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  • Syntax error for makecert.exe tool

    - by user340817
    Did I missed anything during this? I am running a this command from command prompt in Windows 7 to create a certificate but it is showing a syntax error. Command I ran: makecert.exe "c:\1\Test.cer" -a sha1 -n "CN=AppGuid" -sr LocalMachine -ss My -sky signature -pe -len 2048 Output I got: Usage: MakeCert [ basic|extended options] [outputCertificateFile] Basic Options -sk -ss -sr . . . Did I missed anything during this?

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  • Whats wrong with this code.Runtime error

    - by javacode
    Hi I am writing this application in eclipse I added all the jar files.I am pasting the code and error.Please let me know what changes I should make to run the application properly. import javax.mail.*; import javax.mail.internet.*; import java.util.*; public class SendMail { public static void main(String [] args) { SendMail sm=new SendMail(); try{ sm.postMail(new String[]{"[email protected]"},"hi","hello","[email protected]"); } catch(MessagingException e) { e.printStackTrace(); } } public void postMail( String recipients[ ], String subject, String message , String from) throws MessagingException { boolean debug = false; //Set the host smtp address Properties props = new Properties(); props.put("mail.smtp.starttls.enable","true"); props.put("mail.smtp.host", "smtp.gmail.com"); props.setProperty("mail.smtp.port", "25"); // create some properties and get the default Session Session session = Session.getDefaultInstance(props, null); session.setDebug(debug); // create a message Message msg = new MimeMessage(session); // set the from and to address InternetAddress addressFrom = new InternetAddress(from); msg.setFrom(addressFrom); InternetAddress[] addressTo = new InternetAddress[recipients.length]; for (int i = 0; i < recipients.length; i++) { addressTo[i] = new InternetAddress(recipients[i]); } msg.setRecipients(Message.RecipientType.TO, addressTo); // Optional : You can also set your custom headers in the Email if you Want msg.addHeader("MyHeaderName", "myHeaderValue"); // Setting the Subject and Content Type msg.setSubject(subject); msg.setContent(message, "text/plain"); Transport.send(msg); } } Error: com.sun.mail.smtp.SMTPSendFailedException: 530 5.7.0 Must issue a STARTTLS command first. 13sm646598ewy.13 at com.sun.mail.smtp.SMTPTransport.issueSendCommand(SMTPTransport.java:1829) at com.sun.mail.smtp.SMTPTransport.mailFrom(SMTPTransport.java:1368) at com.sun.mail.smtp.SMTPTransport.sendMessage(SMTPTransport.java:886) at javax.mail.Transport.send0(Transport.java:191) at javax.mail.Transport.send(Transport.java:120) at SendMail.postMail(SendMail.java:54) at SendMail.main(SendMail.java:10)

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  • How to make multiple queries with PHP prepared statements (Commands out of sync error)

    - by Tirithen
    I'm trying to run three MySQL queries from a PHP script, the first one works fine, but on the second one I get the "Commands out of sync; you can’t run this command now" error. I have managed to understand that I need to "empty" the resultset before preparing a new query but I can't seem to understand how. I thought that $statement-close; would do that for me. Here is the relevant part of the code: <?php $statement = $db_conn->prepare("CALL getSketches(?,?)"); // Prepare SQL routine to check if user is accepted $statement->bind_param("is", $user_id, $loaded_sketches); // Bind variables to send $statement->execute(); // Execute the query $statement->bind_result( // Set return varables $id, $name, $description, $visibility, $createdby_id, $createdby_name, $createdon, $permission ); $new_sketches_id = array(); while($statement->fetch()) { $result['newSketches'][$id] = array( "name" => $name, "description" => $description, "visibility" => $visibility, "createdById" => $createdby_id, "createdByName" => $createdby_name, "createdOn" => $createdon, "permission" => $permission ); $new_sketches_id[] = $id; } $statement->close; // Close satement $new_sketches_ids = implode(",", $new_sketches_id); // Get the new sketches elements $statement = $db_conn->prepare("CALL getElements(?,'',?,'00000000000000')"); // Prepare SQL routine to check if user is accepted // The script crashes here with $db_conn->error // "Commands out of sync; you can't run this command now" $statement->bind_param("si", $new_sketches_ids, $user_id); // Bind variables to send $statement->execute(); // Execute the query $statement->bind_result( // Set return varables $id, $user_id, $type, $attribute_d, $attribute_stroke, $attribute_strokeWidth, $sketch_id, $createdon ); while($statement->fetch()) { $result['newSketches'][$sketch_id]['newElements']["u".$user_id."e".$id] = array( "type" => $type, "d" => $attribute_d, "stroke" => $attribute_stroke, "strokeWidth" => $attribute_strokeWidth, ); } $statement->close; // Close satement ?> How can I make the second query without closing and reopening the entire database connection?

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  • Error trying to run rails server

    - by David87
    I am trying to get a basic Rails application to run on my Mac OS X 10.6.5. I created a new app called demo (rails new demo), then went into the demo directory and tried to start the app with rails server. Here is the error message I received: "/Users/dpetrovi/.gem/ruby/1.8/gems/sqlite3-ruby-1.3.2/lib/sqlite3/sqlite3_native.bundle: [BUG] Segmentation fault ruby 1.8.7 (2010-12-23 patchlevel 330) [i686-darwin10] Abort trap" I checked bundle install in the demo folder: "Using rake (0.8.7) Using abstract (1.0.0) Using activesupport (3.0.3) Using builder (2.1.2) Using i18n (0.5.0) Using activemodel (3.0.3) Using erubis (2.6.6) Using rack (1.2.1) Using rack-mount (0.6.13) Using rack-test (0.5.6) Using tzinfo (0.3.23) Using actionpack (3.0.3) Using mime-types (1.16) Using polyglot (0.3.1) Using treetop (1.4.9) Using mail (2.2.13) Using actionmailer (3.0.3) Using arel (2.0.6) Using activerecord (3.0.3) Using activeresource (3.0.3) Using bundler (1.0.7) Using thor (0.14.6) Using railties (3.0.3) Using rails (3.0.3) Using sqlite3-ruby (1.3.2) Your bundle is complete! Use bundle show [gemname] to see where a bundled gem is installed." Ruby, RubyGems, and sqlite3 were installed using MacPorts. Then I used gem to try to install the sqlite3-ruby interface. (sudo gem install sqlite3-ruby). Here is where I first noticed something could be off: "Successfully installed sqlite3-ruby-1.3.2 1 gem installed Installing ri documentation for sqlite3-ruby-1.3.2... No definition for libversion Enclosing class/module 'mSqlite3' for class Statement not known Installing RDoc documentation for sqlite3-ruby-1.3.2... No definition for libversion Enclosing class/module 'mSqlite3' for class Statement not known " I had rails running well on my system a few months ago, so I figured maybe I had some duplicates and it was trying to use the wrong one. I ran: "for cmd in ruby irb gem rake; do which $cmd; done" and got: "/opt/local/bin/ruby /opt/local/bin/irb /opt/local/bin/gem /opt/local/bin/rake" Checking where sqlite3 also gets me: "/opt/local/bin/sqlite3" so they all seem to be in the right place. Obviously /opt/local/bin is in my system path. If I check gems server, it shows that I have installed sqlite3-ruby 1.3.2 gem. Not sure what the problem could be? I am using ruby 1.8.7 (2010-12-23 patchlevel 330) [i686-darwin10]. Macports claims this is the latest (although ive seen 1.9.1) One more thing-- in irb, I tried to check which version of sqlite3 my sqlite3-ruby is bound to, but I can only get this far: ":irb(main):001:0 require 'rubygems' = true irb(main):002:0 require 'sqlite3' /Users/dpetrovi/.gem/ruby/1.8/gems/sqlite3-ruby-1.3.2/lib/sqlite3/sqlite3_native.bundle: [BUG] Segmentation fault ruby 1.8.7 (2010-12-23 patchlevel 330) [i686-darwin10] Abort trap" Any suggestions? Im hoping I overlooked something obvious. Thanks

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  • Browser error in IE 6?

    - by Surya sasidhar
    hi, i developed a project in that when when i click on any button it giving some message like.. sys.webforms.pagerequestmanagerservererrorexception:An unknown error occurred while processing the request on the status code returned from the server was:12019 it is especially in IE 7. it is working fine in firefox and IE 6. I have a doubt that when a system contain IE 6 and IE 7 this problem will get i think what do you say?. can u help me and this is my site

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  • SQL error with script to create

    - by PapaDaniel
    I used the SQL Server management studio on a table with Create Script to New and did minor changes. Give me an error "Incorrect syntax near '('" for the "(" after "WITH" /* EventType Table Creation */ CREATE TABLE [EventType] ( [pkEventID] [int] IDENTITY(1,1) NOT NULL, [Description] [nvarchar](50) NOT NULL, [BeginDate] [datetime] NOT NULL, [EndDate] [datetime] NOT NULL, [Comments] [nvarchar](500) NOT NULL, CONSTRAINT [PK_EventType] PRIMARY KEY CLUSTERED ( [pkEventID] ASC ) WITH ( PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON ) ON [PRIMARY] ) ON [PRIMARY] GO

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  • Upload a file to a web server in cocoa

    - by Cam
    Hello, I was wondering the best way to upload file to a web server in cocoa. I cant seem to get my curl code to work even though it works when run from terminal. curl code: system(@"curl -T /file.txt http://webserevertouploadto.com") Thanks for any help

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  • SubSonic error: db.tables with a ~ in the name result in a "Character is not valid" error

    - by Steven
    I renamed a database table and added a ~ character to the table name (my way of notifying it is a backup of something). After generating the SubSonic files, my Visual Studio gives a "Character not valid" error on file "AllStructs.vb" When looking into this file the following line of code was generated; Public Shared ReadOnly DbTable1~old As String = "dbtable1~old". I assume this character has to be filtered out of the db.table names when generating the SubSonic names?

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  • Compile error while adding items to nested dictionary

    - by anshu
    I am trying to created nested dictionary variable like the below, But I get compile error stating that it needs "}" at line where I am adding items (line #2) to my nested dictionary. What Am I missing here? Thanks. Dim myNestedDictionary As Dictionary(Of String, Dictionary(Of String, Integer)) = New Dictionary(Of String, Dictionary(Of String, Integer))() myNestedDictionary.Add("A", New Dictionary("A", 4)())

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  • What exception is thrown if a web service i'm using Times Out?

    - by BT
    I'm calling a .NET web service within my existing .NET webservice, i would like to know what exception is thrown from the web method if timeout happens, i have set the web service timeout to some lower value then the default 90 sec. and want to add business logic if time out happens. Is this the exception i should be looking at? System.Net.WebException

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  • IE6 secure and nonsecure error - nothing in Fiddler/no iframes

    - by seengee
    Hi, I've got the issue of IE6 showing the "secure and nonsecure items" error on an SSL page. Looking into it though none of the usual causes seem to apply. There are no calls to http://, there are no iframes in the page, fiddler and httpfox both show only requests to https:// - what else can i check? In Firefox and IE there is nothing to suggest there is mixed content at all

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  • How can we receive a volume attaching notification

    - by Benjamin
    When a volume is attached to file system, on Windows, the Window explorer detects the volume and refreshes automatically. I wonder the technique. How do an program(include device driver) get the notification? -Of course, it doesn’t mean a polling. I want to get an event(or a message). I would like to get the notification when a network volume(like SMB) is attached. Thanks in advance.

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  • What is the best JSOS?

    - by JamesM
    What is the best JSOS (Javascript Operating System)? Here are some.. /* Remove the "x_" for the link, was needed so I can post this.. */ x_http://fractalbrain.net/ /* Best.. */ x_http://cometdesktop.com/ /* alright */ x_http://skylightproject.com/ /* Wrost */

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  • Zend_Search_Lucene range query error

    - by Maurice
    I have set up each document with a date field. (keyword) Values stored in it are in this format; 20100511 Each time I try to perform a ranged query, I get the following error: date:[10000000 TO 20000000] At least one range query boundary term must be non-empty term Anyone got a clue?

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  • error echo id when i want to echo id for edit

    - by Prasanta Baidya
    I have a entry and edit page of a branch, I want echo id, when I mouse over into edit link in edit button, its show error,: branchedit.php?id=Note:Undefined index:id in line 101, but it work properly in localhost. error picture page link : https://www.dropbox.com/s/i1vu62lz3pezia0/id%20error.JPG My code: <?php include 'include/config.php'; include 'include/opendb.php'; include 'loginheader.php'; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Branch</title> <!--Requered Validation --> <link rel="stylesheet" type="text/css" media="screen" href="jqueryvalidation/demo/css/screen.css" /> <script src="jqueryvalidation/jquery.js" type="text/javascript"></script> <script src="jqueryvalidation/jquery.validate.js" type="text/javascript"></script> <script type="text/javascript"> $(document).ready(function() { $("#commentForm").validate(); }); </script> <!--End Requered Validation --> <style type="text/css"> <!-- body { background-color: #cccccc; } --> </style> <style type="text/css"> <!-- --> </style> <link href="css/usercss.css" rel="stylesheet" type="text/css" /> <style type="text/css"> <!-- .style7 { color: #000000; font-weight: bold; } .style8 {color: #FFFFFF} --> </style> </head> <body> <div id="container"> <table width="453" border="0" align="left" cellpadding="0" cellspacing="1"> <tr> <td width="451"><form name="cmxform" id="commentForm" method="post" action="insert_ac.php"> <table width="100%" border="0" cellspacing="1" cellpadding="3"> <tr> <td colspan="3" class="style2">Insert Branch into Database </td> </tr> <tr> <td width="100" height="46">Branch Code</td> <td width="18">:</td> <td width="309"><input name="branch_code" type="text" id="branch_code" minlength="3" class="required"></td> </tr> <tr> <td height="51">Branch Name</td> <td>:</td> <td><input name="branch_name" type="text" id="branch_name" class="required" ></td> </tr> <tr> <td height="47" colspan="3" align="center"> <div align="right"> <input name="Submit" type="submit" class="submit_button" value="Submit" /> &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; </div></td> </tr> </table> </form></td> </tr> </table> <!--Branch List --> <?php $sql="SELECT * FROM dc_master"; $result=mysql_query($sql); ?> <table width="436" border="1" cellpadding="2" cellspacing="0" class="table" id="list"> <tr> <td colspan="4"><div align="center" class="style7">List of Branches </div></td> </tr> <tr class="style4" > <td width="87" align="center"><span class="style8">Branch Code</span></td> <td width="176" align="center" ><span class="style8">Branch Name</span></td> <td width="70" align="center" ><span class="style8">Edit</span></td> <td width="77" align="center" ><span class="style8">Delete</span></td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td height="28"><div align="center" class="style3"><?php echo $rows['branch_code']; ?></div></td> <td class="style3">&nbsp;&nbsp;&nbsp;<?php echo $rows['dc_name']; ?></td> <!--link to update.php and send value of id --> <td align="center"><a href="branchedit.php?id=<?php echo $rows['id']; ?>" class="style3 style5 style5">Edit</a></td> <td align="center"><a href="delete.php?id=<?php echo $rows['id']; ?>" class="style3 style5 style5" onclick="return confirm('Are you sure, you want to delete? (After delete you can not undo or get it again) <?php ?>')">Delete</a></td> </tr> <?php } ?> </table> <span class="footer">Programmer : Prasanta Baidya / Mobile : 09830980840 / Email id : [email protected]</span></div> <?php mysql_close(); ?> </body> </html>

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  • Datagridview error

    - by Simon
    I have two datagridviews. So for the second one, i just copy-pasted the code from the first and changed where the difference was. But i get an error at the secod data grid when i want to view the result of my sql code. Translated in english the error show something like that there was no value given to at least one required parameter. Please help! private void button1_Click(object sender, EventArgs e) { string connectionString = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=save.mdb"; try { database = new OleDbConnection(connectionString); database.Open(); date = DateTime.Now.ToShortDateString(); string queryString = "SELECT zivila.naziv,(obroki_save.skupaj_kalorij/zivila.kalorij)*100 as Kolicina_v_gramih " + "FROM (users LEFT JOIN obroki_save ON obroki_save.ID_uporabnika=users.ID)" + " LEFT JOIN zivila ON zivila.ID=obroki_save.ID_zivila " + " WHERE users.ID= " + a.ToString(); loadDataGrid(queryString); } catch (Exception ex) { MessageBox.Show(ex.Message); return; } } public void loadDataGrid(string sqlQueryString) { OleDbCommand SQLQuery = new OleDbCommand(); DataTable data = null; dataGridView1.DataSource = null; SQLQuery.Connection = null; OleDbDataAdapter dataAdapter = null; dataGridView1.Columns.Clear(); // <-- clear columns SQLQuery.CommandText = sqlQueryString; SQLQuery.Connection = database; data = new DataTable(); dataAdapter = new OleDbDataAdapter(SQLQuery); dataAdapter.Fill(data); dataGridView1.DataSource = data; dataGridView1.AllowUserToAddRows = false; dataGridView1.ReadOnly = true; dataGridView1.Columns[0].Visible = true; } private void Form8_Load(object sender, EventArgs e) { } private void button2_Click(object sender, EventArgs e) { string connectionString = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=save.mdb"; try { database = new OleDbConnection(connectionString); database.Open(); date = DateTime.Now.ToShortDateString(); string queryString = "SELECT skupaj_kalorij " + "FROM obroki_save " + " WHERE users.ID= " + a.ToString(); loadDataGrid2(queryString); } catch (Exception ex) { MessageBox.Show(ex.Message); return; } } public void loadDataGrid2(string sqlQueryString) { OleDbCommand SQLQuery = new OleDbCommand(); DataTable data = null; dataGridView2.DataSource = null; SQLQuery.Connection = null; OleDbDataAdapter dataAdapter = null; dataGridView2.Columns.Clear(); // <-- clear columns SQLQuery.CommandText = sqlQueryString; SQLQuery.Connection = database; data = new DataTable(); dataAdapter = new OleDbDataAdapter(SQLQuery); dataAdapter.Fill(data); dataGridView2.DataSource = data; dataGridView2.AllowUserToAddRows = false; dataGridView2.ReadOnly = true; dataGridView2.Columns[0].Visible = true; }

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  • Visual studio build error

    - by msfanboy
    Hello, I have selected in VS2010 RC the option create Project from existing code after adding all references and building the stuff I got about 10 of those errors: Error 1 Source file 'obj\x86\Debug\View\FormatButtonBarUC.g.i.cs' could not be found E:\TBM\TBM\CSC How can I fix that?

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