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  • How do I make replies to comments? (PHP)

    - by jpjp
    I want to create something like reddit where they have comments, then replies to the comment, then reply to the reply. What type of database structure do they use so: 1. they keep track of all the comments to a posting 2. a reply to a comment 3. a reply to a reply All I have right are is just a posting and a bunch of comments relating to it like.. POSTING TABLE posting_id | title | author COMMENTS TABLE comment_id | posting_id | comment REPLIES TABLE ???? How do I relate the comments to the replies? What type of css do they use to give replies that indented space?

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  • How to find the differences between the values of a specific column based on a key?

    - by Holicreature
    I've two tables as purchase_details and invoice_details and i want to store the inventory/stock of each product from the data of these two tables. structure of purchase_details. 'pid', 'int(10)' 'product_id', 'int(10)' 'quantity', 'float(8,2)' 'amount', 'float(12,2)' 'expiry_date', 'date' structure of purchase_details. 'invoice_id', 'int(10) unsigned' 'product_id', 'int(10) unsigned' 'quantity', 'float(10,2)' 'price', 'float(12,2)' i want to calculate the total quantity of remaining stock (quantity of sum of products from purchase_details - quantity of sum of products from invoice_details). Product_id is would be same for the two tables. how can i proceed?

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  • Can't select database table even though the code is right

    - by Lisa
    I am trying to display a list of my vbulliten threads on a non-vbulliten portion of my site. However I can't select the vbulliten database: <?php $host = "localhost"; $user = "my username"; $pass = "my password"; $dbname = "tableprefix_forum"; mysql_connect($host, $user, $pass) or die ("Could not connect to database server."); mysql_select_db($dbname) or die ("Could not select database."); ?> I am substituting some things here in this example but all my credentials are correct including my db server username, password and forum db name. So what is the problem? Is it due to some internal security feature in vbulliten, does this system not allow you to connect to it's db if the page trying to connect to it is a non-vbulliten page?

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  • SQL query, select from 2 tables random

    - by klaus
    Hello all i have a problem that i just CANT get to work like i what it.. i want to show news and reviews (2 tables) and i want to have random output and not the same output here is my query i really hope some one can explain me what i do wrong SELECT anmeldelser.billed_sti , anmeldelser.overskrift , anmeldelser.indhold , anmeldelser.id , anmeldelser.godkendt FROM anmeldelser LIMIT 0,6 UNION ALL SELECT nyheder.id , nyheder.billed_sti , nyheder.overskrift , nyheder.indhold , nyheder.godkendt FROM nyheder ORDER BY rand() LIMIT 0,6

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  • Scalably processing large amount of comlpicated database data in PHP, many times a day.

    - by Eph
    I'm soon to be working on a project that poses a problem for me. It's going to require, at regular intervals throughout the day, processing tens of thousands of records, potentially over a million. Processing is going to involve several (potentially complicated) formulas and the generation of several random factors, writing some new data to a separate table, and updating the original records with some results. This needs to occur for all records, ideally, every three hours. Each new user to the site will be adding between 50 and 500 records that need to be processed in such a fashion, so the number will not be steady. The code hasn't been written, yet, as I'm still in the design process, mostly because of this issue. I know I'm going to need to use cron jobs, but I'm concerned that processing records of this size may cause the site to freeze up, perform slowly, or just piss off my hosting company every three hours. I'd like to know if anyone has any experience or tips on similar subjects? I've never worked at this magnitude before, and for all I know, this will be trivial to the server and not pose much of an issue. As long as ALL records are processed before the next three hour period occurs, I don't care if they aren't processed simultaneously (though, ideally, all records belonging to a specific user should be processed in the same batch), so I've been wondering if I should process in batches every 5 minutes, 15 minutes, hour, whatever works, and how best to approach this (and make it scalable in a way that is fair to all users)?

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  • PHP Foreach statement issue. Multiple rows are returned

    - by Daniel Patilea
    I'm a PHP beginner and lately i've been having a problem with my source code. Here it is: <html> <head> <title> Bot </title> <link type="text/css" rel="stylesheet" href="main.css" /> </head> <body> <form action="bot.php "method="post"> <lable>You:<input type="text" name="intrebare"></lable> <input type="submit" name="introdu" value="Send"> </form> </body> </html> <?php //error_reporting(E_ALL & ~E_NOTICE); mysql_connect("localhost", "root", "") or die(mysql_error()); mysql_select_db("robo") or die(mysql_error()); $intrebare=$_POST['intrebare']; $query = "SELECT * FROM dialog where intrebare like '%$intrebare%'"; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_array($result) or die(mysql_error()); ?> <div id="history"> <?php foreach($row as $rows){ echo "<b>The robot says: </b><br />"; echo $row['raspuns']; } ?> </div> It returns me the result x6 times. This problem appeared when I've made that foreach because I wanted the results to stuck on the page one by one after every sql querry. Can you please tell me what seems to be the problem? Thanks!

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  • Codeigniter setting multiple where conditions, how to unset one

    - by Dustin
    I've got a script that is a notify_url from paypal that is supposed to update multiple tables in my database using the following code: //update first table $this-db-where('someid', $somid); $this-db-update('table', $data); ///update second table $this-db-where('somesecondid', $somesecondid) $this-db-update('anothertable', $data2); Then I get the following error: Unknown column 'somesecondid' in 'where clause' UPDATE anothertable SET avail = 0 WHERE someid = '13' AND somesecondid = '199' So codeigniter is combining those where clauses into a single query. Is there a way to unset the first one so it only has "UPDATE anothertable SET avail=0 WHERE somesecondid = 199" ? Thanks!

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  • Want to save data field from form into two columns of two models.

    - by vette982
    I have a Profile model with a hasOne relationship to a Detail model. I have a registration form that saves data into both model's tables, but I want the username field from the profile model to be copied over to the usernamefield in the details model so that each has the same username. function new_account() { if(!empty($this->data)) { $this->Profile->modified = date("Y-m-d H:i:s"); if($this->Profile->save($this->data)) { $this->data['Detail']['profile_id'] = $this->Profile->id; $this->data['Detail']['username'] = $this->Profile->username; $this->Profile->Detail->save($this->data); $this->Session->setFlash('Your registration was successful.'); $this->redirect(array('action'=>'index')); } } } This code in my Profile controller gives me the error: Undefined property: Profile::$username Any ideas?

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  • Retrieve rows where a value exists within a comma separated list

    - by Klaaz
    I like to reverse this query: SELECT * FROM table WHERE status IN ( option,option1,option2 ); in a query like SELECT * FROM table WHERE status contains ( 'option' ); Where field 'status' column contains (by example): 'option,option1'. When I use SELECT * FROM table WHERE status LIKE '%option%' ); It also selects the rows with a 'status' column that only contains 'option1' Is this possible? example data: id,name,status 1,'test1','option,option1' 2,'test2','option,option2' 3,'test3','option2' 4,'test4','option2,option3' 5,'test5','option' SELECT * FROM table WHERE status contains ( 'option' ); This query should select select record 1,2 and 5. 'status' field type is varchar. The problem is that the status fields contains data that is almost alike, exept from the added number to option. Off course this is a made up example but the real thing has this kind of parameters

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  • form not showing for empty records

    - by Chris Hodges
    I have a relatively simple PHP page called editcustomers with 3 columns. The problem I'm having is that the form will show when there is a record in the database and the fields will be populated with that info. When no such records exists, the form is not even shown, eliminating the possibility to insert a record. My page layout is as follows: Column 1 shows a form containing customer information, allowing it to be edited. Column 2 allows ordering of products and showing how many products were ordered Column 3 shows the total paid so far, and the total owing. The code for the page I have at present: <html> <?php $id = $_GET['id']; require_once('connect.php'); $sth = $dbh->query("SELECT * FROM users where id = '$id';"); $sth->setFetchMode(PDO::FETCH_ASSOC); $eth = $dbh->query("SELECT * FROM purchases where id = '$id';"); $eth->setFetchMode(PDO::FETCH_ASSOC); ?> <div id="main"> <div id="left"> <form name="custInfo" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custInfo"/> <?php while($row = $sth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="firstName" size ="30" value=" <?php echo $row["firstName"]?>"/> <p><input type = "text" name ="lastName" size ="30" value="<?php echo $row["lastName"]?>"/> <p><input type = "text" name ="country" size ="30" value="<?php echo $row["country"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="mid"> <form name="custCosts" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custCosts"/> <?php while($row = $eth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="amountOwed" size ="30" value=" <?php echo $row["amountOwed"]?>"/> <p><input type = "text" name ="numAaa" size ="30" value="<?php echo $row["numAaa"]?>"/> <p><input type = "text" name ="numBbb" size ="30" value="<?php echo $row["numBbb"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="right"> <b>Total Balance</b> <p> Money owed: </p> <p> aaa total: </p> <p> bbb total: </p> <p> Total: </p> <input type = "text" name ="pay" size ="20" /></p> <input type="submit" value="Make Payment" /> </div> <?php $dbh =null; ?> </body> </html> And the code for all the database trickery: <?php require_once 'connect.php'; $formType = $_POST['formType']; $id = $_POST['id']; $firstName = $_POST['firstName']; $lastName = $_POST['lastName']; $country = $_POST['country']; $amountOwed = $_POST['amountOwed ']; $numAaa = $_POST['numAaa']; $numBbb = $_POST['numBbb']; if(empty($_POST['id'])) { $sth = $dbh->prepare("INSERT INTO customers (firstName, lastName, country) VALUES ('$firstName', '$lastName', '$country')"); $sth->execute(); } elseif(!empty($_POST['id']) && !isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("UPDATE customers SET firstName = '$firstName', lastName = '$lastName', country = '$country' WHERE id = '$id'"); $sth->execute(); }elseif(!empty($_POST['id']) && isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("INSERT INTO purchases (id, amountOwed, numAaa, numBbb) VALUES ('$id', '$amountOwed', '$numAaa', '$numBbb'"); $sth->execute(); }elseif(!empty($_POST['id']) && $_POST['formType'] == 'guestCosts'){ $sth = $dbh->prepare("UPDATE purchases SET amountOwed= '$amountOwed', numAaa = '$numAaa', numBbb= '$numBbb' WHERE id = '$id'"); $sth->execute(); } $dbh =null; ?> Why does the form not even display if there is no record? An error or something I might understand....but the form is still in the HTML and should still be being output, from what I can see. Why is this not the case?

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  • I want to do a sql update loop statement, by using the do--while in php

    - by Jean
    Hello, I want to loop the update statement, but it only loops once. Here is the code I am using: do { mysql_select_db($database_ll, $ll); $query_query= "update table set ex='$71[1]' where field='val'"; $query = mysql_query($query_query, $ll) or die(mysql_error()); $row_domain_all = mysql_fetch_assoc($query); } while ($row_query = mysql_fetch_assoc($query)); Thanks Jean

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  • Relation to multiple tables of different types for rating?

    - by Tronic
    i have a table structure like this Products Team Images and want to implement a rating/commenting-feature, where users can rate each entry of all tables. what's the best way to make a single rating table? e.g. a user votes a a product and a team entry, and it should be possible to get alle these entries from a single table. what kind of table-structure is best for this purpose? i hope, my questions is clear enough :/ thanks in advance!

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  • PHP - How to retrieve session in php

    - by Klaus Jasper
    I created a table that contains id - names - jobs and page that shows the names only and beside each name there is button Job and session that contains the id. this is my code $query = mysql_query("SELECT * FROM table"); while($fetch = mysql_fetch_array("$query")){ $name = $fetch['names']; $id = $fetch['id']; echo '</br>'; echo $name; $_SESSION['name'] = $id; echo "<button>Job</button>"; } I want when the user click on button Job redirect to a page that contains the job of that session. so how can I do it?

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  • Dynamically Insert Variables into DB Table using PreparedStatement

    - by gran_profaci
    I was working with PreparedStatement today and noticed that it used setString() setTimestamp() etc. to insert variables into the DB. I basically have 20 tables each with at least 15 columns and it would not be feasible for me to manuallt write down all the setters. Considering that I have an ArrayList "Vals" which contains all the variables to be inputted in String format (obtained by getString() using PreparedStatement itself), is there any way I can do an insert without using expressly using the Setters? That would save me a lot of time.

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  • Get category count for a category where only the child categories have products

    - by Matthew
    I'm having problems getting a count for a category collection that will include products in any of that categories children. However I don't want just a full count I want to filter that count by a product collection (so only include products in the count that appear in the product collection)... Any suggestions? Code to get a filtered product collection (filtered by a multiselect attribute) /** @var $attribute Mage_Eav_Model_Entity_Attribute */ $valuesCollection = Mage::getResourceModel('eav/entity_attribute_option_collection') ->setAttributeFilter($attribute->getId()) ->addFieldToFilter('value', array ('like' => $make)) ->addFieldToSelect('option_id') ->setStoreFilter(0, false); $set = array(); foreach($valuesCollection as $option){ $set[] = $option->getData('option_id'); } $_productCollection = Mage::getResourceModel('catalog/product_collection') ->addAttributeToFilter('sparex_makemodel', array('in' => $set ) ) ->addAttributeToSelect('*'); I'm getting the child categories for a given category like thus.. $childCats = Mage::getModel('catalog/category')->load(2)->getChildrenCategories(); Now none of these categories have products assigned to them, however their children (or children of children) do. I want to produce a count for these categories that includes the child categories but only where the products are in my filtered collection.

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  • PHP Ajax not working

    - by Kostis
    I have 3 buttons on my page and depending on which one the user is clickingi want to run through ajax call a delete query in my database. When the user clicks on a button the javascript function seems to work but it doesn't run the query in php script. The html page: <?php session_start(); ?> <!DOCTYPE HTML> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-7"> <script> function myFunction(name) { var r=confirm("Are you sure? This action cannot be undone!"); if (r==true) { alert(name); // check if is getting in if statement and confirm the parameter's value var xmlhttp; if (str.length==0) { document.getElementById("clearMessage").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("clearMessage").innerHTML= responseText; } } xmlhttp.open("GET","clearDatabase.php?q="+name,true); xmlhttp.send(); } else alert('pff'); } </script> </head> <body> <div id="wrapper"> <div id="header"></div> <div id="main"> <?php if (session_is_registered("username")){ ?> <!--<a href="#">???a????s? pa?a??? µ???µ?t??</a><br /> <a href="#">???a????s? pa?a??? s??ed????</a><br /> <a href="#">???a????s? push notifications</a><br />--> <input type="button" value="???a????s? pa?a??? µ???µ?t??" onclick="myFunction('messages')" /> <input type="button" value="???a????s? pa?a??? s??ed????" onclick="myFunction('conferences')" /> <input type="button" value="???a????s? push notifications" onclick="myFunction('notifications')" /> <div id="clearMessage"></div> <?php } else echo "Login first."; ?> </div> <div id="footer"></div> </div> </body> </html> and the php script: <?php if (isset($_GET["q"])) $q=$_GET["q"]; $host = "localhost"; $database = "dbname"; $user = "dbuser"; $pass = "dbpass"; $con = mysql_connect($host,$user,$pass) or die(mysql_error()); mysql_select_db($database,$con) or die(mysql_error()); if ($q=="messages") $query = "DELETE FROM push_message WHERE time_sent IS NOT NULL"; else if ($q=="conferences") $query = "DELETE FROM push_message WHERE time_sent IS NOT NULL"; else if ($q=="notifications") { $query = "DELETE FROM push_friend WHERE time_sent IS NOT NULL"; } $res = mysql_query($query,$con) or die(mysql_error()); if ($res) echo "success"; else echo "failed"; mysql_close($con); ?>

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  • How to pass an array of objects trough a jquery $.post?

    - by majc
    Hi, I want to pass the result of a query trough a $.post. function GetAllTasks() { $sql = "select t.id as task_id, description, createdat, createdby, max_requests, max_duration, j.name as job_name from darkfuture.tasks t, darkfuture.jobs j where t.job_id = j.id"; $sqlresult = mysql_query($sql) or die("The list of works failed: ".mysql_error($this->con)); $result = array(); while($row = mysql_fetch_assoc($sqlresult)) { $task = new TasksResult(); $task->id = $row["task_id"]; $task->description = $row["description"]; $task->createdat = $row["createdat"]; $task->createdby = $row["createdby"]; $task->max_requests = $row["max_requests"]; $task->max_duration = $row["max_duration"]; $task->job_id = $row["job_name"]; array_push($result, $task); } mysql_free_result($sqlresult); return $result; } Here is how i call it: $tasksDB = new TasksDB(); $tasks = $tasksDB->GetAllTasks(); Now i want to pass $tasks through here: $.post("views/insert_tasks.php",{'tasks[]': $tasks}, function(data) { }); I know this {'tasks[]': $tasks} it's wrong but i don't know how to do it right. Some help will be appreciated. Thanks in advance!

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  • Connecting PHP Server and Android?

    - by user3439988
    I am trying to create a simple test application to transfer data back and forth between my server and Android device. The following are the things I aim for: Ability to upload data and files to the server. To be able to view my files on the server. To be able to download the files from the server to my android device. Ability of the server to send me updates on the files or notifications to my phone. I need a safe and secure way to do these things. I have tried these: HTTPPost requests onto the server and echoing the output accordingly and capturing the HTTPresponse and parsing it. For files I have tried using MultipartEntity, but I think that has been deprecated.

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  • Increment my id in my insert request

    - by Mercer
    hello, i have a table with some rows. idClient, name, adress,country,... i want to know how i can do an insert into this table with auto increment my idClient in my sql request..? Thx. edit: i want do a request like this insert into Client values((select max(idClient),...)

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  • SQL: count days in date range?

    - by John Isaacks
    I have a query like this: SELECT COUNT(*) AS amount FROM daily_individual_tracking WHERE sales = 'YES' AND daily_individual_tracking_date BETWEEN '2010-01-01' AND '2010-03-31' I am selected from a date range. Is there a way to also get the total days in the date range?

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  • Does table columns increase select statement execution time

    - by paokg4
    I have 2 tables, same structure, same rows, same data but the first has more columns (fields). For example: I select the same 3 fields from both of them (SELECT a,b,c FROM mytable1 and then SELECT a,b,c FROM mytable2) I've tried to run those queries on 100,000 records (for each table) but at the end I got the same execution time (0.0006 sec) Do you know if the number of the columns (and in the end the size of the one table is bigger than the other) has to do something with the query execution time?

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  • In what way does Wordpress rewrite page URLs?

    - by Mac Taylor
    Hey Recently I'm interested in post's structure of Wordpress. They use a table named (wp_posts) and in this table they saved 3 related fields such as : post_title post_name guid It's clear that they save title of each story in post_title field , and slugs in post_name , and full url of a post in guild filed . But where the hell, they rewrite these urls in way it appears in browsers : http://localhost/wordpress/about/ There is no htaccess rules for this ! I checked rewrite.php and didn't understand an inch ?! i need to create similar pages , what steps should i take !?

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  • Cannot add or update a child row: a foreign key constraint fails

    - by myaccount
    // Getting the id of the restaurant to which we are uploading the pictures $restaurant_id = intval($_GET['restaurant-id']); if(isset($_POST['submit'])) { $tmp_files = $_FILES['rest_pics']['tmp_name']; $target_files = $_FILES['rest_pics']['name']; $tmp_target = array_combine($tmp_files, $target_files); $upload_dir = $rest_pics_path; foreach($tmp_target as $tmp_file => $target_file) { if(move_uploaded_file($tmp_file, $upload_dir."/".$target_file)) { $sql = sprintf(" INSERT INTO rest_pics (branch_id, pic_name) VALUES ('%s', '%s')" , mysql_real_escape_string($restaurant_id) , mysql_real_escape_string(basename($target_file))); $result = mysql_query($sql) or die(mysql_error()); } I get the next error: Cannot add or update a child row: a foreign key constraint fails (rest_v2.rest_pics, CONSTRAINT rest_pics_ibfk_1 FOREIGN KEY (branch_id) REFERENCES rest_branches (branch_id) ON DELETE CASCADE ON UPDATE CASCADE However, this error totally disappears and everything goes well when I put directly the restaurant id (14 for example) instead of $restaurant_id variable in the sql query. The URL am getting the id from is: http://localhost/rest_v2/public_html/admin/add-delete-pics.php?restaurant-id=2 Any help please?

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  • Referral System PHP

    - by Liam
    I have a membership based website and im planning on implementing a referral system. My website is credit based, the idea is that if User X refers User Y, then User X gets 100 bonus credits. Has anybody built a referral system before and if so what obstacles should I bear in mind? I've had a snoop round SO tonight but couldn't find any suitable answers. My theory is to give each user a random string which is generated and stored in the DB when they sign up, The user will then be presented with a URL incl. that string which when they pass to somebody (User Z), User Z is then sent to a page, the page then uses the GET method to gather the Random string and update the DB Row they currently occupy, does this sound feasible or could it easily be breached? Thanks

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