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  • nginx+django serving static files

    - by avalore
    I have followed instruction for setting up django with nginx from the django wiki (https://code.djangoproject.com/wiki/DjangoAndNginx) and have nginx setup as follows (a few name changes to fit my setup). user nginx nginx; worker_processes 2; error_log /var/log/nginx/error_log info; events { worker_connections 1024; use epoll; } http { include /etc/nginx/mime.types; default_type application/octet-stream; log_format main '$remote_addr - $remote_user [$time_local] ' '"$request" $status $bytes_sent ' '"$http_referer" "$http_user_agent" ' '"$gzip_ratio"'; client_header_timeout 10m; client_body_timeout 10m; send_timeout 10m; connection_pool_size 256; client_header_buffer_size 1k; large_client_header_buffers 4 2k; request_pool_size 4k; gzip on; gzip_min_length 1100; gzip_buffers 4 8k; gzip_types text/plain; output_buffers 1 32k; postpone_output 1460; sendfile on; tcp_nopush on; tcp_nodelay on; keepalive_timeout 75 20; ignore_invalid_headers on; index index.html; server { listen 80; server_name localhost; location /static/ { root /srv/static/; } location ~* ^.+\.(jpg|jpeg|gif|png|ico|css|zip|tgz|gz|rar|bz2|doc|xls|exe|pdf|ppt|txt|tar|mid|midi|wav|bmp|rtf|js|mov) { access_log off; expires 30d; } location / { # host and port to fastcgi server fastcgi_pass 127.0.0.1:8080; fastcgi_param PATH_INFO $fastcgi_script_name; fastcgi_param REQUEST_METHOD $request_method; fastcgi_param QUERY_STRING $query_string; fastcgi_param CONTENT_TYPE $content_type; fastcgi_param CONTENT_LENGTH $content_length; fastcgi_pass_header Authorization; fastcgi_intercept_errors off; fastcgi_param REMOTE_ADDR $remote_addr; } access_log /var/log/nginx/localhost.access_log main; error_log /var/log/nginx/localhost.error_log; } } Static files aren't being served (nginx 404). If I look in the access log it seems nginx is looking in /etc/nginx/html/static... rather than /srv/static/ as specified in the config. I've no clue why it's doing this, any help would be hugely appreciated.

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  • Request data from database using Django

    - by user21901
    I have somehow two variables for example x and y. I have also made a model with 3 fields (longitude,latitude,name) and have it activated in mysql database. I need to send these two variables(x,y) to the django server so as to search if there is an object with longitude=x and latitude=y.If there is one i want to get back it's name. How can i do this?

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  • How to build a Django form which requires a delay to be re-submitted ?

    - by pierre-guillaume-degans
    Hey, In order to avoid spamming, I would like to add a waiting time to re-submit a form (i.e. the user should wait a few seconds to submit the form, except the first time that this form is submitted). To do that, I added a timestamp to my form (and a security_hash field containing the timestamp plus the settings.SECRET_KEY which ensures that the timestamp is not fiddled with). This look like: class MyForm(forms.Form): timestamp = forms.IntegerField(widget=forms.HiddenInput) security_hash = forms.CharField(min_length=40, max_length=40, widget=forms.HiddenInput) # + some other fields.. # + methods to build the hash and to clean the timestamp... # (it is based on django.contrib.comments.forms.CommentSecurityForm) def clean_timestamp(self): """Make sure the delay is over (5 seconds).""" ts = self.cleaned_data["timestamp"] if not time.time() - ts > 5: raise forms.ValidationError("Timestamp check failed") return ts # etc... This works fine. However there is still an issue: the timestamp is checked the first time the form is submitted by the user, and I need to avoid this. Any idea to fix it ? Thank you ! :-)

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  • How do I relate two models/tables in Django based on non primary non unique keys?

    - by wizard
    I've got two tables that I need to relate on a single field po_num. The data is imported from another source so while I have a little bit of control over what the tables look like but I can't change them too much. What I want to do is relate these two models so I can look up one from the other based on the po_num fields. What I really need to do is join the two tables so I can do a where on a count of the related table. I would like to do filter for all Order objects that have 0 related EDI856 objects. I tried adding a foreign key to the Order model and specified the db_column and to_fields as po_num but django didn't like that the fact that Edi856.po_num wasn't unique. Here are the important fields of my current models that let me display but not filter for the data that I want. class Edi856(models.Model): po_num = models.CharField(max_length=90, db_index=True ) class Order(models.Model): po_num = models.CharField(max_length=90, db_index=True) def in_edi(self): '''Has the edi been processed?''' return Edi856.objects.filter(po_num = self.po_num).count() Thanks for taking the time to read about my problem. I'm not sure what to do from here.

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  • What kind of data do I pass into a Django Model.save() method?

    - by poswald
    Lets say that we are getting POSTed a form like this in Django: rate=10 items= [23,12,31,52,83,34] The items are primary keys of an Item model. I have a bunch of business logic that will run and create more items based on this data, the results of some db lookups, and some business logic. I want to put that logic into a save signal or an overridden Model.save() method of another model (let's call it Inventory). The business logic will run when I create a new Inventory object using this form data. Inventory will look like this: class Inventory(models.Model): picked_items = models.ManyToManyField(Item, related_name="items_picked_set") calculated_items = models.ManyToManyField(Item, related_name="items_calculated_set") rate = models.DecimalField() ... other fields here ... New calculated_items will be created based on the passed in items which will be stored as picked_items. My question is this: is it better for the save() method on this model to accept: the request object (I don't really like this coupling) the form data as arguments or kwargs (a list of primary keys and the other form fields) a list of Items (The caller form or view will lookup the list of Items and create a list as well as pass in the other form fields) some other approach? I know this is a bit subjective, but I was wondering what the general idea is. I've looked through a lot of code but I'm having a hard time finding a pattern I like.

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  • Django app that can provide user friendly, multiple / mass file upload functionality to other apps

    - by hopla
    Hi, I'm going to be honest: this is a question I asked on the Django-Users mailinglist last week. Since I didn't get any replies there yet, I'm reposting it on Stack Overflow in the hope that it gets more attention here. I want to create an app that makes it easy to do user friendly, multiple / mass file upload in your own apps. With user friendly I mean upload like Gmail, Flickr, ... where the user can select multiple files at once in the browse file dialog. The files are then uploaded sequentially or in parallel and a nice overview of the selected files is shown on the page with a progress bar next to them. A 'Cancel' upload button is also a possible option. All that niceness is usually solved by using a Flash object. Complete solutions are out there for the client side, like: SWFUpload http://swfupload.org/ , FancyUpload http://digitarald.de/project/fancyupload/ , YUI 2 Uploader http://developer.yahoo.com/yui/uploader/ and probably many more. Ofcourse the trick is getting those solutions integrated in your project. Especially in a framework like Django, double so if you want it to be reusable. So, I have a few ideas, but I'm neither an expert on Django nor on Flash based upload solutions. I'll share my ideas here in the hope of getting some feedback from more knowledgeable and experienced people. (Or even just some 'I want this too!' replies :) ) You will notice that I make a few assumptions: this is to keep the (initial) scope of the application under control. These assumptions are of course debatable: All right, my idea's so far: If you want to mass upload multiple files, you are going to have a model to contain each file in. I.e. the model will contain one FileField or one ImageField. Models with multiple (but ofcourse finite) amount of FileFields/ ImageFields are not in need of easy mass uploading imho: if you have a model with 100 FileFields you are doing something wrong :) Examples where you would want my envisioned kind of mass upload: An app that has just one model 'Brochure' with a file field, a title field (dynamically created from the filename) and a date_added field. A photo gallery app with models 'Gallery' and 'Photo'. You pick a Gallery to add pictures to, upload the pictures and new Photo objects are created and foreign keys set to the chosen Gallery. It would be nice to be able to configure or extend the app for your favorite Flash upload solution. We can pick one of the three above as a default, but implement the app so that people can easily add additional implementations (kinda like Django can use multiple databases). Let it be agnostic to any particular client side solution. If we need to pick one to start with, maybe pick the one with the smallest footprint? (smallest download of client side stuff) The Flash based solutions asynchronously (and either sequentially or in parallel) POST the files to a url. I suggest that url to be local to our generic app (so it's the same for every app where you use our app in). That url will go to a view provided by our generic app. The view will do the following: create a new model instance, add the file, OPTIONALLY DO EXTRA STUFF and save the instance. DO EXTRA STUFF is code that the app that uses our app wants to run. It doesn't have to provide any extra code, if the model has just a FileField/ImageField the standard view code will do the job. But most app will want to do extra stuff I think, like filling in the other fields: title, date_added, foreignkeys, manytomany, ... I have not yet thought about a mechanism for DO EXTRA STUFF. Just wrapping the generic app view came to mind, but that is not developer friendly, since you would have to write your own url pattern and your own view. Then you have to tell the Flash solutions to use a new url etc... I think something like signals could be used here? Forms/Admin: I'm still very sketchy on how all this could best be integrated in the Admin or generic Django forms/widgets/... (and this is were my lack of Django experience shows): In the case of the Gallery/Photo app: You could provide a mass Photo upload widget on the Gallery detail form. But what if the Gallery instance is not saved yet? The file upload view won't be able to set the foreignkeys on the Photo instances. I see that the auth app, when you create a user, first asks for username and password and only then provides you with a bigger form to fill in emailadres, pick roles etc. We could do something like that. In the case of an app with just one model: How do you provide a form in the Django admin to do your mass upload? You can't do it with the detail form of your model, that's just for one model instance. There's probably dozens more questions that need to be answered before I can even start on this app. So please tell me what you think! Give me input! What do you like? What not? What would you do different? Is this idea solid? Where is it not? Thank you!

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  • Is it ok to hardcode dynamic links in a permanent view?

    - by meder
    Let's say I wanted to showcase 2-3 clickable buttons on my homepage which will be there permanently. These are links to the css, html, and javascript tag listing pages. Is it fine to just hardcode href=/tags/css and href=/tags/html right in my django templates/view? I won't change them for at least a year or so, meaning I don't think I need to add a column to the tags table to distinguish them - is this common or should I try to make it somewhat dynamic? These tags are in a table but so are 1000 other tags.

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  • Implementing a popularity algorithm in Django

    - by TheLizardKing
    I am creating a site similar to reddit and hacker news that has a database of links and votes. I am implementing hacker news' popularity algorithm and things are going pretty swimmingly until it comes to actually gathering up these links and displaying them. The algorithm is simple: Y Combinator's Hacker News: Popularity = (p - 1) / (t + 2)^1.5` Votes divided by age factor. Where` p : votes (points) from users. t : time since submission in hours. p is subtracted by 1 to negate submitter's vote. Age factor is (time since submission in hours plus two) to the power of 1.5.factor is (time since submission in hours plus two) to the power of 1.5. I asked a very similar question over yonder http://stackoverflow.com/questions/1964395/complex-ordering-in-django but instead of contemplating my options I choose one and tried to make it work because that's how I did it with PHP/MySQL but I now know Django does things a lot differently. My models look something (exactly) like this class Link(models.Model): category = models.ForeignKey(Category) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add = True) modified = models.DateTimeField(auto_now = True) fame = models.PositiveIntegerField(default = 1) title = models.CharField(max_length = 256) url = models.URLField(max_length = 2048) def __unicode__(self): return self.title class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add = True) modified = models.DateTimeField(auto_now = True) karma_delta = models.SmallIntegerField() def __unicode__(self): return str(self.karma_delta) and my view: def index(request): popular_links = Link.objects.select_related().annotate(karma_total = Sum('vote__karma_delta')) return render_to_response('links/index.html', {'links': popular_links}) Now from my previous question, I am trying to implement the algorithm using the sorting function. An answer from that question seems to think I should put the algorithm in the select and sort then. I am going to paginate these results so I don't think I can do the sorting in python without grabbing everything. Any suggestions on how I could efficiently do this? EDIT This isn't working yet but I think it's a step in the right direction: from django.shortcuts import render_to_response from linkett.apps.links.models import * def index(request): popular_links = Link.objects.select_related() popular_links = popular_links.extra( select = { 'karma_total': 'SUM(vote.karma_delta)', 'popularity': '(karma_total - 1) / POW(2, 1.5)', }, order_by = ['-popularity'] ) return render_to_response('links/index.html', {'links': popular_links}) This errors out into: Caught an exception while rendering: column "karma_total" does not exist LINE 1: SELECT ((karma_total - 1) / POW(2, 1.5)) AS "popularity", (S... EDIT 2 Better error? TemplateSyntaxError: Caught an exception while rendering: missing FROM-clause entry for table "vote" LINE 1: SELECT ((vote.karma_total - 1) / POW(2, 1.5)) AS "popularity... My index.html is simply: {% block content %} {% for link in links %} karma-up {{ link.karma_total }} karma-down {{ link.title }} Posted by {{ link.user }} to {{ link.category }} at {{ link.created }} {% empty %} No Links {% endfor %} {% endblock content %} EDIT 3 So very close! Again, all these answers are great but I am concentrating on a particular one because I feel it works best for my situation. from django.db.models import Sum from django.shortcuts import render_to_response from linkett.apps.links.models import * def index(request): popular_links = Link.objects.select_related().extra( select = { 'popularity': '(SUM(links_vote.karma_delta) - 1) / POW(2, 1.5)', }, tables = ['links_link', 'links_vote'], order_by = ['-popularity'], ) return render_to_response('links/test.html', {'links': popular_links}) Running this I am presented with an error hating on my lack of group by values. Specifically: TemplateSyntaxError at / Caught an exception while rendering: column "links_link.id" must appear in the GROUP BY clause or be used in an aggregate function LINE 1: ...karma_delta) - 1) / POW(2, 1.5)) AS "popularity", "links_lin... Not sure why my links_link.id wouldn't be in my group by but I am not sure how to alter my group by, django usually does that.

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  • List of Django model instance foreign keys losing consistency during state changes.

    - by Joshua
    I have model, Match, with two foreign keys: class Match(model.Model): winner = models.ForeignKey(Player) loser = models.ForeignKey(Player) When I loop over Match I find that each model instance uses a unique object for the foreign key. This ends up biting me because it introduces inconsistency, here is an example: >>> def print_elo(match_list): ... for match in match_list: ... print match.winner.id, match.winner.elo ... print match.loser.id, match.loser.elo ... >>> print_elo(teacher_match_list) 4 1192.0000000000 2 1192.0000000000 5 1208.0000000000 2 1192.0000000000 5 1208.0000000000 4 1192.0000000000 >>> teacher_match_list[0].winner.elo = 3000 >>> print_elo(teacher_match_list) 4 3000 # Object 4 2 1192.0000000000 5 1208.0000000000 2 1192.0000000000 5 1208.0000000000 4 1192.0000000000 # Object 4 >>> I solved this problem like so: def unify_refrences(match_list): """Makes each unique refrence to a model instance non-unique. In cases where multiple model instances are being used django creates a new object for each model instance, even if it that means creating the same instance twice. If one of these objects has its state changed any other object refrencing the same model instance will not be updated. This method ensure that state changes are seen. It makes sure that variables which hold objects pointing to the same model all hold the same object. Visually this means that a list of [var1, var2] whose internals look like so: var1 --> object1 --> model1 var2 --> object2 --> model1 Will result in the internals being changed so that: var1 --> object1 --> model1 var2 ------^ """ match_dict = {} for match in match_list: try: match.winner = match_dict[match.winner.id] except KeyError: match_dict[match.winner.id] = match.winner try: match.loser = match_dict[match.loser.id] except KeyError: match_dict[match.loser.id] = match.loser My question: Is there a way to solve the problem more elegantly through the use of QuerySets without needing to call save at any point? If not, I'd like to make the solution more generic: how can you get a list of the foreign keys on a model instance or do you have a better generic solution to my problem? Please correct me if you think I don't understand why this is happening.

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  • Implementing Tagging System with PHP and mySQL. Caching help!!!

    - by Hamid Sarfraz
    With reference to this post: http://stackoverflow.com/questions/2122546/how-to-implement-tag-counting I have implemented the suggested 3 table tagging system completely. To count the number of Articles per tag, i am using another column named tagArticleCount in the tag definition table. (other columns are tagId, tagText, tagUrl, tagArticleCount). If i implement realtime editing of this table, so that whenever user adds another tag to article or deletes an existing tag, the tag_definition_table is updated to update the counter of the added/removed tag. This will cost an extra query each time any modification is made. (at the same time, related link entry for tag and article is deleted from tagLinkTable). An alternative to this is not allowing any real time editing to the counter, instead use CRONs to update counter of each tag after a specified time period. Here comes the problem that i want to discuss. This can be seen as caching the article count in database. Can you please help me find a way to present the articles in a list when a tag is explored and when the article counter for that tag is not up to date. For example: 1. Counter shows 50 articles, but there are infact 55 entries in the tag link table (that links tags and articles). 2. Counter shows 50 articles, but there are infact 45 extries in the tag link table. How to handle these 2 scenerios given in example. I am going to use APC to keep cache of these counters. Consider it too in your solution. Also discuss performance in the realtime / CRONNED counter updates.

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  • django image upload forms

    - by gramware
    I am having problems with django forms and image uploads. I have googled, read the documentations and even questions ere, but cant figure out the issue. Here are my files my models class UserProfile(User): """user with app settings. """ DESIGNATION_CHOICES=( ('ADM', 'Administrator'), ('OFF', 'Club Official'), ('MEM', 'Ordinary Member'), ) onames = models.CharField(max_length=30, blank=True) phoneNumber = models.CharField(max_length=15) regNo = models.CharField(max_length=15) designation = models.CharField(max_length=3,choices=DESIGNATION_CHOICES) image = models.ImageField(max_length=100,upload_to='photos/%Y/%m/%d', blank=True, null=True) course = models.CharField(max_length=30, blank=True, null=True) timezone = models.CharField(max_length=50, default='Africa/Nairobi') smsCom = models.BooleanField() mailCom = models.BooleanField() fbCom = models.BooleanField() objects = UserManager() #def __unicode__(self): # return '%s %s ' % (User.Username, User.is_staff) def get_absolute_url(self): return u'%s%s/%s' % (settings.MEDIA_URL, settings.ATTACHMENT_FOLDER, self.id) def get_download_url(self): return u'%s%s/%s' % (settings.MEDIA_URL, settings.ATTACHMENT_FOLDER, self.name) ... class reports(models.Model): repID = models.AutoField(primary_key=True) repSubject = models.CharField(max_length=100) repRecepients = models.ManyToManyField(UserProfile) repPoster = models.ForeignKey(UserProfile,related_name='repposter') repDescription = models.TextField() repPubAccess = models.BooleanField() repDate = models.DateField() report = models.FileField(max_length=200,upload_to='files/%Y/%m/%d' ) deleted = models.BooleanField() def __unicode__(self): return u'%s ' % (self.repSubject) my forms from django import forms from django.http import HttpResponse from cms.models import * from django.contrib.sessions.models import Session from django.forms.extras.widgets import SelectDateWidget class UserProfileForm(forms.ModelForm): class Meta: model= UserProfile exclude = ('designation','password','is_staff', 'is_active','is_superuser','last_login','date_joined','user_permissions','groups') ... class reportsForm(forms.ModelForm): repPoster = forms.ModelChoiceField(queryset=UserProfile.objects.all(), widget=forms.HiddenInput()) repDescription = forms.CharField(widget=forms.Textarea(attrs={'cols':'50', 'rows':'5'}),label='Enter Report Description here') repDate = forms.DateField(widget=SelectDateWidget()) class Meta: model = reports exclude = ('deleted') my views @login_required def reports_media(request): user = UserProfile.objects.get(pk=request.session['_auth_user_id']) if request.user.is_staff== True: repmedform = reportsForm(request.POST, request.FILES) if repmedform.is_valid(): repmedform.save() repmedform = reportsForm(initial = {'repPoster':user.id,}) else: repmedform = reportsForm(initial = {'repPoster':user.id,}) return render_to_response('staffrepmedia.html', {'repfrm':repmedform, 'rep_media': reports.objects.all()}) else: return render_to_response('reports_&_media.html', {'rep_media': reports.objects.all()}) ... @login_required def settingchng(request): user = UserProfile.objects.get(pk=request.session['_auth_user_id']) form = UserProfileForm(instance = user) if request.method == 'POST': form = UserProfileForm(request.POST, request.FILES, instance = user) if form.is_valid(): form.save() return HttpResponseRedirect('/settings/') else: form = UserProfileForm(instance = user) if request.user.is_staff== True: return render_to_response('staffsettingschange.html', {'form': form}) else: return render_to_response('settingschange.html', {'form': form}) ... @login_required def useradd(request): if request.method == 'POST': form = UserAddForm(request.POST,request.FILES ) if form.is_valid(): password = request.POST['password'] request.POST['password'] = set_password(password) form.save() else: form = UserAddForm() return render_to_response('staffadduser.html', {'form':form}) Example of my templates {% if form.errors %} <ol> {% for field in form %} <H3 class="title"> <p class="error"> {% if field.errors %}<li>{{ field.errors|striptags }}</li>{% endif %}</p> </H3> {% endfor %} </ol> {% endif %} <form method="post" id="form" action="" enctype="multipart/form-data" class="infotabs accfrm"> {{ repfrm.as_p }} <input type="submit" value="Submit" /> </form>

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  • Installation requirements of django installing in hostgator dedicated server

    - by jaypabs
    First, before I install OSQA on my dedicated server at hostgator, I want to know the requirements. I don't want to screw up my server so it's better to ask question first. I have read a lot of tutorial on the internet regarding Django but I want to clarify something before I proceed. On my dedicated server I don't use FCGI. Instead I use Mod SuPHP. A lot of tutorial is talking about installing python using FCGI. My question is if it is safe to install Python if I'm using SuPHP? Is it safe to use the tutorial on this link: http://wiki.osqa.net/display/docs/Installing+OSQA+on+CentOS6?focusedCommentId=4784144 Thanks in advance for your help.

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  • CentOS 6.5 as WebServer for Django Dev

    - by Charlesliam
    During CentOS 6.5 Installation I choose WebServer type for this computer. The server has a static IP address 192.168.111.100. The CentOS was updated I managed to install virtualenv with Python 2.7. Within the virtualenv, I'll be using Django Framework. After I tried to run the command using root user python manage.py runserver 0.0.0.0:8000 I can't see the website from other computer within the LAN when I try to type 192.168.111.100:8000/admin on my browser. I already disable firewall using service iptables stop I can ping the 192.168.111.100 and I have a good feedback with nslookup. What seems the problem of my config?

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  • django + wsgi + suexec + userdir + apache?

    - by Jayen
    I've got a django 1.1 website I want to run in wsgi (as that seems to be the recommended deployment on apache). I want it to run as the www user (apache is running as www-data). I would ideally like this to work out of http://hostname/~www/ (~www/public_html) as well as http://virtualhostname/. I also want this to work for other users who may later use wsgi. Can I make this happen? I've been staring at docs trying to figure where to start, but I'm having trouble combining userdir and wsgi to let me run ~xxx/public_html/index.wsgi as user xxx, for every user xxx.

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  • Different settings for secure & non-secure versions of Django site using WSGI

    - by Jordan Reiter
    I have a Django website where some of the URLs need to be served over HTTPS and some over a normal connection. It's running on Apache and using WSGI. Here's the config: <VirtualHost example.org:80> ServerName example.org DocumentRoot /var/www/html/mysite WSGIDaemonProcess mysite WSGIProcessGroup mysite WSGIScriptAlias / /path/to/mysite/conferencemanager.wsgi </VirtualHost> <VirtualHost *:443> ServerName example.org DocumentRoot /var/www/html/mysite WSGIProcessGroup mysite SSLEngine on SSLCertificateFile /etc/httpd/certs/aace.org.crt SSLCertificateKeyFile /etc/httpd/certs/aace.org.key SSLCertificateChainFile /etc/httpd/certs/gd_bundle.crt WSGIScriptAlias / /path/to/mysite/conferencemanager_secure.wsgi </VirtualHost> When I restart the server, the first site that gets called -- https or http -- appears to select which WSGI script alias gets used. I just need a few settings to be different for the secure server, which is why I'm using a different WSGI script. Alternatively, it there's a way to change settings in the settings.py file based on whether the connection is secure or not, that would also work. Thanks

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  • idle proccesses and high memory bad? uwsgi/django

    - by JimJimThe3rd
    I have a VPS with 256MB of ram. I'm running nginx, uwsgi and postgresql on Ubuntu 12.04 for a soon to be Django site. About 200MB of ram are being used despite the website not being active, the uwsgi processes seem to just be idling. Is this bad? I once heard that having a bunch of free memory isn't necessarily a good metric because it is possible that the memory in use can easily be freed up. I mean, it is possible that the server is storing commonly used "stuff" in case it is accessed but is more than happy to dump it if the ram is needed. But I'm really not sure, hence me asking this question. If it is bad I could set some of the application loading options for uwsgi like "cheap" or "idle" mode. Screenshot of my htop

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  • django fcgi - call a management command with subprocess.Popen

    - by user41855
    Hi, I'm using an app called django-chronograph. It has a code of line which works in my dev environment and does not work in production: p = subprocess.Popen(['python', get_manage_py(), 'run_job', str(self.pk)]) This line crashes in production with: unknown command run_job Whereas when I run directly from command line: manage.py run_job It works fine. Interestingly it worked once when we exchanged 'python' with 'usr/bin/python'. then we restarted the server once more and it was back to old behaviour. Thus it seems as we have a python path issue. I'm not the guy who is running the server, its my app that should run and it would be great to get some help here. Attention: I'm a total noob regarding server-administration.. server environment: NGINX with FCGI-Daemon FCGI in prefork-mode

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  • How do I upgrade Django 1.3.1 to 1.4? Any tips, tutorials, or warnings?

    - by hobbes3
    Django 1.4 was recently released. Almost all the information about Django 1.4 is in the release note, but I didn't see anything about how to upgrade. Should I just remove the django folder inside Python's site-packges and download 1.4? I think I originally installed Django using emerge and yum but I'm not sure if the package management systems are up-to-date with Django 1.4 yet. That might be ok on my server instance (Gentoo Linux), but on my local instance I am using virtualenvwrapper (on Mac OS 10.7), so maybe I want to create a new Python virtual environment for Djago 1.4. Or maybe not since I don't really care about backward compatibility with 1.3.1.

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  • Django - Moving database from development to production servers

    - by Garfonzo
    I am working on a Django project with a MySQL backend. I'm curious about the best way to update a production server's database to reflect the changes made on the development server's database? When I develop now, I make some changes to a models.py file, then to a schemamigration using South. Sometimes I do several migrations across several apps within the main project folder before it's ready for the production database. This means that there are several migration files in the app/migrations/ folder created by South. So on the production server, how does one update the database to reflect all the changes made in development, without having any data loss?

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  • Setting up Django application on lighttpd behind apache reverse proxy

    - by ml256
    I have a Django app at http://some_other_example.com (it will be behind firewall) running on lighttpd server with fastcgi. I need make it available under http://example.com/myapp. It works fine except for redirects - when I login from http://example.com/myapp/login it redirects me to http://example.com instead of http://example.com/myapp. When logging-in from http://some_other_example.com/login it is ok. My configuration: apache2.conf at example.com: ProxyPass /myapp http://some_other_example.com ProxyPassReverse /myapp http://some_other_example.com ProxyHTMLURLMap http://some_other_example.com /myapp <Location /myapp> SetOutputFilter proxy-html ProxyHTMLExtended On ProxyHTMLURLMap / /myapp/ </Location> in settings.py I added USE_X_FORWARDED_HOST = True but it didn't help

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  • Unable to run Django on Mac OS X

    - by cybervaldez
    I'm working with a Django project on my Mac (running Leopard) and I want to show it to my team. I've already passed the neccessary port forwards from my router to my Mac's LAN IP address but it doesn't work. I've also tried running the XAMPP server since that always worked with my Windows XP computer but it still doesn't work. Whenever I type my > it's showing a Page Load Error. Is this possibly an issue with an Mac OS X configuration that I need to setup first to allow my port forwards to get in? It's my first time to do this with Mac, perhaps I need to configure something else in network preferences?

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  • Django: Unicode Filenames with ASCII headers?

    - by TheLizardKing
    I have a list of strangely encoded files: 02 - Charlie, Woody and You/Study #22.mp3 which I suppose isn't so bad but there are a few particular characters which Django OR nginx seem to be snagging on. >>> test = u'02 - Charlie, Woody and You/Study #22.mp3' >>> test u'02 - Charlie, Woody and You\uff0fStudy #22.mp3' I am using nginx as a reverse proxy to connect to django's built in webserver (still in development stages) and postgresql for my database. My database and tables are all en_US.UTF-8 and I am using pgadmin3 to view my tables outside of django. My issue goes a little beyond my title, firstly how should I be saving possibly whacky filenames in my database? My current method is 'path': smart_unicode(path.lstrip(MUSIC_PATH)), 'filename': smart_unicode(file) and when I pprint out the values they do show u'whateverthecrap' I am not sure if that is how I should be doing it but assuming it is now I have issues trying to spit out the download. My download view looks something like this: def song_download(request, song_id): song = get_object_or_404(Song, pk=song_id) url = u'/static_music/%s/%s' % (song.path, song.filename) print url response = HttpResponse() response['X-Accel-Redirect'] = url response['Content-Type'] = 'audio/mpeg' response['Content-Disposition'] = "attachment; filename=test.mp3" return response and most files will download but when I get to 02 - Charlie, Woody and You/Study #22.mp3 I receive this from django: 'ascii' codec can't encode character u'\uff0f' in position 118: ordinal not in range(128), HTTP response headers must be in US-ASCII format. How can I use an ASCII acceptable string if my filename is out of bounds? 02 - Charlie, Woody and You\uff0fStudy #22.mp3 doesn't seem to work... EDIT 1 I am using Ubuntu for my OS.

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  • Cannot turn off autocommit in a script using the Django ORM

    - by Wes
    I have a command line script that uses the Django ORM and MySQL backend. I want to turn off autocommit and commit manually. For the life of me, I cannot get this to work. Here is a pared down version of the script. A row is inserted into testtable every time I run this and I get this warning from MySQL: "Some non-transactional changed tables couldn't be rolled back". #!/usr/bin/python import os import sys django_dir = os.path.abspath(os.path.normpath(os.path.join(os.path.dirname(__file__), '..'))) sys.path.append(django_dir) os.environ['DJANGO_DIR'] = django_dir os.environ['DJANGO_SETTINGS_MODULE'] = 'myproject.settings' from django.core.management import setup_environ from myproject import settings setup_environ(settings) from django.db import transaction, connection cursor = connection.cursor() cursor.execute('SET autocommit = 0') cursor.execute('insert into testtable values (\'X\')') cursor.execute('rollback') I also tried placing the insert in a function and adding Django's commit_manually wrapper, like so: @transaction.commit_manually def myfunction(): cursor = connection.cursor() cursor.execute('SET autocommit = 0') cursor.execute('insert into westest values (\'X\')') cursor.execute('rollback') myfunction() I also tried setting DISABLE_TRANSACTION_MANAGEMENT = True in settings.py, with no further luck. I feel like I am missing something obvious. Any help you can give me is greatly appreciated. Thanks!

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  • Django users and authentication from external source

    - by Boldewyn
    I have a Django app that gets it's data completely from an external source (queried via HTTP). That is, I don't have the option for a local database. Session data is stored in the cache (on my development server I use a SQLite database, so that is no error source). I'm using bleeding edge Django 1.1svn. Enter the problem: I want to use Django's own authentication system for the users. It seems quite simple to write my own Authentication Backend, but always just under the condition that you have a local database where to save the users. Without database my main problem is persistence. I tried it with the following (assume that datasource.get() is a function that returns some kind of dict): class ModelBackend (object): """Login backend.""" def authenticate (self, username=None, password=None): """Check, if a given user/password combination is valid""" data = datasource.get ('login', username, password) if data and data['ok']: return MyUser (username=username) else: raise TypeError return None def get_user (self, username): """get data about a specific user""" try: data = datasource.get ('userdata', username) if data and data['ok']: return data.user except: pass return None class MyUser (User): """Django user who isn't saved in DB""" def save (self): return None But the intentionally missing save() method on MyUser seems to break the session storage of a login. How should MyUser look like without a local database?

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