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  • Why does a change of Session State provider lead to an ASPx page yielding garbage?

    - by Rory Becker
    I have an aspnet webapp which has worked very well up until now. I was recently asked to explore ways of making it scale better. I found that seperation of database and Webapp would help. Further I was told that if I changed my session providing mechanism to SQLServer, I would be able to duplicate the Web Stack to several machines which could each call back to the state server allowing the load to be distirbuted better. This sounds logical. So I created an ASPState database using ASPNet_RegSQL.exe as detailed in many locations across the web and changed the web.config on my app from: <sessionState mode="InProc" cookieless="false" timeout="20" /> To: <sessionState mode="SQLServer" sqlConnectionString="Server=SomeSQLServer;user=SomeUser;password=SomePassword" cookieless="false" timeout="20" /> Then I addressed my app, which presented me with its logon screen and I duly logged in. Once in I was presented, not with the page I was expecting, but with: I can change the sessionstate back and forth. This problem goes away and then comes back based on which set of configuration I use. Why is this happening?

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  • Http authentication with apache httpcomponents

    - by matdan
    Hi, I am trying to develop a java http client with apache httpcomponents 4.0.1. This client calls the page "https://myHost/myPage". This page is protected on the server by a JNDIRealm with a login form authentication, so when I try to get https://myHost/myPage I get a login page. I tried to bypass it unsuccessfully with the following code : //I set my proxy HttpHost proxy = new HttpHost("myProxyHost", myProxyPort); //I add supported schemes SchemeRegistry supportedSchemes = new SchemeRegistry(); supportedSchemes.register(new Scheme("http", PlainSocketFactory .getSocketFactory(), 80)); supportedSchemes.register(new Scheme("https", SSLSocketFactory .getSocketFactory(), 443)); // prepare parameters HttpParams params = new BasicHttpParams(); HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1); HttpProtocolParams.setContentCharset(params, "UTF-8"); HttpProtocolParams.setUseExpectContinue(params, true); ClientConnectionManager ccm = new ThreadSafeClientConnManager(params, supportedSchemes); DefaultHttpClient httpclient = new DefaultHttpClient(ccm, params); httpclient.getParams().setParameter(ConnRoutePNames.DEFAULT_PROXY, proxy); //I add my authentication information httpclient.getCredentialsProvider().setCredentials( new AuthScope("myHost/myPage", 443), new UsernamePasswordCredentials("username", "password")); HttpHost host = new HttpHost("myHost", 443, "https"); HttpGet req = new HttpGet("/myPage"); //show the page ResponseHandler<String> responseHandler = new BasicResponseHandler(); String rsp = httpClient.execute(host, req, responseHandler); System.out.println(rsp); When I run this code, I always get the login page, not myPage. How can I apply my credential parameters to avoid this login form? Any help would be fantastic

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  • Don't serealize a especific data member , but DESEREALIZE, any chance???

    - by CrazyJoe
    Im using DataContractJsonSerializer to serealize this class: public class User { public string id { get; set; } public string name { get; set; } public string password { get; set; } public string email { get; set; } public bool is_broker { get; set; } public string branch_id { get; set; } public string created_at { get; set; } public string updated_at { get; set; } public UserGroup UserGroup {get;set;} public UserAddress UserAddress { get; set; } public List<UserContact> UserContact {get; set;} public User() { UserGroup = new UserGroup(); UserAddress = new UserAddress(); UserContact = new List<UserContact>(); } } The question is when i serealize to json , the property UserGroup is serealized, but i dont need this, i like to serealize to json whitout UserGroup property. Obs: When Deserealize it´s all fine to have UserGroup, i need that!! Any Trick ?????? Thanks!!!

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  • SSRS 2008 - Sending report as email

    - by Mozy
    Hi all, What I want to do is render a SSRS 2008 report as HTML (actually MHTML) and send that as the body in an email. Has anyone done this? I've almost got it (I think) but I seem to have a encoding problem. The email shows up as what looks like some sort of base64 encoding. Like this: MIME-Version: 1.0 Content-Type: multipart/related; boundary="----=_NextPart_01C35DB7.4B204430" X-MSSQLRS-ProducerVersion: V10.0.2531.0 This is a multi-part message in MIME format. ------=_NextPart_01C35DB7.4B204430 Content-ID: Content-Disposition: inline; filename="FollowUpNotification" Content-Type: text/html; name="FollowUpNotification"; charset="utf-8" Content-Transfer-Encoding: base64 PCFET0NUWVBFIEhUTUwgUFVCTElDICItLy9XM0MvL0RURCBIVE1MIDQuMDEgVHJhbnNp... Any ideas on what I'm missing? Here is a code snippet: myMail.BodyEncoding = System.Text.Encoding.UTF8; myMail.IsBodyHtml = true; WebClient client = new WebClient(); System.Net.NetworkCredential repAuthenticationInfo = new System.Net.NetworkCredential(@"username", @"password"); client.Credentials = repAuthenticationInfo; client.Encoding = System.Text.Encoding.UTF8; string messageBody = client.DownloadString( "http://<<reportserver>>&rs%3aFormat=MHTML&Parameter=" + Parameter); myMail.Body = messageBody;

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  • PHP code displayed in browser

    - by Drake
    so, I'm working on a databases project, and i'm trying to code incrementally. the problem is, when i go to test the php in browser, it displays the php code after my use of "-". the html printing is displayed properly, which is AFTER the point where the - is. here is the php: <?php function getGraphicNovel(){ include_once("./connect.php"); $db_connection = new mysqli($SERVER, $USERNAME, $PASSWORD, $DATABASE); if (mysqli_connect_errno()) { echo("Can't connect to MySQL Server. Error code: " . mysqli_connect_error()); return null; } $stmt = $db_connection->stmt_init(); $returnValue = "invalid"; if($stmt.prepare("select series from graphic_novel_main natural join graphic_novel_misc")) { $stmt->execute(); $stmt->bind_result($series); while ($stmt->fetch()) { echo "<tr><td>" . $series . "</td></tr>"; } $stmt->close(); } $db_connection->close(); } getGraphicNovel(); ?> here is a link to the page. hopefully it works for people outside the school's network. http://plato.cs.virginia.edu/~paw5k/cainedb/viewall.html if anyone knows why this is happening, your input would be great!

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  • DOMAIN REDIRECT PROBLEM WITH JQUERY / JAVASCRIPT

    - by GiovanniDema
    Hi guys, first time here. I got a strange problem. I have a fullscreen image scaler javascript (as GOTOCHINA website) that works very well on my website. Then, I purchased a domain redirect pointing on my website and when redirecting suddenly internet explorer 7 and internet explorer 8 give me this error Messagge: is not a valid argument. Line: 34 Char: 17 URI: http://*****/scaler.js The script is var db=document.body; var imag=document.getElementById('wallpaper'); var dbsize={}; var imgsrc=imag.src; var keyStop=function(e){ var e=window.event||e||{}; var tag=e.target.tagName.toLowerCase(); if(tag!='textarea'&&!(tag=='input'&&(e.target.type=='text'||e.target.type=='password'))){ if(e.keyCode==32||e.keyCode==39||e.keyCode==40){ if(e.preventDefault)e.preventDefault(); else e.returnValue=false; } } } if(this.addEventListener)window.addEventListener('keydown',keyStop,false); else window.attachEvent('onkeydown',keyStop); setInterval(function(){ window.scrollTo(0,0); if(imag.complete){ if(db.clientWidth!=dbsize.w||db.clientHeight!=dbsize.h||imag.src!=imgsrc){ imgsrc=imag.src; var dbsizew=db.clientWidth; var dbsizeh=db.clientHeight; var newwidth=Math.round(dbsizeh*(imag.offsetWidth/imag.offsetHeight)); var nextvar=dbsizewnewwidth?dbsizew:newwidth; imag.style.width=nextvar+'px'; } } },300); In other words when i open the official website everything's working correctly. When i open redirect domain pointing on official website... the previous error appears. The line is exactly this - imag.style.width=nextvar+'px'; Thanks in advance Giovanni

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  • Are there any security issues to avoid when providing a email-or-username-can-act-as-username login

    - by Tchalvak
    I am in the process of moving from a "username/password" system to one that uses email for login. I don't think that there's any horrible problem with allowing either email or username for login, and I remember seeing sites that I consider somewhat respectable doing it as well, but I'd like to be aware of any major security flaws that I may be introducing. More specifically, here is the pertinent function (the query_row function parameterizes the sql). function authenticate($p_user, $p_pass) { $user = (string)$p_user; $pass = (string)$p_pass; $returnValue = false; if ($user != '' && $pass != '') { // Allow login via username or email. $sql = "SELECT account_id, account_identity, uname, player_id FROM accounts join account_players on account_id=_account_id join players on player_id = _player_id WHERE lower(account_identity) = lower(:login) OR lower(uname) = lower(:login) AND phash = crypt(:pass, phash)"; $returnValue = query_row($sql, array(':login'=>$user, ':pass'=>$pass)); } return $returnValue; } Notably, I have added the WHERE lower(account_identity) = lower(:login) OR lower(uname) = lower(:login) ...etc section to allow graceful backwards compatibility for users who won't be used to using their email for the login procedure. I'm not completely sure that that OR is safe, though. Are there some ways that I should tighten the security of the php code above?

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  • MySQL - Structure for Permissions to Objects

    - by Kerry
    What would be an ideal structure for users permissions of objects. I've seen many related posts for general permissions, or what sections a user can access, which consists of a users, userGroups and userGroupRelations or something of that nature. In my system there are many different objects that can get created, and each one has to be able to be turned on or off. For instance, take a password manager that has groups and sub groups. Group 1 Group 2 Group 3 Group 4 Group 5 Group 6 Group 7 Group 8 Group 9 Group 10 Each group can contain a set of passwords. A user can be given read, write, edit and delete permissions to any group. More groups can get created at any point in time. If someone has permission to a group, I should be able to make him have permissions to all sub groups OR restrict it to just that group. My current thought is to have a users table, and then a permissions table with columns like: permission_id (int) PRIMARY_KEY user_id (int) INDEX object_id (int) INDEX type (varchar) INDEX read (bool) write (bool) edit (bool) delete (bool) This has worked in the past, but the new system I'm building needs to be able to scale rapidly, and I am unsure if this is the best structure. It also makes the idea of having someone with all subgroup permissions of a group more difficult. So, as a question, should I use the above structure? Or can someone point me in the direction of a better one?

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  • Can't decrypt after encrypting with blowfish Java

    - by user2030599
    Hello i'm new to Java and i have the following problem: i'm trying to encrypt the password of a user using the blowfish algorithm, but when i try to decrypt it back to check the authentication it fails to decrypt it for some reason. public static String encryptBlowFish(String to_encrypt, String salt){ String dbpassword = null; try{ SecretKeySpec skeySpec = new SecretKeySpec( salt.getBytes(), "Blowfish" ); // Instantiate the cipher. Cipher cipher = Cipher.getInstance("Blowfish/CBC/PKCS5Padding"); cipher.init(Cipher.ENCRYPT_MODE, skeySpec); //byte[] encrypted = cipher.doFinal( URLEncoder.encode(data).getBytes() ); byte[] encrypted = cipher.doFinal( to_encrypt.getBytes() ); dbpassword = new String(encrypted); } catch (Exception e) { System.out.println("Exception while encrypting"); e.printStackTrace(); dbpassword = null; } finally { return dbpassword; } } public static String decryptBlowFish(String to_decrypt, String salt){ String dbpassword = null; try{ SecretKeySpec skeySpec = new SecretKeySpec( salt.getBytes(), "Blowfish" ); // Instantiate the cipher. Cipher cipher = Cipher.getInstance("Blowfish/CBC/PKCS5Padding"); cipher.init(Cipher.DECRYPT_MODE, skeySpec); //byte[] encrypted = cipher.doFinal( URLEncoder.encode(data).getBytes() ); byte[] encrypted = cipher.doFinal( to_decrypt.getBytes() ); dbpassword = new String(encrypted); } catch (Exception e) { System.out.println("Exception while decrypting"); e.printStackTrace(); dbpassword = null; } finally { return dbpassword; } } When i call the decrypt function it gives me the following error: java.security.InvalidKeyException: Parameters missing Any ideas? Thank you

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  • Open a dialog box in same window on selectOneMenu change

    - by Pravingate
    I have a jsf page where I have a selectOneMenu and , I want to open a dialog box on selectOneMenu changes. As a example if user selects a value ="passive" from jsf selectOneMenu it should open a dialog box or a light box on same page where I want to display a small jsf form like as here done. http://www.primefaces.org/showcase-labs/ui/dialogLogin.jsf and I also want save that submitted data in my backing bean somewhere so I can store it in to database later. I dont know how to open a dialog box or light box from backing bean in same window,as we will identify value change using valueChangeListener event or by using ajax event. I am able to identify which value is selected from selectOneMenu(DropdownMenu), but dont know how to open a dialog box on selecting particular value. <h:outputLabel value="* Country: "/> <h:selectOneMenu id="someSelect" value="#{testController.countryName}" required="true"> <f:selectItem itemLabel="Select Country" itemValue=""/> <f:selectItems value="#{testController.countryNamesSelectItems}"/> </h:selectOneMenu> Supoose we have 2 options in selectItems as India and Austrlia, then If a user choose India a dialog box should open on same page where a user need to fill some information and need to submit if he is from india (like here in example http://www.primefaces.org/showcase-labs/ui/dialogLogin.jsf user will put his username and password and submits data) Hope this helps How can I achieve that by using jsf or javascript or ajax or by any else way?

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  • Problem uploading app to google app engine

    - by Oberon
    I'm having problems uploading an app to the google-app-engine from my work place. I believe the problem is related to proxy, because I do not see the same problem when following the same procedure from home. (I do not specify HTTP_PROXY from home). These are the commands I run: HTTP_PROXY=http://proxy.<thehostname>.com:8080 HTTP_PROXY=https://proxy.<thehostname>.com:8080 appcfg.py --insecure update myappfolder When running the commands I get prompted for email and password, as expected, but after that it immediately exits with this errormessage: Error 302: --- begin server output --- <HTML> <HEAD> <TITLE>Moved Temporarily</TITLE> </HEAD> <BODY BGCOLOR="#FFFFFF" TEXT="#000000"> <H1>Moved Temporarily</H1> The document has moved <A HREF="https://www.google.com/accounts/ClientLogin">here</A>. </BODY> </HTML> --- end server output --- Note: I added the --insecure option because else it gave a warning of missing ssl module. Any idea how to solve or workaround this problem?

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  • why is a minus sign prepended to my biginteger?

    - by kyrogue
    package ewa; import java.io.UnsupportedEncodingException; import java.security.MessageDigest; import java.security.NoSuchAlgorithmException; import java.util.logging.Level; import java.util.logging.Logger; import java.math.BigInteger; /** * * @author Lotus */ public class md5Hash { public static void main(String[] args) throws NoSuchAlgorithmException { String test = "abc"; MessageDigest md = MessageDigest.getInstance("MD5"); try { md.update(test.getBytes("UTF-8")); byte[] result = md.digest(); BigInteger bi = new BigInteger(result); String hex = bi.toString(16); System.out.println("Pringting result"); System.out.println(hex); } catch (UnsupportedEncodingException ex) { Logger.getLogger(md5Hash.class.getName()).log(Level.SEVERE, null, ex); } } } i am testing conversion of byte to hex and when done, the end result has a minus sign on the beginning of the string, why does this happen? i have read the docs and it says it will add a minus sign, however i do not understand it. And will the minus sign affect the hash result? because i am going to implement it to hash password stored on my database

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  • tomcat resource missing, servlet not running

    - by user2837260
    import javax.servlet.*; import java.io.*; public class MyServlet implements Servlet { public void init(ServletConfig con) {} public void service(ServletRequest req, ServletResponse res) throws IOException,ServletException { res.setContentType("text/html"); PrintWriter out=res.getWriter(); String s="blah"; String s1="blah"; out.println("<html><body>"); if((s.equals(req.getParameter("firstname")))&&(s1.equals(req.getParameter("pwd")))) out.println("passwords match"); else out.println("password and name combo does not match"); out.println("</body></html>"); } public void destroy() {} public ServletConfig getServletConfig() { return null;} public String getServletInfo() { return null;} } this is my java file with the servlet class.its saved with the name MyServlet.java and so is the class file. and here is the xml file: <web-app> <servlet> <servlet-name>demoo</servlet-name> <servlet-class>MyServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>demoo</servlet-name> <url-pattern>/demo</url-pattern> </servlet-mapping> </web-app> i have made the folder as WEB-INF and then classes... WEB-INF also contains the .xml file but when i try to run the servlet , it says resource not found ps- i am already looking for the servlet with the name :demo localhost:8081/s1/demo* s1 is the war file * a html file in the war file seems to run fine on the server though. *

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  • Problem logging in and changing permissions in Facebook

    - by kujawk
    Hi everybody, I've got a piece of code that logs into Facebook, gets a session, sets status_update and offline_access permission if they are not set, and gets a new session with the newly set permissions. This code used to work fine but now I'm getting error 100 "One of the parameters specified was missing or invalid" as a response to the second call to get session and I can't figure out why. Here's the sequence in detail: CREATE TOKEN restserver.php?method=auth.createToken&api_key=[our key]&v=1.0&format=JSON&sig=[sig created with our secret] response: new token LOGIN m.facebook.com/login.php?api_key=[our key]&v=1.0&auth_token=[token created above] login screen loads and user successfully logs in with their username/password. GET SESSION restserver.php?method=auth.getSession&api_key=[our key]&v=1.0&format=JSON&auth_token=token created above&sig=[sig created with our secret] response: session key with expiration date and a secret CHECK/AUTHORIZE PERMISSIONS restserver.php?method=users.hasAppPermission&api_key=[our key]&v=1.0&format=JSON&ext_perm=status_update&call_id=[proper id]&session_key=[key returned above]&sig=[sig created with secret returned for get session] response: 0 m.facebook.com/authorize.php?api_key=[our key]&v=1.0&ext_perm=status_update authorization screen loads and user authorizes Same steps for status_update CREATE NEW TOKEN Same steps as done to create the first token LOGIN m.facebook.com/login.php?api_key=[our key]&v=1.0&auth_token=[new token] user is already logged in, redirected to their homepage GET NEW SESSION restserver.php?method=auth.getSession&api_key=[our key]&format=JSON&auth_token=[new token]&sig=[sig created with our secret] response: error 100 - missing or invalid parameter. Of course it doesn't tell me which one. Anybody have any ideas what I'm doing wrong here? I tried skipping the second login and going right to creating the new session and that didn't work. The only thing that seems to work is logging out the user after they've authorized the permissions and having them log back in again. I'd like to avoid this if possible. Can you have two outstanding sessions at one time? This code used to work but I'm thinking maybe something changed on Facebook's end that I'm not aware of. Thanks, kris

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  • Is it possible to disable/bypass the login popup caused by mod_auth_ntlm_winbind (Single Sign On) an

    - by cvack
    I have an intranet on a remote Web server. This will be integrated with Active Directory on our local server. The web server is running Apache / Linux and the AD server is running Windows 2003. This is all done with VPN. Login to the intranet is conducted in two ways: 1. Users who are logged in to AD to be logged in automatically with SSO. 2. Users who are NOT logged in to AD to be logged in using a common login form. In order to auto login (SSO) I use mod_auth_ntlm_winbind. The problem here is that the users not logged in to AD will get a popup box where they must enter their DOMAIN/username + AD password. If I disable this popup, there is no way to get $_SERVER['REMOTE_USER'] Then my question: Is it possible to turn off this popup box and still get the REMOTE_USER? Or: If possible, can I use AJAX to check if http://my-intranet/auth returns 401 error (non-AD users). If so, do not go to the /auth folder.

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  • Approaches for cross server content sharing?

    - by Anonymity
    I've currently been tasked with finding a best solution to serving up content on our new site from another one of our other sites. Several approaches suggested to me, that I've looked into include using SharePoint's Lists Web Service to grab the list through javascript - which results in XSS and is not an option. Another suggestion was to build a server side custom web service and use SharePoint Request Forms to get the information - this is something I've only very briefly looked at. It's been suggested that I try permitting the requesting site in the HTTP headers of the serving site since I have access to both. This ultimately resulted in a semi-working solution that had major security holes. (I had to include username/password in the request to appease AD Authentication). This was done by allowing Access-Control-Allow-Origin: * The most direct approach I could think of was to simply build in the webpart in our new environment to have the authors manually update this content the same as they would on the other site. Are any one of the suggestions here more valid than another? Which would be the best approach? Are there other suggestions I may be overlooking? I'm also not sure if WebCrawling or Content Scrapping really holds water here...

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  • Managed C++ or C# .NET, Downloading from rapidshare?

    - by cruisx
    I am trying to download a file from rapidshare via C++ .NET but I'm having a bit of trouble. The address used to be "https://ssl.rapidshare.com/cgi-bin/premiumzone.cgi" but that no longer works, does anyone know what the new one is? The code works but the file size is always 1KB, I don't think its connecting to the right server. private: void downloadFileAsync(String^ fileUrl) { String^ uriString; //fileUrl = "http://rapidshare.com/files/356458319/Keeping.Up.with.the.Kardashians.S04E10.Delivering.Baby.Mason.HDTV.XviD-MOMENTUM.rar"; uriString = "https://ssl.rapidshare.com/premzone.html";//"https://ssl.rapidshare.com"; NameValueCollection^ postvals = gcnew NameValueCollection(); postvals->Add("login", "bob"); postvals->Add("password", "12345"); // postvals->Add("uselandingpage", "1"); WebClient^ myWebClient = gcnew WebClient(); array<unsigned char>^ responseArray = gcnew array<unsigned char>(10024); responseArray = myWebClient->UploadValues(uriString, "POST", postvals); StreamReader^ strRdr = gcnew StreamReader(gcnew MemoryStream(responseArray)); String^ cookiestr = myWebClient->ResponseHeaders->Get("Set-Cookie"); myWebClient->Headers->Add("Cookie", cookiestr); //myWebClient->DownloadFileCompleted += gcnew AsyncCompletedEventHandler(myWebClient->DownloadFileCompleted); myWebClient-DownloadFileAsync(gcnew Uri(fileUrl),"C:\rapid\"+Path::GetFileName(fileUrl)); }

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  • Why does grails use hsqldb when I ask for mysql?

    - by John
    I'm following the racetrack example from Jason Rudolph's book at InfoQ, using grails-1.2.1. I got up to the part where I was to switch from hsqldb to mysql. I think I've deleted every reference to hsqldb in the DataSource.groovy file, but I get an exception and the stack trace shows it's still using hsqldb. DataSource.groovy dataSource { boolean pooled = true String driverClassName = "com.mysql.jdbc.Driver" String url = "jdbc:mysql://localhost/dfpc2" String dbCreate = "create" String username = "dfpc2" String password = "dfpc2" dialect = org.hibernate.dialect.MySQL5InnoDBDialect } hibernate { cache.use_second_level_cache=true cache.use_query_cache=true cache.provider_class='net.sf.ehcache.hibernate.EhCacheProvider' } // environment specific settings environments { development { } test { } production { } } When I grails run-app it all starts up with no errors. I can navigate to the home page. But when I click on one of the links, I get a stack trace: java.sql.SQLException: Table not found in statement [select this_.id as id0_0_, this_.version as version0_0_, this_.name as name0_0_, this_.variant as variant0_0_ from domainObject this_ limit ?] at org.hsqldb.jdbc.Util.throwError(Unknown Source) at org.hsqldb.jdbc.jdbcPreparedStatement.<init>(Unknown Source) at org.hsqldb.jdbc.jdbcConnection.prepareStatement(Unknown Source) at dfpc2.domainObjectController$_closure2.doCall(script1269434425504953491149.groovy:13) at dfpc2.domainObjectController$_closure2.doCall(script1269434425504953491149.groovy) at java.lang.Thread.run(Thread.java:619) My mysql database shows no tables created. (I don't think groovy's connected to mysql yet.) Things I've checked: mysql-connector-java-5.1.6.jar is in lib directory. I've tried grails clean I tried putting the dataSource info in the development environment (I haven't graduated to test or prod yet), but it seemed to make no difference. The stdout shows I'm using development env. I've googled for solutions, but the only solution I've found is when people don't change the test or production environments.

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  • iPhone - Problem with in-app purchases

    - by Satyam svv
    I've created iPhone app with in-app purchase. Now, I'm in testing phase. I created provisioning profile com.satyam.testapp In iTunes connected I created the application and uploaded the images, screen shots, desscription etc. I also created two id's for in-app purchase. One is com.satyam.testapp.book1 and the other one is com.satyam.testapp.book5 I created test account also for verifying my in-app purchases. Using com.stayam.testapp i created developer test profile and using the same in my developed application. I logged out the itunes app store account in my iphone. Now i started running my application on my iphone. Its saying that no items are there to purchase. But its not even asking me for credentials where i've to enter test account username and password..... how to debug it? Here's my delegate: - (void)productsRequest:(SKProductsRequest *)request didReceiveResponse:(SKProductsResponse *)response { NSArray *myProduct = [[NSArray alloc] initWithArray:response.products]; for(int i=0;i<[myProduct count];i++) { SKProduct *product = [myProduct objectAtIndex:i]; NSLog(@"Name: %@ - Price: %f",[product localizedTitle],[[product price] doubleValue]); NSLog(@"Product identifier: %@", [product productIdentifier]); } for(NSString *invalidProduct in response.invalidProductIdentifiers) NSLog(@"Problem in iTunes connect configuration for product: %@", invalidProduct); [request autorelease]; [myProduct release]; }

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  • Silverlight 4 XAML Collections

    - by mattduffield
    Hello, I have authored some custom classes that I would like to create using XAML: <Grid Width="300" Height="300"> <l:DashboardTable> <l:DashboardTable.DashboardTableQuery> <dq:DashboardTableQuery ConnectionString="Data Source=bunkerhill;Initial Catalog=emgov_data;User Id=emgovadmin;Password=p@$$word;" Query="select datename(month, cr_tb_DateDue) AS Month, sum(cr_tb_AmountTransaction) AS Total from cr_tb_transactionbill where Year(cr_tb_DateDue) = 2005 and Month(cr_tb_DateDue) IN (1,2,3,4) group by datename(month, cr_tb_DateDue)" > <dq:DashboardTableQuery.DataColumns> <dq:DataColumn ColumnName="Month" ColumnOrder="0" Label="Month" /> <dq:DataColumn ColumnName="Total" ColumnOrder="1" Label="Total" /> </dq:DashboardTableQuery.DataColumns> </dq:DashboardTableQuery> </l:DashboardTable.DashboardTableQuery> </l:DashboardTable> </Grid> The problem is that I get a XamlParseException when I try to run this XAML. I have determined it is when it gets to the dq:DataColumn element. It seems like this is only happening when I have a property that then has a collection and then several items in the collection that I am getting this issue. Has any encountered anything similar? I am try to achieve this all in XAML declaratively.

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  • How to visually reject user input in a table?

    - by FX
    In the programming of a table-based application module (i.e. the user mostly enters tabular data in an already laid-out table), how would you reject user input for a given cell? The scenario is: the user edits the cell, enters something (text, picture, ...) and you want them to notice when they finish editing (hitting enter, for example) that their entry is not valid for your given "format" (in the wider meaning: it can be that they entered a string instead of a number, that their entry is too long, too short, they include a picture while it's not acceptable, ...). I can see two different things happening: You can rather easily fit their entry into your format, and you do so, but you want them to notice it so they can change if your guess is not good enough (example: they entered "15.47" in a field that needs to be an integer, so your program makes it "15") You cannot guess what to do with their entry, and want to inform them that it's not valid. My question specifically is: what visual display can you offer to inform the user that his input is invalid? Is it preferable to refuse to leave the editing mode, or not? The two things I can imagine are: using colors (red background if invalid, yellow background for my case 1 above) when you reject an input, do something like Apple does for password entry of user accounts: you make the cell "shaking" (i.e. oscillating left and right) for one second, and keep the focus/editing in their so they don't loose what they've typed. Let's hear your suggestions. PS: This question is, at least in my thought process, somehow a continuation and a specialization of my previous question on getting users to read error messages. PPS: Made this community wiki, was that the right thing to do on this kind of question or not?

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  • Session variables not getting set but only in Internet Explorer and not on all machines

    - by gaoshan88
    Logging into a site I'm working on functions as expected on my local machine but fails on the remote server but ONLY in Internet Explorer. The kicker is that it works in IE locally, just not on the remote machine. What in the world could cause this? I have stepped through the code on the remote machine and can see the entered login values being checked in the database, they are found and then a login function is called. This sets two $_SESSION variables and redirects to the main admin page. However, in IE only (and not when run on local machine... this is key) the $_SESSION variables are not present by the time you get to the main admin page. var_dump($_SESSION) gives me what I expect on every browser when I am running this in my local environment and in every browser except IE 6, 7 and 8 when run on the remote server (where I get a null value as if nothing has been set for $_SESSION). This really has me stumped so any advice is appreciated. For an example... in IE, run locally, var_dump gives me: array 'Username' => string 'theusername' length=11 'UserID' => string 'somevalue' length=9 Run on the remote server (IE only... works fine in other browsers) var_dump gives me: array(0){} Code: $User = GetUser($Username, $Password); if ($User->UserID <> "") { // this works so we call Login()... Login($User); // this also works and gives expected results. on to redirect... header("Location: index.php"); // a var_dump at index.php shows that there is no session data at all in IE, remotely. } else { header("Location: login.php"); } function Login($data) { $_SESSION['Username'] = $data->Username; $_SESSION['UserID'] = $data->UserID; // a var dump here gives the expected data in every browser }

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  • LDAP query using Python: always no result

    - by Grey
    I am trying to use python to query LDAP server, and it always returns me no result. and anyone help me find what wrong with my python code? it runs fine without excpetions, and it always has no result. i played around with the filter like "cn=partofmyname" but just no luck. thanks for help import ldap try: l = ldap.open("server") l.protocol_version = ldap.VERSION3 l.set_option(ldap.OPT_REFERRALS, 0) output =l.simple_bind("cn=username,cn=Users,dc=domian, dc=net",'password$R') print output except ldap.LDAPError, e: print e baseDN = "DC=rim,DC=net" searchScope = ldap.SCOPE_SUBTREE ## retrieve all attributes - again adjust to your needs - see documentation for more options retrieveAttributes = None Filter = "(&(objectClass=user)(sAMAccountName=myaccount))" try: ldap_result_id = l.search(baseDN, searchScope, Filter, retrieveAttributes) print ldap_result_id result_set = [] while 1: result_type, result_data = l.result(ldap_result_id, 0) if len(result_data) == 0: print 'no reslut' break else: for i in range(len(result_set)): for entry in result_set[i]: try: name = entry[1]['cn'][0] email = entry[1]['mail'][0] phone = entry[1]['telephonenumber'][0] desc = entry[1]['description'][0] count = count + 1 print "%d.\nName: %s\nDescription: %s\nE-mail: %s\nPhone: %s\n" %\ (count, name, desc, email, phone) except: pass ## here you don't have to append to a list ## you could do whatever you want with the individual entry #if result_type == ldap.RES_SEARCH_ENTRY: # result_set.append(result_data) # print result_set except ldap.LDAPError, e: print e l.unbind()

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  • PHP Ampersand in String

    - by John
    Hello. I'm having a bit of a problem. I am trying to create an IRC bot, which has an ampersand in its password. However, I'm having trouble putting the ampersand in a string. For example... <?php $var = "g&abc123"; echo $var; ?> I believe this should print g&abc123. However it's printing g. I have tried this as well: <?php $arr = array("key" => "g&abc123"); print_r($arr); ?> This prints it correctly with the g&abc123, however when I say echo $arr['key']; it prints g again. Any help would be appreciated. I'm running PHP5.3.1. EDIT: Also, I just noticed that if I use g&abc123&abc123 it prints g&abc123. Any suggestions?

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  • How many WCF connections can a single host handle?

    - by mafutrct
    I'll try to explain this with an example. I'm writing a chat application. There are users that can join chat rooms. A user has to log in before he can join any room. Currently, there is a single service. A user logs in using this service. Then, the user sends and receives messages for all joined rooms via this single service. channel.Login("Hans Moleman", "password"); channel.JoinRoom("name of room"); channel.SendChat("name of room", "hello"); I'm thinking about changing the design so there is a new WCF connection for each joined room. In the actual app, the number of connections is likely going to be in the range of 10-100, possibly more. Is this a good idea? Or are ~100 connections per client too much? The server should be able to handle many clients (range 100-1000, later up to 10k). In case it matters, I'm using NetTcpBinding.

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