Search Results

Search found 18213 results on 729 pages for 'hibernate cfg xml'.

Page 48/729 | < Previous Page | 44 45 46 47 48 49 50 51 52 53 54 55  | Next Page >

  • Hibernate Many-To-One Foreign Key Default 0

    - by user573648
    I have a table where the the parent object has an optional many-to-one relationship. The problem is that the table is setup to default the fkey column to 0. When selecting, using fetch="join", etc-- the default of 0 on the fkey is being used to try over and over to select from another table for the ID 0. Of course this doesn't exist, but how can I tell Hibernate to treat a value of 0 to be the same as NULL-- to not cycle through 20+ times in fetching a relationship which doesn't exist? <many-to-one name="device" lazy="false" class="Device" not-null="true" access="field" cascade="none" not-found="ignore"> <column name="DEVICEID" default="0" not-null="false"/>

    Read the article

  • How do I use a custom select statement in Hibernate using the HibernateDaoSupport class

    - by Bill Leeper
    I am trying to write a custom select statement in Hibernate using the getHibernateTemplate() method. I am having problems with the resulting mapping. Example Code: List<User> users = getHibernateTemplate().find("Select user, sysdate as latestPost from User as user"); for (User user : users) { assertNotNull(users.name); } The goal of the above line is to eventually have a join where I get the max(date) of posts made by the user. The problem I am having is that the resulting users list is not a list of User objects and I get a class cast exception. Hopefully that is enough code. It is a greatly simplified version of my problem and a combination of snippets from various parts of my application.

    Read the article

  • Spring / Hibernate project with Tomcat and JQuery.

    - by Tiago
    Hi, I have a Dynamic Web Project that implements Spring and Hibernate using a Tomcat Server (v6). I'm lauching Tomcat with my Eclipse Galileo and I'm not getting any errors in the console but Tomcat is rendering my webpages randomly. The page just keep loading but without displaying anything, there's nothing on the console either. When I go in debug mode, it goes throught the right steps, everything seems alright. When I display the source code on the web browser (Firefox latest build) it shows me the right code that is needed to display the page I called. What am I not getting here? Plus when I stop Tomcat, it renders a part of the page. I'm wondering if JQuery could be the problem? The thing is that it's a collaborative project and that the others managed to run the web application in the most alright way. Please, share your experience with me.

    Read the article

  • Hibernate Save Parent Only

    - by user239905
    Hi, I'm having an issue with Hibernate 3.2.5, where I have to save only the parent object in a one-to-many relationship. For example, I have a flower A, that can have many details. Firstly I want to save only the flower, and the details will be added later. This process throws an exception: not-null property references a null or transient value: com.juflora.bean.JFlora._floraSetBackref This is my code: JFlora flora = new JFlora(); flora.setTypeId(Integer.parseInt(type)); flora.setDescription(description); flora.setName(name); flora.setImage(image); flora.setFloraDetails(new HashSet()); session.save(flora); session.getTransaction().commit();

    Read the article

  • How to model a relationship that NHibernate (or Hibernate) doesn’t easily support

    - by MylesRip
    I have a situation in which the ideal relationship, I believe, would involve Value Object Inheritance. This is unfortunately not supported in NHibernate so any solution I come up with will be less than perfect. Let’s say that: “Item” entities have a “Location” that can be in one of multiple different formats. These formats are completely different with no overlapping fields. We will deal with each Location in the format that is provided in the data with no attempt to convert from one format to another. Each Item has exactly one Location. “SpecialItem” is a subtype of Item, however, that is unique in that it has exactly two Locations. “Group” entities aggregate Items. “LocationGroup” is as subtype of Group. LocationGroup also has a single Location that can be in any of the formats as described above. Although I’m interested in Items by Group, I’m also interested in being able to find all items with the same Location, regardless of which group they are in. I apologize for the number of stipulations listed above, but I’m afraid that simplifying it any further wouldn’t really reflect the difficulties of the situation. Here is how the above could be diagrammed: Mapping Dilemma Diagram: (http://www.freeimagehosting.net/uploads/592ad48b1a.jpg) (I tried placing the diagram inline, but Stack Overflow won't allow that until I have accumulated more points. I understand the reasoning behind it, but it is a bit inconvenient for now.) Hmmm... Apparently I can't have multiple links either. :-( Analyzing the above, I make the following observations: I treat Locations polymorphically, referring to the supertype rather than the subtype. Logically, Locations should be “Value Objects” rather than entities since it is meaningless to differentiate between two Location objects that have all the same values. Thus equality between Locations should be based on field comparisons, not identifiers. Also, value objects should be immutable and shared references should not be allowed. Using NHibernate (or Hibernate) one would typically map value objects using the “component” keyword which would cause the fields of the class to be mapped directly into the database table that represents the containing class. Put another way, there would not be a separate “Locations” table in the database (and Locations would therefore have no identifiers). NHibernate (or Hibernate) do not currently support inheritance for value objects. My choices as I see them are: Ignore the fact that Locations should be value objects and map them as entities. This would take care of the inheritance mapping issues since NHibernate supports entity inheritance. The downside is that I then have to deal with aliasing issues. (Meaning that if multiple objects share a reference to the same Location, then changing values for one object’s Location would cause the location to change for other objects that share the reference the same Location record.) I want to avoid this if possible. Another downside is that entities are typically compared by their IDs. This would mean that two Location objects would be considered not equal even if the values of all their fields are the same. This would be invalid and unacceptable from the business perspective. Flatten Locations into a single class so that there are no longer inheritance relationships for Locations. This would allow Locations to be treated as value objects which could easily be handled by using “component” mapping in NHibernate. The downside in this case would be that the domain model becomes weaker, more fragile and less maintainable. Do some “creative” mapping in the hbm files in order to force Location fields to be mapped into the containing entities’ tables without using the “component” keyword. This approach is described by Colin Jack here. My situation is more complicated than the one he describes due to the fact that SpecialItem has a second Location and the fact that a different entity, LocatedGroup, also has Locations. I could probably get it to work, but the mappings would be non-intuitive and therefore hard to understand and maintain by other developers in the future. Also, I suspect that these tricky mappings would likely not be possible using Fluent NHibernate so I would use the advantages of using that tool, at least in that situation. Surely others out there have run into similar situations. I’m hoping someone who has “been there, done that” can share some wisdom. :-) So here’s the question… Which approach should be preferred in this situation? Why?

    Read the article

  • Can I bypass an intermediate object in hibernate

    - by Jherico
    I have top level entities TRACK, MEDIA_GROUP and MEDIA, each with an integer primary key. I also have a join table from TRACK to MEDIA_GROUP which is 1:1 and MEDIA has a FK column into MEDIA_GROUP. I'm trying to find a way in hibernate to map a collection of Media directly into the Track object, bypassing the creation of a MediaGroup object. Basically I want to turn this: TRACK <-> MEDIA_TRACK_MAP <-> MEDIA_GROUP <-> MEDIA into this: TRACK <-> MEDIA_TRACK_MAP <-> MEDIA But the join column between MEDIA_TRACK_MAP and MEDIA isn't the primary key of MEDIA.

    Read the article

  • Groovy and XML: Not able to insert processing instruction

    - by rhellem
    Scenario Need to update some attributes in an existing XML-file. The file contains a XSL processing instruction, so when the XML is parsed and updated I need to add the instruction before writing it to a file again. Problem is - whatever I do - I'm not able to insert the processing instruction Based on the Java-example found at rgagnon.com I have created the code below Example code ## import groovy.xml.* def xml = '''|<something> | <Settings> | </Settings> |</something>'''.stripMargin() def document = DOMBuilder.parse( new StringReader( xml ) ) def pi = document.createProcessingInstruction('xml-stylesheet', 'type="text/xsl" href="Bp8DefaultView.xsl"'); document.insertBefore(pi, document.documentElement) println document.documentElement Creates output <?xml version="1.0" encoding="UTF-8"?> <something> <Settings> </Settings> </something> What I want <?xml version="1.0" encoding="UTF-8"?> <?xml-stylesheet type="text/xsl" href="Bp8DefaultView.xsl"?> <something> <Settings> </Settings> </something>

    Read the article

  • how to check if a data exist on a table using hibernate

    - by David
    im using hibernate with my jsp page and mySQL ,how can i do that select * from student wher userName = *** with HQL and how i chek if that username exist in 'Student' table ? in my sql i use that ResultSet resultat = statement.executeQuery(); if (resultat.next()) { ....} i try this Session hibernateSession = MyDB.HibernateUtil.currentSession(); hibernateSession.find("select xxx from Etudinat where p.Nom=xxxx"); thats give an exception so how can i do that ? i have a login form send me a username and password i want to chek if that username exist in the table Student to set the user on a session what is the safty way to do that

    Read the article

  • Hibernate criterion Projection alias not being used

    - by sbzoom
    Do Hibernate Projection aliases even work? I could swear it just doesn't. At least, it doesn't do what I would expect it to do. Here is the java: return sessionFactory.getCurrentSession().createCriteria( PersonProgramActivity.class ).setProjection( Projections.projectionList().add( Projections.alias( Projections.sum( "numberOfPoints" ), "number_of_points" ) ).add( Projections.groupProperty( "person.id" ) ) ).setFirstResult( start ).setFetchSize( size ).addOrder( Order.desc( "numberOfPoints" ) ).list(); Here is the SQL that it generates: select sum(this_.number_of_points) as y0_, this_.person_id as y1_ from PERSON_PROGRAM_ACTIVITY this_ group by this_.person_id order by this_.number_of_points desc It doesn't seem to use the alias at all. I would think setting the alias would mean that "sum(this_.number_of_points)" would be aliased as "number_of_points" and not "y0_". Is there some trick I am missing? Thanks.

    Read the article

  • Noob question about hibernate criteria

    - by Dimitri
    Hello, I have a class called User which has 2 properties : login/password. I am trying to authenticate a user in my application using hibernate criteria but my request doesn't work. [EDIT] The returned value is NULL. I have two users in my database for testing. Here is my code : @Override public User authenticate(String login, String password) throws NullPointerException { Session session = this.getSession(); User user = (User) session .createCriteria(User.class) .add( Restrictions.and( Property.forName("login").eq(login), Property.forName("password").eq(password) )).uniqueResult(); if (user == null){ throw new NullPointerException("User not found"); } return user; } Can someone tells me what is wrong with my code? Happy new Year 2011 !!

    Read the article

  • Hibernate + Spring + session + cache

    - by andromeda
    We are using Hibernate with Spring for our Java application. We find out that when a session update something in database other sessions can not see the update. For example user1 get the account balance from database then user2 increase the balance , if user1 get the object another time he see the account balance before updating (seems that session use the value from its cache) but we want to get the updated object with new account balance. User1 use one session during all activity that is different from user2 session. Is any configuration to force to get the updated object from database? or any other help?

    Read the article

  • Storing data in XML or MongoDB

    - by user766473
    Here is my usecase. 1.Have some data, which I am storing now in the xml files. The data that I am storing is not persistent i.e I would be deleting the user data once the user logs out. 2.My server communicates with the client using the XML requests and responses. So initially we decided, since we are sending the XML as response, lets store it in XML so that conversion from database to XML format time is saved. 3.Client will request for XML based on some filter conditions. So will have to use XQUERY. 4.Maximum of 100 entries will be there in an XML, atleast as of now. Now I would like to hear some advice on whether I should use XML or mongodb. My Concerns : 1. How good is it to store temporary data in mongodb and delete/take backup once done with session 2. Conversion from mongodb json format to XML. 3. Handling the changes in the schema design. Cant use any other DB than mongodb. As some persistent operation or still done on mongodb. Thanks in advance.

    Read the article

  • Hibernate mysql groupe by day whith 0 entities

    - by Touhami
    I have this function i need to do that in sql (hibernate or mysql) or a java function that interpert the array of results select DAY(affaire.docCreationDate), count(affaire.docfullName) from CRMAffaireCode.AffaireClass as affaire where affaire.docfullName like 'CRMAffaire.Affaire%' and affaire.docCreationDate = '" + startDate + " 00:00:00' and affaire.docCreationDate <= '" + endDate + " 23:59:59' GROUP BY DAY(affaire.docCreationDate)" i have this entitie count in my table 2012-10-05 3 2012-10-06 0 2012-10-07 7 2012-10-08 13 2012-10-09 9 2012-10-10 0 2012-10-11 0 2012-10-12 3 the request return me this values 5 3 7 7 8 13 9 9 12 3 in this way i loose three lignes that have 0 as value, i need a request that return me this 5 3 6 0 7 7 8 13 9 9 10 0 11 0 12 3

    Read the article

  • 1:M relationship in Hibernate and cascading operations

    - by EugeneP
    Table SUBCOURSE references COURSE COURSE(id, name) SUBCOURSE(id, course_id, name) So, 1:M. Hibernate generates for Course: @OneToMany(fetch = FetchType.LAZY, mappedBy = "course", cascade = CascadeType.ALL) public Set getSubCourses() { return this.subCourses; } for Subcourse it generates @ManyToOne(fetch = FetchType.LAZY) @JoinColumn(name = "course_id", nullable = false) public Course getCourse() { return this.course; } Now the problem is that cascading does not work as expected. I want to create a collection of SubCourse objects (Set), fill it and then bind it to setSubCourses() of Course object. Though, having ManyToOne thing in a Subcourses table, I need to manually setCourse() before adding to collection on each object. If I do not do so, an exception is raised. What can you recommend me?

    Read the article

  • How to prevent creation of monitors.xml?

    - by user222723
    I'm using Ubuntu on a tablet and have a problem with the screen rotation, which I can fix by removing ~/.config/monitors.xml, but sadly every time I rotate the screen a new monitors.xml is created. Is there any way to prevent this? I already tried to create an empty file with the same name as root but it was still overwritten after rotating the screen. Edit: I think I finally found the reason for the problem. Everytime the orientation is changed the new orientation is saved in monitors.xml while the original monitors.xml is saved as monitors.xml.backup. By playing around with chattr I found out that this causes Ubuntu to try to restore monitors.xml out of monitors.xml.backup after every login. So if I turn the screen to the left and then back to normal monitors.xml says "orientation=normal" and monitors.xml.backup says "orientation=left". After the login Ubuntu overwrites monitors.xml with the backup and uses its configuration and turns the screen to the left.

    Read the article

  • How do I add a namespace attribute to an element in JAXB when marshalling?

    - by Ryan Elkins
    I'm working with eBay's LMS (Large Merchant Services) and kept running into the error: org.xml.sax.SAXException: SimpleDeserializer encountered a child element, which is NOT expected, in something it was trying to deserialize. After alot of trial and error I traced the problem down. It turns out this works: <?xml version="1.0" encoding="UTF-8"?> <BulkDataExchangeRequests xmlns="urn:ebay:apis:eBLBaseComponents"> <Header> <Version>583</Version> <SiteID>0</SiteID> </Header> <AddFixedPriceItemRequest xmlns="urn:ebay:apis:eBLBaseComponents"> while this (what I've been sending) doesn't: <?xml version="1.0" encoding="UTF-8"?> <BulkDataExchangeRequests xmlns="urn:ebay:apis:eBLBaseComponents"> <Header> <Version>583</Version> <SiteID>0</SiteID> </Header> <AddFixedPriceItemRequest> The difference is the xml namespace attribute on the AddFixedPriceItemRequest . All of my XML is currently being marshalled via JAXB and I'm not sure what is the best way to go about adding a second xmlns attribute to a different element in my file. So that's the question. How do I add an xmlns attribute to another element in JAXB? UPDATE: package ebay.apis.eblbasecomponents; import javax.xml.bind.annotation.XmlAccessType; import javax.xml.bind.annotation.XmlAccessorType; import javax.xml.bind.annotation.XmlElement; import javax.xml.bind.annotation.XmlType; @XmlAccessorType(XmlAccessType.FIELD) @XmlType(name = "AddFixedPriceItemRequestType", propOrder = { "item" }) public class AddFixedPriceItemRequestType extends AbstractRequestType { @XmlElement(name = "Item") protected ItemType item; public ItemType getItem() { return item; } public void setItem(ItemType value) { this.item = value; } } Added class definition by request. UPDATE 2: Edited the above class like so to no effect: @XmlAccessorType(XmlAccessType.FIELD) @XmlType(namespace = "urn:ebay:apis:eBLBaseComponents", name = "AddFixedPriceItemRequestType", propOrder = { "item" }) public class AddFixedPriceItemRequestType UPDATE 3: Here is a snippet of the BulkDataExchangeRequestsType class. I tried throwing a namespace="urn:ebay:apis:eBLBaseComponents" into the @XmlElement for AddFixedPriceItemRequest but it didn't do anything. @XmlAccessorType(XmlAccessType.FIELD) @XmlType(name = "BulkDataExchangeRequestsType", propOrder = { "header", "addFixedPriceItemRequest" }) public class BulkDataExchangeRequestsType { @XmlElement(name = "Header") protected MerchantDataRequestHeaderType header; @XmlElement(name = "AddFixedPriceItemRequest") protected List<AddFixedPriceItemRequestType> addFixedPriceItemRequest; UPDATE 4: Here's the hideous chunk of code that is updating the xml after marshalling for me. This is currently working although I'm not particulary proud of it. DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); dbf.setNamespaceAware(true); DocumentBuilder db = dbf.newDocumentBuilder(); Document doc = db.newDocument(); marshaller.marshal(request, doc); NodeList nodes = doc.getChildNodes(); nodes = nodes.item(0).getChildNodes(); for(int i = 0; i < nodes.getLength(); i++){ Node node = nodes.item(i); if (!node.getNodeName().equals("Header")){ ((Element)node).setAttribute("xmlns", "urn:ebay:apis:eBLBaseComponents"); } } Update 5: For anyone else that runs into this problem with eBay and wonders why - The reasoning behind this most likely has to do with how eBay is handling these requests. The BulkDataExchange probably takes the XML payload, breaks it up, and send the pieces out to the Merchant or Trading API. The inner pieces of the payload then do not have the namespace and the get the error. This is a guess on my part but I wouldn't be surprised if this is what was going on behind the scenes. Thanks for all the help everyone.

    Read the article

  • Invoke a SOAP method with namespace prefixes

    - by mvladic
    My C# web service client sends following soap message to Java-based web service: <?xml version="1.0" encoding="utf-8"?> <soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <soap:Body> <getData> <request> <requestParameters xmlns="http://b..."> <equals> ... </equals> </requestParameters> </request> </getData> </soap:Body> </soap:Envelope> and Java-based web service returns error: 500 Internal Server Error ... Cannot find dispatch method for {}getData ... Client written in Java, which works, sends the following message: <?xml version="1.0" encoding="utf-8"?> <soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <soap:Body> <ns2:getData xmlns:ns2="http://a..."> <ns2:request> <ns3:requestParameters xmlns:ns3="http://b..."> <ns3:equals> ... </ns3:equals> </ns3:requestParameters> </ns2:request> </ns2:getData> </soap:Body> </soap:Envelope> Is there an easy way in C# to send SOAP messages the same way Java client sends: with namespace prefixes? Following is C# code that sends message: // class MyService is auto-generated using wsdl.exe tool MyService service = new MyService(); RequestMessage request = new RequestMessage(); ... ResponseMessage response = service.getData(request); ... UPDATE: RequestMessage class looks like this: /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("svcutil", "3.0.4506.2152")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(Namespace="http://uri.etsi.org/02657/v1.5.1#/RetainedData")] public partial class RequestMessage { private byte[] requestPriorityField; private RequestConstraints requestParametersField; private string deliveryPointHIBField; private string maxHitsField; private NationalRequestParameters nationalRequestParametersField; private System.Xml.XmlElement anyField; /// <remarks/> [System.Xml.Serialization.XmlElementAttribute(DataType="hexBinary", Order=0)] public byte[] requestPriority { get { return this.requestPriorityField; } set { this.requestPriorityField = value; } } /// <remarks/> [System.Xml.Serialization.XmlElementAttribute(Order=1)] public RequestConstraints requestParameters { get { return this.requestParametersField; } set { this.requestParametersField = value; } } /// <remarks/> [System.Xml.Serialization.XmlElementAttribute(Order=2)] public string deliveryPointHIB { get { return this.deliveryPointHIBField; } set { this.deliveryPointHIBField = value; } } /// <remarks/> [System.Xml.Serialization.XmlElementAttribute(DataType="integer", Order=3)] public string maxHits { get { return this.maxHitsField; } set { this.maxHitsField = value; } } /// <remarks/> [System.Xml.Serialization.XmlElementAttribute(Order=4)] public NationalRequestParameters nationalRequestParameters { get { return this.nationalRequestParametersField; } set { this.nationalRequestParametersField = value; } } /// <remarks/> [System.Xml.Serialization.XmlAnyElementAttribute(Order=5)] public System.Xml.XmlElement Any { get { return this.anyField; } set { this.anyField = value; } } }

    Read the article

  • XML url link in Flash

    - by Vickyboy
    Hi, I am new to XML and am having a small problem in Flash. I have a number of buttons. Each of these buttons need to open up a different URL which is in a xml file (I have added only one button for now (banstead), as I wasn´t sure how to add more). My XML: <?xml version="1.0" encoding="utf-8"?> <banstead targ="_self" href="http://www.marca.com"> </banstead> My AS: weblinkXML = new XML(); weblinkXML.ignoreWhite = true; weblinkXML.load("xml/counties.xml"); weblinkXML.onLoad = function (success) { var url = weblinkXML.firstChild.attributes.href; banstead.onRelease = function () { getURL(weblinkXML.url); } } For some reason when I test the movie and click on the button it doesn´t open the URL I requested. Appreciate any help

    Read the article

  • noob question : reading xml from url link by using php

    - by mireille raad
    Hello, I am trying to build an authentication plugin that uses php/xml. My application can communicate to another application by sending this : http://tst.example.net/remote/validate_user.jhtml?ticket=$ticket_value in return i get a formatted xml document. i want to be able to parse that document. I googled and read a bit around here , but what i could find is that using php_simplexml i can do the following $xml = simplexml_load_file("test.xml"); echo $xml-getName() . ""; foreach($xml-children() as $child) { echo $child-getName() . ": " . $child . ""; } my question is : i don't have a test.xml file, it is a url that i am reading/parsing, any way how to get the info from the url, not a file. I know this is a very noobish question, i would appreciate the help

    Read the article

  • What does this web.xml error mean?

    - by jacekn
    <?xml version="1.0" encoding="UTF-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_5.xsd"> Referenced file contains errors (http://java.sun.com/xml/ns/j2ee/web-app_2_5.xsd). For more information, right click on the message in the Problems View and select "Show Details..." The errors below were detected when validating the file "web-app_2_5.xsd" via the file "web.xml". In most cases these errors can be detected by validating "web-app_2_5.xsd" directly. However it is possible that errors will only occur when web-app_2_5.xsd is validated in the context of web.xml. In details, I see a bunch of these: s4s-elt-character: Non-whitespace characters are not allowed in schema elements other than xs:appinfo and xs:documentation. Saw 'var _U="undefined";'

    Read the article

  • System.XML or Regex.Replace?

    - by cam
    I'm generating a large amount of XML documents from a set of values in an Excel file. The only thing that changes for each XML document is the values. I figured the best way to generate these documents was to make a "XML skeleton" (since the XML format never changes) and then plug in symbols like "&%blahNameblahTest", so then I could just preform a Regex.Replace on each value. I will be handing over this project to another developer and I'm wondering if I should convert the project to generate the XML file manually everytime through the System.XML namespace. The only advantages I see to this is ensuring that the XML document is valid. The current method would be more readable than that method, and way faster since I'm generating around 1500 documents.

    Read the article

  • Parsing mutiple xml files in android

    - by cppdev
    Hi, I ma writing an application where I have to parse multiple xml files as a response from a server. Till now, I have written different xml parser classes for each xml depepending on the tags present in different xmls ? Can I combine all xml parser classes and write a single xml parser that handles all different tags in different xmls ? Will it work ? Will combining xml parser classes add an overhead because xml parser will check for every tag irrespective of whether that is part of file or not ? Please help.

    Read the article

  • XML testing in Rails - Fixed attributes order in Builder::XmlMarkup in ruby -

    - by Daniel Cukier
    I have the following test in my Rails Application: it "should validate xml" do builder = Builder::XmlMarkup.new builder.server(:name => "myServer", :ip => "192.168.1.1").should == "<server name=\"myServer\" ip=\"192.168.1.1\"/>" end The problem is that this test passes sometimes, because the order of the xml tag attributes is unpredictable. Is there a way to force this order? Is there any other easy way to build xml? This example is simplified, I have a big XML. My problem is that I want to do an integration test, which compares a WebService call with a fixed XML file. Otherwise, I would have to parse the xml and verify element by element in the XML.

    Read the article

  • Browser Not Reading Entire XML File

    - by Chris
    I have an XML file that is written by a PHP script. The data for the XML file is gathered from several different RSS feeds. The PHP script is invoked every 5 minutes by a Cron Job. The PHP Script takes maybe 5-10 seconds to write the XML File. Here's the problem: After the XML file is written, I can open it through DreamWeaver and read everything just fine - but when I enter the XML File's URL into my Web Browser (IE or Firefox), I get a "XML Parsing Error: not well-formed" Error in the Browser. When I do View Source in the Browser, the XML file appears incomplete - but when I open the file directly off the server, it is complete. Anyone know what's going on here?

    Read the article

  • XML and .NET: How to replace specific node with many other ones loaded from raw xml data

    - by Entrase
    Let's suppose we have an element like this one in the main xml file: <group name="gr1" filename="groups/gr1.xml"/>. The second file gr1.xml contains something like this: <item name="i1">Item one</item> <item name="i2">Item two</item> <item name="i3">Item three</item> Note that there is no XML declaration in gr1.xml, just plain items without single parent node. So… Which is the best way to replace <group/> with its <item/>s? I have already tried some things like manual enclosing of gr1.xml content into a single node with XML declaration and loading it into XmlDocument, but it doesn't look like a good solution.

    Read the article

< Previous Page | 44 45 46 47 48 49 50 51 52 53 54 55  | Next Page >