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  • How to mount encrypted volume at login (Ubuntu 12.04, pam_mount)

    - by Nick Lothian
    I'm trying to get pam_mount working on Ubuntu 12.04. I have /dev/sda1 (encrypted partition) with /dev/dm-1 (ext4 formatted) inside it. Should ~/.pam_mount.conf.xml be trying to mount /dev/sda1 or /dev/dm-1? If I use the line: <volume fstype="ext4" path="/dev/dm-1" mountpoint="~/slowstore" options="rw" /> then it nearly works. It prompts for the password (ok, I'd like pam_mount to do that for me, but still..) then I get: pam_mount(rdconf2.c:126): checking sanity of luserconf volume record (/dev/dm-1) pam_mount(rdconf2.c:132): user-defined volume (/dev/dm-1), volume not owned by user If I do: sudo chown nick:disk /dev/dm-1 Then re-login the encrypted partition mounts correctly (ignoring th fact I have to reneter the password). However, if I log out completely the ownership on /dev/dm-1 gets reset to root:disk. What am I doing wrong?

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  • Touchpad not working after login in Ubuntu

    - by Maria Mateescu
    At some point my touchpad stopped working on Lenovo x220 under Ubuntu 11.10, after login. I have found two possible solutions for that online, but neither of them work. First, gconftool-2 --set --type boolean /desktop/gnome/peripherals/touchpad/touchpad_enabled true and a second one, xinput set-int-prop "SynPS/2 Synaptics TouchPad" "Synaptics Off" 8 0 After looking more carefully into xinput I have realized that xinput list-props "SynPS/2 Synaptics TouchPad" outputs: Device Enabled (132): 0 This field seems to be stuck to zero, because trying to set it back to 1 by: xinput set-int-prop "SynPS/2 Synaptics TouchPad" "Device Enabled" 8 1 doesn't seem to have any effect, e.g. I still have: Device Enabled (132): 0 Any ideas? Thank you!

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  • What''s the "earliest" place one can set an environment variable during Linux boot process?

    - by amn
    I know I can set a variable in a shell startup file, but the thing is, I am trying to set up a POSIX-compatible environment, and a POSIX shell does not parse any startup files other than the one specified by the environment variable ENV. This presents a problem - currently my login starts the shell as bash, which I will try to replace with sh so Bash runs as POSIX shell - however then it will not parse the default startup files and I need ENV set to specify these. Which means as far as I understand that I need to specify ENV before login starts the shell, correct? Now, how would I do that? I hope my question is clear, if not I will gladly redact it.

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  • Terminal Server 2003 Login Issue - Insufficient system resources exist to complete the requested ser

    - by LP
    Afternoon. We have three identical terminal servers running Windows Server 2003 SP2, on these servers there are about 250 concurrent users logged on. We're running Roaming Profiles on a central server running Active Directory which cache the profiles locally on each terminal server as well. When one, and just that one, user tries to login she gets this error message (roughly translated from Swedish): "You could not be logged in becouse your principle could not be registered. Check that you're connected to the network or ask your administrator Insufficient system resources exist to complete the requested service." Anyone have an idea about this? I'm stumped ... Best Regards LP

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  • Need a GUI app for group policy login script

    - by jayPal
    I wrote a C# 4.0 application that works on a Windows computer but when using Group Policy to set it as a login script, it does not run. The application is being called from the same location and using rsop.msc shows that the application should be run. I see that using C# 4.0 may be a little overkill for this purpose, but it just seems wrong to write a VB6 application to do the same thing. The requirements for the application states that there need to be specific GUI elements that can't be just text on the window. I need larger fonts and color elements. Is there something more appropriate (and current) that I should be using?

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  • Help with user login on Centos 5.6

    - by Owen
    I added a user for the sole purpose of using SU for root. I did not allow the creation of a home directory when creating the user. So now when I login as this user I get the following: Could not chdir to home directory /home/MYUSERNAME: No such file or directory Couldn't resolve homedir for current user at - line 0 BEGIN failed--compilation aborted. Couldn't resolve homedir for current user at - line 0 BEGIN failed--compilation aborted. Is this an error, and if so how do I fix it so it is not looking to "resolve" the homedir?

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  • Limit access on login and IP in .htaccess

    - by Rob
    There are many examples showing how to use .htaccess to restrict users by login or on their IP address (i.e they are ok from the ones given without authorisation). For some reason the following is never mentioned, yet it seems quite useful. How do I restrict using groups and ip, e.g. group1 can access the page from anywhere group2 can access the page only from certain IP addresses if you are not logged on, you cant see the page, regardless where you are I would like to have all 3 of these working at the same time.

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  • Can't get to the login screen

    - by Rod
    I upgraded my wife's Windows 7 machine, to Windows 8 Pro, about 10 days ago. She's been using it fine ever since. We typically leave our desktops running 24/7, and just turn off the monitor. This morning she turned the monitor on, and saw the screen with the Seattle Space Needle, and then she pressed the enter key to get to the login screen. Nothing happened. Next she pressed the mouse key. Nothing happened. The mouse moves around fine. But we can't get it past the Seattle Space Needle screen. She replaced the batteries in both her keyboard and mouse recently. So, what's going on? How do we fix it?

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  • Citrix on ESX 4 U1 - Slow login times

    - by thomps01
    I'm sure they'd be just as slow if not slower using ESX 3 but I'm looking for some assistance. On a physical Citrix server, logins are 1 - 4 seconds. The virtual - 16 - 23 seconds. I'm looking for performance enhancements that I can make to me VMs to try and reduce the login wait times. The hardware is fine (HP BL685 (24 cores, 64GB RAM). And there's nothing pushing it yet. Network 10Gb I'm planning to test the configuration with VMXNET3 tomorrow, but does anyone have a list a best practices I can use when testing?

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  • FaceBook Login Problem

    - by toman
    Hi All, I am for an application which extracts information from facebook search, hence i require to login facebook. i have registered my application in facebook developers site and have got api key and secret key. in my code i am getting an exception when i am trying to login. Here is my code for login to facebook: import com.facebook.api.FacebookRestClient; import org.apache.commons.httpclient.HttpClient; import org.apache.commons.httpclient.HttpState; import org.apache.commons.httpclient.NameValuePair; import org.apache.commons.httpclient.methods.GetMethod; import org.apache.commons.httpclient.methods.PostMethod; import org.apache.commons.httpclient.params.HttpClientParams; public class FaceLogin { public FaceLogin(){ getUserID("username", "password"); } private static void getUserID(String email, String password) { String session = null; try { HttpClient http = new HttpClient(); http.setParams(new HttpClientParams()); //http.getHostConfiguration().setHost("http://www.facebook.com/"); http.setState(new HttpState()); String api_key = "****some key****"; String secret = "****some key****"; FacebookRestClient client = new FacebookRestClient(api_key, secret); client.setIsDesktop(true); String token = client.auth_createToken(); final String loginId = "http://www.facebook.com/login.php"; GetMethod get = new GetMethod(loginId + "?api_key=" + api_key + "&v=1.0&auth_token=" +token); System.out.println("Get="+get); http.executeMethod(get); PostMethod post = new PostMethod(loginId); post.addParameter(new NameValuePair("api_key", api_key)); post.addParameter(new NameValuePair("v", "1.0")); post.addParameter(new NameValuePair("auth_token", token)); post.addParameter(new NameValuePair("fbconnect","true")); post.addParameter(new NameValuePair("return_session","true")); post.addParameter(new NameValuePair("session_key_only","true")); post.addParameter(new NameValuePair("req_perms","read_stream,publish_stream")); post.addParameter(new NameValuePair("lsd","8HYdi")); post.addParameter(new NameValuePair("locale","en_US")); post.addParameter(new NameValuePair("persistent","1")); post.addParameter(new NameValuePair("email", email)); post.addParameter(new NameValuePair("pass", password)); System.out.println("Token ="+token); int postStatus = http.executeMethod(post); System.out.println("Response : " + postStatus); session = client.auth_getSession(token); // Here I am getting error System.out.println("Session string: " + session); long userid = client.users_getLoggedInUser(); System.out.println("User Id is : " + userid); } catch (Exception e) { e.printStackTrace(); } } public static void main(String k[]) { FaceLogin facebookLoginObj=new FaceLogin(); } } I am getting the following exception: org.apache.commons.httpclient.HttpMethodBase processResponseHeaders WARNING: Cookie rejected: "$Version=0; $Domain=deleted; $Path=/; $Domain=.facebook.com". Cookie name may not start with $ Response : 200 Jun 8, 2010 2:07:36 PM org.apache.commons.httpclient.HttpMethodBase processResponseHeaders WARNING: Cookie rejected: "$Version=0; $Path=deleted; $Path=/; $Domain=.facebook.com". Cookie name may not start with $ Facebook returns error code 100 com.facebook.api.FacebookException: Invalid parameter - v - 1.0 at com.facebook.api.FacebookRestClient.callMethod(FacebookRestClient.java:828) - auth_token - 004e90dc8818d5f0921d1065d24508d3 at com.facebook.api.FacebookRestClient.callMethod(FacebookRestClient.java:606) - method - facebook.auth.getSession - call_id - 1275986256796 - api_key - f7cb1e48c383ef599da9021fc4dec322 at com.facebook.api.FacebookRestClient.auth_getSession(FacebookRestClient.java:1891) at facebookcrawler.FacebookLogin.getUserID(FacebookLogin.java:81) at facebookcrawler.FacebookLogin.( - sig - 9344ec75b74a0a87bcae645046d45da8 FacebookLogin.java:24) at facebookcrawler.FaceLogin.main(FaceLogin.java:80) Here may be the problem is for creating session, i searched for all the solutions on net but could not helped me to get login. Please help me if you can suggest me some way to resolve this problem. i thanks to all your valuable suggestion.

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  • mobile browsers' can't login to my site

    - by imin
    i've tested my site on 2 phone models using the 'generic' browser that came with the phone, but sadly, everytime I tried to login, it will return me back to my index page. here's my login code <form name='login' method='POST' action='authentication.php'> <table border=0 cellpadding=2> <tr><td>Login:</td><td></td></tr> <tr><td>E-mail: </td><td><input type=text name='email' id='email' size=20 maxlength="200"></td></tr> <tr><td>Password: </td><td><input type=password name='password' id='password' size=20 maxlength="100"></td></tr> <tr><td></td><td><input type=submit value='Login'></td></tr> </table></form> and here's the authentication.php (snippet) $currentUserEmail = $_POST["email"]; $currentUserPwd = md5($_POST["password"]); $stmt = $dbi->prepare("select status from users where email=? and pwd=?"); $stmt->bind_param('ss', $currentUserEmail,$currentUserPwd); mysqli_stmt_execute($stmt); mysqli_stmt_store_result($stmt); $isUserAvailable = mysqli_stmt_num_rows($stmt); $stmt->bind_result($getUserStatus); $stmt->execute() or die (mysqli_error()); $stmt->store_result(); $stmt->fetch(); $stmt->close(); if($isUserAvailable > 0){ if ($getUserStatus == "PENDING") { $userIsLoggedIn = "NO"; $registeredUser = "NO"; unset($userIsLoggedIn); setcookie("currentMobileUserName", "", time()-3600); setcookie("currentMobileUserEmail", "", time()-3600); setcookie("currentMobileSessionID", "", time()-3600); setcookie("currentMobileUID", "", time()-3600); header('Location: '.$config['MOBILE_URL'].'/index.php?error=2&email='.$currentUserEmail); }elseif (($getUserStatus == "ACTIVE") || ($getUserStatus == "active")){ //means successfully logged in //set the cookie setcookie("currentMobileUserName", $currentUserName, $expire); setcookie("currentMobileUserEmail", $currentUserEmail, $expire); setcookie("currentMobileSessionID", $getGeneratedMobileUSID, $expire); setcookie("currentMobileUID", $currentUID, $expire); $userIsLoggedIn = "YES"; $registeredUser = "YES"; $result = $stmt->execute() or die (mysqli_error($dbi)); if ($caller == "indexLoginForm"){ header('Location: '.$config['MOBILE_URL'].'/home.php'); }else{ header('Location: '.$config['MOBILE_URL'].'/home.php'); } } }else{ $userIsLoggedIn = "NO"; $registeredUser = "NO"; unset($userIsLoggedIn); setcookie("currentMobileUserName", "", time()-3600); setcookie("currentMobileUserEmail", "", time()-3600); setcookie("currentMobileSessionID", "", time()-3600); setcookie("currentMobileUID", "", time()-3600); header('Location: '.$config['MOBILE_URL'].'/index.php?error=1'); } The only way I can access my mobile site is by using opera mini. Just FYI, both the 'generic browsers' i tested my site with supports cookie (at least this is what the browser settings said). thanks

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  • SQL SERVER – FIX ERROR – Cannot connect to . Login failed. The login is from an untrusted domain and cannot be used with Windows authentication. (Microsoft SQL Server, Error: 18452)

    - by pinaldave
    Just a day ago, I was doing small attempting to connect to my local SQL Server using IP 127.0.0.1. The IP is of my local machine and SQL Server is installed on the local box as well. However, whenever I try to connect to the server it gave me following strange error. Cannot connect to 127.0.0.1. Login failed. The login is from an untrusted domain and cannot be used with Windows authentication. (Microsoft SQL Server, Error: 18452) The reason was indeed strange as I was trying to connect from local box to local box and it said my login was from an untrusted domain. As my system is not part of any domain, this was really confusing to me. Another thing was that I have been always able to connect always using 127.0.0.1 to SQL Server and this was a bit strange to me. I started to think what did I change since it  last time I connected to SQL Server. Suddenly I remembered that I had modified my computer’s host file for some other purpose. Solution: I opened my host file and immediately added entry like 127.0.0.1 localhost. Once I added it I was able to reconnect to SQL Server as usual. The location of the host file is C:\Windows\System32\drivers\etc. You will find file with the name hosts in it, make sure to open it with notepad. If you are part of a domain and your organization is using active directory, make sure that your account is added properly to active directory as well have proper security permissions to execute the task. Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Error Messages, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Vagrant - Failed login, ssh not set up

    - by motleydev
    This question is two fold because somewhere in my attempts to solve the problem, I created a new one. First: I was trying to vagrant up using a Vagranfile based on the standard hashicorp/precise32 box. Everything worked up until default: SSH auth method: private key where it would eventually time out. Enabling gui in the Vagrantfile showed that the machine never actually logs in. I can use the standard user/pass and log in from that point but the vagrant up process still remains at that prior status. Here's where my understanding might be a little dim. I've tried setting auth method from the insecure_pass_key to my root ~/.ssh/id_rsa or whichever one I wanted to use. I'm not entirely sure where to put a copy of the public key or my authorized keys file. I've got a .vagrant.d folder in my user dir (I'm on OSX) which seems to contain the box images. I've got a .vagrant folder in my directory with the Vagrantfile which seems to contain the specific machine I am building off of. I've tried pouring over the docs and forums but I seem to be missing a key concept here. And Now: After a host of tips/tricks such as rolling back by VirtualBox install, uninstalling/reinstalling Vagrant and VritualBox several times, when I try to run vagrant ssh-config with a Vagrantfile based on the same hashicorp/precise32 it says that the box is not enabled for SSH. Specifically, this error: The provider for this Vagrant-managed machine is reporting that it is not yet ready for SSH. Depending on your provider this can carry different meanings. Make sure your machine is created and running and try again. Additionally, check the output of `vagrant status` to verify that the machine is in the state that you expect. If you continue to get this error message, please view the documentation for the provider you're using. So now I am slightly up a creek. Any help would be appreciated if not just clarifying a concept. Some pertinent info: I'm on OSX Maverics Due to the fact I'm running a dual HD system with system files on one HD and user files on another, my permissions are a little wonky and VBoxManage will only let me run commands via Sudo - not sure if it's pertinent - but maybe. I have no idea what I'm doing. That part is perhaps more important.

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  • Windows 8 with LiveID login authenticates as Guest to remote SQl Server

    - by Tim Long
    I have a network where several users are using Office Accounting 2009 in multi-user client/server mode. OA is built on SQL Server. One PC acts as the 'server' and has the SQl Server instance, the others have only the application installed and no SQL instance, all of the apps connect remotely to the SQL instance on the 'server'. I'm using the term 'server' loosely here, it is just a normal workstation that happens to be designated as the server and runs the SQL instance. There is no NT domain, all user accounts are local accounts. The way that OA works in multi-user mode is that each user is required to have a local account with the same username and password on both the client and 'server' PCs. This has been working well, no along comes Windows 8. I use my 'Microsoft Account' aka LiveID to log into Windows 8. Office Accounting runs fine and attempts to connect to the database, but fails, 'you do not have permission to perform this operation'. In the SQL logs, I get this error: 2012-10-28 17:54:01.32 Logon Error: 18456, Severity: 14, State: 11. 2012-10-28 17:54:01.32 Logon Login failed for user 'SERVER\Guest'. Reason: Token-based server access validation failed with an infrastructure SERVER is the hostname of the server. So it seems to be authenticating as 'Guest'?? To verify this, I enabled the Guest account on the 'server' PC and then added Guest as an allowed user within Office Accounting (this simply creates the user in SQL and gives it an appropriate database role). Sure enough, My Windows 8 PC was then able to connect to the database when using Office Accounting. Clearly, having users authenticate as 'Guest' stinks from a security and auditing standpoint. So what I need are some ideas for how to work around this. I've tried switching the Windows 8 PC to a 'local account' and that works too, but requires giving up significant functionality on the Windows 8 PC. What I really need is a way to force the Windows 8 PC to use a specific set of credentials when connecting to the remote SQL instance. Office Accounting takes the logged in username, which is my LiveID and doesn't correspond to any Windows user name. Anyone solved this issue?

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  • SQL Server 2008 - Login failed. The login is from an untrusted domain and cannot be used with Window

    - by Tom
    I've just installed SQL Server 2008 Developer edition and I'm trying to connect using SQLCMD.exe, but I get the following error: H:\>sqlcmd.exe -S ".\SQL2008" Msg 18452, Level 14, State 1, Server DEVBOX\SQL2008, Line 1 Login failed. The login is from an untrusted domain and cannot be used with Windows authentication. Has anyone seen this before? Any idea what it means??

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  • problem in login in yahoo massanger

    - by khoyendra
    package session; import java.io.FileWriter; import java.text.DateFormat; import java.text.SimpleDateFormat; import javax.swing.JOptionPane; import org.openymsg.network.FireEvent; import org.openymsg.network.Session; import org.openymsg.network.SessionState; import org.openymsg.network.event.SessionListener; public class BotGUI extends javax.swing.JFrame implements SessionListener{ /** Creates new form BotGUI */ FileWriter fw; DateFormat dateFormat = new SimpleDateFormat("yyyy/MM/dd HH:mm:ss"); public BotGUI() { initComponents(); } @SuppressWarnings("unchecked") // <editor-fold defaultstate="collapsed" desc="Generated Code"> private void initComponents() { jPanel1 = new javax.swing.JPanel(); jPanel2 = new javax.swing.JPanel(); jPanel3 = new javax.swing.JPanel(); jLabel1 = new javax.swing.JLabel(); jPanel4 = new javax.swing.JPanel(); jLabel2 = new javax.swing.JLabel(); jLabel3 = new javax.swing.JLabel(); uNameTextField = new javax.swing.JTextField(); uPassPasswordField = new javax.swing.JPasswordField(); jButton1 = new javax.swing.JButton(); jMenuBar1 = new javax.swing.JMenuBar(); jMenu1 = new javax.swing.JMenu(); jMenuItem1 = new javax.swing.JMenuItem(); jMenuItem2 = new javax.swing.JMenuItem(); jMenuItem3 = new javax.swing.JMenuItem(); jMenu2 = new javax.swing.JMenu(); setDefaultCloseOperation(javax.swing.WindowConstants.EXIT_ON_CLOSE); jPanel2.setLayout(new org.netbeans.lib.awtextra.AbsoluteLayout()); jPanel3.setBackground(new java.awt.Color(51, 51, 51)); jLabel1.setBackground(new java.awt.Color(0, 0, 255)); jLabel1.setFont(new java.awt.Font("Tahoma", 1, 12)); jLabel1.setForeground(new java.awt.Color(255, 255, 255)); jLabel1.setText("Yahoo Login Panel"); javax.swing.GroupLayout jPanel3Layout = new javax.swing.GroupLayout(jPanel3); jPanel3.setLayout(jPanel3Layout); jPanel3Layout.setHorizontalGroup( jPanel3Layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addGroup(jPanel3Layout.createSequentialGroup() .addGap(38, 38, 38) .addComponent(jLabel1, javax.swing.GroupLayout.PREFERRED_SIZE, 140, javax.swing.GroupLayout.PREFERRED_SIZE) .addContainerGap(532, Short.MAX_VALUE)) ); jPanel3Layout.setVerticalGroup( jPanel3Layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addComponent(jLabel1, javax.swing.GroupLayout.Alignment.TRAILING, javax.swing.GroupLayout.DEFAULT_SIZE, 30, Short.MAX_VALUE) ); jPanel2.add(jPanel3, new org.netbeans.lib.awtextra.AbsoluteConstraints(0, 0, 710, 30)); jPanel4.setLayout(new org.netbeans.lib.awtextra.AbsoluteLayout()); jLabel2.setText("Username"); jPanel4.add(jLabel2, new org.netbeans.lib.awtextra.AbsoluteConstraints(30, 20, 60, 20)); jLabel3.setText("Password"); jPanel4.add(jLabel3, new org.netbeans.lib.awtextra.AbsoluteConstraints(270, 20, 60, 20)); jPanel4.add(uNameTextField, new org.netbeans.lib.awtextra.AbsoluteConstraints(100, 20, 140, 20)); jPanel4.add(uPassPasswordField, new org.netbeans.lib.awtextra.AbsoluteConstraints(330, 20, 140, -1)); jButton1.setFont(new java.awt.Font("Tahoma", 1, 14)); // NOI18N jButton1.setText("Login"); jButton1.addActionListener(new java.awt.event.ActionListener() { public void actionPerformed(java.awt.event.ActionEvent evt) { jButton1ActionPerformed(evt); } }); jPanel4.add(jButton1, new org.netbeans.lib.awtextra.AbsoluteConstraints(490, 15, 90, -1)); jPanel2.add(jPanel4, new org.netbeans.lib.awtextra.AbsoluteConstraints(0, 30, 710, 60)); javax.swing.GroupLayout jPanel1Layout = new javax.swing.GroupLayout(jPanel1); jPanel1.setLayout(jPanel1Layout); jPanel1Layout.setHorizontalGroup( jPanel1Layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addComponent(jPanel2, javax.swing.GroupLayout.DEFAULT_SIZE, javax.swing.GroupLayout.DEFAULT_SIZE, Short.MAX_VALUE) ); jPanel1Layout.setVerticalGroup( jPanel1Layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addGroup(jPanel1Layout.createSequentialGroup() .addComponent(jPanel2, javax.swing.GroupLayout.PREFERRED_SIZE, 135, javax.swing.GroupLayout.PREFERRED_SIZE) .addContainerGap(293, Short.MAX_VALUE)) ); jMenu1.setText("Option"); jMenuItem1.setText("Logout"); jMenu1.add(jMenuItem1); jMenuItem2.setText("Load CSV"); jMenu1.add(jMenuItem2); jMenuItem3.setText("Exit"); jMenu1.add(jMenuItem3); jMenuBar1.add(jMenu1); jMenu2.setText("Help"); jMenuBar1.add(jMenu2); setJMenuBar(jMenuBar1); javax.swing.GroupLayout layout = new javax.swing.GroupLayout(getContentPane()); getContentPane().setLayout(layout); layout.setHorizontalGroup( layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addComponent(jPanel1, javax.swing.GroupLayout.DEFAULT_SIZE, javax.swing.GroupLayout.DEFAULT_SIZE, Short.MAX_VALUE) ); layout.setVerticalGroup( layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addComponent(jPanel1, javax.swing.GroupLayout.DEFAULT_SIZE, javax.swing.GroupLayout.DEFAULT_SIZE, Short.MAX_VALUE) ); pack(); }// </editor-fold> public void handleConnectionClosed() { connectionClosed = true; loggedIn = false; } private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) { if(!uNameTextField.getText().equals("") && !uPassPasswordField.getText().equals("")){ Yahoo_login(uNameTextField.getText(),uPassPasswordField.getText()); }else{ JOptionPane.showMessageDialog(null, "Plese Enter User Id and Password"); } } Session yahooMessengerSession; MySessionListener mySessionListener; boolean loggedIn = false; boolean connectionClosed = false; public void Yahoo_login(String uName, String pass) { connectionClosed = false; if (loggedIn == false) { yahooMessengerSession = new Session(); mySessionListener = new MySessionListener(this); yahooMessengerSession.addSessionListener(mySessionListener); try { if ((uName.equals("")) || (pass.equals(""))) { System.out.println("User name/password is blank"); } else{ //initialized a file writer for log file System.out.println("Login start........"); yahooMessengerSession.login(uName, pass, true); //checks whether user was succesful in login in if (yahooMessengerSession!=null && yahooMessengerSession.getSessionStatus()== SessionState.LOGGED_ON) { //this loop is reached when the user has been successfully logined System.out.println("Login Success"); fw.write("User (" + uName + ") logged in at : " + dateFormat.format("09.05.10") + " \n"); fw.close(); } else { yahooMessengerSession.reset(); } } } catch(Exception e){ } } } public static void main(String args[]) { java.awt.EventQueue.invokeLater(new Runnable() { public void run() { new BotGUI().setVisible(true); } }); } // Variables declaration - do not modify private javax.swing.JButton jButton1; private javax.swing.JLabel jLabel1; private javax.swing.JLabel jLabel2; private javax.swing.JLabel jLabel3; private javax.swing.JMenu jMenu1; private javax.swing.JMenu jMenu2; private javax.swing.JMenuBar jMenuBar1; private javax.swing.JMenuItem jMenuItem1; private javax.swing.JMenuItem jMenuItem2; private javax.swing.JMenuItem jMenuItem3; private javax.swing.JPanel jPanel1; private javax.swing.JPanel jPanel2; private javax.swing.JPanel jPanel3; private javax.swing.JPanel jPanel4; private javax.swing.JTextField uNameTextField; private javax.swing.JPasswordField uPassPasswordField; // End of variables declaration public void dispatch(FireEvent fe) { throw new UnsupportedOperationException("Not supported yet."); } } i have to find the error SEVERE: error during the dispatch of event: FireEvent [org.openymsg.network.event.SessionListEvent to:null from:null message:null timestamp:0 status:0 list type:Friends size:2 LIST] java.lang.UnsupportedOperationException: Not supported yet. at yahoomessangerbot.MySessionListener.dispatch(MySessionListener.java:131) at org.openymsg.network.EventDispatcher.runEventNOW(EventDispatcher.java:133) at org.openymsg.network.EventDispatcher.run(EventDispatcher.java:114)

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  • unable to login in to phpbb through session of wesite

    - by pramod4u
    With the below code we unable to session ingrate please help us how to integrate is there any modification let give modification. Thank you <?php session_start(); include "conn.php"; include "PHPBB_Login.php"; echo $_SESSION['username']; $data=mysql_query("select * from people where username='".$_SESSION['username']."'"); $data_data=mysql_fetch_array($data); echo $_SESSION['username']; $_SESSION['username']=$data_data['username']; echo $_SESSION['username']; $phpbbq=mysql_query("select user_id from phpbb_users where username='".$data_data['username']."'"); $phpbbr=mysql_fetch_array($phpbbq); //echo $phpbbr['user_id']; $id=$phpbbr['user_id']; $phpbb->login($id ); ?> <? class PHPBB_Login { function PHPBB_Login() { } function login($phpbb_user_id) { $id=$phpbb_user_id ; global $db, $board_config; global $HTTP_COOKIE_VARS, $HTTP_GET_VARS, $SID; // Setup the phpbb environment and then // run through the phpbb login process // You may need to change the following line to reflect // your phpBB installation. require_once('./phpBB-3.0.7-PL1/phpBB3/config.php'); define('IN_PHPBB',true); // You may need to change the following line to reflect // your phpBB installation. $phpbb_root_path = "./phpBB-3.0.7-PL1/phpBB3/"; require_once( $phpbb_root_path . "extension.inc" ); require_once( $phpbb_root_path . "common.php" ); // return session_begin($id,$user_ip, PAGE_INDEX, FALSE, TRUE ); return session_begin($id,$user_ip, PAGE_INDEX, FALSE, $autologin, '0'); } function logout( $session_id, $phpbb_user_id ) { global $db, $lang, $board_config; global $HTTP_COOKIE_VARS, $HTTP_GET_VARS, $SID; // Setup the phpbb environment and then // run through the phpbb login process // You may need to change the following line to reflect // your phpBB installation. require_once( './phpBB-3.0.7-PL1/phpBB3/config.php' ); define('IN_PHPBB',true); // You may need to change the following line to reflect // your phpBB installation. $phpbb_root_path = "./phpBB-3.0.7-PL1/phpBB3/"; require_once( $phpbb_root_path . "extension.inc" ); require_once( $phpbb_root_path . "common.php" ); session_end( $session_id, $phpbb_user_id ); // session_end doesn't seem to get rid of these cookies, // so we'll do it here just in to make certain. setcookie( $board_config[ "cookie_name" ] . "_sid", "", time() - 3600, " " ); setcookie( $board_config[ "cookie_name" ] . "_mysql", "", time() - 3600, " " ); } } ?>

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  • UML Class Diagram for User Login

    - by 01010011
    Hi, The diagram below is my very first attempt at creating a UML class diagram describing a user login into a website. I'm sure its a poor design and full of flaws, but I'm hoping to learn from you guys how you would design a simple login like this. I'm particularly interested in your use of design patterns and which patterns you would use, how you would implement it in the design, and why. Any advise, criticisms, comments and suggestions will be really appreciated. Thanks in advance.

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  • Login Using HtmlUnit

    - by Sunil
    Hello I am using HtmlUnit to login into the page. I got the userid amd password field and also the submit button .The type of submit button is image . and I fill the userid and password field with values and when I click the button i is unable to login. Thanks in advance.

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  • System.Windows.Forms.WebBrowser login dialog doesn't appear

    - by CalvinCD
    When I navigate to an intranet site requiring windows authentication, the WinForms WebBrowser control isn't displaying a login dialog. But it will display (after refreshing the page) if I first open Internet Explorer and view the same page. Also, if I make the URL refer to my local IIS instance, the login dialog will appear. Any ideas? Thanks!

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  • asp:Login control, remember me is not remembering me

    - by Gogster
    Hi all, I have an ASP.NET login control on a page, with the "Remember Me" checkbox displayed. I have checked in trace and the authentication cookie is being created, I have sliding expiration set and a timeout of 60000, yet when I return to the website the login is not being remembered. Any ideas where else I can check? Thanks, Darryl

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  • CDI SessionScoped Bean instance remains unchanged when login with different user

    - by Jason Yang
    I've been looking for the workaround of this problem for rather plenty of time and no result, so I ask question here. Simply speaking, I'm using a CDI SessionScoped Bean User in my project to manage user information and display them on jsf pages. Also container-managed j_security_check is used to resolve authentication issue. Everything is fine if first logout with session.invalidate() and then login in the same browser tab with a different user. But when I tried to directly login (through login.jsf) with a new user without logout beforehand, I found the user information remaining unchanged. I debugged and found the User bean, as well as the HttpSession instance, always remaining the same if login with different users in the same browser, as long as session.invalidate() not invoked. But oddly, the session id did modified, and I've both checked in Java code and Firebug. org.apache.catalina.session.StandardSessionFacade@5d7b4092 StandardSession[c69a71d19f369d08b5dddbea2ef0] attrName = org.jboss.weld.context.conversation.ConversationIdGenerator : attrValue=org.jboss.weld.context.conversation.ConversationIdGenerator@583c9dd8 attrName = org.jboss.weld.context.ConversationContext.conversations : attrValue = {} attrName = org.jboss.weld.context.http.HttpSessionContext#org.jboss.weld.bean-Discipline-ManagedBean-class com.netease.qa.discipline.profile.User : attrValue = Bean: Managed Bean [class com.netease.qa.discipline.profile.User] with qualifiers [@Any @Default @Named]; Instance: com.netease.qa.discipline.profile.User@c497c7c; CreationalContext: org.jboss.weld.context.CreationalContextImpl@739efd29 attrName = javax.faces.request.charset : attrValue = UTF-8 org.apache.catalina.session.StandardSessionFacade@5d7b4092 StandardSession[c6ab4b0c51ee0a649ef696faef75] attrName = org.jboss.weld.context.conversation.ConversationIdGenerator : attrValue = org.jboss.weld.context.conversation.ConversationIdGenerator@583c9dd8 attrName = com.sun.faces.renderkit.ServerSideStateHelper.LogicalViewMap : attrValue = {-4968076393130137442={-7694826198761889564=[Ljava.lang.Object;@43ff5d6c}} attrName = org.jboss.weld.context.ConversationContext.conversations : attrValue = {} attrName = org.jboss.weld.context.http.HttpSessionContext#org.jboss.weld.bean-Discipline-ManagedBean-class com.netease.qa.discipline.profile.User : attrValue = Bean: Managed Bean [class com.netease.qa.discipline.profile.User] with qualifiers [@Any @Default @Named]; Instance: com.netease.qa.discipline.profile.User@c497c7c; CreationalContext: org.jboss.weld.context.CreationalContextImpl@739efd29 attrName = javax.faces.request.charset : attrValue = UTF-8 Above block contains two successive logins and their Session info. We can see that the instance(1st row) the same while session id(2nd row) different. Seems that session object is reused to contain different session id and CDI framework manages session bean life cycle in accordance with the session object only(?). I'm wondering whether there could be only one server-side session object within the same browser unless invalidated? Since I'm adopting j_security_check I fancy intercepting it and invalidating old session is not so easy. So is it possible to accomplish the goal without altering the CDI+JSF+j_security_check design that one can relogin with different account in the same or different tab within the same browser? Really look forward for your response. More info: Glassfish v3.1 is my appserver.

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  • twitter login button

    - by alexarsh
    HI I have a django application running on app engine and I want to add a twitter login to my application. Do you have a good links how to do that. I already registered my app in twitter. Just don't know how to do login/logout buttons. Thanks, Arshavski Alexander

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