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  • MVC: models interacts with the view?

    - by fayer
    i know that everything is going through the controller. but i often read articles that says something like this: user interacts with the view controller asks the model to change its state model notifies the view when its sate has changed i dont get the 3rd one. why saying that the model notifies the view, when it actually is notifying the controller and the controller is notifying the view?

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  • JQuery and Patial view in MVC

    - by Poomjai
    Belong to this article Jquery Partial View What should i do when i want to submit the value fill from user and sent it to the ActionResult controller that return the partial view -- View Code that call the controller (from article) <script language="JavaScript" type="text/javascript"> $('#centerbody').load('/Custom/CustomAction', function(html) { $('#centerbody')[0].value = html; }); </script> -- Controller Action with no parameter (from article) public ActionResult CustomAction() { return View("_CustomParialView"); } Thanks for your suggestion

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  • Xib view file is not working in landscape mode

    - by senthilmuthu
    Hi, I have added new Xib view file in my project. I assigned to view controller and in the view controller I set: - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation { //return (interfaceOrientation == UIInterfaceOrientationLandscapeRight); return YES; } But when the application runs in landscape mode, xib is not in landscape mode. I have set in info.plist file also xib file is also in landscape view. What do I have to do? Any help?

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  • ASP.NET MVC 2 AJAX dilemma: Lose Models concept or create unmanageable JavaScript

    - by Slightly Frustrated
    Hi, Ok, let's assume we are working with ASP.NET MVC 2 (latest and greatest preview) and we want to create AJAX user interface with jQuery. So what are our real options here? Option 1 - Pass Json from the Controller to the view, and then the view submits Json back to the controller. This means (in the order given): User opens some View (let's say - /Invoices/January) which has to visualize a list of data (e.g. <IEnumerable<X.Y.Z.Models.Invoice>>) Controller retrieves the Model from the repository (assuming we are using repository pattern). Controller creates a new instance of a class which we will serialize to Json. The reasaon we do this, is because the model may not be serializable (circular reference ftl) Controller populates the soon-to-be-serialized class with data Controller serializes the class to Json and passes it the view. User does some change and submits the 'form' The View submits back Json to the controller The Controller now must 'manually' validate the input, because the Json passed does not bind to a Model See, if our View is communicating to the controller via Json, we lose the Model validation, which IMHO is incredible disadvantage. In this case, forget about data annotations and stuff. Option 2 - Ok, the alternative of the first approach is to pass the Models to the Views, which is the default behavior in the template when you start a new project. We pass a strong typed model to the view The view renders the appropriate html and javascript, sticking to the model property names. This is important! The user submits the form. If we stick to the model names, when we .serialize() the form and submit it to the controller it will map to a model. There is no Json mapping. The submitted form directly binds to a strongly typed model, hence, we can use the model validation. E.g. we keep the business logic where it should be. Problem with this approach is, if we refactor some of the Models (change property names, types, etc), the javascript we wrote would become invalid. We will have to manually refactor the scripting and hope we don't miss something. There is no way you can test it either. Ok, the question is - how to write an AJAX front end, which keeps the business logic validation in the model (e.g. controller passes and receives a Model type), but in the same time doesn't screw up the javascript and html when we refactor the model?

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  • Oracle HRMS API – Create Employee Payment Method

    - by PRajkumar
    API --  hr_personal_pay_method_api.create_personal_pay_method   Example -- DECLARE   ln_method_id  PAY_PERSONAL_PAYMENT_METHODS_F.PERSONAL_PAYMENT_METHOD_ID%TYPE; ln_ext_acc_id        PAY_EXTERNAL_ACCOUNTS.EXTERNAL_ACCOUNT_ID%TYPE; ln_obj_ver_num    PAY_PERSONAL_PAYMENT_METHODS_F.OBJECT_VERSION_NUMBER%TYPE; ld_eff_start_date   DATE;   ld_eff_end_date    DATE; ln_comment_id     NUMBER; BEGIN      -- Create Employee Payment Method      -- --------------------------------------------------       hr_personal_pay_method_api.create_personal_pay_method       (   -- Input data elements           -- ------------------------------           p_effective_date                                     => TO_DATE('21-JUN-2011'),           p_assignment_id                                   => 33561,           p_org_payment_method_id               => 2,           p_priority                                                 => 50,           p_percentage                                           => 100,           p_territory_code                                     => 'US',           p_segment1                                              => 'PRAJKUMAR',           p_segment2                                              => 'S',           p_segment3                                              => '100200300',           p_segment4                                              => '567',           p_segment5                                              => 'HDFC',           p_segment6                                              => 'INDIA',           -- Output data elements           -- --------------------------------           p_personal_payment_method_id   => ln_method_id,           p_external_account_id                       => ln_ext_acc_id,           p_object_version_number                  => ln_obj_ver_num,           p_effective_start_date                          => ld_eff_start_date,           p_effective_end_date                           => ld_eff_end_date,          p_comment_id                                        => ln_comment_id      );    COMMIT; EXCEPTION           WHEN OTHERS THEN                           ROLLBACK;                            dbms_output.put_line(SQLERRM); END; / SHOW ERR;    

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  • MVC Partial View Postback - Jquery validation lost

    - by user415394
    I have a partial view which uses Jquery Valiation. This works OK when initially loaded, however after I do a ajax postback and return the partial view from the server with an error showing, the jquery validation seems to be lost. In that, if I delete a required field and hit save the partial view gets submitted, when I would expect it to show an error message and not get submitted. Does Jquery validation need to be initialised somehow for the form in the partial view?

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  • Force Normal View when generating Word doc via HTML

    - by Jared
    I am creating an HTML document which we are then pushing out to MS Word using a "application/msword" content type. This works so far except that the files open in Word with Web View. Once Normal View is selected all works fine. Is there any way to force Word to open with Normal View instead of Web View?

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  • iPhone: How to Trigger the Loading of a View Using a UI Element in a Previous View

    - by Kevin Horvath
    I've been reading the Head First iPhone Development book and I understand how to get to a new view from a table but how exactly would I be able to get to a new view or view controller, by just simply pressing a button? Is that even possible? I mean there are some apps where you click a button, not a table cell and it loads a new view. How exactly is that done? If someone could help out a newbie it would be greatly appreciated!

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  • Creating a generic NotFound View in ASP.MVC

    - by George
    Hello guys, I'm having a problem to create a generic View to represent NotFound pages. The view is created and it's fine. I need to know how i can direct the user to the NotFound view in my Controllers and how to render a specific "Return to Index" in each controller. Here is some code: public class NotFoundModel { private string _contentName; private string _notFoundTitle; private string _apologiesMessage; public string ContentName { get; private set; } public string NotFoundTitle { get; private set; } public string ApologiesMessage { get; private set; } public NotFoundModel(string contentName, string notFoundTitle, string apologiesMessage) { this._contentName = contentName; this._notFoundTitle = notFoundTitle; this._apologiesMessage = apologiesMessage; } } // NotFound View <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<Geographika.Models.NotFoundModel>" %> <asp:Content ID="Content1" ContentPlaceHolderID="TitleContent" runat="server"> <%= Html.Encode(Model.ContentName) %> </asp:Content> <asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server"> <h2><%= Html.Encode(Model.NotFoundTitle) %></h2> <p><%= Html.Encode(Model.ApologiesMessage) %></p> <!-- How can i render here a specific "BackToIndexView", but that it's not bound to my NotFoundModel? --> </asp:Content> // Controller piece of code // // GET: /Term/Details/2 public ActionResult Details(int id) { Term term = termRepository.SingleOrDefault(t => t.TermId == id); if (term == null) return View("NotFound"); // how can i return the specific view that its not bound to Term Model? // the idea here would be something like: // return View("NotFound",new NotFoundModel("a","b","c")); else return View("Details", term); } I'm not sure how to redirect to a whole different page. Can anyone give me any pointers? Thanks

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  • How to create Chat application using Servlets & JSP

    - by Crazy boy
    I want to create chat application using Servlets & JSP. May I know how can I create chat application as I have never created before? How much knowledge I need to have to create chat application? Is there any need of networking API to create chat application? What's the design pattern I need to follow to create that application? Is there any need of database?

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  • How to check which action method rendered the current view (from within the current view) ?

    - by Richard77
    Hello, I would like to know how to check which action displayed the current View (from the current view). For instance, to check if controller myController originated the rendering (I guess) I can write: <% if(ViewContext.Controller is myApplication.Controllers.myController)%> In fact, I want to use the same View model for 2 actions methods, like this: <% If( First Action rendered this view){%> // Display this <%} else {%> //Display that <%}%> Thanks for helping

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  • SharePoint Error - Datasheet View refuses to show up!

    - by Marius
    Hi, Recently the DataSheet view of my list refuses to dispaly. I tried numerouse times and with no luck. Other lists works just fine, except for this one. there is a Java error message on the left bottom corner of the screen that disapears in 2 seconds, then it renders the list in Standard view any time you try it. I even created a new Datasheet View - the result a Standard View. Any suggestions? Thanks,

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  • Drupal show / hide fields in view

    - by SteD
    I would like to show / hide certain fields in my Drupal view accordingly to the user role. Provided I can only have this view to work with, how can I achieve this programmatically or there's some settings that I am not aware of in Drupal. P/S: I am aware of the access settings under basic settings in View but that would restrict access to the whole view, not field level.

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  • Calling method from view in mvc

    - by Alice in wonderland
    I'm implementing paging on an mvc view, and I want to call a method in the controller from the view view: >a href=">%= Url.Action("Search", new { page = NextPage(Request["exactPage"])).ToString()}) %" controller: public string NextPage(string currentPage) { return (int.Parse(currentPage) + 1).ToString(); } How can I call the NextPage method from the view? thanks!

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  • Converting DTOs to View Models

    - by illvm
    Does anyone know of a good (read: quick to code) method for converting DTOs to View Models or mapping DTO members to View Model members? Lately I've been finding myself writing many conversion and helper methods but this is a very arduous and tedious task. Moreover, it will often needs to be done twice (DTO - View Model, View Model - DTO). Is there a methodology, technique, or technology which would allow me to do this more quickly and efficiently?

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  • Oracle HRMS API – Create Employee Contact

    - by PRajkumar
    API - hr_contact_rel_api.create_contact Example --   DECLARE      ln_contact_rel_id                   PER_CONTACT_RELATIONSHIPS.CONTACT_RELATIONSHIP_ID%TYPE;      ln_ctr_object_ver_num         PER_CONTACT_RELATIONSHIPS.OBJECT_VERSION_NUMBER%TYPE;      ln_contact_person                 PER_ALL_PEOPLE_F.PERSON_ID%TYPE;      ln_object_version_number  PER_CONTACT_RELATIONSHIPS.OBJECT_VERSION_NUMBER%TYPE;      ld_per_effective_start_date DATE;      ld_per_effective_end_date  DATE;      lc_full_name                            PER_ALL_PEOPLE_F.FULL_NAME%TYPE;      ln_per_comment_id              PER_ALL_PEOPLE_F.COMMENT_ID%TYPE;      lb_name_comb_warning     BOOLEAN;      lb_orig_hire_warning           BOOLEAN;   BEGIN     -- Create Employee Contact     -- -------------------------------------      hr_contact_rel_api.create_contact      (    -- Input data elements            -- -----------------------------            p_start_date                                      => TO_DATE('14-JUN-2011'),            p_business_group_id                    => fnd_profile.value('PER_BUSINESS_GROUP_ID'),            p_person_id                                      => 32979,            p_contact_type                                 => 'M',            p_date_start                                      => TO_DATE('14-JUN-2011'),            p_last_name                                     => 'TEST',            p_first_name                                     => 'CONTACT',            p_personal_flag                               => 'Y',            -- Output data elements            -- --------------------------------           p_contact_relationship_id            => ln_contact_rel_id,           p_ctr_object_version_number      => ln_ctr_object_ver_num,           p_per_person_id                              => ln_contact_person,           p_per_object_version_number     => ln_object_version_number,           p_per_effective_start_date             => ld_per_effective_start_date,           p_per_effective_end_date              => ld_per_effective_end_date,           p_full_name                                       => lc_full_name,           p_per_comment_id                          => ln_per_comment_id,           p_name_combination_warning  => lb_name_comb_warning,           p_orig_hire_warning                      => lb_orig_hire_warning      );    COMMIT; EXCEPTION             WHEN OTHERS THEN                       ROLLBACK;                       dbms_output.put_line(SQLERRM); END; / SHOW ERR;  

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  • Adding view to NSOutlineView

    - by Felix
    Hi All, I need to add a view to NSOutlineView. This view contains some text field and button, while expanding the outlineview should show this view. Please let me know how to add the view the NSOutliveView. Thanks, Felix.

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  • How to create svn folder in mac os x

    - by niceramar
    hi, i am working on iphone project, i like to create an svn folder and link that one to my server I tried to run the below command fsp3s-MacBook-Pro:~ fsp3$ svnadmin create /ram/Code/SVN i got the below error svnadmin: Repository creation failed svnadmin: Could not create top-level directory svnadmin: Can't create directory '/ram/Code/SVN': No such file or directory How to create an SVN folder in mac os x? thanks!

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