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  • Storing unique values into an array and comparing against a loop - PHP

    - by Aphex22
    I'm writing a PHP report which is designed to be exported purely as a CSV file, using commma delimiters. There are three columns relating to product_id, these three columns are as follows: SKU Parent / Child Parent SKU 12345 parent 12345 12345_1 child 12345 12345_2 child 12345 12345_3 child 12345 12345_4 child 12345 18099 parent 18099 18099_1 child 18099 Here's a link to the full CSV file: http://i.imgur.com/XELufRd.png At the moment the code looks like this: $sql = "select * from product WHERE on_amazon = 'on' AND active = 'on'"; $result = mysql_query($sql) or die ( mysql_error() );?> <? // set headers echo " Type, SKU, Parent / Child, Parent SKU, Product name, Manufacturer name, Gender, Product_description, Product price, Discount price, Quantity, Category, Photo 1, Photo 2, Photo 3, Photo 4, Photo 5, Photo 6, Photo 7, Photo 8, Color id, Color name, Size name <br> "; // load all stock while ($line = mysql_fetch_assoc($result) ) { ?> <?php // Loop through each possible size variation to see whether any of the quantity column has stock > 0 $con_size = array (35,355,36,37,375,38,385,39,395,40,405,41,415,42,425,43,435,44,445,45,455,46,465,47,475,48,485); $arrlength=count($con_size); for($x=0;$x<$arrlength;$x++) { // check if size is available if($line['quantity_c_size_'.$con_size[$x].'_chain'] > 0 ) { ?> <? echo 'Shoes'; ?>, <?=$line['product_id']?>, , , <?=$line['title']?>, <? $brand = $line['jys_brand']; echo ucfirst($brand); ?>, <? $gender = $line['category']; if ($gender == 'Mens') { echo 'H'; } else{ echo 'F'; } ?>, <?=preg_replace('/[^\da-z]/i', ' ', $line['amazon_desc']) ?>, <?=$line['price']?>, <?=$line['price']?>, <?=$line['quantity_c_size_'.$con_size[$x].'_chain']?>, <? $category = $line['style1']; switch ($category) { case "ankle-boots": echo "10013"; break; case "knee-high-boots": echo "10011"; break; case "high-heel-boots": echo "10033"; break; case "low-heel-boots": echo "10014"; break; case "wedge-boots": echo "10014"; break; case "western-boots": echo "10032"; break; case "flat-shoes": echo "10034"; break; case "high-heel-shoes": echo "10039"; break; case "low-heel-shoes": echo "10039"; break; case "wedge-shoes": echo "10035"; break; case "ballerina-shoes": echo "10008"; break; case "boat-shoes": echo "10018"; break; case "loafer-shoes": echo "10037"; break; case "work-shoes": echo "10039"; break; case "flat-sandals": echo "10041"; break; case "low-heel-sandals": echo "10042"; break; case "high-heel-sandals": echo "10042"; break; case "wedge-sandals": echo "10042"; break; case "mule-sandals": echo "10038"; break; case "mary-jane-shoes": echo "10039"; break; case "sports-shoes": echo "10026"; break; case "court-shoes": echo "10035"; break; case "peep-toe-shoes": echo "10035"; break; case "flat-boots": echo "10609"; break; case "mid-calf-boots": echo "10014"; break; case "trainer-shoes": echo "10009"; break; case "wellington-boots": echo "10012"; break; case "lace-up-boots": echo "10609"; break; case "chelsea-and-jodphur-boots": echo "10609"; break; case "desert-and-chukka-boots": echo "10032"; break; case "lace-up-shoes": echo "10034"; break; case "slip-on-shoes": echo "10043"; break; case "gibson-and-derby-shoes": echo "10039"; break; case "oxford-shoes": echo "10039"; break; case "brogue-shoes": echo "10039"; break; case "winter-boots": echo "10021"; break; case "slipper-shoes": echo "10016"; break; case "mid-heel-shoes": echo "10039"; break; case "sandals-and-beach-shoes": echo "10044"; break; case "mid-heel-sandals": echo "10042"; break; case "mid-heel-boots": echo "10014"; break; default: echo ""; } ?>, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_1.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_2.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_3.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_4.jpg, , , , , <? $colour = preg_replace('/[^\da-z]/i', ' ', $line['colour']); if( preg_match( '/white.*/i', $colour)) { echo '1'; } elseif( preg_match( '/yellow.*/i', $colour)) { echo '4'; } elseif( preg_match( '/orange.*/i', $colour)) { echo '7'; } elseif( preg_match( '/red.*/i', $colour)) { echo '8'; } elseif( preg_match( '/pink.*/i', $colour)) { echo '13'; } elseif( preg_match( '/purple.*/i', $colour)) { echo '15'; } elseif( preg_match( '/blue.*/i', $colour)) { echo '19'; } elseif( preg_match( '/green.*/i', $colour)) { echo '25'; } elseif( preg_match( '/brown.*/i', $colour)) { echo '28'; } elseif( preg_match( '/grey.*/i', $colour)) { echo '35'; } elseif( preg_match( '/black.*/i', $colour)) { echo '38'; } elseif( preg_match( '/gold.*/i', $colour)) { echo '41'; } elseif( preg_match( '/silver.*/i', $colour)) { echo '46'; } elseif( preg_match( '/multi.*/i', $colour)) { echo '594'; } elseif( preg_match( '/beige.*/i', $colour)) { echo '6887'; } elseif( preg_match( '/nude.*/i', $colour)) { echo '6887'; } else { echo '534'; } ?>, <?=$line['colour']?>, <?=$con_size[$x]?> <br> <? // finish checking if size is available } } ?> So at the moment this is simply echoing out the product_ID into the SKU column. The code would need to enter the product_id into an array and check whether it is unique. If the product_id is unique to the array, then the product_id is echoed out unaltered, and parent is echoed out to the 'Parent/Child' column and then the product_id is repeated to the 'Parent SKU' column. However, if the array is checked and the product_id already exists in the array, then the product_id is echoed out to the 'SKU' column with a suffix i.e. _1. Then child is echoed to the 'Parent / Child' column and the original parent product_id echoed to the 'Parent SKU' column. HOWEVER - the same SKU cannot be repeated with the same suffix i.e. 12345_1, 12345_1 - so presumably there would be to be another array for the suffixed SKUs to be checked against. If anybody could help, it would be great. Thanks --- UPDATE ANSWER --- I managed to solved this myself and thought I would share my solution for future reference. /* * Array to collect product_ids and check whether unique. * If unique product_id becomes parent SKU * If not product_id becomes child of previous parent and suffixed with _1, _2 etc... */ if (!in_array($line['product_id'], $SKU)) { $SKU[] = $line['product_id']; $parent = $line['product_id']; $a = 0; ?> <? echo 'Shoes'; ?>, <? echo $parent; ?>, <? echo "Parent"; ?>, <? echo $parent; ?>, <? } else { $child = $line['product_id'] . "_" . $a; ?> <? echo 'Shoes'; ?>, <? echo $child; ?>, <? echo "Child"; ?>, <? echo $child; <? // increment suffix value for child SKU $a++; ?>

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  • How to get rank based on SUM's?

    - by Kenan
    I have comments table where everything is stored, and i have to SUM everything and add BEST ANSWER*10. I need rank for whole list, and how to show rank for specified user/ID. Here is the SQL: SELECT m.member_id AS member_id, (SUM(c.vote_value) + SUM(c.best)*10) AS total FROM comments c LEFT JOIN members m ON c.author_id = m.member_id GROUP BY c.author_id ORDER BY total DESC LIMIT {$sql_start}, 20

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  • Zend Framework Error:Invalid parameter number: no parameters were bound'

    - by roast_soul
    I'm using the Zend Frameworker 1.12. According to the help file, I used the Zend_Db_Statement to execute my sql. Below is my php code: $sql = "delete from options where id=?"; $stmt = new Zend_Db_Statement_Mysqli($this->getAdapter(), $sql); return $stmt->execute(array('1')); But the error is exception 'PDOException' with message 'SQLSTATE[HY093]: Invalid parameter number: no parameters were bound' in D:\Zend\workspaces\DefaultWorkspace.metadata.plugins\org.zend.php.framework.resource\resources\ZendFramework-1\library\Zend\Db\Statement\Mysqli.php:209 Stack trace: ......... ......... I googled for days, but nothing works. Any one know how to fix it?

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  • details in one Row without any redundancy in the CATID

    - by alkitbi
    $query1 = "select * from linkat_link where emailuser = '$email2' or linkname ='$domain_name2' ORDER BY date desc LIMIT $From,$PageNO"; id   catid      discription            price ------------------------------------ 1         1     domain name     100 2         1      book                  50 3        2      hosting               20 4        2      myservice           20 in this script i have one problem , if i have an ID for Each Cantegory , i have some duplicated CATID which has different content but shares the same CATID, i need to make any duplicated CATID to show in one , and all the discription will be in the same line (Cell) on the same row . So Each CatID will have all the details in one Row without any redundancy in the CATID

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  • Having a problem displaying data from last inserted data

    - by Gideon
    I'm designing a staff rota planner....have three tables Staff (Staff details), Event (Event details), and Job (JobId, JobDate, EventId (fk), StaffId (fk)). I need to display the last inserted job detail with the staff name. I've been at it for couple of hours and getting nowhere. Thanks for the help in advance. My code is the following: $eventId = $_POST['eventid']; $selectBox = $_POST['selectbox']; $timePeriod = $_POST['time']; $selectedDate = $_POST['date']; $count = count($selectBox); //constructing the staff selection if (empty($selectBox)) { echo "<p>You didn't select any member of staff to be assigned."; echo "<p><input type='button' value='Go Back' onClick='history.go(-1)'>"; } else { echo "<p> You selected ".$count. " staff for this show."; for ($i=0;$i<$count;$i++) { $selectId = $selectBox[$i]; //insert the details into the Job table in the database $insertJob = "INSERT INTO Job (JobDate, TimePeriod, EventId, StaffId) VALUES ('".$selectedDate."', '".$timePeriod."', ".$eventId.", ".$selectId.")"; $exeinsertJob = mysql_query($insertJob) or die (mysql_error()); } } //display the inserted job details $insertedlist = "SELECT Job.JobId, Staff.LastName, Staff.FirstName, Job.JobDate, Job.TimePeriod FROM Staff, Job WHERE Job.StaffId = Staff.StaffId AND Job.EventId = $eventId AND Job.JobDate = ".$selectedDate; $exeinsertlist = mysql_query($insertedlist) or die (mysql_error()); if ($exeinsertlist) { echo "<p><table cellspacing='1' cellpadding='3'>"; echo "<tr><th colspan=5> ".$eventname."</th></tr>"; echo "<tr><th>Job Id</th><th>Last Name</th> <th>First Name </th><th>Date</th><th>Hours</th></tr>"; while ($joblistarray = mysql_fetch_array($exeinsertlist)) { echo "<tr><td align=center>".$joblistarray['JobId']." </td><td align=center>".$joblistarray['LastName']."</td><td align=center>".$joblistarray['FirstName']." </td><td align=center>".$joblistarray['JobDate']." </td><td align=center>".$joblistarray['TimePeriod']."</td></tr>"; } echo "</table>"; echo "<h3><a href=AssignStaff.php>Add More Staff?</a></h3>"; } else { echo "The Job list can not be displayed at this time. Try again."; echo "<p><input type='button' value='Go Back' onClick='history.go(-1)'>"; }

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  • Decoding mysql_real_escape_string() for outputting HTML

    - by Peter
    I'm trying to protect myself from sql injection and am using: mysql_real_escape_string($string); When posting HTML it looks something like this: <span class="\&quot;className\&quot;"> <p class="\&quot;pClass\&quot;" id="\&quot;pId\&quot;"></p> </span> I'm not sure how many other variations real_escape_string adds so don't want to just replace a few and miss others... How do I "decode" this back into correctly formatted HTML, with something like: html_entity_decode(stripslashes($string));

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  • php paypal ipn membership error

    - by aleksander haugas
    hello I integrated the membership subscription in the website, but I fail to insert data to the database. checking out all the function I make a txt file with php with data and generates me correctly. but I can not verify any data and less insert. <?php // read the post from PayPal system and add 'cmd' $req = 'cmd=_notify-validate'; foreach ($_POST as $key => $value) { $value = urlencode(stripslashes($value)); $req .= "&$key=$value"; } // Post back to PayPal system to validate $header .= "POST /cgi-bin/webscr HTTP/1.0\r\n"; $header .= "Content-Type: application/x-www-form-urlencoded\r\n"; $header .= "Content-Length: " . strlen($req) . "\r\n\r\n"; $fp = fsockopen ('ssl://www.paypal.com', 443, $errno, $errstr, 30); // Assign posted variables to local variables $item_name = $_POST['item_name']; $item_number = $_POST['item_number']; $payment_status = $_POST['payment_status']; $payment_amount = $_POST['mc_gross']; $payment_currency = $_POST['mc_currency']; $txn_id = $_POST['txn_id']; $receiver_email = $_POST['receiver_email']; $payer_email = $_POST['payer_email']; $user_id = $_POST['custom']; //Here i make the txt file and it works correctly //but after this does not work or make a txt file //Insert and update data if (!$fp) { // HTTP ERROR } else { fputs ($fp, $header . $req); while (!feof($fp)) { $res = fgets ($fp, 1024); if (strcmp ($res, "VERIFIED") == 0) { //Verificamos el estado del pedido if ($payment_status == 'Completed') { $txn_id_check = mysql_query("SELECT Transaction_ID FROM ".$db_table_prefix."Users_Payments WHERE Transaction_ID='".$txn_id."'"); if (mysql_num_rows($txn_id_check) !=1) { //Si el pago se ha realizado al dueño especificado y coincide con el dueño if ($receiver_email == $website_Payment_Email) { //Tipo de cuenta segun pagado if ($payment_amount == '10.00' && $payment_currency == 'EUR') { //add txn_id to database $log_query = mysql_query("INSERT INTO `".$db_table_prefix."Users_Payments` VALUES ('','".$txn_id."','".$payer_email."')"); //update premium to 3 $update_premium = mysql_query("UPDATE ".$db_table_prefix."Users SET Group_ID='3' WHERE User_ID='".$user_id."'"); } } } } } else if (strcmp ($res, "INVALID") == 0) { // log for manual investigation } } fclose ($fp); } ?> I call this file with require_once () with the connection to the database any ideas? thanks

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  • SQL Command for the following table.

    - by Sanju
    I have a table named with "Sales" having the following columns: Sales_ID|Product_Code|Zone|District|State|Distributor|Total_Sales Now i want to generate a sales summary to view the total sales by zone and then by district and then by State by which distributor for the last/past month period. How can i write a Sql Statement to do this? Can anyone help me Plz. Thanks in advance. And i have another question that, how can i select the second largest or third largest values from any column of a table.

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  • Remove duplicate records/objects uniquely identified by multiple attributes

    - by keruilin
    I have a model called HeroStatus with the following attributes: id user_id recordable_type hero_type (can be NULL!) recordable_id created_at There are over 100 hero_statuses, and a user can have many hero_statuses, but can't have the same hero_status more than once. A user's hero_status is uniquely identified by the combination of recordable_type + hero_type + recordable_id. What I'm trying to say essentially is that there can't be a duplicate hero_status for a specific user. Unfortunately, I didn't have a validation in place to assure this, so I got some duplicate hero_statuses for users after I made some code changes. For example: user_id = 18 recordable_type = 'Evil' hero_type = 'Halitosis' recordable_id = 1 created_at = '2010-05-03 18:30:30' user_id = 18 recordable_type = 'Evil' hero_type = 'Halitosis' recordable_id = 1 created_at = '2009-03-03 15:30:00' user_id = 18 recordable_type = 'Good' hero_type = 'Hugs' recordable_id = 1 created_at = '2009-02-03 12:30:00' user_id = 18 recordable_type = 'Good' hero_type = NULL recordable_id = 2 created_at = '2009-012-03 08:30:00' (Last two are not a dups obviously. First two are.) So what I want to do is get rid of the duplicate hero_status. Which one? The one with the most-recent date. I have three questions: How do I remove the duplicates using a SQL-only approach? How do I remove the duplicates using a pure Ruby solution? Something similar to this: http://stackoverflow.com/questions/2790004/removing-duplicate-objects. How do I put a validation in place to prevent duplicate entries in the future?

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  • selecting data from table based on date .

    - by mehdi
    i have database table like this +-------+--------------+----------+ | id | ip | date | +-------+--------------+----------+ | 505 |192.168.100.1 |2010-04-03| | 252 |192.168.100.5 |2010-03-03| | 426 |192.168.100.6 |2010-03-03| | 201 |192.168.100.7 |2010-04-03| | 211 |192.168.100.10|2010-04-03| +-------+--------------+----------+ how can i retirive data from this table where month=03 how to write sql to do that . select * from table where month=03 something like that .

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  • SQL How to join multiplue columns with same name to one column

    - by Choi Shun Chi
    There is a super class account {User, TYPE} and subclasses saving{User, ID, balance,TYPE,interest,curency_TYPE} time{User,ID,balance,TYPE,interest,curency_TYPE,start_date,due_date,period} fore{User,ID,balance,interest,curency_TYPE} User and TYPE is the primary key of account and foreign key of three subclasses ID is primary key of three subclasses how to make a list of showing all IDs in one column?Also the same as balance and TYPE meet the problem I considered a.ID as saving, b.ID as time but it showing them separately

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  • Why is str_replace not replacing this string?

    - by Niall
    I have the following PHP code which should load the data from a CSS file into a variable, search for the old body background colour, replace it with the colour from a submitted form, resave the CSS file and finally update the colour in the database. The problem is, str_replace does not appear to be replacing anything. Here is my PHP code (stored in "processors/save_program_settings.php"): <?php require("../security.php"); $institution_name = mysql_real_escape_string($_POST['institution_name']); $staff_role_title = mysql_real_escape_string($_POST['staff_role_title']); $program_location = mysql_real_escape_string($_POST['program_location']); $background_colour = mysql_real_escape_string($_POST['background_colour']); $bar_border_colour = mysql_real_escape_string($_POST['bar_border_colour']); $title_colour = mysql_real_escape_string($_POST['title_colour']); $url = $global_variables['program_location']; $data_background = mysql_query("SELECT * FROM sents_global_variables WHERE name='background_colour'") or die(mysql_error()); $background_output = mysql_fetch_array($data_background); $css = file_get_contents($url.'/default.css'); $str = "body { background-color: #".$background_output['data']."; }"; $str2 = "body { background-color: #".$background_colour."; }"; $css2 = str_replace($str, $str2, $css); unlink('../default.css'); file_put_contents('../default.css', $css2); mysql_query("UPDATE sents_global_variables SET data='{$institution_name}' WHERE name='institution_name'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$staff_role_title}' WHERE name='role_title'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$program_location}' WHERE name='program_location'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$background_colour}' WHERE name='background_colour'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$bar_border_colour}' WHERE name='bar_border_colour'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$title_colour}' WHERE name='title_colour'") or die(mysql_error()); header('Location: '.$url.'/pages/start.php?message=program_settings_saved'); ?> Here is my CSS (stored in "default.css"): @charset "utf-8"; /* CSS Document */ body,td,th { font-family: Arial, Helvetica, sans-serif; font-size: 14px; color: #000; } body { background-color: #CCCCFF; } .main_table th { background:#003399; font-size:24px; color:#FFFFFF; } .main_table { background:#FFF; border:#003399 solid 1px; } .subtitle { font-size:20px; } input#login_username, input#login_password { height:30px; width:300px; font-size:24px; } input#login_submit { height:30px; width:150px; font-size:16px; } .timetable_cell_lesson { width:100px; font-size:10px; } .timetable_cell_tutorial_a, .timetable_cell_tutorial_b, .timetable_cell_break, .timetable_cell_lunch { width:100px; background:#999; font-size:10px; } I've run some checks using the following code in the PHP file: echo $css . "<br><br>" . $str . "<br><br>" . $str2 . "<br><br>" . $css2; exit; And it outputs (as you can see it's not changing anything in the CSS): @charset "utf-8"; /* CSS Document */ body,td,th { font-family: Arial, Helvetica, sans-serif; font-size: 14px; color: #000; } body { background-color: #CCCCFF; } .main_table th { background:#003399; font-size:24px; color:#FFFFFF; } .main_table { background:#FFF; border:#003399 solid 1px; } .subtitle { font-size:20px; } input#login_username, input#login_password { height:30px; width:300px; font-size:24px; } input#login_submit { height:30px; width:150px; font-size:16px; } .timetable_cell_lesson { width:100px; font-size:10px; } .timetable_cell_tutorial_a, .timetable_cell_tutorial_b, .timetable_cell_break, .timetable_cell_lunch { width:100px; background:#999; font-size:10px; } body { background-color: #CCCCFF; } body { background-color: #FF5719; } @charset "utf-8"; /* CSS Document */ body,td,th { font-family: Arial, Helvetica, sans-serif; font-size: 14px; color: #000; } body { background-color: #CCCCFF; } .main_table th { background:#003399; font-size:24px; color:#FFFFFF; } .main_table { background:#FFF; border:#003399 solid 1px; } .subtitle { font-size:20px; } input#login_username, input#login_password { height:30px; width:300px; font-size:24px; } input#login_submit { height:30px; width:150px; font-size:16px; } .timetable_cell_lesson { width:100px; font-size:10px; } .timetable_cell_tutorial_a, .timetable_cell_tutorial_b, .timetable_cell_break, .timetable_cell_lunch { width:100px; background:#999; font-size:10px; }

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  • SQL conditional row insert

    - by Pablo
    Is it possible to insert a new row if a condition is meet? For example, i have this table with no primary key nor uniqueness +----------+--------+ | image_id | tag_id | +----------+--------+ | 39 | 8 | | 8 | 39 | | 5 | 11 | +----------+--------+ I would like to insert a row if a combination of image_id and tag_id doesn't exists for example; INSERT ..... WHERE image_id!=39 AND tag_id!=8

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  • SQL Server Long Query

    - by thormj
    Ok... I don't understand why this query is taking so long (MSSQL Server 2005): [Typical output 3K rows, 5.5 minute execution time] SELECT dbo.Point.PointDriverID, dbo.Point.AssetID, dbo.Point.PointID, dbo.Point.PointTypeID, dbo.Point.PointName, dbo.Point.ForeignID, dbo.Pointtype.TrendInterval, coalesce(dbo.Point.trendpts,5) AS TrendPts, LastTimeStamp = PointDTTM, LastValue=PointValue, Timezone FROM dbo.Point LEFT JOIN dbo.PointType ON dbo.PointType.PointTypeID = dbo.Point.PointTypeID LEFT JOIN dbo.PointData ON dbo.Point.PointID = dbo.PointData.PointID AND PointDTTM = (SELECT Max(PointDTTM) FROM dbo.PointData WHERE PointData.PointID = Point.PointID) LEFT JOIN dbo.SiteAsset ON dbo.SiteAsset.AssetID = dbo.Point.AssetID LEFT JOIN dbo.Site ON dbo.Site.SiteID = dbo.SiteAsset.SiteID WHERE onlinetrended =1 and WantTrend=1 PointData is the biggun, but I thought its definition should allow me to pick up what I want easily enough: CREATE TABLE [dbo].[PointData]( [PointID] [int] NOT NULL, [PointDTTM] [datetime] NOT NULL, [PointValue] [real] NULL, [DataQuality] [tinyint] NULL, CONSTRAINT [PK_PointData_1] PRIMARY KEY CLUSTERED ( [PointID] ASC, [PointDTTM] ASC ) WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] GO CREATE NONCLUSTERED INDEX [IX_PointDataDesc] ON [dbo].[PointData] ( [PointID] ASC, [PointDTTM] DESC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, SORT_IN_TEMPDB = OFF, IGNORE_DUP_KEY = OFF, DROP_EXISTING = OFF, ONLINE = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] GO PointData is 550M rows, and Point (source of PointID) is only 28K rows. I tried making an Indexed View, but I can't figure out how to get the Last Timestamp/Value out of it in a compatible way (no Max, no subquery, no CTE). This runs twice an hour, and after it runs I put more data into those 3K PointID's that I selected. I thought about creating LastTime/LastValue tables directly into Point, but that seems like the wrong approach. Am I missing something, or should I rebuild something? (I'm also the DBA, but I know very little about A'ing a DB!)

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  • PHP Login, Store Session Variables.

    - by Andreas Carlbom
    Yo. I'm trying to make a simple login system in PHP and my problem is this: I don't really understand sessions. Now, when I log a user in, I run session_register("user"); but I don't really understand what I'm up to. Does that session variable contain any identifiable information, so that I for example can get it out via $_SESSION["user"] or will I have to store the username in a separate variable? Thanks.

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  • problem parsing JSON Strings

    - by blacktooth
    var records = JSON.parse(JsonString); for(var x=0;x<records.result.length;x++) { var record = records.result[x]; ht_text+="<b><p>"+(x+1)+" " +record.EMPID+" " +record.LOCNAME+" " +record.DEPTNAME+" " +record.CUSTNAME +"<br/><br/><div class='slide'>" +record.REPORT +"</div></p></b><br/>"; } The above code works fine when the JsonString contains an array of entities but fails for single entity. result is not identified as an array! Whats wrong with it? http://pastebin.com/hgyWw5hd

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  • counting number of new entries in guest book

    - by Lucka
    I want to display the number of new(unseen) guest entries in the guest book of a user. I was thinking to count it so that, total number of entries in guestbook minus entries in guestbook at time of last login. However, I think that is not a good approach, because if the user logs in but does not go to his guestbook, in that case, the entries should be still "new", also if some new entry is posted in the user while he is online, it does not work in that case too. Any suggested please?

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  • Is SQL DATEDIFF(year, ..., ...) an Expensive Computation?

    - by rlb.usa
    I'm trying to optimize up some horrendously complicated SQL queries because it takes too long to finish. In my queries, I have dynamically created SQL statements with lots of the same functions, so I created a temporary table where each function is only called once instead of many, many times - this cut my execution time by 3/4. So my question is, can I expect to see much of a difference if say, 1,000 datediff computations are narrowed to 100?

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  • How to secure phpMyAdmin

    - by Andrei
    Hi, I have noticed that there are strange requests to my website trying to find phpmyadmin, like /phpmyadmin/ /pma/ etc. Now I have installed PMA on Ubuntu via apt and would like to access it via webaddress different from /phpmyadmin/. What can I do to change it? Thanks

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  • While loop problems

    - by Luke
    I have put together the following code, the problem is that each while loop is only returning one set of data. $result = mysql_query("SELECT date FROM ".TBL_FIXTURES." WHERE compname = '$comp_name' GROUP BY date"); $i = 1; echo "<table cellspacing=\"10\" style='border: 1px dotted' width=\"300\" bgcolor=\"#eeeeee\">"; while ($row = mysql_fetch_assoc($result)) { $date=date("F j Y", $row['date']); echo $date; echo " <tr> <td>Fixture $i - Deadline on $date</td> </tr> "; $result = mysql_query("SELECT * FROM ".TBL_FIXTURES." WHERE compname = '$comp_name' AND date = '$row[date]' ORDER BY date"); while ($row = mysql_fetch_assoc($result)) { extract ($row); echo " <tr> <td>$home_user - $home_team V $away_user - $away_team</td> </tr> "; } $i++; } echo "</table>"; I should get many dates, and then each set of fixture below. At the moment, the first row from the first while loop is present, along with the data from the second while loop. However, it doesn't continue? Any ideas where I can correct this? Thanks

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  • SQL hidden techniques?

    - by AlexRednic
    What are those pro/subtle techniques that SQL provides and not many know about which also cut code and improve performance? eg: I have just learned how to use CASE statements inside aggregate functions and it totally changed my approach on things. Are there others?

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  • Fiscal year, quarters, student table, and faculty table... How do I relate these?!

    - by yuudachi
    I have a student and faculty table. The primary key for student is studendID (SID) and faculty's primary key is facultyID, naturally. Student has an advisor column and a requested advisor column, which are foreign key to faculty. That's simple enough, right? However, now I have to throw in dates. I want to be able to view who their advisor was for a certain quarter (such as 2009 Winter) and who they had requested. The result will be a table like this: Year | Term | SID | Current | Requested ------------------------------------------------ 2009 | Winter | 860123456 | 1 | NULL 2009 | Winter | 860445566 | 3 | NULL 2009 | Winter | 860369147 | 5 | 1 And then if I feel like it, I could also go ahead and view a different year and a different term. I am not sure how these new table(s) will look like. Will there be a year table with three columns that are Fall, Spring and Winter? And what will the Fall, Spring, Winter table have? I am new to the art of tables, so this is baffling me... Also, I feel I should clarify how the site works so far now. Admin can approve student requests, and what happens is that the student's current advisor gets overwritten with their request. However, I think I should not do that anymore, right?

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  • Which database I can used and relationship in it ??

    - by mimo-hamad
    My projece make me confused which I didn't find clear things that make me understand the required database and the relationships in it So, would a super one help me to solve it ?!! ;D this is required: 1) Model the data stored in the database (Identify the entities, roles, relationships, constraints, etc.) 2) Write the Oracle commands to create the database, find appropriate data, and populate the database 3) Write five different queries on your database, using the SELECT/FROM/WHERE construct provided in SQL. Your five queries should illustrate several different aspects of database querying, such as: a. Queries over more than one relation (by listing more than one relation in the FROM clause) b. Queries involving aggregate functions, such as SUM, COUNT, and AVG c. Queries involving complicated selects and joins d. Queries involving GROUP BY, HAVING or other similar functions. e. Queries that require the use of the DISTINCT keyword. And this the condition that we need to determine it to solve the required Q's above : 5) It is desired to develop an Internet membership club to buy products at special prices online. To join, new members must be referred by another existing member of the club. The system will keep the following information for each member: The member ID, referring member, birth date, member name, address, phone, mobile, credit card type, number and expiration date. The items are always shipped to the member's address noted in the membership application. The shipping fees will differ for each order.For each item to be requested, the member will select an item from a long list of possible items. For each item in the database, we store an item ID, an item name, description, and list price. The list price will be different from the actual sale price. The available quantity and the back-ordered quantity (the back-ordered quantity is the quantity on-order by the club from its suppliers) is also noted

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  • Set primary key with two integers

    - by user299196
    I have a table with primary key (ColumnA, ColumnB). I want to make a function or procedure that when passed two integers will insert a row into the table but make sure the largest integer always goes into ColumnA and the smaller one into ColumnB. So if we have SetKeysWithTheseNumbers(17, 19) would return |-----------------| |ColumnA | ColumnB| |-----------------| |19 | 17 | |-----------------| SetKeysWithTheseNumbers(19, 17) would return the same thing |-----------------| |ColumnA | ColumnB| |-----------------| |19 | 17 | |-----------------|

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