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  • Keyword Density - How Much is Too Much For SEO?

    A long time ago the easiest way to reach high rankings in many search engines at that time was to stuff pages with target keywords. Some tried to hide some part of the page by using background color also for text, while others simply put few paragraphs with apparently irrelevant keywords at the end of the page. Because word frequency was one of the most important factors to rank pages, it was pretty easy to reach top positions just by exaggerating with keywords.

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  • When should I use String.Format or String.Concat instead of the concatenation operator?

    - by Kramii
    In C# it is possible to concatenate strings in several different ways: Using the concatenation operator: var newString = "The answer is '" + value + "'."; Using String.Format: var newString = String.Format("The answer is '{0}'.", value); Using String.Concat: var newString = String.Concat("The answer is '", value, "'."); What are the advantages / disadvantages of each of these methods? When should I prefer one over the others? The question arises because of a debate between developers. One never uses String.Format for concatenation - he argues that this is for formatting strings, not for concatenation, and that is is always unreadable because the items in the string are expressed in the wrong order. The other frequently uses String.Format for concatenation, because he thinks it makes the code easier to read, especially where there are several sets of quotes involved. Both these developers also use the concatenation operator and String.Builder, too.

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  • sed to insert on first match only

    - by SS.
    UPDATED: Using sed, how can I insert (NOT SUBSTITUTE) a new line on only the first match of keyword for each file. Currently I have the following but this inserts for every line containing Matched Keyword and I want it to only insert the New Inserted Line for only the first match found in the file: sed -ie '/Matched Keyword/ i\New Inserted Line' *.* For example: Myfile.txt: Line 1 Line 2 Line 3 This line contains the Matched Keyword and other stuff Line 4 This line contains the Matched Keyword and other stuff Line 6 changed to: Line 1 Line 2 Line 3 New Inserted Line This line contains the Matched Keyword and other stuff Line 4 This line contains the Matched Keyword and other stuff Line 6

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  • Move constructor and assignment operator: why no default for derived classes?

    - by doublep
    Why there is default move constructor or assignment operator not created for derived classes? To demonstrate what I mean; having this setup code: #include <utility> struct A { A () { } A (A&&) { throw 0; } A& operator= (A&&) { throw 0; } }; struct B : A { }; either of the following lines throws: A x (std::move (A ()); A x; x = A (); but neither of the following does: B x (std::move (B ()); B x; x = B (); In case it matters, I tested with GCC 4.4.

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  • In Ruby, can the coerce() method know what operator it is that requires the help to coerce?

    - by Jian Lin
    In Ruby, it seems that a lot of coerce() help can be done by def coerce(something) [self, something] end that's is, when 3 + rational is needed, Fixnum 3 doesn't know how to handle adding a Rational, so it asks Rational#coerce for help by calling rational.coerce(3), and this coerce instance method will tell the caller: # I know how to handle rational + something, so I will return you the following: [self, something] # so that now you can invoke + on me, and I will deal with Fixnum to get an answer So what if most operators can use this method, but not when it is (a - b) != (b - a) situation? Can coerce() know which operator it is, and just handle those special cases, while just using the simple [self, something] to handle all the other cases where (a op b) == (b op a) ? (op is the operator).

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  • Why can't I reclaim my dynamically allocated memory using the "delete" keyword?

    - by synaptik
    I have the following class: class Patient { public: Patient(int x); ~Patient(); private: int* RP; }; Patient::Patient(int x) { RP = new int [x]; } Patient::~Patient() { delete [] RP; } I create an instance of this class on the stack as follows: void f() { Patient p(10); } Now, when f() returns, I get a "double free or corruption" error, which signals to me that something is attempted to be deleted more than once. But I don't understand why that would be so. The space for the array is created on the heap, and just because the function from inside which the space was allocated returns, I wouldn't expect the space to be reclaimed. I thought that if I allocate space on the heap (using the new keyword), then the only way to reclaim that space is to use the delete keyword. Help! :)

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  • Why aren't operator conversions implicitly called for templated functions? (C++)

    - by John Gordon
    I have the following code: template <class T> struct pointer { operator pointer<const T>() const; }; void f(pointer<const float>); template <typename U> void tf(pointer<const float>); void g() { pointer<float> ptr; f(ptr); tf(ptr); } When I compile the code with gcc 4.3.3 I get a message (aaa.cc:17: error: no matching function for call to ‘tf(pointer<float>&)’) indicating that the compiler called 'operator pointer<const T>' for the non-templated function f(), but didn't for the templated function tf(). Why and is there any workaround short of overloading tf() with a const and non-const version? Thanks in advance for any help.

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  • Where would I use a bitwise operator in JavaScript?

    - by J-P
    I've read this (http://stackoverflow.com/quest...), so I know what bitwise operators are but I'm still not clear on how one might use them... Can anyone offer any real-world examples of where a bitwise operator would be useful in JavaScript? Thanks. Edit: Just digging into the jQuery source I've found a couple of places where bitwise operators are used, for example: (only the & operator) // Line 2756: event.which = (event.button & 1 ? 1 : ( event.button & 2 ? 3 : ( event.button & 4 ? 2 : 0 ) )); // Line 2101 var ret = a.compareDocumentPosition(b) & 4 ? -1 : a === b ? 0 : 1;

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  • Searching a keyword in a long string in mysql?

    - by user187580
    Hello keyword = house SELECT * FROM products WHERE description LIKE '%house%' This query also returns records having keyword, for example, courthouse, but I want to look for house only. How do I search anywhere in the description for "house" only? Thanks. UPDATE just for more clarification .. actually house, can be at - the start of the description .. "House for sale..", - can be quoted -- "house", 'house' - can have exclamation .. house!!!, house! - others - house? etc .. this is why I used %house%

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  • How can I mix optional keyword arguments with the & rest stuff?

    - by Rayne
    I have a macro that takes a body: (defmacro blah [& body] (dostuffwithbody)) But I'd like to add an optional keyword argument to it as well, so when called it could look like either of these: (blah :specialthingy 0 body morebody lotsofbody) (blah body morebody lotsofboy) How can I do that? Note that I'm using Clojure 1.2, so I'm also using the new optional keyword argument destructuring stuff. I naively tried to do this: (defmacro blah [& {specialthingy :specialthingy} & body]) But obviously that didn't work out well. How can I accomplish this or something similar?

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  • Is it possible to pass arithmetic operators to a method in java?

    - by drJames
    Right now I'm going to have to write a method that looks like this: public String Calculate(String Operator, Double Operand1, Double Operand2) { if (Operator.equals("+")) { return String.valueOf(Operand1 + Operand2); } else if (Operator.equals("-")) { return String.valueOf(Operand1 - Operand2); } else if (Operator.equals("*")) { return String.valueOf(Operand1 * Operand2); } else { return "error..."; } } It would be nice if I could write the code more like this: public String Calculate(String Operator, Double Operand1, Double Operand2) { return String.valueOf(Operand1 Operator Operand2); } So Operator would replace the Arithmetic Operators (+, -, *, /...) Does anyone know if something like this is possible in java?

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  • Is it possible to pass arithmatic operators to a method in java?

    - by user349611
    Right now I'm going to have to write a method that looks like this: public String Calculate(String Operator, Double Operand1, Double Operand2) { if (Operator.equals("+")) { return String.valueOf(Operand1 + Operand2); } else if (Operator.equals("-")) { return String.valueOf(Operand1 - Operand2); } else if (Operator.equals("*")) { return String.valueOf(Operand1 * Operand2); } else { return "error..."; } } It would be nice if I could write the code more like this: public String Calculate(String Operator, Double Operand1, Double Operand2) { return String.valueOf(Operand1 Operator Operand2); } So Operator would replace the Arithmetic Operators (+, -, *, /...) Does anyone know if something like this is possible in java?

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  • Use of .apply() with 'new' operator. Is this possible?

    - by Premasagar
    In JavaScript, I want to create an object instance (via the new operator), but pass an arbitrary number of arguments to the constructor. Is this possible? What I want to do is something like this (but the code below does not work): function Something(){ // init stuff } function createSomething(){ return new Something.apply(null, arguments); } var s = createSomething(a,b,c); // 's' is an instance of Something The Answer From the responses here, it became clear that there's no in-built way to call .apply() with the new operator. However, people suggested a number of really interesting solutions to the problem. My preferred solution was this one from Matthew Crumley (I've modified it to pass the arguments property): var createSomething = (function() { function F(args) { return Something.apply(this, args); } F.prototype = Something.prototype; return function() { return new F(arguments); } })();

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  • Search multiple search engines with a single keyword at the same time in Chrome?

    - by cptloop
    I want to search multiple websites at once by using a keyword trigger in Google Chrome. I am trying to achieve this with Javascript as described in this topic over at mozillazine. This is the code that supposedly works in Firefox: javascript:void(window.open('http://www.google.com/search?q=%s'));void(window.open('http://www.altavista.com/web/results?q=%s')) I have tried to insert this code into the "URL with %s in place of query" but nothing happens when I invoke it. Is it possible to get this to work this way or another in Chrome?

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  • Why can't I sort this container?

    - by Knowing me knowing you
    Please don't mind that there is no insert fnc and that data are hardcoded. The main purpouse of it is to correctly implement iterator for this container. //file Set.h #pragma once template<class T> class Set { template<class T> friend ostream& operator<<(ostream& out, const Set<T>& obj); private: T** myData_; std::size_t mySize_; std::size_t myIndex_; public: Set(); class iterator : public std::iterator<std::random_access_iterator_tag, T*> { private: T** itData_; public: iterator(T** obj) { itData_ = obj; } T operator*() const { return **itData_; } /*Comparing values of two iterators*/ bool operator<(const iterator& obj) { return **itData_ < **obj.itData_; } /*Substracting two iterators*/ difference_type operator-(const iterator& obj) { return itData_ - obj.itData_; } /*Moving iterator backward for value*/ iterator operator-(const int value) { return itData_ - value; } /*Adding two iterators*/ difference_type operator+(const iterator& obj) { return itData_ + obj.itData_; } /*Moving iterator forward for value*/ iterator operator+(const int value) { return itData_ + value; } bool operator!=(const iterator& obj) { return (itData_ != obj.itData_); } bool operator==(const iterator& obj) { return (itData_ == obj.itData_); } T** operator++() { return ++itData_; } T** operator--() { return --itData_; } }; iterator begin() const { return myData_; } iterator end() const { return myData_ + myIndex_; } }; template<class T> ostream& operator<<(ostream& out, const Set<T>& obj) { for (int i = 0;i < 3; ++i) { out << *obj.myData_[i] << "\n"; } return out; } //file Set_impl.h #pragma once #include "stdafx.h" #include "Set.h" template<class T> Set<T>::Set() { mySize_ = 3; myIndex_ = 3; myData_ = new T*[mySize_]; myData_[0] = new T(3); myData_[1] = new T(1); myData_[2] = new T(2); } //main include "stdafx.h" #include "Set_impl.h" int _tmain(int argc, _TCHAR* argv[]) { Set<int> a; Set<int>::iterator beg_ = a.begin(); Set<int>::iterator end_ = a.end(); std::sort(beg_,end_);//WONT SORT THIS RANGE cin.get(); return 0; } Why sort can't accept this iterators even though I've provided all operators needed for sort to work? I think the best way to check what's going on is to paste this code and run it first. Thanks

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  • How do search engines handle hyphenated words?

    - by NinjaKC
    I am not sure my title fully explains what I mean. I thought this might be an interesting question. If I had a set of keywords, broken with a dash or 2, will search engines consider the dashed split keyword as maybe a full keyword? Say I have a site that sort of breaks words down, like the dictionary sites do. So a keyword for that page, might end up in the page, and / or the URL, as broken by dashes. Key-word = keyword Co-op-er-at-ive = cooperative Pho-to-gra-phy = Photography www.example.com/key-word/ www.example.com/co-op-er-at-ive/ www.example.com/pho-to-gra-phy/ I know search engines will consider a dash (at least Google) as a space, and understand it as multiple words. But in the English language, a dash can also break a word down (at least I think it can, can't it?), so will search engines also take this into consideration? I did a 'little' research, I Googled some words and placed random dashes, and it returned the words I searched for, but this could be considered a typo from the user on Google's search end, so really I am wondering if I can purposely put a dash in a keyword, and have the search engine spiders still catch that keyword as the real word without dashes? I've done a little Googling and looking here on Stackoverflow, but everything comes down to dashes for multiple words, not really the specific thing I'm trying to figure out. Hopefully that makes sense, I am not an expert in SEO, yet, but get the basics and have been playing, and this is just really a random question to satisfy my knowledge of playing :P

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  • nginx subdomain rewrite

    - by ivan73
    I need a nginx rewrite rule to rewrite from: http://some-keyword.example.com to www. example.com/keyword.php?keyword=$some-keyword while domain without www in front still rewrites to www.example.com and 'www' isn't taken as a keyword. Please could you help me to solve this problem, how to write these two rules?

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  • How do I keep the keyword.url setting in firefox to default when you restart the browser without del

    - by user34801
    I am on the latest version of Firefox (not beta or anything like that) and currently my keyword.url is stuck on search.google.com (which I don't remember setting even though the about:config says it's a user setting. Can someone tell me how to set it back to default and keep it at default when I reset my browser? I do not want to delete prefs.js as I do not want to go thru setting up all the extension settings I have just to have my location bar search google (if this is the only way then I'll stick with searching from the search bar instead). I've checked all my extensions that may effect the location bar but could not find anything that says it would change the default search engine for this. I've also tried to open the prefs.js in wordpad or notepad but it just ends up freezing when trying to edit it at all (yes the browser is closed at the time). I also deleted the prefs-1.js (along with 2 others) that were older (after trying to rename those to prefs.js and see if this corrects it. It might have but had such old extension settings I went back to my latest prefs.js with this one issue instead of the issue of setting back up a ton of extensions. I can give any other info if needed, someone please help me fix this issue if possible.

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  • How to write a streaming 'operator<<' that can take arbitary containers (of type 'X')?

    - by Drew Dormann
    I have a C++ class "X" which would have special meaning if a container of them were to be sent to a std::ostream. I originally implemented it specifically for std::vector<X>: std::ostream& operator << ( std::ostream &os, const std::vector<X> &c ) { // The specialized logic here expects c to be a "container" in simple // terms - only that c.begin() and c.end() return input iterators to X } If I wanted to support std::ostream << std::deque<X> or std::ostream << std::set<X> or any similar container type, the only solution I know of is to copy-paste the entire function and change only the function signature! Is there a way to generically code operator << ( std::ostream &, const Container & )? ("Container" here would be any type that satisfies the commented description above.)

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  • Passing arguments to objects created using the new operator?

    - by Abhijit
    Hi guys, I have a small C++ problem to which I don't know the best solution. I have two classes A and B as follows: class A { int n; B* b; public: A(int num): n(num) { b = new B[n]; for (int i = 0; i < n; i++) { b[i].setRef(this); } } ~A() { delete [] b; } }; class B { A* a; public: B() { } B(A* aref) { a = aref; } void setRef(A* aref) { a = aref; } }; I am creating an object of class A by passing to its constructor the number of objects of class B I want to be created. I want every object of class B to hold a pointer to the class A object that creates it. I think the best way to do this would be by passing the pointer to the class A object as a constructor argument to the class B object. However, since I'm using the new operator, the no-args constructor for class B is called. As a result, the only solution I can see here is calling the setRef(A*) method for every object of class B after it has been constructed using the new operator. Is there a better solution/design pattern that would be more applicable here? Would using placement new for class B be a better solution? Thanks in advance for your help.

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  • Is Perl's flip-flop operator bugged? It has global state, how can I reset it?

    - by Evan Carroll
    I'm dismayed. Ok, so this was probably the most fun perl bug I've ever found. Even today I'm learning new stuff about perl. Essentially, the flip-flop operator .. which returns false until the left-hand-side returns true, and then true until the right-hand-side returns false keep global state (or that is what I assume.) My question is can I reset it, (perhaps this would be a good addition to perl4-esque hardly ever used reset())? Or, is there no way to use this operator safely? I also don't see this (the global context bit) documented anywhere in perldoc perlop is this a mistake? Code use feature ':5.10'; use strict; use warnings; sub search { my $arr = shift; grep { !( /start/ .. /never_exist/ ) } @$arr; } my @foo = qw/foo bar start baz end quz quz/; my @bar = qw/foo bar start baz end quz quz/; say 'first shot - foo'; say for search \@foo; say 'second shot - bar'; say for search \@bar; Spoiler $ perl test.pl first shot foo bar second shot

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