Search Results

Search found 13303 results on 533 pages for 'position fixed'.

Page 468/533 | < Previous Page | 464 465 466 467 468 469 470 471 472 473 474 475  | Next Page >

  • "reset" cells after changing orientation

    - by Christian
    Hi, I added the interfaceOrientation to my app. It works fine concerning the views. Some of the table-cells I defined by CGRects to position the text in the cell. In portrait-mode the cell is 300px long, in landscape-mode 420px. I use the following code to change the CGRects depending the orientation: - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { if (self.interfaceOrientation == UIDeviceOrientationPortrait) { NSString *currentLanguage = [[NSString alloc] initWithContentsOfFile:[NSHomeDirectory() stringByAppendingPathComponent:@"/Documents/sprache.txt"]]; static NSString *TableViewTableCellIdentifier = @"TableViewTableCellIdentifier"; UITableViewCell *cell = (UITableViewCell *) [tableView dequeueReusableCellWithIdentifier:TableViewTableCellIdentifier]; CGRect cellRect = CGRectMake(0, 0, 300, 175); cell.backgroundColor = [UIColor darkGrayColor]; cell = [[[UITableViewCell alloc] initWithFrame:cellRect reuseIdentifier:TableViewTableCellIdentifier] autorelease]; CGRect keyLabelRect = CGRectMake(0, 5, 5, 20); UILabel *keyLabel = [[UILabel alloc]initWithFrame:keyLabelRect]; keyLabel.tag = 100;......... } else { NSString *currentLanguage = [[NSString alloc] initWithContentsOfFile:[NSHomeDirectory() stringByAppendingPathComponent:@"/Documents/sprache.txt"]]; static NSString *TableViewTableCellIdentifier = @"TableViewTableCellIdentifier"; UITableViewCell *cell = (UITableViewCell *) [tableView dequeueReusableCellWithIdentifier:TableViewTableCellIdentifier]; CGRect cellRect = CGRectMake(0, 0, 450, 175); cell.backgroundColor = [UIColor darkGrayColor]; cell = [[[UITableViewCell alloc] initWithFrame:cellRect reuseIdentifier:TableViewTableCellIdentifier] autorelease]; CGRect keyLabelRect = CGRectMake(0, 5, 5, 20); UILabel *keyLabel = [[UILabel alloc]..... My problem is, when the table is visible and the orientation is changed, I need to scroll to see the new "layout". How can I manage to "reload" the view after changing the orientation?

    Read the article

  • OpenGL fast texture drawing with vertex buffer objects. Is this the way to do it?

    - by Matthew Mitchell
    Hello. I am making a 2D game with OpenGL. I would like to speed up my texture drawing by using VBOs. Currently I am using the immediate mode. I am generating my own coordinates when I rotate and scale a texture. I also have the functionality of rounding the corners of a texture, using the polygon primitive to draw those. I was thinking, would it be fastest to make a VBO with vertices for the sides of the texture with no offset included so I can then use glViewport, glScale (Or glTranslate? What is the difference and most suitable here?) and glRotate to move the drawing position for my texture. Then I can use the same VBO with no changes to draw the texture each time. I could only change the VBO when I need to add coordinates for the rounded corners. Is that the best way to do this? What things should I look out for while doing it? Is it really fastest to use GL_TRIANGLES instead of GL_QUADS in modern graphics cards? Thank you for any answer.

    Read the article

  • Why is my Scala function returning type Unit and not whatever is the last line?

    - by Andy
    I am trying to figure out the issue, and tried different styles that I have read on Scala, but none of them work. My code is: .... val str = "(and x y)"; def stringParse ( exp: String, pos: Int, expreshHolder: ArrayBuffer[String], follow: Int ) var b = pos; //position of where in the expression String I am currently in val temp = expreshHolder; //holder of expressions without parens var arrayCounter = follow; //just counts to make sure an empty spot in the array is there to put in the strings if(exp(b) == '(') { b = b + 1; while(exp(b) == ' '){b = b + 1} //point of this is to just skip any spaces between paren and start of expression type if(exp(b) == 'a') { temp(arrayCounter) = exp(b).toString; b = b+1; temp(arrayCounter)+exp(b).toString; b = b+1; temp(arrayCounter) + exp(b).toString; arrayCounter+=1} temp; } } val hold: ArrayBuffer[String] = stringParse(str, 0, new ArrayBuffer[String], 0); for(test <- hold) println(test); My error is: Driver.scala:35: error: type mismatch; found : Unit required: scala.collection.mutable.ArrayBuffer[String] ho = stringParse(str, 0, ho, 0); ^one error found When I add an equals sign after the arguments in the method declaration, like so: def stringParse ( exp: String, pos: Int, expreshHolder: ArrayBuffer[String], follow: Int ) ={....} It changes it to "Any". I am confused on how this works. Any ideas? Much appreciated.

    Read the article

  • jquery delay a link from being followed

    - by Dan Sinker
    I have a short css-based animation that I want to play out before a link is followed (a card that swooped in on page load swoops out after click). Currently, however, the page called loads too quickly. I want to be able to briefly delay the href from being followed. Here's what I've got: $(document).ready(function() { $("#card").css("top","0px"); $(".clickit").click(function() { $("#card").css("top","-500"); }); }); The first line swoops the card in on page load. After that is the click call that modifies the CSS, but like I said there needs to be some kind of delay in there because the page loads immediately, instead of after the animation. The CSS that is modified looks like this: #card { width: 400px; height: 500px; position: relative; top: -500px; -webkit-transition:all .5s; } (yes, I know this is webkit-only right now) This is a problem very similar to this question from 2008, but I know jQuery has been updated significantly since then, so I wanted to see if there was a more modern solution. Thank you!

    Read the article

  • iphone - why is this flip animation using layers not working?

    - by Digital Robot
    I would like to make an animation that goes like this: imagine a picture sitting on a shelve. It drops from the shelve and as it falls it rotates along the horizontal axis and translates along the vertical axis. I would like to do this with perspective and the back side should be the image reversed, like the picture is a kind of slide. I have done this: CALayer* layer = myImageView.layer; layer.doubleSided = YES; CAKeyframeAnimation* animationTransform = [CAKeyframeAnimation animationWithKeyPath:@"transform"]; CATransform3D startTransform = CATransform3DIdentity; CATransform3D endTransform = CATransform3DTranslate (layer.transform, 0.0f, 200.0f, 0.0f); endTransform = CATransform3DRotate (endTransform, degreesToRadian(350.0f), 1.0f, 0.0f, 0.0f); endTransform.m34 = 1.0 / -500; NSArray *values = [NSArray arrayWithObjects: [NSValue valueWithCATransform3D:startTransform], [NSValue valueWithCATransform3D:endTransform], nil]; [animationTransform setValues:values]; NSArray *tempos = [NSArray arrayWithObjects: [NSNumber numberWithFloat:0.0f], [NSNumber numberWithFloat:0.7f], nil]; [animationTransform setKeyTimes:tempos]; NSArray *timing = [NSArray arrayWithObjects: [CAMediaTimingFunction functionWithName:kCAMediaTimingFunctionEaseInEaseOut], nil]; [animationTransform setTimingFunctions:timing]; animationTransform.fillMode = kCAFillModeRemoved; animationTransform.removedOnCompletion = YES; animationTransform.repeatCount = 1; animationTransform.duration = 3.7f; animationTransform.cumulative = YES; the result of this has nothing to do with anything. The result is: the image translates down an inch on the screen and then up half inch. Then it disappears and appears at its starting position again. What am I missing? thanks

    Read the article

  • View results of affine transform

    - by stckjp
    I am trying to find out the reason why when I apply affine transformations on an image in OpenCV, the result of it is not visible in the preview window, but the entire window is black.How can I find workaround for this problem so that I can always view my transformed image (the result of the affine transform) in the window no matter the applied transformation? Update: I think that this happens because all the transformations are calculated with respect to the origin of the coordinate system (top left corner of the image). While for rotation I can specify the center of the rotation, and I am able to view the result, when I perform scaling I am not able to control where the transformed image goes. Is it possible to somehow move the coordinate system to make the image fit in the window? Update2: I have an image which contains only ROI at some position in it (the rest of the image is black), and I need to apply a set of affine transforms on it. To make things simpler and to see the effect of each individual transform, I applied each transform one by one. What I noticed is that, whenever I move (translate) the image such that the center of the ROI is in the center of the coordinate system (top left corner of the view window), all the affine transforms perform correctly without moving. However, by translating the center of ROI at the center of the coordinate system, the upper and the left part of the ROI remain cut out of the current view window. If I move ROI's central point to another point in the view window (for example the window center), an affine transform of type: A=[a 0 0; 0 b 0] (A is 2x3 matrix, parameter of the warpAffine function) moves the image (ROI), outside of the view window (which doesn't happen if the ROI's center is in the top-left corner). How can I modify the affine transform so the image doesn't move out of its place (behaves the same way as when the ROI center is in the center of the coordinate system)?

    Read the article

  • String literal recognition problem

    - by helicera
    Hello! I'm trying to recognize string literal by reading string per symbol. Here is a sample code: #region [String Literal (")] case '"': // {string literal ""} { // skipping '"' ChCurrent = Line.ElementAtOrDefault<Char>(++ChPosition); while(ChCurrent != '"') { Value.Append(ChCurrent); ChCurrent = Line.ElementAtOrDefault<Char>(++ChPosition); if(ChCurrent == '"') { // "" sequence only acceptable if(Line.ElementAtOrDefault<Char>(ChPosition + 1) == '"') { Value.Append(ChCurrent); // skip 2nd double quote ChPosition++; // move position next ChCurrent = Line.ElementAtOrDefault<Char>(++ChPosition); } } else if(default(Char) == ChCurrent) { // message: unterminated string throw new ScanningException(); } } ChPosition++; break; } #endregion When I run test: [Test] [ExpectedException(typeof(ScanningException))] public void ScanDoubleQuotedStrings() { this.Scanner.Run(@"""Hello Language Design""", default(System.Int32)); this.Scanner.Run(@"""Is there any problems with the """"strings""""?""", default(System.Int32)); this.Scanner.Run(@"""v#:';?325;.<>,|+_)""(*&^%$#@![]{}\|-_=""", default(System.Int32)); while(0 != this.Scanner.TokensCount - 1) { Assert.AreEqual(Token.TokenClass.StringLiteral, this.Scanner.NextToken.Class); } } It passes with success.. while I'm expecting to have an exception according to unmatched " mark in this.Scanner.Run(@"""v#:';?325;.<>,|+_)""(*&^%$#@![]{}\|-_=""", default(System.Int32)); Can anyone explain where is my mistake or give an advice on algorithm.

    Read the article

  • Saving a single entity instead of the entire context - revisited

    - by nite
    I’m looking for a way to have fine grained control over what is saved using Entity Framework, rather than the whole ObjectContext.SaveChanges(). My scenario is pretty straight forward, and I’m quite amazed not catered for in EF – pretty basic in NHibernate and all other data access paradigms I’ve seen. I’m generating a bunch of data (in a WPF UI) and allowing the user to fine tune what is proposed and choose what is actually committed to the database. For the proposed entities I’m: getting a bunch of reference entities (eg languages) via my objectcontext, creating the proposed entities and assigning these reference entities to them (as navigation properties), so by virtue of their relationship to the reference entities they’re implicitly added to the objectconext Trying to create & save individual entites based on the proposed entities. I figure this should be really simple & trivial but everything I’ve tried I’ve hit a brick wall, either I set up another objectcontext & add just the entity I need (it then tries to add the whole graph and fails as it’s on another objectcontext). I’ve tried MergeOptions = NoTracking on my reference entities to try to get the Attach/AddObject not to navigate through these to create a graph, no avail. I've removed the navigation properties from the reference entities. I've tried AcceptAllChanges, that works but pretty useless in practice as I do still want to track & save other entities. In a simple test, I can create 2 of my proposed entities, AddObject the one I want to save and then Detach the one I dont then call SaveChanges, this works but again not great in practice. Following are a few links to some of the nifty ideas which in the end don’t help in the end but illustrate the complexity of EF for something so simple. I’m really looking for a SaveSingle/SaveAtomic method, and think it’s a pretty reasonable & basic ask for any DAL, letalone a cutting edge ORM. http://stackoverflow.com/questions/1301460/saving-a-single-entity-instead-of-the-entire-context www.codeproject.com/KB/architecture/attachobjectgraph.aspx?fid=1534536&df=90&mpp=25&noise=3&sort=Position&view=Quick&select=3071122&fr=1 bernhardelbl.spaces.live.com/blog/cns!DB54AE2C5D84DB78!238.entry

    Read the article

  • How to set gravity (or margins) of ImageView using code?

    - by mastojun
    Hi. I want to add ImageView to FrameLayout with Gravity or margins. but FramLayout and ImageView has no method about that(Actually, I can't found that). Reason that selects Framelayout is to put ImageView on ImageView. Help me plz. It is emergency for me to find solution. thx. Bellow is my code which help understanding my question. FrameLayout imageFrame = new FrameLayout(mContext); imageFrame.setLayoutParams(new GridView.LayoutParams(158, 158)); ImageView frame = new ImageView(mContext); frame = new ImageView(mContext); frame.setLayoutParams(new LayoutParams(158, 158)); frame.setScaleType(ImageView.ScaleType.CENTER_CROP); frame.setImageResource(R.drawable.image_frame_n); ImageView image = new ImageView(mContext); image.setLayoutParams(new LayoutParams(148, 148)); image.setScaleType(ImageView.ScaleType.CENTER_CROP); image.setImageResource(mThumbIds[position]); // image is needed to have a margin or gravity to be positioned at center imageFrame.addView(image); imageFrame.addView(frame);

    Read the article

  • TypeError when using v 0.8.1 of FLOT library, but no error with v. 0.7

    - by DanielAttard
    I need some help to figure out why I am getting an error when trying to create a simple graph using the jQuery FLOT library. When I reference version 0.7 of the FLOT library, the page renders correctly: http://attardpropertytax.ca/flot07.html But when I switch to version 0.8.1 of the FLOT library, the page returns an error saying: Uncaught TypeError: Cannot read property 'left' of null http://attardpropertytax.ca/flot81.html The HTML is the same for both pages, so I cannot figure out why the new version 0.8.1 of FLOT returns an error, but the old version 0.7 does not. Any ideas? I somehow stumbled across a work-around that managed to fix my problem. I'm nut sure why, but I had to comment-out the following two sections of code from the v. 0.8.1 FLOT library: This was the first spot: // If the grid is visible, add its border width to the offset for (var a in plotOffset) { if(typeof(options.grid.borderWidth) == "object") { plotOffset[a] += showGrid ? options.grid.borderWidth[a] : 0; } else { plotOffset[a] += showGrid ? options.grid.borderWidth : 0; } } And this was the second spot: if (isNaN(v) || v < axis.min || v > axis.max // skip those lying on the axes if we got a border || (t == "full" && ((typeof bw == "object" && bw[axis.position] > 0) || bw > 0) && (v == axis.min || v == axis.max))) continue; I'm sure eventually @DNS will be taking a look at this question and maybe he will be able to help me understand what is going wrong with my code. Thanks.

    Read the article

  • Looking for the log file on iPhone

    - by zp26
    Hi, I have a problem. I have the code below for save a data on file. I build my app on the device, and run. The result variable is TRUE, but i don't find the file on the my iPhone device. Can you help me? Thank and sorry for my english XP -(void)saveXML:(NSString*)name:(float)x:(float)y:(float)z{ NSMutableData *data = [NSMutableData data]; NSKeyedArchiver *archiver = [[NSKeyedArchiver alloc] initForWritingWithMutableData:data]; [archiver setOutputFormat:NSPropertyListXMLFormat_v1_0]; [archiver encodeFloat:x forKey:@"x"]; [archiver encodeFloat:y forKey:@"y"]; [archiver encodeFloat:z forKey:@"z"]; [archiver encodeObject:name forKey:@"name"]; [archiver finishEncoding]; NSString* filePath = [[NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES) objectAtIndex:0] stringByAppendingPathComponent:@"XML Position"]; BOOL result = [data writeToFile:filePath atomically:YES]; if(result) [self updateTextView:@"success"]; [archiver release]; }

    Read the article

  • Why isn't this company contacting me? [closed]

    - by Alan
    I had a phone screen the other day with a company that I really want to work for. It went pretty well, based on cues from the HR person, such as "Next step we're going to send you a programming test," and "Well, before I get ahead of myself, do you want to continue the interviewing process." and "We'll send out the test later this afternoon. It doesn't sound like you'll have trouble with it, but I want to be honest we do have a high failure rate on it." The questions asked weren't technical, just going down my resume, and talking about the work I've done, and how it relates to the position. Nothing I couldn't talk through. This was last Thursday. It's now Tuesday, and haven't received the test yet. I sent a follow up email yesterday to the lady who interviewed me, but haven't gotten a response. Anyone had a similar experience? Am I reading too much into this? Or was I off the mark by thinking I had moved on to the next step in the interview process. Since this is a company I really want to work for, I'm driving myself insane enumerating all the various what-if scenarios.

    Read the article

  • Why does Python sometimes upgrade a string to unicode and sometimes not?

    - by samtregar
    I'm confused. Consider this code working the way I expect: >>> foo = u'Émilie and Juañ are turncoats.' >>> bar = "foo is %s" % foo >>> bar u'foo is \xc3\x89milie and Jua\xc3\xb1 are turncoats.' And this code not at all working the way I expect: >>> try: ... raise Exception(foo) ... except Exception as e: ... foo2 = e ... >>> bar = "foo2 is %s" % foo2 ------------------------------------------------------------ Traceback (most recent call last): File "<ipython console>", line 1, in <module> UnicodeEncodeError: 'ascii' codec can't encode characters in position 0-1: ordinal not in range(128) Can someone explain what's going on here? Why does it matter whether the unicode data is in a plain unicode string or stored in an Exception object? And why does this fix it: >>> bar = u"foo2 is %s" % foo2 >>> bar u'foo2 is \xc3\x89milie and Jua\xc3\xb1 are turncoats.' I am quite confused! Thanks for the help! UPDATE: My coding buddy Randall has added to my confusion in an attempt to help me! Send in the reinforcements to explain how this is supposed to make sense: >>> class A: ... def __str__(self): return "string" ... def __unicode__(self): return "unicode" ... >>> "%s %s" % (u'niño', A()) u'ni\xc3\xb1o unicode' >>> "%s %s" % (A(), u'niño') u'string ni\xc3\xb1o' Note that the order of the arguments here determines which method is called!

    Read the article

  • Positioning DIV element at center of screen

    - by iSumitG
    I want to position a DIV (or a TABLE) element at the center of screen irrespective of screen size. In other words, the space left on 'top' and 'bottom' should be equal and space left on 'right' and 'left' sides should be equal. How to do it? Note: I prefer a complete CSS solution, but if is not possible without Javascript then using Javascript is also fine. I am trying the following but it is not working: <body> <div style="top:0px; border:1px solid red;"> <table border="1" align="center"> <tr height="100%"> <td height="100%" width="100%" valign="middle" align="center"> We are launching soon! </td> </tr> </table> </div> </body> Note: It is either way fine if the DIV element (or TABLE) scrolls with the website or not. Just want it to be at center when page loads.

    Read the article

  • Scroll view to bottom while keyboard is hiding

    - by Manu
    Hi! I'm using a scroll view to move my view and show certain text fields (that otherwise would be hidden) when the keyboard shows. I basically resize the scroll view to make room for the keyboard, and then scroll up the view smoothly with "scrollRectToVisible", which works perfectly. After that, I can scroll and edit the rest of the text fields without lowering the keyboard, which is what I intend. The problem comes when I want to hide the keyboard again. I have been able to lower the keyboard and scroll down the view to its original position without a problem, but I have been unable to make that transition smooth. At the moment I use the following: - (void)keyboardWillHide: (NSNotification *)notif { CGRect topRect = CGRectMake(0, 0, 1, 1); [scrollview scrollRectToVisible:topRect animated:YES]; scrollview.frame = CGRectMake(0, 0, scrollviewWidth, scrollviewHeight); } I create a CGRect at the top, which I then move into view with "scrollRectToVisible". That works fine and commences the scrolling right when the keyboard is hiding (I use "keyboardWillHide" and not "keyboardDidHide" because the scroll view frame is still missing its lower part). The problem comes when I resize the scroll view frame back to its original dimensions (which I need to do), because then the scrolling is interrupted and the view drops to the bottom suddenly (as there is nothing else to scroll). This causes a glitch, which is why I cannot complete the transition smoothly. Any ideas on how could I lower the keyboard while scrolling the view down smoothly? Should I be scrolling up a bigger view, instead of resizing it? That way I would not have to restore the scroll view frame dimensions when lowering the keyboard, or would I? Thanks very much in advance!

    Read the article

  • ListView in Android, handler for clicking item

    - by eljainc
    Hello, I have an activity in Android which uses a ListView. When I click on an item in the ListView, I would like to be able to determine which item was clicked. I have the following code: @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setRequestedOrientation (ActivityInfo.SCREEN_ORIENTATION_PORTRAIT); setContentView(R.layout.listr); //setupDB(); // populateList3(); ListView lv = (ListView) findViewById(R.id.ListView01); lv.setClickable(true); lv.setOnItemClickListener(new OnItemClickListener() { public void onItemClick(AdapterView<?> parent, View view, int position, long id) { Toast.makeText(ListRecords.this,"Clicked!", Toast.LENGTH_LONG).show(); } }); } My XML code: xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/Linear03lr" android:layout_width="fill_parent" android:orientation="vertical" android:gravity="center" android:layout_height="fill_parent"> android:layout_width="wrap_content" android:layout_height="400dp" / <Button android:id="@+id/previousbutton" android:gravity="center_horizontal" android:layout_width = "fill_parent" android:layout_height = "fill_parent" android:text="Previous Menu"/> </LinearLayout> What am I missing here to be able to intercept clicks on the Listview? Thanks

    Read the article

  • When I Add <DIV> Bottom Scroll Bar Appears, Even Though It Is Not Greater Than The Page Width

    - by Clay Dempsey
    I have searched for this with no answer. My page loads up perfectly when I load the header, navigation and then center image...all 3 different divs. However I have more I need to add and the div tags change the size of the page even though the css I'm using isn't larger than the page. I have no idea what is happening. Here's the code page where everything is fine: http://www.thehdmgroup.com/midwaymissionary/test.php When I add the below div tag with the below css I get a bottom scrollbar on the page and I don't know why. Can someone please explain it to me? #middleTextBox1 { position: absolute; top:507px; left:172px; width:180px; height:180px; background-color:#411b42; border: 1px solid #434343; padding:10px; color: #FFFFFF; font-size: 10px; font-family: Arial, Helvetica, sans-serif; } <div id="middleTextBox1"> <h3 align="center">Mission:</h3> Words </div> I really have no idea why this is happening, could someone please help me out? Thanks for your time.

    Read the article

  • Error while sending mail (attachment file)

    - by Surya sasidhar
    hi, in my application i am using to send mail with attachments i write the code like this Using System.Net.Mail; MailMessage mail = new MailMessage(); mail.Body = "<html><body><b> Name Of The Job Seeker: " + txtName.Text + "<br><br>" + "The Mail ID:" + txtEmail.Text + "<br><br>" + " The Mobile Number: " + txtmobile.Text + "<br><br>" + "Position For Applied: " + txtPostionAppl.Text + "<br><br>" + "Description " + txtdescript.Text + "<br><br></b></body></html>"; mail.From = new MailAddress ( txtEmail.Text); mail.To .Add (new MailAddress ( mailid)); mail.Priority = MailPriority.High; FileUpload1.PostedFile.SaveAs("~/Resume/" + FileUpload1.FileName); mail.Attachments.Add(filenme); SmtpMail sm = new SmtpMail(); sm.Send(mail); it is giving error at attachment like mail.Attachemts.Add(filena) like this 'System.Collections.ObjectModel.Collection.Add(System.Net.Mail.Attachment)' has some invalid arguments.

    Read the article

  • What are the general strategies for the server of an FPS multiplayer game to update its clients?

    - by Hooray Im Helping
    A friend and I were having a discussion about how a FPS server updates the clients connected to it. We watched a video of a guy cheating in Battlefield: Bad Company 2 and saw how it highlighted the position of enemies on the screen and it got us thinking. His contention was that the server only updates the client with information that is immediately relevant to the client. I.e. the server won't send information about enemy players if they are too far away from the client or out of the client's line of sight for reasons of efficiency. He was unsure though - he brought up the example of someone hiding behind a rock, not able to see anyone. If the player were suddenly to pop up where he had three players in his line of sight, there would be a 50ms delay before they were rendered on his screen while the server transmitted the necessary information. My contention was the opposite: that the server sends the client all the information about every player and lets the client sort out what is allowed and what isn't. I figured it would actually be less expensive computationally for the server to just send everything to the client and let the client do the heavy lifting, so to speak. I also figured this is how cheat programs work - they intercept the server packets, get the location of enemies, then show them on the client's view. So the question: What are some general policies or strategies a modern first person shooter server employs to keep its clients updated?

    Read the article

  • image display in block <a> - CSS

    - by blasteralfred
    I have a page like below; <style type="text/css"> #div1 { height: 100px; background-color: #CCCCCC; } #div2 { display: inline; height: 48px; margin: 0; padding: 0; position: relative; white-space: nowrap; } #div2 a { display: block; background-color: #FF9900; height: 51px; width: 150px; padding-right: 50px; text-decoration: none; word-wrap: break-word; white-space: normal; } #div2 img { border:0; float: right; } </style> <div id="div1"> <div id="div2"> <a href="">text1 text2 text3 text4 text5 text6 text7 text8<img src="image.jpg"></a> </div> </div> What I am getting is something like this; and I want this; Here is the fiddle. Thanks in advance...:)

    Read the article

  • What makes you trust that a piece of open source software is not malicious?

    - by Daniel DiPaolo
    We developers are in a unique position when it comes to the ability to not only be skeptical about the capabilities provided by open source software, but to actively analyze the code since it is freely available. In fact, one may even argue that open source software developers have a social responsibility to do so to contribute to the community. But at what point do you as a developer say, "I better take a look at what this is doing before I trust using it" for any given thing? Is it a matter of trusting code with your personal information? Does it depend on the source you're getting it from? What spurred this question on was a post on Hacker News to a javascript bookmarklet that supposedly tells you how "exposed" your information on Facebook is as well as recommending some fixes. I thought for a second "I'd rather not start blindly running this code over all my (fairly locked down) Facebook information so let me check it out". The bookmarklet is simple enough, but it calls another javascript function which at the time (but not anymore) was highly compressed and undecipherable. That's when I said "nope, not gonna do it". So even though I could have verified the original uncompressed javascript from the Github site and even saved a local copy to verify and then run without hitting their server, I wasn't going to. It's several thousand lines and I'm not a total javascript guru to begin with. Yet, folks are using it anyway. Even (supposedly) bright developers. What makes them trust the script? Did they all scrutinize it line by line? Do they know the guy personally and trust him not to do anything bad? Do they just take his word? What makes you trust that a piece of open source software is not malicious?

    Read the article

  • Understanding C++ pointers (when they point to a pointer)

    - by Stephano
    I think I understand references and pointers pretty well. Here is what I (think I) know: int i = 5; //i is a primitive type, the value is 5, i do not know the address. int *ptr; //a pointer to an int. i have no way if knowing the value yet. ptr = &i; //now i have an address for the value of i (called ptr) *ptr = 10; //go get the value stored at ptr and change it to 10 Please feel free to comment or correct these statements. Now I'm trying to make the jump to arrays of pointers. Here is what I do not know: char **char_ptrs = new char *[50]; Node **node_ptrs = new Node *[50]; My understanding is that I have 2 arrays of pointers, one set of pointers to chars and one to nodes. So if I wanted to set the values, I would do something like this: char_ptrs[0] = new char[20]; node_ptrs[0] = new Node; Now I have a pointer, in the 0 position of my array, in each respective array. Again, feel free to comment here if I'm confused. So, what does the ** operator do? Likewise, what is putting a single * next to the instantiation doing (*[50])? (what is that called exactly, instantiation?)

    Read the article

  • Randomly sorting an array

    - by Cam
    Does there exist an algorithm which, given an ordered list of symbols {a1, a2, a3, ..., ak}, produces in O(n) time a new list of the same symbols in a random order without bias? "Without bias" means the probability that any symbol s will end up in some position p in the list is 1/k. Assume it is possible to generate a non-biased integer from 1-k inclusive in O(1) time. Also assume that O(1) element access/mutation is possible, and that it is possible to create a new list of size k in O(k) time. In particular, I would be interested in a 'generative' algorithm. That is, I would be interested in an algorithm that has O(1) initial overhead, and then produces a new element for each slot in the list, taking O(1) time per slot. If no solution exists to the problem as described, I would still like to know about solutions that do not meet my constraints in one or more of the following ways (and/or in other ways if necessary): the time complexity is worse than O(n). the algorithm is biased with regards to the final positions of the symbols. the algorithm is not generative. I should add that this problem appears to be the same as the problem of randomly sorting the integers from 1-k, since we can sort the list of integers from 1-k and then for each integer i in the new list, we can produce the symbol ai.

    Read the article

  • Iphone xcode simulator crashes when I move up and down on a table row

    - by Frames84
    I can't get my head round this. When the page loads, everything works fine - I can drill up and down, however 'stream' (in the position I have highlighted below) becomes not equal to anything when I pull up and down on the tableview. But the error is only sometimes. Normally it returns key/pairs. If know one can understand above how to you test for // (int)[$VAR count]} key/value pairs in a NSMutableDictionary object - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *FirstLevelCell = @"FirstLevelCell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:FirstLevelCell]; if(cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:FirstLevelCell] autorelease]; } NSInteger row = [indexPath row]; //NSDictionary *stream = (NSDictionary *) [dataList objectAtIndex:row]; NSString *level = self.atLevel; if([level isEqualToString:@"level2"]) { NSMutableDictionary *stream = [[NSMutableArray alloc] init]; stream = (NSMutableDictionary *) [dataList objectAtIndex:row]; // stream value is (int)[$VAR count]} key/value pairs if ([stream valueForKey:@"title"] ) { cell.textLabel.text = [stream valueForKey:@"title"]; cell.textLabel.numberOfLines = 2; cell.textLabel.font =[UIFont systemFontOfSize:10]; NSString *detailText = [stream valueForKey:@"created"]; cell.detailTextLabel.numberOfLines = 2; cell.detailTextLabel.font= [UIFont systemFontOfSize:9]; cell.detailTextLabel.text = detailText; NSString *str = @"http://www.mywebsite.co.uk/images/stories/Cimex.jpg"; NSData *imageURL = [[NSData alloc] initWithContentsOfURL:[NSURL URLWithString:str]]; UIImage *newsImage = [[UIImage alloc] initWithData:imageURL]; cell.imageView.image = newsImage; [stream release]; } } else { cell.textLabel.text = [dataList objectAtIndex:row]; } return cell; } Thanks for your time

    Read the article

  • CSS to create curved corner between two elements?

    - by Tauren
    My UI has an unordered list on the left. When a list item is selected, a div appears on the right of it. I'd like to have a curved outer corner where the <li> and the <div> meet. See the white arrow in the image below. To extend the blue <li> to the edge of the <ul>, I'm planning to do something like this: li { right-margin: 2em; border-radius: 8px; } li.active { right-margin: 0; border-bottom-right-radius: 0; border-top-right-radius: 0; } Is there a better way to extend the <li> to the edge of the <ul>? Obviously, I'll include the webkit and mozilla border radius CSS as well. The main thing I'm unsure about is that outer corner underneath the bottom right corner of the active <li>. I have some ideas, but they seem like hacks. Any suggestions? NOTE that the <ul> is indicated in grey, but it would be white in the real design. Also, I'm planning to use Javascript to position the <div> correctly when an <li> is selected.

    Read the article

< Previous Page | 464 465 466 467 468 469 470 471 472 473 474 475  | Next Page >