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Search found 142 results on 6 pages for 'endian'.

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  • Does my AMD-based machine use little endian or big endian?

    - by Frank
    I'm going though a computers system course and I'm trying to establish, for sure, if my AMD based computer is a little endian machine? I believe it is because it would be Intel-compatible. Specifically, my processor is an AMD 64 Athlon x2. I understand that this can matter in C programming. I'm writing C programs and a method I'm using would be affected by this. I'm trying to figure out if I'd get the same results if I ran the program on an Intel based machine (assuming that is little endian machine). Finally, let me ask this: Would any and all machines capable of running Windows (XP, Vista, 2000, Server 2003, etc) and, say, Ubuntu Linux desktop be little endian? Thank You, Frank

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  • Converting float values from big endian to little endian

    - by Bobby
    Is it possible to convert floats from big to little endian? I have a value from a PowerPC(big endian)platform that I am send via TCP to a Windows process (little endian). This value is a float, but when I "memcpy" the value into a win32 float type and then call _byteswap_ulongon that value, I always get 0.0000? What am I doing wrong?

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  • How to Make Red zone Network settings to Endian OS

    - by Gash
    Please help me, Currently we have about 10 pc's sharing internet. and We have CISCO 800 series router that connect the ADSL, to the lan Segment it connect switch throw the switch all pc's are getting connecting. all user pc's having 192.168.3.--- range ips and gateway is 192.168.3.254 now i install the endian firewall to one PC, it must work as firewall,VPN & proxy i made green zone ip as 192.168.3.222 then how to give red zone IP? i know that is static IP but it cant be same range so please help me out to sort this without changing anything in router, if want i can change the internal IP sets instead of 3.-- 10.-- or something like that and also please state me at present i tried Endian firewall red and green zone cables are pluged in to network switch only please help me to overcome this its urgent

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  • Endian Destination NAT

    - by Ben Swinburne
    I have installed Endian Community Firewall 2.3 and am clearly misunderstanding/doing something wrong with it. I'm trying to create some destination NAT rules to allow incoming connections to various services within the network. Router - RED I/F - x.x.x.x Router - GREEN I/F - 192.168.11.253 ECF - RED I/F - 192.168.11.254/24 ECF - GREEN I/F - 192.168.12.254/24 Target server - 192.168.12.1 Please ignore the haphazard choice of subnets and addresses- I'm trying to quickly plop Endian into an existing network before a complete rework in 6-12 months so for now. Everything works except destination NAT, so outgoing connections are fine, the routes between the two subnets are OK etc. I want to create various incoming NATs but let's take for the sake of argument, SMTP port 25 from the Internet to Target server 192.168.12.1. I've tried almost every combination of options in the Destination NAT section to achieve this and clearly am doing something wrong. I suspect my confusion must be somewhere in the Access From and/or Target section. The rest seems OK Filter Policy = Allow Service = SMTP Protocol = TCP Port = 25 Translate to type = IP DNAT Policy = NAT Insert IP = 192.168.12.1 Port Range = 25 Enabled = Checked Position = First I can't work out what I'm doing wrong, or am I doing it right and it's just not working!? Any help would be greatly appreciated.

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  • Has Little Endian won?

    - by espertus
    When teaching recently about the Big vs. Little Endian battle, a student asked whether it had been settled, and I realized I didn't know. Looking at the Wikipedia article, it seems that the most popular current OS/architecture pairs use Little Endian but that Internet Protocol specifies Big Endian for transferring numeric values in packet headers. Would that be a good summary of the current status? Do current network cards or CPUs provide hardware support for switching byte order?

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  • Marshalling a big-endian byte collection into a struct in order to pull out values

    - by Pat
    There is an insightful question about reading a C/C++ data structure in C# from a byte array, but I cannot get the code to work for my collection of big-endian (network byte order) bytes. (EDIT: Note that my real struct has more than just one field.) Is there a way to marshal the bytes into a big-endian version of the structure and then pull out the values in the endianness of the framework (that of the host, which is usually little-endian)? This should summarize what I'm looking for (LE=LittleEndian, BE=BigEndian): void Main() { var leBytes = new byte[] {1, 0}; var beBytes = new byte[] {0, 1}; Foo fooLe = ByteArrayToStructure<Foo>(leBytes); Foo fooBe = ByteArrayToStructureBigEndian<Foo>(beBytes); Assert.AreEqual(fooLe, fooBe); } [StructLayout(LayoutKind.Explicit, Size=2)] public struct Foo { [FieldOffset(0)] public ushort firstUshort; } T ByteArrayToStructure<T>(byte[] bytes) where T: struct { GCHandle handle = GCHandle.Alloc(bytes, GCHandleType.Pinned); T stuff = (T)Marshal.PtrToStructure(handle.AddrOfPinnedObject(),typeof(T)); handle.Free(); return stuff; } T ByteArrayToStructureBigEndian<T>(byte[] bytes) where T: struct { ??? }

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  • CIL and JVM Little endian to big endian in c# and java

    - by Haythem
    Hello, I am using on the client C# where I am converting double values to byte array. I am using java on the server and I am using writeDouble and readDouble to convert double values to byte arrays. The problem is the double values from java at the end are not the double values at the begin giving to c# writeDouble in Java Converts the double argument to a long using the doubleToLongBits method , and then writes that long value to the underlying output stream as an 8-byte quantity, high byte first. DoubleToLongBits Returns a representation of the specified floating-point value according to the IEEE 754 floating-point "double format" bit layout. The Program on the server is waiting of 64-102-112-0-0-0-0-0 from C# to convert it to 1700.0 but he si becoming 0000014415464 from c# after c# converted 1700.0 this is my code in c#: class User { double workingStatus; public void persist() { byte[] dataByte; using (MemoryStream ms = new MemoryStream()) { using (BinaryWriter bw = new BinaryWriter(ms)) { bw.Write(workingStatus); bw.Flush(); bw.Close(); } dataByte = ms.ToArray(); for (int j = 0; j < dataByte.Length; j++) { Console.Write(dataByte[j]); } } public double WorkingStatus { get { return workingStatus; } set { workingStatus = value; } } } class Test { static void Main() { User user = new User(); user.WorkingStatus = 1700.0; user.persist(); } thank you for the help.

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  • Convert a raw string to an array of big-endian words with Ruby

    - by Zag zag..
    Hello, I would like to convert a raw string to an array of big-endian words. As example, here is a JavaScript function that do it well (by Paul Johnston): /* * Convert a raw string to an array of big-endian words * Characters >255 have their high-byte silently ignored. */ function rstr2binb(input) { var output = Array(input.length >> 2); for(var i = 0; i < output.length; i++) output[i] = 0; for(var i = 0; i < input.length * 8; i += 8) output[i>>5] |= (input.charCodeAt(i / 8) & 0xFF) << (24 - i % 32); return output; } I believe the Ruby equivalent can be String#unpack(format). However, I don't know what should be the correct format parameter. Thank you for any help. Regards

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  • Big and Little endian question

    - by Bobby
    I have the following code: // Incrementer datastores.cmtDatastores.u32Region[0] += 1; // Decrementer datastores.cmtDatastores.u32Region[1] = (datastores.cmtDatastores.u32Region[1] == 0) ? 10 : datastores.cmtDatastores.u32Region[1] - 1; // Toggler datastores.cmtDatastores.u32Region[2] = (datastores.cmtDatastores.u32Region[2] == 0x0000) ? 0xFFFF : 0x0000; The u32Region array is an unsigned int array that is part of a struct. Later in the code I convert this array to Big endian format: unsigned long *swapL = (unsigned long*)&datastores.cmtDatastores.u32Region[50]; for (int i=0;i<50;i++) { swapL[i] = _byteswap_ulong(swapL[i]); } This entire code snippet is part of a loop that repeats indefinitely. It is a contrived program that increments one element, decrements another and toggles a third element. The array is then sent via TCP to another machine that unpacks this data. The first loop works fine. After that, since the data is in big endian format, when I "increment", "decrement", and "toggle", the values are incorrect. Obviously, if in the first loop datastores.cmtDatastores.u32Region[0] += 1; results in 1, the second loop it should be 2, but it's not. It is adding the number 1(little endian) to the number in datastores.cmtDatastores.u32Region[0](big endian). I guess I have to revert back to little endian at the start of every loop, but it appears there should be an easier way to do this. Any thoughts? Thanks, Bobby

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  • IAR Embedded Workbench - setting endian-ness of variable

    - by Seidleroni
    I'm using IAR Embedded Workbench for ARM (ARM7TDMI-S) and the majority of my work is done using little-endian format. However, I saw in the manual that I can do something like : __big_endian int i, j; to declare those two variables as big endian (while the rest of the app as little endian). This seems like a fantastic feature, but when I try to compile, I always get the errror: Error[Pa002]: the type attribute "__big_endian" is not allowed on this declaration. The big endian line above is copied directly from the manual, but it does not work. This is a great feature of the compiler and would make life a big easier. Any ideas how to get it working? I have my language conformance set to 'Allow IAR extensions' on the C/C++ Compiler options tab on the IDE options.

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  • MIPS assembly: big and little endian confusion

    - by Barney
    I've run the following code snippet on the MIPS MARS simulator. That simulator is little endian. So the results are as follows: lui $t0,0x1DE # $t0 = 0x01DE0000 ori $t0,$t0,0xCADE # $t0 = 0x01DECADE lui $t1,0x1001 # $t1 = 0x10010000 sw $t0,200($t1) # $t1 + 200 bytes = 0x01DECADE lw $t2,200($t1) # $t2 = 0x01DECADE So on a little endian MIPS simulator, the value of $t2 at the end of the program is 0x01DECADE. If this simulator was big endian, what would the value be? Would it be 0xDECADE01 or would it still be 0x01DECADE?

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  • Endian check in C

    - by webgenius
    Got this code snippet from some website: int num = 1; if(*(char *)&num == 1) { printf("\nLittle-Endian\n"); } else { printf("Big-Endian\n"); } Can anyone explain this step-by-step? &num - Adress of a (char *)&num - Type-cast address of a into a string *(char *)&num - Points to the first character of the string Am I missing anything here?

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  • Byte order (endian) of int in NSLog?

    - by Eonil
    NSLog function accepts printf format specifiers. My question is about %x specifier. Does this print hex codes as sequence on memory? Or does it have it's own printing sequence style? unsigned int a = 0x000000FF; NSLog(@"%x", a); Results of above code on little or big endian processors are equal or different? And how about NSString's -initWithFormat method? Does it follows this rule equally?

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  • how to convert big-endian numbers to native numbers delphi

    - by steve0
    hi all i want to know how to convert big endian numbers to native numbers in delphi i am porting some c++ code in that i came accross this part unsigned long blockLength = *blockLengthPtr++ << 24; blockLength |= *blockLengthPtr++ << 16; blockLength |= *blockLengthPtr++ << 8; blockLength |= *blockLengthPtr; unsigned long dataLength = *dataLengthPtr++ << 24; dataLength |= *dataLengthPtr++ << 16; dataLength |= *dataLengthPtr++ << 8; dataLength |= *dataLengthPtr; i am not familiar with c++ ,so i didnt understand what those operators doing can any one help ? regards

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  • Boost Binary Endian parser not working?

    - by Hai
    I am studying how to use boost spirit Qi binary endian parser. I write a small test parser program according to here and basics examples, but it doesn't work proper. It gave me the msg:"Error:no match". Here is my code. #include "boost/spirit/include/qi.hpp" #include "boost/spirit/include/phoenix_core.hpp" #include "boost/spirit/include/phoenix_operator.hpp" #include "boost/spirit/include/qi_binary.hpp" // parsing binary data in various endianness template '<'typename P, typename T void binary_parser( char const* input, P const& endian_word_type, T& voxel, bool full_match = true) { using boost::spirit::qi::parse; char const* f(input); char const* l(f + strlen(f)); bool result1 = parse(f,l,endian_word_type,voxel); bool result2 =((!full_match) || (f ==l)); if ( result1 && result2) { //doing nothing, parsing data is pass to voxel alreay } else { std::cerr << "Error: not match!!" << std::endl; exit(1); } } typedef boost::uint16_t bs_int16; typedef boost::uint32_t bs_int32; int main ( int argc, char *argv[] ) { namespace qi = boost::spirit::qi; namespace ascii = boost::spirit::ascii; using qi::big_word; using qi::big_dword; boost::uint32_t ui; float uf; binary_parser("\x01\x02\x03\x04",big_word,ui); assert(ui=0x01020304); binary_parser("\x01\x02\x03\x04",big_word,uf); assert(uf=0x01020304); return 0; }' I almost copy the example, but why this binary parser doesn't work. I use Mac OS 10.5.8 and gcc 4.01 compiler.

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  • receive string with chars

    - by Meloun
    Hi all, i am quite new in python. I am receiving (through pyserial) string with data values. How can I parse these data to particular data structure? I know that 0-1 byte : id 2-5 byte : time1 =>but little endian (lsb first) 6-9 byte : time2 =>but little endian (lsb first) and I looking for a function: def parse_data(string): data={} data['id'] = ?? data['time1'] = ?? data['time2'] = ?? return data thanks

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  • Difference between C# and java big endian bytes using miscutil

    - by Eric Hauser
    I'm using the miscutil library to communicate between and Java and C# application using a socket. I am trying to figure out the difference between the following code (this is Groovy, but the Java result is the same): import java.io.* def baos = new ByteArrayOutputStream(); def stream = new DataOutputStream(baos); stream.writeInt(5000) baos.toByteArray().each { println it } /* outputs - 0, 0, 19, -120 */ and C#: using (var ms = new MemoryStream()) using (EndianBinaryWriter writer = new EndianBinaryWriter(EndianBitConverter.Big, ms, Encoding.UTF8)) { writer.Write(5000); ms.Position = 0; foreach (byte bb in ms.ToArray()) { Console.WriteLine(bb); } } /* outputs - 0, 0, 19, 136 */ As you can see, the last byte is -120 in the Java version and 136 in C#.

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  • How to transform phrases and words into MD5 hash?

    - by brilliant
    Can anyone, please, explain to me how to transform a phrase like "I want to buy some milk" into MD5? I read Wikipedia article on MD5, but the explanation given there is beyond my comprehension: "MD5 processes a variable-length message into a fixed-length output of 128 bits. The input message is broken up into chunks of 512-bit blocks (sixteen 32-bit little endian integers)" "sixteen 32-bit little endian integers" is already hard for me. I checked the article on little endians and didn't understand a bit. However, the examples of some phrases and their MD5 hashes are very nice: MD5("The quick brown fox jumps over the lazy dog") = 9e107d9d372bb6826bd81d3542a419d6 MD5("The quick brown fox jumps over the lazy dog.") = e4d909c290d0fb1ca068ffaddf22cbd0 Can anyone, please, explain to me how this MD5 algorithm works on some very simple example? And also, perhaps you know some software or a code that would transform phrases into their MD5. If yes, please, let me know.

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  • Swap bits in c++ for a double

    - by hidayat
    Im trying to change from big endian to little endian on a double. One way to go is to use double val, tmp = 5.55; ((unsigned int *)&val)[0] = ntohl(((unsigned int *)&tmp)[1]); ((unsigned int *)&val)[1] = ntohl(((unsigned int *)&tmp)[0]); But then I get a warning: "dereferencing type-punned pointer will break strict-aliasing rules" and I dont want to turn this warning off. Another way to go is: #define ntohll(x) ( ( (uint64_t)(ntohl( (uint32_t)((x << 32) >> 32) )) << 32) | ntohl( ((uint32_t)(x >> 32)) ) ) val = (double)bswap_64(unsigned long long(tmp)); //or val = (double)ntohll(unsigned long long(tmp)); But then a lose the decimals. Anyone know a good way to swap the bits on a double without using a for loop?

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