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  • Upload image from J2ME client to a Servlet

    - by Akash
    I want to send an image from a J2ME client to a Servlet. I am able to get a byte array of the image and send it using HTTP POST. conn = (HttpConnection) Connector.open(url, Connector.READ_WRITE, true); conn.setRequestMethod(HttpConnection.POST); conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded"); os.write(bytes, 0, bytes.length); // bytes = byte array of image This is the Servlet code: String line; BufferedReader r1 = new BufferedReader(new InputStreamReader(in)); while ((line = r1.readLine()) != null) { System.out.println("line=" + line); buf.append(line); } String s = buf.toString(); byte[] img_byte = s.getBytes(); But the problem I found is, when I send bytes from the J2ME client, some bytes are lost. Their values are 0A and 0D hex. Exactly, the Carriage Return and Line Feed. Thus, either POST method or readLine() are not able to accept 0A and 0D values. Any one have any idea how to do this, or how to use any another method?

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  • Sell digital goods online

    - by Adam
    What's the best solution for a photographer wanting to sell image files online? I tried zencart, but it's way over the top and their backend looks like a 3 year old designed it. Is there a free solution out there? One that has easily modifiable templates and isn't too tedious to add hundreds of pictures for sale? I'm seriously thinking learning how to do it myself with the whole paypal IPN thing might be the way to go.. Suggestions is greatly appreciated! Adam

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  • django image upload forms

    - by gramware
    I am having problems with django forms and image uploads. I have googled, read the documentations and even questions ere, but cant figure out the issue. Here are my files my models class UserProfile(User): """user with app settings. """ DESIGNATION_CHOICES=( ('ADM', 'Administrator'), ('OFF', 'Club Official'), ('MEM', 'Ordinary Member'), ) onames = models.CharField(max_length=30, blank=True) phoneNumber = models.CharField(max_length=15) regNo = models.CharField(max_length=15) designation = models.CharField(max_length=3,choices=DESIGNATION_CHOICES) image = models.ImageField(max_length=100,upload_to='photos/%Y/%m/%d', blank=True, null=True) course = models.CharField(max_length=30, blank=True, null=True) timezone = models.CharField(max_length=50, default='Africa/Nairobi') smsCom = models.BooleanField() mailCom = models.BooleanField() fbCom = models.BooleanField() objects = UserManager() #def __unicode__(self): # return '%s %s ' % (User.Username, User.is_staff) def get_absolute_url(self): return u'%s%s/%s' % (settings.MEDIA_URL, settings.ATTACHMENT_FOLDER, self.id) def get_download_url(self): return u'%s%s/%s' % (settings.MEDIA_URL, settings.ATTACHMENT_FOLDER, self.name) ... class reports(models.Model): repID = models.AutoField(primary_key=True) repSubject = models.CharField(max_length=100) repRecepients = models.ManyToManyField(UserProfile) repPoster = models.ForeignKey(UserProfile,related_name='repposter') repDescription = models.TextField() repPubAccess = models.BooleanField() repDate = models.DateField() report = models.FileField(max_length=200,upload_to='files/%Y/%m/%d' ) deleted = models.BooleanField() def __unicode__(self): return u'%s ' % (self.repSubject) my forms from django import forms from django.http import HttpResponse from cms.models import * from django.contrib.sessions.models import Session from django.forms.extras.widgets import SelectDateWidget class UserProfileForm(forms.ModelForm): class Meta: model= UserProfile exclude = ('designation','password','is_staff', 'is_active','is_superuser','last_login','date_joined','user_permissions','groups') ... class reportsForm(forms.ModelForm): repPoster = forms.ModelChoiceField(queryset=UserProfile.objects.all(), widget=forms.HiddenInput()) repDescription = forms.CharField(widget=forms.Textarea(attrs={'cols':'50', 'rows':'5'}),label='Enter Report Description here') repDate = forms.DateField(widget=SelectDateWidget()) class Meta: model = reports exclude = ('deleted') my views @login_required def reports_media(request): user = UserProfile.objects.get(pk=request.session['_auth_user_id']) if request.user.is_staff== True: repmedform = reportsForm(request.POST, request.FILES) if repmedform.is_valid(): repmedform.save() repmedform = reportsForm(initial = {'repPoster':user.id,}) else: repmedform = reportsForm(initial = {'repPoster':user.id,}) return render_to_response('staffrepmedia.html', {'repfrm':repmedform, 'rep_media': reports.objects.all()}) else: return render_to_response('reports_&_media.html', {'rep_media': reports.objects.all()}) ... @login_required def settingchng(request): user = UserProfile.objects.get(pk=request.session['_auth_user_id']) form = UserProfileForm(instance = user) if request.method == 'POST': form = UserProfileForm(request.POST, request.FILES, instance = user) if form.is_valid(): form.save() return HttpResponseRedirect('/settings/') else: form = UserProfileForm(instance = user) if request.user.is_staff== True: return render_to_response('staffsettingschange.html', {'form': form}) else: return render_to_response('settingschange.html', {'form': form}) ... @login_required def useradd(request): if request.method == 'POST': form = UserAddForm(request.POST,request.FILES ) if form.is_valid(): password = request.POST['password'] request.POST['password'] = set_password(password) form.save() else: form = UserAddForm() return render_to_response('staffadduser.html', {'form':form}) Example of my templates {% if form.errors %} <ol> {% for field in form %} <H3 class="title"> <p class="error"> {% if field.errors %}<li>{{ field.errors|striptags }}</li>{% endif %}</p> </H3> {% endfor %} </ol> {% endif %} <form method="post" id="form" action="" enctype="multipart/form-data" class="infotabs accfrm"> {{ repfrm.as_p }} <input type="submit" value="Submit" /> </form>

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  • upload file from window application to Remote Web Server

    - by user208466
    string filePath = "C:\\test\\564.flv"; try { WebClient client = new WebClient(); NetworkCredential nc = new NetworkCredential(uName, password); Uri addy = new Uri("\\\\192.168.1.28\\Files\\test.flv"); client.Credentials = nc; byte[] arrReturn = client.UploadFile(addy, filePath); Console.WriteLine(arrReturn.ToString()); } catch (Exception ex) { Console.WriteLine(ex.Message); } i am get this error "The remote server returned an error: (405) Method Not Allowed." what should i doo ??

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  • How to maximize http.sys file upload performance

    - by anelson
    I'm building a tool that transfers very large streaming data sets (possibly on the order of terabytes in a single stream; routinely in the tens of gigabytes) from one server to another. The client portion of the tool will read blocks from the source disk, and send them over the network. The server side will read these blocks off the network and write them to a file on the server disk. Right now I'm trying to decide which transport to use. Options are raw TCP, and HTTP. I really, REALLY want to be able to use HTTP. The HttpListener (or WCF if I want to go that route) make it easy to plug in to the HTTP Server API (http.sys), and I can get things like authentication and SSL for free. The problem right now is performance. I wrote a simple test harness that sends 128K blocks of NULL bytes using the BeginWrite/EndWrite async I/O idiom, with async BeginRead/EndRead on the server side. I've modified this test harness so I can do this with either HTTP PUT operations via HttpWebRequest/HttpListener, or plain old socket writes using TcpClient/TcpListener. To rule out issues with network cards or network pathways, both the client and server are on one machine and communicate over localhost. On my 12-core Windows 2008 R2 test server, the TCP version of this test harness can push bytes at 450MB/s, with minimal CPU usage. On the same box, the HTTP version of the test harness runs between 130MB/s and 200MB/s depending upon how I tweak it. In both cases CPU usage is low, and the vast majority of what CPU usage there is is kernel time, so I'm pretty sure my usage of C# and the .NET runtime is not the bottleneck. The box has two 6-core Xeon X5650 processors, 24GB of single-ranked DDR3 RAM, and is used exclusively by me for my own performance testing. I already know about HTTP client tweaks like ServicePointManager.MaxServicePointIdleTime, ServicePointManager.DefaultConnectionLimit, ServicePointManager.Expect100Continue, and HttpWebRequest.AllowWriteStreamBuffering. Does anyone have any ideas for how I can get HTTP.sys performance beyond 200MB/s? Has anyone seen it perform this well on any environment?

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  • how to read image uri in to byte conversion in android image upload in sdcard

    - by satyamurthy
    public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); Button b1 = (Button) findViewById(R.id.Button01); b1.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { // TODO Auto-generated method stub startActivityForResult(new Intent(Intent.ACTION_PICK,android.provider.MediaStore.Images.Media.INTERNAL_CONTENT_URI), 1); } }); } public void onActivityResult(int requestCode,int resultCode,Intent data) { super.onActivityResult(requestCode, resultCode, data); if (resultCode == Activity.RESULT_OK) { Uri selectedImage = data.getData(); Cursor cur = PhotoImage.this.managedQuery(selectedImage, null, null, null, null); if(cur.moveToFirst()) { File Img = new File(selectedImage+inFileType); try { FileInputStream fis = new FileInputStream(Img); Bitmap bi = BitmapFactory.decodeStream(fis); ByteArrayOutputStream baos = new ByteArrayOutputStream(); bi.compress(Bitmap.CompressFormat.JPEG, 100, baos); byte[] data1 = baos.toByteArray(); for (int i = 0; i < data1.length; i++) { System.out.print(""+data1[i]); } } catch (FileNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } } } } } this code not i am implementing file not found error please help some suggition

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  • WYSIHAT Photos upload not working - Paperclip - Ruby on Rails

    - by bgadoci
    I just successfully installed WysiHat in my rails blog. Seems that the 'add a picture' feature is not working. It successfully allows me to find and select a picture from my desktop but upon clicking save, it does nothing. I also have Paperclip successfully installed. I am wondering if this may have something to do with it. Perhaps Paperclip is getting in the way, or, perhaps I need to connect Paperclip and WysiHat somehow. Any ideas? (let me know if I need to post any code). Also, WysiHat-engine uses facebox, not sure if that is relevant. UPDATE: Added Server Log, looks like paperclip is saving it so not sure what else is going wrong. Processing PostsController#update (for 127.0.0.1 at 2010-04-23 16:42:14) [PUT] Parameters: {"commit"=>"Update", "post"=>{"body"=>"<p>Duis autem vel eum iriure dolor in hendrerit in vulputate velit esse molestie consequat, vel illum dolore eu feugiat nulla facilisis at vero eros et accumsan et iusto odio dignissim qui blandit praesent luptatum zzril delenit augue duis dolore te feugait nulla facilisi. Lorem ipsum dolor sit amet, consectetuer adipiscing elit, sed diam nonummy nibh euismod tincidunt ut laoreet dolore magna aliquam erat volutpat.</p>", "title"=>"Rails Code for Search"}, "authenticity_token"=>"hndm6pxaPLfgnSMFAmLDGNo86mZG3XnlfJoNOI/P+O8=", "id"=>"105"} Post Load (0.2ms) SELECT * FROM "posts" WHERE ("posts"."id" = 105) Post Update (0.3ms) UPDATE "posts" SET "updated_at" = '2010-04-23 21:42:14', "body" = '<p>Duis autem vel eum iriure dolor in hendrerit in vulputate velit esse molestie consequat, vel illum dolore eu feugiat nulla facilisis at vero eros et accumsan et iusto odio dignissim qui blandit praesent luptatum zzril delenit augue duis dolore te feugait nulla facilisi. Lorem ipsum dolor sit amet, consectetuer adipiscing elit, sed diam nonummy nibh euismod tincidunt ut laoreet dolore magna aliquam erat volutpat.</p>' WHERE "id" = 105 [paperclip] Saving attachments. Redirected to http://localhost:3000/posts/105 Completed in 12ms (DB: 0) | 302 Found [http://localhost/posts/105]

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  • How to order <script> tags vs. <style> tags in HTML markup for best results.

    - by Tchalvak
    I'm building up my site over at http://royronalds.com, and I'm trying to figure out what order of elements in the <head> makes most sense. Just to take from what I current have, I have: <head> <style> external stylesheet <meta> <title> <link> to favicon <script> for jQuery <script> main javascript for site <script> google analytics, asynchronous script. </head> Are there reasons to order these differently so that load times and other issues happen more smoothly, and if so, what would the ideal order be?

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  • Page upload data again on page refresh in ASP.NET

    - by Etienne
    For some reason when the user click on the submit button and he re-fresh the page the same data get's uploaded again to my SQL Server 2005 database. I do not what this to happen........... Why is this happening? I am making use of a SQL Data Source!! My code Try 'See if user typed the correct code. If Me.txtSecurity.Text = Session("Captcha") Then If Session("NotifyMe") = "Yes" Then SendEmailNS() End If RaterRate.Insert() RaterRate.Update() DisableItems() lblResultNS.Text = "Thank you for leaving a comment" LoadCompanyList() LoadRateRecords() txtCommentNS.Text = "" txtSecurity.Text = "" lblResultNS.Focus() Else Session("Captcha") = GenerateCAPTCHACode() txtSecurity.Text = "" txtSecurity.Focus() Validator10.Validate() End If Catch ex As Exception lblResultNS.Visible = True lblResultNS.Text = ex.Message.ToString lblResultNS.Focus() End Try

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  • A Python Wrapper for Shutterfly. Uploading an Image

    - by iJames
    I'm working on a Django app in which I want to order prints through Shutterfly's Open API: http://www.shutterfly.com/documentation/start.sfly So far I've been able to build the appropriate POSTs and GETs using the modules and suggested code snippets including httplib, httplib2, urllib, urllib2, mimetype, etc. But I'm stuck on the image uploading when placing an order (the ordering process is not the same process as uploading images to albums which I haven't tried.) From what I can tell, I'm supposed to basically create the multipart form data by concatenating the HTTP request body together with the binary data of the image. I take the strings: --myuniqueboundary1273149960.175.1 Content-Disposition: form-data; name="AuthenticationID" auniqueauthenticationid --myuniqueboundary1273149960.175.1 Content-Disposition: file; name="Image.Data"; filename="1_41_orig.jpg" Content-Type: image/jpeg and I put this data into it and end with the final boundary: ...\xb5|\xf88\x1dj\t@\xd9\'\x1f\xc6j\x88{\x8a\xc0\x18\x8eGaJG\x03\xe9J-\xd8\x96[\x91T\xc3\x0eTu\xf4\xaa\xa5Ty\x80\x01\x8c\x9f\xe9Z\xad\x8cg\xba# g\x18\xe2\xaa:\x829\x02\xb4["\x17Q\xe7\x801\xea?\xad7j\xfd\xa2\xdf\x81\xd2\x84D\xb6)\xa8\xcb\xc8O\\\x9a\xaf(\x1cqM\x98\x8d*\xb8\'h\xc8+\x8e:u\xaa\xf3*\x9b\x95\x05F8\xedN%\xcb\xe1B2\xa9~Tw\xedF\xc4\xfe\xe8\xfc\xa9\x983\xff\xd9... That ends up making it look like this (when I use print to debug): ... --myuniqueboundary1273149960.175.1 Content-Disposition: file; name="Image.Data"; filename="1_41_orig.jpg" Content-Type: image/jpeg ????q?ExifMM* ? ??(1?2?<??i?b?NIKON CORPORATIONNIKON D40HHQuickTime 7.62009:02:17 13:05:25Mac OS X 10.5.6%??????"?'??0220?????? ???? ? ?|_???,b???50??5 ... --myuniqueboundary1273149960.175.1-- My code for grabbing the binary data is pretty much this: filedata = open('myjpegfile.jpeg','rb').read() Which I then add to the rest of the body. I've see something like this code everywhere. I'm then using this to post the full request (with the headers too): response = urllib2.urlopen(request).read() This seems to me to be the standard way that form POSTS with files happens. Am I missing something here? At some point I might be able to make this into a library worth posting up on github, but this problem has stopped me cold in my tracks. Thanks for any insight!

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  • Sample code for image upload

    - by Michael
    Hi, In would like to write a simple Android application that takes a picture from the camera and uploads it to a webserver. Additionaly, I would like it to print in the screen the response from the server wich is a simple text string. Do you know if there is any sample code that does something like that? Thank you, Michael

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  • Alert show when extension of FileUpLoads are not allowed

    - by Vy Clarks
    I have a asp FileUpload control in my aspx page. And the code behind to check file's extension and then insert them into database: private string Write(HttpPostedFile file, string table) { string fileNameMain = Path.GetFileName(file.FileName); // check for the valid file extension string fileExtension = Path.GetExtension(fileNameMain).ToLower(); if (fileExtension.Equals(".pdf") || fileExtension.Equals(".doc")) { ...insert fileupload into database } else { LabelError.Text = "Extension of files are not allowed."; return null; } } With the code above, it checks the extension and then show the message "Extension of files are not allowed." in a LabelError if the fileupload is not allowed. Now, I'm required to do the "check-extension" in the other way: at the moment the client click and choose FileUpload, an alert show "Extension of files are not allowed.". I need a way to make an alert show at the momment the FileUpload choosed in browser. Help!!!!

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  • HTTP POST prarameters order / REST urls

    - by pq
    Let's say that I'm uploading a large file via a POST HTTP request. Let's also say that I have another parameter (other than the file) that names the resource which the file is updating. The resource cannot be not part of the URL the way you can do it with REST (e.g. foo.com/bar/123). Let's say this is due to a combination of technical and political reasons. The server needs to ignore the file if the resource name is invalid or, say, the IP address and/or the logged in user are not authorized to update the resource. Looks like, if this POST came from an HTML form that contains the resource name first and file field second, for most (all?) browsers, this order is preserved in the POST request. But it would be naive to fully rely on that, no? In other words the order of HTTP parameters is insignificant and a client is free to construct the POST in any order. Isn't that true? Which means that, at least in theory, the server may end up storing the whole large file before it can deny the request. It seems to me that this is a clear case where RESTful urls have an advantage, since you don't have to look at the POST content to perform certain authorization/error checking on the request. Do you agree? What are your thoughts, experiences?

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  • File upload in asp.net mvc using ajax

    - by Maxim
    Hello! i have a simple html form with two controls: input-text and input-file i need to write an ajax query (using jquery is better) to send data (file and value from text field to mvc acton) i wrote $.ajax({ type: "POST", url: "/controller/acton", enctype: 'multipart/form-data', data: 'text=' + $("#text").val() + '&file=' + $("#file").val() ... and in controller: [HttpPost] public ActionResult StoreItem(FormCollection forms) { foreach (string inputTagName in Request.Files) ... returns null in Request... Thank you

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  • MeioUpload and phpThumb() does not exist error

    - by Cameeob2003
    I am currently using CakePHP v2.2.1 and MeioUpload 4.0 along with phpThumb() to try and generate image uploads and thumbnails for those images. If i set my $actAs = array() without the thumbsizes property everything is uploaded well, but when I add the following: 'thumbsizes' => array( 'small' => array('width' => 165, 'height' => 115), 'medium' => array('width' => 800, 'height' => 600) ), to generate thumbnails I get an error stating the following: "E:/xampp/htdocs/site/vendors/phpthumb/img/posts/image-name.jpg" does not exist I have tried several different methods of fixing this from around the web and nothing seems to work. I am new to cakephp so this may be an easy fix and I am just not connecting the dots to find the solution. Any help would be very much appreciated.

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  • multipart file-upload post request from java

    - by Martin
    I'm trying to make a program that uploads a image to a webserver that accepts multipart file-uploads. More specificly i want to make a http POST request to http://iqs.me that sends a file in the variable "pic". I've made a lot of tries but i don't know if i've even been close. The hardest part seems to be to get a HttpURLConnection to make a request of the type POST. The response i get looks like it makes a GET. (And i want to do this without any third party libs) UPDATE: non-working code goes here (no errors but doesn't seem to do a POST): HttpURLConnection conn = null; BufferedReader br = null; DataOutputStream dos = null; DataInputStream inStream = null; InputStream is = null; OutputStream os = null; boolean ret = false; String StrMessage = ""; String exsistingFileName = "myScreenShot.png"; String lineEnd = "\r\n"; String twoHyphens = "--"; String boundary = "*****"; int bytesRead, bytesAvailable, bufferSize; byte[] buffer; int maxBufferSize = 1*1024*1024; String responseFromServer = ""; String urlString = "http://iqs.local.com/index.php"; try{ FileInputStream fileInputStream = new FileInputStream( new File(exsistingFileName) ); URL url = new URL(urlString); conn = (HttpURLConnection) url.openConnection(); conn.setDoInput(true); conn.setDoOutput(true); conn.setRequestMethod("POST"); conn.setUseCaches(false); conn.setRequestProperty("Connection", "Keep-Alive"); conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary); dos = new DataOutputStream( conn.getOutputStream() ); dos.writeBytes(twoHyphens + boundary + lineEnd); dos.writeBytes("Content-Disposition: form-data; name=\"pic\";" + " filename=\"" + exsistingFileName +"\"" + lineEnd); dos.writeBytes(lineEnd); bytesAvailable = fileInputStream.available(); bufferSize = Math.min(bytesAvailable, maxBufferSize); buffer = new byte[bufferSize]; bytesRead = fileInputStream.read(buffer, 0, bufferSize); while (bytesRead > 0){ dos.write(buffer, 0, bufferSize); bytesAvailable = fileInputStream.available(); bufferSize = Math.min(bytesAvailable, maxBufferSize); bytesRead = fileInputStream.read(buffer, 0, bufferSize); } dos.writeBytes(lineEnd); dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd); fileInputStream.close(); dos.flush(); dos.close(); }catch (MalformedURLException ex){ System.out.println("Error:"+ex); }catch (IOException ioe){ System.out.println("Error:"+ioe); } try{ inStream = new DataInputStream ( conn.getInputStream() ); String str; while (( str = inStream.readLine()) != null){ System.out.println(str); } inStream.close(); }catch (IOException ioex){ System.out.println("Error: "+ioex); }

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  • How can I write a file on an ftps-server with PHP?

    - by Daniel
    Hi, I hope someone here could help me, because I couldn't find any solution with Google. What I have to do is to generate a XML-string (that works) an save that directly into a file on an ftps-server. So far, so good... I used the following code with ftp and it works to, but not with ftps. So I either need another options-configuration for the stream or a different way to solve that task. Here my current code: $host = 'ftp.example.com'; $port = 22; $user = 'xxxxxx'; $pass = 'xxxxxx'; $file = 'test_' . time() . '.txt'; $ftpPath = sprintf('ftp://%s:%s@%s:%d/%s', $user, $pass, $host, $port, $file); $context = stream_context_create(array('ftp' = array('overwrite' = true))); file_put_contents($ftpPath, 'test', 0, $context);

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