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• stored as array understanding mongoid

  - by Gagan

  Hello frens, This is not a problem, but I just want to know stored as array of Mongoid better. I have following code in my model. class Company include Mongoid::Document include Mongoid::Timestamps references_many :people, :stored_as => :array, :inverse_of => :companies end class Person include Mongoid::Document include Sunspot::Mongoid references_many :companies, :stored_as => :array, :inverse_of => :people end Now in Company object we get person_ids as a result of stored_as array and company_ids in Person object. Now initially I inserted lots of person in company and the ids in person_ids fields is huge. Now I deleted most of person from company down to 8 people. Now I don't get why person_ids fields of Company object storing all the deleted ids of person. My console snapshot is follwing ruby-1.9.2-head Company.first.person_ids = [BSON::ObjectId('4d12d2907adf350695000025'), BSON::ObjectId('4d12d2907adf35069500002c'), BSON::ObjectId('4d12d2907adf350695000035'), BSON::ObjectId('4d12d2907adf35069500003f'), BSON::ObjectId('4d12d2907adf350695000048'), BSON::ObjectId('4d12d2907adf350695000052'), BSON::ObjectId('4d12d2907adf350695000059'), BSON::ObjectId('4d12d2907adf350695000062'), BSON::ObjectId('4d12d4017adf35069500008d'), BSON::ObjectId('4d12d4017adf350695000094'), BSON::ObjectId('4d12d4017adf35069500009d'), BSON::ObjectId('4d12d4017adf3506950000a7'), BSON::ObjectId('4d12d4017adf3506950000b0'), BSON::ObjectId('4d12d4017adf3506950000ba'), BSON::ObjectId('4d12d4017adf3506950000c1'), BSON::ObjectId('4d12d4017adf3506950000ca'), BSON::ObjectId('4d12d48a7adf3506950000f5'), BSON::ObjectId('4d12d48a7adf3506950000fc'), BSON::ObjectId('4d12d48a7adf350695000108'), BSON::ObjectId('4d12d48b7adf350695000115'), BSON::ObjectId('4d12d48b7adf350695000121'), BSON::ObjectId('4d12d48b7adf35069500012e'), BSON::ObjectId('4d12d48b7adf350695000135'), BSON::ObjectId('4d12d48b7adf350695000141'), BSON::ObjectId('4d12d53e7adf35069500016f'), BSON::ObjectId('4d12d53e7adf350695000176'), BSON::ObjectId('4d12d53e7adf350695000182'), BSON::ObjectId('4d12d53e7adf35069500018f'), BSON::ObjectId('4d12d53e7adf35069500019b'), BSON::ObjectId('4d12d53f7adf3506950001a8'), BSON::ObjectId('4d12d53f7adf3506950001af'), BSON::ObjectId('4d12d53f7adf3506950001bb'), BSON::ObjectId('4d12d8587adf3506950001e9'), BSON::ObjectId('4d12d8587adf3506950001f0'), BSON::ObjectId('4d12d8587adf3506950001ff'), BSON::ObjectId('4d12d8597adf35069500020f'), BSON::ObjectId('4d12d8597adf35069500021e'), BSON::ObjectId('4d12d8597adf35069500022e'), BSON::ObjectId('4d12d8597adf350695000235'), BSON::ObjectId('4d12d85a7adf350695000244'), BSON::ObjectId('4d12d9587adf35069500025b'), BSON::ObjectId('4d12db8b7adf35069500026a'), BSON::ObjectId('4d12de6f7adf3509c9000024'), BSON::ObjectId('4d12de6f7adf3509c900002b'), BSON::ObjectId('4d12de6f7adf3509c900003a'), BSON::ObjectId('4d12de707adf3509c900004a'), BSON::ObjectId('4d12de707adf3509c9000059'), BSON::ObjectId('4d12de707adf3509c9000069'), BSON::ObjectId('4d12de707adf3509c9000070'), BSON::ObjectId('4d12de717adf3509c900007f'), BSON::ObjectId('4d12e7f27adf350bd2000009'), BSON::ObjectId('4d12e81f7adf350bd2000015'), BSON::ObjectId('4d12e87f7adf350bd2000024'), BSON::ObjectId('4d12e8b87adf350bd200004c'), BSON::ObjectId('4d12e8b97adf350bd2000053'), BSON::ObjectId('4d12e8b97adf350bd200005c'), BSON::ObjectId('4d12e8b97adf350bd2000066'), BSON::ObjectId('4d12e8b97adf350bd200006f'), BSON::ObjectId('4d12e8b97adf350bd2000079'), BSON::ObjectId('4d12e8ba7adf350bd2000080'), BSON::ObjectId('4d12e8ba7adf350bd2000089'), BSON::ObjectId('4d12ee6b7adf350bd2000198'), BSON::ObjectId('4d12ee6b7adf350bd200019f'), BSON::ObjectId('4d12ee6c7adf350bd20001a5'), BSON::ObjectId('4d12ee6c7adf350bd20001ac'), BSON::ObjectId('4d12ee6c7adf350bd20001b2'), BSON::ObjectId('4d12ee6c7adf350bd20001b9'), BSON::ObjectId('4d12ee6c7adf350bd20001c0'), BSON::ObjectId('4d12ee6c7adf350bd20001c6'), BSON::ObjectId('4d141ca57adf35033e00006e'), BSON::ObjectId('4d141ca57adf35033e000075'), BSON::ObjectId('4d1420aa7adf350705000003'), BSON::ObjectId('4d1420aa7adf35070500000a'), BSON::ObjectId('4d1420f47adf350705000011'), BSON::ObjectId('4d1420f57adf350705000015'), BSON::ObjectId('4d1420f57adf350705000018'), BSON::ObjectId('4d1420f57adf35070500001c'), BSON::ObjectId('4d1420f57adf350705000023'), BSON::ObjectId('4d1420f57adf350705000026'), BSON::ObjectId('4d14215f7adf35070500004b'), BSON::ObjectId('4d14215f7adf350705000052'), BSON::ObjectId('4d14215f7adf350705000055'), BSON::ObjectId('4d14215f7adf350705000059'), BSON::ObjectId('4d14215f7adf35070500005c'), BSON::ObjectId('4d14215f7adf350705000060'), BSON::ObjectId('4d14215f7adf350705000067'), BSON::ObjectId('4d14215f7adf35070500006a')] Company.first.people.collect(&:id) = [BSON::ObjectId('4d14215f7adf35070500004b'), BSON::ObjectId('4d14215f7adf350705000052'), BSON::ObjectId('4d14215f7adf350705000055'), BSON::ObjectId('4d14215f7adf350705000059'), BSON::ObjectId('4d14215f7adf35070500005c'), BSON::ObjectId('4d14215f7adf350705000060'), BSON::ObjectId('4d14215f7adf350705000067'), BSON::ObjectId('4d14215f7adf35070500006a')] Isn't the Company.first.person_ids array be only storing the ids shown by Company.first.people.collect(&:id) It would be helpful if some one tell me when to best use stored_as = :array method. Do stored_as = :array increase querying performance? Thanks

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• SQL Server Select Distinct

  - by homam

  I want to write a query like this: For a table that has these columns: ColA ColB ColC, ColD select first(ColA, ColB, ColC, ColD) distinct(ColB, ColC) from table order by ColD The query is supposed to order the table by ColD, then group the results by the combination of ColB and ColC (they may have different data types) and returns the first rows (with all the columns of the table) in the groups. How is it possible in MS SQL Server 2005?

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• I don't find the sql request

  - by user301089

  Hi everybody, Here it's my problem I've a list of the following measure : src1 dst2 24th december 2009 src1 dst3 22th december 2009 src1 dst2 18th december 2009 I would like to have just the latest measures with a sql request - 2 first lines in my case because the pairs(src and dst) aren't the same. I try to use DISTINCT but I have just the 2 first columns and I will all columns. I try too GROUP BY but I hadn't success. Anyone can help me ? Thx Narglix

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• VB.net Reading from ListViews with Multiple Columns

  - by xzerox

  Alright. So I was able to find out how to read from the first column but I need to read from both of them. I am using full row select which I need on there. Here is the code I am using to get it for the first column. Dim I As Integer For I = 0 To ListView1.SelectedItems.Count - 1 MsgBox(ListView1.SelectedItems(I).Text) Next MessageBox.Show(ListView1.Columns(0).Text)

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• How to label each equation in align environment?

  - by Tim

  Hi, I wonder how to label each equation in align environment? For example \begin{align} \label{eq:lnnonspbb} \lambda_i + \mu_i = 0 \\ \mu_i \xi_i = 0 \\ \lambda_i [y_i( w^T x_i + b) - 1 + \xi_i] = 0 \end{align} only label the first equation and only the first equation can be referred later. Thanks and regards!

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• Creating an intro followed by a loop

  - by voodoo555

  Hey everybody, I just recorded some song and cut it into two parts. The first part contains an intro and the second is supposed to loop. What I want to do now, is to have a simple graphical animation (5 keyframes or so) that loops as well, while the music plays along. There's probably a simple solution to it, when you're familiar with AS. Unfortunately this is the first thing I've ever tried to do with Flash. I'm using Flash CS4. Greetings

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• jQuery, Hiding elements on ready is always jumping on page load. how can this be avoided?

  - by adardesign

  This is the code. I can't apply display:none; $(document).ready(function() { $("#LeftNav li.navCatHead").not(":first").siblings("li").hide().end().end().first().addClass("open"); });

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• UIKeyboard slides from wrong coordinates when in landscape, why?

  - by Horatiu Paraschiv

  Hi I have an app that starts in Landscape Right mode. When I tap a textField the keyboard should slide up, however first time when the keyboard slides it slides from the right (where the home button is). After that it slides up and down as expected. So only the first time when I call the keyboard in it comes from where it would come if the app would be in portrait mode. Does anyone know how can I fix this?

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• Reading and writing to/from memory in Python

  - by Honza Pokorny

  Let's imagine a situation: I have two Python programs. The first one will write some data (str) to computer memory, and then exit. I will then start the second program which will read the in-memory data saved by the first program. Is this possible?

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• Induction of graduate programmers

  - by spong

  What are some practical ideas that you have found useful for bringing graduates on to your team in their first job? Some of the things that are working well for us include: Assigning a mentor to assist the learning process Written coding standards/guidelines Spending a period of time with the test team to learn the product Where possible, a broad range of experiences in the first few months Anything else that works well for you? A related question can be found here.

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• XNA/C# Game Settings (Menu?)

  - by PCAddict

  It's my first time trying to make anything really interesting in C# and I was trying to make a simple form or game screen where the user could define a custom resolution/screen ratio etc. or to automatically detect the max screen size/ratio and output? its my first game, so I was wondering if it was possible or if there would be any major issues with such, rather than just setting it to 1366x768 (the resolution of all of my computers). Thanks in advance for any assistance.

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• JQuery: combine two jq selectors

  - by Bruno

  Hi there. Im sure the solution is simple but I cant figure it out :( I need to combine two jquery selectors in one selector: $(this) + $('input[type=text]:first') $(this) is e.g div#selected so the result should be: $('div#selected input[type=text]:first').focus(); How to do?

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• How can a new hire/intern make a good impression?

  - by Tristan

  In a week I start at my first real programming internship for a multinational company, I want to know, aside from "hard work" what can I do to prepare for this? How do I be a good new employee? (FYI, my first assignment is to help the team with "enhancements to our test driver to automate our regression testing" on an air traffic control system written in ADA)

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• Is there a straight forward way to append one PDF doc to another using iTextSharp?

  - by Danno

  I've scoured the Web looking for examples on how to do this. I've found a few that seem to be a little more involved then they need to be. So my question is, using iTextSharp, is there a fairly concise way to append one PDF document to another one? Optimally this would NOT involve a third file. Just open the first PDF doc, append the second PDF doc to the first and then close them both.

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• How do you stop RadioButtonList Label text from wrapping under the button

  - by Mark Dickinson

  I have a radio button list and some of the labels are quite long so they wrap and the second line appears underneath the radio button. Ideally I would like the text to wrap with the second line starting beneath the first character of the first line. Any ideas on how? or would I have to make my own list based control for this?

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• Use of HAVING in MySQL

  - by KBrian

  I have a table from which I need to select all persons that have a first name that is not unique and that that set should be selected only if among the persons with a similar first name, all have a different last name. Example: FirstN LastN Bill Clinton Bill Cosby Bill Maher Elvis Presley Elvis Presley Largo Winch I want to obtain FirstN LastN Bill Clinton or FirstN LastN Bill Clinton Bill Cosby Bill Maher I tried this but it does not return what I want. SELECT * FROM Ids GROUP BY FirstN, LastN HAVING (COUNT(FirstN)>1 AND COUNT(LastN)=1)) [Edited my post after Aleandre P. Lavasseur remark]

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• jQuery: Selector confusion

  - by JamesBrownIsDead

  What is wrong with this jQuery selector? $("#masterHeaderMenu.masterHeaderMenuButton a:first") I'm intending to select the first anchor tag that is a child of an element whose class is "masterHeaderMenuButton", itself a child of the element with an "id" attribute value of "masterHeaderMenu". Can't I do this in jQuery?

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• Removing contiguous duplicate lines in vi without sorting

  - by Dave Tapley

  This question already addresses how to remove duplicate lines, but enforces that the list is sorted first. I would like to perform the remove contiguous duplicate lines step (i.e. uniq) without first sorting them. Example before: Foo Foo Bar Bar Example after: Foo Bar

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• Java - strange problem storing text to a String[] and then storing the array to a Vector. Help plea

  - by hatboysam

  OK so for background I've only been using Java for a little more than a week and I am making a basic GUI "Recipe Book" application just to test out some of the techniques I've learned. Currently I'm working on the "Add New Recipe" page that allows the user to make a new recipe by adding ingredients one at a time. The ingredients have 3 attributes: Name, amount, and unit (like cups, oz, etc) that come from two text fields and a combo box respectively. The 3 values are stores as strings to a String array that represents the ingredient, then the arrays are stored in a vector that holds all of the ingredients for one recipe. When an ingredient is added, the user first types in the 3 necessary values into empty boxes/combo box dropdown and then clicks "Add Ingredient". Here is my code for when the button is clicked: public void actionPerformed(ActionEvent event) { Object source = event.getSource(); if (source == addIngredientButton) { //make sure 3 ingredient fields are not blank if (!ingredientNameField.getText().equals("") && !ingredientAmountField.getText().equals("") && !ingredientUnitDropdown.getSelectedItem().equals("")) { tempIngredientsArray[0] = ingredientNameField.getText(); //set ingredient name to first position in array tempIngredientsArray[1] = ingredientAmountField.getText(); //set ingredient amount to second position in array tempIngredientsArray[2] = (String) ingredientUnitDropdown.getSelectedItem(); //set ingredient unit to third position in array int ingredientsVectorSize = tempRecipe.ingredientsVector.size(); tempRecipe.ingredientsVector.add(this.tempIngredientsArray); //why would it matter if this and previous statement were switched for (int k = 0; k < ingredientsVectorSize + 1; k++ ) { liveIngredientsListArea.append("\n" + tempRecipe.makeIngredientSentence(k)); System.out.println(Arrays.toString(tempIngredientsArray)); //shows that tempIngredientsArray gets messed up each time } } Now here's the really strange problem I've been having. The first time the user adds an ingredient everything works fine. The second time, the String[] for that ingredient seems to be duplicated, and the third time it's triplicated. Aka the first time it runs the System.out.println might return "{Sugar, 3, Cups}" and the second time it will return "{Flour, 2, Oz.} {Flour, 2, Oz.}" etc. What's causing this strange problem? All help greatly appreciated, let me know if you need any clarification.

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• Quartz scheduler theadpool

  - by Shamik

  The SimpleThreadPool class shipped along with Quartz Scheduler does not have a FIFO behavior. I want to make sure if I keep adding jobs to the scheduler, they are addressed in a First - in - First - out basis. Is there any ThreadPool available for this ? Or is there any other way to achieve this?

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• Print Alternating Characters From Two Strings (Interleaving) Using Recursion Java

  - by babi2balla

  I'm trying to write a method that uses recursion to print the string formed by "interleaving" the strings str1 and str2. In other words, it should alternate characters from the two strings: the first character from str1, followed by the first character from str2, followed by the second character from str1, followed by the second character from str2, etc. How would I go about this? Any ideas are greatly appreciated!! Thanks

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• overriding previously-bound click events

  - by JamesBrownIsDead

  When I use this code with an element whose id is "foobar": $("#foobar").click(function () { alert("first"); }); $("#foobar").click(function () { alert("second"); }); I get two alerts: "first" and "second" second. How do I specify a click event that also clears out any previous click events attached to the element? I want the last $("#foobar").click(...) to erase any previously bound events.

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• Jquery recursive selector

  - by Mazzi

  Hi There, I have whole bunch of <div class="productlistname"><a href="#">The Text!</a></div>. What I want to do go through all .productlistname and truncate the text and replace the current text with the truncated version. Here is what I have so far: $(".productlistname a").html($(".productlistname a").html().substring(0,10)); This just truncate the first one and replaces the rest of .productlistname with the truncated version of the first one.

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• How can i scroll to an anchor on Datapager click?

  - by strakastroukas

  First of all, I have bound a datapager control to a listview. I would like to scroll to the first item of the listview control on the DataPager click. I guess by using javascript, but it seems that the datapager does not allow that... So what option do i have? How can i scroll, onto a specific anchor, when clicking on the DataPager?

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• Blackberry ListField Text Wrapping - only two lines.

  - by Diego Tori

  Within my ListField, I want to be able to take any given long String, and just be able to wrap the first line within the width of the screen, and just take the remaining string and display it below and ellipsis the rest. Right now, this is what I'm using to detect wrapping within my draw paint call: int totalWidth = 0; int charWidth = 0; int lastIndex = 0; int spaceIndex = 0; int lineIndex = 0; String firstLine = ""; String secondLine = ""; boolean isSecondLine = false; for (int i = 0; i < longString.length(); i++){ charWidth = Font.getDefault().getAdvance(String.valueOf(longString.charAt(i))); //System.out.println("char width: " + charWidth); if(longString.charAt(i) == ' ') spaceIndex = i; if((charWidth + totalWidth) > (this.getWidth()-32)){ //g.drawText(longString.substring(lastIndex, spaceIndex), xpos, y +_padding, DrawStyle.LEFT, w - xpos); lineIndex++; System.out.println("current lines to draw: " + lineIndex); /*if (lineIndex = 2){ int idx = i; System.out.println("first line " + longString.substring(lastIndex, spaceIndex)); System.out.println("second line " + longString.substring(spaceIndex+1, longString.length())); }*/ //firstLine = longString.substring(lastIndex, spaceIndex); firstLine = longString.substring(0, spaceIndex); //System.out.println("first new line: " +firstLine); //isSecondLine=true; //xpos = 0; //y += Font.getDefault().getHeight(); i = spaceIndex + 1; lastIndex = i; System.out.println("Rest of string: " + longString.substring(lastIndex, longString.length())); charWidth = 0; totalWidth = 0; } totalWidth += charWidth; System.out.println("total width: " + totalWidth); //g.drawText(longString.substring(lastIndex, i+1), xpos, y + (_padding*3)+4, DrawStyle.ELLIPSIS, w - xpos); //secondLine = longString.substring(lastIndex, i+1); secondLine = longString.substring(lastIndex, longString.length()); //isSecondLine = true; } Now this does a great job of actually wrapping any given string (assuming the y values were properly offsetted and it only drew the text after the string width exceeded the screen width, as well as the remaining string afterwards), however, every time I try to get the first two lines, it always ends up returning the last two lines of the string if it goes beyond two lines. Is there a better way to do this sort of thing, since I am fresh out of ideas?

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