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  • Personal Technology – Excel Tip: Comparing Excel Files

    - by Pinal Dave
    This guest post is by Vinod Kumar. Vinod Kumar has worked with SQL Server extensively since joining the industry over a decade ago. Working on various versionsfrom SQL Server 7.0, Oracle 7.3 and other database technologies – he now works with the Microsoft Technology Center (MTC) as a Technology Architect. Let us read the blog post in Vinod’s own voice. I have been writing about Excel Tips over my blog and thought it would be great to share one interesting tips here as a guest blog here. Assume a situation where you want to compare multiple excel files. Here is a typical scenario I have encountered as a common activity. Assume you are sending an Excel file with tons of data, formulae and multiple sheets. Now you are requesting your colleague to validate the file and if required change content for correctness. After receiving the file from your colleague, now you want to know what changes were made by this person to your document. Now here is a cool new addition to Excel 2013 that can help you achieve this task. To get to this option, click the INQUIRE Tab. Incase you don’t have the INQUIRE Tab, check Options using INQUIRE blog. In that post, we discuss all the other options of INQUIRE tab. Once you are on the INQUIRE Tab, select “Compare Files” button as shown in the figure above. This brings a dialog as below. If you are on Windows 8 or Windows 7 OS, search for an application called “Spreadsheet Compare 2013”. Ultimately both the options lead us to the same application. If you are using the stand alone app, once the App initializes, click the “Compare files” options from the toolbar. Make sure to give two different Excel files as shown in the figure above. After selecting the Excel Sheets, you can see the Compare tool has a number of other options to play from. We will talk about some of them later in this post. Just below our toolbar is a colorful side-by-side comparison of both our excel sheets. We can also see the various Tab’s from each file. There is a meaning for each of our color coding which will be discussed next. As you saw above, the color coding has a meaning. For example the bottom pane lists each of the color coding and most importantly each of the changes as compared side-by-side. The detailed information shown below can be exported using the “Export Results” options from the toolbar as a separate Excel Workbook or can be copied to clipboard to be used later. The final piece of the puzzle is to show a graphical view of these differences results based on each category. We cannot drill down per se, but this is a great way to know that the maximum changes seem to be based on “Cell Formats” and then few “Calculated Values” have changed. The INQUIRE option and Spreadsheet Compare 2013 tool is part of Excel 2013. So as you explore using the new version of Excel, there are many such hidden features that are worth exploring. Do let us know if you enjoyed learning a new feature today and I hope you will play around with this feature in your day-today challenges when working with Excel files. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, SQLAuthority News, T SQL, Technology Tagged: Excel, Personal Technology

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  • "type" Command Not Working As Expected on Git Bash

    - by trysis
    The type command, in Linux, returns the location, on the filesystem, of the given file, if it is in the current folder or the $PATH. This functionality is also available through Windows with the Git Bash command line program. The command also returns a file's location given the file without its extension (.exe, .vbs, etc.) However, I have run into what seems like a strange corner case where the file exists on the $PATH but doesn't get returned using the command. I am thinking of buying a new computer soon, so I looked up the method of transferring the license key from one computer to another, in preparation for actually doing this. The method I found mentioned the files slmgr.vbs and slui.exe, both of which reside in the C:/Windows\System32 folder, which is in my $PATH, as usual for a Windows computer. However, these two files aren't showing up when I use the type command. Also, neither gets executed when I call the files as commands without their extensions in Git Bash, and only slmgr.vbs gets executed when I call them with the extensions. Finally, slmgr.vbs is shown when listing the folder's contents in Git Bash, as well, but slui.exe isn't. I thought this might have to do with permissions, and, indeed, both files have very restrictive permissions, as you can see in the pictures below, but they both have the same permissions, which wouldn't explain why one gets executed and the other doesn't when called directly, nor why one file is listed on command line but the other isn't. C:\Windows\System32 folder, proving the files exist: File permissions for the Users and Administrators groups for the two files (they are identical): And the folder: type command and its output in Git Bash for the 2 files, plus listing the files in the folder (using grep to filter as the folder is huge), as well as listing part of the $PATH (keep in mind, for all these, that Git Bash changes the paths as they are displayed): Sean@MYPC ~ $ type -a slmgr sh.exe": type: slmgr: not found Sean@MYPC ~ $ type -a slmgr.vbs sh.exe": type: slmgr.vbs: not found Sean@MYPC ~ $ type -a slui sh.exe": type: slui: not found Sean@MYPC ~ $ type -a slui.exe sh.exe": type: slui.exe: not found Sean@MYPC ~ $ slmgr sh.exe": slmgr: command not found Sean@MYPC ~ $ slmgr.vbs /c/WINDOWS/system32/slmgr.vbs: line 2: syntax error near unexpected token `(' /c/WINDOWS/system32/slmgr.vbs: line 2: `' Copyright (c) Microsoft Corporation. A ll rights reserved.' Sean@MYPC ~ $ slui sh.exe": slui: command not found Sean@MYPC ~ $ slui.exe sh.exe": slui.exe: command not found Sean@MYPC ~ $ ls /c/Windows/System32/slui.exe /c/Windows/System32/slmgr.vbs ls: /c/Windows/System32/slui.exe: No such file or directory /c/Windows/System32/slmgr.vbs Sean@MYPC ~ $ echo $PATH /c/Users/Sean/bin:.:/usr/local/bin:/mingw/bin:/bin:/cmd:/c/Python33/:/c/Program Files (x86)/Intel/iCLS Client/:/c/Program Files/Intel/iCLS Client/:/c/WINDOWS/sy stem32:/c/WINDOWS:/c/WINDOWS/System32/Wbem:/c/WINDOWS/System32/WindowsPowerShell /v1.0/:/c/Program Files/Intel/Intel(R) Management Engine Components/DAL:/c/Progr am Files/Intel/Intel(R) Management Engine Components/IPT:/c/Program Files (x86)/ Intel/Intel(R) Management Engine Components/DAL:/c/Program Files (x86)/Intel/Int el(R) Management Engine Components/IPT:/c/Program Files/Intel/WiFi/bin/:/c/Progr am Files/Common Files/Intel/WirelessCommon/:/c/strawberry/c/bin:/c/strawberry/pe rl/site/bin:/c/strawberry/perl/bin:/c/Program Files (x86)/Microsoft ASP.NET/ASP. NET Web Pages/v1.0/:/c/Program Files/Microsoft SQL Server/110/Tools/Binn/:/c/Pro gram Files (x86)/Microsoft SQL Server/90/Tools/binn/:/c/Program Files (x86)/Open AFS/Common:/c/HashiCorp/Vagrant/bin:/c/Program Files (x86)/Windows Kits/8.1/Wind ows Performance Toolkit/:/c/Program Files/nodejs/:/c/Program Files (x86)/Git/cmd :/c/Program Files (x86)/Git/bin:/c/Program Files/Microsoft/Web Platform Installe r/:/c/Ruby200-x64/bin:/c/Users/Sean/AppData/Local/Box/Box Edit/:/c/Program Files (x86)/SSH Communications Security/SSH Secure Shell:/c/Users/Sean/Documents/Lisp :/c/Program Files/GCL-2.6.1/lib/gcl-2.6.1/unixport:/c/Chocolatey/bin:/c/Users/Se an/AppData/Roaming/npm:/c/wamp/bin/mysql/mysql5.6.12/bin:/c/Program Files/Oracle /VirtualBox:/c/Program Files/Java/jdk1.7.0_51/bin:/c/Program Files/Node-Growl:/c /chocolatey/bin:/c/Program Files/eclipse:/c/MongoDB/bin:/c/Program Files/7-Zip:/ c/Program Files (x86)/Google/Chrome/Application:/c/Program Files (x86)/LibreOffi ce 4/program:/c/Program Files (x86)/OpenOffice 4/program What's happening? Why aren't these files listed with the type command? Is this issue because of weird Windows permissions, or something even weirder? If permissions, why do they seem to have the same permissions, yet both are not handled in the same way?

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  • Get UITableView to scroll to the selected UITextField and Avoid Being Hidden by Keyboard

    - by Lauren Quantrell
    I have a UITextField in a table view on a UIViewController (not a UITableViewController). If the table view is on a UITableViewController, the table will automatically scroll to the textField being edited to prevent it from being hidden by the keyboard. But on a UIViewController it does not. I have tried for a couple of days reading through multiple ways to try to accomplish this and I cannot get it to work. The closest thing that actually scrolls is: -(void) textFieldDidBeginEditing:(UITextField *)textField { // SUPPOSEDLY Scroll to the current text field CGRect textFieldRect = [textField frame]; [self.wordsTableView scrollRectToVisible:textFieldRect animated:YES]; } However this only scrolls the table to the topmost row. What seems like an easy task has been a couple of days of frustration. I am using the following to construct the tableView cells: - (UITableViewCell *)tableView:(UITableView *)aTableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { NSString *identifier = [NSString stringWithFormat: @"%d:%d", [indexPath indexAtPosition: 0], [indexPath indexAtPosition:1]]; UITableViewCell *cell = [aTableView dequeueReusableCellWithIdentifier:identifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:identifier] autorelease]; cell.accessoryType = UITableViewCellAccessoryNone; UITextField *theTextField = [[UITextField alloc] initWithFrame:CGRectMake(180, 10, 130, 25)]; theTextField.adjustsFontSizeToFitWidth = YES; theTextField.textColor = [UIColor redColor]; theTextField.text = [textFieldArray objectAtIndex:indexPath.row]; theTextField.keyboardType = UIKeyboardTypeDefault; theTextField.returnKeyType = UIReturnKeyDone; theTextField.font = [UIFont boldSystemFontOfSize:14]; theTextField.backgroundColor = [UIColor whiteColor]; theTextField.autocorrectionType = UITextAutocorrectionTypeNo; theTextField.autocapitalizationType = UITextAutocapitalizationTypeNone; theTextField.clearsOnBeginEditing = NO; theTextField.textAlignment = UITextAlignmentLeft; //theTextField.tag = 0; theTextField.tag=indexPath.row; theTextField.delegate = self; theTextField.clearButtonMode = UITextFieldViewModeWhileEditing; [theTextField setEnabled: YES]; [cell addSubview:theTextField]; [theTextField release]; } return cell; } I suspect I can get the tableView to scroll properly if I can somehow pass the indexPath.row in the textFieldDidBeginEditing method? Any help is appreciated.

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  • jquery show hidden div

    - by Fahad
    Firstly, I'm sort of embarrassed asking about this, so many people have already asked this question but even after having gone through so many posts, I'm unable to achieve what I want. Basically, a div, initially hidden, has to be displayed on a button click. I tried hiding the div using display:none and hide() and then displaying it using show(), toggle(), and css("display","block"). Using all sorts of combinations of the above, I was still unable to get the result. Code: <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title></title> <link href="css/smoothness/jquery-ui-1.9.2.custom.min.css" rel="stylesheet" type="text/css" /> <script src="jQuery/jquery-1.8.3.min.js" type="text/javascript"></script> <script src="jQuery/jquery-ui-1.9.2.custom.min.js" type="text/javascript"></script> <script type="text/javascript"> $(document).ready(function () { $('#one').hide(); $('#Button1').click(function () { $('#one').toggle(500); }); }); </script> </head> <body> <form id="form1" runat="server"> <div id="one" style="height: 20px;width:200px; background-color: Red; "> </div> <asp:Button ID="Button1" runat="server" Text="Show" /> </form> </body> </html> On button click, the div is shown for a brief second before it disappears again. The same thing happens if I use show() instead of toggle() in the above code. Again the same thing if I set style="display:none" to the div instead of using hide() and then use show() or toggle(). I also tried using $('#one').css("display","block"); but again, the same result. Can anyone please tell me where I'm going wrong. Just started learning jQuery and it is really frustrating when something apparently so simple will not work. Thanks in advance. :)

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  • position:absolute within border-radius and overflow:hidden

    - by JaNightmare
    I had a problem with border-radius in webkit browsers and found the solution at the following URL: How to make CSS3 rounded corners hide overflow in Chrome/Opera but iam using a another element with position: absolute; inside this now I need to make the caption with rounded border too, but do not know how note: i can't use another border-radius in caption, because this will have an animation see the code with: <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>Problem</title> <style type="text/css"> img { border: 0; } a { text-decoration: none; } .wrap-events { float: left; position: relative; width: 500px; height: 250px; } .events { overflow: hidden; -webkit-border-radius: 50px; -moz-border-radius: 50px; border-radius: 50px; } .caption { position: absolute; width: 100%; bottom: 0; color: #FFFFFF; background-color: #151515; font: 12px "Arial", Helvetica, sans-serif; opacity: 0.6; border-radius: 0 0 50px 50px; /* add border-radius to caption */ } .caption p { padding: 10px; } </style> </head> <body> <div class="wrap-events"> <div class="events"> <a href="#"> <img src="http://www.cg-auto.com.br/forum/imagens/imagens_news/26c4dc4359edcfd4c6871ee1fa958539.jpg" alt="image"> </a> <div class="caption"> <p>This is a caption</p> </div> </div> </div> <button id="slide">Slide It!</button> <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script> <script type="text/javascript"> $('#slide').click(function(){ $('.caption').hide().slideDown(2000); }); </script> </body> </html> cheers

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  • OAF Page to Upload Files into Server from local Machine

    - by PRajkumar
    1. Create a New Workspace and Project File > New > General > Workspace Configured for Oracle Applications File Name – PrajkumarFileUploadDemo   Automatically a new OA Project will also be created   Project Name -- FileUploadDemo Default Package -- prajkumar.oracle.apps.fnd.fileuploaddemo   2. Create a New Application Module (AM) Right Click on FileUploadDemo > New > ADF Business Components > Application Module Name -- FileUploadAM Package -- prajkumar.oracle.apps.fnd.fileuploaddemo.server Check Application Module Class: FileUploadAMImpl Generate JavaFile(s)   3. Create a New Page Right click on FileUploadDemo > New > Web Tier > OA Components > Page Name -- FileUploadPG Package -- prajkumar.oracle.apps.fnd.fileuploaddemo.webui   4. Select the FileUploadPG and go to the strcuture pane where a default region has been created   5. Select region1 and set the following properties --     Attribute Property ID PageLayoutRN AM Definition prajkumar.oracle.apps.fnd.fileuploaddemo.server.FileUploadAM Window Title Uploading File into Server from Local Machine Demo Window Title Uploading File into Server from Local Machine Demo     6. Create Stack Layout Region Under Page Layout Region Right click PageLayoutRN > New > Region   Attribute Property ID MainRN AM Definition messageComponentLayout   7. Create a New Item messageFileUpload Bean under MainRN Right click on MainRN > New > messageFileUpload Set Following Properties for New Item --   Attribute Property ID MessageFileUpload Item Style messageFileUpload   8. Create a New Item Submit Button Bean under MainRN Right click on MainRN > New > messageLayout Set Following Properties for messageLayout --   Attribute Property ID ButtonLayout   Right Click on ButtonLayout > New > Item   Attribute Property ID Submit Item Style submitButton Attribute Set /oracle/apps/fnd/attributesets/Buttons/Go   9. Create Controller for page FileUploadPG Right Click on PageLayoutRN > Set New Controller Package Name: prajkumar.oracle.apps.fnd.fileuploaddemo.webui Class Name: FileUploadCO   Write Following Code in FileUploadCO processFormRequest   import oracle.cabo.ui.data.DataObject; import java.io.FileOutputStream; import java.io.InputStream; import oracle.jbo.domain.BlobDomain; import java.io.File; import oracle.apps.fnd.framework.OAException; public void processFormRequest(OAPageContext pageContext, OAWebBean webBean) { super.processFormRequest(pageContext, webBean);    if(pageContext.getParameter("Submit")!=null)  {   upLoadFile(pageContext,webBean);      } }   -- Use Following Code if want to Upload Files in Local Machine -- ----------------------------------------------------------------------------------- public void upLoadFile(OAPageContext pageContext,OAWebBean webBean) { String filePath = "D:\\PRajkumar";  System.out.println("Default File Path---->"+filePath);  String fileUrl = null;  try  {   DataObject fileUploadData =  pageContext.getNamedDataObject("MessageFileUpload"); //FileUploading is my MessageFileUpload Bean Id   if(fileUploadData!=null)   {    String uFileName = (String)fileUploadData.selectValue(null, "UPLOAD_FILE_NAME");  // include this line    String contentType = (String) fileUploadData.selectValue(null, "UPLOAD_FILE_MIME_TYPE");  // For Mime Type    System.out.println("User File Name---->"+uFileName);    FileOutputStream output = null;    InputStream input = null;    BlobDomain uploadedByteStream = (BlobDomain)fileUploadData.selectValue(null, uFileName);    System.out.println("uploadedByteStream---->"+uploadedByteStream);                               File file = new File("D:\\PRajkumar", uFileName);    System.out.println("File output---->"+file);    output = new FileOutputStream(file);    System.out.println("output----->"+output);    input = uploadedByteStream.getInputStream();    System.out.println("input---->"+input);    byte abyte0[] = new byte[0x19000];    int i;         while((i = input.read(abyte0)) > 0)    output.write(abyte0, 0, i);    output.close();    input.close();   }  }  catch(Exception ex)  {   throw new OAException(ex.getMessage(), OAException.ERROR);  }     }   -- Use Following Code if want to Upload File into Server -- ------------------------------------------------------------------------- public void upLoadFile(OAPageContext pageContext,OAWebBean webBean) { String filePath = "/u01/app/apnac03r12/PRajkumar/";  System.out.println("Default File Path---->"+filePath);  String fileUrl = null;  try  {   DataObject fileUploadData =  pageContext.getNamedDataObject("MessageFileUpload");  //FileUploading is my MessageFileUpload Bean Id     if(fileUploadData!=null)   {    String uFileName = (String)fileUploadData.selectValue(null, "UPLOAD_FILE_NAME");   // include this line    String contentType = (String) fileUploadData.selectValue(null, "UPLOAD_FILE_MIME_TYPE");   // For Mime Type    System.out.println("User File Name---->"+uFileName);    FileOutputStream output = null;    InputStream input = null;    BlobDomain uploadedByteStream = (BlobDomain)fileUploadData.selectValue(null, uFileName);    System.out.println("uploadedByteStream---->"+uploadedByteStream);                               File file = new File("/u01/app/apnac03r12/PRajkumar", uFileName);    System.out.println("File output---->"+file);    output = new FileOutputStream(file);    System.out.println("output----->"+output);    input = uploadedByteStream.getInputStream();    System.out.println("input---->"+input);    byte abyte0[] = new byte[0x19000];    int i;         while((i = input.read(abyte0)) > 0)    output.write(abyte0, 0, i);    output.close();    input.close();   }  }  catch(Exception ex)  {   throw new OAException(ex.getMessage(), OAException.ERROR);  }     }   10. Congratulation you have successfully finished. Run Your page and Test Your Work           -- Used Code to Upload files into Server   -- Before Upload files into Server     -- After Upload files into Server       -- Used Code to Upload files into Local Machine   -- Before Upload files into Local Machine       -- After Upload files into Local Machine

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  • Removing offline/defunct files in SQL server 2008

    - by philox
    How to remove traces of files marked as OFFLINE or DEFUNCT in Microsoft SQL server 2008? I have been playing around with a setup where I create a database with 3 file-groups which are: Primary, FileGroupData and FileGroupIndex. The clustered index is using FileGroupData and a non-clustered index is set to use FileGroupIndex. To simulate a disk failure I've shut down SQL server and manually deleted the files in index file-group. To start the database I'll mark the files 'OFFLINE', but after that I can't delete the index files, which are now offline. I don't have backup of the files as they are merely indices, but that has the implication that I can't restore the files and have their status as "ONLINE". How would you recommend removing the files and the file-group as they still show up in management studio under files/file-groups. Management studio is not able to delete them. As far as I can tell this is different from the question posted in : http://stackoverflow.com/questions/462637/how-do-i-remove-offline-files-from-a-sql-server-2005-database /Philip

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  • What do I need in order to extract and combine text files from multiple ZIP files, via command line?

    - by Iszi
    I've got an interesting scripting challenge in front of me. I'm fairly certain there's a way to do it, but I feel like I'm probably lacking some particular tools and/or functional knowledge. There's some fifty-plus ZIP files that each contain, among other things, text files that need to be merged with one another. The structure is something like this: C:\Reports\FirstJob-1.zip |-MyName |-FirstJob |-1 |-[Some other folders] |-TXTReports |-English |-[Some other files] |-Report.txt C:\Reports\FirstJob-2.zip |-MyName |-FirstJob |-1 |-[Some other folders] |-TXTReports |-English |-[Some other files] |-Report.txt C:\Reports\SecondJob-1.zip |-MyName |-SecondJob |-1 |-[Some other folders] |-TXTReports |-English |-[Some other files] |-Report.txt If I had all the Report.txt files in one regular folder, and uniquely named, I could probably just write a FOR statement that targets *.txt and runs something like type filename.txt >> Consolidated.txt on each. However, these all have the same file name and are embedded deep within separate ZIP files. The potentially useful tools I currently have at my disposal are Windows XP Professional SP3, PowerShell, and WinZip. I'd rather not download or install anything else, but I do understand that third-party tools (or additional tools from Microsoft or WinZip) may be necessary. Whatever tools I use should run natively in Windows. I really don't want to have to mess with Cygwin or other emulators on this system. At the very least, I need a tool that will allow me to analyze and manipulate ZIP files from the command line. Also, are there any other particular complications to this that I've not yet thought of?

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  • paypal address1 HTML name doensnt work?

    - by ajsie
    i use this code to send the customer to the paypals payment page: <form action="https://www.paypal.com/cgi-bin/webscr" method="post"> <input type='hidden' name='cmd' value='_cart' /> <input type='hidden' name='upload' value='1' /> <input type="hidden" name="business" value="[email protected]"> <input type="hidden" name="currency_code" value="SEK"> <input type="hidden" name="return" value="http://freelanceswitch.com/payment-complete/"> <input type="hidden" name="item_number_1" value="01 - General Payment"> <input type="hidden" name="item_name_1" size="45"> <input type="hidden" name="amount_1" size="45"> <input type="hidden" name="item_number_2" value="01 - Bonus Payment"> <input type="hidden" name="item_name_2" size="45"> <input type="hidden" name="amount_2" size="45"> <!-- PREPOPULATING FIELDS --> <input type='hidden' name='address1' value='Open Bridge street 19' /> <input type='hidden' name='address2' value='Easter heaven garden 12' /> <input type='hidden' name='first_name' value='Peter' /> <input type='hidden' name='last_name' value='Hansen' /> <input type="submit" name="Submit" value="Submit"> </form> everything works except the address1 and address2 in PREPOPULATING FIELDS. the fields for the Billing Address Line 1 and Billing Address Line 2 are empty. anyone knows why?

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  • Quick question on using the constructer with multiple files.

    - by sil3nt
    Hi there, I have this class header //header for class. #ifndef Container_H #define Container_H #include <iostream> using namespace std; const int DEFAULT=32; class Container{ public: Container(int maxCapacity = DEFAULT); ~Container(); void insert(int item, int index); void erase(int index); int size()const; private: int sizeC; int capacityC; int * elements; }; void info(); #endif and this source file #include "container.h" Container::Container(int maxCapacity = DEFAULT){ int y; } void Container::insert(int item, int index){ int x; } and when i compile this i get the following error message test.cpp:4: error: default argument given for parameter 1 of `Container::Container(int)' container.h:12: error: after previous specification in `Container::Container(int) what have i done wrong here?

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  • Horizontal navigation from next previous buttons for Overflow:Hidden div

    - by brz dot net
    See following Code <div> <a id="west" href="javascript:void(0);" onclick="scrollBlockWest();"><<West</a> <a id="east" href="javascript:void(0);" onclick="scrollBlockEast();">East >></a> </div> <div id="myScrollContainer" style="overflow:hidden; width:900px; height:700px"> <table id="myScrollContent"><tr><td> <div id="block0" style="display:block;height:300px; width:300px; background-color:Lime">Content 0</div> </td><td> <div id="block1" style="display:block;height:300px; width:300px; background-color:Aqua">Content 1</div> </td><td> <div id="block2" style="display:block;height:300px; width:300px; background-color:Blue">Content 2</div> </td><td> <div id="block3" style="display:block;height:300px; width:300px; background-color:Gray">Content 3</div> </td><td> <div id="block4" style="display:block;height:300px; width:300px; background-color:Gray">Content 4</div> </td> </tr></table> </div> This is my script: <script type="text/javascript" > var totalBlock = 4; var currentBlock = 0; function scrollBlockEast() { var blk = document.getElementById('block'+currentBlock); //alert('block'+blockid); blk.style.display='none'; currentBlock++; //document.getElementById('myScrollContent').style.left = -100; if(currentBlock<totalBlock) { document.getElementById('west').style.display='inline'; } //alert(totlaBlock-1); if(currentBlock==totalBlock) { document.getElementById('east').style.display='none'; } } function scrollBlockWest() { currentBlock--; document.getElementById('block'+currentBlock).style.display='inline'; if(currentBlock<1) { document.getElementById('west').style.display='none'; } else { document.getElementById('east').style.display='inline'; } } </script> Now My object is to slide block on << and click. By default, 3 blocks(Content 0,Content 1,Content 2) are coming. When is clicked then (Content 1,Content 2,Content 3) will come. For this, I hide content 0 block. But layout will disturb on << click. I know this is wrong way. I should set left position instead of hiding content but it is empty I tried to set left position but no luck. Let me know How the block can be moved one by one using javascript and what is the best approach to do this?

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  • Hidden UIView Orientation Change / Layout problems

    - by gargantaun
    The Problem: I have two View Controllers loaded into a root View Controller. Both sub view layouts respond to orientation changes. I switch between the two views using [UIView transformationFromView:...]. Both sub views work fine on their own, but if... Views are swapped Orientation Changes Views are swapped again the View that was previously hidden has serious layout problems. The more I repeat these steps the worse the problem gets. Implementation Details I have three viewsControllers. MyAppViewController A_ViewController B_ViewController A & B ViewControllers have a background image each, and a UIWebView and an AQGridView respectively. To give you an example of how i'm setting it all up, here's the loadView method for A_ViewController... - (void)loadView { [super loadView]; // background image // Should fill the screen and resize on orientation changes UIImageView *bg = [[UIImageView alloc] initWithFrame:self.view.bounds]; bg.contentMode = UIViewContentModeCenter; bg.autoresizingMask = UIViewAutoresizingFlexibleHeight | UIViewAutoresizingFlexibleWidth; bg.image = [UIImage imageNamed:@"fuzzyhalo.png"]; [self.view addSubview:bg]; // frame for webView // Should have a margin of 34 on all sides and resize on orientation changes CGRect webFrame = self.view.bounds; webFrame.origin.x = 34; webFrame.origin.y = 34; webFrame.size.width = webFrame.size.width - 68; webFrame.size.height = webFrame.size.height - 68; projectView = [[UIWebView alloc] initWithFrame:webFrame]; projectView.autoresizingMask = UIViewAutoresizingFlexibleHeight | UIViewAutoresizingFlexibleWidth; [self.view addSubview:projectView]; } For the sake of brevity, the AQGridView in B_ViewController is set up pretty much the same way. Now both these views work fine on their own. However, I use both of them in the AppViewController like this... - (void)loadView { [super loadView]; self.view.autoresizesSubviews = YES; [self setWantsFullScreenLayout:YES]; webView = [[WebProjectViewController alloc] init]; [self.view addSubview:webView.view]; mainMenu = [[GridViewController alloc] init]; [self.view addSubview:mainMenu.view]; activeView = mainMenu; [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(switchViews:) name:SWAPVIEWS object:nil]; } and I switch betweem the two views using my own switchView method like this - (void) switchViews:(NSNotification*)aNotification; { NSString *type = [aNotification object]; if ([type isEqualToString:MAINMENU]){ [UIView transitionFromView:activeView.view toView:mainMenu.view duration:0.75 options:UIViewAnimationOptionTransitionFlipFromRight completion:nil]; activeView = mainMenu; } if ([type isEqualToString:WEBVIEW]) { [UIView transitionFromView:activeView.view toView:webView.view duration:0.75 options:UIViewAnimationOptionTransitionFlipFromLeft completion:nil]; activeView = webView; } // These don't seem to do anything //[mainMenu.view setNeedsLayout]; //[webView.view setNeedsLayout]; } I'm fumbling my way through this, and I suspect a lot of what i've done is implemented incorrectly so please feel free to point out anything that should be done differently, I need the input. But my primary concern is to understand what's causing the layout problems. Here's two images which illustrate the nature of the layout issues... UPDATE: I just noticed that when the orientation is landscape, the transition flips vertically, when I would expect it to be horizontal. I don't know wether that's a clue as to what might be going wrong. Switch to the other view... change orientation.... switch back....

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  • Concatenation of files using ffmpeg does not work as I expected. Why?

    - by Peter Olson
    I execute the following command line for ffmpeg.exe -i C:\Beema\video-source\DO_U_BEEMA176x144short.avi -i C:\Beema\video-source\DO_U_BEEMA176x144short.avi -i C:\Beema\temp\9016730-51056331-stitcheds.avi -i C:\Beema\video-source\GOTTA_BEEMA176x144short.avi -y -ac 1 -r 24 -b 25K C:\Beema\video-out\9a062fb6-d448-48fe-b006-a85d51adf8a1.mpg The output file in video-out ends up having a single copy of DO_U_BEEMA. I do not understand why ffmpeg is not concatenating. Any help is dramatically appreciated,

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  • Windows Server - share files without access for administrator

    - by Pawel
    We have a MS Windows Server 2008 R8 based server that is administrated by our IT department. We would like to achieve two things simultaneously: A folder on the server, containing several thousand files (new files added frequently) that is accessible to some ActiveDirectory users (e.g. board of directors) but is not accessible by IT department employees IT department employees still maintain rights to administrate the server, including installing new software and services We already checked some solutions: Using NTFS access rights. Unfortunately IT (members of "Administrators" group) can set themselves as new owners of the files and change the permissions so that they gain access to the files. Enabling EFS. Unfortunately even if you do not allow IT to access files, they still can disable EFS completely because they have administrative rights. Moreover as far as I know you have to manually add permissions for all users but the owner for each new file - very inconvenient. Creating a new role for the IT department that has all the privileges apart from taking ownership of files. Unfortunately if you're not a member of the Administrators group, you cannot install new software, no matter what privileges you add to the role. TrueCrypt - nice free encryption software, but with poor sharing capabilities. You can either mount an encryption container on the server (and then IT has access to its contents) or you mount them locally but only one user can mount it for writing. AxCrypt - free encryption software that enables file-by-file encryption on the server. There are some disadvantages though - you have to manually encrypt each new file added. The files have their extensions changes. You can only set one password for all files (so all users have to know this one password). Any other ideas? Our budget is limited so enterprise-class software from Symantec or PGP would probably be not an option.

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  • How do I define a template class and divide it into multiple files?

    - by hkBattousai
    I have written a simple template class for test purpose. It compiles without any errors, but when I try to use it in main(), it give some linker errors. main.cpp #include <iostream> #include "MyNumber.h" int wmain(int argc, wchar_t * argv[]) { MyNumber<float> num; num.SetValue(3.14); std::cout << "My number is " << num.GetValue() << "." << std::endl; system("pause"); return 0; } MyNumber.h #pragma once template <class T> class MyNumber { public: MyNumber(); ~MyNumber(); void SetValue(T val); T GetValue(); private: T m_Number; }; MyNumber.cpp #include "MyNumber.h" template <class T> MyNumber<T>::MyNumber() { m_Number = static_cast<T>(0); } template <class T> MyNumber<T>::~MyNumber() { } template <class T> void MyNumber<T>::SetValue(T val) { m_Number = val; } template <class T> T MyNumber<T>::GetValue() { return m_Number; } When I build this code, I get the following linker errors: Error 7 Console Demo C:\Development\IDE\Visual Studio 2010\SAVE\Grand Solution\X64\Debug\Console Demo.exe 1 error LNK1120: 4 unresolved externals Error 3 Console Demo C:\Development\IDE\Visual Studio 2010\SAVE\Grand Solution\Console Demo\main.obj error LNK2019: unresolved external symbol "public: __cdecl MyNumber::~MyNumber(void)" (??1?$MyNumber@M@@QEAA@XZ) referenced in function wmain Error 6 Console Demo C:\Development\IDE\Visual Studio 2010\SAVE\Grand Solution\Console Demo\main.obj error LNK2019: unresolved external symbol "public: __cdecl MyNumber::MyNumber(void)" (??0?$MyNumber@M@@QEAA@XZ) referenced in function wmain Error 4 Console Demo C:\Development\IDE\Visual Studio 2010\SAVE\Grand Solution\Console Demo\main.obj error LNK2019: unresolved external symbol "public: float __cdecl MyNumber::GetValue(void)" (?GetValue@?$MyNumber@M@@QEAAMXZ) referenced in function wmain Error 5 Console Demo C:\Development\IDE\Visual Studio 2010\SAVE\Grand Solution\Console Demo\main.obj error LNK2019: unresolved external symbol "public: void __cdecl MyNumber::SetValue(float)" (?SetValue@?$MyNumber@M@@QEAAXM@Z) referenced in function wmain But, if I leave main() empty, I don't get any linker errors. What is wrong with my template class? What am I doing wrong?

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  • Windows Server - share files without access for administrator

    - by Pawel
    We have a MS Windows Server 2008 R8 based server that is administrated by our IT department. We would like to achieve two things simultaneously: A folder on the server, containing several thousand files (new files added frequently) that is accessible to some ActiveDirectory users (e.g. board of directors) but is not accessible by IT department employees IT department employees still maintain rights to administrate the server, including installing new software and services We already checked some solutions: Using NTFS access rights. Unfortunately IT (members of "Administrators" group) can set themselves as new owners of the files and change the permissions so that they gain access to the files. Enabling EFS. Unfortunately even if you do not allow IT to access files, they still can disable EFS completely because they have administrative rights. Moreover as far as I know you have to manually add permissions for all users but the owner for each new file - very inconvenient. Creating a new role for the IT department that has all the privileges apart from taking ownership of files. Unfortunately if you're not a member of the Administrators group, you cannot install new software, no matter what privileges you add to the role. TrueCrypt - nice free encryption software, but with poor sharing capabilities. You can either mount an encryption container on the server (and then IT has access to its contents) or you mount them locally but only one user can mount it for writing. AxCrypt - free encryption software that enables file-by-file encryption on the server. There are some disadvantages though - you have to manually encrypt each new file added. The files have their extensions changes. You can only set one password for all files (so all users have to know this one password). Any other ideas? Our budget is limited so enterprise-class software from Symantec or PGP would probably be not an option.

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  • logrotate: neither rotate nor compress empty files

    - by Andrew Tobey
    i have just set up an (r)syslog server to receive the logs of various clients, which works fine. only logrotate is still not behaving as intending. i want logrotate to create a new logfile for each day, but only to keep and store i.e. compress non-empty files. my logrotate config looks currently like this # sample configuration for logrotate being a remote server for multiple clients /var/log/syslog { rotate 3 daily missingok notifempty delaycompress compress dateext nomail postrotate reload rsyslog >/dev/null 2>&1 || true endscript } # local i.e. the system's very own logs: keep logs for a whole month /var/log/kern.log /var/log/kernel-info /var/log/auth.log /var/log/auth-info /var/log/cron.log /var/log/cron-info /var/log/daemon.log /var/log/daemon-info /var/log/mail.log /var/log/rsyslog /var/log/rsyslog-info { rotate 31 daily missingok notifempty delaycompress compress dateext nomail sharedscripts postrotate reload rsyslog >/dev/null 2>&1 || true endscript } # received i.e. logs from the clients /var/log/path-to-logs/*/* { rotate 31 daily missingok notifempty delaycompress compress dateext nomail } what i end up with is having is some sort of "summarized" files such as filename-datestampDay-Day and corresponding .gz files. What I do have are empty files, which are eventually zipped. so does the notifempty directive is in fact responsible for these DayX-DayY files, days on which really nothing happened? what would be an efficient way to drop both, empty log files and their .gz files, so that I eventually only keep logs/compressed files that truly contain data?

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  • Export files to remote server using TortoiseSVN

    - by Matt
    Hi, I'm using TortoiseSVN to keep revisions of my code. When I commit changes, I take note of what files have changed and upload them to my server using FTP. Here's my workflow: Edit files on local computer (eg. files in C:\Users\Me\web) Commit changes to local repository using rightclick- TortoiseSVN- SVN Commit. Take the files, open FileZilla (FTP client) and upload the files to a remote server. I was wondering if there was a way in which I could omit step 3 from my workflow. Basically I would like the changed files to be automatically uploaded to the remote server when I commit a version to the repository. Information about my computer environment: Windows 7 Ultimate x64 with TortoiseSVN x64 Notepad++ text editor Files edited are PHP, CSS, JS, HTML, etc. Server is running Linux with PHP 5.2 and MySQL. FileZilla is used to upload files. I can connect to the server via SSH if that is needed. Thank you in advance.

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  • Searching for just files

    - by M Schenkel
    I have a couple questions about searching for files on Windows 7. I find the XP method much easier than this new Windows 7 search. Note: I am only concerned about finding files matching a search term, not ALL files containing the search term. Is there a way to search just for files? When I use the search it seems to be searching "within" files and returning instances where the name of the file is used. Example: I have a whole web directory and want to find the javascript files. But if I enter "myjavascript.js" in the search, it also returns all the html files which reference the javascript file. This is both slow and difficult to actually find the reference to the file. Is there a way to search for an exact match? The search seems to implicitly use wildcards. For instance, say I have a bunch of files in a folder: file1.txt,file11.txt, file12.txt, file13.txt. If I enter "file1.txt" in the searcher it returns instances as if I were using a wild card file1*.txt I miss XP!!!!

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  • Export files to remote server using TortoiseSVN

    - by Matt
    I'm using TortoiseSVN to keep revisions of my code. When I commit changes, I take note of what files have changed and upload them to my server using FTP. Here's my workflow: Edit files on local computer (eg. files in C:\Users\Me\web) Commit changes to local repository using rightclick- TortoiseSVN- SVN Commit. Take the files, open FileZilla (FTP client) and upload the files to a remote server. I was wondering if there was a way in which I could omit step 3 from my workflow. Basically I would like the changed files to be automatically uploaded to the remote server when I commit a version to the repository. Information about my computer environment: Windows 7 Ultimate x64 with TortoiseSVN x64 Notepad++ text editor Files edited are PHP, CSS, JS, HTML, etc. Server is running Linux with PHP 5.2 and MySQL. FileZilla is used to upload files. I can connect to the server via SSH if that is needed. Thank you in advance.

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  • Should '#include' and 'using' statements be repeated in both header and implementation files (C++)?

    - by Dr. Monkey
    I'm fairly new to C++, but my understanding is that a #include statement will essentially just dump the contents of the #included file into the location of that statement. This means that if I have a number of '#include' and 'using' statements in my header file, my implementation file can just #include the header file, and the compiler won't mind if I don't repeat the other statements. What about people though? My main concern is that if I don't repeat the '#include', 'using', and also 'typedef' (now that I think of it) statements, it takes that information away from the file in which it's used, which could lead to confusion. I am just working on small projects at the moment where it won't really cause any issues, but I can imagine that in larger projects with more people working on them it could become a significant issue. An example follows: //Unit.h #include <string> #include <ostream> #include "StringSet.h" using std::string; using std::ostream; class Unit { public: //public members private: //private members //unrelated side-question: should private members //even be included in the header file? } ; //Unit.cpp #include "Unit.h" //The following are all redundant from a compiler perspective: #include <string> #include <ostream> #include "StringSet.h" using std::string; using std::ostream; //implementation goes here

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  • How do I copy files into an existing JAR file with Ant?

    - by Blue
    I have a project that needs to access resources within its own JAR file. When I create the JAR file for the project, I would like to copy a directory into that JAR file (I guess the ZIP equivalent would be "adding" the directory to the existing ZIP file). I only want the copy to happen after the JAR has been created (and I obviously don't want the copy to happen if I clean and delete the JAR file). Currently the build file looks like this: <?xml version="1.0" encoding="UTF-8"?> <project name="foobar" basedir=".." default="jar"> <!-- project-specific properties --> <property name="project.path" value="my/project/dir/foobar" /> <patternset id="project.include"> <include name="${project.path}/**" /> </patternset> <patternset id="project.jar.include"> <include name="${project.path}/**" /> </patternset> <import file="common-tasks.xml" /> <property name="jar.file" location="${test.dir}/foobar.jar" /> <property name="manifest.file" location="misc/foobar.manifest" /> </project> Some of the build tasks are called from another file (common-tasks.xml), which I can't display here. Thanks.

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  • How To Completely Move Users/Program Files/Program Files (x86)/ProgramData (Folders) To Another Partition(s) On Windows 8?

    - by Enigma83
    I am attempting to move folders Users Program Files Program Files (x86), ProgramData (at the root of the C drive) to at least 2 other partitions, preferably on a fresh install. I have read that there are methods for doing this post-install, but it seems like it would be a bit more tedious to do things that way. I want to move the 2 Program Files folders to another partition on the same HDD, and Users/ProgramData will go to yet another partition on same HDD. I have done a bit of research on this, read up on some things that involved booting into Audit Mode, using the RoboCopy command to copy folders via booting into my Windows 8 USB drive, creating NTFS junctions/symbolic links, Registry edits, as well as accomplishing this automatically by creating an auto-attend file which Windows Setup processes automatically before the user is ever booted in for the 1st time. I tried this morning and now have a basic installation in which programs like Internet Explorer fail to open, certain files can't be found/opened (even if I click on them directly), an example is Regedit. Also, I can't run the Command/DOS (CMD) prompt as Administrator (or otherwise, as any other user), can't activate the real Administrator account or open any of the Administrative Tools (despite having added them to my Start Screen). So far I have only tried RoboCopy-ing Program Files and Program Files (x86) so far, creating junction points for them, and editing the Registry in the relevant locations. This is what I'm left with now. I also found the following blog article which describes how to do this for Windows 7 So, where should I go from here and where can I find more information? And how can this be done without disabling the Metro apps, which I've read will stop working if you move ProgramData. Once I have everything moved, where do I install programs to? Do I tell them to install to C:\Program Files\Program Files (x86) or to the junctioned/symbolic-linked partition/drive? I plan to test in VMware virtual machines from here on until things are working correctly, while using a baseline default install for daily tasks.

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