and get it to forward the requests to the django dev server: ServerName localhost <Proxy *> Order deny,allow Allow from all </Proxy> <VirtualHost *> ServerName localhost ServerAdmin [email protected] ProxyRequests off ProxyPass * http://127.0.0.1:8000 </VirtualHost> All I get are 404s with this, and in error.log I get the following (192.168.1.101 is the IP of my computer 192.168.1.142 is the IP of the virtual machine): [Mon Mar 08 08:42:30 2010] [error] [client 192.168.1.101] File does not exist: /htdocs

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• Getting a "403 access denied" error instead of serving file (using django, gunicorn nginx)

  - by Finglish

  Getting a "403 access denied" error instead of serving file (using django, gunicorn nginx) I am attempting to use nginx to serve private files from django. For X-Access-Redirect settings I followed the following guide http://www.chicagodjango.com/blog/permission-based-file-serving/ Here is my site config file (/etc/nginx/site-available/sitename): server { listen 80; listen 443 default_server ssl; server_name localhost; client_max_body_size 50M; ssl_certificate /home/user/site.crt; ssl_certificate_key /home/user/site.key; access_log /home/user/nginx/access.log; error_log /home/user/nginx/error.log; location / { access_log /home/user/gunicorn/access.log; error_log /home/user/gunicorn/error.log; alias /path_to/app; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_set_header Host $http_host; proxy_redirect off; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Scheme $scheme; proxy_pass http://127.0.0.1:8000; proxy_connect_timeout 100s; proxy_send_timeout 100s; proxy_read_timeout 100s; } location /protected/ { internal; alias /home/user/protected; } } I then tried using the following in my django view to test the download: response = HttpResponse() response['Content-Type'] = "application/zip" response['X-Accel-Redirect'] = '/protected/test.zip' return response but instead of the file download I get: 403 Forbidden nginx/1.1.19 Please note: I have removed all the personal data from the the config file, so if there are any obvious mistakes not related to my error that is probably why. My nginx error log gives me the following: 2012/09/18 13:44:36 [error] 23705#0: *44 directory index of "/home/user/protected/" is forbidden, client: 80.221.147.225, server: localhost, request: "GET /icbdazzled/tmpdir/ HTTP/1.1", host: "www.icb.fi"

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• Server Clustering (Django, Apache, Nginx, Postgres)

  - by system-matrix

  I have a project deployed with django, Apache, Nginx and Postgres. The project has requirement of live data viewable to customers. The projects main points are: 1. Devices in field send data to server(devices are also like website users) after login. 2. There is background import process which imports the uploaded data in postgres. 3. The webusers of the system use this data and can send commands to the devices, which devices read when they login. 4. There are also background analysis routines running on the data. All the above mentioned setup and system is deployed on one amazon EC2 cloud machine. The project currently supports over 600 devices and 400 users. But as the number of devices are increasing with time the performance of the server is going down. We want to extend this project so that it can support more and more devices. My initial thinking is, We will create one more server like current one and divide the devices amongst these to servers. But Again We need a central user and device managment point though django admin. Any Ideas? What are the best possible ways to create a scalable architecture? How can I create a Postgres Cluster and Use it with Django, if possible?

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• EC2 configuration for medium load service on Django

  - by Luberg

  I have created a very basic Django application which puts an email to the database (Coming soon page for a startup). I launched a t1.micro instance to try out which load it can carry out. Nginx+FastCGI from Django+sqllite/postgres - tried both. blitz.io test gave me a pretty unhappy result (just 100 users within 1 minute): This rush generated 542 successful hits in 1.0 min and we transferred 809.01 KB of data in and out of your app. The average hit rate of 8.81/second translates to about 761,612 hits/day. You got bigger problems though: 87.28% of the users during this rush experienced timeouts or errors! I tried both to put varnish, disabled Debub mode in django and started fastcgi in threaded mode - nothing helps. This is not gonna be a super highload page - just a coming soon page to save email of subscribers, it should carry at least 500-1000 users at the same time in peak... I believe t1.micro is super small for that, but I also have tried small instance - not better result.. Please let me know should I use something different from Amazon EC2, or to pick smth better than t1.micro, or I that is definetely a configuration issues?...

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• safely hosting a django project over apache using centos

  - by tipu

  Error can be seen at: http://djaffry.selfip.com:8080/ I had a project working great, but I had all the files under /var/www/ and with my limited understanding it's bad, according to django's site: "If your background is in PHP, you’re probably used to putting code under the Web server’s document root (in a place such as /var/www). With Django, you don’t do that. It’s not a good idea to put any of this Python code within your Web server’s document root, because it risks the possibility that people may be able to view your code over the Web. That’s not good for security. Put your code in some directory outside of the document root, such as /home/mycode." So I went to /home/tipu/stuff/ and executed django-admin.py startproject twingle. Then I went to apache and did <VirtualHost *:8080> ServerName tweet_search_engine DocumentRoot /home/tipu/stuff/twingle/ </VirtualHost> <Directory /home/tipu/stuff/twingle> SetHandler python-program PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE settings PythonOption django.root /home/tipu/stuff/twingle PythonDebug On PythonPath "['/home/tipu/stuff/', '/home/tipu/stuff/twingle/'] + sys.path" </Directory> Now I am getting a 403 Forbidden error.. any idea what I'm doing wrong? I'm newer to Linux (CentOS) and django, so I could be over looking some very simple things.

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• eclipse django using wrong settings.py in pythonpath

  - by user1290264

  I have pydev/django installed in eclipse, and it runs fine. However, after adding a second django project to eclipse and running the server ('http://127.0.0.1:8000') the pythonpath seems to be stuck on project2 even when I run project1. As a summary, I have two django projects: project1, project2. When I run the django server for project1 I get: Validating models... 0 errors found Django version 1.5, using settings 'project1.settings' Development server is running at 'http://127.0.0.1:8000/' Quit the server with CTRL-BREAK. The above seems to suggest that django is using the correct settings file; however, when I go to 'http://127.0.0.1:8000/' it displays the urls from project2. Also, if I go to 'http://127.0.0.1:8000/admin' the models are getting pulled from the sqlite.db file in project2 as well. I've even tried removing project2 from eclipse entirely and now at 'http://127.0.0.1:8000/admin' I get this error: Python Path: ['C:\Users\Brad\workspaces\In Progress\project2', 'C:\Users\Brad\workspaces\In Progress\project2', 'C:\Python27\DLLs', 'C:\Python27\lib', 'C:\Python27\lib\plat-win', 'C:\Python27\lib\lib-tk', 'C:\Python27', 'C:\Python27\lib\site-packages', 'C:\Windows\system32\python27.zip'] If I run the server on a different port with project1 the path seems to be fine: runserver 7000 --noreload Then 'http://127.0.0.1:7000/' uses project1's paths, but it doesn't seem like I should have to do this. Note: I have setup the run configurations as correctly as I know how. In the main tab, the project and main module both point to the correct project (project1), and the "PYTHONPATH that will be used in the run:" includes project1. Also, I have cleared my browser history, cookies, and everything that chrome would let me delete.

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• Use Django ORM as standalone [closed]

  - by KeyboardInterrupt

  Possible Duplicates: Use only some parts of Django? Using only the DB part of Django I want to use the Django ORM as standalone. Despite an hour of searching Google, I'm still left with several questions: Does it require me to set up my Python project with a setting.py, /myApp/ directory, and modules.py file? Can I create a new models.py and run syncdb to have it automatically setup the tables and relationships or can I only use models from existing Django projects? There seems to be a lot of questions regarding PYTHONPATH. If you're not calling existing models is this needed? I guess the easiest thing would be for someone to just post a basic template or walkthrough of the process, clarifying the organization of the files e.g.: db/ __init__.py settings.py myScript.py orm/ __init__.py models.py And the basic essentials: # settings.py from django.conf import settings settings.configure( DATABASE_ENGINE = "postgresql_psycopg2", DATABASE_HOST = "localhost", DATABASE_NAME = "dbName", DATABASE_USER = "user", DATABASE_PASSWORD = "pass", DATABASE_PORT = "5432" ) # orm/models.py # ... # myScript.py # import models.. And whether you need to run something like: django-admin.py inspectdb ... (Oh, I'm running Windows if that changes anything regarding command-line arguments.).

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