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• Samba new file ownership, permissions configuration

  - by Martin Melka

  I have recently installed Samba on my server. Now I have a question about permissions and how to set it up. Currently I mount the Samba shared drive to my laptop with this line in /etc/fstab: //<host>/share /mnt/melka-server-data/ cifs username=<usrname> password=<passwd> _netdev 0 0 This works, as I can read from the files and create them (as root). The problem is when I want to create files as a regular user. I always get a Permission Denied error. These are ll outputs of the mounted folder: magicmaster@magicmaster-kubuntu:/mnt$ ll total 8 drwxr-xr-x 3 root root 4096 lis 11 14:15 ./ drwxr-xr-x 26 root root 4096 ríj 26 11:01 ../ drwxrwxrwx 8 magicmaster magicmaster 0 lis 12 22:12 melka-server-data/ and the inside: magicmaster@magicmaster-kubuntu:/mnt/melka-server-data$ ll total 4 drwxrwxrwx 8 magicmaster magicmaster 0 lis 12 22:12 ./ drwxr-xr-x 3 root root 4096 lis 11 14:15 ../ drwxrwxrwx 5 magicmaster magicmaster 0 lis 12 09:35 downloads/ drwxrwxrwx 2 magicmaster magicmaster 0 ríj 28 12:57 lost+found/ drwxrwxrwx 15 magicmaster magicmaster 0 lis 12 09:45 movies/ drwxrwxrwx 2 magicmaster magicmaster 0 lis 1 21:15 newest/ drwxrwxrwx 3 magicmaster magicmaster 0 lis 2 23:14 photos/ drwxrwxrwx 2 magicmaster magicmaster 0 ríj 30 12:44 software/ -rw-r--r-- 1 nobody nogroup 0 lis 12 22:12 zdar I called sudo chown -R magicmaster:magicmaster melka-server-data/ to try and change all the files to belong to me. Then the file zdar was created by magicmaster just by calling touch. I got the Permission Denied, but it was still created, though it belongs to nobody and I can't write into it. When I create a file as root, it still belongs to nobody, but at least I can write into it. What am I missing? I didn't notice anything in Samba config that would be related to this and I don't like the idea of having to log on as root in order to copy files.. Thanks

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• How does Google Analytics aggregate the Count of Visits (Frequency & Recency Report)?

  - by Brian Dant

  Here's my simple understanding of Count of Visits: Each person that comes to my site gets one "count" for each visit. They are put into a bucket of people with the same number of total counts -- if you visit twice, you are in the two bucket, if you visit six times, you are in the six bucket. From there, a report (Frequency & Recency) makes a line for each bucket and reaches into the bucket and totals the number of people in that bucket, putting that total in the second column. My Question: Will a two month report automatically put someone into two buckets, and put them on two separate lines in the Count of Visits table? This explaination makes it seem like a two-month long report will put the same person into a bucket twice, one bucket for each month. The two-month report will then show that person's visits on two different lines, instead of aggregating them. Example for Clarification: Bob comes to my site three times in January and seven times in February. I run a report for Jan 1 -- Feb 28. Will Bob be on both the Three Count line and the Seven Count line, or will he be on the Ten Count line?

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• Screen resolution stuck at 1024x768

  - by Dananjaya

  I just updated from Ubuntu 10.10 to 11.04 and have an issue regarding the screen resolution. I have Intel integrated gfx chip and my monitor supports resolutions larger than 1024x768. (in 10.10 I've been using 1280x1024) But as soon as I upgraded, I'm stuck with 1024x768 resolution and seems I can't change it. running xrandr In terminal yields the following results, Screen 0: minimum 320 x 200, current 1024 x 768, maximum 4096 x 4096 LVDS1 connected 1024x768+0+0 (normal left inverted right x axis y axis) 0mm x 0mm 1280x800 58.1 + 1024x768 60.0* 800x600 60.3 56.2 640x480 59.9 VGA1 connected 1024x768+0+0 (normal left inverted right x axis y axis) 344mm x 194mm 1366x768 59.9 + 1360x768 60.0 1024x768 75.1 72.0 70.1 60.0* 832x624 74.6 800x600 72.2 75.0 60.3 56.2 640x480 72.8 75.0 66.7 60.0 720x400 70.1 1280x1024_60.00 (0xce) 109.0MHz h: width 1280 start 1368 end 1496 total 1712 skew 0 clock 63.7KHz v: height 1024 start 1027 end 1034 total 1063 clock 59.9Hz What maybe the problem? Is it a bug? What kind of steps I should take in order to get a higher resolution? (changing xorg.conf maybe?) Any insight is highly appreciated. Thanks in advance. UPDATE Screenshot after running xrandr --addmode VGA1 1360x768 As you can see, side bar is not completely visible and Ubuntu logo at the task bar is missing. Also when you open an application, the Task bar of the application (where it should go to the top panel) is missing as well..

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• Red Samurai Performance Audit Tool – OOW 2013 release (v 1.1)

  - by JuergenKress

  We are running our Red Samurai Performance Audit tool and monitoring ADF performance in various projects already for about one year and the half. It helps us a lot to understand ADF performance bottlenecks and tune slow ADF BC View Objects or optimise large ADF BC fetches from DB. There is special update implemented for OOW'13 - advanced ADF BC statistics are collected directly from your application ADF BC runtime and later displayed as graphical information in the dashboard. I will be attending OOW'13 in San Francisco, feel free to stop me and ask about this tool - I will be happy to give it away and explain how to use it in your project. Original audit screen with ADF BC performance issues, this is part of our Audit console application: Audit console v1.1 is improved with one more tab - Statistics. This tab displays all SQL Selects statements produced by ADF BC over time, logged users, AM access load distribution and number of AM activations along with user sessions. Available graphs: Daily Queries  - total number of SQL selects per day Hourly Queries - Last 48 Hours Logged Users - total number of user sessions per day SQL Selects per Application Module - workload per Application Module Number of Activations and User sessions - last 48 hours - displays stress load Read the complete article here. WebLogic Partner Community For regular information become a member in the WebLogic Partner Community please visit: http://www.oracle.com/partners/goto/wls-emea ( OPN account required). If you need support with your account please contact the Oracle Partner Business Center. Blog Twitter LinkedIn Mix Forum Wiki Technorati Tags: Red Samurai,ADF performance,WebLogic,WebLogic Community,Oracle,OPN,Jürgen Kress

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• Defining a function that is both a generator and recursive [on hold]

  - by user96454

  I am new to python, so this code might not necessarily be clean, it's just for learning purposes. I had the idea of writing this function that would display the tree down the specified path. Then, i added the global variable number_of_py to count how many python files were in that tree. That worked as well. Finally, i decided to turn the whole thing into a generator, but the recursion breaks. My understanding of generators is that once next() is called python just executes the body of the function and "yields" a value until we hit the end of the body. Can someone explain why this doesn't work? Thanks. import os from sys import argv script, path = argv number_of_py = 0 lines_of_code = 0 def list_files(directory, key=''): global number_of_py files = os.listdir(directory) for f in files: real_path = os.path.join(directory, f) if os.path.isdir(real_path): list_files(real_path, key=key+' ') else: if real_path.split('.')[-1] == 'py': number_of_py += 1 with open(real_path) as g: yield len(g.read()) print key+real_path for i in list_files(argv[1]): lines_of_code += i print 'total number of lines of code: %d' % lines_of_code print 'total number of py files: %d' % number_of_py

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• How do I find out which process is eating up my bandwidth?

  - by Bruce Connor

  I think I'm being the victim of a bug here. Sometimes while I'm working (I still don't know why), my network traffic goes up to 200 KB/s and stays that way, even tough I'm not doing anything internet-related. This sometimes happens to me with the CPU usage. When it does, I just run a top command to find out which process is responsible and then kill it. Problem is: I have no way of knowing which process is responsible for my high network usage. Both the resource monitor and the top command only tell me my total network usage, neither of them tells me process specific network info. Is there another command I can use to find out which process is getting out of hand? I've already tried killing all the obvious ones (firefox, update-manager, pidgin, etc) with no luck. So far, restarting the machine is the only way I found of getting rid of the issue. EDIT: (just to be clear) I've found questions here about monitoring total bandwidth usage, but, as I mentioned, that's not what I need. UPDATE: The command iftop gives results that disagree entirely with the information reported by System Monitor. While the latter claims there's high network traffic, the former claims there's barely 1 KB/s. Thanks

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• Defining formula through user interface in user form

  - by BriskLabs Pakistan

  I am a student and developing a simple assignment - windows form application in visual studio 2010. The application is suppose to construct formulas as per user requirement. The process: It has to pick data from columns of Microsoft Access database and the user should be able to pick the data by column name like we do in a drop down menu. and create reusable formulas in it ( configure it once and can change it again). followings are column titles from database that can be picked for example. e.g Col -1 : Marks in Maths Col -2 : Total Marks in Maths Col -3 : Marks in science Col -4 : Total marks in science Finally we should be able to construct any formula in the UI like (Col 1 + Col 3 ) / ( col 2 + col 4) = Formula 1 once this is formula is set saved and a name is assigned to it by user. he/she can use the formula and results shall appear in a window below. i.e He would be able to calculate his desired figures (formula) by only manipulating underlying data on the UI layer....choose the data for a period and apply the formula and get the answer Problem: It looks like I have to create an app where rules are set through UI....... this means no stored procedures are required in SQL.... please suggest the right approach.

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• Unable to mount an LVM Hard-drive after upgrade

  - by Bruce Staples

  I imagine this is a basic gotcha ... but I can't see it. I have a system with 2(physical) harddrives. The boot system (/dev/sda) was running 10.04 & the second drive (/dev/sdb) was just a mounted filesystem. I did a clean load of Ubuntu 12.04 overwriting /dev/sda (not an upgrade) & now cannot mount the second drive. so I do not know what to enter it into the fstab ... I had expected to use: /dev/sdb /tera ext4 defaults 0 2 But even manual mounting fails (I also have tried various "-t" options on the off chance!) sudo mount -t ext4 /dev/sdb1 /tera mount: wrong fs type, bad option, bad superblock on /dev/sdb1, missing codepage or helper program, or other error In some cases useful info is found in syslog - try dmesg | tail or so Output from disk queries indicate that it is a Linux LVM & a healthy disk still. sudo lshw -C disk *-disk:0 description: ATA Disk product: WDC WD5000AACS-0 vendor: Western Digital physical id: 0 bus info: scsi@2:0.0.0 logical name: /dev/sda version: 01.0 serial: WD-WCASU1401098 size: 465GiB (500GB) capabilities: partitioned partitioned:dos configuration: ansiversion=5 signature=00015a55 *-disk:1 description: ATA Disk product: WDC WD10EADS-00L vendor: Western Digital physical id: 1 bus info: scsi@3:0.0.0 logical name: /dev/sdb version: 01.0 serial: WD-WCAU47836304 size: 931GiB (1TB) capabilities: partitioned partitioned:dos configuration: ansiversion=5 sudo fdisk -l Disk /dev/sda: 500.1 GB, 500106780160 bytes 255 heads, 63 sectors/track, 60801 cylinders, total 976771055 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00015a55 Device Boot Start End Blocks Id System /dev/sda1 * 2048 972580863 486289408 83 Linux /dev/sda2 972582910 976769023 2093057 5 Extended /dev/sda5 972582912 976769023 2093056 82 Linux swap / Solaris Disk /dev/sdb: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Device Boot Start End Blocks Id System /dev/sdb1 1 1953525167 976762583+ 8e Linux LVM LVM doesn't appear to be an option for mount or fstab. ... and here's a Smart data Screenshot from Disk Utility.

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• How many copies are needed to enlarge an array?

  - by user10326

  I am reading an analysis on dynamic arrays (from the Skiena's algorithm manual). I.e. when we have an array structure and each time we are out of space we allocate a new array of double the size of the original. It describes the waste that occurs when the array has to be resized. It says that (n/2)+1 through n will be moved at most once or not at all. This is clear. Then by describing that half the elements move once, a quarter of the elements twice, and so on, the total number of movements M is given by: This seems to me that it adds more copies than actually happen. E.g. if we have the following: array of 1 element +--+ |a | +--+ double the array (2 elements) +--++--+ |a ||b | +--++--+ double the array (4 elements) +--++--++--++--+ |a ||b ||c ||c | +--++--++--++--+ double the array (8 elements) +--++--++--++--++--++--++--++--+ |a ||b ||c ||c ||x ||x ||x ||x | +--++--++--++--++--++--++--++--+ double the array (16 elements) +--++--++--++--++--++--++--++--++--++--++--++--++--++--++--++--+ |a ||b ||c ||c ||x ||x ||x ||x || || || || || || || || | +--++--++--++--++--++--++--++--++--++--++--++--++--++--++--++--+ We have the x element copied 4 times, c element copied 4 times, b element copied 4 times and a element copied 5 times so total is 4+4+4+5 = 17 copies/movements. But according to formula we should have 1*(16/2)+2*(16/4)+3*(16/8)+4*(16/16)= 8+8+6+4=26 copies of elements for the enlargement of the array to 16 elements. Is this some mistake or the aim of the formula is to provide a rough upper limit approximation? Or am I missunderstanding something here?

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• Dropbox Doubles Referral Credit; Score 500MB for Each Friend You Refer

  - by Jason Fitzpatrick

  Dropbox is doubling the amount of free storage you get per-referral to 500MB, doubling the previous 250MB credit–better yet, the bonus is retroactive and applies to referrals you’ve already made. From the DropBox blog: How much space is that, exactly? For every friend you invite that installs Dropbox, you’ll both get 500 MB of free space. If you’ve got a free account, you can invite up to 32 people for a whopping total of 16 GB of extra space. Pro accounts now earn 1 GB per referral, for a total of 32 GB of extra space. Have you already invited a bunch of people? Don’t worry. Within a few days, you’ll get full credit for every referral that’s already been completed. Boom! Hit up the link below for the full announcement. Dropbox Referrals Now Twice As Nice [Dropbox] How to Sync Your Media Across Your Entire House with XBMC How to Own Your Own Website (Even If You Can’t Build One) Pt 2 How to Own Your Own Website (Even If You Can’t Build One) Pt 1

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• Bundling in visual studio 2012 for web optimization

  - by Jalpesh P. Vadgama

  I have been writing a series of posts about Visual Studio 2012 features. This series describes what are the new features in the Visual Studio 2012. This post will also be part of Visual Studio 2012 feature series. As we know now days web applications or site are providing more and more features and due to that we have include lots of JavaScript and CSS files in our web application.So once we load site then we will have all the JavaScript  js files and CSS files loaded in the browsers and If you have lots of JavaScript files then its consumes lots of time when browser request them. Following images show the same situation over there.   Here you can see total 25 files loaded into the system and it's almost more than 1MB of total size. As we need to have our web application of site very responsive and need to have high performance application/site, this will be a performance bottleneck to our site. In situation like this, the bundling feature of Visual Studio 2012 and ASP.NET 4.5 comes very handy. With the help of this feature we do optimization there and we can increase performance of our application. To enable this feature in Visual Studio 2012 we just made debug=”false” in web.config of our application like following. Now once you enable this feature and run this application in the browser to see your traffic it will have less items like following. As you can see in the above image there are only 8 items. So after enabling bundling it will automatically convert all js and css files into the one request. Isn’t that cool feature? This feature will surely going to have great impact on performance. Hope you like it. Stay tuned for more.. Till then happy programming!!

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• Dealing with three Windows partitions in dual boot installation

  - by Tim

  For dual-boot installation of Ubuntu after Windows. Quoted from ubuntuguide If a Windows boot partition exists as a second NTFS partition, it should be left alone. If there is a Windows recovery partition also installed, it can also be left alone as long as there are only two NTFS partitions total on the hard drive (i.e. there is no NTFS boot partition as well). If there are a total of 3 NTFS partitions on the hard drive, then the third Windows NTFS partition (the recovery partition) should be removed after creating Recovery CDs from it (see here). In the last case where Windows has three partitions, I was wondering why it says the recovery partition shall be removed? Is it possible to keep the three and create another extended partition with several logical partitions for installing Ubuntu and dual-booting the two OSes? I plan to dual-boot install Ubuntu 10.04 with existing Windows 7. Following is the layout of the current partitions of my hard drive viewed from Windows 7: So must I remove the Lenovo_Recovery (Q:) partition for the same reason you give for the first question? Thanks and regards!

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• Why does Ubuntu 13.10 not detect my Win7 partition?

  - by goutham

  I'm trying to install Ubuntu 13.10 alongside Windows 7 on my DELL INSPIRON 14z 5423 laptop and I'm new to all of this. I'm using the Ubuntu 13.10 64-bit ISO burned onto a CD. The first time I tried to install it, Ubuntu said it did not detect any other OS, which meant I only had 4 options: Erase disk and install Ubuntu (I don't want to do this) Encrypt new Ubuntu. Use LVM. Something else. If I choose the Something else option, it brings me to the partition menu and says that I have 1 disk with free space of (500Gb), but that's not true because I have Windows 7. I restarted the laptop several times and booted the CD again and I got exactly the same as I did previously. How do fix this problem and install Ubuntu alongside Windows 7? After executing "sudo fdisk -l" command in terminal ubuntu@ubuntu:~$ sudo fdisk -l WARNING: GPT (GUID Partition Table) detected on '/dev/sda'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sda: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders, total 976773168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0xd2b811c5 Device Boot Start End Blocks Id System /dev/sda1 * 2048 206847 102400 7 HPFS/NTFS/exFAT /dev/sda2 206848 314574847 157184000 7 HPFS/NTFS/exFAT /dev/sda3 314574848 629147647 157286400 7 HPFS/NTFS/exFAT /dev/sda4 629147648 976771071 173811712 7 HPFS/NTFS/exFAT After removing one partition I executed command once again ubuntu@ubuntu:~$ sudo fdisk -l WARNING: GPT (GUID Partition Table) detected on '/dev/sda'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sda: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders, total 976773168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0xd2b811c5 Device Boot Start End Blocks Id System /dev/sda1 * 2048 206847 102400 7 HPFS/NTFS/exFAT /dev/sda2 206848 629145599 314469376 7 HPFS/NTFS/exFAT /dev/sda3 629147648 976771071 173811712 7 HPFS/NTFS/exFAT

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• Update fails to Install

  - by FirmTech

  I get the below error when I try to install updates using Software Updater: Not enough free disk space The upgrade needs a total of 81.3 M free space on disk '/boot'. Please free at least an additional 15.9 M of disk space on '/boot'. Empty your trash and remove temporary packages of former installations using 'sudo apt-get clean'. What should I do? firmtechnologies@FirmTechnologies:~$ (ls -l /boot) total 155801 -rw-r--r-- 1 root root 1158016 May 3 01:30 abi-3.13.0-24-generic -rw-r--r-- 1 root root 1161713 May 8 01:31 abi-3.13.0-26-generic -rw-r--r-- 1 root root 1161713 May 15 20:07 abi-3.13.0-27-generic -rw-r--r-- 1 root root 1161764 Jun 4 22:57 abi-3.13.0-29-generic -rw-r--r-- 1 root root 165510 May 3 01:30 config-3.13.0-24-generic -rw-r--r-- 1 root root 165538 May 8 01:31 config-3.13.0-26-generic -rw-r--r-- 1 root root 165521 May 15 20:07 config-3.13.0-27-generic -rw-r--r-- 1 root root 165544 Jun 4 22:57 config-3.13.0-29-generic drwxr-xr-x 5 root root 1024 Jun 6 14:31 grub -rw-r--r-- 1 root root 29091568 May 7 21:31 initrd.img-3.13.0-24-generic -rw-r--r-- 1 root root 29094684 May 12 12:24 initrd.img-3.13.0-26-generic -rw-r--r-- 1 root root 29095678 May 18 10:57 initrd.img-3.13.0-27-generic -rw-r--r-- 1 root root 29093700 Jun 6 14:32 initrd.img-3.13.0-29-generic drwx------ 2 root root 12288 Apr 30 17:11 lost+found -rw-r--r-- 1 root root 176500 Mar 12 13:31 memtest86+.bin -rw-r--r-- 1 root root 178176 Mar 12 13:31 memtest86+.elf -rw-r--r-- 1 root root 178680 Mar 12 13:31 memtest86+_multiboot.bin -rw------- 1 root root 3372643 May 3 01:30 System.map-3.13.0-24-generic -rw------- 1 root root 3377429 May 8 01:31 System.map-3.13.0-26-generic -rw------- 1 root root 3377429 May 15 20:07 System.map-3.13.0-27-generic -rw------- 1 root root 3378267 Jun 4 22:57 System.map-3.13.0-29-generic -rw------- 1 root root 5776416 May 3 01:30 vmlinuz-3.13.0-24-generic -rw------- 1 root root 5790912 May 8 01:30 vmlinuz-3.13.0-26-generic -rw------- 1 root root 5790912 May 15 20:07 vmlinuz-3.13.0-27-generic -rw------- 1 root root 5792544 Jun 4 22:57 vmlinuz-3.13.0-29-generic

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• Estimate angle to launch missile, maths question

  - by Jonathan

  I've been working on this for an hour or two now and my maths really isn't my strong suit which is definitely not a good thing for a game programmer but that shouldn't stop me enjoying a hobby surely? After a few failed attempts I was hoping someone else out there could help so here's the situation. I'm trying to implement a bit of faked intelligence when the A.I fires it's missiles at a target in a 2D game world. By predicting the likely position the target will be in given it's current velocity and the time it will take the missile to reach it's target. I created an image to demonstrate my thinking: http://i.imgur.com/SFmU3.png which also contains the logic I use for accelerating the missile after launch. The ship that fires the missile can fire within a total of 40 degree angle, 20 either side of itself, but this could likely become variable. My current attempt was to break the space between the two lines into segments which match the targets width. Then calculate the time it would take the missile to get to that location using the formula. So for each iteration of this we total up the values and that tells us the distance travelled, ad it would then just need compared to distance to the segment. startVelocity * ((startVelocity * acceleration)^(currentframe-1) So for example. If we start at a velocity of 1f/frame with an acceleration of 0.1f the formula, at frame 4, would be 1 * (1.1^3) = 1.331 But I quickly realized I was getting lost when trying to put this into practice. Does this seem like a correct starting point or am I going completely the wrong way about it? Any pointers would help me greatly. Maths really isn't my strong suit so I get easily lost in these matters and don't even really know a good phrase to search for with this. So I guess in summary my question is more about the correct way to approach this problem and any additional code samples on top of that would be great but I'm not averse to working out the complete code from helpful pointers.

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• How to add display resolution fo an LCD in Ubuntu 12.04? xrandr problem

  - by SeregaI

  I am fresh for Ubuntu and Linux in general. I have installed Ubuntu 12.04 and stuck trying to setup correct resolution for my LCD display. The native resolution for the LCD is 1920x1080 here is the output from xrandr: $xrandr Screen 0: minimum 320 x 200, current 1280 x 720, maximum 4096 x 4096 LVDS1 connected 1280x720+0+0 (normal left inverted right x axis y axis) 0mm x 0mm 1280x720 60.0*+ 800x600 60.3 56.2 640x480 59.9 VGA1 disconnected (normal left inverted right x axis y axis) Then I create new modeline: $ cvt 1920 1080 60 1920x1080 59.96 Hz (CVT 2.07M9) hsync: 67.16 kHz; pclk: 173.00 MHz Modeline "1920x1080_60.00" 173.00 1920 2048 2248 2576 1080 1083 1088 1120 -hsync +vsync So far so good. then I create new mode using xrandr: $ xrandr --newmode "1920x1080_60.00" 173.00 1920 2048 2248 2576 1080 1083 1088 1120 -hsync +vsync But for some reason that new mode was created for VGA (VGA1) output instead of LCD output (LVDS1): $ xrandr Screen 0: minimum 320 x 200, current 1280 x 720, maximum 4096 x 4096 LVDS1 connected 1280x720+0+0 (normal left inverted right x axis y axis) 0mm x 0mm 1280x720 60.0*+ 800x600 60.3 56.2 640x480 59.9 VGA1 disconnected (normal left inverted right x axis y axis) 1920x1080_60.00 (0xbc) 173.0MHz <---------- ????!!!!!! h: width 1920 start 2048 end 2248 total 2576 skew 0 clock 67.2KHz v: height 1080 start 1083 end 1088 total 1120 clock 60.0Hz So, if I try to add mode to LVDS1, I get an error: $ xrandr --addmode LVDS1 "1920x1080_60.00" X Error of failed request: BadMatch (invalid parameter attributes) Major opcode of failed request: 149 (RANDR) Minor opcode of failed request: 18 (RRAddOutputMode) Serial number of failed request: 25 Current serial number in output stream: 26 Adding that new mode to VGA1 works fine, but I don't use that VGA1 output.

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• C++ Succinctly now available!

  - by Michael B. McLaughlin

  Over the summer I worked with SyncFusion to create an eBook based off of my C# to C++ guide for their free Succinctly Series of eBooks. Today the result, C++ Succinctly, was published for download. It is a free (registration required; they make tools and libraries for .NET development so you might get an occasional email from them – I’ve been signed up for a few months and have had maybe 3 emails total so it’s not horrible super spam or anything ) and you can download it as a PDF or a Kindle .MOBI file (or both). I’m excited with how it turned out and enjoyed working with the people at SyncFusion. The book contains a total of 20 code samples, which you can download from BitBucket (there’s a link very early in the book). Almost all of the code is also inline in the book itself so that you don’t need to worry about flipping back and forth between your dev machine and your eReader (but if you want to try to understand a concept better, you can easily download the code, open it up in VS 2012, and play around with it to see what happens when you tinker with things). The code does require Visual Studio 2012 because of its expanded support for C++11 features and since I wrote all of the samples as Console programs for clarity and compactness, you will need a version that supports C++ desktop development (currently VS 2012 Pro, Premium, or Ultimate). Sometime this Fall, Microsoft will be releasing Visual Studio 2012 Express for Windows Desktop which should provide a free way to use the samples. That said, I tested all of the samples with MinGW and only the StorageDurationSample will not compile with it due to the thread-local storage code. If you comment that out then you can compile and run all the samples with MinGW (or using a recent version of GCC in a GNU/Linux environment, or any other C++ compiler that provides the same level of C++11 support that Visual Studio 2012 does). I hope it proves helpful to those of you who choose to check it out!

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• SEO and internal links

  - by hanazair

  I'm fairly new to SEO and although I've read many articles on the topic I still don't have a clear idea of how to get my client's website get to the first page of Google Search. I run MOZ competitor analysis and see that a competitor that comes up at the top of Google Search has approximately same Domain Authority, Domain Moz Rank and Trust. They have 8 External Linking Root Domains while my client's site has five. Yet the competitor comes up as one of the top sites on the first page, and my client's side is on page #3. Then I noticed one drastic difference in competitor's ranking and that is Total Links. He has 1,388! I don't understand how this could be a positive factor in Search Engine ranking and how can they legitimately have 1,388 links (while only 14 of those are external). Another competitor who is #2 in search engine rankings has 773 links total with only 14 external links. It seems fishy, but yet there they are - at the top of the search engine results. Is that some current way to trick Search Engines? What to do if I'd like to get my client's website onto the first page by some legitimate means? Thanks.

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• PeopleSoft CRM 9.2 Release Value Proposition

  - by Race Bannon

  Oracle's PeopleSoft Customer Relationship Management (CRM) delivers solutions that have been tailored to fit your industry business processes, your customer strategies, and your success criteria. With PeopleSoft CRM 9.2, organizations will be able to deploy a solution that delivers built-in best practices specific to your industry with a highly configurable, tightly integrated platform, ensuring that solutions will be fast to implement. The result is less configuration, less customization, and less integration. PeopleSoft Customer Relationship Management (CRM) is a world-class solution for organizations of every size and Oracle’s planned product roadmap for PeopleSoft applications is to deliver valuable, needed features for all of an organization’s constituents along three design principles — Simplicity, Productivity, and Lowered Total Cost of Ownership — as well as new application functionality as prioritized by our customers. The upcoming 9.2 release of PeopleSoft Customer Relationship Management focuses on these themes of Simplicity, Productivity, and Lower Total Cost of Ownership while also delivering robust new functionality to help your organization succeed. The recently published PeopleSoft CRM 9.2 Release Value Proposition provides overviews of the new features and enhancements planned for these applications for Release 9.2. This document offers customers a road map intended to help them assess the business benefits of upgrading to the 9.2 release while also helping them plan their IT projects and investments. (Link is to a My Oracle Support page, available to customers and partners.) Oracle continues to deliver enterprise-wide features that enhance our customer ownership experience and helps them run their businesses more efficiently and profitably. With the CRM 9.2 release, we continue to abide by this firm commitment we’ve made to our customers.

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• Show and Tell: What work are you the most proud of? [closed]

  - by dannywartnaby

  Hey, In the spirit of building community, and because it's always cool to see great work being pushed out and created by people, anyone up for a little show and tell? The rules are really simple, and this is supposed to be a bit of fun, so; post a link to a single piece of work (anything you've produced, designed or developed (or helped developed)) and write a little paragraph or two on what it is, what you like about it, the technology you used and perhaps one thing that you learnt from the project. It could be a website, framework, open source project, game, mobile application... etc. So, allow me to start. I'm personally very proud of a tiny iPhone application I designed and developed. It's only available to UK AppStore users, and I only have a small userbase, but, I like it. The application is called Sushi Total: http://knowledgeisporridge.com/sushitotal.html It's written in Objective-C. It's a very simply application that allows you to total up your bill at Yo Sushi restaurants by tapping coloured plates. If I learnt anything from making this application it's this: I believe software should be simple and uncluttered, and that producing an application with one feature is absolutely fine as long as it works really well. So, who's next?

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• Where ORMs blur the lines between code and data, how do you decide what logic should be a stored procedure, and what should be coded?

  - by PhonicUK

  Take the following pseudocode: CreateInvoiceAndCalculate(ItemsAndQuantities, DispatchAddress, User); And say CreateInvoice does the following: Create a new entry in an Invoices table belonging to the specified User to be sent to the given DispatchAddress. Create a new entry in an InvoiceItems table for each of the items in ItemsAndQuantities, storing the Item, the Quantity, and the cost of the item as of now (by looking it up from an Items table) Calculate the total amount of the invoice (ex shipping and taxes) and store it in the new Invoice row. At a glace you wouldn't be able to tell if this was a method in my applications code, or a stored procedure in the database that is being exposed as a function by the ORM. And to some extent it doesn't really matter. Now technically none of this is business logic. You're not making any decisions - just performing a calculation and creating records. However some may argue that because you are performing a calculation that affects the business (the total amount to be invoiced) that this isn't something that should be done in a stored procedure and instead should be in code. So for this specific example - why would it be more appropriate to do one or the other? And where do you draw the line? Or does it even particular matter as long as it's sufficiently well documented?

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• What is the recommended MongoDB schema for this quiz-engine scenario?

  - by hughesdan

  I'm working on a quiz engine for learning a foreign language. The engine shows users four images simultaneously and then plays an audio file. The user has to match the audio to the correct image. Below is my MongoDB document structure. Each document consists of an image file reference and an array of references to audio files that match that image. To generate a quiz instance I select four documents at random, show the images and then play one audio file from the four documents at random. The next step in my application development is to decide on the best document schema for storing user guesses. There are several requirements to consider: I need to be able to report statistics at a user level. For example, total correct answers, total guesses, mean accuracy, etc) I need to be able to query images based on the user's learning progress. For example, select 4 documents where guess count is 10 and accuracy is <=0.50. The schema needs to be optimized for fast quiz generation. The schema must not cause future scaling issues vis a vis document size. Assume 1mm users who make an average of 1000 guesses. Given all of this as background information, what would be the recommended schema? For example, would you store each guess in the Image document or perhaps in a User document (not shown) or a new document collection created for logging guesses? Would you recommend logging the raw guess data or would you pre-compute statistics by incrementing counters within the relevant document? Schema for Image Collection: _id "505bcc7a45c978be24000005" date 2012-09-21 02:10:02 UTC imageFileName "BD3E134A-C7B3-4405-9004-ED573DF477FE-29879-0000395CF1091601" random 0.26997075392864645 user "2A8761E4-C13A-470E-A759-91432D61B6AF-25982-0000352D853511AF" audioFiles [ 0 { audioFileName "C3669719-9F0A-4EB5-A791-2C00486665ED-30305-000039A3FDA7DCD2" user "2A8761E4-C13A-470E-A759-91432D61B6AF-25982-0000352D853511AF" audioLanguage "English" date 2012-09-22 01:15:04 UTC } 1 { audioFileName "C3669719-9F0A-4EB5-A791-2C00486665ED-30305-000039A3FDA7DCD2" user "2A8761E4-C13A-470E-A759-91432D61B6AF-25982-0000352D853511AF" audioLanguage "Spanish" date 2012-09-22 01:17:04 UTC } ]

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• Database Insider - December 2012 issue

  - by Javier Puerta

  The December issue of the Database Insider newsletter is now available. (Full newsletter here) Big Data: From Acquisition to Analysis 2012 will likely be remembered as the year of big data, as a new generation of technologies enables organizations to acquire, organize, and analyze the exponentially growing and typically less-structured data generated from a variety of new sources. Oracle has produced a series of five short videos that offer a quick and compelling high-level introduction to big data. Read More Total Cost of Ownership Comparison: Oracle Exadata vs. IBM P-Series Read the research that found that over three years, the IBM hardware running Oracle Database cost 31 percent more in total cost of ownership than Oracle Exadata. Webcast - Oracle Exadata Database Machine X3 Learn about Oracle’s next-generation database machine, Oracle Exadata X3, that combines massive memory and low-cost disks to deliver the highest performance at the lowest cost. Available in an eight-rack configuration, it allows you to start small and grow.    Maximum Availability with Oracle GoldenGate Discover how to eliminate not only unplanned downtime but also planned downtime resulting from database upgrades, migrations, and consolidation.Thursday, December 1319:00 CET / 6 pm. UK   

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• How can I get rid of the motd message "*** /dev/sdb1 will be checked for errors at next reboot ***"? [duplicate]

  - by kmm

  This question already has an answer here: Persistent “disk will be checked…” in the message of the day (motd) even after reboot 3 answers My motd persistently has: *** /dev/sdb1 will be checked for errors at next reboot *** The problem is that I don't have /dev/sdb1 on my system. I only have /dev/sdb2 (mouted as /) and /dev/sda1 which mounts to /media/backup. I delete that line from /etc/motd, but it reappears after reboot. Here's my df output: Filesystem Size Used Avail Use% Mounted on /dev/sdb2 73G 3.7G 66G 6% / udev 490M 4.0K 490M 1% /dev tmpfs 200M 760K 199M 1% /run none 5.0M 0 5.0M 0% /run/lock none 498M 0 498M 0% /run/shm /dev/sda1 1.9T 429G 1.4T 25% /media/backup Update Here is the output of sudo fdisk -l Disk /dev/sda: 2000.4 GB, 2000398934016 bytes 255 heads, 63 sectors/track, 243201 cylinders, total 3907029168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x0003dfc2 Device Boot Start End Blocks Id System /dev/sda1 63 3907024064 1953512001 83 Linux Disk /dev/sdb: 80.0 GB, 80026361856 bytes 255 heads, 63 sectors/track, 9729 cylinders, total 156301488 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00049068 Device Boot Start End Blocks Id System /dev/sdb1 152301568 156301311 1999872 82 Linux swap / Solaris /dev/sdb2 * 2048 152301567 76149760 83 Linux Partition table entries are not in disk order I guess /dev/sdb1 is my swap space.

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• How do I get 12.04 to recognize swap partition so that I can hibernate?

  - by Kayla

  I justed installed 12.04 and used gparted to erase and enlarge my swap partition. When I rebooted, gparted said that the file partition for the swap was unknown. Gparted doesn't let me change the file partition to "linux-swap". It does let me change it to NTFS, but when I reboot, it goes back to "unknown". Thanks in advance for your help. Output from sudo swapon -s: Filename Type Size Used Priority /dev/mapper/cryptswap1 partition 9025532 0 -1 Output from sudo fdisk -l: Disk /dev/sda: 250.1 GB, 250059350016 bytes 255 heads, 63 sectors/track, 30401 cylinders, total 488397168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x9d63ac84 Device Boot Start End Blocks Id System /dev/sda1 * 2048 2459647 1228800 7 HPFS/NTFS/exFAT /dev/sda2 2459648 197836472 97688412+ 7 HPFS/NTFS/exFAT /dev/sda3 466890752 488395119 10752184 7 HPFS/NTFS/exFAT /dev/sda4 197836798 466890751 134526977 5 Extended /dev/sda5 197836800 448837631 125500416 83 Linux /dev/sda6 448839680 466890751 9025536 82 Linux swap / Solaris Partition table entries are not in disk order Disk /dev/mapper/cryptswap1: 9242 MB, 9242148864 bytes 255 heads, 63 sectors/track, 1123 cylinders, total 18051072 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x951b7f53 Disk /dev/mapper/cryptswap1 doesn't contain a valid partition table

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