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  • Regex to use each letter only once?

    - by gtcaz
    Is it possible to construct a PCRE-style regular expression that will only match each letter in a list only once? For example, if you have the letters "lrsa" and you try matching a word list against: ^[lrsa]*m[lrsa]*$ you're going to match "lams" (valid), but also "lamas" (invalid for our purposes because you only had one "a"). If your letter set was "lrsaa", you would want to match "lamas". Is this possible with regular expressions, or should I handle it programmatically?

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  • Is Minus Zero some sort of JavaScript performance trick?

    - by James Wiseman
    Looking in the jQuery core I found the folloiwng code convention: nth: function(elem, i, match){ return match[3] - 0 === i; }, And I was really curious about the snippet match[3] - 0 Hunting around for '-0' on google isn't too productive, and a search for 'minus zero' brings back a reference to a Bob Dylan song. So, can anyone tell me. Is this some sort of performance trick, or is there a reason for doing this rather than a parseInt or parseFloat? Thanks

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  • javascript string exec strange behavior

    - by Michael
    have funciton in my object which is called regularly. parse : function(html) { var regexp = /...some pattern.../ var match = regexp.exec(html); while (match != null) { ... match = regexp.exec(html); } ... var r = /...pattern.../g; var m = r.exec(html); } with unchanged html the m returns null each other call. let's say parse(html);// ok parse(html);// m is null!!! parse(html);// ok parse(html);// m is null!!! // ...and so on... is there any index or somrthing that has to be reset on html ... I'm really confused. Why match always returns proper result?

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  • Shortening code

    - by Misiur
    Nah, looks like it was hosting fault. Who can make this code shorter? private function replaceFunc($subject) { foreach($this->func as $t) { preg_match_all('/\{'.$t.'\([a-zA-Z,\']+\)\}/i', $subject, $res); for($j = 0; $j < sizeof($res[0]); $j++) { preg_match('/\([a-zA-Z,\']+\)/i', $res[0][$j], $match); if($match > 0) { $prep = explode(", ", substr($match[0], 1, -1)); $args = array(); for($i = 0; $i < sizeof($prep); $i++) { $args[] = substr($prep[$i], 1, -1); } } else { $args = array(); } $subject = preg_replace('/\{'.$t.preg_quote($match[0]).'\}/i', call_user_func_array($t, $args), $subject); } } return $subject; }

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  • If-elseif-else Logic Question

    - by Changeling
    I have a set of three values, call them x, y, and z. If value A happens to match only one in the set x, y, and z, then that means we have a proper match and we stop searching for a match, even if it is at y. It can match any one in that set. These values x, y, and z are non-constant so I cannot use a switch-case statement. How do I do this with an if-elseif-else statements without having to use GOTO. I am using C++ (no boost or any of that other fancy stuff). Now, I am trying to do this in code and it is racking my brain this morning (not enough coffee?)

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  • Python Regular Expressions: Capture lookahead value (capturing text without consuming it)

    - by Lattyware
    I wish to use regular expressions to split words into groups of (vowels, not_vowels, more_vowels), using a marker to ensure every word begins and ends with a vowel. import re MARKER = "~" VOWELS = {"a", "e", "i", "o", "u", MARKER} word = "dog" if word[0] not in VOWELS: word = MARKER+word if word[-1] not in VOWELS: word += MARKER re.findall("([%]+)([^%]+)([%]+)".replace("%", "".join(VOWELS)), word) In this example we get: [('~', 'd', 'o')] The issue is that I wish the matches to overlap - the last set of vowels should become the first set of the next match. This appears possible with lookaheads, if we replace the regex as follows: re.findall("([%]+)([^%]+)(?=[%]+)".replace("%", "".join(VOWELS)), word) We get: [('~', 'd'), ('o', 'g')] Which means we are matching what I want. However, it now doesn't return the last set of vowels. The output I want is: [('~', 'd', 'o'), ('o', 'g', '~')] I feel this should be possible (if the regex can check for the second set of vowels, I see no reason it can't return them), but I can't find any way of doing it beyond the brute force method, looping through the results after I have them and appending the first character of the next match to the last match, and the last character of the string to the last match. Is there a better way in which I can do this? The two things that would work would be capturing the lookahead value, or not consuming the text on a match, while capturing the value - I can't find any way of doing either.

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  • Create fulltext index on a VIEW

    - by kylex
    Is it possible to create a full text index on a VIEW? If so, given two columns column1 and column2 on a VIEW, what is the SQL to get this done? The reason I'd like to do this is I have two very large tables, where I need to do a FULLTEXT search of a single column on each table and combine the results. The results need to be ordered as a single unit. Suggestions? EDIT: This was my attempt at creating a UNION and ordering by each statements scoring. (SELECT a_name AS name, MATCH(a_name) AGAINST('$keyword') as ascore FROM a WHERE MATCH a_name AGAINST('$keyword')) UNION (SELECT s_name AS name,MATCH(s_name) AGAINST('$keyword') as sscore FROM s WHERE MATCH s_name AGAINST('$keyword')) ORDER BY (ascore + sscore) ASC sscore was not recognized.

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  • lexical analysis gives only one output?

    - by Caffè
    I tested this example(lexe.java), but it gave me only one output. I gave this text as a reader: public class LexeTest{ private int a = 14; } And the nextToken() function is : public Category nextToken () { if (inp.findWithinHorizon (tokenPat, 0) == null) return Category.EOF; else { lastLexeme = inp.match ().group (0); if (inp.match ().start (1) != -1) return nextToken (); else if (inp.match ().start (2) != -1) return Category.IDENT; else if (inp.match ().start (3) != -1) return Category.NUMERAL; Category result = tokenMap.get (lastLexeme); if (result == null) return Category.ERROR; else return result; } } Isdie the main method: System.out.println(lexeObject.nextToken()); output is : IDENT Why? but the textfile contains multiple keywords? Anyone know what's the problem?

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  • How to apply or chain multiple matching templates in XSLT?

    - by Ignatius
    I am working on a stylesheet employing many templates with match attributes: <xsl:template match="//one" priority="0.7"> <xsl:param name="input" select="."/> <xsl:value-of select="util:uppercase($input)"/> <xsl:next-match /> </xsl:template> <xsl:template match="/stuff/one"> <xsl:param name="input" select="."/> <xsl:value-of select="util:add-period($input)"/> </xsl:template> <xsl:function name="util:uppercase"> <xsl:param name="input"/> <xsl:value-of select="upper-case($input)"/> </xsl:function> <xsl:function name="util:add-period"> <xsl:param name="input"/> <xsl:value-of select="concat($input,'.')"/> </xsl:function> What I would like to do is be able to 'chain' the two functions above, so that an input of 'string' would be rendered in the output as 'STRING.' (with the period.) I would like to do this in such a way that doesn't require knowledge of other templates in any other template. So, for instance, I would like to be able to add a "util:add-colon" method without having to open up the hood and monkey with the existing templates. I was playing around with the <xsl:next-match/> instruction to accomplish this. Adding it to the first template above does of course invoke both util:uppercase and util:add-period, but the output is an aggregation of each template output (i.e. 'STRINGstring.') It seems like there should be an elegant way to chain any number of templates together using something like <xsl:next-match/>, but have the output of each template feed the input of the next one in the chain. Am I overlooking something obvious?

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  • Difference in regex between Python and Rubular?

    - by Rosarch
    In Rubular, I have created a regular expression: (Prerequisite|Recommended): (\w|-| )* It matches the bolded: Recommended: good comfort level with computers and some of the arts. Summer. 2 credits. Prerequisite: pre-freshman standing or permission of instructor. Credit may not be applied toward engineering degree. S-U grades only. Here is a use of the regex in Python: note_re = re.compile(r'(Prerequisite|Recommended): (\w|-| )*', re.IGNORECASE) def prereqs_of_note(note): match = note_re.match(note) if not match: return None return match.group(0) Unfortunately, the code returns None instead of a match: >>> import prereqs >>> result = prereqs.prereqs_of_note("Summer. 2 credits. Prerequisite: pre-fres hman standing or permission of instructor. Credit may not be applied toward engi neering degree. S-U grades only.") >>> print result None What am I doing wrong here?

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  • Stringbuilder problem creating dynamic links

    - by wali
    Hi all, I'm having an issue creating a link like "<a href="javascript:window.open('www.microsoft.com');">Visit Microsoft</a> using stringbuilder. I am adding html to a panel dynamically and I am trying to create a popup link. The problem is that for some reason the link gets "mixed up". For example: Dim s As String sb.Append("<A HREF='javascript:void(0)' onclick='window.open(") sb.Append("'") sb.Append("Match.aspx?MatchID=") sb.Append(mt.MatchID) sb.Append("&batchid=") sb.Append(mb.batchID) sb.Append("')>") sb.Append("Match</A>") gives an output of : <a match.aspx?matchid="28840&amp;batchid=26596')" onclick="window.open(" href="javascript:void(0)">Match</a> I have no clue what I'm doing wrong, it even does this kind of crap for a regular string! Please help!

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  • need code for search another character

    - by klox
    hi,all..i have this code: var str = "KD-R435MUN2D"; var hasUD; var patt1 = str.match(/U/gi); var patt2 = str.match(/D/gi); if (patt1 && patt2) { hasUD = 'UD'; } else { hasUD = false; } document.write(hasUD); how to modify this code if i want search JD from var str="KD-S35JWD"..i try this but doesn't work: <script type="text/javascript"> var str = "KD-R435jwd"; var hasUD; var hasJD; var patt1 = str.match(/U/gi); var patt2 = str.match(/J/gi); var patt3 = str.match(/D/gi); if (patt1 && patt3) { hasUD = 'UD'; document.write(hasUD); } elseif (patt2 && patt3) { hasJD = 'JD'; document.write(hasJD); } </script>

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  • Solr/Lucene Scorer

    - by TFor
    We are currently working on a proof-of-concept for a client using Solr and have been able to configure all the features they want except the scoring. Problem is that they want scores that make results fall in buckets: Bucket 1: exact match on category (score = 4) Bucket 2: exact match on name (score = 3) Bucket 3: partial match on category (score = 2) Bucket 4: partial match on name (score = 1) First thing we did was develop a custom similarity class that would return the correct score depending on the field and an exact or partial match. The only problem now is that when a document matches on both the category and name the scores are added together. Example: searching for "restaurant" returns documents in the category restaurant that also have the word restaurant in their name and thus get a score of 5 (4+1) but they should only get 4. I assume for this to work we would need to develop a custom Scorer class but we have no clue on how to incorporate this in Solr. Another option is to create a custom SortField implementation similar to the RandomSortField already present in Solr. Maybe there is even a simpler solution that we don't know about. All suggestions welcome!

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  • How to Generate XML from Database

    - by Nisarg Mehta
    Hi , I am fetching data from two tables CARRIER_IFTA ,IFTA_NAME. My Select Query is like below.. SELECT t1.IFTA_LICENSE_NUMBER,t1.IFTA_BASE_STATE,t2.NAME_TYPE,t2.NAME from CARRIER_IFTA t1 inner join IFTA_NAME t2 on t1.IFTA_LICENSE_NUMBER=t2.IFTA_LICENSE_NUMBER My Data is coming in this way... IFTA_LICENSE_NUMBER IFTA_BASE_STATE NAME_TYPE NAME -------------------------------------------------------- 630908333 US LG XYZ 630908333 US MG PQR 730908344 US LG ABC Now using XSLT I want to generate XML like this <T0019> <IFTA_ACCOUNT> <IFTA_LICENSE_NUMBER>630908333</IFTA_LICENSE_NUMBER> <IFTA_BASE_STATE>US</IFTA_BASE_STATE> <IFTA_NAME> <NAME_TYPE>LG<NAME_TYPE> <NAME>XYZ</NAME> </IFTA_NAME> <IFTA_NAME> <NAME_TYPE>MG<NAME_TYPE> <NAME>PQR</NAME> <IFTA_NAME> </IFTA_ACCOUNT> <IFTA_ACCOUNT> <IFTA_LICENSE_NUMBER>730908344</IFTA_LICENSE_NUMBER> <IFTA_BASE_STATE>US</IFTA_BASE_STATE> <IFTA_NAME> <NAME_TYPE>LG<NAME_TYPE> <NAME>ABC</NAME> </IFTA_NAME> </IFTA_ACCOUNT> </T0019> i have used below xslt but it is not giveng me desire result ... <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:template match="/ROWSET"> <xsl:element name="T0019"> <xsl:apply-templates select="IFTAACCOUNT"/> </xsl:element> </xsl:template> <xsl:template match="IFTAACCOUNT"> <xsl:element name="IFTAACCOUNT"> <xsl:apply-templates select="IFTA_CARRIER_ID_NUMBER"/> </xsl:element> </xsl:template> <xsl:template match="IFTA_LICENSE_NUMBER"> <xsl:element name="IFTA_LICENSE_NUMBER"> <xsl:apply-templates /> </xsl:element> </xsl:template> <xsl:template match="IFTA_BASE_STATE"> <xsl:element name="IFTA_BASE_STATE"> <xsl:apply-templates /> </xsl:element> </xsl:template> <xsl:template match="IRP_NAME"> <IRP_NAME> <xsl:apply-templates select="NAME"/> <xsl:apply-templates select="NAME_TYPE"/> </IRP_NAME> </xsl:template> <xsl:template match="NAME"> <xsl:element name="NAME"> <xsl:value-of select="." /> </xsl:element> </xsl:template> <xsl:template match="NAME_TYPE"> <xsl:element name="NAME_TYPE"> <xsl:apply-templates /> </xsl:element> </xsl:template> </xsl:stylesheet> but it is not giving desire result ... Please help me ... Thanks in Advance...

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  • Help with Regular Expression

    - by shivesh
    Hello I need help with Regular Expression, I want to match each section (number and it's text - 2 groups), the text can be multi line, each section ends when another section starts (another number) or when .END is reached or EOF. Demo Expression: \(\d{1,3}\) ([\s\S]*?)(\.END|\(\d{1,3}\)) Input text: (1) some text some text some text some text some text some text (2) some text some textsome text (3) some textsome text some textsome textsome text (4) some text .END first group should match number (with brackets) and second group should match corresponded text.

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  • XPath ordered priority attribute search

    - by user94000
    I want to write an XPath that can return some link elements on an HTML DOM. The syntax is wrong, but here is the gist of what I want: //web:link[@text='Login' THEN_TRY @href='login.php' THEN_TRY @index=0] THEN_TRY is a made-up operator, because I can't find what operator(s) to use. If many links exist on the page for the given set of [attribute=name] pairs, the link which matches the most left-most attribute(s) should be returned instead of any others. For example, consider a case where the above example XPath finds 3 links that match any of the given attributes: link A: text='Sign In', href='Login.php', index=0 link B: text='Login', href='Signin.php', index=15 link C: text='Login', href='Login.php', index=22 Link C ranks as the best match because it matches the First and Second attributes. Link B ranks second because it only matches the First attribute. Link A ranks last because it does not match the First attribute; it only matches the Second and Third attributes. The XPath should return the best match, Link C. If more than one link were tied for "best match", the XPath should return the first best link that it found on the page.

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  • convert xml document to comma delimited (CSV) file using xslt stylesheet.

    - by Brad H
    I need some assistance converting an xml document to a CSV file using an xslt stylesheet. I am trying to use the following xsl and I can't seem to get it right. I want my comma delimited file to include column headings, followed by the data. My biggest issues are removing the final comma after the last item and inserting a carriage return so each group of data appears on a separate line. I have been using XML Notepad. <xsl:template match="/"> <xsl:element name="table"> <xsl:apply-templates select="/*/*[1]" mode="header" /> <xsl:apply-templates select="/*/*" mode="row" /> </xsl:element> </xsl:template> <xsl:template match="*" mode="header"> <xsl:element name="tr"> <xsl:apply-templates select="./*" mode="column" /> </xsl:element> </xsl:template> <xsl:template match="*" mode="row"> <xsl:element name="tr"> <xsl:apply-templates select="./*" mode="node" /> </xsl:element> </xsl:template> <xsl:template match="*" mode="column"> <xsl:element name="th"> <xsl:value-of select="translate(name(.),'qwertyuiopasdfghjklzxcvbnm_','QWERTYUIOPASDFGHJKLZXCVBNM ')" /> </xsl:element>, </xsl:template> <xsl:template match="*" mode="node"> <xsl:element name="td"> <xsl:value-of select="." /> </xsl:element>, </xsl:template>

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  • Problem with regular expression for some special parttern.

    - by SpawnCxy
    Hi all, I got a problem when I tried to find some characters with following code: preg_match_all('/[\w\uFF10-\uFF19\uFF21-\uFF3A\uFF41-\uFF5A]/',$str,$match); //line 5 print_r($match); And I got error as below: Warning: preg_match_all() [function.preg-match-all]: Compilation failed: PCRE does not support \L, \l, \N, \U, or \u at offset 4 in E:\mycake\app\webroot\re.php on line 5 I'm not so familiar with reg expression and have no idea about this error.How can I fix this?Thanks.

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  • finding common prefix of array of strings

    - by bumperbox
    I have an array like this $sports = array( 'Softball - Counties', 'Softball - Eastern', 'Softball - North Harbour', 'Softball - South', 'Softball - Western' ); and i would like to find the longest common part of the string so in this instance, it would be 'Softball - '; I am thinking that I would follow the this process $i = 1; // loop to the length of the first string while ($i < strlen($sports[0]) { // grab the left most part up to i in length $match = substr($sports[0], 0, $i); // loop through all the values in array, and compare if they match foreach ($sports as $sport) { if ($match != substr($sport, 0, $i) { // didn't match, return the part that did match return substr($sport, 0, $i-1); } } // foreach // increase string length $i++; } // while // if you got to here, then all of them must be identical Questions is there a built in function or much simpler way of doing this ? for my 5 line array that is probably fine, but if i were to do several thousand line arrays, there would be a lot of overhead, so i would have to be move calculated with my starting values of $i, eg $i = halfway of string, if it fails, then $i/2 until it works, then increment $i by 1 until we succeed. so that we are doing the least number of comparisons to get a result If there a formula/algorithm out already out there for this kind of problem ? thanks alex

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  • Problem with Replace in Eclipse

    - by Imran
    I'm using regex to match all non-quoted property names in my json files. Eclipse has no problem finding the desired matches, but when I want to replace the matched strings with "$2", I get this error: Match string has changed in file filename.json. Match skipped Here's the regex I'm using: `((\w+)\s*(?!['"])(?=:))` Any idea on how to work around this issue?

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  • Find and replace numbers in string with regex

    - by James
    What I'm trying to achieve is to replace the numbers in the string with a new values calculated from the (match * int). So the string input looks like: 500g Flour 14g Salt 7g Dry yeast 45ml Olive oil 309ml Water And the result should look like this: 1000g Flour 14g Salt 14g Dry yeast 90ml Olive oil 618 ml Water row["ingredients"] is a DataRow. This is where I'm at: System.Text.RegularExpressions. Regex.Replace(row["ingredients"].ToString(), @"[^/d]", Delegate(Match match) { return match * 2; }, RegexOptions.Multiline); Any solution is greatly appreciated.

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  • Delphi 6: How to search a dynamic array for sub-string quickly?

    - by Robert Oschler
    How can I search a dynamic array of char in Delphi 6 for a sub-string and get back an index to a match, not a pointer? I've seen functions in Delphi 6 that do this for strings but not for dynamic char arrays. There is a function called SearchBuf but that function returns a PChar pointer to the match location when what I need is the array index of the match. Thanks.

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  • Routing Error in Chapter 7.1.2 of the Ruby on Rails Tutorial

    - by user2985910
    I've been working through the tutorial for the past few days, and finally hit a snag in chapter 7. It is in this step where the line in routes.rb: get "users/new" is replaced with resource :users After I do this, I get a routing error when visiting http://localhost:3000/users/1 - No route matches [GET] "/users/1" instead of the other "Unknown Action" error shown here. Per the instructions, my routes.db file looks like this: SampleApp::Application.routes.draw do resource :users root "static_pages#home" match '/signup', to: 'users#new', via: 'get' match '/help', to: 'static_pages#help', via: 'get' match '/about', to: 'static_pages#about', via: 'get' match '/contact', to: 'static_pages#contact', via: 'get' end Output from 'rake routes' shows: Prefix Verb URI Pattern Controller#Action users POST /users(.:format) users#create new_users GET /users/new(.:format) users#new edit_users GET /users/edit(.:format) users#edit GET /users(.:format) users#show PATCH /users(.:format) users#update PUT /users(.:format) users#update DELETE /users(.:format) users#destroy root GET / static_pages#home signup GET /signup(.:format) users#new help GET /help(.:format) static_pages#help about GET /about(.:format) static_pages#about contact GET /contact(.:format) static_pages#contact Does anyone have any insight to get past this? Many thanks.

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