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  • How do I show the print with AJAX/jQuery?

    - by Doug
    So I'm trying to understand this whole AJAX/jQuery thing. Right now, when I run this PHP script alone, I would have to wait and watch the wheel spin until it's done with the loop and then it will load. while ( $row = mysql_fetch_array($res) ) { postcode_to_storm( $row['Test'] ); $dom = new DOMDocument(); @$dom->loadHTML($result); $xPath = new DOMXPath($dom); $failInvite = 'Rejected'; $findFalse = strpos($result, $failInvite); if ( $findFalse == true ) { $array[$i] = $row['Test']; $i++; echo $array[$i]}; } } Now, how do I use AJAX/jQuery to show echo $array[$i]}; everytime it is invoked instead of waiting for the whole process to complete?

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  • Determine week number based on starting date

    - by kreetiv
    I need help to create a function to determine the week number based on these 2 parameters: Starting date Specified date For example, if I specify April 7, 2010 as the starting date & passed April 20, 2010 as the date to lookup, I would like the function to return WEEK 2. Another example, if I set March 6, 2010 as starting date and looked up April 5, 2010 then it should return WEEK 6. I appreciate your time and help.

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  • need an sql query

    - by CKeven
    I currently have two tables: 1. car(plate_number, brand, cid) 2. borrow(StartDate, endDate, brand, id) I want to write a query to get all available brand and count of available cars for each brand

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  • Store database, good pattern for simultaneous access

    - by dygi
    I am kinda new to database designing so i ask for some advices or some kind of a good pattern. The situation is that, there is one database, few tables and many users. How should i design the database, or / and which types of queries should i use, to make it work, if users can interact with the database simultaneously? I mean, they have access to and can change the same set of data. I was thinking about transactions, but I am not sure, if that is the right / good / the only solution. I will appreciate some google keywords too.

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  • User welcome message in php

    - by user225269
    How do I create a user welcome message in php. So that the user who has been logged on will be able to see his username. I have this code, but it doesn't seem to work. <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM users WHERE Username='$username'"); while($row = mysql_fetch_array($result)) { echo $row['Username']; echo "<br />"; } ?> I'm trying to make use of the data that is inputted in this login form: <form name="form1" method="post" action="verifylogin.php"> <td> <table border="0" cellpadding="3" cellspacing="1" bgcolor=""> <tr> <td colspan="16" height="25" style="background:#5C915C; color:white; border:white 1px solid; text-align: left"><strong><font size="2">Login User</strong></td> </tr> <tr> <td width="30" height="35"><font size="2">Username:</td> <td width="30"><input name="myusername" type="text" id="idnum" maxlength="5"></td> </tr> <tr> <td width="30" height="35" ><font size="2">Password:</td> <td width="30"><input name="mypassword" type="password" id="lname" maxlength="15"></td> </tr> <td align="right" width="30"><td align="right" width="30"><input type="submit" name="Submit" value="Submit" /></td> <td align="right" width="30"><input type="reset" name="Reset" value="Reset"></td></td> </tr> </form> But this, verifylogin.php, seems to be in the way. <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="school"; $tbl_name="users"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $myusername=$_POST['myusername']; $mypassword=$_POST['mypassword']; $myusername = stripslashes($myusername); $mypassword = stripslashes($mypassword); $myusername = mysql_real_escape_string($myusername); $mypassword = mysql_real_escape_string($mypassword); $sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'"; $result=mysql_query($sql); $count=mysql_num_rows($result); if($count==1){ session_register("myusername"); session_register("mypassword"); header("location:userpage.php"); } else { echo "Wrong Username or Password"; } ?> How do I do it? I always get this error when I run it: Notice: Undefined variable: username in C:\wamp\www\exp\userpage.php on line 53 Can you recommend of an easier on how I can achieve the same thing?

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  • paging php error - undefined index

    - by fusion
    i've a search form with paging. when the user enters the keyword initially, it works fine and displays the required output; however, it also shows this error: Notice: Undefined index: page in C:\Users\user\Documents\Projects\Pro\search.php on line 21 Call Stack: 0.0011 372344 1. {main}() C:\Users\user\Documents\Projects\Pro\search.php:0 . .and if the user clicks on the 'next' page, it shows no output with this error thrown: Notice: Undefined index: q in C:\Users\user\Documents\Projects\Pro\search.php on line 19 Call Stack: 0.0016 372048 1. {main}() C:\Users\user\Documents\Projects\Pro\search.php:0 this is my code: <?php ini_set('display_errors',1); error_reporting(E_ALL|E_STRICT); include 'config.php'; $search_result = ""; $search_result = trim($_GET["q"]); $page= $_GET["page"]; //Get the page number to show if($page == "") $page=1; $search_result = mysql_real_escape_string($search_result); //Check if the string is empty if ($search_result == "") { echo "<p class='error'>Search Error. Please Enter Your Search Query.</p>" ; exit(); } if ($search_result == "%" || $search_result == "_" || $search_result == "+" ) { echo "<p class='error1'>Search Error. Please Enter a Valid Search Query.</p>" ; exit(); } if(!empty($search_result)) { // the table to search $table = "thquotes"; // explode search words into an array $arraySearch = explode(" ", $search_result); // table fields to search $arrayFields = array(0 => "cQuotes"); $countSearch = count($arraySearch); $a = 0; $b = 0; $query = "SELECT cQuotes, vAuthor, cArabic, vReference FROM ".$table." WHERE ("; $countFields = count($arrayFields); while ($a < $countFields) { while ($b < $countSearch) { $query = $query."$arrayFields[$a] LIKE '%$arraySearch[$b]%'"; $b++; if ($b < $countSearch) { $query = $query." AND "; } } $b = 0; $a++; if ($a < $countFields) { $query = $query.") OR ("; } } $query = $query.")"; $result = mysql_query($query, $conn) or die ('Error: '.mysql_error()); $totalrows = mysql_num_rows($result); if($totalrows < 1) { echo '<span class="error2">No matches found for "'.$search_result.'"</span>'; } else { $limit = 3; //Number of results per page $numpages=ceil($totalrows/$limit); $query = $query." ORDER BY idQuotes LIMIT " . ($page-1)*$limit . ",$limit"; $result = mysql_query($query, $conn) or die('Error:' .mysql_error()); ?> <div class="caption">Search Results</div> <div class="center_div"> <table> <?php while ($row= mysql_fetch_array($result, MYSQL_ASSOC)) { $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); ?> <tr> <td style="text-align:right; font-size:15px;"><?php h($row['cArabic']); ?></td> <td style="font-size:16px;"><?php echo $cQuote; ?></td> <td style="font-size:12px;"><?php h($row['vAuthor']); ?></td> <td style="font-size:12px; font-style:italic; text-align:right;"><?php h($row['vReference']); ?></td> </tr> <?php } ?> </table> </div> <?php //Create and print the Navigation bar $nav=""; if($page > 1) { $nav .= "<a href=\"search.php?page=" . ($page-1) . "&string=" .urlencode($search_result) . "\"><< Prev</a>"; } for($i = 1 ; $i <= $numpages ; $i++) { if($i == $page) { $nav .= "<B>$i</B>"; }else{ $nav .= "<a href=\"search.php?page=" . $i . "&string=" .urlencode($search_result) . "\">$i</a>"; } } if($page < $numpages) { $nav .= "<a href=\"search.php?page=" . ($page+1) . "&searchstring=" .urlencode($search_result) . "\">Next >></a>"; } echo "<br /><br />" . $nav; } } else { exit(); } ?>

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  • Is there a fast way to change all the collation to utf8_unicode?

    - by Mark
    I have realised after making about 20 tables that I need to user utf8_unicode as opposed to utf8_general. What is the fastest way to change it using PHPMyAdmin? I had one idea: Export the database as SQL then using notepad run a find and replace on it and then reimport it... but it sounds like a bit of a headache. Is there a better way?

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  • Help needed to construct a SQL query

    - by song202y
    Need your help to get the list of suggested friends (who aren't friends of the current user but are friends of 2 or more of the current user's friends). The primary ordering should put people at the same school at the top, and the secondary ordering should put people with more common friends (that is, the number of people who are friends of that person and the current user) near the top. Users: user_id PK, user_name Profiles: user_id PK, school_name, ... Friendships: id PK, user_id FK, friend_id FK Thank you in advance. Joe

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  • What is the best way to go about grouping rows by the same timestamp?

    - by Luke
    Hello all. I am looking for some advice. I have rows of data in the database that i want to group together. There is a timestamp involved. That column is called date. What is the best way to go about grouping rows by the same timestamp. EDITED..... <? $result = mysql_query("SELECT * FROM ".TBL_FIXTURES." ORDER BY date"); $current_week = null; while ($row = mysql_fetch_assoc($result)) { if ($row['date'] != $current_week) { $current_week = $row['date']; echo 'Week ' . $current_week .': '; } echo $row['home_user']; echo $row['home_team']; echo $row['away_user']; echo $row['away_team']; } ?> I have this code. What i am trying to do is organise each round of fixtures in a row with a title Week 1 - date. I want Week 1 and the date and all fixtures with that date displayed. Then move onto week 2 and the date and all fixtures again. This should be done for every fixture in the database, so if there are 6 rounds of fixtures, there will be 6 dates and therefore 6 blocks of fixtures.. Please help, thanks

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  • Get a unique data in a SQL query

    - by Jensen
    Hi, I've a database who contain some datas in that form: icon(name, size, tag) (myicon.png, 16, 'twitter') (myicon.png, 32, 'twitter') (myicon.png, 128, 'twitter') (myicon.png, 256, 'twitter') (anothericon.png, 32, 'facebook') (anothericon.png, 128, 'facebook') (anothericon.png, 256, 'facebook') So as you see it, the name field is not uniq I can have multiple icons with the same name and they are separated with the size field. Now in PHP I have a query that get ONE icon set, for example : $dbQueryIcons = mysql_query("SELECT * FROM pl_icon WHERE tag LIKE '%".$SEARCH_QUERY."%' GROUP BY name ORDER BY id DESC LIMIT ".$firstEntry.", ".$CONFIG['icon_per_page']."") or die(mysql_error()); With this example if $tag contain 'twitter' it will show ONLY the first SQL data entry with the tag 'twitter', so it will be : (myicon.png, 16, 'twitter') This is what I want, but I would prefer the '128' size by default. Is this possible to tell SQL to send me only the 128 size when existing and if not another size ? In an another question someone give me a solution with the GROUP BY but in this case that don't run because we have a GROUP BY name. And if I delete the GROUP BY, it show me all size of the same icons. Thanks !

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  • How i can do the following querry to get needed information

    - by Night Walker
    Hello there I have two tables CompList table with following columns : CompId , McID , station , slot ,subslot , and several others BookingTable with columns: CompId , LineID , McID , station , slot ,subslot. I want to get following result: rows only that CompList.CompId == BookingTable.CompId (only CompId that is in both tables) and i need in the result columns from CompList: CompId , McID , station , slot ,subslot . and from BookingTable: LineID , McID , station , slot ,subslot and how i will be able to distinguish between same columns with same table in the result table them in the result table? Thanks for help.

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  • ASP, My SQL & case sensitity suddenly broken

    - by user131812
    Hi There, We have an old ASPsite that has been working fine for years with a MY SQL database. All of a sudden last week lots fo SQL queries stopped working. The database has a table called 'members' but the code calls 'Members'. It appears the queries used to work regardless of case sensitivity on the table names, but something has changed recently somewhere to enforce case. This has me stumped as the site has not been touched in years, the server config hasn't changed & the database provide has not changed anything. Is there any simple way to ignore case for an ASP site (without editing lots fo files :) Thanks Ben

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  • how do i release the auto increment serial nos that are missing

    - by mmdel
    i have a table with auto increment field and i am using transactions when inserting new data. now i find there are a few serial nos that are missing. suppose the last serial no was 475, now when i insert new row, the serial allotted to it is 481. how do i correct this. table_A fields ID(Auto increment),Name,Address table_B fields ID(Auto increment FK TO table_A ID),Tel,Fax,Email,Salesman table_C fields ID(Auto increment FK TO table_A ID),monthly_commitment mysql_query(BEGIN); $a = mysql_query("INSERT INTO table_A VALUES('','name','address')"); $b = mysql_query("INSERT INTO table_B VALUES('','tel','fax','email','salesman')"); $b = mysql_query("INSERT INTO table_C VALUES('','monthly commitment')"); if(($a) && ($b) && ($c)){mysql_query("COMMIT");} else {mysql_query("ROLLBACK");}

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  • Selecting first records of a type in a given period

    - by Emanuil Rusev
    I have a database table that stores user comments: comments(id, user_id, created_at) I want to get from it the number of users that have commented for the first time in the past week. Here's what I have so far: SELECT COUNT(DISTINCT `user_id`) FROM `comments` WHERE `created_at` BETWEEN DATE_SUB(NOW(), INTERVAL 7 DAY) AND NOW() This would give the number of users that have commented, but it would not take into consideration whether these comments are first for these users.

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  • Update is not updating the whole string

    - by Malik
    Following is my SQL fiddle: http://sqlfiddle.com/#!2/f9bae/1 In which i am trying to check if the whole name is being verified by lookup table or not and if there is any error then it should get replaced by the correct value but the problem i am facing is that if any name contains more than one wrong values then query only update one part of that name and leave the rest unchanged , kindly let me know how can i modify my query for update so it'll update the whole name as per lookup table correct values. Thanks,

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  • Session is working in Localhost Properly but not Online (Cpanel)

    - by nando pandi
    Hello guys Sorry for my stupid question regarding to my yesterday question its not solved yet even the advice you have given but still not working. i have removed all of spaces but still showing the problem for me. it's working perfect in localhost but not in CPANEL. Here is the errors which give: Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at /home/scalepro/public_html/Admin Panel/Remote Employee/main.php:1) in /home/scalepro/public_html/Admin Panel/Remote Employee/main.php on line 1 Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /home/scalepro/public_html/Admin Panel/Remote Employee/main.php:1) in /home/scalepro/public_html/Admin Panel/Remote Employee/main.php on line 1 Warning: Cannot modify header information - headers already sent by (output started at /home/scalepro/public_html/Admin Panel/Remote Employee/main.php:1) in /home/scalepro/public_html/Admin Panel/Remote Employee/main.php on line 13 Warning: Unknown: Your script possibly relies on a session side-effect which existed until PHP 4.2.3. Please be advised that the session extension does not consider global variables as a source of data, unless register_globals is enabled. You can disable this functionality and this warning by setting session.bug_compat_42 or session.bug_compat_warn to off, respectively in Unknown on line 0 ANY ONE PLEASE ??? Here is my code: <?php session_start(); require_once('../../Admin Panel/db.php'); if(isset($_POST['email']) && !empty($_POST['email']) && isset($_POST['password']) && !empty($_POST['password'])) { $email = $_POST['email']; $password = $_POST['password']; $query="SELECT RemoteEmployeeFullName, RemoteEmployeeEmail, RemoteEmployeePassword FROM remoteemployees WHERE RemoteEmployeeEmail='".$email."' AND RemoteEmployeePassword='".$password."'"; $queryrun=$connection->query($query); if($queryrun->num_rows > 0) { $_SESSION['email']=$RemoteEmployeeFullName; header("Location: /home/scalepro/public_html/Admin Panel/Remote Employee/REPLists.php"); } else { echo 'Email: <b>'.$email. '</b> or Password <b>'. $password.'</b> Is Not Typed Correctly Try Again Please!.'; header( "refresh:5;url= /home/scalepro/public_html/spd/myaccount.php" ); } } else { header( "refresh:5;url= /home/scalepro/public_html/spd/myaccount.php" ); } ?> if the condition gets true this will be redirected to a page by the name of REPLists.php here is the page. <?php session_start(); require_once('../../Admin Panel/db.php'); ?> <html> <head> <style> .wrapper { width:1250px; height:auto; border:solid 1px #000; margin:0 auto; padding:5px; border-radius:5px; -webkit-border-radius:5px; -moz-border-radius:5px; -ms-border-radius:5px; } .wrapper .header { width:1250px; height:20px; border-bottom:solid 1px #f0eeee; margin:auto 0; margin-bottom:12px; } .wrapper .header div { text-decoration:none; color:#F60; } .wrapper .header div a { text-decoration:none; color:#F60; } .wrapper .Labelcon { width:1250px; height:29px; border-bottom:solid 1px #ccc; } .wrapper .Labelcon .Label { width:125px; height:20px; float:left; text-align:center; border-left:1px solid #f0eeee; font:Verdana, Geneva, sans-serif; font-size:14.3px; font-weight:bold; } .wrapper .Valuecon { width:1250px; height:29px; border-bottom:solid 1px #ccc; color:#F60; text-decoration:none; } .wrapper .Valuecon .Value { width:125px; height:20px; float:left; text-align:center; border-left:1px solid #f0eeee; font-size:14px; } </style> </head> <body> <div class="wrapper"> <div class="header"> <div style="float:left;"><font color="#000000">Email: </font> <?php if(isset($_SESSION['email'])) { echo $_SESSION['email']; } ?> </div> <div style="float:right;"> <a href="#">My Profile</a> | <a href="logout.php">Logout</a></div> </div> <div class="Labelcon"> <div class="Label">Property ID</div> <div class="Label">Property Type</div> <div class="Label">Property Deal Type</div> <div class="Label">Property Owner</div> <div class="Label">Proposted Price</div> </div> <?php if(!isset($_SESSION['email'])) { header('Location:../../spd/myaccount.php'); } else { $query = "SELECT properties.PropertyID, properties.PropertyType, properties.PropertyDealType, properties.Status, properties.PropostedPrice, remoteemployees.RemoteEmployeeFullName, propertyowners.PropertyOwnerName, propertydealers.PropertyDealerName FROM remoteemployees, propertyowners, propertydealers, properties WHERE properties.PropertyOwnerID=propertyowners.PropertyOwnerID AND properties.PropertyDealerID=propertydealers.PropertyDealerID AND remoteemployees.RemoteEmployeeID=properties.RemoteEmployeeID ORDER BY properties.PropertyID "; $query_run = $connection->query($query); if( $connection->error ) exit( $connection->error ); while($row=$query_run->fetch_assoc()) { ?> <div class="Valuecon"> <div class="Value"><?php echo $row['PropertyID'] ?></div> <div class="Value"><?php echo $row['PropertyType'] ?></div> <div class="Value"><?php echo $row['PropertyDealType']?></div> <div class="Value"><?php echo $row['PropertyOwnerName'] ?></div> <div class="Value"><?php echo $row['PropostedPrice'];?></div> </div> <?php } }?> </div> </body> </html>

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  • How to verify if two tables have exactly the same data?

    - by SiLent SoNG
    Basically we have one table (original table) and it is backed up into another table (backup table); thus the two tables have exactly the same schema. At the beginning both tables (original table and backup table) contains exactly the same set of data. After sometime for some reason I need to verify whether dataset in the original table has changed or not. In order to do this I have to compare the dataset in the original table against the backup table. Let's say the original table has the following schema: `create table LemmasMapping ( lemma1 int, lemma2 int, index ix_lemma1 using btree (lemma1), index ix_lemma2 using btree (lemma2) )` How could I achieve the dataset comparision? Update: the table does not have a primary key. It simply stores mappings between two ids.

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  • SELECT product from subclass: How many queries do I need?

    - by Stefano
    I am building a database similar to the one described here where I have products of different type, each type with its own attributes. I report a short version for convenience product_type ============ product_type_id INT product_type_name VARCHAR product ======= product_id INT product_name VARCHAR product_type_id INT -> Foreign key to product_type.product_type_id ... (common attributes to all product) magazine ======== magazine_id INT title VARCHAR product_id INT -> Foreign key to product.product_id ... (magazine-specific attributes) web_site ======== web_site_id INT name VARCHAR product_id INT -> Foreign key to product.product_id ... (web-site specific attributes) This way I do not need to make a huge table with a column for each attribute of different product types (most of which will then be NULL) How do I SELECT a product by product.product_id and see all its attributes? Do I have to make a query first to know what type of product I am dealing with and then, through some logic, make another query to JOIN the right tables? Or is there a way to join everything together? (if, when I retrieve the information about a product_id there are a lot of NULL, it would be fine at this point). Thank you

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  • Cannot add or update a child row: a foreign key constraint fails

    - by myaccount
    // Getting the id of the restaurant to which we are uploading the pictures $restaurant_id = intval($_GET['restaurant-id']); if(isset($_POST['submit'])) { $tmp_files = $_FILES['rest_pics']['tmp_name']; $target_files = $_FILES['rest_pics']['name']; $tmp_target = array_combine($tmp_files, $target_files); $upload_dir = $rest_pics_path; foreach($tmp_target as $tmp_file => $target_file) { if(move_uploaded_file($tmp_file, $upload_dir."/".$target_file)) { $sql = sprintf(" INSERT INTO rest_pics (branch_id, pic_name) VALUES ('%s', '%s')" , mysql_real_escape_string($restaurant_id) , mysql_real_escape_string(basename($target_file))); $result = mysql_query($sql) or die(mysql_error()); } I get the next error: Cannot add or update a child row: a foreign key constraint fails (rest_v2.rest_pics, CONSTRAINT rest_pics_ibfk_1 FOREIGN KEY (branch_id) REFERENCES rest_branches (branch_id) ON DELETE CASCADE ON UPDATE CASCADE However, this error totally disappears and everything goes well when I put directly the restaurant id (14 for example) instead of $restaurant_id variable in the sql query. The URL am getting the id from is: http://localhost/rest_v2/public_html/admin/add-delete-pics.php?restaurant-id=2 Any help please?

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  • Having different database sorting order (default_scope) for two different views

    - by Juniper747
    In my model (pins.rb), I have two sorting orders: default_scope order: 'pins.featured DESC' #for adding featured posts to the top of a list default_scope order: 'pins.created_at DESC' #for adding the remaining posts beneath the featured posts This sorting order (above) is how I want my 'pins view' (index.html.erb) to look. Which is just a list of ALL user posts. In my 'users view' (show.html.erb) I am using the same model (pins.rb) to list only current_user pins. HOWEVER, I want to sorting order to ignore the "featured" default scope and only use the second scope: default_scope order: 'pins.created_at DESC' How can I accomplish this? I tried doing something like this: default_scope order: 'pins.featured DESC', only: :index default_scope order: 'pins.created_at DESC' But that didn't fly... UPDATE I updated my model to define a scope: scope :featy, order: 'pins.featured DESC' default_scope order: 'pins.created_at DESC' And updated my pins view to: <%= render @pins.featy %> However, now when I open my pins view, I get the error: undefined method `featy' for #<Array:0x00000100ddbc78> UPDATE 2 User.rb class User < ActiveRecord::Base attr_accessible :name, :email, :username, :password, :password_confirmation, :avatar, :password_reset_token, :password_reset_sent_at has_secure_password has_many :pins, dependent: :destroy #destroys user posts when user is destroyed # has_many :featured_pins, order: 'featured DESC', class_name: "Pin", source: :pin has_attached_file :avatar, :styles => { :medium => "300x300#", :thumb => "120x120#" } before_save { |user| user.email = user.email.downcase } before_save { |user| user.username = user.username.downcase } before_save :create_remember_token before_save :capitalize_name validates :name, presence: true, length: { maximum: 50 } VALID_EMAIL_REGEX = /\A[\w+\-.]+@[a-z\d\-.]+\.[a-z]+\z/i VALID_USERNAME_REGEX = /^[A-Za-z0-9]+(?:[_][A-Za-z0-9]+)*$/ validates :email, presence: true, format: { with: VALID_EMAIL_REGEX }, uniqueness: { case_sensitive: false } validates :username, presence: true, format: { with: VALID_USERNAME_REGEX }, uniqueness: { case_sensitive: false } validates :password, length: { minimum: 6 }, on: :create #on create, because was causing erros on pw_reset Pin.rb class Pin < ActiveRecord::Base attr_accessible :content, :title, :privacy, :date, :dark, :bright, :fragmented, :hashtag, :emotion, :user_id, :imagesource, :imageowner, :featured belongs_to :user before_save :capitalize_title before_validation :generate_slug validates :content, presence: true, length: { maximum: 8000 } validates :title, presence: true, length: { maximum: 24 } validates :imagesource, presence: { message: "Please search and choose an image" }, length: { maximum: 255 } validates_inclusion_of :privacy, :in => [true, false] validates :slug, uniqueness: true, presence: true, exclusion: {in: %w[signup signin signout home info privacy]} # for sorting featured and newest posts first default_scope order: 'pins.created_at DESC' scope :featured_order, order: 'pins.featured DESC' def to_param slug # or "#{id}-#{name}".parameterize end def generate_slug # makes the url slug address bar freindly self.slug ||= loop do random_token = Digest::MD5.hexdigest(Time.zone.now.to_s + title)[0..9]+"-"+"#{title}".parameterize break random_token unless Pin.where(slug: random_token).exists? end end protected def capitalize_title self.title = title.split.map(&:capitalize).join(' ') end end users_controller.rb class UsersController < ApplicationController before_filter :signed_in_user, only: [:edit, :update, :show] before_filter :correct_user, only: [:edit, :update, :show] before_filter :admin_user, only: :destroy def index if !current_user.admin? redirect_to root_path end end def menu @user = current_user end def show @user = User.find(params[:id]) @pins = @user.pins current_user.touch(:last_log_in) #sets the last log in time if [email protected]? render 'pages/info/' end end def new @user = User.new end pins_controller.rb class PinsController < ApplicationController before_filter :signed_in_user, except: [:show] # GET /pins, GET /pins.json def index #Live Feed @pins = Pin.all @featured_pins = Pin.featured_order respond_to do |format| format.html # index.html.erb format.json { render json: @pins } end end # GET /pins, GET /pins.json def show #single Pin View @pin = Pin.find_by_slug!(params[:id]) require 'uri' #this gets the photo's id from the stored uri @image_id = URI(@pin.imagesource).path.split('/').second if @pin.privacy == true #check for private pins if signed_in? if @pin.user_id == current_user.id respond_to do |format| format.html # show.html.erb format.json { render json: @pin } end else redirect_to home_path, notice: "Prohibited 1" end else redirect_to home_path, notice: "Prohibited 2" end else respond_to do |format| format.html # show.html.erb format.json { render json: @pin } end end end # GET /pins, GET /pins.json def new @pin = current_user.pins.new respond_to do |format| format.html # new.html.erb format.json { render json: @pin } end end # GET /pins/1/edit def edit @pin = current_user.pins.find_by_slug!(params[:id]) end Finally, on my index.html.erb I have: <%= render @featured_pins %>

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  • Difficults on sql query

    - by João Madureira Pires
    I have the following tables: TableA (id, tableB_id, tableC_id) TableB (id, expirationDate) TableC (id, expirationDate) I want to retrieve all the results from TableA ordered by tableB.expirationDate and tableC.expirationDate. thanks

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  • Saving data that is in a table efficiently and also is easy to retrieve and echo back out

    - by Harry
    Information I currently have a table which image is below, Problem I have made this table using ul & li Here is the code http://jsfiddle.net/8j2qe/1/ Question What would be the best way of storing the data in the image and easily displaying it? Keeping in mind that each column can only have 1 entry. Thank you! And any questions will be answered ASAP! EDIT Sorry, I dont think I was clear enough in my initial question. What I am asking is, what is the best way to store and then display this type of data. I want to DISPLAY data from my database to show like it would in the image. Should I have a column in my database for each column on the table, then say either A,B,C or D depending on what column it is in but then how would I display it using PHP in my code provided? Im struggling to find a good way of explaining this, I am sorry.

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  • Force reload/refresh when pressing the back button

    - by FlyingCat
    I will try my best to explain this. I have an application that show the 50+ projects in my view page. The user can click the individual project and go to the update page to update the project information. Everything works fine except that after user finish updating the individual project information and hit 'back' button on the browser to the previous view page. The old project information (before update) is still there. The user has to hit refresh to see the updated information. It not that bad, but I wish to provide better user experience. Any idea to fix this? Thanks a lot.

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  • mailing system DB structure, need help

    - by Anna
    i have a system there user(sender) can write a note to friends(receivers), number of receivers=0. Text of the message is saved in DB and visible to sender and all receivers then they login to system. Sender can add more receivers at any time. More over any of receivers can edit the message and even remove it from DB. For this system i created 3 tables, shortly: users(userID, username, password) messages(messageID, text) list(id, senderID, receiverID, messageID) in table "list" each row corresponds to pair sender-receiver, like sender_x_ID -- receiver_1_ID -- message_1_ID sender_x_ID -- receiver_2_ID -- message_1_ID sender_x_ID -- receiver_3_ID -- message_1_ID Now the problem is: 1. if user deletes the message from table "messages" how to automatically delete all rows from table "list" which correspond to deleted message. Do i have to include some foreign keys? More important: 2. if sender has let say 3 receivers for his message1 (username1, username2 and username3) and at certain moment decides to add username4 and username5 and at the same time exclude username1 from the list of receivers. PHP code will get the new list of receivers (username2, username3, username4, username5) That means insert to table "list" sender_x_ID -- receiver_4_ID -- message_1_ID sender_x_ID -- receiver_5_ID -- message_1_ID and also delete from table "list" the row corresponding to user1 (which is not in the list or receivers any more) sender_x_ID -- receiver_1_ID -- message_1_ID which sql query to send from PHP to make it in an easy and intelligent way? Please help! Examples of sql queries would be perfect!

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