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  • How to solve 404 for static files with Django and Nginx?

    - by Lucio
    I setup a Trusty VM with Django + Nginx (other stuffs too). The server is working, I get the "Welcome to Django" page. But when I enter to servername/admin it loads the HTML page but fails to load the static content. And the admin page have this links to static content: <link rel="stylesheet" type="text/css" href="/static/admin/css/base.css" /> <link rel="stylesheet" type="text/css" href="/static/admin/css/login.css" /> Both of the CSS files give me 404, as the Nginx log shows: 192.168.56.1 - - [05/Jun/2014:12:04:09 -0300] "GET /admin HTTP/1.1" 301 5 "-" "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:29.0) Gecko/20100101 Firefox/29.0" 192.168.56.1 - - [05/Jun/2014:12:04:09 -0300] "GET /admin/ HTTP/1.1" 200 833 "-" "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:29.0) Gecko/20100101 Firefox/29.0" 192.168.56.1 - - [05/Jun/2014:12:04:10 -0300] "GET /static/admin/css/base.css HTTP/1.1" 404 142 "http://ubuntu-server/admin/" "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:29.0) Gecko/20100101 Firefox/29.0" 192.168.56.1 - - [05/Jun/2014:12:04:10 -0300] "GET /static/admin/css/login.css HTTP/1.1" 404 142 "http://ubuntu-server/admin/" "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:29.0) Gecko/20100101 Firefox/29.0" I think that the error is on my nginx.conf file, but do not know how to solve it.

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  • Trouble getting SSL to work with django + nginx + wsgi

    - by Kevin
    I've followed a couple of examples for Django + nginx + wsgi + ssl, but I can't get them to work. I simply get an error in my browser than I can't connect. I'm running two websites off the host. The config files are identical except for the ip addresses, server names, and directories. When neither use SSL, they work fine. When I try to listen on 443 with one of them, I can't connect to either. My config files are below, and any suggestions would be appreciated. server{ listen xxx.xxx.xxx.xxx:80; server_name sub.domain.com; access_log /home/django/logs/nginx_customerdb_http_access.log; error_log /home/django/logs/nginx_customerdb_http_error.log; location / { proxy_pass http://127.0.0.1:8080; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffers 32 4k; } location /site_media/ { alias /home/django/customerdb_site_media/; } location /admin-media/ { alias /home/django/django_admin_media/; } } server{ listen xxx.xxx.xxx.xxx:443; server_name sub.domain.com; access_log /home/django/logs/nginx_customerdb_http_access.log; error_log /home/django/logs/nginx_customerdb_http_error.log; ssl on; ssl_certificate sub.domain.com.crt; ssl_certificate_key sub.domain.com.key; ssl_prefer_server_ciphers on; location / { proxy_pass http://127.0.0.1:8080; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_set_header X-Forwarded-Protocol https; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffers 32 4k; } location /site_media/ { alias /home/django/customerdb_site_media/; } location /admin-media/ { alias /home/django/django_admin_media/; } } <VirtualHost *:8080> ServerName xxx.xxx.xxx.xxx ServerAlias xxx.xxx.xxx.xxx LogLevel warn ErrorLog /home/django/logs/apache_customerdb_error.log CustomLog /home/django/logs/apache_customerdb_access.log combined WSGIScriptAlias / /home/django/customerdb/apache/django.wsgi WSGIDaemonProcess customerdb_wsgi processes=4 threads=5 WSGIProcessGroup customerdb_wsgi SetEnvIf X-Forwarded-Protocol "^https$" HTTPS=on </VirtualHost> UDPATE: the existence of two sites (on separate IPs) on the host is the issue. if i delete the other site, the setting above mostly work. doing so also brings up another issue: chrome doesn't accept the site as secure saying that some content is not encrypted.

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  • Django | Apache | Deploy website behind SSL

    - by planet260
    So here are my requirements. I have a website built in Django. I deployed it on Apache Ubuntu. Before there was no SSL involved so the deployment was pretty simple. But now the requirements are changed. Now I have to take a few actions like signup and login behind SSL and present the admin panel and other normally via HTTP. By following the this tutorial I have set-up Apache and SSL and generated certificates for SSL communication. But I am not sure how to proceed, ie. how to serve only a few of my actions through SSL. Below is my configuration. The normal actions are working fine but I don't know how to configure SSL calls. WSGIScriptAlias / /home/ubuntu/myproject/src/myproject/wsgi.py WSGIPythonPath /home/ubuntu/myproject/src <VirtualHost *:80> ServerName mydomain.com <Directory /home/ubuntu/myproject/src/myproject> <Files wsgi.py> order deny,allow Allow from all </Files> </Directory> Alias /static/admin/ "/home/ubuntu/myproject/src/static/admin/" <Directory "/home/ubuntu/myproject/src/static/admin/"> Order allow,deny Options Indexes Allow from all IndexOptions FancyIndexing </Directory> <Location "/login"> RewriteEngine on RewriteRule /admin(.*)$ https://mydomain.com/login$1 [L,R=301] </Location> </VirtualHost> <VirtualHost *:443> ServerName mydomain.com SSLEngine on SSLOptions +StrictRequire SSLCertificateFile /etc/apache2/ssl/apache.crt SSLCertificateKeyFile /etc/apache2/ssl/apache.key <Directory /home/ubuntu/myproject/src/myproject> <Files wsgi.py> order deny,allow Allow from all </Files> </Directory> Alias /static/admin/ "/home/ubuntu/myproject/src/static/admin/" <Directory "/home/ubuntu/myproject/src/static/admin/"> Order allow,deny Options Indexes Allow from all IndexOptions FancyIndexing </Directory> </VirtualHost> Can you please help me out on how to achieve this? What am I doing wrong? I have read a lot of tutorials but honestly I am not really good at configurations. Any help is appreciated.

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  • Can't get python.manage.py syncdb to work

    - by Diego
    I just created my first django app, initialized variables DATABASE_ENGINE and DATABASE_NAME in settings.py, but now when I run python manage.py syncdb, I get the following error Can somebody help? Does this have to do with having two python versions installed? I'm a django/python noob, please help. thanks!! my-computer:~/Django-1.1.1 mycomp$ python manage.py syncdb /Library/Frameworks/Python.framework/Versions/2.6/Resources/Python.app/Contents/MacOS/Python: can't open file 'manage.py': [Errno 2] No such file or directory my-computer:~/Django-1.1.1 mycomp$ export PATH=/Users/mycomp/bin:$PATH

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  • How to serve static files for multiple Django projects via nginx to same domain

    - by thanley
    I am trying to setup my nginx conf so that I can serve the relevant files for my multiple Django projects. Ultimately I want each app to be available at www.example.com/app1, www.example.com/app2 etc. They all serve static files from a 'static-files' directory located in their respective project root. The project structure: Home Ubuntu Web www.example.com ref logs app app1 app1 static bower_components templatetags app1_project templates static-files app2 app2 static templates templatetags app2_project static-files app3 tests templates static-files static app3_project app3 venv When I use the conf below, there are no problems for serving the static-files for the app that I designate in the /static/ location. I can also access the different apps found at their locations. However, I cannot figure out how to serve all of the static files for all the apps at the same time. I have looked into using the 'try_files' command for the static location, but cannot figure out how to see if it is working or not. Nginx Conf - Only serving static files for one app: server { listen 80; server_name example.com; server_name www.example.com; access_log /home/ubuntu/web/www.example.com/logs/access.log; error_log /home/ubuntu/web/www.example.com/logs/error.log; root /home/ubuntu/web/www.example.com/; location /static/ { alias /home/ubuntu/web/www.example.com/app/app1/static-files/; } location /media/ { alias /home/ubuntu/web/www.example.com/media/; } location /app1/ { include uwsgi_params; uwsgi_param SCRIPT_NAME /app1; uwsgi_modifier1 30; uwsgi_pass unix:///home/ubuntu/web/www.example.com/app1.sock; } location /app2/ { include uwsgi_params; uwsgi_param SCRIPT_NAME /app2; uwsgi_modifier1 30; uwsgi_pass unix:///home/ubuntu/web/www.example.com/app2.sock; } location /app3/ { include uwsgi_params; uwsgi_param SCRIPT_NAME /app3; uwsgi_modifier1 30; uwsgi_pass unix:///home/ubuntu/web/www.example.com/app3.sock; } # what to serve if upstream is not available or crashes error_page 400 /static/400.html; error_page 403 /static/403.html; error_page 404 /static/404.html; error_page 500 502 503 504 /static/500.html; # Compression gzip on; gzip_http_version 1.0; gzip_comp_level 5; gzip_proxied any; gzip_min_length 1100; gzip_buffers 16 8k; gzip_types text/plain text/css application/x-javascript text/xml application/xml application/xml+rss text/javascript; # Some version of IE 6 don't handle compression well on some mime-types, # so just disable for them gzip_disable "MSIE [1-6].(?!.*SV1)"; # Set a vary header so downstream proxies don't send cached gzipped # content to IE6 gzip_vary on; } Essentially I want to have something like (I know this won't work) location /static/ { alias /home/ubuntu/web/www.example.com/app/app1/static-files/; alias /home/ubuntu/web/www.example.com/app/app2/static-files/; alias /home/ubuntu/web/www.example.com/app/app3/static-files/; } or (where it can serve the static files based on the uri) location /static/ { try_files $uri $uri/ =404; } So basically, if I use try_files like above, is the problem in my project directory structure? Or am I totally off base on this and I need to put each app in a subdomain instead of going this route? Thanks for any suggestions TLDR: I want to go to: www.example.com/APP_NAME_HERE And have nginx serve the static location: /home/ubuntu/web/www.example.com/app/APP_NAME_HERE/static-files/;

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  • Looking for a good example usage of get_or _create in Django views and raising a Form error

    - by Rik Wade
    I am looking for a good example of how to achieve the following: I would like to use get_or_create to check whether an object already exists in my database. If it does not, then it will be created. If it does exist, then I will not create the new object, but need to raise a form error to inform the user that they need to enter different data (for example, a different username). The view contains: p, created = Person.objects.get_or_create( email = registration_form.cleaned_data['email'], defaults = { 'creationDate': datetime.datetime.now(), 'dateOfBirth': datetime.date(1970,1,1) }) So 'p' will contain the existing Person if it exists, or the new Person if not. I would like to act on the boolean value in 'created' in order to skip over saving the Person and re-display the registration_form and raise an appropriate form validation error. The alternative I'm considering is doing a check in a custom Form validation method to see whether a Person exists with the data in the provided 'email' field, and just raising a validation error.

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  • Django QuerySet API: How do I join iexact and icontains?

    - by Zeynel
    Hello, I have this join: lawyers = Lawyer.objects.filter(last__iexact=last_name).filter(first__icontains=first_name) This is the site If you try Last Name: Abbas and First Name: Amr it tells you that amr abbas has 1 schoolmates. But if you try First name only it says that there are no lawyers in the database called amr (obviously there is). If I change (last__iexact=last_name) to (last__icontains=last_name) then leaving Last Name blank works fine and amr is found. But with last__icontains=last_name if you search for "collin" you also get "collins" and "collingwood" which is not what I want. Do you know how I can use iexact and also have it ignored if it is blank? Thanks This is the view function: def search_form(request): if request.method == 'POST': search_form = SearchForm(request.POST) if search_form.is_valid(): last_name = search_form.cleaned_data['last_name'] first_name = search_form.cleaned_data['first_name'] lawyers = Lawyer.objects.filter(last__iexact=last_name).filter(first__icontains=first_name) if len(lawyers)==0: form = SearchForm() return render_to_response('not_in_database.html', {'last': last_name, 'first': first_name, 'form': form}) if len(lawyers)>1: form = SearchForm(initial={'last_name': last_name}) return render_to_response('more_than_1_match.html', {'lawyers': lawyers, 'last': last_name, 'first': first_name, 'form': form}) q_school = Lawyer.objects.filter(last__icontains=last_name).filter(first__icontains=first_name).values_list('school', flat=True) q_year = Lawyer.objects.filter(last__icontains=last_name).filter(first__icontains=first_name).values_list('year_graduated', flat=True) lawyers1 = Lawyer.objects.filter(school__iexact=q_school[0]).filter(year_graduated__icontains=q_year[0]).exclude(last__icontains=last_name) form = SearchForm() return render_to_response('search_results.html', {'lawyers': lawyers1, 'last': last_name, 'first': first_name, 'form': form}) else: form = SearchForm() return render_to_response('search_form.html', {'form': form, })

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  • Is there a Django template tag that lets me set a context variable?

    - by hekevintran
    I want to be able to set variables in a template to string values. I wrote a tag, but it doesn't seem to change the context. The intended use is: {% define my_var as "a string" %} class DefineNode(Node): def __init__(self, value, variable_name, nodelist): self.value = value self.variable_name = variable_name self.nodelist = nodelist def __repr__(self): return "<DefineNode>" def render(self, context): context[self.variable_name] = self.value return '' @register.tag def define(parser, token): bits = list(token.split_contents()) if len(bits) != 4: raise TemplateSyntaxError("%r expected format is 'value as variable'" % bits[0]) if bits[1][0] in ('"', "'") and bits[1][-1] == bits[1][0]: value = bits[1][1:-1] nodelist = parser.parse(('enddefine',)) parser.delete_first_token() return DefineNode(value, bits[3], nodelist) I

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  • Display a boolean model field in a django form as a radio button rather than the default Checkbox.

    - by Lakshman Prasad
    This is how I went about, to display a Boolean model field in the form as Radio buttons Yes and No. choices = ( (1,'Yes'), (0,'No'), ) class EmailEditForm(forms.ModelForm): #Display radio buttons instead of checkboxes to_send_form = forms.ChoiceField(choices=choices,widget=forms.RadioSelect) class Meta: model = EmailParticipant fields = ('to_send_email','to_send_form') def clean(self): """ A workaround as the cleaned_data seems to contain u'1' and u'0'. There may be a better way. """ self.cleaned_data['to_send_form'] = int(self.cleaned_data['to_send_form']) return self.cleaned_data As you can see in the code above, I need a clean method that converts input string to an integer, which may be unnecessary. Is there a better and/or djangoic way to do this. If so, how? And no, using BooleanField seems to cause a lot more problems. Using that seemed obvious to me; but it isn't. Why is it so.

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  • Django: How can I delete a formset entry if one of it's data is blank?

    - by mkret
    Hi, I have the following scenario: I have a form with data that does not need translation and a formset with a textfield that should be translated into an undefined amount of languages. Both parts are bound to a model. Each translated text is kept in a model with a foreign key that binds it to the untranslatable data. Something like: class Person(models.Model): name = models.CharField(max_length=60) birth_date = models.DateField() class PersonBio(models.Model): person = models.ForeignKey(Person) locale = models.CharField(max_length=10) bio = models.TextField() Each form in the formset has 2 fields: A textfield (with the translated text) A locale field (with the language into which the text was translated) I've got it working with no problems until I tryed to change it's normal behaviour. I wanted to eliminate the need for the DELETE field by deleting an instance of the translated text if the textfield was left blank. I've googled quite a lot now and read the whole documentation for forms, formsets and model validation but had no luck. To be honest, I couldn't even think of a solution. Where should I implement this? On a Form clean() method? On the view? Somewhere in the Fieldset? Fieldset's save() method, maybe? I'll keep trying to find a way to do that, but any help/tip/clue is appreciated. Thanks in advance.

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  • Sorting and indexing into a list in a Django template?

    - by slypete
    How can you perform complex sorting on an object before passing it to the template? For example, here is my view: @login_required def overview(request): physicians = PhysicianGroup.objects.get(pk=physician_group).physicians for physician in physicians.all(): physician.service_patients.order_by('bed__room__unit', 'bed__room__order', 'bed__order') return render_to_response('hospitalists/overview.html', RequestContext(request, {'physicians': physicians,})) The physicians object is not ordered correctly in the template. Why not? Additionally, how do you index into a list inside the template? For example, (this doesn't work): {% for note_type in note_types %} <div><h3>{{ note_type }}</h3> {% for notes in note_sets.index(parent.forloop.counter0) %} #only want to display the notes of this note_type! {% for note in notes %} <p>{{ note }}</p> {% endfor %} {% endfor %} </div> {% endfor %}

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  • Can I filter a django model with a python list?

    - by Rhubarb
    Say I have a model object 'Person' defined, which has a field called 'Name'. And I have a list of people: l = ['Bob','Dave','Jane'] I would like to return a list of all Person records where the first name is not in the list of names defined in l. What is the most pythonic way of doing this?

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  • How do I memoize expensive calculations on Django model objects?

    - by David Eyk
    I have several TextField columns on my UserProfile object which contain JSON objects. I've also defined a setter/getter property for each column which encapsulates the logic for serializing and deserializing the JSON into python datastructures. The nature of this data ensures that it will be accessed many times by view and template logic within a single Request. To save on deserialization costs, I would like to memoize the python datastructures on read, invalidating on direct write to the property or save signal from the model object. Where/How do I store the memo? I'm nervous about using instance variables, as I don't understand the magic behind how any particular UserProfile is instantiated by a query. Is __init__ safe to use, or do I need to check the existence of the memo attribute via hasattr() at each read? Here's an example of my current implementation: class UserProfile(Model): text_json = models.TextField(default=text_defaults) @property def text(self): if not hasattr(self, "text_memo"): self.text_memo = None self.text_memo = self.text_memo or simplejson.loads(self.text_json) return self.text_memo @text.setter def text(self, value=None): self.text_memo = None self.text_json = simplejson.dumps(value)

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  • How do I flag only one of the formsets in django admin ?

    - by azuer88
    I have these (simplified) models: class Question(models.Model): question = models.CharField(max_length=60) class Choices(models.Model): question = models.ForeignKey(Question) text = models.CharField(max_length=60) is_correct = models.BooleanField(default=False) I've made Choices as an inline of Question (in admin). Is there a way to make sure that only one Choice will have is_correct = True? Ideally, is_correct will be displayed as a radio button when it is displayed in the admin formset (TabularInline). My first solution was to override the validation of the formset but did understand how to do this. (is_correct is displayed as checkbox, and I'd display an error that only one is_correct should be selected.)

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  • How do I modify the HttpResponse object in django ?

    - by Rohit
    I need the html returned using render_to_response to be escaped. I am unable to find any suitable documentation. Can someone point in some direction ? the code is : return render_to_response(template_name, {return render_to_response(template_name, { 'form': form, redirect_field_name: redirect_to, 'site': current_site, 'site_name': current_site.name, }, context_instance=RequestContext(request)) Here I need the response html text to be escaped. I way I know is reading template file in string and escaping it with re.escape() and then rendering it. whats a cleaner and simpler way to do that ??

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  • Django, Redirecting staff from login to the admin site.

    - by Francisco Gomez
    So my site basically has 2 kinds of ways to login, one of them is for the common users, who get the regular screen that asks them for username and password, the other way its for staff. The staff login should redirect them to the admin site after logging in, but for some reason the redirect doesnt happen, it stays on the same login page. I use this condition on the login view. if user is not None and user.is_active and user.is_staff: auth.login(request,user) return HttpResponseRedirect("/admin/") The admin site its up and running in my url configuration and everything, but i dont know if this is the correct way to redirect to the admin site already on session. Thanks, any help would be appreciated.

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  • Django: How to iterate over formsets and access cleaned data?

    - by Mark
    What if I want to do something with my formset other than immediately saving it? How can I do this? for form in vehicles_formset.forms: listing.id = None listing.vehicle_year = form.cleaned_data['year'] listing.vehicle_make = form.cleaned_data['make'] listing.vehicle_model = form.cleaned_data['model'] listing.vin = form.cleaned_data['vin'] listing.vehicle_runs = form.cleaned_data['runs'] listing.vehicle_convertible = form.cleaned_data['convertible'] listing.vehicle_modified = form.cleaned_data['modified'] listing.save() (Thus creating multiple listings) Apparently cleaned_data does not exist. There's a bunch of stuff in the data dict like form-0-year but it's pretty useless to me like that.

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  • How to preprocess a Django model field value before return?

    - by Satoru.Logic
    Hi, all. I have a Note model class like this: class Note(models.Model): author = models.ForeignKey(User, related_name='notes') content = NoteContentField(max_length=256) NoteContentField is a custom sub-class of CharField that override the to_python method in purpose of doing some twitter-text-conversion processing. class NoteContentField(models.CharField): __metaclass__ = models.SubfieldBase def to_python(self, value): value = super(NoteContentField, self).to_python(value) from ..utils import linkify return mark_safe(linkify(value)) However, this doesn't work. When I save a Note object like this: note = Note(author=request.use, content=form.cleaned_data['content']) The conversed value is saved into the database, which is not what I wanna see. Would you please tell me what's wrong with this? Thanks in advance.

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  • How to extend models of other applications in Django?

    - by culebrón
    I have a small app with Category model and want to make a required foreign key referencing it from Photologue Gallery model. What's the right approach? I can make many-to-many field in Category, but this way it will not be required in Gallery. Use "register" and modify the Gallery model? Inherit it in my app?

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  • Django Querysets -- need a less expensive way to do this..

    - by rh0dium
    Hi all, I have a problem with some code and I believe it is because of the expense of the queryset. I am looking for a much less expensive (in terms of time) way to to this.. log.info("Getting Users") employees = Employee.objects.filter(is_active = True) log.info("Have Users") if opt.supervisor: if opt.hierarchical: people = getSubs(employees, " ".join(args)) else: people = employees.filter(supervisor__name__icontains = " ".join(args)) else: log.info("Filtering Users") people = employees.filter(name__icontains = " ".join(args)) | \ employees.filter(unix_accounts__username__icontains = " ".join(args)) log.info("Filtered Users") log.info("Processing data") np = [] for person in people: unix, p4, bugz = "No", "No", "No" if len(person.unix_accounts.all()): unix = "Yes" if len(person.perforce_accounts.all()): p4 = "Yes" if len(person.bugzilla_accounts.all()): bugz = "Yes" if person.cell_phone != "": exphone = fixphone(person.cell_phone) elif person.other_phone != "": exphone = fixphone(person.other_phone) else: exphone = "" np.append({ 'name':person.name, 'office_phone': fixphone(person.office_phone), 'position': person.position, 'location': person.location.description, 'email': person.email, 'functional_area': person.functional_area.name, 'department': person.department.name, 'supervisor': person.supervisor.name, 'unix': unix, 'perforce': p4, 'bugzilla':bugz, 'cell_phone': fixphone(exphone), 'fax': fixphone(person.fax), 'last_update': person.last_update.ctime() }) log.info("Have data") Now this results in a log which looks like this.. 19:00:55 INFO phone phone Getting Users 19:00:57 INFO phone phone Have Users 19:00:57 INFO phone phone Processing data 19:01:30 INFO phone phone Have data As you can see it's taking over 30 seconds to simply iterate over the data. That is way too expensive. Can someone clue me into a more efficient way to do this. I thought that if I did the first filter that would make things easier but seems to have no effect. I'm at a loss on this one. Thanks To be clear this is about 1500 employees -- Not too many!!

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  • Django says the "id may not be NULL" but why is it?

    - by Oli
    I'm going crazy today. I just tried to insert a new record and it threw back a "post_blogpost.id may not be NULL" error. Here's my model: class BlogPost(models.Model): title = models.CharField(max_length=100) slug = models.SlugField(max_length=100) who = models.ForeignKey(User, default=1) when = models.DateTimeField() intro = models.TextField(blank=True, null=True) content = models.TextField(blank=True, null=True) counter = models.PositiveIntegerField(default=0) published = models.BooleanField(default=False) css = models.TextField(blank=True, null=True) class Meta: ordering = ('-when', 'id') There are a number of functions beneath the model too but I won't include them in full here. Their names are: content_cache_key, clear_cache, __unicode__, reads, read, processed_content. I'm adding through the admin... And I'm running out of hair.

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  • How to limit fields in django-admin depending on user?

    - by minder
    I suppose similar problem would have been discussed here, but I couldn't find it. Let's suppose I have an Editor and a Supervisor. I want the Editor to be able to add new content (eg. a news post) but before publication it has to be acknowledged by Supervisor. When Editor lists all items, I want to set some fields on the models (like an 'ack' field) as read-only (so he could know what had been ack'ed and what's still waiting approval) but the Supervisor should be able to change everything (list_editable would be perfect) What are the possible solutions to this problem?

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