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  • How to add network printer remotely without knowing the IP?

    - by Steve
    Assume your friend from over 100km away asked you to add a network printer to his computer since you're so tech savvy. How would you add network printer remotely in this case? You would need: 0. Remote connection to your friend's computer 1. Printer IP and brand/model names 2. Respective drivers downloaded either from manufacturer's website or Windows Update driver Question is, how would you find out the IP address of the printer without bothering your friend too much with technical steps? Since your friend isn't as tech savvy as you - they wouldn't know which buttons to press to get IP address.

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  • Why do I have inconsistent network issues with my laptop's wireless?

    - by Jason
    I'm having trouble with my laptop Internet connection. It's patchy at best and resets or freezes a lot. The signal strength is also random. I thought it might be a driver issue but now I don't know. Three other computers using the same wireless network run well. I've switched out wireless routers so I don't think it's the router. I thought it might be the laptop's internal wireless card but I just bought an external USB network card and I'm still having problems. Specs Lenovo T-60p Windows 7 Ultimate Edition Patches/drivers are up to date I only use one of the below at a time, disabling the other: Intel PRO/Wireless 3945ABG v. 13.3.0.137 (Internal wireless) Medialink Wireless-N USB 2.0 Adapter (USB wireless) Any ideas on what might be the problem?

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  • How to capture a motion in iphone camera.

    - by Kishore
    Hi, In My application as the user opens the camera, camera should capture a image as soon as there is a difference in image when compared to previous image and camera should always be in capturing mode. This should be done automatically without any user interaction.Please Help me out as i couldn't find the solution asap. Thanks, ravi

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  • Total network data sent/received of a non-daemon Linux process?

    - by leden
    I'm looking for a simple and effective way of measuring total bytes received/sent from a single process upon its termination. Basically, I am looking for a tool which has the interface similar to "time" and "/usr/bin/time", e.g. measure-net-data <prog_to_run> <prog_args> Received (b): XYZ Sent (b): ABC I know that there are many tools for bandwidth/network monitoring, but as far I can tell all of them are performing the measurements it real-time, which is inappropriate not only because of overhead but also because of the inconvenience - I would need to stop the program, capture the output of the tool and then kill it. I have seen that newer versions of Linux 2.6.20+ provide /proc/<pid>/io/ which contain the information I'm looking for; however, everything under /proc/<pid> when the process terminates, so I'm again back to the same problem as with any network monitoring tool.

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  • Why / how does XNA's right-handed coordinate system effect anything if you can specify near/far Z values?

    - by vargonian
    I am told repeatedly that XNA Game Studio uses a right-handed coordinate system, and I understand the difference between a right-handed and left-handed coordinate system. But given that you can use a method like Matrix.CreateOrthographicOffCenter to create your own custom projection matrix, specifying the left, right, top, bottom, zNear and zFar values, when does XNA's coordinate system come into play? For example, I'm told that in a right-handed coordinate system, increasingly negative Z values go "into" the screen. But I can easily create my projection matrix like this: Matrix.CreateOrthographicOffCenter(left, right, bottom, top, 0.1f, 10000f); I've now specified a lower value for the near Z than the far Z, which, as I understand it, means that positive Z now goes into the screen. I can similarly tweak the values of left/right/top/bottom to achieve similar results. If specifying a lower zNear than zFar value doesn't affect the Z direction of the coordinate system, what does it do? And when is the right-handed coordinate system enforced? The reason I ask is that I'm trying to implement a 2.5D camera that supports zooming and rotation, and I've spent two full days encountering one unexpected result after another.

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  • Cocos2d-x CCFollow Zooming issue

    - by blakey87
    Hi I am currently building a cocos2d-x game which incorporates pinch zoom using CCLayerPanZoom class which can be found here The problem is basically when using CCFollow and zooming and out, it does'nt zoom on the actually followed node, so the camera appears to zoom towards the bottom left corner of the screen, when I would rather it zoom centrally on the followed node. If I could resolve this I would pretty darn happy. I converted a fix from the cocos2d objective C version in the CCfollow class to cocos2d-x which improved the issue,but if you look at the post in latter link you will see the guy is having the exact same problem, he gave up on fixing it sadly. I think its close but I don't really know what going on, hopefully someone out there has already faced and fixed this problem. My converted code is below. CCPoint p1 = ccpMult(m_obHalfScreenSize, m_pTarget->getScale() ); CCPoint p2 = ccpMult(m_pobFollowedNode->getPosition(), m_pTarget->getScale() ); CCPoint offect = ccpMult(ccpSub(p1, m_obHalfScreenSize), 0.5f); CCPoint tempPos = ccpAdd(ccpSub(p1, p2), offect); m_pTarget->setPosition(ccp(clampf(tempPos.x,m_fLeftBoundary,m_fRightBoundary), clampf(tempPos.y,m_fBottomBoundary,m_fTopBoundary))); I have attached before and after to hopefully make things more clear.

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  • Red Dot Scope Makes Sighting In Long Lenses a Snap

    - by Jason Fitzpatrick
    If you’ve ever used a high power lens, you know how tricky it can be to sight a distant subject as the field of view through the lens is so tiny. This hack takes care of that problem by using a zero-magnification red dot rifle scope. Chris Malcolm enjoys photographing birds and other wildlife with high power lenses. The problem, when shooting with huge 500mm lens and other high power lenses, is that they’re practically telescopes and acquiring a fast moving target like a bird using a through-the-lens technique is very tricky. Malcolm’s solution hinges on mounting a zero-magnification red dot rifle scope in parallel with the lens. His mock up is a bit unpolished (although we can understand not wanting to run out and buy a brand new black scope just for the experiment) but works great to get him on target. Hit up the link below to read more about his build, how be created the rail mount for the scope, and why he opted to mount it to the barrel of the lens and not the hot shoe mount on the camera. 500mm Reflex Lens with Red Dot Sight [via DIY Photography] Make Your Own Windows 8 Start Button with Zero Memory Usage Reader Request: How To Repair Blurry Photos HTG Explains: What Can You Find in an Email Header?

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  • Rotating a view of a chunked 2d tilemap

    - by Danie Clawson
    I'm working on a top-down (oblique) tile-based engine. I would like for the tiles to have a definable height in the world, with Characters being occluded by them, etc. This has led to a desire to be able to "rotate" the view of the world, even though I'm using all hand-drawn graphics and blitting. Therefor, I need to rotate the actual world itself, or change how the Camera traverses these arrays. How can, or should, I create individual rotations of 90 degrees, when I have multi-dimensional arrays? Is it faster to actually rotate the array, to access it differently, or to create pre-computed accessor(?) arrays, something like how my chunks work? How can I rotate an individual chunk, or set of chunks? Currently I establish my tile grid like this (tile height not included): function Surface(WIDTH, HEIGHT) { WIDTH = Math.max(WIDTH-(WIDTH%TPC), TPC); HEIGHT = Math.max(HEIGHT-(HEIGHT%TPC), TPC); this.tiles = []; this.chunks = []; //Establish tiles for(var x = 0; x < WIDTH; x++) { var col = [], ch_x = Math.floor(x/TPC); if(!this.chunks[ch_x]) this.chunks.push([]); for(var y = 0; y < HEIGHT; y++) { var tile = new Tile(x, y), ch_y = Math.floor(y/TPC); if(!this.chunks[ch_x][ch_y]) this.chunks[ch_x].push([]); this.chunks[ch_x][ch_y].push(tile); col.push(tile); } this.tiles.push(col); } }; Even some basic advice on my data struct would be much appreciated.

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  • Project collision shapes to plane for 2.5D collision detection

    - by Jkh2
    I am working on a top down 2.5D game. In the game anything that overlaps on the screen should be 'colliding' with each other regardless of whether they are on the same plane in the 3D world. This is illustrated below from a side-ways view: The orange and green circles are spheres floating in the 3D world. They are projected onto a plane parallel to the viewport plane (y = 0 in the image) and if they overlap there is a collision event between them. These spheres are attached to other meshes to represent the sphere bounding boxes for collisions. The way I plan to implement this at the moment is the following: Get the 3D world position at the center of the sphere. Use Camera.WorldToViewportPoint to project the point to the viewport plane. Move a Sphere Collider with the radius of the sphere to that point. Test for collisions using unity colliders. My question is how to extend this to work for rotated cuboids. For instance if I have two rotated cuboids, if I follow the logic above it would not work as intended as the cuboids may not collide but they could still be intersected on the view plane. An example is below: Is there a way to project a cuboid that would be aligned with the plane? Would it be a valid cuboid for all rotations if I did this?

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  • Orthographic unit translation mismatch on grid (e.g. 64 pixels translates incorrectly)

    - by Justin Van Horne
    I am looking for some insight into a small problem with unit translations on a grid. Setup 512x448 window 64x64 grid gl_Position = projection * world * position; projection is defined by ortho(-w/2.0f, w/2.0f, -h/2.0f, h/2.0f); This is a textbook orthogonal projection function. world is defined by a fixed camera position at (0, 0) position is defined by the sprite's position. Problem In the screenshot below (1:1 scaling) the grid spacing is 64x64 and I am drawing the unit at (64, 64), however the unit draws roughly ~10px in the wrong position. I've tried uniform window dimensions to prevent any distortion on the pixel size, but now I am a bit lost in the proper way in providing a 1:1 pixel-to-world-unit projection. Anyhow, here are some quick images to aide in the problem. I decided to super-impose a bunch of the sprites at what the engine believes is 64x offsets. When this seemed off place, I went about and did the base case of 1 unit. Which seemed to line up as expected. The yellow shows a 1px difference in the movement. Vertices It would appear that the vertices going into the vertex shader are correct. For example, in reference to the first image the data looks like this in the VBO: x y x y ---------------------------- tl | 0.0 24.0 64.0 24.0 bl | 0.0 0.0 -> 64.0 0.0 tr | 16.0 0.0 80.0 0.0 br | 16.0 24.0 80.0 24.0 With that said, all I am left to believe is that I am munging up my actual projection. So, I am looking for any insight into maintaining the 1:1 pixel-to-world-unit projection.

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  • Incomplete mesh using DrawIndexedPrimitives after rotating mesh

    - by user1278255
    Through help on this site I was able to draw the triangles of an unrotated, nonscaled nontransformed mesh created in Blender and exported to OBJ, accurately imported through Assimp and rendered in XNA Graphics. However after applying rotation on a single axis in Blender(Z) and adding materials(I wanted to test loading of materials through Assimp) the same mesh appears incomplete. Is something wrong with my view matrix or is it something else? This is what the unrotated mesh looks like: http://www.4shared.com/photo/qXNUSvxtba/okcube.html Here is the rotated mesh: http://www.4shared.com/photo/HAys2rWvba/badcube.html Camera, View and Projection are defined as follows: cameraPos = new Vector3(0, 5, 9); viewMatrix = Matrix.CreateLookAt(cameraPos, new Vector3(0, 0, 1), new Vector3(0, 1, 0)); projectionMatrix = Matrix.CreatePerspectiveFieldOfView(MathHelper.PiOver4, device.Viewport.AspectRatio, 1.0f, 200.0f); Rendering is done through this code: device.Clear(ClearOptions.Target | ClearOptions.DepthBuffer, Color.DarkSlateBlue, 1.0f, 0); effect = new BasicEffect(GraphicsDevice); effect.VertexColorEnabled = true; effect.View = viewMatrix; effect.Projection = projectionMatrix; effect.World = Matrix.Identity; foreach (EffectPass pass in effect.CurrentTechnique.Passes) { pass.Apply(); device.SetVertexBuffer(vertexBuffer); device.Indices = indexBuffer; device.DrawIndexedPrimitives(Microsoft.Xna.Framework.Graphics.PrimitiveType.TriangleList, 0, 0, oScene.Meshes[0].VertexCount, 0, mMesh.FaceCount); } base.Draw(gameTime);

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  • How to prevent showing outside of world game in Cocos2D-x

    - by HRZ
    I'm trying to make a tower defense game and it can zoom in/out and scrolling over my world map. How to scroll over the game and how to restrict it not to show outside of my map(black area). At below I scroll over the map by using CCCamera but I don't know how I can restrict it. CCPoint tap = touch->getLocation(); CCPoint prev_tap = touch->getPreviousLocation(); CCPoint sub_point = tap - prev_tap; float xNewPos, yNewPos; float xEyePos, yEyePos, zEyePos; float cameraPosX, cameraPosY, cameraPosZ; // First we get the current camera position. GameLayer->getCamera()->getCenterXYZ(&cameraPosX, &cameraPosY, &cameraPosZ); GameLayer->getCamera()->getEyeXYZ(&xEyePos, &yEyePos, &zEyePos); // Calculate the new position xNewPos = cameraPosX - sub_point.x; yNewPos = cameraPosY - sub_point.y; GameLayer->getCamera()->setCenterXYZ(xNewPos, yNewPos, cameraPosZ); GameLayer->getCamera()->setEyeXYZ(xNewPos, yNewPos, zEyePos); And for zooming I used such code: GameLayer->setScale(GameLayer->getScale() + 0.002); //zooming in

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  • how to prevent showing outside of world game in cocos2dx

    - by HRZ
    Im trying to make a tower defence game and it can zoom in/out and scrolling over my world map.How to scroll over the game and how to restrict it to don't show outside of my map. At below I scroll over the map by using CCCamera but i don't know how i can restrict it. CCPoint tap = touch->getLocation(); CCPoint prev_tap = touch->getPreviousLocation(); CCPoint sub_point = tap - prev_tap; float xNewPos, yNewPos; float xEyePos, yEyePos, zEyePos; float cameraPosX, cameraPosY, cameraPosZ; // First we get the current camera position. GameLayer->getCamera()->getCenterXYZ(&cameraPosX, &cameraPosY, &cameraPosZ); GameLayer->getCamera()->getEyeXYZ(&xEyePos, &yEyePos, &zEyePos); // Calculate the new position xNewPos = cameraPosX - sub_point.x; yNewPos = cameraPosY - sub_point.y; GameLayer->getCamera()->setCenterXYZ(xNewPos, yNewPos, cameraPosZ); GameLayer->getCamera()->setEyeXYZ(xNewPos, yNewPos, zEyePos); And for zooming i used such code: GameLayer->setScale(this->getScale() + 0.002); //zooming in

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  • Network communications mechanisms for SQL Server

    - by Akshay Deep Lamba
    Problem I am trying to understand how SQL Server communicates on the network, because I'm having to tell my networking team what ports to open up on the firewall for an edge web server to communicate back to the SQL Server on the inside. What do I need to know? Solution In order to understand what needs to be opened where, let's first talk briefly about the two main protocols that are in common use today: TCP - Transmission Control Protocol UDP - User Datagram Protocol Both are part of the TCP/IP suite of protocols. We'll start with TCP. TCP TCP is the main protocol by which clients communicate with SQL Server. Actually, it is more correct to say that clients and SQL Server use Tabular Data Stream (TDS), but TDS actually sits on top of TCP and when we're talking about Windows and firewalls and other networking devices, that's the protocol that rules and controls are built around. So we'll just speak in terms of TCP. TCP is a connection-oriented protocol. What that means is that the two systems negotiate the connection and both agree to it. Think of it like a phone call. While one person initiates the phone call, the other person has to agree to take it and both people can end the phone call at any time. TCP is the same way. Both systems have to agree to the communications, but either side can end it at any time. In addition, there is functionality built into TCP to ensure that all communications can be disassembled and reassembled as necessary so it can pass over various network devices and be put together again properly in the right order. It also has mechanisms to handle and retransmit lost communications. Because of this functionality, TCP is the protocol used by many different network applications. The way the applications all can share is through the use of ports. When a service, like SQL Server, comes up on a system, it must listen on a port. For a default SQL Server instance, the default port is 1433. Clients connect to the port via the TCP protocol, the connection is negotiated and agreed to, and then the two sides can transfer information as needed until either side decides to end the communication. In actuality, both sides will have a port to use for the communications, but since the client's port is typically determined semi-randomly, when we're talking about firewalls and the like, typically we're interested in the port the server or service is using. UDP UDP, unlike TCP, is not connection oriented. A "client" can send a UDP communications to anyone it wants. There's nothing in place to negotiate a communications connection, there's nothing in the protocol itself to coordinate order of communications or anything like that. If that's needed, it's got to be handled by the application or by a protocol built on top of UDP being used by the application. If you think of TCP as a phone call, think of UDP as a postcard. I can put a postcard in the mail to anyone I want, and so long as it is addressed properly and has a stamp on it, the postal service will pick it up. Now, what happens it afterwards is not guaranteed. There's no mechanism for retransmission of lost communications. It's great for short communications that doesn't necessarily need an acknowledgement. Because multiple network applications could be communicating via UDP, it uses ports, just like TCP. The SQL Browser or the SQL Server Listener Service uses UDP. Network Communications - Talking to SQL Server When an instance of SQL Server is set up, what TCP port it listens on depends. A default instance will be set up to listen on port 1433. A named instance will be set to a random port chosen during installation. In addition, a named instance will be configured to allow it to change that port dynamically. What this means is that when a named instance starts up, if it finds something already using the port it normally uses, it'll pick a new port. If you have a named instance, and you have connections coming across a firewall, you're going to want to use SQL Server Configuration Manager to set a static port. This will allow the networking and security folks to configure their devices for maximum protection. While you can change the network port for a default instance of SQL Server, most people don't. Network Communications - Finding a SQL Server When just the name is specified for a client to connect to SQL Server, for instance, MySQLServer, this is an attempt to connect to the default instance. In this case the client will automatically attempt to communicate to port 1433 on MySQLServer. If you've switched the port for the default instance, you'll need to tell the client the proper port, usually by specifying the following syntax in the connection string: <server>,<port>. For instance, if you moved SQL Server to listen on 14330, you'd use MySQLServer,14330 instead of just MySQLServer. However, because a named instance sets up its port dynamically by default, the client never knows at the outset what the port is it should talk to. That's what the SQL Browser or the SQL Server Listener Service (SQL Server 2000) is for. In this case, the client sends a communication via the UDP protocol to port 1434. It asks, "Where is the named instance?" So if I was running a named instance called SQL2008R2, it would be asking the SQL Browser, "Hey, how do I talk to MySQLServer\SQL2008R2?" The SQL Browser would then send back a communications from UDP port 1434 back to the client telling the client how to talk to the named instance. Of course, you can skip all of this of you set that named instance's port statically. Then you can use the <server>,<port> mechanism to connect and the client won't try to talk to the SQL Browser service. It'll simply try to make the connection. So, for instance, is the SQL2008R2 instance was listening on port 20080, specifying MySQLServer,20080 would attempt a connection to the named instance. Network Communications - Named Pipes Named pipes is an older network library communications mechanism and it's generally not used any longer. It shouldn't be used across a firewall. However, if for some reason you need to connect to SQL Server with it, this protocol also sits on top of TCP. Named Pipes is actually used by the operating system and it has its own mechanism within the protocol to determine where to route communications. As far as network communications is concerned, it listens on TCP port 445. This is true whether we're talking about a default or named instance of SQL Server. The Summary Table To put all this together, here is what you need to know: Type of Communication Protocol Used Default Port Finding a SQL Server or SQL Server Named Instance UDP 1434 Communicating with a default instance of SQL Server TCP 1433 Communicating with a named instance of SQL Server TCP * Determined dynamically at start up Communicating with SQL Server via Named Pipes TCP 445

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  • With 2 superposed cameras at different depths and switching their culling masks between layers to implement object-selective antialising:

    - by user36845
    We superposed two cameras, one of which uses AA as post-processing effect (AA filtering is cancelled). The camera with the AA effect has depth 0 and the camera with no effect has depth 1 as can be seen in the 5th and 6th Picture. The objects seen on the left are in layer 1 and the ones on the right are in layer 2. We then wrote a script that switches the culling masks of the cameras between the two layers at the push of buttons 1 and 2 respectively, and accomplishes object-selective antialiasing as seen in the first the three pictures. (The way two cameras separately switch culling masks between layers is illustrated in pictures 7,8 & 9.) HOWEVER, after making the environment 3D (see pictures 1-4), by parenting the 2 cameras under First-Person Controller, we started moving around in the environment and stumbled upon a big issue: When we look at the objects from such an angle as in the 4th Picture and we want to apply antialiasing to the first object (object on the left) which stands closer to our cameras now, the culling mask of 1st camera which is at depth 0, has to be switched to that object’s layer while the second object has to be in the culling mask of the 2nd camera at depth 1. And since the two image outputs of two superposed cameras are laid on top of one another; we obtain the erroneous/unrealistic result of the object farther in the back appearing closer to the camera than the front object (see 4th Picture). We already tried switching depths of cameras so that the 1st camera –with AA- now has depth 1 and the second has depth 0; BUT the camera with the AA effect Works in such a way that it applies the AA effect to its full view. So; the camera with the AA effect always has to remain at the lowest depth and the layer of the object to be antialiased has to be then assigned to the culling mask of the AA camera; otherwise all objects in the AA camera’s view (the two cubes in our case) become antialised, which we don’t want. So; how can we resolve this? The pictures are below and in the comments since each post can have 2 pics: Pic 1. No button is pushed: Both objects seem aliased. Pic 2. Button 1 is pushed: Left (1st) object is antialiased. 2nd object remains aliased. Pic 3. Button 2 is pushed: Right (2nd) object is antialiased. 1st object remains aliased. Pic 4. The problematic result in 3D, when using two superposed cameras with different depths Pic 5. Camera 1’s properties can be seen: using AA post-processing and its depth is 0 Pic 6. Camera 2’s properties can be seen: NOT using AA post-processing and its depth is 1 Pic 7. When no button is pushed, both objects are in the culling mask of Camera 2 and are aliased Pic 8. When pushed 1, camera 1 (bottom) shows the 1st object and camera 2 (top) shows the 2nd Pic 9. When pushed 2, camera 1 (bottom) shows the 2nd object and camera 2 (top) shows the 1st

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  • Setting an XAML Window always on top (but no TopMost property)

    - by Brian Scherady
    I am developing an application based on OptiTrack SDK (from NaturalPoint). I need to run the application window as "Always on Top". The window is designed in XAML and is controled in the class "CameraView" but it does not seem to include a "TopMost" property or equivalent. Attached are the code of "CameraView.xaml.cs" and the code of "CameraView.xaml" that are part of OptiTrack SDK (NaturalPoint) called "Single_Camera_CSharp_.NET_3.0". One could expect the class CameraView to contain properties or members to set the position of the window on the screen or to set it to TopMost but as far as searched I found nothing. I wonder what I should do. Thank you, Brian ================ "CameraView.xaml.cs" using System; using System.IO; using System.Net; using System.Windows; using System.Windows.Controls; using System.Windows.Data; using System.Windows.Media; using System.Windows.Media.Animation; using System.Windows.Navigation; using System.Drawing.Imaging; using System.Drawing.Drawing2D; using System.Windows.Threading; namespace TestProject { public partial class CameraView { private const int NP_OPTION_OBJECT_COLOR_OPTION = 3; private const int NP_OPTION_VIDEO_TYPE = 48; private const int NP_OPTION_NUMERIC_DISPLAY_ON = 71; private const int NP_OPTION_NUMERIC_DISPLAY_OFF = 72; private const int NP_OPTION_FETCH_RLE = 73; private const int NP_OPTION_FETCH_GRAYSCALE = 74; private const int NP_OPTION_FRAME_DECIMATION = 52; private const int NP_OPTION_INTENSITY = 50; private const int NP_OPTION_SEND_EMPTY_FRAMES = 41; private const int NP_OPTION_THRESHOLD = 5; private const int NP_OPTION_EXPOSURE = 46; private const int NP_OPTION_SEND_FRAME_MASK = 73; private const int NP_OPTION_TEXT_OVERLAY_OPTION = 74; // public delegate void OnCameraViewCreate(CameraView camera); // public static OnCameraViewCreate onCameraViewCreate; private System.Drawing.Bitmap raw = new System.Drawing.Bitmap(353, 288, System.Drawing.Imaging.PixelFormat.Format32bppArgb); private int mFrameCounter; private int mDisplayCounter; private DispatcherTimer timer1 = new DispatcherTimer(); private bool mVideoFrameAvailable = false; private int mNumeric = -1; private bool mGreyscale = false; private bool mOverlay = true; public CameraView() { this.InitializeComponent(); timer1.Interval = new TimeSpan(0, 0, 0, 0, 10); timer1.Tick += new EventHandler(timer1_Tick); } public int Numeric { get { return mNumeric; } set { mNumeric = value % 100; if (mNumeric = 0) { if (Camera != null) Camera.SetOption(NP_OPTION_NUMERIC_DISPLAY_ON, value % 100); } } } private bool CameraRunning = false; private OptiTrack.NPCamera mCamera; public OptiTrack.NPCamera Camera { get { return mCamera; } set { if (mCamera == value) return; //== Don't do anything if you're assigning the same camera == if (mCamera != null) { //== Shut the selected camera down ==<< if (CameraRunning) { CameraRunning = false; mCamera.Stop(); mCamera.FrameAvailable -= FrameAvailable; } } mCamera = value; if (mCamera == null) { mNumeric = -1; } else { serialLabel.Content = "Camera "+mCamera.SerialNumber.ToString(); //mNumeric.ToString(); } } } private void FrameAvailable(OptiTrack.NPCamera Camera) { mFrameCounter++; try { OptiTrack.NPCameraFrame frame = Camera.GetFrame(0); int id = frame.Id; if (CameraRunning) { GetFrameData(Camera, frame); } frame.Free(); } catch (Exception) { int r = 0; r++; } } private void GetFrameData(OptiTrack.NPCamera camera, OptiTrack.NPCameraFrame frame) { BitmapData bmData = raw.LockBits(new System.Drawing.Rectangle(0, 0, raw.Width, raw.Height), ImageLockMode.ReadWrite, System.Drawing.Imaging.PixelFormat.Format32bppArgb); int stride = bmData.Stride; System.IntPtr bufferPtr = bmData.Scan0; unsafe { byte* buffer = (byte*)(void*)bufferPtr; camera.GetFrameImage(frame, bmData.Width, bmData.Height, bmData.Stride, 32, ref buffer[0]); } raw.UnlockBits(bmData); mVideoFrameAvailable = true; } private void timer1_Tick(object sender, EventArgs e) { if (CameraRunning && mVideoFrameAvailable) { mVideoFrameAvailable = false; cameraImage.Source = Img(raw); mDisplayCounter++; } } private System.Windows.Media.ImageSource Img(System.Drawing.Bitmap img) { System.Drawing.Imaging.BitmapData bmData = img.LockBits(new System.Drawing.Rectangle(0, 0, img.Width, img.Height), System.Drawing.Imaging.ImageLockMode.ReadWrite, System.Drawing.Imaging.PixelFormat.Format32bppPArgb); System.Windows.Media.Imaging.BitmapSource bitmap = System.Windows.Media.Imaging.BitmapSource.Create( img.Width, img.Height, 96, 96, PixelFormats.Bgra32, System.Windows.Media.Imaging.BitmapPalettes.WebPalette, bmData.Scan0, bmData.Stride * bmData.Height, bmData.Stride); img.UnlockBits(bmData); return bitmap; } private void startStopButton_Click(object sender, RoutedEventArgs e) { if (CameraRunning) StopCamera(); else StartCamera(); } public void StartCamera() { if (Camera != null) { mFrameCounter = 0; mDisplayCounter = 0; Camera.FrameAvailable += FrameAvailable; Camera.SetOption(NP_OPTION_VIDEO_TYPE, 0); Camera.SetOption(NP_OPTION_FRAME_DECIMATION, 1); Camera.SetOption(NP_OPTION_INTENSITY, 0); Camera.SetOption(NP_OPTION_EXPOSURE, 10); Camera.SetOption(NP_OPTION_THRESHOLD, 50); Camera.SetOption(NP_OPTION_OBJECT_COLOR_OPTION, 0); SetOverlayOption(); SetGreyscaleOption(); timer1.Start(); Camera.Start(); CameraRunning = true; this.Numeric = mNumeric; startStopButton.Content = "Stop Camera"; } } private void SetGreyscaleOption() { if(mGreyscale) Camera.SetOption(NP_OPTION_VIDEO_TYPE, 1); else Camera.SetOption(NP_OPTION_VIDEO_TYPE, 0); } private void SetOverlayOption() { if(mOverlay) Camera.SetOption(NP_OPTION_TEXT_OVERLAY_OPTION, 255); else Camera.SetOption(NP_OPTION_TEXT_OVERLAY_OPTION, 0); } public void StopCamera() { if (Camera != null) { Camera.Stop(); timer1.Stop(); CameraRunning = false; Camera.FrameAvailable -= FrameAvailable; Camera.SetOption(NP_OPTION_NUMERIC_DISPLAY_OFF, 0); startStopButton.Content = "Start Camera"; } } private void greyscaleButton_Click(object sender, RoutedEventArgs e) { if(mGreyscale) mGreyscale = false; else mGreyscale = true; SetGreyscaleOption(); } private void OverlayButton_Click(object sender, RoutedEventArgs e) { if(mOverlay) mOverlay = false; else mOverlay = true; SetOverlayOption(); } private void exposureSlider_ValueChanged(object sender, RoutedEventArgs e) { if (mCamera!=null) { mCamera.SetOption(NP_OPTION_EXPOSURE, (int) this.exposureSlider.Value); } } private void thresholdSlider_ValueChanged(object sender, RoutedEventArgs e) { if (mCamera != null) { mCamera.SetOption(NP_OPTION_THRESHOLD, (int)this.thresholdSlider.Value); } } private void optionsButton_Click(object sender, RoutedEventArgs e) { if (!propertyPanel.IsVisible) propertyPanel.Visibility = Visibility.Visible; else propertyPanel.Visibility = Visibility.Collapsed; } } } ================ "CameraView.xaml"

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  • Cannot enable network discovery on Windows Server 2008 R2

    - by dariom
    I'm trying to enable the Network Discovery feature on a newly installed Windows Server 2008 R2 instance. The network connection is in the Home or Work profile (it is not domain joined). These are the steps I've followed: Within the Network and Sharing Center I select Change advanced sharing settings Then I select the Turn on network discovery option for the current network profile (Home or Work) I then click Save changes If I then go back to the Advanced sharing settings screen the Turn off network discovery option is selected and the machine is not visible to others within the Network node in Windows Explorer. Things I've checked: I can ping the server and connect to it using the machine name/IP address. The Windows Firewall has exceptions for Network Discovery for both Private and Public networks. File and Printer sharing is enabled and I can transfer files to/from the server by connecting to the server using a UNC path. What am I missing here?

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  • recover lost files from sd card(digital camera)

    - by user23950
    How do I recover lost data from sd card? I already tried using: Photorec Recuva Tune up undelete Pareto data recovery chkdsk x: /F from here: http://superuser.com/questions/128259/how-to-recover-images-from-memory-card But none of them worked. I think I've only lost the data yesterday. And I haven't used the camera. So there's a possibility that it is still there. But the question is how I can recover the images? I think its lost when I tried to connect the digicam with the computer. But the camera froze so I tried to remove the batteries then try again.

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  • OS X 10.6 won't automatically connect to wireless even though remember network is checked

    - by Hendy
    Upgraded to 10.6 recently. 10.5 would connect to my home network whenever I was home. 10.6 constantly pops up the network selection dialog and asks me what network I want to join. I click my home network and the password is already entered (so it "remembers" the network). "Remember network" is checked... but it does it every time. How do I get 10.6 to connect to networks automatically whenever it sees them?

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  • bond0 and xen = crash

    - by Rajat
    Bonding with xen 1 - Stop all guests. Reboot dom0 after running "chkconfig xend off" and "chkconfig xendomains off". 2 - Configure bond0 by enslaving eth0 and eth1 to it. I added the below two entries to /etc/modprobe.conf. alias bond0 bonding options bond0 mode=6,miimon=100 Content of /etc/sysconfig/network-scripts/ifcfg-eth0 DEVICE=eth0 USERCTL=no ONBOOT=yes MASTER=bond0 SLAVE=yes BOOTPROTO=none Content of /etc/sysconfig/network-scripts/ifcfg-eth1 DEVICE=eth1 USERCTL=no ONBOOT=yes MASTER=bond0 SLAVE=yes BOOTPROTO=none Content of /etc/sysconfig/network-scripts/ifcfg-bond0 DEVICE=bond0 IPADDR= NETMASK= ONBOOT=yes BOOTPROTO=static USERCTL=no Did "modprobe bond0" and "service network restart" after that. 3 - Edit /etc/xen/xend-config.sxp Change (network-script network-bridge) To (network-script 'network-bridge netdev=bond0') 4 - Start xend. "service xend start". 5 - chkconfig xend on. 6 - modprode bond0 7 - more /proc/net/bonding/bond0 8 - Create guest images as usual and bridge it to xenbr0. about config i did for my xen kernel rhel 5.3 after i reboot the host server i get in place bond0 get pbond0 and its get disconnect from network only i ping to my vm's on the host server any one have any idea why xen bond0 is acting like that or what is solutions to come out of pbond0 to bond0.

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  • Options for small windows network setup without dedicated server?

    - by Mitch
    I'm very weak on networking and hope someone can point me in the right direction: I have written some windows client/server software which incorporates a database which is located on a windows server. I have a test installation running at a customer's office where the server has a static IP address. In this case its easy for the clients to access the database because of the fixed IP address. Also, customers with network servers generally have specialist support staff to set up my software, so its not such a problem for me. However I also need to offer the software to customers who have small offices with less than 10 PCs and no dedicated network server. In this case I want the customer to be able to nominate one PC as the database "server" and install my software and have the clients access it. But in this situation I believe the "server" PC may not have a dedicated IP address. Q1: What is the best way to set this up simply and make it work? Can I reliably reference the "server" by using its name, or is there a way to assign dummy fixed IP addresses? Ideally this needs to be workable on small networks running a mixture of XP/Vista/Windows7 as my target market may well have mixed OSes etc. I guess this would be akin to home networking? Many thanks Mitch

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  • Windows Server 2008 R2 Virtual Network Setup

    - by jpearl01
    Hi all, Some background: I'm very much new to networking in general, and virtualization in particular. I'm trying to set up a series of VMs as we are transitioning to a thin client setup. I have been supplied a limited number of static ip addresses. The server is located in an offsite building which houses the network we use to connect to the internet, share folders etc. The setup I've been trying to go for is this: The host OS (Windows Server 2008 R2) is bound to one nic using one of the static ips (say, Nic1 and ip 10.255.6.61). I've set up another external virtual network attached to another physical nic , and a virtual private network attached to no nic. There is one VM running the same os (as the host). This VM is connected to both the external virtual network (and uses another static ip say Nic2 and ip 10.255.6.62) and also to the virtual private network (I gave it a static random ip 192.168.88.1 subnet mask 255.255.255.0). This virtual private network is connected to all the other VMs. I'd like to share the internet connection with all the other VMs on the private virtual network, and so I installed the RRAS role on the server connected to Nic2, and selected the option to share the internet over the vpn. I've run through the RRAS wizard a few times, trying different configurations, but none of them seem to be letting the other vms connect to the 'net. The vms seem to connect to the virtual private network fine, they are assigned an ip address and everything, but no internet, and no rest of the network either. The other problem is in general I connect to the vms with RDP. Will that be possible with a setup like this? i.e. will the vms show up as computers on the network? If not, what are my other options? Thanks! ~josh

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  • Why are certain folders in my XP network share really, really slow?

    - by bikefixxer
    I have a workgroup set up with Windows XP. My file "server" is running XP Pro and the clients are running XP home. I've turned simple file sharing off on the server because certain clients need access to certain folders and not to others, and I want to keep it that way. Therefore, I've used the granular sharing/security settings to enable certain clients access to certain folders. I'm using the net use command in a batch file on the clients to add the share when they logon so it's always available via a mapped drive or a shortcut. On some clients "My Documents" points to the mapped drive, but all of the local and application settings stay local. Everything works well except for accessing a certain folder on the network. It contains a lot of random batch files and self-executable programs I use for diagnostics and what not, and nearly every time I open the folder the computer hangs for 15-60 seconds. This happens on every machine, including the server (but not nearly as often as the clients). I've searched high and low and cannot figure it out and it's driving me crazy. Here are all the things I've tried to no avail: Disabled firewall (XP) and anti-virus (ESET NOD32) Deleted any desktop.ini file I can find in the share Disabled "automatically search for network folders and printers" Disabled "remember each folder's view settings" Set HKCU\Software\Microsoft\Windows\CurrentVersion\Policies\Explorer NoRecentDocsNetHood = 1 Tried with mapped drives and with UNC shortcuts Ran CHKDSK Removed Read-Only attribute from all folders (well, tried to remove, it always came back on with a half check) Added the server's static IP to the hosts file on the clients I've tried monitoring the server's performance to see if anything makes sense. Occasionally the issue coincides with a spike in pages/sec (memory) but not always. Other than that, everything else seems normal. The anti-virus would seem to be the most likely cause to me considering the batch files and what not, but it still hangs when it is completely disabled. I'm at a loss and if anyone can help me with this I'd greatly appreciate it!

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  • How to record tv to network share with Windows Media Center?

    - by Peterdk
    Well, you would think that Windows 7's new MediaCenter would be up to the task of recording your TV to a network share/drive. Too bad, it looks like it's just not possible. I have a windows 2008 R2 server, and a Windows 7 machine with a TV card. Since my server has 2TB of storage, it would be nice to record directly to it's networked drive. (I mounted it as Z:). I tried the following: Selecting it in Media Center Itself: Not working. Not available. Editing the registry: HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows\CurrentVersion\Media Center\Service\Recording , setting RecordPath to Z:\TV. Not working. Editing the registry: setting RecordPath to \\server\TV. Not working. Creating a Symlink (mklink \D) to Z:\TV and \\server\TV and setting that in the registry as RecordPath. Currently I am out of options. I could ofcourse Install Windows7 on my server, but I have no license for that, and my windows 2008 r2 is free from dreamspark. Are there people that are succesfully recording to a networked drive/storage? edit I also need to mention that I need to be able to acces the stored files from other PC's, like my laptop. So iSCSI is great for recording, but it looks like you can't access iSCSI devices from multiple PC's. Looks like sharing a iSCSI device is out of the question, so: Are there workarounds to get this thing recording to my network drive?

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  • Windows Server 2008 R2 Virtual Network Setup

    - by jpearl01
    Some background: I'm very much new to networking in general, and virtualization in particular. I'm trying to set up a series of VMs as we are transitioning to a thin client setup. I have been supplied a limited number of static ip addresses. The server is located in an offsite building which houses the network we use to connect to the internet, share folders etc. The setup I've been trying to go for is this: The host OS (Windows Server 2008 R2) is bound to one nic using one of the static ips (say, Nic1 and ip 10.255.6.61). I've set up another external virtual network attached to another physical nic , and a virtual private network attached to no nic. There is one VM running the same os (as the host). This VM is connected to both the external virtual network (and uses another static ip say Nic2 and ip 10.255.6.62) and also to the virtual private network (I gave it a static random ip 192.168.88.1 subnet mask 255.255.255.0). This virtual private network is connected to all the other VMs. I'd like to share the internet connection with all the other VMs on the private virtual network, and so I installed the RRAS role on the server connected to Nic2, and selected the option to share the internet over the vpn. I've run through the RRAS wizard a few times, trying different configurations, but none of them seem to be letting the other vms connect to the 'net. The vms seem to connect to the virtual private network fine, they are assigned an ip address and everything, but no internet, and no rest of the network either. The other problem is in general I connect to the vms with RDP. Will that be possible with a setup like this? i.e. will the vms show up as computers on the network? If not, what are my other options? Thanks! ~josh

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