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  • Nhibernate criteria query inserts an extra order by expression when using JoinType.LeftOuterJoin and Projections

    - by Aaron Palmer
    Why would this nhibernate criteria query produce the sql query below? return Session.CreateCriteria(typeof(FundingCategory), "fc") .CreateCriteria("FundingPrograms", "fp") .CreateCriteria("Projects", "p", JoinType.LeftOuterJoin) .Add(Restrictions.Disjunction() .Add(Restrictions.Eq("fp.Recipient.Id", recipientId)) .Add(Restrictions.Eq("p.Recipient.Id", recipientId)) ) .SetProjection(Projections.ProjectionList() .Add(Projections.GroupProperty("fc.Name"), "fcn") .Add(Projections.Sum("fp.ObligatedAmount"), "fpo") .Add(Projections.Sum("p.ObligatedAmount"), "po") ) .AddOrder(Order.Desc("fpo")) .AddOrder(Order.Desc("po")) .AddOrder(Order.Asc("fcn")) .List<object[]>(); SELECT this_.Name as y0_, sum(fp1_.ObligatedAmount) as y1_, sum(p2_.ObligatedAmount) as y2_ FROM fundingCategories this_ inner join fundingPrograms fp1_ on this_.fundingCategoryId = fp1_.fundingCategoryId left outer join projects p2_ on fp1_.fundingProgramId = p2_.fundingProgramId WHERE (fp1_.recipientId = 6 /* @p0 */ or p2_.recipientId = 6 /* @p1 */) GROUP BY this_.Name ORDER BY p2_.name asc, y1_ desc, y2_ desc, y0_ asc It is incorrectly putting the p2_name asc into the ORDER BY statement, and causing it to crash. This only happens when I use JoinType.LeftOuterJoin on my Projects criteria. Is this a known nhibernate bug? I'm using nhibernate 2.0.1.4000. Thanks for any insight.

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  • Shorter Binding expression with validation

    - by Andrii V
    Hi, I'm repeating same binding parameters for every textbox and they're quite long strings (which is not good for many reasons). And I'm wondering if there's a way to make them shorter? For instance all my controls on forms are using the following binding template: Text="{Binding SourceProperty, UpdateSourceTrigger=PropertyChanged, ValidatesOnExceptions=True, ValidatesOnDataErrors=True, NotifyOnValidationError=True}" I'd would like to have something shorter that ideally will take SourceProperty as parameter. Possbly like this: Text="{MyBinding SourceProperty}" or Text="{Binding SourceProperty, Params=MyParams}" One possible option would be to inherit from Binding and create new markup extension. Did someone tried this? Any other ideas how to make these repetetive bindings look better?

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  • regular expression help

    - by hao
    <li class="zk_list_c2 f_l"><a title="abc" target="_blank" href="link"> abc </a>&nbsp;</li> how would i extract abc and link? $pattern="/<li class=\"zk_list_c2 f_l\"><a title=\"(.*)\" target=\"_blank\" href=\"(.*)\">\s*(.*)\s*<\/a>&nbsp;<\/li>/m"; preg_match_all($pattern, $content, $matches); the one i have right now doesnt seems to work

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  • I'm trying to use a regular expression to retrieve text from RichTextBox

    - by Simon
    Hello! As the header is implying I'm trying to retrieve a certain line of numbers from a richtextbox and then put it into a separate textbox. I've tried this code below but it doesn't wanna work with me. It's probably way wrong and there's probably easier ways of doing it but I'm quite new to this stuff and I would appreciate all the help I can get in this matter. I have a textbox called tbPersNr; A RichTextBox called tbText; A button which is called btnGet; string regPattern = @"\\d{6}-\\d{4}"; int indexOfSearch = 0; private void btnGet_Click(object sender, EventArgs e) { int startIndex = 0; if (tbText.Text.Length > 0) { startIndex = HittaPersNr(regPattern, startIndex, tbText.Text.Length); } if (startIndex > 0) { this.tbPersNr.Text = regPattern.ToString(); } } public int HittaPersNr(string txtToSearch, int searchStart, int searchEnd) { // Setting default value to -1. int retVal = -1; // Validating start of the search // om indexOfSearch = -1, slutar sökningen if (searchStart >= 0 && indexOfSearch >= 0) { // Validating end of search if (searchEnd > searchStart || searchEnd == -1) { // Searching for results in richtextbox indexOfSearch = tbText.Find(regPattern, searchStart, searchEnd, RichTextBoxFinds.None); // Validating if search resulted in any finds. if (indexOfSearch != -1) { // putting index to value in the text. retVal = indexOfSearch; } } } return retVal; } } } Cheers

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  • can't insert xml dml expression as a string

    - by 81967
    Here is the code below that would explain you the problem... I create a table below with an xml column and declare a variable, initialize it and Insert the Value into the xml column, create table CustomerInfo (XmlConfigInfo xml) declare @StrTemp nvarchar(2000) set @StrTemp = '<Test></Test>' insert into [CustomerInfo](XmlConfigInfo) values (@StrTemp) Then comes the part of the question,, if I write this... update [CustomerInfo] set XmlConfigInfo.modify('insert <Info></Info> into (//Test)[1]') -- Works Fine!!! but when I try this, set @StrTemp = 'insert <Info></Info> into (//Test)[1]' update [CustomerInfo] set XmlConfigInfo.modify(@StrTemp) -- Doesn't Work!!! and throws an error The argument 1 of the xml data type method "modify" must be a string literal. is there a way around for this one? I tried this, but it is not working :(

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  • Javascript expression to define object's property name?

    - by Kirzilla
    Hello, I'd like to create this object... object = { 'object[1][var_name_1]' : 'value1', 'object[1][var_name_2]' : 'value2', }; I'm trying to it this way, but I'm getting error missing : after property id... function getPrefix() { return 'object[1]'; } object = { getPrefix() + '[var_name_1]' : 'value1', getPrefix() + '[var_name_2]' : 'value2', } What am I doing wrong? Or maybbe it is impossible to set object property name using js experession? Thank you

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  • .NET Regular Expression to split multiple words or phrases

    - by Cj Anderson
    I'm using the code below to take a string and split it up into an array. It will take: Disney Land and make it two separate elements. If the string contains "Disney Land" then it is one element in the array. Works great, however it adds some empty elements to the array each time. So I just iterate over the elements and remove them if they are empty. Is there a tweak to the code below that will prevent those empty elements from occurring? Private m_Reg As Regex m_Reg = New Regex("([^""^\s]+)\s*|""([^""]+)""\s*") Dim rezsplit = m_Reg.Split(criteria)

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  • Regular Expression Help - Brackets within brackets

    - by adbox
    Hello I'm trying to develop a function that can sort through a string that looks like this: Donny went to the {park|store|{beach with friends|beach alone}} so he could get a breath of freash air. What I intend to do is search the text recursively for {} patterns where there is no { or } inside the {}, so only the innermost sandwiched text is selected, where I will then run a php to array the contents and select one at random, repeating process until the whole string has been parsed, showing a complete sentence. I just cannot wrap my head around regular expressions though. Appreciate any help!

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  • Excel Matching problem with logic expression

    - by abelenky
    (I understand Excel is only borderline programming) I have a block of data that represents the steps in a process and the possible errors: ProcessStep Status FeesPaid OK FormRecvd OK RoleAssigned OK CheckedIn Not Checked In. ReadyToStart Not Ready for Start I want to find the first Status that is not "OK". I have attempted this: =Match("<>""OK""", StatusRange, 0) which is supposed to return the index of the first element in the range that is NOT-EQUAL (<) to "OK" But this doesn't work, instead returning #N/A. I expect it to return 4 (index #4, in a 1-based index, representing that CheckedIn is the first non-OK element) Any ideas how to do this?

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  • JSP: EL expression is not evaluated

    - by James
    I have a JSP page running on Tomcat 5.5. I have the following code: <c:forEach var="i" begin="1" end="10" step="1"> <c:out value="${i}" /> <br /> </c:forEach> The output I am getting is: ${i} ${i} ${i} ${i} ${i} ${i} ${i} ${i} ${i} ${i} I cant work out why the forEach loop is working but the output is not working. Any help any one could give would be great.

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  • Regular expression of unicode characters on string

    - by Marcus King
    I'm working in c# doing some OCR work and have extracted the text I need to work with. Now I need to parse a line using Regular Expressions. string checkNum; string routingNum; string accountNum; Regex regEx = new Regex(@"\u9288\d+\u9288"); Match match = regEx.Match(numbers); if (match.Success) checkNum = match.Value.Remove(0, 1).Remove(match.Value.Length - 1, 1); regEx = new Regex(@"\u9286\d{9}\u9286"); match = regEx.Match(numbers); if(match.Success) routingNum = match.Value.Remove(0, 1).Remove(match.Value.Length - 1, 1); regEx = new Regex(@"\d{10}\u9288"); match = regEx.Match(numbers); if (match.Success) accountNum = match.Value.Remove(match.Value.Length - 1, 1); The problem is that the string contains the necessary unicode characters when I do a .ToCharArray() and inspect the contents of the string, but it never seems to recognize the unicode characters when I parse the string looking for them. I thought strings in C# were unicode by default.

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  • How to evaluate a custom math expression in Python

    - by taynaron
    I'm writing a custom dice rolling parser (snicker if you must) in python. Basically, I want to use standard math evaluation but add the 'd' operator: #xdy sum = 0 for each in range(x): sum += randInt(1, y) return sum So that, for example, 1d6+2d6+2d6-72+4d100 = (5)+(1+1)+(6+2)-72+(5+39+38+59) = 84 I was using regex to replace all 'd's with the sum and then using eval, but my regex fell apart when dealing with parentheses on either side. Is there a faster way to go about this than implementing my own recursive parsing? Perhaps adding an operator to eval?

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  • Can you reverse order a string in one line with LINQ or a LAMBDA expression

    - by Student for Life
    Not that I would want to use this practically (for many reasons) but out of strict curiousity I would like to know if there is a way to reverse order a string using LINQ and/or LAMBDA expressions in one line of code, without utilising any framework "Reverse" methods. e.g. string value = "reverse me"; string reversedValue = (....); and reversedValue will result in "em esrever" EDIT Clearly an impractical problem/solution I know this, so don't worry it's strictly a curiosity question around the LINQ/LAMBDA construct.

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  • Regular expression does not find the first occurrence

    - by scharan
    I have the following input to a perl script and I wish to get the first occurrence of NAME="..." strings in each of the ... structures. The entire file is read into a single string and the reg exp acts on that input. However, the regex always returns the LAST occurrence of NAME="..." strings. Can anyone explain what is going on and how this can be fixed? Input file: ADSDF <TABLE> NAME="ORDERSAA" line1 line2 NAME="ORDERSA" line3 NAME="ORDERSAB" </TABLE> <TABLE> line1 line2 NAME="ORDERSB" line3 </TABLE> <TABLE> line1 line2 NAME="ORDERSC" line3 </TABLE> <TABLE> line1 line2 NAME="ORDERSD" line3 line3 line3 </TABLE> <TABLE> line1 line2 NAME="QUOTES2" line3 NAME="QUOTES3" NAME="QUOTES4" line3 NAME="QUOTES5" line3 </TABLE> <TABLE> line1 line2 NAME="QUOTES6" NAME="QUOTES7" NAME="QUOTES8" NAME="QUOTES9" line3 line3 </TABLE> <TABLE> NAME="MyName IsKhan" </TABLE> Perl Code starts here: use warnings; use strict; my $nameRegExp = '(<table>((NAME="(.+)")|(.*|\n))*</table>)'; sub extractNames($$){ my ($ifh, $ofh) = @_; my $fullFile; read ($ifh, $fullFile, 1024);#Hardcoded to read just 1024 bytes. while( $fullFile =~ m#$nameRegExp#gi){ print "found: ".$4."\n"; } } sub main(){ if( ($#ARGV + 1 )!= 1){ die("Usage: extractNames infile\n"); } my $infileName = $ARGV[0]; my $outfileName = $ARGV[1]; open my $inFile, "<$infileName" or die("Could not open log file $infileName"); my $outFile; #open my $outFile, ">$outfileName" or die("Could not open log file $outfileName"); extractNames( $inFile, $outFile ); close( $inFile ); #close( $outFile ); } #call main();

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  • Regular Expression to break row with comma separated values into distinct rows

    - by Nick
    I have a file with many rows. Each row has a column which may contain comma separated values. I need each row to be distinct (ie no comma separated values). Here is an example row: AB AB10,AB11,AB12,AB15,AB16,AB21,AB22,AB23,AB24,AB25,AB99 ABERDEEN Aberdeenshire The columns are comma separated (Postcode area, Postcode districts, Post town, Former postal county). So the above row would get turned into: AB AB10 ABERDEEN Aberdeenshire AB AB11 ABERDEEN Aberdeenshire AB AB12 ABERDEEN Aberdeenshire ... ... I tried the following but it didn't work... (.+)\t(([0-9A-Z]+),)+\t(.+)\t(.+)

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  • Regular expression literal

    - by Marcus
    As I'm RegEx dyslexic.. what RegEx can you use to find each of the following strings - with the exception of "LoginException"? NullPointerException LoginException BooException Abc123Exception

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  • Regular expression for parsing CSV in PHP

    - by Discodancer
    I already managed to split the CSV file using this regex: "/,(?=(?:[^\"]\"[^\"]\")(?![^\"]\"))/" But I ended up with an array of strings that contain the opening and ending double quotes. Now I need a regex that would strip those strings of the delimiter double quotes. As far as I know the CSV format can encapsulate strings in double quotes, and all the double quotes that are already a part of the string are doubled. For example: My "other" cat becomes "My ""other"" cat" What I basically need is a regex that will replace all sequences of N doublequotes with a sequence of (N/2 - rounded down) double quotes. Or is there a better way ? Thanks in advance.

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