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  • regex. How can I match the value between '+' and ':' ?

    - by martin
    I have this string: sometext +[value]:- I would like to match the value(1-3 numerical characters) (with regex, javascript) sometext may contain a +sign if i'm unlucky so I don't wanna end up with matching some +text +value:- I sat up last night banging my head against this, so I would be really glad if someone could help me.

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  • Save File Contents to Variable in Python3.3 [migrated]

    - by Neo_Programmer
    I have a Python3.3 script that seems to not work. The script will search for an XML pattern and then print the results to the screen. I am using Ubuntu 12.10 (AMD64) and python3.3. I prefer to use regex with XML, so please disregard this unconventional form of programming. #!/usr/bin/python3.3 import io, re openfile = open('./temp/xaiml/temp_db1.xaiml', 'r') TEMPDB = openfile.read() OUTPUT = print(''.join(re.findall('<cgy><prn>.*_.*<\/prn>.*<\/cgy>', TEMPDB, flags=re.I)))

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  • List of events triggered on pages matching regex

    - by Cubius
    Is there a way to get the grouped list of events (such as in Top events) which were triggered on pages matching a regular expression? I may add the Page secondary dimension in Top events and apply the regex filter but this way I won't get a grouped list. I may apply the filter to Events - Pages report but this way the events will be grouped only inside pages whilst I need global grouping. Any suggestions?

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  • Javascript regex returning true.. then false.. then true.. etc

    - by betamax
    I have a strange problem with the validation I am writing on a form. It is a 'Check Username' button next to an input. The input default value is the username for example 'betamax'. When I press 'Check Username' it passes the regex and sends the username to the server. The server behaves as expected and returns '2' to tell the javascript that they are submitting their own username. Then, when I click the button again, the regex fails. Nothing is sent to the server obviously because the regex has failed. If I press the button again, the regex passes and then the username is sent to the server. I literally cannot figure out what would be making it do this! It makes no sense to me! This is my code: $j("#username-search").click(checkUserName); function checkUserName() { var userName = $j("#username").val(); var invalidUserMsg = 'Invalid username (a-zA-Z0-9 _ - and not - or _ at beginning or end of string)'; var filter = /^[^-_]([a-z0-9-_]{4,20})[^-_]$/gi; if (filter.test(userName)) { console.log("Pass") $j.post( "/account/profile/username_check/", { q: userName }, function(data){ if(data == 0) { $j("#username-search-results").html("Error searching for username. Try again?"); } else if(data == 5) { $j("#username-search-results").html(invalidUserMsg); } else if(data == 4) { $j("#username-search-results").html("Username too short or too long."); } else if(data == 2) { $j("#username-search-results").html("This is already your username."); } else if(data == 3) { $j("#username-search-results").html("This username is taken."); } else if(data == 1){ $j("#username-search-results").html("This username is available!"); } }); } else { console.log("fail") $j("#username-search-results").html(invalidUserMsg); } return false; } The HTML: <input name="username" id="username" value="{{ user.username }}" /> <input type="button" value="Is it taken?" id="username-search"> <span id="username-search-results"></span>

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  • Word VBA - Find text between delimiters and convert to lower case

    - by jJack
    I would like to find text which is between the < and characters, and then turn any found text into "normal" case, where first letter of word is capitalized. Here is what I have thus far: Function findTextBetweenCarots() As String Dim strText As String With Selection .Find.Text = "<" ' what about <[^0-9]+> ? .Find.Forward = True .Find.Wrap = wdFindContinue End With Selection.Find.Execute ' Application.Selection. ' how do I get the text between the other ">"? findCarotSymb = Application.Selection.Text End Function Or, is there a better way of doing this? I also approached the problem using the VBScript Regex 5.5 library, which worked on simple documents, but not on certain documents with complex tables. For example, trying to just bold the text (for simplicity): Sub BoldUpperCaseWords() Dim regEx, Match, Matches Dim rngRange As Range Set regEx = New RegExp regEx.Pattern = "<[^0-9]+>" regEx.IgnoreCase = False regEx.Global = True Set Matches = regEx.Execute(ActiveDocument.Range.Text) For Each Match In Matches ActiveDocument.Range(Match.FirstIndex, Match.FirstIndex + Len(Match.Value)).Bold = True Next End Sub would not work in a document with tables. In fact, it would not even bold the correct text (the text between the <. This leads me to believe I have a broader issue here that I am missing. Here is what a sample doc looks like. Notice the wrong text is bold:

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  • Python: Convert format string to regular expression

    - by miracle2k
    The users of my app can configure the layout of certain files via a format string. For example, the config value the user specifies might be: layout = '%(group)s/foo-%(locale)s/file.txt' I now need to find all such files that already exist. This seems easy enough using the glob module: glob_pattern = layout % {'group': '*', 'locale': '*'} glob.glob(glob_pattern) However, now comes the hard part: Given the list of glob results, I need to get all those filename-parts that matched a given placeholder, for example all the different "locale" values. I thought I would generate a regular expression for the format string that I could then match against the list of glob results (or then possibly skipping glob and doing all the matching myself). But I can't find a nice way to create the regex with both the proper group captures, and escaping the rest of the input. For example, this might give me a regex that matches the locales: regex = layout % {'group': '.*', 'locale': (.*)} But to be sure the regex is valid, I need to pass it through re.escape(), which then also escapes the regex syntax I have just inserted. Calling re.escape() first ruins the format string. I know there's fnmatch.translate(), which would even give me a regex - but not one that returns the proper groups. Is there a good way to do this, without a hack like replacing the placeholders with a regex-safe unique value etc.? Is there possibly some way (a third party library perhaps?) that allows dissecting a format string in a more flexible way, for example splitting the string at the placeholder locations?

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  • regular expression for emails NOT ending with replace script

    - by corroded
    I'm currently modifying my regex for this: http://stackoverflow.com/questions/2782031/extracting-email-addresses-in-an-html-block-in-ruby-rails basically, im making another obfuscator that uses ROT13 by parsing a block of text for all links that contain a mailto referrer(using hpricot). One use case this doesn't catch is that if the user just typed in an email address(without turning it into a link via tinymce) So here's the basic flow of my method: 1. parse a block of text for all tags with href="mailto:..." 2. replace each tag with a javascript function that changes this into ROT13 (using this script: http://unixmonkey.net/?p=20) 3. once all links are obfuscated, pass the resulting block of text into another function that parses for all emails(this one has an email regex that reverses the email address and then adds a span to that email - to reverse it back) step 3 is supposed to clean the block of text for remaining emails that AREN'T in a href tags(meaning it wasn't parsed by hpricot). Problem with this is that the emails that were converted to ROT13 are still found by my regex. What i want to catch are just emails that WEREN'T CONVERTED to ROT13. How do i do this? well all emails the WERE CONVERTED have a trailing "'.replace" in them. meaning, i need to get all emails WITHOUT that string. so far i have this regex: /\b([A-Z0-9._%+-]+@[A-Z0-9.-]+.[A-Z]{2,4}('.replace))\b/i but this gets all the emails with the trailing '.replace i want to get the opposite and I'm currently stumped with this. any help from regex gurus out there? MORE INFO: Here's the regex + the block of text im parsing: http://www.rubular.com/r/NqXIHrNqjI as you can see, the first two 'email addresses' are already obfuscated using ROT13. I need a regex that gets the emails [email protected] and [email protected]

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  • What is a Perl regex for finding the first non-consecutively-repeating character in a string.

    - by DVK
    Your task, should you choose to accept it, is to write a Perl regular expression that for a given string, will return the first occurence of a character that is not consecutively duplicated. In other words, both preceded AND succeeded by characters different from itself (or start/end of string respectively). Example: IN: aabbcdecc OUT: c Please note that "not consecutively duplicated" does not mean "anywhere in the string". NOTE: it must be a pure regex expression. E.g. the solution that obviously comes to mind (clone the string, delete all the duplicates, and print the first remaining character) does not count, although it solves the problem. The question is inspired by my somewhat off-topic answer to this: http://stackoverflow.com/questions/2548606/perl-function-to-find-first-non-repeating-character-in-a-string

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  • A regex to match a comma that isn't surrounded by quotes.

    - by Rayne
    I'm using Clojure, so this is in the context of Java regexes. Here is an example string: "{:a "ab,cd, efg", :b "ab,def, egf,", :c "Conjecture"}" The important bits are the commas after each string. I'd like to be able to replace them with newline characters with Java's replaceAll method. A regex that will match any comma that is not surrounded by quotes will do. If I'm not coming across well, please ask and I'll be happily to clarify anything. edit: sorry for the confusion in the title. I haven't been awake very long. String: {:a "ab, cd efg",} <-- In this example, the comma at the end would be matched, but the ones inside the quote would not.

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  • How can I capture multiple matches from the same Perl regex?

    - by Sho Minamimoto
    I'm trying to parse a single string and get multiple chunks of data out from the same string with the same regex conditions. I'm parsing a single HTML doc that is static (For an undisclosed reason, I can't use an HTML parser to do the job.) I have an expression that looks like: $string =~ /\<img\ssrc\="(.*)"/; and I want to get the value of $1. However, in the one string, there are many img tags like this, so I need something like an array returned (@1?) is this possible?

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  • How to add title of link as a alt of img. using regex and in dreamweaver?

    - by jitendra
    How to add title of link as a alt of img. using regex and in dreamweaver. I have to do in a large document. and in multiple files Before <a title="Whatever is written here" href="#" target="_blank"> <img width="14" height="14" src="#" /></a> after <a title="Whatever is written here" href="#" target="_blank"> <img width="14" height="14" src="#" alt="Whatever is written here" /></a>

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  • How can I match end-of-line multiple times in a regex without interpolation?

    - by harschware
    Hi, if I have a input with new lines in it like: [INFO] xyz [INFO] How can I pull out the xyz part? I tried a pattern like /^\[INFO\]$(.*?)$\[INFO\]/ms, but perl gives me: Use of uninitialized value $\ in regexp compilation at scripts\t.pl line 6. I've been trying things to get interpolation to stop like using qr// but alas, no love. EDIT: The key is that the end-of-line anchor is a dollar sign but at times it may be necessary to intersperse the end-of-line anchor through the pattern. If the pattern is interpolating then you might get problems such as uninitialized $\. For instance an acceptable solution here is /^\[INFO\]\s*^(.*?)\s*^\[INFO\]/ms but that does not solve the crux of the first problem. I've changed the anchors to be ^ so there is no interpolation going on, and with this input I'm free to do that. But what about when I really do want to reference EOL with $ in my pattern? How do I get the regex to compile?

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  • What would be the PHP equivalent of this Perl regex?

    - by Jamie
    What would be the PHP equivalent of this Perl regex? if (/^([a-z0-9-]+)\s+(\S+)\s+(\S+)\s+(\S+)\s+(\S+)\s+(\S+)\s+(\S+)\s+(\S+)$/ and $1 ne "global" and $1 ne "") { print " <tr>\n"; print " <td>$1</td>\n"; print " <td>$2</td>\n"; print " <td>$3</td>\n"; print " <td>$4</td>\n"; print " <td>$5</td>\n"; print " <td>$6</td>\n"; print " <td>$7</td>\n"; print " <td>$8</td>\n"; print " </tr>\n"; }

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  • Is it possible to join these two regex expressions into one?

    - by Pure.Krome
    Hi folks, i have the following two regular expressions (in order btw). 1. ^~/buying/(.*)\?(.*) => foo= group 1 baa= group 2. 2. ^~/buying/(.*) => foo= group 1 baa= nothing/empty/null/baibai What's i'm trying to do is, if the url has a questionmark, then split it into two groups. Otherwise, just throw all the stuff into the first group. the reason why the order is important for me, is that if i switch them round, the '?' regex will never get fired because the #2 expression (above) will catch all. So .. can this be re-fixed? NOTE: I have tried using this website** to help me debug/tweak .. but I can't figure it out. ** I have no affiliation with that site.

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  • Regex in Flex 3: How to Wrap Quotations Around a Dynamic String?

    - by Laxmidi
    Hi, I need some Regex help. I need to find beacon_ followed by an alphanumeric code and then wrap it in quotation marks. For something static, like the example, below it's straight forward. myReturn = myReturn.replace( 'id=beacon_80291ee9b3', 'id="beacon_80291ee9b3"'); But, my problem is that the part after beacon is a random alphanumeric code. (However, it is always the same length). For example, the beacon part could be: beacon_c8ac873136 beacon_dc83b5953e beacon_7a910d03d8 etc. The haystack that I'll search will look like: myReturn = "blah blah id=beacon_80291ee9b3 blah blah"; Thanks. -Laxmidi

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  • How can match end-of-line multiple times in a regex without interpolation?

    - by harschware
    Hi, if I have a input with new lines in it like: [INFO] xyz [INFO] How can I pull out the xyz part? I tried a pattern like /^\[INFO\]$(.*?)$\[INFO\]/ms, but perl gives me: Use of uninitialized value $\ in regexp compilation at scripts\t.pl line 6. I've been trying things to get interpolation to stop like using qr// but alas, no love. EDIT: The key is that the end-of-line anchor is a dollar sign but at times it may be necessary to intersperse the end-of-line anchor through the pattern. If the pattern is interpolating then you might get problems such as uninitialized $\. For instance an acceptable solution here is /^\[INFO\]\s*^(.*?)\s*^\[INFO\]/ms but that does not solve the crux of the first problem. I've changed the anchors to be ^ so there is no interpolation going on, and with this input I'm free to do that. But what about when I really do want to reference EOL with $ in my pattern? How do I get the regex to compile?

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  • How to duplicate "title" <a> as a "alt" of "img". using regex, manually?

    - by jitendra
    How to add title of link as a alt of img. using regex and in dreamweaver. I have to do in a large document. and in multiple files Before <a title="Whatever is written here" href="#" target="_blank"> <img width="14" height="14" src="#" /></a> after <a title="Whatever is written here" href="#" target="_blank"> <img width="14" height="14" src="#" alt="Whatever is written here" /></a>

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  • Can somone help fix up my simple regex query, please?

    - by Pure.Krome
    Hi folks, yep - another noob regex query, which I can't seem to get. I'm trying to get all matches for the string foo.mydomain.com/ or foo.mydomain.com:1234/ or foo.mydomain.com:<random port>/ but any other paths do not match, ie. foo.mydomain.com/bar or foo.mydomain.com/bar/pewpew I tried to use: foo.mydomain.com(.*)/$ ( starts with anything, then foo.mydomain.com, then any thing after that .. until a slash. then end. (this search query is anchored to the end of the line). but that doesn't work. It doesn't match when i pass in foo.mydomain.com:1234 but it correct says foo.mydomain.com/bar/pewpew is not a match (as expected). any ideas?

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  • To remove garbage characters from a string using regex...

    - by Harjit Singh
    Hi I want to remove characters from a string other then a-z, and A-Z. Created following function for the same and it works fine. public String stripGarbage(String s) { String good = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789abcdefghijklmnopqrstuvwxyz"; String result = ""; for (int i = 0; i < s.length(); i++) { if (good.indexOf(s.charAt(i)) >= 0) { result += s.charAt(i); } } return result; } Can anyone tell me a better way to achieve the same. Probably regex may be better option. Regards Harry

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  • Can you use zero-width matching regex in String split?

    - by polygenelubricants
    System.out.println( Arrays.deepToString( "abc<def>ghi".split("(?:<)|(?:>)") ) ); This prints [abc, def, ghi], as if I had split on "<|>". I want it to print [abc, <def>, ghi]. Is there a way to work some regex magic to accomplish what I want here? Perhaps a simpler example: System.out.println( Arrays.deepToString( "Hello! Oh my!! Good bye!!".split("(?:!+)") ) ); This prints [Hello, Oh my, Good bye]. I want it to print [Hello!, Oh my!!, Good bye!!]. `.

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