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  • Is it possible to LIMIT results from a JOIN query?

    - by Arms
    I've got a query that currently queries a Post table while LEFT JOINing a Comment table. It fetches all Posts and their respective Comments. However, I want to limit the number of Comments returned. I tried adding a sub-select, but ran into errors if I didn't LIMIT the results to 1. I'm really not sure how to go about this while still using only one query. Is this possible?

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  • Storing unique values into an array and comparing against a loop - PHP

    - by Aphex22
    I'm writing a PHP report which is designed to be exported purely as a CSV file, using commma delimiters. There are three columns relating to product_id, these three columns are as follows: SKU Parent / Child Parent SKU 12345 parent 12345 12345_1 child 12345 12345_2 child 12345 12345_3 child 12345 12345_4 child 12345 18099 parent 18099 18099_1 child 18099 Here's a link to the full CSV file: http://i.imgur.com/XELufRd.png At the moment the code looks like this: $sql = "select * from product WHERE on_amazon = 'on' AND active = 'on'"; $result = mysql_query($sql) or die ( mysql_error() );?> <? // set headers echo " Type, SKU, Parent / Child, Parent SKU, Product name, Manufacturer name, Gender, Product_description, Product price, Discount price, Quantity, Category, Photo 1, Photo 2, Photo 3, Photo 4, Photo 5, Photo 6, Photo 7, Photo 8, Color id, Color name, Size name <br> "; // load all stock while ($line = mysql_fetch_assoc($result) ) { ?> <?php // Loop through each possible size variation to see whether any of the quantity column has stock > 0 $con_size = array (35,355,36,37,375,38,385,39,395,40,405,41,415,42,425,43,435,44,445,45,455,46,465,47,475,48,485); $arrlength=count($con_size); for($x=0;$x<$arrlength;$x++) { // check if size is available if($line['quantity_c_size_'.$con_size[$x].'_chain'] > 0 ) { ?> <? echo 'Shoes'; ?>, <?=$line['product_id']?>, , , <?=$line['title']?>, <? $brand = $line['jys_brand']; echo ucfirst($brand); ?>, <? $gender = $line['category']; if ($gender == 'Mens') { echo 'H'; } else{ echo 'F'; } ?>, <?=preg_replace('/[^\da-z]/i', ' ', $line['amazon_desc']) ?>, <?=$line['price']?>, <?=$line['price']?>, <?=$line['quantity_c_size_'.$con_size[$x].'_chain']?>, <? $category = $line['style1']; switch ($category) { case "ankle-boots": echo "10013"; break; case "knee-high-boots": echo "10011"; break; case "high-heel-boots": echo "10033"; break; case "low-heel-boots": echo "10014"; break; case "wedge-boots": echo "10014"; break; case "western-boots": echo "10032"; break; case "flat-shoes": echo "10034"; break; case "high-heel-shoes": echo "10039"; break; case "low-heel-shoes": echo "10039"; break; case "wedge-shoes": echo "10035"; break; case "ballerina-shoes": echo "10008"; break; case "boat-shoes": echo "10018"; break; case "loafer-shoes": echo "10037"; break; case "work-shoes": echo "10039"; break; case "flat-sandals": echo "10041"; break; case "low-heel-sandals": echo "10042"; break; case "high-heel-sandals": echo "10042"; break; case "wedge-sandals": echo "10042"; break; case "mule-sandals": echo "10038"; break; case "mary-jane-shoes": echo "10039"; break; case "sports-shoes": echo "10026"; break; case "court-shoes": echo "10035"; break; case "peep-toe-shoes": echo "10035"; break; case "flat-boots": echo "10609"; break; case "mid-calf-boots": echo "10014"; break; case "trainer-shoes": echo "10009"; break; case "wellington-boots": echo "10012"; break; case "lace-up-boots": echo "10609"; break; case "chelsea-and-jodphur-boots": echo "10609"; break; case "desert-and-chukka-boots": echo "10032"; break; case "lace-up-shoes": echo "10034"; break; case "slip-on-shoes": echo "10043"; break; case "gibson-and-derby-shoes": echo "10039"; break; case "oxford-shoes": echo "10039"; break; case "brogue-shoes": echo "10039"; break; case "winter-boots": echo "10021"; break; case "slipper-shoes": echo "10016"; break; case "mid-heel-shoes": echo "10039"; break; case "sandals-and-beach-shoes": echo "10044"; break; case "mid-heel-sandals": echo "10042"; break; case "mid-heel-boots": echo "10014"; break; default: echo ""; } ?>, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_1.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_2.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_3.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_4.jpg, , , , , <? $colour = preg_replace('/[^\da-z]/i', ' ', $line['colour']); if( preg_match( '/white.*/i', $colour)) { echo '1'; } elseif( preg_match( '/yellow.*/i', $colour)) { echo '4'; } elseif( preg_match( '/orange.*/i', $colour)) { echo '7'; } elseif( preg_match( '/red.*/i', $colour)) { echo '8'; } elseif( preg_match( '/pink.*/i', $colour)) { echo '13'; } elseif( preg_match( '/purple.*/i', $colour)) { echo '15'; } elseif( preg_match( '/blue.*/i', $colour)) { echo '19'; } elseif( preg_match( '/green.*/i', $colour)) { echo '25'; } elseif( preg_match( '/brown.*/i', $colour)) { echo '28'; } elseif( preg_match( '/grey.*/i', $colour)) { echo '35'; } elseif( preg_match( '/black.*/i', $colour)) { echo '38'; } elseif( preg_match( '/gold.*/i', $colour)) { echo '41'; } elseif( preg_match( '/silver.*/i', $colour)) { echo '46'; } elseif( preg_match( '/multi.*/i', $colour)) { echo '594'; } elseif( preg_match( '/beige.*/i', $colour)) { echo '6887'; } elseif( preg_match( '/nude.*/i', $colour)) { echo '6887'; } else { echo '534'; } ?>, <?=$line['colour']?>, <?=$con_size[$x]?> <br> <? // finish checking if size is available } } ?> So at the moment this is simply echoing out the product_ID into the SKU column. The code would need to enter the product_id into an array and check whether it is unique. If the product_id is unique to the array, then the product_id is echoed out unaltered, and parent is echoed out to the 'Parent/Child' column and then the product_id is repeated to the 'Parent SKU' column. However, if the array is checked and the product_id already exists in the array, then the product_id is echoed out to the 'SKU' column with a suffix i.e. _1. Then child is echoed to the 'Parent / Child' column and the original parent product_id echoed to the 'Parent SKU' column. HOWEVER - the same SKU cannot be repeated with the same suffix i.e. 12345_1, 12345_1 - so presumably there would be to be another array for the suffixed SKUs to be checked against. If anybody could help, it would be great. Thanks --- UPDATE ANSWER --- I managed to solved this myself and thought I would share my solution for future reference. /* * Array to collect product_ids and check whether unique. * If unique product_id becomes parent SKU * If not product_id becomes child of previous parent and suffixed with _1, _2 etc... */ if (!in_array($line['product_id'], $SKU)) { $SKU[] = $line['product_id']; $parent = $line['product_id']; $a = 0; ?> <? echo 'Shoes'; ?>, <? echo $parent; ?>, <? echo "Parent"; ?>, <? echo $parent; ?>, <? } else { $child = $line['product_id'] . "_" . $a; ?> <? echo 'Shoes'; ?>, <? echo $child; ?>, <? echo "Child"; ?>, <? echo $child; <? // increment suffix value for child SKU $a++; ?>

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  • PHP While() Stop Looping

    - by Axel
    Hi, i have a php loop which displays only one record even if there is hundreds. here is the code: <?php $result1 = mysql_query("SELECT * FROM posts") or die(mysql_error()); $numexem = mysql_num_rows($result1); $s="0"; while($s<$numexem){ $postid=mysql_result($result1,$s,"id"); echo "Post id:".$postid; $result2 = mysql_query("SELECT * FROM pics WHERE postid='$postid'") or die(mysql_error()); $rows = mysql_fetch_array($result2) or die(mysql_error()); $pnum = mysql_num_rows($result2); echo " There is ".$pnum." Attached Pictures"; $s++; } ?> I'm wondering if the loop stop because there is other SQL query inside it or what? and i don't think so. Thanks

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  • Avoiding Nested Queries

    - by Midhat
    How Important is it to avoid nested queries. I have always learnt to avoid them like a plague. But they are the most natural thing to me. When I am designing a query, the first thing I write is a nested query. Then I convert it to joins, which sometimes takes a lot of time to get right. And rarely gives a big performance improvement (sometimes it does) So are they really so bad. Is there a way to use nested queries without temp tables and filesort

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  • PHP coding a price comparaison tool

    - by Tristan
    Hello, it's the first time I developp such tool you all know (the possibility to compare articles according to price and/or options) Since I never did that i want to tell me what do you think of the way i see that : On the database we would have : offer / price / option 1 / option 2 / option 3 / IDseller / IDoffer best buy / 15$ / full FTP / web hosting / php.ini / 10 / 1 .../..../.... And the request made by the client : "SELECT * FROM offers WHERE price <= 20 AND option1 = fullFTP"; I don't know if it seems OK to you. Plus i was wondering, how to avoid multiples entries for the same seller. Imagine you have multiple offers with a price <= 20 with the option FullFTP for the same seller, i don't want him to be shown 5 times on the comparator. If you have any advices ;) Thanks

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  • current_date casting

    - by Armen Mkrtchyan
    Hi. string selectSql = "update " + table + " set state_" + mode + "_id=1 WHERE stoping_" + mode + " < current_date;"; when i call current_date, it return yyyy-MM-dd format, but i want to return dd.MM.yyyy format, how can i do that. please help. my program works fine when i am trying string selectSql = "update " + table + " set state_" + mode + "_id=1 WHERE stoping_" + mode + " < '16.04.2010';";

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  • Unknown column even thoug it exits

    - by george
    I have SELECT servisler.geo_location, servisler.ADRES_MERKEZ, servisler.ADRES_ILCE, servisler.ADRES_IL, servisler.FIRMA_UNVANI, servisler.ADRES_ISTEL, servisler.YETKILI_ADISOYADI, urun_gruplari.GRUP_ADI FROM servisler INNER JOIN urun_gruplari ON kullanici_cihaz.URUN_GRUP_NO= urun_gruplari.RECNO INNER JOIN kullanici ON kullanici.SERVIS_RECNO = servisler.RECNO INNER JOIN kullanici_cihaz ON kullanici.RECNO = kullanici_cihaz.KUL_RECNO AND kullanici_cihaz.URUN_GRUP_NO = urun_gruplari.RECNO where kullanici.kullanici = 'MAR.EDI.003' but it says [Err] 1054 - Unknown column 'kullanici_cihaz.URUN_GRUP_NO' in 'on clause' enen though the column exits. What is its problem? schema Server version: 5.1.33-community-log

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  • Extending URIs with 2 queries (i.e. 'viewauthorbooks.php?authorid=4' AND 'orderby=returndate") Possi

    - by Jess
    I have a link in my system as displayed above; 'viewauthorbooks.php?authorid=4' which works fine and generates a page displaying the books only associated with the particular author. However I am implementing another feature where the user can sort the columns (return date, book name etc) and I am using the ORDER BY SQL clause. I have this also working as required for other pages, which do not already have another query in the URI. But for this particular page there is already a paramter returned in the URL, and I am having difficulty in extending it. When the user clicks on the a table column title I'm getting an error, and the original author ID is being lost!! This is the URI link I am trying to use: <th><a href="viewauthorbooks.php?authorid=<?php echo $row['authorid']?>&orderby=returndate">Return Date</a></th> This is so that the data can be sorted in order of Return Date. When I run this; the author ID gets lost for some reason, also I want to know if I am using correct layout to have 2 parameters run in the address? Thanks.

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  • Using a nested group by statement or sub query to filter this result sets

    - by vivid-colours
    This question is a continuation of Changing this query to group rows and filter out all rows apart from the one with smallest value but with an extra bit at the end.... I have the following results set: 275 72.87368055555555555555555555555555555556 foo 70 275 72.87390046296296296296296296296296296296 foo 90 113 77.06431712962962962962962962962962962963 foo 80 113 77.07185185185185185185185185185185185185 foo 60 that I got from this query: SELECT id, (tbl2.date_modified - tbl1.date_submitted)/86400, some_value FROM tbl1, tbl2, tbl3 WHERE tbl1.id = tbl2.fid AND tbl1.id = tbl3.fid Notice there are 4 rows with 2 ids. I wanted to filter the rows to get only the minimum number in the second column. This fixed it: SELECT id, min((tbl2.date_modified - tbl1.date_submitted)/86400), max(some_value) FROM tbl1, tbl2, tbl3 WHERE tbl1.id = tbl2.fid AND tbl1.id = tbl3.fid GROUP BY tbl1.id so I got: 275 72.87368055555555555555555555555555555556 foo 70 113 77.06431712962962962962962962962962962963 foo 80 How can I change it to do the same but not include rows where the are other rows with some_value=90 ? I.e. 113 77.06431712962962962962962962962962962963 foo 80 I think I need some nested group or nested query ?! Many thanks :).

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  • Zend Framework Error:Invalid parameter number: no parameters were bound'

    - by roast_soul
    I'm using the Zend Frameworker 1.12. According to the help file, I used the Zend_Db_Statement to execute my sql. Below is my php code: $sql = "delete from options where id=?"; $stmt = new Zend_Db_Statement_Mysqli($this->getAdapter(), $sql); return $stmt->execute(array('1')); But the error is exception 'PDOException' with message 'SQLSTATE[HY093]: Invalid parameter number: no parameters were bound' in D:\Zend\workspaces\DefaultWorkspace.metadata.plugins\org.zend.php.framework.resource\resources\ZendFramework-1\library\Zend\Db\Statement\Mysqli.php:209 Stack trace: ......... ......... I googled for days, but nothing works. Any one know how to fix it?

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  • Spring can't find a lib and webapp doesn't start up in tomcat 6

    - by gotch4
    I've this problem using STS: I'm building a simple Spring app, just to try out features like MVC and persistence. Now I've created something very simple, out of a bunch of tutorials for Spring 3, that I'm using. The application fails with this, during server startup: Code: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping#0': Initialization of bean failed; nested exception is org.springframework.beans.factory.CannotLoadBeanClassException: Cannot find class [org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean] for bean with name 'mySessionFactory' defined in ServletContext resource [/WEB-INF/spring/appServlet/servlet-context.xml]; nested exception is java.lang.ClassNotFoundException: org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean but I've org.springframework.orm in web-inf/classes folder (I even tried putting it in web-inf/lib). As I copied these libs there, the came out in Web App Libraries folder. Building this project in STS works fine as this dependency is set up in build path throught project properties, but how do I transfer the libs to the web app? (I'm using Tomcat 6 as it is the server I'm going to use sometime in the future for production). Is this a config problem of my XML? Or am I just missing the right way to put this lib? (I encountered the same problem before, but adding the needed lib in classes worked it out). More than this I that if I browse inside my workspace to the folder where the working folder of tomcat should be, I can't find any work directory and any commo

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  • what is the question for the query?

    - by Kevinniceguy
    Sorry...I mean what question will be for this query? SELECT SUM(price) FROM Room r, Hotel h WHERE r.hotelNo = h.hotelNo and hotelName = 'Paris Hilton' and roomNo NOT IN (SELECT roomNo FROM Booking b, Hotel h WHERE (dateFrom <= CURRENT_DATE AND dateTo >= CURRENT_DATE) AND b.hotelNo = h.hotelNo AND hotelName = 'Paris Hilton');

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  • Favouriting things in a database - most efficient method of keeping track?

    - by a2h
    I'm working on a forum-like webapp where I'd like to allow users to favourite an item so that they can keep track of it, and also so that others can see how many times an item's been favourited. The problem is, I'm unsure on the best practices for databases, which includes this situation. I have two ideas in my head on how to do this: Add an extra column to the user table and store things like so: "|2|5|73|" Add an extra table with at least two columns, one for referencing an item, the other for referencing a user. I feel uncomfortable about going for the second method as it involves an extra table, and potentially more queries would be required. Perhaps these beliefs aren't an issue, as I have little understanding of databases beyond simply working with table layouts and basic queries.

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  • Why is str_replace not replacing this string?

    - by Niall
    I have the following PHP code which should load the data from a CSS file into a variable, search for the old body background colour, replace it with the colour from a submitted form, resave the CSS file and finally update the colour in the database. The problem is, str_replace does not appear to be replacing anything. Here is my PHP code (stored in "processors/save_program_settings.php"): <?php require("../security.php"); $institution_name = mysql_real_escape_string($_POST['institution_name']); $staff_role_title = mysql_real_escape_string($_POST['staff_role_title']); $program_location = mysql_real_escape_string($_POST['program_location']); $background_colour = mysql_real_escape_string($_POST['background_colour']); $bar_border_colour = mysql_real_escape_string($_POST['bar_border_colour']); $title_colour = mysql_real_escape_string($_POST['title_colour']); $url = $global_variables['program_location']; $data_background = mysql_query("SELECT * FROM sents_global_variables WHERE name='background_colour'") or die(mysql_error()); $background_output = mysql_fetch_array($data_background); $css = file_get_contents($url.'/default.css'); $str = "body { background-color: #".$background_output['data']."; }"; $str2 = "body { background-color: #".$background_colour."; }"; $css2 = str_replace($str, $str2, $css); unlink('../default.css'); file_put_contents('../default.css', $css2); mysql_query("UPDATE sents_global_variables SET data='{$institution_name}' WHERE name='institution_name'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$staff_role_title}' WHERE name='role_title'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$program_location}' WHERE name='program_location'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$background_colour}' WHERE name='background_colour'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$bar_border_colour}' WHERE name='bar_border_colour'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$title_colour}' WHERE name='title_colour'") or die(mysql_error()); header('Location: '.$url.'/pages/start.php?message=program_settings_saved'); ?> Here is my CSS (stored in "default.css"): @charset "utf-8"; /* CSS Document */ body,td,th { font-family: Arial, Helvetica, sans-serif; font-size: 14px; color: #000; } body { background-color: #CCCCFF; } .main_table th { background:#003399; font-size:24px; color:#FFFFFF; } .main_table { background:#FFF; border:#003399 solid 1px; } .subtitle { font-size:20px; } input#login_username, input#login_password { height:30px; width:300px; font-size:24px; } input#login_submit { height:30px; width:150px; font-size:16px; } .timetable_cell_lesson { width:100px; font-size:10px; } .timetable_cell_tutorial_a, .timetable_cell_tutorial_b, .timetable_cell_break, .timetable_cell_lunch { width:100px; background:#999; font-size:10px; } I've run some checks using the following code in the PHP file: echo $css . "<br><br>" . $str . "<br><br>" . $str2 . "<br><br>" . $css2; exit; And it outputs (as you can see it's not changing anything in the CSS): @charset "utf-8"; /* CSS Document */ body,td,th { font-family: Arial, Helvetica, sans-serif; font-size: 14px; color: #000; } body { background-color: #CCCCFF; } .main_table th { background:#003399; font-size:24px; color:#FFFFFF; } .main_table { background:#FFF; border:#003399 solid 1px; } .subtitle { font-size:20px; } input#login_username, input#login_password { height:30px; width:300px; font-size:24px; } input#login_submit { height:30px; width:150px; font-size:16px; } .timetable_cell_lesson { width:100px; font-size:10px; } .timetable_cell_tutorial_a, .timetable_cell_tutorial_b, .timetable_cell_break, .timetable_cell_lunch { width:100px; background:#999; font-size:10px; } body { background-color: #CCCCFF; } body { background-color: #FF5719; } @charset "utf-8"; /* CSS Document */ body,td,th { font-family: Arial, Helvetica, sans-serif; font-size: 14px; color: #000; } body { background-color: #CCCCFF; } .main_table th { background:#003399; font-size:24px; color:#FFFFFF; } .main_table { background:#FFF; border:#003399 solid 1px; } .subtitle { font-size:20px; } input#login_username, input#login_password { height:30px; width:300px; font-size:24px; } input#login_submit { height:30px; width:150px; font-size:16px; } .timetable_cell_lesson { width:100px; font-size:10px; } .timetable_cell_tutorial_a, .timetable_cell_tutorial_b, .timetable_cell_break, .timetable_cell_lunch { width:100px; background:#999; font-size:10px; }

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  • how to set a status

    - by ejah85
    hello guys..here i've a problem where i want to set the status whether it is approved or reject.. the condition are if admin select the registration number and driver name, that means the status is approve otherwise, if admin fill up the reason, that means the request is reject.. here is the code to set status if ($reason =='null'){ $query2 = "UPDATE usage SET status ='APPROVED' WHERE '$bookingno'=bookingno"; $result2 = @mysql_query($query2); } elseif (($regno =='null')&&($d_name =='null')) { $query3 = "UPDATE usage SET status ='REJECT' WHERE '$bookingno'=bookingno"; $result3 = @mysql_query($query3); } when i save the data, the status field are not updates..

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  • Php INNER JOING jqGrid help

    - by yanike
    I'm trying to get INNER JOIN to work with JQGRID, but I can't get it working. I want the code to get the first_name and last_name from members using the "efrom" from messages that matches the "id" from members. $col = array(); $col["title"] = "From"; $col["name"] = "messages.efrom"; $col["width"] = "70"; $col["hidden"] = false; $col["editable"] = false; $col["sortable"] = true; $col["search"] = true; $cols[] = $col; $col = array(); $col["title"] = "First Name"; $col["name"] = "members.first_name"; $col["width"] = "80"; $col["hidden"] = false; $col["editable"] = false; $col["sortable"] = true; $col["search"] = true; $cols[] = $col; $col = array(); $col["title"] = "Last Name"; $col["name"] = "members.last_name"; $col["width"] = "80"; $col["hidden"] = false; $col["editable"] = false; $col["sortable"] = true; $col["search"] = true; $cols[] = $col; $col = array(); $col["title"] = "Subject"; $col["name"] = "messages.esubject"; $col["width"] = "300"; $col["hidden"] = false; $col["editable"] = false; $col["sortable"] = true; $col["search"] = true; $cols[] = $col; $col = array(); $col["title"] = "Date"; $col["name"] = "messages.edatetime"; $col["width"] = "150"; $col["hidden"] = false; $col["editable"] = false; $col["sortable"] = true; $col["search"] = true; $cols[] = $col; $g = new jqgrid(); $grid["sortname"] = 'messages.edatetime'; $g->select_command = "SELECT messages.efrom, messages.esubject, messages.edatetime, members.first_name, members.last_name FROM messages INNER JOIN members ON messages.efrom = members.id";

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  • How to get rank based on SUM's?

    - by Kenan
    I have comments table where everything is stored, and i have to SUM everything and add BEST ANSWER*10. I need rank for whole list, and how to show rank for specified user/ID. Here is the SQL: SELECT m.member_id AS member_id, (SUM(c.vote_value) + SUM(c.best)*10) AS total FROM comments c LEFT JOIN members m ON c.author_id = m.member_id GROUP BY c.author_id ORDER BY total DESC LIMIT {$sql_start}, 20

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  • Preventing spam bots on site?

    - by Mike
    We're having an issue on one of our fairly large websites with spam bots. It appears the bots are creating user accounts and then posting journal entries which lead to various spam links. It appears they are bypassing our captcha somehow -- either it's been cracked or they're using another method to create accounts. We're looking to do email activation for the accounts, but we're about a week away from implementing such changes (due to busy schedules). However, I don't feel like this will be enough if they're using an SQL exploit somewhere on the site and doing the whole cross site scripting thing. So my question to you: If they are using some kind of XSS exploit, how can I find it? I'm securing statements where I can but, again, its a fairly large site and it'd take me awhile to actively clean up SQL statements to prevent XSS. Can you recommend anything to help our situation?

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  • What's the best UML diagramming tool?

    - by eplawless
    I'm trying to choose a tool for creating UML diagrams of all flavours. Usability is a major criteria for me, but I'd still take more power with a steeper learning curve and be happy. Free (as in beer) would be nice, but I'd be willing to pay if the tool's worth it. What should I be using?

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  • Compare structures of two databases?

    - by streetparade
    Hello, I wanted to ask whether it is possible to compare the complete database structure of two huge databases. We have two databases, the one is a development database, the other a production database. I've sometimes forgotten to make changes in to the production database, before we released some parts of our code, which results that the production database doesn't have the same structure, so if we release something we got some errors. Is there a way to compare the two, or synchronize?

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  • T_BOOLEAN_AND error?

    - by Ronnie Chester Lynwood
    whats wrong with this? anybody help me please.. if(stripos($nerde, $hf) !== false) && (stripos($nerde, $rs) !== false){ @mysql_query("update table set dltur = '3' where id = '".$ppl[id]."'"); } else { //dont do anything } i get T_BOOLEAN_AND error.

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  • how to specify a BIGINT in a ruby scaffold?

    - by webdestroya
    I am trying to create a model in ruby that uses a BIGINT datatype (as opposed to the INT done by :integer). I have search all over Google, but all I seem to find is "run an SQL statement to alter the table to a BIGINT" - This seems a bit hack-ish to me, so I wanted to know if there was a way to specify a bigint in the ruby system like :big_int or something Any ideas?

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  • Need to map classes to different databases at runtime in Hibernate

    - by serg555
    I have MainDB database and unknown number (at compile time) of UserDB_1, ..., UserDB_N databases. MainDB contains names of those UserDB databases in some table (new UserDB can be created at runtime). All UserDB have exactly the same table names and fields. How to handle such situation in Hibernate? (database structure cannot be changed). Currently I am planning to create generic User classes not mapped to anything and just use native SQL for all queries: session.createSQLQuery("select * from " + db + ".user where id=1") .setResultTransformer(Transformers.aliasToBean(User.class)); Is there anything better I can do? Ideally I would want to have mappings for UserDB tables and relations and use HQL on required database.

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  • counting twice in a query, once using restrictions

    - by Andrew Heath
    Given the following tables: Table1 [class] [child] math boy1 math boy2 math boy3 art boy1 Table2 [child] [glasses] boy1 yes boy2 yes boy3 no If I want to query for number of children per class, I'd do this: SELECT class, COUNT(child) FROM Table1 GROUP BY class and if I wanted to query for number of children per class wearing glasses, I'd do this: SELECT Table1.class, COUNT(table1.child) FROM Table1 LEFT JOIN Table2 ON Table1.child=Table2.child WHERE Table2.glasses='yes' GROUP BY Table1.class but what I really want to do is: SELECT class, COUNT(child), COUNT(child wearing glasses) and frankly I have no idea how to do that in only one query. help?

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