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  • Get number of posts in a topic PHP

    - by Wayne
    How do I get to display the number of posts on a topic like a forum. I used this... (how very noobish): function numberofposts($n) { $sql = "SELECT * FROM posts WHERE topic_id = '" . $n . "'"; $result = mysql_query($sql) or die(mysql_error()); $count = mysql_num_rows($result); echo number_format($count); } The while loop of listing topics: <div class="topics"> <div class="topic-name"> <p><?php echo $row['topic_title']; ?></p> </div> <div class="topic-posts"> <p><?php echo numberofposts($row['topic_id']); ?></p> </div> </div> Although it is a bad method of doing this... All I need is to know what would be the best method, don't just point me out to a website, do it here, because I'm trying to learn much. Okay? :D Thanks.

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  • Querying Last Entries group by DeviceId

    - by TTCG
    I have the database table logs as the following: I would like to extract the last entry of device, pollDate, status. For eg. deviceId, pollDate, status 1, 2010-95-06 10:53:28, 1 3, 2010-95-06 10:26:28, 1 I tried to run the following query but the distinct only selects the first records, not the latest SELECT DISTINCT deviceId, pollDate, status FROM logs GROUP By deviceId ORDER BY pollDate DESC So, could you please help me to extract the latest entries from the table? Thanks.

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  • What's the ROI of using a build tool like ant or nant?

    - by leeand00
    To me this sounds like a really stupid question. Why would you not use a build tool? However, I need to explain my co-worker why he should be using a build tool of some sort. He's getting really into the idea of working as a team with more programmers, but he isn't understanding the bigger picture of what needs to change in the build process in order to work with a larger team; (i.e. defensive programming/unit testing your code, having a bug database, programming modular libraries, and using sub-repositories to store modules in version control. This is a rather large stack of technologies that I need to prove the ROI of...so I figured I'd start with the ROI of using a build tool rather than just...say...clicking compile.

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  • How to display thumbnails with category by category

    - by shin
    http://pastie.org/962429 I have the above SQL. There are three categories, webdesign, logos and prints. I want to display them as following html. http://pastie.org/962432 Basically pulling thumbnail image and name from database category by category. I am not really sure how to do it. I will appreciate any inputs or help. Thanks in advance.

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  • PHP auto refresh page without losing user input

    - by Tony
    I'm working on a PHP collaboration software project. I have a page that shows the latest updates from other users who are adding content to the database, but also has a form input to allow the user to enter text. I am currently using this code to refresh the page automatically every 30 seconds: header('Refresh: 30'); The problem is that the header code refreshes the entire page, and not just what is pulled from the database. Is there any PHP code that will just pull any new data from the database without refreshing the entire page? If someone could point me in the right direction I'd appreciate it.

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  • Prevent two users from editing the same data

    - by Industrial
    Hi everyone, I have seen a feature in different web applications including Wordpress (not sure?) that warns a user if he/she opens an article/post/page/whatever from the database, while someone else is editing the same data simultaneously. I would like to implement the same feature in my own application and I have given this a bit of thought. Is the following example a good practice on how to do this? It goes a little something like this: 1) User A enters a the editing page for the mysterious article X. The database tableEvents is queried to make sure that no one else is editing the same page for the moment, which no one is by then. A token is then randomly being generated and is inserted into a database table called Events. 1) User B also want's to make updates to the article X. Now since our User A already is editing the article, the Events table is queried and looks like this: | timestamp | owner | Origin | token | ------------------------------------------------------------ | 1273226321 | User A | article-x | uniqueid## | 2) The timestamp is being checked. If it's valid and less than say 100 seconds old, a message appears and the user cannot make any changes to the requested article X: Warning: User A is currently working with this article. In the meantime, editing cannot be done. Please do something else with your life. 3) If User A decides to go on and save his changes, the token is posted along with all other data to update the database, and toggles a query to delete the row with token uniqueid##. If he decides to do something else instead of committing his changes, the article X will still be available for editing in 100 seconds for User B Let me know what you think about this approach! Wish everyone a great weekend!

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  • how to specify a BIGINT in a rails scaffold?

    - by webdestroya
    I am trying to create a model in ruby that uses a BIGINT datatype (as opposed to the INT done by :integer). I have search all over Google, but all I seem to find is "run an SQL statement to alter the table to a BIGINT" - This seems a bit hack-ish to me, so I wanted to know if there was a way to specify a bigint in the ruby system like :big_int or something Any ideas?

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  • Where/When do C# and the .NET Framework fail to be the right tool?

    - by Nate Bross
    In my non-programming life, I always attempt to use the appropriate tool for the job, and I feel that I do the same in my programming life, but I find that I am choosing C# and .NET for almost everything. I'm finding it hard to come up with (realistic business) needs that cannot be met by .NET and C#. Obviously embedded systems might require something less bloated than the .NET Micro Framework, but I'm really looking for line of business type situations where .NET is not the best tool. I'm primarly a C# and .NET guy since its what I'm the most comfertable in, but I know a fair amount of C++, php, VB, PowerShell, batch files, and Java, as well as being versed in the web technologes (JavaScript, HTML, and CSS). But I'm open minded about it my skill set and I'm looking for cases where C# and .NET are not the right tool for the job. I choose .NET and C# because I'm comfortable with it, but I'm looking for cases where it isn't appropriate.

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  • Data Modeling Help - Do I add another table, change existing table's usage, or something else?

    - by StackOverflowNewbie
    Assume I have the following tables and relationships: Person - Id (PK) - Name A Person can have 0 or more pets: Pet - Id (PK) - PersonId (FK) - Name A person can have 0 or more attributes (e.g. age, height, weight): PersonAttribute _ Id (PK) - PersonId (FK) - Name - Value PROBLEM: I need to represent pet attributes, too. As it turns out, these pet attributes are, in most cases, identical to the attributes of a person (e.g. a pet can have an age, height, and weight too). How do I represent pet attributes? Do I create a PetAttribute table? PetAttribute Id (PK) PetId (FK) Name Value Do I change PersonAttribute to GenericAttribute and have 2 foreign keys in it - one connecting to Person, the other connecting to Pet? GenericAttribute Id (PK) PersonId (FK) PetId (FK) Name Value NOTE: if PersonId is set, then PetId is not set. If PetId is set, PersonId is not set. Do something else?

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  • Spring can't find a lib and webapp doesn't start up in tomcat 6

    - by gotch4
    I've this problem using STS: I'm building a simple Spring app, just to try out features like MVC and persistence. Now I've created something very simple, out of a bunch of tutorials for Spring 3, that I'm using. The application fails with this, during server startup: Code: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping#0': Initialization of bean failed; nested exception is org.springframework.beans.factory.CannotLoadBeanClassException: Cannot find class [org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean] for bean with name 'mySessionFactory' defined in ServletContext resource [/WEB-INF/spring/appServlet/servlet-context.xml]; nested exception is java.lang.ClassNotFoundException: org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean but I've org.springframework.orm in web-inf/classes folder (I even tried putting it in web-inf/lib). As I copied these libs there, the came out in Web App Libraries folder. Building this project in STS works fine as this dependency is set up in build path throught project properties, but how do I transfer the libs to the web app? (I'm using Tomcat 6 as it is the server I'm going to use sometime in the future for production). Is this a config problem of my XML? Or am I just missing the right way to put this lib? (I encountered the same problem before, but adding the needed lib in classes worked it out). More than this I that if I browse inside my workspace to the folder where the working folder of tomcat should be, I can't find any work directory and any commo

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  • problem in counting children category

    - by moustafa
    I have this table: fourn_category (id , sub) I am using this code to count: function CountSub($id){ $root = array($id); $query = mysql_query("SELECT id FROM fourn_category WHERE sub = '$id'"); while( $row = mysql_fetch_array( $query, MYSQL_ASSOC ) ){ array_push($root,$row['id']); CountSub($row['id']); } return implode(",",$root); } It returns the category id as 1,2,3,4,5 to using it to count the sub by IN() But the problem is that it counts this: category 1 category 2 category 3 category 4 category 5 Category 1 has 1 child not 4. Why? How can I get all children's trees?

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  • PHP - Select from database the same query

    - by How to PHP
    I created a table that contains the name of the user and his job, and created PHP page that shows me all the users that works doctor, I entered doctor into a variable then I selected from the table where Jobs equal to $doctor, that is great, but I need it to get the same Jobs into a table in the page and the other same jobs into a table in the same page. this is my code that shows only the users works doctor in one table, <html> <h1>Doctors</h1> </html> <?php mysql_connect('localhost','root',''); mysql_select_db('data'); $doctor='doctor'; $query= mysql_query("SELECT * FROM `users` WHERE `job` = '$doctor'")or die(mysql_error()); while ($arr = mysql_fetch_array($query)) $name= $arr['name']; echo $name; } ?> That shows me doctors when I put doctor in a variable I want to show all same Jobs in a table. Is there is a way to do this? Thanks :)

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  • select query from mysql_num_rows

    - by Andi Nugroho
    i want create multiple search where statement $where_search is a multiple condition from post form. but stil error when iam using this code ".where_search." in where condition with mysql_num_rows for paging $tampil2 = mysql_query("SELECT * FROM bb where ".$where_search." and kd_kelompok='2' and kd_komoditi='11' and nm_sebutan IS NOT NULL " ); this is the complete code. $where_search = "kd_pok='2' and kd_komoditi='11' "; if (isset($_POST['lakpus'])) { if (empty($_POST['lakpus'])) { } else { if (empty($where_search)) { $where_search .= "lakpus = '$lakpus' "; } else { $where_search .= "AND lakpus = '$lakpus' "; } } } if (isset($_POST['kd_por'])) { $kd_por = $_POST['kd_por'] ; if (empty($_POST['kd_por'])) { } else { if (empty($where_search)) { $where_search .= "kd_por = '$kd_por' "; } else { $where_search .= "AND tab1.kd_por = '$kd_por' "; } } } $max=15; $tampil2 = mysql_query("SELECT * FROM bb where ".$where_search." and kd_kelompok='2' and kd_komoditi='11' and nm_sebutan IS NOT NULL " ); $jml = mysql_num_rows($tampil2); $jmlhal = ceil($jml/$max);

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  • Delphi trace tool

    - by Max
    I was wondering if there's a tool or a component for Delphi that can trace method execution line by line and create a log file. With this kind of tool it is easy to compare how method performs on two sets of input data by comparing two log files. EDIT: Let's say there is a function 10: function MyFunction(aInput: Integer): Integer; 11: begin 12: if aInput 10 then 13: Result := 10 14: else 15: Result := 0; 16: end; I'm looking for a tool that would give the log which whould be similar to the following: When aInput parameter is 1: Line 10: 'function MyFunction(aInput: Integer): Integer;' Line 11: 'begin' Line 12: 'if aInput 10 then' Line 15: 'Result := 0;' Line 16: 'end;' and when aInput parameter is 11: Line 10: 'function MyFunction(aInput: Integer): Integer;' Line 11: 'begin' Line 12: 'if aInput 10 then' Line 13: 'Result := 10;' Line 16: 'end;' The only information that should be required by the tool is the function name. It's like stepping through the method under debugger, but in an automatic manner with logging every line of code.

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  • Avoiding Nested Queries

    - by Midhat
    How Important is it to avoid nested queries. I have always learnt to avoid them like a plague. But they are the most natural thing to me. When I am designing a query, the first thing I write is a nested query. Then I convert it to joins, which sometimes takes a lot of time to get right. And rarely gives a big performance improvement (sometimes it does) So are they really so bad. Is there a way to use nested queries without temp tables and filesort

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  • software to manage applications within business.

    - by Richard Friend
    Hi I have been tasked to either find an off the shelf solution or to build inhouse some software that can maintain a list of all of the applications within our business, assign them to the different business areas that use them and list all the servers, documents, knowledge base etc that relate to the app in question. Does anyone know of any existing software that can do this ? Regards

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  • INSERT INTO ... SELECT FROM ... ON DUPLICATE KEY UPDATE

    - by dnagirl
    I'm doing an insert query where most of many columns would need to be updated to the new values if a unique key already existed. It goes something like this: INSERT INTO lee(exp_id, created_by, location, animal, starttime, endtime, entct, inact, inadur, inadist, smlct, smldur, smldist, larct, lardur, lardist, emptyct, emptydur) SELECT id, uid, t.location, t.animal, t.starttime, t.endtime, t.entct, t.inact, t.inadur, t.inadist, t.smlct, t.smldur, t.smldist, t.larct, t.lardur, t.lardist, t.emptyct, t.emptydur FROM tmp t WHERE uid=x ON DUPLICATE KEY UPDATE ...; //update all fields to values from SELECT, except for exp_id, created_by, location, animal, starttime, endtime I'm not sure what the syntax for the UPDATE clause should be. How do I refer to the current row from the SELECT clause?

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  • Any universal notification service like Adobe Wave

    - by Michael Pliskin
    Any ideas for an universal notification service like Adobe Wave? I need to send status updates (more specifically, things like document change notifications and the like). I could stick to RSS but then I will need either long URLs or HTTP authentications on feeds which not all the clients like. Adobe Wave looked promising but they are only desktop, in BETA, without active development, and seem a bit buggy sometimes. Any other ideas?

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  • PHP errors -> Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt | Warning: mysqli_stmt::c

    - by Tunji Gbadamosi
    I keep getting this error while trying to modify some tables. Here's my code: /** <- line 320 * * @param array $guests_array * @param array $tickets_array * @param integer $seat_count * @param integer $order_count * @param integer $guest_count */ private function book_guests($guests_array, $tickets_array, &$seat_count, &$order_count, &$guest_count){ /* @var $guests_array ArrayObject */ $sucess = false; if(sizeof($guests_array) >= 1){ //$this->mysqli->autocommit(FALSE); //insert the guests into guest, person, order, seat $menu_stmt = $this->mysqli->prepare("SELECT id FROM menu WHERE name=?"); $menu_stmt->bind_param('s',$menu); //$menu_stmt->bind_result($menu_id); $table_stmt = $this->mysqli->prepare("SELECT id FROM tables WHERE name=?"); $table_stmt->bind_param('s',$table); //$table_stmt->bind_result($table_id); $seat_stmt = $this->mysqli->prepare("SELECT id FROM seat WHERE name=? AND table_id=?"); $seat_stmt->bind_param('ss',$seat, $table_id); //$seat_stmt->bind_result($seat_id); for($i=0;$i<sizeof($guests_array);$i++){ $menu = $guests_array[$i]['menu']; $table = $guests_array[$i]['table']; $seat = $guests_array[$i]['seat']; //get menu id if($menu_stmt->execute()){ $menu_stmt->bind_result($menu_id); while($menu_stmt->fetch()) ; } $menu_stmt->close(); //get table id if($table_stmt->execute()){ $table_stmt->bind_result($table_id); while($table_stmt->fetch()) ; } $table_stmt->close(); //get seat id if($seat_stmt->execute()){ $seat_stmt->bind_result($seat_id); while($seat_stmt->fetch()) ; } $seat_stmt->close(); $dob = $this->create_date($guests_array[$i]['dob_day'], $guests_array[$i]['dob_month'], $guests_array[$i]['dob_year']); $id = $this->add_person($guests_array[$i]['first_name'], $guests_array[$i]['surname'], $dob, $guests_array[$i]['sex']); if(is_string($id)){ $seat = $this->add_seat($table_id, $seat_id, $id); /* @var $tickets_array ArrayObject */ $guest = $this->add_guest($id,$tickets_array[$i+1],$menu_id, $this->volunteer_id); /* @var $order integer */ $order = $this->add_order($this->volunteer_id, $table_id, $seat_id, $id); if($guest == 1 && $seat == 1 && $order == 1){ $seat_count += $seat; $guest_count += $guest; $order_count += $order; $success = true; } } } } return $success; } <- line 406 Here are the warnings: The person PRSN10500000LZPH has been added to the guest tablePRSN10500000LZPH added to table (1), seat (1)The order for person(PRSN10500000LZPH) is registered with volunteer (PRSN10500000LZPH) at table (1) and seat (1)PRSN10600000LZPH added to table (1), seat (13)The person PRSN10600000LZPH has been added to the guest tableThe order for person(PRSN10600000LZPH) is registered with volunteer (PRSN10500000LZPH) at table (1) and seat (13) Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 358 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 363 Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 366 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 371 Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 374 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 379 PRSN10700000LZPH added to table (1), seat (13)The person PRSN10700000LZPH has been added to the guest tableThe order for person(PRSN10700000LZPH) is registered with volunteer (PRSN10500000LZPH) at table (1) and seat (13) Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 358 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 363 Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 366 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 371 Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 374 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 379 PRSN10800000LZPH added to table (1), seat (13)The person PRSN10800000LZPH has been added to the guest tableThe order for person(PRSN10800000LZPH) is registered with volunteer (PRSN10500000LZPH) at table (1) and seat (13)

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  • counting twice in a query, once using restrictions

    - by Andrew Heath
    Given the following tables: Table1 [class] [child] math boy1 math boy2 math boy3 art boy1 Table2 [child] [glasses] boy1 yes boy2 yes boy3 no If I want to query for number of children per class, I'd do this: SELECT class, COUNT(child) FROM Table1 GROUP BY class and if I wanted to query for number of children per class wearing glasses, I'd do this: SELECT Table1.class, COUNT(table1.child) FROM Table1 LEFT JOIN Table2 ON Table1.child=Table2.child WHERE Table2.glasses='yes' GROUP BY Table1.class but what I really want to do is: SELECT class, COUNT(child), COUNT(child wearing glasses) and frankly I have no idea how to do that in only one query. help?

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