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  • java multipart POST library

    - by tom
    Is there a multipart POST library out there that achieve the same effect of doing a POST from a html form? for example - upload a file programmingly in Java versus upload the file using a html form. And on the server side, it just blindly expect the request from client side to be a multipart POST request and parse out the data as appropriate. Has anyone tried this? specifically, I am trying to see if I can simulate the following with Java The user creates a blob by submitting an HTML form that includes one or more file input fields. Your app sets blobstoreService.createUploadUrl() as the destination (action) of this form, passing the function a URL path of a handler in your app. When the user submits the form, the user's browser uploads the specified files directly to the Blobstore. The Blobstore rewrites the user's request and stores the uploaded file data, replacing the uploaded file data with one or more corresponding blob keys, then passes the rewritten request to the handler at the URL path you provided to blobstoreService.createUploadUrl(). This handler can do additional processing based on the blob key. Finally, the handler must return a headers-only, redirect response (301, 302, or 303), typically a browser redirect to another page indicating the status of the blob upload. Set blobstoreService.createUploadUrl as the form action, passing the application path to load when the POST of the form is completed. <body> <form action="<%= blobstoreService.createUploadUrl("/upload") %>" method="post" enctype="multipart/form-data"> <input type="file" name="myFile"> <input type="submit" value="Submit"> </form> </body> Note that this is how the upload form would look if it were created as a JSP. The form must include a file upload field, and the form's enctype must be set to multipart/form-data. When the user submits the form, the POST is handled by the Blobstore API, which creates the blob. The API also creates an info record for the blob and stores the record in the datastore, and passes the rewritten request to your app on the given path as a blob key.

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  • Using one data source across multiple views in Kendo UI SPA

    - by user3731783
    I am trying to build a Kendo UI SPA. I have two views. View 1 (appListView) shows Application Details in a grid and view 2 (activityView) will have a dropdown for application names and a grid that shows the activity for selected application As I am loading all the application details on the loading of view 1, I would like to re-use those details to populate the dropdown on view 2. Please see my code below. Everything works fine but when I go to View 2 it makes a call to the service again to get application details. I would like to use the existing data if it is already loaded and if the uses comes to view 2 directly then it should get application data also. I am not sure what I am missing in the code. View Markup: <script id="appListView" type="text/x-kendo-template"> <h3 data-bind="html: displayName"></h3> <div data-role="grid" data-editable="{'mode':'popup'}" data-bind="source: items" data-columns="[ {'field': 'Name'}, {'field': 'ContactEmail','title':'Contact Email'} ]"> </div> </script> <script id="" type="text\x-kendo-template"> <div> Activity for Application&nbsp;&nbsp; <input name="AppName" data-role="dropdownlist" data-source="appsModel.items" data-text-field="Name" data-value-field="Id" data-option-label="Choose an application name" style="width:250px;" /> </div> <div id="Activities" data-role="grid" data-bind="source: items" data-auto-bind="false" data-columns="[ {'field': 'Domain','title':'Domain'}, {'field': 'ActivityType','title':'Activity Type'} ]"> </div> </script> js with DataSource and View Model: //data sources var applications = new kendo.data.DataSource({ schema: { model: { id: "Id" } }, serverFiltering : true, transport: { read: { url: '/api/App', dataType: 'json', type:'GET' } } }); var activities = new kendo.data.DataSource({ schema: { model: { id: "Id" } }, transport: { read: { url: '/api/Activity', dataType: 'json', type: 'GET' }, parameterMap: function (data, type) { if (type == "read") { return 'appId=' + $("#AppName").val() ; } } } }); //Models var appsModel = kendo.observable({ items: applications, displayName: 'My Applications' }); var activityModel = kendo.observable({ items: activities, onAppChange: function(t){ $("#Activities").data("kendoGrid").dataSource.read(); }, dispayName: 'Application Activities' }); //views var layout = new kendo.Layout("layout-template"); var appListView = new kendo.View("appListView", { model: appsModel }); var activityView = new kendo.View("activityView", { model: activityModel }); Thank you for taking time to read this long question.

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  • IE is not firing ajax call in jquery

    - by VinTem
    I have this code that it is working on firefox and chrome, but in IE8/IE7 it's not working. The server is not been reached ever. $("#adicionarItem").click(function(){ $.ajax({ type: 'GET', url: $("#formAdicionaItem").attr("action"), data: $("#formAdicionaItem").serialize(), success: function(result){ //do something } } }); }); Does anyone has any idea what is wrong? Thanks

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  • 404 with spring 3

    - by markjason72
    hi I am going through my first lessons with spring 3.I created a dynamic web app in eclipse with the following structure. spring3mvc \src\my.spring.HelloWorldController.java \WebContent | |-----WEB-INF\jsp\hello.jsp |-----index.jsp |-----web.xml |-----WEB-INF\spring-servlet.xml |-----WEB-INF\lib\...*.jar files I created the spring-servlet.xml as below <context:component-scan base-package="my.spring" /> <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" /> <property name="prefix" value="/WEB-INF/jsp/" /> <property name="suffix" value=".jsp" /> </bean> and coded the controller package my.spring; import org.springframework.stereotype.Controller; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.servlet.ModelAndView; @Controller public class HelloWorldController { @RequestMapping("/hello") public ModelAndView helloWorld() { String message = "Hello World, Spring 3.0!"; return new ModelAndView("hello", "message", message); } } index.jsp has a link to hello view <html> <body> <a href="hello.html">Say Hello</a> </body> </html> finally in hello.jsp I have put <html> <body> ${message} </body> </html> My web.xml has <display-name>Spring3MVC</display-name> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> <servlet> <servlet-name>spring</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>spring</servlet-name> <url-pattern>*.html</url-pattern> </servlet-mapping> When I run the app on Tomcat6 server( thru eclipse),I can see the index page at http://localhost:8080/Spring3MVC/ .It displays the link to hello page.When I click on it(http://localhost:8080/Spring3MVC/hello.html),I get a 404 error. message /Spring3MVC/hello.html description The requested resource (/Spring3MVC/hello.html) is not available. Any idea how I can solve this? thanks mark.

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  • Making a rewriterule remove .php extension?

    - by Sam
    Hello, I have come up with a rewriterule to to go to any page on my website without typing in the .php extension because it is automatically added to the url. The rule is: RewriteRule ^(\w+)/?$ /$1.php It takes anything you type in my index and adds .php to it, so you can put in http://sampardee.com/index and it pulls up index.php Now my question is how to detect when a user enters http://sampardee.com/index.php and change it to http://sampardee.com/index How could I do so with a rewriterule?

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  • Preview an html page without opening it

    - by Hulk
    On click a image how can another page be previewed in the same page without opening the actual page.And lets say the url /home/home.php?id=3 The preview should be in the preview div <img src="/home/app/img/toggle.gif" onlclick="show();" /> <div id="preview"></div> Thanks..

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  • error with redirect using listener JSF 2.0

    - by Ray
    I have a index.xhtml page <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:h="http://java.sun.com/jsf/html" xmlns:f="http://java.sun.com/jsf/core" xmlns:ui="http://java.sun.com/jsf/facelets"> <f:view> <ui:insert name="metadata" /> <f:event type="preRenderView" listener="#{item.show}" /> <h:body></h:body> </f:view> </html> And in bean class with scope session this method public void show() throws IOException, DAOException { ExternalContext externalContext = FacesContext.getCurrentInstance() .getExternalContext(); //smth String rootPath = externalContext.getRealPath("/"); String realPath = rootPath + "pages\\template\\body\\list.xhtml"; externalContext.redirect(realPath); } i think that I should redirect to next page but I have "browser can't show page" and list.xhtml (if I do this page as welcome-page I haven't error, it means that error connected with redirect) <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:h="http://java.sun.com/jsf/html" xmlns:f="http://java.sun.com/jsf/core" xmlns:ui="http://java.sun.com/jsf/facelets"> <h:body> <ui:composition template="/pages/layouts/mainLayout.xhtml"> <ui:define name="content"> <h:form></h:form></ui:define></ui:composition> </h:body> </html> in consol i didn't have any error. in web.xml <welcome-file-list> <welcome-file>index.xhtml</welcome-file> </welcome-file-list> <servlet> <servlet-name>Faces Servlet</servlet-name> <servlet-class>javax.faces.webapp.FacesServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>Faces Servlet</servlet-name> <url-pattern>*.xhtml</url-pattern> </servlet-mapping> What can be the reason this problem?

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  • will_paginate link to nested resources

    - by neotracker
    Hi, I'm using the will paginate gem from http://github.com/mislav/will_paginate Routes: map.resources :post do |post| post.resources :comments end Post Controller: @post = Post.first @comments = @post.comments.paginate :page => params[:page], :per_page => 10 My problem lies in the view: <%= will_paginate @comments %> This generates links like /post/1?page=1 What I need is /post/1/comments?page=1 Is there a way to just tell will_paginate what url helper to use? (like post_comments_path) Any ideas?

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  • Simple Iphone XML Example

    - by dub
    Hi, I a bit overwhelmed with all of the sample code I've seen on the apple dev site. I'm looking for a simple example to show me how to load an xml file from a server into iphone. I would like to read url's from this xml file and load an image.

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  • Problem Executing Async Web Request

    - by davidhayes
    Hi Can anyone tell me what I've done wrong with this simple code? When I run it it hangs on using (Stream postStream = request.EndGetRequestStream(asynchronousResult)) If I comment out the requestState.Wait.WaitOne(); line the code executes correctly but obviously doesn't wait for the response. I'm guessing the the call to EndGetRequestStream is somehow returning me to the context of the main thread?? I'm pretty sure my code is essentially the same as the sample though (MSDN Documentation) using System; using System.Net; using System.Windows; using System.Windows.Controls; using System.Windows.Documents; using System.Windows.Ink; using System.Windows.Input; using System.Windows.Media; using System.Windows.Media.Animation; using System.Windows.Shapes; using System.IO; using System.Text; namespace SBRemoteClient { public class JSONClient { public string ExecuteJSONQuery(string url, string query) { System.Uri uri = new Uri(url); HttpWebRequest request = (HttpWebRequest)WebRequest.Create(uri); request.Method = "POST"; request.Accept = "application/json"; byte[] requestBytes = Encoding.UTF8.GetBytes(query); RequestState requestState = new RequestState(request, requestBytes); IAsyncResult resultRequest = request.BeginGetRequestStream(new AsyncCallback(GetRequestStreamCallback), requestState); requestState.Wait.WaitOne(); IAsyncResult resultResponse = (IAsyncResult)request.BeginGetResponse(new AsyncCallback(GetResponseStreamCallback), requestState); requestState.Wait.WaitOne(); return requestState.Response; } private static void GetRequestStreamCallback(IAsyncResult asynchronousResult) { try { RequestState requestState = (RequestState)asynchronousResult.AsyncState; HttpWebRequest request = requestState.Request; using (Stream postStream = request.EndGetRequestStream(asynchronousResult)) { postStream.Write(requestState.RequestBytes, 0, requestState.RequestBytes.Length); } requestState.Wait.Set(); } catch (Exception e) { Console.Out.WriteLine(e); } } private static void GetResponseStreamCallback(IAsyncResult asynchronousResult) { RequestState requestState = (RequestState)asynchronousResult.AsyncState; HttpWebRequest request = requestState.Request; using (HttpWebResponse response = (HttpWebResponse)request.EndGetResponse(asynchronousResult)) { using (Stream responseStream = response.GetResponseStream()) { using (StreamReader streamRead = new StreamReader(responseStream)) { requestState.Response = streamRead.ReadToEnd(); requestState.Wait.Set(); } } } } } }

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  • iframe src based on javascript variable value

    - by Ra
    Hi, I have a Iframe, and how to pass a javascript vairable to along with a iframe src. ex: var param1=test1; how to pass "param1" value along with the iframe url. and i want to pass like this. <iframe frameborder=0 src="http://cart.demo.com/c_jp.php?action=param1" name="navigationframe" id="navigationframe" width="220" height="800"> Thanks in advance.

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  • Get individual query parameters from Uri

    - by Ghostrider
    I have a uri string like: http://example.com/file?a=1&b=2&c=string%20param Is there an existing function that would convert query parameter string into a dictionary same way as ASP.NET Context.Request does it. I'm writing a console app and not a web-service so there is no Context.Request to parse the URL for me. I know that it's pretty easy to crack the query string myself but I'd rather use a FCL function is if exists.

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  • Can this jQuery/Javascript functionality be replicated with PHP

    - by benhowdle89
    This is the code to grab tweets, but i need this in PHP, can anybody offer any insight? $(document).ready( function() { var url = "http://twitter.com/status/user_timeline/joebloggs.json?count=1&callback=?"; $.getJSON(url, function(data){ $.each(data, function(i, item) { $("#twitter-posts").append("<p>" + item.text.linkify() + " <span class='created_at'>" + relative_time(item.created_at) + " via " + item.source + "</span></p>"); }); }); }); String.prototype.linkify = function() { return this.replace(/[A-Za-z]+:\/\/[A-Za-z0-9-_]+\.[A-Za-z0-9-_:%&\?\/.=]+/, function(m) { return m.link(m); }); }; function relative_time(time_value) { var values = time_value.split(" "); time_value = values[1] + " " + values[2] + ", " + values[5] + " " + values[3]; var parsed_date = Date.parse(time_value); var relative_to = (arguments.length > 1) ? arguments[1] : new Date(); var delta = parseInt((relative_to.getTime() - parsed_date) / 1000); delta = delta + (relative_to.getTimezoneOffset() * 60); var r = ''; if (delta < 60) { r = 'a minute ago'; } else if(delta < 120) { r = 'couple of minutes ago'; } else if(delta < (45*60)) { r = (parseInt(delta / 60)).toString() + ' minutes ago'; } else if(delta < (90*60)) { r = 'an hour ago'; } else if(delta < (24*60*60)) { r = '' + (parseInt(delta / 3600)).toString() + ' hours ago'; } else if(delta < (48*60*60)) { r = '1 day ago'; } else { r = (parseInt(delta / 86400)).toString() + ' days ago'; } return r; } function twitter_callback () { return true; }

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  • question on rss feed application

    - by molleman
    Hello Guys i just want to create a simple application that will allow a user to input a url to a rss feed and display the contents to a user. what would be a good java library to enable me to read rss feeds? cheers

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  • Dynamic content doesn't work when loaded with ajax

    - by Wurlitzer
    I'm trying to load some dynamic content after the user has logged in, using $.ajax, like so: $.ajax({ url: "functions.php", type: "GET", data: login_info, datatype: 'html', async: false, success: function (response) { $('#main').html(response); } }); The problem is, that some events don't work, when loaded this way. I fixed the buttons with the .live() method, but a sortable list for example, doesn't work. How can I somehow refresh the DOM, and let jquery know of these new added elements? Thanks!

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  • deallocated memory in tableview: message sent to deallocated instance

    - by Kirn
    I tried looking up other issues but couldn't find anything to match so here goes: I'm trying to display text in the table view so I use this bit of code: // StockData is an object I created and it pulls information from Yahoo APIs based on // a stock ticker stored in NSString *heading NSArray* tickerValues = [heading componentsSeparatedByString:@" "]; StockData *chosenStock = [[StockData alloc] initWithContents:[tickerValues objectAtIndex:0]]; [chosenStock getData]; // Set up the cell... NSDictionary *tempDict = [chosenStock values]; NSArray *tempArr = [tempDict allValues]; cell.textLabel.text = [tempArr objectAtIndex:indexPath.row]; return cell; This is all under cellForRowAtIndexPath When I try to release the chosenStock object though I get this error: [CFDictionary release]: message sent to deallocated instance 0x434d3d0 Ive tried using NSZombieEnabled and Build and Analyze to detect problems but no luck thus far. Ive even gone so far as to comment bits and pieces of the code with NSLog but no luck. I'll post the code for StockData below this. As far as I can figure something is getting deallocated before I do the release but I'm not sure how. The only place I've got release in my code is under dealloc method call. Here's the StockData code: // StockData contains all stock information pulled in through Yahoo! to be displayed @implementation StockData @synthesize ticker, values; - (id) initWithContents: (NSString *)newName { if(self = [super init]){ ticker = newName; } return self; } - (void) getData { NSURL *url = [NSURL URLWithString: [NSString stringWithFormat:@"http://download.finance.yahoo.com/d/quotes.csv?s=%@&f=%@&e=.csv", ticker, @"chgvj1"]]; NSError *error; NSURLResponse *response; NSURLRequest *request = [NSURLRequest requestWithURL:url]; NSData *stockData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; if(stockData) { NSString *tempStr = [[NSString alloc] initWithData:stockData encoding:NSASCIIStringEncoding]; NSArray *receivedValuesArr = [tempStr componentsSeparatedByString:@","]; [tempStr release]; values = [NSDictionary dictionaryWithObjects:receivedValuesArr forKeys:[@"change, high, low, volume, market" componentsSeparatedByString:@", "]]; } else { NSLog(@"Connection failed: %@", error); } } - (void)dealloc { [ticker release]; [values release]; [super dealloc]; NSLog(@"Release took place fine"); } @end

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  • Window.open is not working in IE8 fine in firefox.

    - by lakshmi
    I having trouble getting pop-up window in IE. I have used following code. Its works fine in Firefox but not in IE6. Code: com.google.gwt.user.client.Window.open(url, "Admin ", "menubar=no," + "location=false," + "resizable=yes," + "scrollbars=yes," + "status=no," + "dependent=true");; Any Help greatly Appreciated

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