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  • List<> of objects, different types, sort and pull out types individually?

    - by Brazos
    I've got a handful of products, any, all, or none of which may be associated with a specific submission. All 7 products are subclasses of the class Product. I need to store all the products associated with a submission, and then retrieve them and their field data on my presentation layer. I've been using a List, and List, but when I use the OfType, I throw an error saying that I can't implicitly convert systems.generic.IEnumerable to type 'Product'. I've tried to cast, but to no avail. When I use prodlist.OfType<EPL>(); there are no errors, but when I try and store that in an instance of EPL "tempEpl", I get the aforementioned cast-related error. What gives? Code below. ProductService pserv = new ProductService(); IList<object> prodlist = pserv.getProductById(x); EPL tempEpl = new EPL(); if ((prodlist.OfType<EPL>()) != null) { tempEpl = prodlist.OfType<EPL>(); // this throws a conversion error. } the Data layer List<object> TempProdList = new List<object>(); conn.Open(); SqlCommand EplCmd = new SqlCommand(EPLQuery, conn); SqlDataReader EplRead = null; EplRead = EplCmd.ExecuteReader(); EPL TempEpl = new EPL(); if (EplRead.Read()) { TempEpl.Entity1 = EplRead.GetString(0); TempEpl.Employees1 = EplRead.GetInt32(1); TempEpl.CA1 = EplRead.GetInt32(2); TempEpl.MI1 = EplRead.GetInt32(3); TempEpl.NY1 = EplRead.GetInt32(4); TempEpl.NJ1 = EplRead.GetInt32(5); TempEpl.PrimEx1 = EplRead.GetInt32(6); TempEpl.EplLim1 = EplRead.GetInt32(7); TempEpl.EplSir1 = EplRead.GetInt32(8); TempEpl.Premium1 = EplRead.GetInt32(9); TempEpl.Wage1 = EplRead.GetInt32(10); TempEpl.Sublim1 = EplRead.GetInt32(11); TempProdList.Add(TempEpl); }

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  • How do I sort feeds returned from Google Reader?

    - by Ed Marty
    When I query Google Reader for the list of subscriptions for a user, it seems to be returned in a fixed order, no matter what the order is as shown at google.com/reader. (see http://www.google.com/reader/api/0/subscription/list for the list I'm talking about) Each subscription returns a 'sortid', which Google Reader uses when the user rearranges subscriptions, by sending back a concatenation of all sortids in the new order after rearranging is finished. However, that sortid never changes. So my question is this: How do I actually get the order the subscriptions are supposed to be in? I've been using http://code.google.com/p/pyrfeed/wiki/GoogleReaderAPI as a reference, but it is lacking in this department, and I haven't found anything anywhere else either.

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  • How to sort a list so that managers are always ahead of their subordinates (How do I do a topologica

    - by James Black
    I am working on a project using Groovy, and I would like to take an array of employees, so that no manager follows their subordinates in the array. The reason being that I need to add people to a database and I would prefer not to do it in two passes. So, I basically have: <employees> <employee> <employeeid>12</employeeid> <manager>3</manager> </employee> <employee> <employeeid>1</employeeid> <manager></manager> </employee> <employee> <employeeid>3</employeeid> <manager>1</manager> </employee> </employees> So, it should be sorted as such: employeeid = 1 employeeid = 3 employeeid = 12 The first person should have a null for managers. I am thinking about a binary tree representation, but I expect it will be very unbalanced, and I am not certain the best way to do this using Groovy properly. Is there a way to do this that isn't going to involve using nested loops?

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  • What sort of object is this and how to use it?

    - by Gary
    What would be the correct name for this type of array? There are 3 main sections and 4 sub-parts consisting of "issuedTime" "text" "url" and "validToTime", how do you start to convert this to an object? If there was only 1 main section, it would be fairly simple to do however with 3 main parts and no identification for each main section has me scratching my head as where to start. Any advise appreciated. [{ "issuedTime":"7:13pm Sunday 13 June 2010", "text":"\nAmended 7:10pm.\n\nText text and more text\n", "url":"\/folder\/fc\/name.png", "validToTime":"12:00am Monday 14 June 2010" },{ "issuedTime":"8:33pm Sunday 13 June 2010", "text":"\nText and more text.\n", "url":"\/folder\/fc\/name.png", "validToTime":"12:00pm Monday 14 June 2010" },{ "issuedTime":"10:40am Sunday 13 June 2010", "text":"\nAnd even more text.", "url":"\/folder\/fc\/name.png", "validToTime":"12:00am Tuesday 15 June 2010" } ]

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  • acts-as-taggable-on: find tags with name LIKE, sort by tag_counts?

    - by James
    Hi I'm using the rails plugin acts-as-taggable-onand I'm trying to find the top 5 most used tags whose names match and partially match a given query. When I do User.skill_counts.order('count DESC').limit(5).where('name LIKE ?', params[:query]) This return the following error: ActiveRecord::StatementInvalid: SQLite3::SQLException: ambiguous column name: name: SELECT tags.*, COUNT(*) AS count FROM "tags" INNER JOIN users ON users.id = taggings.taggable_id LEFT OUTER JOIN taggings ON tags.id = taggings.tag_id AND taggings.context = 'skills' WHERE (taggings.taggable_type = 'User') AND (taggings.taggable_id IN(SELECT users.id FROM "users")) AND (name LIKE 'asd') GROUP BY tags.id, tags.name HAVING COUNT(*) > 0 ORDER BY count DESC LIMIT 5 But when I do User.skill_counts.first.name this returns "alliteration" I'd appreciate any help on this matter.

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  • Is this a bad version of the Merge Sort algorithm?

    - by SebKom
    merge1(int low, int high, int S[], U[]) { int k = (high - low + 1)/2 for q (from low to high) U[q] = S[q] int j = low int p = low int i = low + k while (j <= low + k - 1) and (i <= high) do { if ( U[j] <= U[i] ) { S[p] := U[j] j := j+1 } else { S[p] := U[i] i := i+1 } p := p+1 } if (j <= low + k - 1) { for q from p to high do { S[q] := U[j] j := j+1 } } } merge_sort1(int low, int high, int S[], U[]) { if low < high { int k := (high - low + 1)/2 merge_sort1(low, low+k-1, S, U) merge_sort1(low+k, high, S, U) merge1(low, high, S, U) } } I am really sorry for the terrible formating, as you can tell I am not a regular visitor here. So, basically, this is on my lecture notes. I find it quite confusing in general but I understand the biggest part of it. What I don't understand is the need of the "if (j <= low + k - 1)" part. It looks like it checks if there are any elements "left" in the left part. Is that even possible when mergesorting?

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  • Possible to sort via two time stamps and display same row twice.

    - by jamiethompson90
    I'm looking at creating a time table solution. I have a task sheet that looks like Area 1 item 1 startTime endTime Area 1 item1 startTime endTime I wish to create a display where I can view what even is happening next, either endTime or startTime i.e. Newcastle reel 16:45 18:45 Newcastle reel2 17:45 19:45 would output Newcastle reel 16:45 Newcastle reel 17:45 Newcastle reel 18:45 Newcastle reel 19:45 More so, I would like to detect if the time is a startTime or an endTime would I have to enter two rows for each activity (time,area,item, start|end). I can make the interface to the creation of two rows. I just wondered if there was a better solution. Any input is appreciated, Thanks, Jamie

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  • How to properly sort MPTT hierarchy data into multidimensional array ?

    - by DiegoMax
    Helo there, im trying to figure out how to write a function that returns a multidimensional array, based on the data below: I know how to write the function using the "category_parent" value, but im just trying to write a function that can create a multidimensional array by JUST using the left and right keys. Any help greatly appreciated! array(71) { [0]=> array(9) { ["id"]=> string(1) "1" ["category_name"]=> string(6) "Rubros" ["category_parent"]=> string(1) "0" ["category_slug"]=> string(6) "rubros" ["category_image"]=> NULL ["category_totals"]=> NULL ["category_lft"]=> string(1) "1" ["category_rgt"]=> string(3) "142" } [1]=> array(9) { ["id"]=> string(4) "1000" ["category_name"]=> string(12) "Restaurantes" ["category_parent"]=> string(1) "1" ["category_slug"]=> string(12) "restaurantes" ["category_image"]=> string(16) "restaurantes.png" ["category_totals"]=> string(1) "1" ["category_lft"]=> string(1) "2" ["category_rgt"]=> string(2) "13" } [2]=> array(9) { ["id"]=> string(1) "3" ["category_name"]=> string(21) "Restaurantes de Campo" ["category_parent"]=> string(4) "1000" ["category_slug"]=> string(21) "restaurantes-de-campo" ["category_image"]=> NULL ["category_totals"]=> string(1) "1" ["category_lft"]=> string(1) "3" ["category_rgt"]=> string(1) "4" } [3]=> array(9) { ["id"]=> string(2) "37" ["category_name"]=> string(25) "Restaurantes en la Ciudad" ["category_parent"]=> string(4) "1000" ["category_slug"]=> string(19) "restaurantes-ciudad" ["category_image"]=> string(0) "" ["category_totals"]=> string(1) "6" ["category_lft"]=> string(1) "5" ["category_rgt"]=> string(1) "6" } [4]=> array(9) { ["id"]=> string(2) "41" ["category_name"]=> string(21) "Servicios de Catering" ["category_parent"]=> string(4) "1000" ["category_slug"]=> string(8) "catering" ["category_image"]=> string(0) "" ["category_totals"]=> string(1) "1" ["category_lft"]=> string(1) "7" ["category_rgt"]=> string(1) "8" } [5]=> array(9) { ["id"]=> string(2) "48" ["category_name"]=> string(10) "Rotiserias" ["category_parent"]=> string(4) "1000" ["category_slug"]=> string(10) "rotiserias" ["category_image"]=> string(0) "" ["category_totals"]=> string(1) "1" ["category_lft"]=> string(1) "9" ["category_rgt"]=> string(2) "10" } [6]=> array(9) { ["id"]=> string(2) "62" ["category_name"]=> string(10) "Pizzerías" ["category_parent"]=> string(4) "1000" ["category_slug"]=> string(9) "pizzerias" ["category_image"]=> string(0) "" ["category_totals"]=> string(1) "1" ["category_lft"]=> string(2) "11" ["category_rgt"]=> string(2) "12" } [7]=> array(9) { ["id"]=> string(1) "2" ["category_name"]=> string(13) "Profesionales" ["category_parent"]=> string(1) "1" ["category_slug"]=> string(13) "profesionales" ["category_image"]=> string(17) "profesionales.png" ["category_totals"]=> string(1) "2" ["category_lft"]=> string(2) "14" ["category_rgt"]=> string(2) "35" } [8]=> array(9) { ["id"]=> string(2) "29" ["category_name"]=> string(11) "Arquitectos" ["category_parent"]=> string(1) "2" ["category_slug"]=> string(11) "arquitectos" ["category_image"]=> NULL ["category_totals"]=> string(1) "0" ["category_lft"]=> string(2) "15" ["category_rgt"]=> string(2) "16" } [9]=> array(9) { ["id"]=> string(2) "30" ["category_name"]=> string(8) "Abogados" ["category_parent"]=> string(1) "2" ["category_slug"]=> string(8) "abogados" ["category_image"]=> NULL ["category_totals"]=> string(1) "6" ["category_lft"]=> string(2) "17" ["category_rgt"]=> string(2) "18" } }

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  • Is there a better way to do SELECT queries in MySQL and sort them in PHP than this way?

    - by Kent
    I am just learning PHP/MySQL, one this I am having to do a lot is displaying data that was previously inserted into the database out to the user's browser. So I am doing this: $select = mysql_query('SELECT * FROM pages'); while ($return = mysql_fetch_assoc($select)) { $title = $return['title']; $author = $return['author']; $content = $return['content']; } then I can use these variables through out the page. Now, doing it the above way isn't an issue when I only have 3 columns in a database but what if I am dealing with a huge database with many more columns. I have a nagging feeling that the pros do it in some more efficient way where they maybe loop through the table they are selecting from to find all columns it has and associate them with variables automatically. Is that the case? or is the above how you guys do it too?

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  • KnockoutJS showing a sorted list by item category

    - by Darksbane
    I just started learning knockout this week and everything has gone well except for this one issue. I have a list of items that I sort multiple ways but one of the ways I want to sort needs to have a different display than the standard list. As an example lets say I have this code var BetterListModel = function () { var self = this; food = [ { "name":"Apple", "quantity":"3", "category":"Fruit", "cost":"$1", },{ "name":"Ice Cream", "quantity":"1", "category":"Dairy", "cost":"$6", },{ "name":"Pear", "quantity":"2", "category":"Fruit", "cost":"$2", },{ "name":"Beef", "quantity":"1", "category":"Meat", "cost":"$3", },{ "name":"Milk", "quantity":"5", "category":"Dairy", "cost":"$4", }]; self.allItems = ko.observableArray(food); // Initial items // Initial sort self.sortMe = ko.observable("name"); ko.utils.compareItems = function (l, r) { if (self.sortMe() =="cost"){ return l.cost > r.cost ? 1 : -1 } else if (self.sortMe() =="category"){ return l.category > r.category ? 1 : -1 } else if (self.sortMe() =="quantity"){ return l.quantity > r.quantity ? 1 : -1 }else { return l.name > r.name ? 1 : -1 } }; }; ko.applyBindings(new BetterListModel()); and the HTML <p>Your values:</p> <ul class="deckContents" data-bind="foreach:allItems().sort(ko.utils.compareItems)"> <li><div style="width:100%"><div class="left" style="width:30px" data-bind="text:quantity"></div><div class="left fixedWidth" data-bind="text:name"></div> <div class="left fixedWidth" data-bind="text:cost"></div> <div class="left fixedWidth" data-bind="text:category"></div><div style="clear:both"></div></div></li> </ul> <select data-bind="value:sortMe"> <option selected="selected" value="name">Name</option> <option value="cost">Cost</option> <option value="category">Category</option> <option value="quantity">Quantity</option> </select> </div> So I can sort these just fine by any field I might sort them by name and it will display something like this 3 Apple $1 Fruit 1 Beef $3 Meat 1 Ice Cream $6 Dairy 5 Milk $4 Dairy 2 Pear $2 Fruit Here is a fiddle of what I have so far http://jsfiddle.net/Darksbane/X7KvB/ This display is fine for all the sorts except the category sort. What I want is when I sort them by category to display it like this Fruit 3 Apple $1 Fruit 2 Pear $2 Fruit Meat 1 Beef $3 Meat Dairy 1 Ice Cream $6 Dairy 5 Milk $4 Dairy Does anyone have any idea how I might be able to display this so differently for that one sort?

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  • Getting text after URL in asp.net / URL Rewriting (sort of!)

    - by alex
    My app is a very simple "one page" type app- It has Default.aspx I'm basically trying to get, for example: www.myappurl.com/this is my text I want to get hold of "this is my text" from the above example. This will be displayed on the page (for now) I didn't really want to have to use any complext url rewriting things for this... (My hosting provider uses IIS6) I tried using a 404 handler, but this is a bit long winded, and i'm using shared hosting, that can't set the "execute url" on custom 404 pages. Any other ideas?

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  • Trouble Upgrading Rails 2 Routes for a Redmine Plugin

    - by user1858628
    I am trying to get a Redmine plugin designed for Rails 2 to work with Rails 3. https://github.com/dalyons/redmine-todos-scrum-plugin I've pretty much fixed most parts, but having no success whatsoever in getting the routes to work. The original routes for Rails 2 are as follows: map.resources :todos, :name_prefix => 'project_', :path_prefix => '/projects/:project_id', :member => {:toggle_complete => :post }, :collection => {:sort => :post} map.resources :todos, :name_prefix => 'user_', :path_prefix => '/users/:user_id', :controller => :mytodos, :member => {:toggle_complete => :post }, :collection => {:sort => :post} map.my_todos 'my/todos', :controller => :mytodos, :action => :index map.connect 'projects/:project_id/todos/show/:id', :controller => "todos", :action => "show" rake routes outputs the following: sort_project_todos POST /projects/:project_id/todos/sort(.:format) {:controller=>"todos", :action=>"sort"} project_todos GET /projects/:project_id/todos(.:format) {:controller=>"todos", :action=>"index"} POST /projects/:project_id/todos(.:format) {:controller=>"todos", :action=>"create"} new_project_todo GET /projects/:project_id/todos/new(.:format) {:controller=>"todos", :action=>"new"} toggle_complete_project_todo POST /projects/:project_id/todos/:id/toggle_complete(.:format) {:controller=>"todos", :action=>"toggle_complete"} edit_project_todo GET /projects/:project_id/todos/:id/edit(.:format) {:controller=>"todos", :action=>"edit"} project_todo GET /projects/:project_id/todos/:id(.:format) {:controller=>"todos", :action=>"show"} PUT /projects/:project_id/todos/:id(.:format) {:controller=>"todos", :action=>"update"} DELETE /projects/:project_id/todos/:id(.:format) {:controller=>"todos", :action=>"destroy"} sort_user_todos POST /users/:user_id/todos/sort(.:format) {:controller=>"mytodos", :action=>"sort"} user_todos GET /users/:user_id/todos(.:format) {:controller=>"mytodos", :action=>"index"} POST /users/:user_id/todos(.:format) {:controller=>"mytodos", :action=>"create"} new_user_todo GET /users/:user_id/todos/new(.:format) {:controller=>"mytodos", :action=>"new"} toggle_complete_user_todo POST /users/:user_id/todos/:id/toggle_complete(.:format) {:controller=>"mytodos", :action=>"toggle_complete"} edit_user_todo GET /users/:user_id/todos/:id/edit(.:format) {:controller=>"mytodos", :action=>"edit"} user_todo GET /users/:user_id/todos/:id(.:format) {:controller=>"mytodos", :action=>"show"} PUT /users/:user_id/todos/:id(.:format) {:controller=>"mytodos", :action=>"update"} DELETE /users/:user_id/todos/:id(.:format) {:controller=>"mytodos", :action=>"destroy"} my_todos /my/todos {:controller=>"mytodos", :action=>"index"} /projects/:project_id/todos/show/:id {:controller=>"todos", :action=>"show"} The nearest I have got for Rails 3 is follows: scope '/projects/:project_id', :name_prefix => 'project_' do resources :todos, :controller => 'todos' do member do post :toggle_complete end collection do post :sort end end end scope '/users/:user_id', :name_prefix => 'user_' do resources :todos, :controller => 'mytodos' do member do post :toggle_complete end collection do post :sort end end end match 'my/todos' => 'mytodos#index', :as => :my_todos match 'projects/:project_id/todos/show/:id' => 'todos#show' rake routes outputs the following: toggle_complete_todo POST /projects/:project_id/todos/:id/toggle_complete(.:format) todos#toggle_complete {:name_prefix=>"project_"} sort_todos POST /projects/:project_id/todos/sort(.:format) todos#sort {:name_prefix=>"project_"} todos GET /projects/:project_id/todos(.:format) todos#index {:name_prefix=>"project_"} POST /projects/:project_id/todos(.:format) todos#create {:name_prefix=>"project_"} new_todo GET /projects/:project_id/todos/new(.:format) todos#new {:name_prefix=>"project_"} edit_todo GET /projects/:project_id/todos/:id/edit(.:format) todos#edit {:name_prefix=>"project_"} todo GET /projects/:project_id/todos/:id(.:format) todos#show {:name_prefix=>"project_"} PUT /projects/:project_id/todos/:id(.:format) todos#update {:name_prefix=>"project_"} DELETE /projects/:project_id/todos/:id(.:format) todos#destroy {:name_prefix=>"project_"} POST /users/:user_id/todos/:id/toggle_complete(.:format) mytodos#toggle_complete {:name_prefix=>"user_"} POST /users/:user_id/todos/sort(.:format) mytodos#sort {:name_prefix=>"user_"} GET /users/:user_id/todos(.:format) mytodos#index {:name_prefix=>"user_"} POST /users/:user_id/todos(.:format) mytodos#create {:name_prefix=>"user_"} GET /users/:user_id/todos/new(.:format) mytodos#new {:name_prefix=>"user_"} GET /users/:user_id/todos/:id/edit(.:format) mytodos#edit {:name_prefix=>"user_"} GET /users/:user_id/todos/:id(.:format) mytodos#show {:name_prefix=>"user_"} PUT /users/:user_id/todos/:id(.:format) mytodos#update {:name_prefix=>"user_"} DELETE /users/:user_id/todos/:id(.:format) mytodos#destroy {:name_prefix=>"user_"} my_todos /my/todos(.:format) mytodos#index /projects/:project_id/todos/show/:id(.:format) todos#show I am guessing that I am not using :name_prefix correctly, resulting in duplicate paths which are then omitted. Any help would be greatly appreciated.

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  • How can I set a default sort for tables in PHPMyAdmin (i.e. always "Primary key - Descending")

    - by jeremyclarke
    Even though its obnoxious in a lot of ways I use PHPMyAdmin all the time to debug database issues while writing PHP. By default it sorts tables by primary key ascending. 99% of the time I would rather have the newest data (my test data) shown at the top by default rather than the useless first few records ever saved. Is there a way to configure PHPMyAdmin to show the newest records by default? To alter similar behavior?

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  • How do I sort an activerecord result set on a i18n translated column?

    - by PlanetMaster
    Hi, I have the following line in a view: <%= f.select(:province_id, options_from_collection_for_select(Province.find(:all, :conditions => { :country_id => @property.country_id }, :order => "provinces.name ASC"), :id, :name) %> In the province model I have the following: def name I18n.t(super) end Problem is that the :name field is translated (through the province model) and that the ordering is done by activerecord on the english name. The non-english result set can be wrongly sorted this way. We have a province in Belgium called 'Oost-Vlaanderen'. In english that is 'East-Flanders". Not good for sorting:) I need something like this, but it does not work: <%= f.select(:province_id, options_from_collection_for_select(Province.find(:all, :conditions => { :country_id => @property.country_id }, :order => "provinces.I18n.t(name) ASC"), :id, :name) %> What would be the best approach to solve this? As you may have noticed, my coding knowledge is very limited, sorry for that.

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  • What sort of schema can I use to accommodate manual date based data entries?

    - by meder
    I have an admin where users from multiple properties can enter in monthly statistics for twitter/facebook followers. We do not have access to the real data/db so this is why a manual entry. The form looks like this: Type ( radio, select **one** only ): - Twitter - Facebook Followers/Fans ( textfield ): Property (dropdown): Hotel A, Hotel B Date Start: mm/dd/yyyy (textfield) Date End: mm/dd/yyyy (textfield) Question 1.1: Since I am only keeping track of month per month, the date start/end fields which I have already created might be too specific. Would it be a better idea just to have a start month/year and and month/year if that's the only thing I care about? Question 1.2: What schema could I use for month to month statistics if I were to change the date start and end textfields to start month/year and end month/year dropdowns?

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  • When the user first visits the page I want all the checkboxes to be checked in my index page. Below is the code from my controller and index.html.haml

    - by user1760920
    I want the checkbox to be checked when the user visits the page for the first time. -# This file is app/views/movies/index.html.haml %h1 All Movies = form_tag movies_path, :method => :get, :id => 'ratings_form' do Include: - @all_ratings.each do |rating| = rating = check_box_tag "ratings[#{rating}]", "1", @checked_ratings.include?(rating), :id => "ratings_#{rating}", = submit_tag 'Refresh', :id => 'ratings_submit' %table#movies %thead %tr %th{:class => ("hilite" if @sort == "title")}= link_to "Movie Title", movies_path( :sort => "title", :ratings => @checked_ratings), :id => "title_header" %th Rating %th{:class => ("hilite" if @sort == "release_date")}= link_to "Release Date", movies_path( :sort => "release_date", :ratings => @checked_ratings), :id => "release_date_header" %th More Info %tbody - @movies.each do |movie| %tr %td= movie.title %td= movie.rating %td= movie.release_date %td= link_to "More about #{movie.title}", movie_path(movie) = link_to 'Add new movie', new_movie_path #This is my Controller class MoviesController < ApplicationController def show id = params[:id] # retrieve movie ID from URI route @movie = Movie.find(id) # look up movie by unique ID # will render app/views/movies/show.<extension> by default end def index #get all the ratings available @all_ratings = Movie.all_ratings @checked_ratings = (params[:ratings].present? ? params[:ratings] : []) @sort = params[:sort] @movies = Movie.scoped if @sort && Movie.attribute_names.include?(@sort) @movies = @movies.order @sort end id @checked_ratings.empty? @checked_ratings = @all_ratings end unless @checked_ratings.empty? @movies = @movies.where :rating => @checked_ratings.keys end end def new # default: render 'new' template end def create @movie = Movie.create!(params[:movie]) flash[:notice] = "#{@movie.title} was successfully created." redirect_to movies_path end def edit @movie = Movie.find params[:id] end def update @movie = Movie.find params[:id] @movie.update_attributes!(params[:movie]) flash[:notice] = "#{@movie.title} was successfully updated." redirect_to movie_path(@movie) end def destroy @movie = Movie.find(params[:id]) @movie.destroy flash[:notice] = "Movie '#{@movie.title}' deleted." redirect_to movies_path end end In the controller, I set the @checked_rating to be @all_rating if the @checked.rating is empty but it does not do anything. I tried putting :checked = true in the index.html.haml on the check_box_tag but that makes the checkboxes checked everytime the page is refreshed. Everytime I check a particular checkbox and hit refresh button the page loads with all the checkboxes checked. Please help me with this. Thank you in Advance.

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  • Heaps of Trouble?

    - by Paul White NZ
    If you’re not already a regular reader of Brad Schulz’s blog, you’re missing out on some great material.  In his latest entry, he is tasked with optimizing a query run against tables that have no indexes at all.  The problem is, predictably, that performance is not very good.  The catch is that we are not allowed to create any indexes (or even new statistics) as part of our optimization efforts. In this post, I’m going to look at the problem from a slightly different angle, and present an alternative solution to the one Brad found.  Inevitably, there’s going to be some overlap between our entries, and while you don’t necessarily need to read Brad’s post before this one, I do strongly recommend that you read it at some stage; he covers some important points that I won’t cover again here. The Example We’ll use data from the AdventureWorks database, copied to temporary unindexed tables.  A script to create these structures is shown below: CREATE TABLE #Custs ( CustomerID INTEGER NOT NULL, TerritoryID INTEGER NULL, CustomerType NCHAR(1) COLLATE SQL_Latin1_General_CP1_CI_AI NOT NULL, ); GO CREATE TABLE #Prods ( ProductMainID INTEGER NOT NULL, ProductSubID INTEGER NOT NULL, ProductSubSubID INTEGER NOT NULL, Name NVARCHAR(50) COLLATE SQL_Latin1_General_CP1_CI_AI NOT NULL, ); GO CREATE TABLE #OrdHeader ( SalesOrderID INTEGER NOT NULL, OrderDate DATETIME NOT NULL, SalesOrderNumber NVARCHAR(25) COLLATE SQL_Latin1_General_CP1_CI_AI NOT NULL, CustomerID INTEGER NOT NULL, ); GO CREATE TABLE #OrdDetail ( SalesOrderID INTEGER NOT NULL, OrderQty SMALLINT NOT NULL, LineTotal NUMERIC(38,6) NOT NULL, ProductMainID INTEGER NOT NULL, ProductSubID INTEGER NOT NULL, ProductSubSubID INTEGER NOT NULL, ); GO INSERT #Custs ( CustomerID, TerritoryID, CustomerType ) SELECT C.CustomerID, C.TerritoryID, C.CustomerType FROM AdventureWorks.Sales.Customer C WITH (TABLOCK); GO INSERT #Prods ( ProductMainID, ProductSubID, ProductSubSubID, Name ) SELECT P.ProductID, P.ProductID, P.ProductID, P.Name FROM AdventureWorks.Production.Product P WITH (TABLOCK); GO INSERT #OrdHeader ( SalesOrderID, OrderDate, SalesOrderNumber, CustomerID ) SELECT H.SalesOrderID, H.OrderDate, H.SalesOrderNumber, H.CustomerID FROM AdventureWorks.Sales.SalesOrderHeader H WITH (TABLOCK); GO INSERT #OrdDetail ( SalesOrderID, OrderQty, LineTotal, ProductMainID, ProductSubID, ProductSubSubID ) SELECT D.SalesOrderID, D.OrderQty, D.LineTotal, D.ProductID, D.ProductID, D.ProductID FROM AdventureWorks.Sales.SalesOrderDetail D WITH (TABLOCK); The query itself is a simple join of the four tables: SELECT P.ProductMainID AS PID, P.Name, D.OrderQty, H.SalesOrderNumber, H.OrderDate, C.TerritoryID FROM #Prods P JOIN #OrdDetail D ON P.ProductMainID = D.ProductMainID AND P.ProductSubID = D.ProductSubID AND P.ProductSubSubID = D.ProductSubSubID JOIN #OrdHeader H ON D.SalesOrderID = H.SalesOrderID JOIN #Custs C ON H.CustomerID = C.CustomerID ORDER BY P.ProductMainID ASC OPTION (RECOMPILE, MAXDOP 1); Remember that these tables have no indexes at all, and only the single-column sampled statistics SQL Server automatically creates (assuming default settings).  The estimated query plan produced for the test query looks like this (click to enlarge): The Problem The problem here is one of cardinality estimation – the number of rows SQL Server expects to find at each step of the plan.  The lack of indexes and useful statistical information means that SQL Server does not have the information it needs to make a good estimate.  Every join in the plan shown above estimates that it will produce just a single row as output.  Brad covers the factors that lead to the low estimates in his post. In reality, the join between the #Prods and #OrdDetail tables will produce 121,317 rows.  It should not surprise you that this has rather dire consequences for the remainder of the query plan.  In particular, it makes a nonsense of the optimizer’s decision to use Nested Loops to join to the two remaining tables.  Instead of scanning the #OrdHeader and #Custs tables once (as it expected), it has to perform 121,317 full scans of each.  The query takes somewhere in the region of twenty minutes to run to completion on my development machine. A Solution At this point, you may be thinking the same thing I was: if we really are stuck with no indexes, the best we can do is to use hash joins everywhere. We can force the exclusive use of hash joins in several ways, the two most common being join and query hints.  A join hint means writing the query using the INNER HASH JOIN syntax; using a query hint involves adding OPTION (HASH JOIN) at the bottom of the query.  The difference is that using join hints also forces the order of the join, whereas the query hint gives the optimizer freedom to reorder the joins at its discretion. Adding the OPTION (HASH JOIN) hint results in this estimated plan: That produces the correct output in around seven seconds, which is quite an improvement!  As a purely practical matter, and given the rigid rules of the environment we find ourselves in, we might leave things there.  (We can improve the hashing solution a bit – I’ll come back to that later on). Faster Nested Loops It might surprise you to hear that we can beat the performance of the hash join solution shown above using nested loops joins exclusively, and without breaking the rules we have been set. The key to this part is to realize that a condition like (A = B) can be expressed as (A <= B) AND (A >= B).  Armed with this tremendous new insight, we can rewrite the join predicates like so: SELECT P.ProductMainID AS PID, P.Name, D.OrderQty, H.SalesOrderNumber, H.OrderDate, C.TerritoryID FROM #OrdDetail D JOIN #OrdHeader H ON D.SalesOrderID >= H.SalesOrderID AND D.SalesOrderID <= H.SalesOrderID JOIN #Custs C ON H.CustomerID >= C.CustomerID AND H.CustomerID <= C.CustomerID JOIN #Prods P ON P.ProductMainID >= D.ProductMainID AND P.ProductMainID <= D.ProductMainID AND P.ProductSubID = D.ProductSubID AND P.ProductSubSubID = D.ProductSubSubID ORDER BY D.ProductMainID OPTION (RECOMPILE, LOOP JOIN, MAXDOP 1, FORCE ORDER); I’ve also added LOOP JOIN and FORCE ORDER query hints to ensure that only nested loops joins are used, and that the tables are joined in the order they appear.  The new estimated execution plan is: This new query runs in under 2 seconds. Why Is It Faster? The main reason for the improvement is the appearance of the eager Index Spools, which are also known as index-on-the-fly spools.  If you read my Inside The Optimiser series you might be interested to know that the rule responsible is called JoinToIndexOnTheFly. An eager index spool consumes all rows from the table it sits above, and builds a index suitable for the join to seek on.  Taking the index spool above the #Custs table as an example, it reads all the CustomerID and TerritoryID values with a single scan of the table, and builds an index keyed on CustomerID.  The term ‘eager’ means that the spool consumes all of its input rows when it starts up.  The index is built in a work table in tempdb, has no associated statistics, and only exists until the query finishes executing. The result is that each unindexed table is only scanned once, and just for the columns necessary to build the temporary index.  From that point on, every execution of the inner side of the join is answered by a seek on the temporary index – not the base table. A second optimization is that the sort on ProductMainID (required by the ORDER BY clause) is performed early, on just the rows coming from the #OrdDetail table.  The optimizer has a good estimate for the number of rows it needs to sort at that stage – it is just the cardinality of the table itself.  The accuracy of the estimate there is important because it helps determine the memory grant given to the sort operation.  Nested loops join preserves the order of rows on its outer input, so sorting early is safe.  (Hash joins do not preserve order in this way, of course). The extra lazy spool on the #Prods branch is a further optimization that avoids executing the seek on the temporary index if the value being joined (the ‘outer reference’) hasn’t changed from the last row received on the outer input.  It takes advantage of the fact that rows are still sorted on ProductMainID, so if duplicates exist, they will arrive at the join operator one after the other. The optimizer is quite conservative about introducing index spools into a plan, because creating and dropping a temporary index is a relatively expensive operation.  It’s presence in a plan is often an indication that a useful index is missing. I want to stress that I rewrote the query in this way primarily as an educational exercise – I can’t imagine having to do something so horrible to a production system. Improving the Hash Join I promised I would return to the solution that uses hash joins.  You might be puzzled that SQL Server can create three new indexes (and perform all those nested loops iterations) faster than it can perform three hash joins.  The answer, again, is down to the poor information available to the optimizer.  Let’s look at the hash join plan again: Two of the hash joins have single-row estimates on their build inputs.  SQL Server fixes the amount of memory available for the hash table based on this cardinality estimate, so at run time the hash join very quickly runs out of memory. This results in the join spilling hash buckets to disk, and any rows from the probe input that hash to the spilled buckets also get written to disk.  The join process then continues, and may again run out of memory.  This is a recursive process, which may eventually result in SQL Server resorting to a bailout join algorithm, which is guaranteed to complete eventually, but may be very slow.  The data sizes in the example tables are not large enough to force a hash bailout, but it does result in multiple levels of hash recursion.  You can see this for yourself by tracing the Hash Warning event using the Profiler tool. The final sort in the plan also suffers from a similar problem: it receives very little memory and has to perform multiple sort passes, saving intermediate runs to disk (the Sort Warnings Profiler event can be used to confirm this).  Notice also that because hash joins don’t preserve sort order, the sort cannot be pushed down the plan toward the #OrdDetail table, as in the nested loops plan. Ok, so now we understand the problems, what can we do to fix it?  We can address the hash spilling by forcing a different order for the joins: SELECT P.ProductMainID AS PID, P.Name, D.OrderQty, H.SalesOrderNumber, H.OrderDate, C.TerritoryID FROM #Prods P JOIN #Custs C JOIN #OrdHeader H ON H.CustomerID = C.CustomerID JOIN #OrdDetail D ON D.SalesOrderID = H.SalesOrderID ON P.ProductMainID = D.ProductMainID AND P.ProductSubID = D.ProductSubID AND P.ProductSubSubID = D.ProductSubSubID ORDER BY D.ProductMainID OPTION (MAXDOP 1, HASH JOIN, FORCE ORDER); With this plan, each of the inputs to the hash joins has a good estimate, and no hash recursion occurs.  The final sort still suffers from the one-row estimate problem, and we get a single-pass sort warning as it writes rows to disk.  Even so, the query runs to completion in three or four seconds.  That’s around half the time of the previous hashing solution, but still not as fast as the nested loops trickery. Final Thoughts SQL Server’s optimizer makes cost-based decisions, so it is vital to provide it with accurate information.  We can’t really blame the performance problems highlighted here on anything other than the decision to use completely unindexed tables, and not to allow the creation of additional statistics. I should probably stress that the nested loops solution shown above is not one I would normally contemplate in the real world.  It’s there primarily for its educational and entertainment value.  I might perhaps use it to demonstrate to the sceptical that SQL Server itself is crying out for an index. Be sure to read Brad’s original post for more details.  My grateful thanks to him for granting permission to reuse some of his material. Paul White Email: [email protected] Twitter: @PaulWhiteNZ

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