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  • Help with Perl Regex Recursive Replace One Liner? Replace MySQL comments '--' with '#'

    - by NJTechie
    I have various SQL files with '--' comments and we migrated to the latest version of MySQL and it hates these comments. I want to replace -- with #. I am looking for a recursive, inplace replace one-liner. This is what I have : perl -p -i -e 's/--/# /g' `fgrep -- -- * ` A sample .sql file : use myDB; --did you get an error I get the following error : Unrecognized switch: --did (-h will show valid options). p.s : fgrep skipping 2 dashes was just discussed here if you are interested. Any help is appreciated.

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  • How to validate a domain name using Regex & Php?

    - by David
    Hi, I want a solution to validate only domain names not full urls, The following example is what i'm looking for: domain.com -> true domain.net/org/biz... -> true domain.co.uk -> true sub.domain.com -> true domain.com/folder -> false domµ*$ain.com -> false Thank you

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  • Can I improve this regex check for valid domain names?

    - by Josh
    So, I have been working on this domain name regular expression. So far, it seems to pick up domain names with SLDs and TLDs (with the optional ccTLD), but there is duplication of the TLD listing. Can this be refactored any further? params[:domain_name].downcase.strip.match(/^[a-z0-9\-]{2,63} \.((a[cdefgilmnoqrstuwxz]|aero|arpa)|(b[abdefghijmnorstvwyz]|biz)| (c[acdfghiklmnorsuvxyz]|cat|com|coop)|d[ejkmoz]|(e[ceghrstu]|edu)|f[ijkmor]| (g[abdefghilmnpqrstuwy]|gov)|h[kmnrtu]|(i[delmnoqrst]|info|int)| (j[emop]|jobs)|k[eghimnprwyz]|l[abcikrstuvy]| (m[acdghklmnopqrstuvwxyz]|me|mil|mobi|museum)|(n[acefgilopruz]|name|net)|(om|org)| (p[aefghklmnrstwy]|pro)|qa|r[eouw]|s[abcdeghijklmnortvyz]| (t[cdfghjklmnoprtvwz]|travel)|u[agkmsyz]|v[aceginu]|w[fs]|y[etu]|z[amw]) (\.((a[cdefgilmnoqrstuwxz]|aero|arpa)|(b[abdefghijmnorstvwyz]|biz)| (c[acdfghiklmnorsuvxyz]|cat|com|coop)|d[ejkmoz]|(e[ceghrstu]|edu)|f[ijkmor]| (g[abdefghilmnpqrstuwy]|gov)|h[kmnrtu]|(i[delmnoqrst]|info|int)| (j[emop]|jobs)|k[eghimnprwyz]|l[abcikrstuvy]| m[acdghklmnopqrstuvwxyz]|mil|mobi|museum)| (n[acefgilopruz]|name|net)|(om|org)| (p[aefghklmnrstwy]|pro)|qa|r[eouw]|s[abcdeghijklmnortvyz]| (t[cdfghjklmnoprtvwz]|travel)|u[agkmsyz]|v[aceginu]|w[fs]|y[etu]|z[amw]))?$/)

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  • .NET Regex - Replace multiple characters at once without overwriting?

    - by Everaldo Aguiar
    I'm implementing a c# program that should automatize a Mono-alphabetic substitution cipher. The functionality i'm working on at the moment is the simplest one: The user will provide a plain text and a cipher alphabet, for example: Plain text(input): THIS IS A TEST Cipher alphabet: A - Y, H - Z, I - K, S - L, E - J, T - Q Cipher Text(output): QZKL KL QJLQ I thought of using regular expressions since I've been programming in perl for a while, but I'm encountering some problems on c#. First I would like to know if someone would have a suggestion for a regular expression that would replace all occurrence of each letter by its corresponding cipher letter (provided by user) at once and without overwriting anything. Example: In this case, user provides plaintext "TEST", and on his cipher alphabet, he wishes to have all his T's replaced with E's, E's replaced with Y and S replaced with J. My first thought was to substitute each occurrence of a letter with an individual character and then replace that character by the cipherletter corresponding to the plaintext letter provided. Using the same example word "TEST", the steps taken by the program to provide an answer would be: 1 - replace T's with (lets say) @ 2 - replace E's with # 3 - replace S's with & 4 - Replace @ with E, # with Y, & with j 5 - Output = EYJE This solution doesn't seem to work for large texts. I would like to know if anyone can think of a single regular expression that would allow me to replace each letter in a given text by its corresponding letter in a 26-letter cipher alphabet without the need of splitting the task in an intermediate step as I mentioned. If it helps visualize the process, this is a print screen of my GUI for the program:

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  • How to extract part of the path and the ending file name with Regex?

    - by brasofilo
    I need to build an associative array with the plugin name and the language file it uses in the following sequence: /whatever/path/length/public_html/wp-content/plugins/adminimize/languages/adminimize-en_US.mo /whatever/path/length/public_html/wp-content/plugins/audio-tube/lang/atp-en_US.mo /whatever/path/length/public_html/wp-content/languages/en_US.mo /whatever/path/length/public_html/wp-content/themes/twentyeleven/languages/en_US.mo Those are the language files WordPress is loading. They are all inside /wp-content/, but with variable server paths. I'm looking only for those inside the plugins folder, grab the plugin folder name and the filename. Hipothetical case in PHP, where reg_extract_* functions are the parts I'm missing: $plugins = array(); foreach( $big_array as $item ) { $folder = reg_extract_folder( $item ); if( 'plugin' == $folder ) { // "folder-name-after-plugins-folder" $plugin_name = reg_extract_pname( $item ); // "ending-mo-file.mo" $file_name = reg_extract_fname( $item ); $plugins[] = array( 'name' => $plugin_name, 'file' => $file_name ); } } [update] Ok, so I was missing quite a basic function, pathinfo... :/ No problem to detect if /plugins/ is contained in the array. But what about the plugin folder name?

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  • How does this RegEx for parsing emails work in PHP?

    - by George Edison
    Okay, I have the following PHP code to extract an email address of the following two forms: Random Stranger <[email protected]> [email protected] Here is the PHP code: // The first example $sender = "Random Stranger <[email protected]>"; $pattern = '/([\w_-]*@[\w-\.]*)|.*<([\w_-]*@[\w-\.]*)>/'; preg_match($pattern,$sender,$matches,PREG_OFFSET_CAPTURE); echo "<pre>"; print_r($matches); echo "</pre><hr>"; // The second example $sender = "[email protected]"; preg_match($pattern,$sender,$matches,PREG_OFFSET_CAPTURE); echo "<pre>"; print_r($matches); echo "</pre>"; My question is... what is in $matches? It seems to be a strange collection of arrays. Which index holds the match from the parenthesis? How can I be sure I'm getting the email address and only the email address? Update: Here is the output: Array ( [0] => Array ( [0] => Random Stranger [1] => 0 ) [1] => Array ( [0] => [1] => -1 ) [2] => Array ( [0] => [email protected] [1] => 5 ) ) Array ( [0] => Array ( [0] => [email protected] [1] => 0 ) [1] => Array ( [0] => [email protected] [1] => 0 ) )

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  • How to count the Chinese word in a file using regex in perl?

    - by Ivan
    I tried following perl code to count the Chinese word of a file, it seems working but not get the right thing. Any help is greatly appreciated. The Error message is Use of uninitialized value $valid in concatenation (.) or string at word_counting.pl line 21, <FILE> line 21. Total things = 125, valid words = which seems to me the problem is the file format. The "total thing" is 125 that is the string number (125 lines). The strangest part is my console displayed all the individual Chinese words correctly without any problem. The utf-8 pragma is installed. #!/usr/bin/perl -w use strict; use utf8; use Encode qw(encode); use Encode::HanExtra; my $input_file = "sample_file.txt"; my ($total, $valid); my %count; open (FILE, "< $input_file") or die "Can't open $input_file: $!"; while (<FILE>) { foreach (split) { #break $_ into words, assign each to $_ in turn $total++; next if /\W|^\d+/; #strange words skip the remainder of the loop $valid++; $count{$_}++; # count each separate word stored in a hash ## next comes here ## } } print "Total things = $total, valid words = $valid\n"; foreach my $word (sort keys %count) { print "$word \t was seen \t $count{$word} \t times.\n"; } ##---Data---- sample_file.txt ??????,???????,????.??????.????:"?????????????,??????,????????.????????,?????????, ???????????.????????,???????????,??????,??????.???:`??,???????????.'?????, ??????????."??????,??????.????.???, ????????????,????,??????,?????????,??????????????. ????????,??????,???????????,????????,????????.????,????,???????, ??????????,??????,????????.??????.

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  • How do you replace many characters in a regex?

    - by macca1
    I am sanitizing an input field and manually getting and setting the caret position in the process. With some abstraction, here's the basic idea: <input type="text" onkeyup"check(this)"> And javascript... function check(element) { var charPosition = getCaretPosition(element); $(element).val( sanitize( $(element).val() ) ); setCaretPosition(element, charPosition); } function sanitize(s) { return s.replace(/[^a-zA-Z0-9\s]/g, ''); } This is working fine except when a character does actually get sanitized, my caret position is off by one. Basically I'd like a way to see if the sanitize function has actually replaced a character (and at what index) so then I can adjust the charPosition if necessary. Any ideas?

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  • jQuery and regex for adding icons to specific links?!

    - by rayne
    I'm using jQuery to add icons to specific links, e.g. a myspace icon for sites starting with http://myspace.com etc. However, I can't figure out how to use regular expressions (if that's even possible here), to make jQuery recognize the link either with or without "www." (I'm very bad at regular expressions in general). Here are two examples: $("a[href^='http://www.last.fm']").addClass("lastfm").attr("target", "_blank"); $("a[href^='http://livejournal.com']").addClass("livejournal").attr("target", "_blank"); They work fine, but I now I want the last.fm link to work with http://last.fm, http://www.last.fm and http://www.lastfm.de. Currently it only works for www.last.fm. I also would like to make the livejournal link work with subdomains links like http://username.livejournal.com How can I do that? Thanks in advance!

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  • Regex for Eclipse/Flash Builder File Search for comments?

    - by Brian Bishop
    In Eclipse (and Flash/Flex Builder) you get the option with Ctrl+Shift+F to do a file search and look for a regular expression. Would be a real handy thing to know. I want to find the word negate if it appears in a Flex/java comment like the following: // It was negated because or /* The negate option was.... */ or /** * We have to negate the value */ Any ideas? Will test them out at http://www.regexplanet.com/simple/index.html

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  • How can I check with a regex that a string contains only certain allowed characters?

    - by Camran
    I need a special regular expression, have no experience in them whatsoever so I am turning to you guys on this one: I need to validate a classifieds title field so it doesn't have any special characters in it, almost. Only letters and numbers should be allowed, and also the swedish three letters å, ä, ö, and also not case sensitive. Besides the above, these should also be allowed: The "&" sign. Parenthesis sign "()" Mathematical signs "-", "+", "%", "/", "*" Dollar and Euro signs One accent signed letter: "é". //Only this one is required Double quote and singel quote signs. The comma "," and point "." signs Thanks

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  • Regex for Password Must be contain at least 8 characters, least 1 number and both lower and uppercase letters and special characters

    - by user2442653
    I want a regular expression to check that Password Must be contain at least 8 characters, including at least 1 number and includes both lower and uppercase letters and special characters (e.g., #, ?, !) Cannot be your old password or contain your username, "password", or "websitename" And here is my validation expression which is for 8 characters including 1 uppercase letter, 1 lowercase letter, 1 number or special character. (?=^.{8,}$)((?=.*\d)|(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$" How I can write it for password must be 8 characters including 1 uppercase letter, 1 special character and alphanumeric characters?

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  • What's the RegEx to make sure that delimiters are escaped?

    - by Kuyenda
    I'm looking for a regular expression that will check whether or not delimiters in a string are escaped with a backward slash. The delimiters I am concerned about are comma (\,), colon (\:), semicolon (\;) and of course the backward slash itself has to be escaped (\). For example, the string "test" should return a match because there are no delimiters in it, and no escaping is necessary. The string "te\;st" would return a match because the semicolon delimiter is escaped. "te;st" and "t\;s:t" would both fail because the both contain at least one delimiter that is not escaped. I know that I need a conditional and a positive look behind, and this is what I have so far, but it is not giving me the expected answer. ^(?<delimiter>[:;,\\])?(?(delimiter)\(?<=(?:\\\\)*\\)k<delimiter>|.)$ Any suggestions on how I can make this work? Thanks.

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  • How to replace href using javascript regex in Firefox?

    - by Andrei
    I try to change some links on a webpage using the following code for jQuery on Rails $(function () { $('#lesson a').live('click', function () { $.getScript(this.href.replace(/^(http...[^\/]+)?\/+(.*)$/,'/ajax/\\$2')); return false; }); }) This trick works for Chrome and Safari, but fails (nothing happens on click) for Firefox and Opera. What can be wrong with the code? EDIT1: The webpage contains: <div id="lesson"> <a href="/subj1">Subject 1</a> ... </div> On click, a browser (i.e. Firefox and Opera) should make an ajax-request of /ajax/subj1.

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  • Regex to catch all files but those starting with "."

    - by tmslnz
    In a directory with mixed content such as: .afile .anotherfile bfile.file bnotherfile.file .afolder/ .anotherfolder/ bfolder/ bnotherfolder/ How would you catch everything but the files (not dirs) starting with .? I have tried with a negative lookahead ^(?!\.).+? but it doesn't seem to work right. Please note that I would like to avoid doing it by excluding the . by using [a-zA-Z< plus all other possible chars minus the dot >] Any suggestions?

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  • How to understand the output of the PHP regex matching below?

    - by smarty
    $file = '{include file="{$COMMON_TPL_PATH}common/header_admin.tpl"} {include file="{$mainPage}"} {include file="{$COMMON_TPL_PATH}common/footer_admin.tpl"}'; preg_match('/^(\{\})|^(\{\*([\S\s]*?)\*\})|^(<\?(?:php\w+|=|[a-zA-Z]+)?)|^([ ]*[ ]+[ ]*)|^(\{strip\})|^(\{\/strip\})|^(\{literal\})|^(\{\s{1,}\/)|^(\{\s{1,})|^(\{\/)|^(\{)|^(([\S\s]*?)(?=([ ]*[ ]+[ ]*|\{|<\?)))|^([\S\s]+)/', $file, $matches); var_dump($matches); Why the output is: array(13) { [0]=> string(1) "{" [1]=> string(0) "" [2]=> string(0) "" [3]=> string(0) "" [4]=> string(0) "" [5]=> string(0) "" [6]=> string(0) "" [7]=> string(0) "" [8]=> string(0) "" [9]=> string(0) "" [10]=> string(0) "" [11]=> string(0) "" [12]=> string(1) "{" } It seems to me that ^([\S\s]+) can match the whole string..

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  • Removing certain characters in all rows that match a regex?

    - by user001
    I'd like to change {foo, {bar}, foobar} to {foo, bar, foobar} in all rows that match '{.*{'. I.e. remove all curly braces { and } except the outer most pair. So doing mysql -h $H -u $U -p$P $DB -B -e "SELECT id FROM t WHERE col REGEXP '{.*{'" > bad.txt selects all the rows that will need this substitution. How do I make this substitution very quickly? EDIT: Could I do it by update table set column = REPLACE(column,'{',''); Then restore the out most pair update table set column = REPLACE(column,'^','{'); update table set column = REPLACE(column,'$','}');

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  • Regex to split a string (in Java) so that spaces are preserved?

    - by david
    I need to split a string (in Java) into individual words ... but I need to preserve spaces. An example of the text I need to split is something like this: ABC . . . . DEF . . . . GHI I need to see "ABC", " . . . .", "DEF", ". . . .", and "GHI". Obviously splitting on the space character \s isn't going to work, as all the spaces get swallowed up as one space. Any suggestions? Thanks

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