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  • OBJ-C - Getting a class name from a class hierarchy

    - by mmmilo
    Let's say I have the following headers: @interface SuperClass : NSObject @interface SubClass : SuperClass I'm alloc'ing an instance of the class by doing: SubClass *sc = [[SubClass alloc] init]; In my SuperClass.m: - (id) init { self = [super init]; if (self != nil) { NSString *cString = NSStringFromClass([self class]); } return self; } Simple, right? My question is: how can I get cString to return the SuperClass class, rather than the SubClass class? Since the SubClass is alloc'd/init'd, is this not possible? Thanks!

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  • deleting and reusing a temp table in a stored precedures

    - by Sheagorath
    Hi I need to SELECT INTO a temp table multiple times with a loop but I just can't do it, because after the table created( in SELECT into you can't simply drop the table at the end of the loop because you can't delete a table and create it again in the same batch. so how can I delete a table in a stored procedure and create it again? here is a snippet of where I am actualy using the temp table which is supposed to be a pivoting algorithm: WHILE @offset<@NumDays BEGIN SELECT bg.*, j.ID, j.time, j.Status INTO #TEMP1 FROM #TEMP2 AS bg left outer join PersonSchedule j on bg.PersonID = j.PersonID and bg.TimeSlotDateTime = j.TimeSlotDateTime and j.TimeSlotDateTime = @StartDate + @offset DROP TABLE #TEMP2; SELECT * INTO #TEMP2 FROM #TEMP1 DROP TABLE #TEMP1 SET @offset = @offset + 1 END

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  • How to insert the recently inserteddata of a table to others DB's Table? See description...

    - by Parth
    I am using MySQL DB and I have created a PHP script for the following, now i need the idea for the below asked question.... please help... I have a table called audit trail whose structure is: id, trackid, table, operation, newvalue, oldvalue, field, changedone I have created triggers for insert/update/delete for every table of same DB, now whenever there is change in ny DB the triggers get activated and updates the Audit trail table accordingly.. I am tracking these changes so that i can use these changes to be done on production DB which is of same structure as of this test DB. Also when the admin finds that he does not need the changes recently he did for production DB then he can rollback it using the Old Data it stored in Ausittrail table of test db. Now here in audit trail table structure, there will be an insert for every single field change like-wise if a table has 4 fields then the change in that tavle will insert 4 rows in audit trail.. Coming to the question now, How can i find the latest change done from the Audit table so that I can insert these changes in Production DB.

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  • how to integrate my users database table with the aspnet_users table that comes with asp.net members

    - by ooo
    i have a database that already has a users table COLUMNS: userID - int loginName - string First - string Last - string i just installed the asp.net membership table. Right now all of my tables are joined into my users table foreign keyed into the "userId" field How do i integrate asp.net_users table into my schema? here are the ideas i thought of: Add a membership_id field to my users table and on new inserts, include that new field in my users table. This seems like the cleanest way as i dont need to break any existing relationships. break all existing relationship and move all of the fields in my user table into the asp.net_users table. This seems like a pain but ultimately will lead to the most simple, normalized solution any thoughts?

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  • Control-Break Style ADF Table - Comparing Values with Previous Row

    - by Steven Davelaar
    Sometimes you need to display data in an ADF Faces table in a control-break layout style, where rows should be "indented" when the break column has the same value as in the previous row. In the screen shot below, you see how the table breaks on both the RegionId column as well as the CountryId column. To implement this I didn't use fancy SQL statements. The table is based on a straightforward Locations ViewObject that is based on the Locations entity object and the Countries reference entity object, and the join query was automatically created by adding the reference EO. To get the indentation in the ADF Faces table, we simple use two rendered properties on the RegionId and CountryId outputText items:  <af:column sortProperty="RegionId" sortable="false"            headerText="#{bindings.LocationsView1.hints.RegionId.label}"            id="c5">   <af:outputText value="#{row.RegionId}" id="ot2"                  rendered="#{!CompareWithPreviousRowBean['RegionId']}">     <af:convertNumber groupingUsed="false"                       pattern="#{bindings.LocationsView1.hints.RegionId.format}"/>   </af:outputText> </af:column> <af:column sortProperty="CountryId" sortable="false"            headerText="#{bindings.LocationsView1.hints.CountryId.label}"            id="c1">   <af:outputText value="#{row.CountryId}" id="ot5"                  rendered="#{!CompareWithPreviousRowBean['CountryId']}"/> </af:column> The CompareWithPreviousRowBean managed bean is defined in request scope and is a generic bean that can be used for all the tables in your application that needs this layout style. As you can see the bean is a Map-style bean where we pass in the name of the attribute that should be compared with the previous row. The get method in the bean that is called returns boolean false when the attribute has the same value in the same row. Here is the code of the get method:  public Object get(Object key) {   String attrName = (String) key;   boolean isSame = false;   // get the currently processed row, using row expression #{row}   JUCtrlHierNodeBinding row = (JUCtrlHierNodeBinding) resolveExpression(getRowExpression());   JUCtrlHierBinding tableBinding = row.getHierBinding();   int rowRangeIndex = row.getViewObject().getRangeIndexOf(row.getRow());   Object currentAttrValue = row.getRow().getAttribute(attrName);   if (rowRangeIndex > 0)   {     Object previousAttrValue = tableBinding.getAttributeFromRow(rowRangeIndex - 1, attrName);     isSame = currentAttrValue != null && currentAttrValue.equals(previousAttrValue);   }   else if (tableBinding.getRangeStart() > 0)   {     // previous row is in previous range, we create separate rowset iterator,     // so we can change the range start without messing up the table rendering which uses     // the default rowset iterator     int absoluteIndexPreviousRow = tableBinding.getRangeStart() - 1;     RowSetIterator rsi = null;     try     {       rsi = tableBinding.getViewObject().getRowSet().createRowSetIterator(null);       rsi.setRangeStart(absoluteIndexPreviousRow);       Row previousRow = rsi.getRowAtRangeIndex(0);       Object previousAttrValue = previousRow.getAttribute(attrName);       isSame = currentAttrValue != null && currentAttrValue.equals(previousAttrValue);     }     finally     {       rsi.closeRowSetIterator();     }   }   return isSame; } The row expression defaults to #{row} but this can be changed through the rowExpression  managed property of the bean.  You can download the sample application here.

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  • apache eat up too many ram per child

    - by mrc4r7m4n
    Hello to everyone. I've got fallowing problem: Apache eat to many ram per child. The fallowing comments shows: cat /etc/redhat-release -- Fedora release 8 (Werewolf) free -m: total used free shared buffers cached Mem: 3566 3136 429 0 339 1907 -/+ buffers/cache: 889 2676 Swap: 4322 0 4322 I know that you will say that there is nothing to worry about because swap is not use, but i think it's not use for now. 3.httpd -v: Server version: Apache/2.2.14 (Unix) 4.httpd -l: Compiled in modules: core.c mod_authn_file.c mod_authn_default.c mod_authz_host.c mod_authz_groupfile.c mod_authz_user.c mod_authz_default.c mod_auth_basic.c mod_include.c mod_filter.c mod_log_config.c mod_env.c mod_setenvif.c mod_version.c mod_ssl.c prefork.c http_core.c mod_mime.c mod_status.c mod_autoindex.c mod_asis.c mod_cgi.c mod_negotiation.c mod_dir.c mod_actions.c mod_userdir.c mod_alias.c mod_rewrite.c mod_so.c 5.List of loaded dynamic modules: LoadModule authz_host_module modules/mod_authz_host.so LoadModule include_module modules/mod_include.so LoadModule log_config_module modules/mod_log_config.so LoadModule setenvif_module modules/mod_setenvif.so LoadModule mime_module modules/mod_mime.so LoadModule autoindex_module modules/mod_autoindex.so LoadModule vhost_alias_module modules/mod_vhost_alias.so LoadModule negotiation_module modules/mod_negotiation.so LoadModule dir_module modules/mod_dir.so LoadModule alias_module modules/mod_alias.so LoadModule rewrite_module modules/mod_rewrite.so LoadModule proxy_module modules/mod_proxy.so LoadModule cgi_module modules/mod_cgi.so 6.My prefrok directive <IfModule prefork.c> StartServers 8 MinSpareServers 5 MaxSpareServers 25 ServerLimit 80 MaxClients 80 MaxRequestsPerChild 4000 </IfModule> KeepAliveTimeout 6 MaxKeepAliveRequests 100 KeepAlive On 7.top -u apache: ctrl+ M top - 09:19:42 up 2 days, 19 min, 2 users, load average: 0.85, 0.87, 0.80 Tasks: 113 total, 1 running, 112 sleeping, 0 stopped, 0 zombie Cpu(s): 7.3%us, 15.7%sy, 0.0%ni, 75.7%id, 0.0%wa, 0.7%hi, 0.7%si, 0.0%st Mem: 3652120k total, 3149964k used, 502156k free, 348048k buffers Swap: 4425896k total, 0k used, 4425896k free, 1944952k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 16956 apache 20 0 700m 135m 100m S 0.0 3.8 2:16.78 httpd 16953 apache 20 0 565m 130m 96m S 0.0 3.7 1:57.26 httpd 16957 apache 20 0 587m 129m 102m S 0.0 3.6 1:47.41 httpd 16955 apache 20 0 567m 126m 93m S 0.0 3.6 1:43.60 httpd 17494 apache 20 0 626m 125m 96m S 0.0 3.5 1:58.77 httpd 17515 apache 20 0 540m 120m 88m S 0.0 3.4 1:45.57 httpd 17516 apache 20 0 573m 120m 88m S 0.0 3.4 1:50.51 httpd 16954 apache 20 0 551m 120m 88m S 0.0 3.4 1:52.47 httpd 17493 apache 20 0 586m 120m 94m S 0.0 3.4 1:51.02 httpd 17279 apache 20 0 568m 117m 87m S 16.0 3.3 1:51.87 httpd 17302 apache 20 0 560m 116m 90m S 0.3 3.3 1:59.06 httpd 17495 apache 20 0 551m 116m 89m S 0.0 3.3 1:47.51 httpd 17277 apache 20 0 476m 114m 81m S 0.0 3.2 1:37.14 httpd 30097 apache 20 0 536m 113m 83m S 0.0 3.2 1:47.38 httpd 30112 apache 20 0 530m 112m 81m S 0.0 3.2 1:40.15 httpd 17513 apache 20 0 516m 112m 85m S 0.0 3.1 1:43.92 httpd 16958 apache 20 0 554m 111m 82m S 0.0 3.1 1:44.18 httpd 1617 apache 20 0 487m 111m 85m S 0.0 3.1 1:31.67 httpd 16952 apache 20 0 461m 107m 75m S 0.0 3.0 1:13.71 httpd 16951 apache 20 0 462m 103m 76m S 0.0 2.9 1:28.05 httpd 17278 apache 20 0 497m 103m 76m S 0.0 2.9 1:31.25 httpd 17403 apache 20 0 537m 102m 79m S 0.0 2.9 1:52.24 httpd 25081 apache 20 0 412m 101m 70m S 0.0 2.8 1:01.74 httpd I guess thats all information needed to help me solve this problem. I think the virt memory is to big, the same res. The consumption of ram is increasing all the time. Maybe it's memory leak because i see there is so many static modules compiled. Could someone help me with this issue? Thank you in advance.

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  • RedHat 5.5 server does not show per processor memory utilization

    - by Mike S
    I have been searching all over internet but not finding any leads. I have a system with a memory leak that I am trying to troubleshoot. Unfortunately I am not able to see per processor memory utilization. Here are the outputs of TOP and PS commands. Linux SERVER_NAME 2.6.18-194.8.1.el5 #1 SMP Wed Jun 23 10:52:51 EDT 2010 x86_64 x86_64 x86_64 GNU/Linux top - 09:17:13 up 18:43, 3 users, load average: 0.00, 0.00, 0.00 Tasks: 375 total, 1 running, 373 sleeping, 0 stopped, 1 zombie Cpu(s): 0.0%us, 0.0%sy, 0.0%ni,100.0%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Mem: 32922828k total, 32776712k used, 146116k free, 267128k buffers Swap: 5245212k total, 0k used, 5245212k free, 32141044k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 1 root 15 0 10348 744 620 S 0.0 0.0 0:05.65 init 2 root RT -5 0 0 0 S 0.0 0.0 0:00.05 migration/0 3 root 34 19 0 0 0 S 0.0 0.0 0:00.00 ksoftirqd/0 4 root RT -5 0 0 0 S 0.0 0.0 0:00.00 watchdog/0 5 root RT -5 0 0 0 S 0.0 0.0 0:00.00 migration/1 6 root 34 19 0 0 0 S 0.0 0.0 0:00.00 ksoftirqd/1 7 root RT -5 0 0 0 S 0.0 0.0 0:00.00 watchdog/1 8 root RT -5 0 0 0 S 0.0 0.0 0:00.00 migration/2 9 root 34 19 0 0 0 S 0.0 0.0 0:00.00 ksoftirqd/2 10 root RT -5 0 0 0 S 0.0 0.0 0:00.00 watchdog/2 11 root RT -5 0 0 0 S 0.0 0.0 0:00.01 migration/3 12 root 34 19 0 0 0 S 0.0 0.0 0:00.01 ksoftirqd/3 13 root RT -5 0 0 0 S 0.0 0.0 0:00.00 watchdog/3 14 root RT -5 0 0 0 S 0.0 0.0 0:00.00 migration/4 15 root 34 19 0 0 0 S 0.0 0.0 0:00.01 ksoftirqd/4 16 root RT -5 0 0 0 S 0.0 0.0 0:00.00 watchdog/4 17 root RT -5 0 0 0 S 0.0 0.0 0:00.00 migration/5 18 root 34 19 0 0 0 S 0.0 0.0 0:00.00 ksoftirqd/5 19 root RT -5 0 0 0 S 0.0 0.0 0:00.00 watchdog/5 20 root RT -5 0 0 0 S 0.0 0.0 0:00.00 migration/6 % ps -auxf | sort -nr -k 4 | head -10 Warning: bad syntax, perhaps a bogus '-'? See /usr/share/doc/procps-3.2.7/FAQ xfs 6205 0.0 0.0 23316 3892 ? Ss Aug19 0:00 xfs -droppriv -daemon uuidd 6101 0.0 0.0 60976 224 ? Ss Aug19 0:00 /usr/sbin/uuidd USER PID %CPU %MEM VSZ RSS TTY STAT START TIME COMMAND smmsp 6130 0.0 0.0 57900 1784 ? Ss Aug19 0:00 sendmail: Queue runner@01:00:00 for /var/spool/clientmqueue rpc 5126 0.0 0.0 8052 632 ? Ss Aug19 0:00 portmap root 99 0.0 0.0 0 0 ? S< Aug19 0:00 [events/1] root 98 0.0 0.0 0 0 ? S< Aug19 0:00 [events/0] root 97 0.0 0.0 0 0 ? S< Aug19 0:00 [watchdog/31] root 96 0.0 0.0 0 0 ? SN Aug19 0:00 [ksoftirqd/31] root 95 0.0 0.0 0 0 ? S< Aug19 0:00 [migration/31] Any help with this is appretiate.

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  • django modelformset - one form per related table row

    - by Toby
    Hello, I have two models: class Model1(): name = CharField() url = CharField() class Model2(): model1 = ForeignKey(Model1) user = ForeignKey(User) zzz = CharField() There are 5 rows for model1 in the database, these are fixed and will rarely change. I need to display a formset for model2 that allows users to enter the zzz value, the formset must always show one form per row in the model1 table, the label for each form in the formset must be the name of the related model1. If the user deletes a model2 in the formset the next time the page loads it will render an empty zzz value for that form and the user must be able to edit the previous zzz value - meaning it must be pre populated with all model2 rows associated with the user. The idea is to print each row in the model1 table as a form instead of the user selecting the related model1 name in a select box. I know its not that complicated, but I'm seriously stumped and keep going round in circles!! Many thanks in advance. Similar to http://stackoverflow.com/questions/298779/form-or-formset-to-handle-multiple-table-rows-in-django

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  • Cost Comparison Hard Disk Drive to Solid State Drive on Price per Gigabyte - dispelling a myth!

    - by tonyrogerson
    It is often said that Hard Disk Drive storage is significantly cheaper per GiByte than Solid State Devices – this is wholly inaccurate within the database space. People need to look at the cost of the complete solution and not just a single component part in isolation to what is really required to meet the business requirement. Buying a single Hitachi Ultrastar 600GB 3.5” SAS 15Krpm hard disk drive will cost approximately £239.60 (http://scan.co.uk, 22nd March 2012) compared to an OCZ 600GB Z-Drive R4 CM84 PCIe costing £2,316.54 (http://scan.co.uk, 22nd March 2012); I’ve not included FusionIO ioDrive because there is no public pricing available for it – something I never understand and personally when companies do this I immediately think what are they hiding, luckily in FusionIO’s case the product is proven though is expensive compared to OCZ enterprise offerings. On the face of it the single 15Krpm hard disk has a price per GB of £0.39, the SSD £3.86; this is what you will see in the press and this is what sales people will use in comparing the two technologies – do not be fooled by this bullshit people! What is the requirement? The requirement is the database will have a static size of 400GB kept static through archiving so growth and trim will balance the database size, the client requires resilience, there will be several hundred call centre staff querying the database where queries will read a small amount of data but there will be no hot spot in the data so the randomness will come across the entire 400GB of the database, estimates predict that the IOps required will be approximately 4,000IOps at peak times, because it’s a call centre system the IO latency is important and must remain below 5ms per IO. The balance between read and write is 70% read, 30% write. The requirement is now defined and we have three of the most important pieces of the puzzle – space required, estimated IOps and maximum latency per IO. Something to consider with regard SQL Server; write activity requires synchronous IO to the storage media specifically the transaction log; that means the write thread will wait until the IO is completed and hardened off until the thread can continue execution, the requirement has stated that 30% of the system activity will be write so we can expect a high amount of synchronous activity. The hardware solution needs to be defined; two possible solutions: hard disk or solid state based; the real question now is how many hard disks are required to achieve the IO throughput, the latency and resilience, ditto for the solid state. Hard Drive solution On a test on an HP DL380, P410i controller using IOMeter against a single 15Krpm 146GB SAS drive, the throughput given on a transfer size of 8KiB against a 40GiB file on a freshly formatted disk where the partition is the only partition on the disk thus the 40GiB file is on the outer edge of the drive so more sectors can be read before head movement is required: For 100% sequential IO at a queue depth of 16 with 8 worker threads 43,537 IOps at an average latency of 2.93ms (340 MiB/s), for 100% random IO at the same queue depth and worker threads 3,733 IOps at an average latency of 34.06ms (34 MiB/s). The same test was done on the same disk but the test file was 130GiB: For 100% sequential IO at a queue depth of 16 with 8 worker threads 43,537 IOps at an average latency of 2.93ms (340 MiB/s), for 100% random IO at the same queue depth and worker threads 528 IOps at an average latency of 217.49ms (4 MiB/s). From the result it is clear random performance gets worse as the disk fills up – I’m currently writing an article on short stroking which will cover this in detail. Given the work load is random in nature looking at the random performance of the single drive when only 40 GiB of the 146 GB is used gives near the IOps required but the latency is way out. Luckily I have tested 6 x 15Krpm 146GB SAS 15Krpm drives in a RAID 0 using the same test methodology, for the same test above on a 130 GiB for each drive added the performance boost is near linear, for each drive added throughput goes up by 5 MiB/sec, IOps by 700 IOps and latency reducing nearly 50% per drive added (172 ms, 94 ms, 65 ms, 47 ms, 37 ms, 30 ms). This is because the same 130GiB is spread out more as you add drives 130 / 1, 130 / 2, 130 / 3 etc. so implicit short stroking is occurring because there is less file on each drive so less head movement required. The best latency is still 30 ms but we have the IOps required now, but that’s on a 130GiB file and not the 400GiB we need. Some reality check here: a) the drive randomness is more likely to be 50/50 and not a full 100% but the above has highlighted the effect randomness has on the drive and the more a drive fills with data the worse the effect. For argument sake let us assume that for the given workload we need 8 disks to do the job, for resilience reasons we will need 16 because we need to RAID 1+0 them in order to get the throughput and the resilience, RAID 5 would degrade performance. Cost for hard drives: 16 x £239.60 = £3,833.60 For the hard drives we will need disk controllers and a separate external disk array because the likelihood is that the server itself won’t take the drives, a quick spec off DELL for a PowerVault MD1220 which gives the dual pathing with 16 disks 146GB 15Krpm 2.5” disks is priced at £7,438.00, note its probably more once we had two controller cards to sit in the server in, racking etc. Minimum cost taking the DELL quote as an example is therefore: {Cost of Hardware} / {Storage Required} £7,438.60 / 400 = £18.595 per GB £18.59 per GiB is a far cry from the £0.39 we had been told by the salesman and the myth. Yes, the storage array is composed of 16 x 146 disks in RAID 10 (therefore 8 usable) giving an effective usable storage availability of 1168GB but the actual storage requirement is only 400 and the extra disks have had to be purchased to get the  IOps up. Solid State Drive solution A single card significantly exceeds the IOps and latency required, for resilience two will be required. ( £2,316.54 * 2 ) / 400 = £11.58 per GB With the SSD solution only two PCIe sockets are required, no external disk units, no additional controllers, no redundant controllers etc. Conclusion I hope by showing you an example that the myth that hard disk drives are cheaper per GiB than Solid State has now been dispelled - £11.58 per GB for SSD compared to £18.59 for Hard Disk. I’ve not even touched on the running costs, compare the costs of running 18 hard disks, that’s a lot of heat and power compared to two PCIe cards!Just a quick note: I've left a fair amount of information out due to this being a blog! If in doubt, email me :)I'll also deal with the myth that SSD's wear out at a later date as well - that's just way over done still, yes, 5 years ago, but now - no.

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  • Specifying distinct sequence per table in Hibernate on subclasses

    - by gutch
    Is there a way to specify distinct sequences for each table in Hibernate, if the ID is defined on a mapped superclass? All entities in our application extend a superclass called DataObject like this: @MappedSuperclass public abstract class DataObject implements Serializable { @Id @GeneratedValue(strategy = GenerationType.SEQUENCE) @Column(name = "id") private int id; } @Entity @Table(name = "entity_a") public class EntityA extends DataObject { ... } @Entity @Table(name = "entity_b") public class EntityB extends DataObject { ... } This causes all entities to use a shared sequence, the default hibernate_sequence. What I would like to do is use a separate sequence for each entity, for example entity_a_sequence and entity_b_sequence in the example above. If the ID were specified on the subclasses then I could use the @SequenceGenerator annotation to specify a sequence for each entity, but in this case the ID is on the superclass. Given that ID is in the superclass, is there a way I can use a separate sequence for each entity — and if so, how? (We are using PostgreSQL 8.3, in case that's relevant)

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  • [PHP] building html tables from query data... faster?

    - by Andrew Heath
    With my limited experience/knowledge I am using the following structure to generate HTML tables on the fly from MySQL queries: $c = 0; $t = count($results); $table = '<table>'; while ($c < $t) { $table .= "<tr><td>$results[0]</td><td>$results[1]</td> (etc etc) </tr>"; ++$c; } $table .= '</table>'; this works, obviously. But for tables with 300+ rows there is a noticeable delay in pageload while the script builds the table. Currently the maximum results list is only about 1,100 rows, and the wait isn't long, but there's clearly a wait. Are there other methods for outputting an HTML table that are faster than my WHILE loop? (PHP only please...)

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  • Building html tables from query data... faster?

    - by Andrew Heath
    With my limited experience/knowledge I am using the following structure to generate HTML tables on the fly from MySQL queries: $c = 0; $t = count($results); $table = '<table>'; while ($c < $t) { $table .= "<tr><td>$results[0]</td><td>$results[1]</td> (etc etc) </tr>"; ++$c; } $table .= '</table>'; this works, obviously. But for tables with 300+ rows there is a noticeable delay in pageload while the script builds the table. Currently the maximum results list is only about 1,100 rows, and the wait isn't long, but there's clearly a wait. Are there other methods for outputting an HTML table that are faster than my WHILE loop? (PHP only please...)

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  • Database Design Question

    - by deniz
    Hi, I am designing a database for a project. I have a table that has 10 columns, most of them are used whenever the table is accessed, and I need to add 3 more rows; View Count Thumbs Up (count) Thumbs Down (Count) which will be used on %90 of the queries when the table is accessed. So, my question is that whether it is better to break the table up and create new table which will have these 3 columns + Foreign ID, or just make it 13 columns and use no joins? Since these columns will be used frequently, I guess adding 3 more columns is better, but if I need to create 10 more columns which will be used %90 of the time, should I add them as well, or create a new table and use joins? I am not sure when to break the table if the columns are used very frequently. Do you have any suggestions? Thanks in advance,

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  • Table per subclass inheritance relationship: How to query against the Parent class without loading a

    - by Arthur Ronald F D Garcia
    Suppose a Table per subclass inheritance relationship which can be described bellow (From wikibooks.org - see here) Notice Parent class is not abstract @Entity @Inheritance(strategy=InheritanceType.JOINED) public class Project { @Id private long id; // Other properties } @Entity @Table(name="LARGEPROJECT") public class LargeProject extends Project { private BigDecimal budget; } @Entity @Table(name="SMALLPROJECT") public class SmallProject extends Project { } I have a scenario where i just need to retrieve the Parent class. Because of performance issues, What should i do to run a HQL query in order to retrieve the Parent class and just the Parent class without loading any subclass ???

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  • select from multiple tables with different columns

    - by Qaiser Iftikhar
    Say I got this sql schema. Table Job: id,title, type, is_enabled Table JobFileCopy: job_id,from_path,to_path Table JobFileDelete: job_id, file_path Table JobStartProcess: job_id, file_path, arguments, working_directory There are many other tables with varying number of columns and they all got foreign key job_id which is linked to id in table Job. My questions: Is this the right approach? I don't have requirement to delete anything at anytime. I will require to select and insert mostly. Secondly, what is the best approach to get the list of jobs with relevant details from all the different tables in a single database hit? e.g I would like to select top 20 jobs with details, their details can be in any table (depends on column type in table Job) which I don't know until runtime. Thanks in advance. Regards,

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  • How to edit the code table for one row only?

    - by TomatoSandwich
    I understand that dw-control.Object.columnname.Values("Red~tR/Blue~tB) changes columnname's values for all rows, but is there code that can just change the dropdown values of a code table for specific row/s? I've tried dw-control.Object.columnname[row].Values but I get R0039 in response :(

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  • How do I add complex where clause to Zend Table Select?

    - by AD
    I searched the Web and could not find anything that would show me a good solid example. My question is basically this: How do I convert this: SELECT * FROM table WHERE ((a = 1 AND b = 2) OR (c = 3 OR c = 4)) AND d = 5; To Zend syntax similar to this: $this -select() -from($this-_schema.'.'.$this-_name) -where('a = ?', '1'); So how can it be done? Thank a lot in advance.

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  • Stored procedure with output parameters vs. table-valued function?

    - by abatishchev
    Which approach is better to use if I need a member (sp or func) returning 2 parameters: CREATE PROCEDURE Test @in INT, @outID INT OUT, @amount DECIMAL OUT AS BEGIN ... END or CREATE FUNCTION Test ( @in INT ) RETURNS @ret TABLE (outID INT, amount DECIMAL) AS BEGIN ... END What are pros and cons of each approach considering that the result will passed to another stored procedure: EXEC Foobar @outID, @outAmount

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  • How can I convert a file to an HTML table using Perl?

    - by user329313
    I am trying to write a simple Perl CGI script that: runs a CLI script reads the resulting .out file and converts the data in the file to an HTML table. Here is some sample data from the .out file: 10.255.202.1 2472327594 1720341 10.255.202.21 2161941840 1484352 10.255.200.0 1642646268 1163742 10.255.200.96 1489876452 1023546 10.255.200.26 1289738466 927513 10.255.202.18 1028316222 706959 10.255.200.36 955477836 703926 Any help would be much appreciated.

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  • How do I remove separation between rows in a HTML table?

    - by Roman
    I have a html table with 3 rows and 1 column. In the top and button row I have images and in the middle row I have div. Between my rows I see a separation (I see background of my page). I tried to set all padding and margins to zero (for tables, div and images) and I still have this separation. Can anybody, please, help me to solve this problem. The page is here:

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