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  • Re-Convert timestamp DATE back to original format (when editing) PHP MySQL

    - by Jess
    Ok so I have managed to get the format of the date presented in HTML (upon display) to how I want (dd/mm/yyy)...However, the user also can change the date via a form. So this is how it's setup as present. Firstly, the conversion from YYYY-MM-DD to DD/MM/YYYY and then display in HTML: $timestamp = strtotime($duedate); echo date('d/m/Y', $timestamp); Now when the user selects to update the due date, the value already stored value is drawn up and presented in my text field (using exactly the same code as above).. All good so far. But when my user runs the update script (clicks submit), the new due date is not being stored, and in my DB its seen as '0000-00-00'. I know I need to convert it back to the correct format that MySQL wants to have it in, in order for it to be saved, but I'm not sure on how to do this. This is what I have so far in my update script (for the due date): $duedate = $_POST['duedate']; $timestamp = strtotime($duedate); date('Y/m/d', $timestamp); $query = "UPDATE films SET filmname= '".$filmname."', duedate= '".$duedate; Can somebody please point me in the right direction to have the new date, when processed, converted back to the accepted format by MySQL. I appreciate any help given! Thanks.

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  • Php recursion into multidimensional array

    - by dclowd9901
    I'm trying to write a script that, in its process, would need to be able to write an undefined number of nested arrays, and those arrays need to be able to have custom keys. Essentially, the script is being used to convert an HTML DOM into a multidimensional array. I'm not extremely well versed in recursion, so any pointers would be awesome.

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  • PHP mail send code not working

    - by acctman
    I'm trying to use this coding but its not processing, and its not outputing any errors. function send_email($subject='Activate Your Account', $html_content, $text_content, $headers) { $en['email'] = '[email protected]'; $to = $en['email']; $en['memb_id'] = '39'; $en['confcode'] = '69696969'; $en['user'] = 'couple'; $text_content = "Confirm Your domain.com Account\r\n"; $text_content.= "UserName: " . $en['user'] . "\r\n"; $text_content.= "Activate Your Account by visiting this link below:\r\n"; $text_content.= "http://www.domain.com/confirm/" . $en['memb_id'] . "/" . $en['confcode'] . "\r\n"; $text_content.= "\r\n"; $text_content.= "______________________\r\n"; $text_content.= "Thanks,\r\n"; $text_content.= "Staff"; $html_content = "<html><body><h1>Confirm Your domain.com Account</h1>"; $html_content.= "<p>UserName: " . $en['user'] . "<br>"; $html_content.= "Activate Your Account by visiting this link below:<br>"; $html_content.= "<a href=http://www.domain.com/confirm/" . $en['memb_id'] . "/" . $en['confcode'] . ">http://www.domain.com/confirm/" . $en['memb_id'] . "/" . $en['confcode'] . "</a>"; $html_content.= "</p>"; $html_content.= "______________________<br>"; $html_content.= "Thanks,<br>"; $html_content.= " Staff"; $html_content.= "</body></html>"; $mime_boundary = 'Multipart_Boundary_x'.md5(time()).'x'; $headers = "MIME-Version: 1.0\r\n"; $headers.= "Content-Type: multipart/alternative; boundary=\"$mime_boundary\"\r\n"; $headers.= "Content-Transfer-Encoding: 7bit\r\n"; $body = "This is a multi-part message in mime format.\n\n"; $body.= "--$mime_boundary\n"; $body.= "Content-Type: text/plain; charset=\"charset=us-ascii\"\n"; $body.= "Content-Transfer-Encoding: 7bit\n\n"; $body.= $text_content; $body.= "\n\n"; $body.= "--$mime_boundary\n"; $body.= "Content-Type: text/html; charset=\"UTF-8\"\n"; $body.= "Content-Transfer-Encoding: 7bit\n\n"; $body.= $html_content; $body.= "\n\n"; $body.= "--$mime_boundary--\n"; $headers.= 'From: <[email protected]>' . "\r\n"; $headers.= "X-Sender-IP: $_SERVER[SERVER_ADDR]\r\n"; $headers.= 'Date: '.date('n/d/Y g:i A')."\r\n"; $headers.= 'Reply-To: <[email protected]>' . "\r\n"; return mail($to, $subject, $body, $headers); echo $to; echo $subject; echo $body; echo $headers; }

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  • PHP: How to cast object to inherited class?

    - by andreyvlru
    I'd like to inherit PDOStatement class and use it in my website scripts. But I am frustrated how to get required object. PDO::query returns only direct PDOStatement object and looks like there are no other method to create PDOStatement object or inherited class. Initially i thought to move PDOStatement object to constructor of inherit class Something like that: $stmt = PDO -> query("select * from messages"); $messageCollection = new Messaging_Collection($stmt); But how to make instance of PDOStatement to inherited object (Messaging_Collection). It is a big question for me. class Messaging_Collection extends PDOStatement { public function __construct(PDOStatement $stmt) { //there i should to transform $stmt to $this // direct $this = $stmt is not possible // is there other right way? }

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  • Select and copy to MySQL table PHP

    - by Liju
    Can insert the table1 value to Table2 like the follows.. based on Name Date. Table1 Id Date Name time 1 20/11/2010 Tom 08:00 2 20/11/2010 Tom 08:30 3 20/11/2010 Tom 09:00 4 20/11/2010 Tom 09:30 5 20/11/2010 Tom 10:00 6 20/11/2010 Tom 10:30 7 20/11/2010 Tom 11:30 8 20/11/2010 Tom 14:30 9 20/11/2010 John 08:10 10 20/11/2010 John 09:30 11 20/11/2010 John 11:00 12 20/11/2010 John 13:00 13 20/11/2010 John 14:30 14 20/11/2010 John 16:00 15 20/11/2010 John 17:30 16 20/11/2010 John 19:00 17 20/11/2010 Ram 08:05 18 20/11/2010 Ram 08:30 19 20/11/2010 Ram 09:00 20 20/11/2010 Ram 09:45 21 20/11/2010 Ram 12:00 22 20/11/2010 Ram 13:30 23 20/11/2010 Ram 15:00 Table2 Id Date Name Time In1 Time Out1 Time In1 Time Out1 Time In1 Time Out1 Time In4 Time Out4 1 20/11/2010 Tom 08:00 08:30 09:00 09:30 10:00 10:30 11:30 14:30 2 20/11/2011 John 08:10 09:30 11:00 13:00 14:30 16:00 17:30 19:00 3 20/11/2012 Ram 08:05 08:30 09:00 09:45 12:00 13:30 15:00 Null Help me Please... Liju

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  • PHP - Opening uploaded DOCX files with the correct MIME TYPE

    - by user270797
    I have users uploading DOCX files which I make available for download. The issues we have been experiencing is the unknown mime types of DOCX files which causes IE to open these docs as Zip files. It is running on a Windows/IIS server. Because this is a shared host, I cannot change any server settings. I was thinking that I could just write some code that would handle DOCX files, perhaps custom output: if (extension=docx) { header("Content-Disposition: attachment; etc) header('Content-Type: application/application/vnd.openxmlformats-officedocument.wordprocessingml.document'); Output the file contents etc } Would this be a viable solution?? If so, can someone help fill in the gaps? (PS I know the above syntax is not correct, just a quick example)

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  • Add information through a stored procedure and PHP?

    - by theband
    I have a form which contains a lot of elements, my DB guy has generated an SP and now i need to call that stored procedure. My form has twenty elements, when i click on submit the data must be saved in database. I know how to do this on insert query, but how to call an SP and perform this operation.

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  • help, php calendar links

    - by Ray
    Below is a partial table row that will create a line row of 3 columns. Two columns in each side is links, left is previous year and right is next year links. Center is links for january thru december. When you click a month links, the calendar will show that month you've clicked in the current year the calendar is on. For example, the calendar will open current month and year by default...March 2010. If you clicked previous year (2009), it will display current month (March) of last year (2009)...and then if you click Jun, the calendar will display June of whatever the year the calendar is currently on, which is June of 2009. my question is, what can i do to following code to do such thing. $Calendar.= "</tr><tr><td>"."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=" . $LastYear["year"] ."\"> $LastY </a></td>\n"; $Calendar.= "<td colspan=\"5\">"."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[0] ."\">Jan.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[1] ."\">Feb.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[2] ."\">Mar.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[3] ."\">Apr.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[4] ."\">May</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[5] ."\">Jun.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[6] ."\">Jul.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[7] ."\">Aug.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[8] ."\">Sep.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[9] ."\">Oct.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[10] ."\">Nov.</a> | "."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=".$ThisYear["year"]."&month=" . $MonthArray[11] ."\">Dec.</a> </td>"; $Calendar.= "<td>"."<a "."href=\"".$_SERVER["PHP_SELF"]."?year=" . $NextYear["year"] ."\"> $NextY </a></td>\n"; Thanks in advance.

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  • File version maintainence via PHP FTP?

    - by Michael
    Currently I'm working on a "plugin" that will be installed on many different sites and I was wondering on the best way for me to maintain the file version of this "plugin". Here's what I was thinking. Have a "master copy" of the plugin on a server, then connect via FTP to the target sites and upload the copy to their site overwriting whatever files they may have. I was wondering the best way to go about this. The "plugin" will have many different folders and files so transferring one file at a time will be too tedious. Is there a way to copy an entire folder over at a time? Or even better, is there a way to recurse through the folders and checking for file difference before uploading the new file? This is to make sure we are uploading a new file and not just the same one.

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  • php mysql query strings array

    - by Chocho
    i am building a string that i check in mysql db. eg: formFields[] is an array - input1 is: string1 array_push(strings, formFields) 1st string and mysql query looks like this: "select * from my table where id in (strings)" formFields[] is an array - input2 is: string1, string2 array_push(strings, formFields) 2nd string and mysql query looks like this: "select * from my table where id in (strings)" formFields[] is an array - input3 is: string1, string2,string3 array_push(strings, formFields) 3rd string and mysql query looks like this: "select * from my table where id in (strings)" i will like to add single quotes and a comma to the array so that i have this for the array strings: "select * from my table where id in ('string1', 'string2','string3')" i tried using array implode, but still no luck any ideas? thanks

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  • php regex for strong password validation

    - by Jason
    Hello, I've seen around the web the following regex (?=^.{8,}$)((?=.*\d)|(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$ which validates only if the string: * contain at least (1) upper case letter * contain at least (1) lower case letter * contain at least (1) number or special character * contain at least (8) characters in length I'd like to know how to convert this regex so that it checks the string to * contain at least (2) upper case letter * contain at least (2) lower case letter * contain at least (2) digits * contain at least (2) special character * contain at least (8) characters in length well if it contains at least 2 upper,lower,digits and special chars then I wouldn't need the 8 characters length. special characters include: `~!@#$%^&*()_-+=[]\|{};:'".,/<? thanks in advance.

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  • PHP site keeps opening to blank page, no errors.

    - by gene
    First, the premises: PHP loaded on IIS6 on Win2003 STD R2 SP2, PHP_5213 using FastCGI, MySQL_5145. Customer sent me the site files, which I unzipped to C:\InetPub\wwwroot\<site root>, then I created a new site in IIS, pointed to <site root>, added test.php to the site files for testing and it works, but visiting index.php produces a blank page with no errors. The readme.txt file present makes reference to application.php and explains root folder var and sets it to a non-existent file. I don't know PHP syntax, but I tried several logical changes with zero results. At this point I'm not even sure if that is the problem anymore. With PHP, MySQL & site debugging have put in over 20 hours. Still confused, I have resorted to heavy drug use and purchased a small firearm, loaded with a single round (even this seemed to take an inordinate amount of time). I've given up all hope. Someone please help save a new server and/or old administrator.

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  • PHP Session Cookies fail with users changing IP

    - by Columbo
    Hello, I have a login script for a small application that works by storing session cookies and checking them on each page to make sure the user is logged in. One of the two users who uses the system keeps getting logged out randomly. This appears to be down to the session cookie that shows then authenticated no longer being present. After a lot of investigation the only thing I can see that is different about this user is that their IP address is changing (today it was changing every hour (their on Sky)). The only thing is the change of IP address has happened 5 times this morning and only once has the user been logged off. Has anyone had a similar issue? Are session cookies in someway tied to IP addresses? Any help or links much appreciated. Thanks C

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  • MySQL query cache and PHP variables

    - by Saif Bechan
    I have seen the following statement made about the query cache: // query cache does NOT work $r = mysql_query("SELECT username FROM user WHERE signup_date >= CURDATE()"); // query cache works! $today = date("Y-m-d"); $r = mysql_query("SELECT username FROM user WHERE signup_date >= '$today'"); So the query cache only works on the second query. I was wondering if the query cache will also work on this: define('__TODAY',date("Y-m-d")); $r = mysql_query("SELECT username FROM user WHERE signup_date >= '".__TODAY."'");

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  • php warning mysql_fetch_assoc

    - by death the kid
    I am trying to access some information from mysql, but am getting the warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource for the second line of code below, any help would be much appreciated. $musicfiles=getmusicfiles($records['m_id']); $mus=mysql_fetch_assoc($musicfiles); for($j=0;$j<2;$j++) { if(file_exists($mus['musicpath'])) { echo '<a href="'.$mus['musicpath'].'">'.$mus['musicname'].'</a>'; } else { echo 'Hello world'; } } function getmusicfiles($m_id) { $music="select * from music WHERE itemid=".$s_id; $result=getQuery($music,$l); return $result; }

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  • php resize image

    - by haohan
    I have a class to read and output the image content, if $width is set, it will resize the image, and then output it. If I call the function like this $image-readImage('123.jpg'); , it can output the image file correctly, but when I call $image-readImage('123.jpg'); , it just display a black image with resized width & height. And I tried to replace the code from @imagejpeg($thumb, null, 100); to @imagejpeg($image, null, 100); will works~ - protected function readImage($fileName, $width = 0) { if ($width <= 0) { return @file_get_contents($this-destination . '/' . $fileName); } else { $imageSize = @getimagesize($this-destination . '/' . $fileName); $actualWidth = $imageSize[0]; $actualHeigth = $imageSize[1]; if ($actualWidth <= $width) { return @file_get_contents($this-destination . '/' . $fileName); } $height = (100 / ($actualWidth / $width)) * .01; $height = @round($actualHeigth * $height); $image = @imagecreatefromjpeg($this-destination . '/' . $fileName); $thumb = @imagecreatetruecolor($width, $height); @imagecopyresampled($thumb, $image, 0, 0, 0, 0, $width, $height, $actualWidth, $actualHeight); ob_start(); @imagejpeg($thumb, null, 100); $bits = ob_get_contents(); ob_end_clean(); return $bits; } } Any experts know what happened and help me to solve it ? Thanks.

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  • PHP Variable with Array

    - by Crays
    Hi guys, i'm trying to make a "update user's power" page. It is something similar to those you can find in say, invisionfree forums. I need it to generate a list of members with checkbox [done] Add an option for it [done] What i don't know how to do is to update, to say, give all the selected users the selected power. Then i went searching for something and found most of them uses array to do this, but i never found one that actually explains how it works. The example i took (with my own modification) was this: while($row = mysql_fetch_array($result)) { echo '<tr>'.$id[]=$rows['id'].''; echo '<td width="50px" align="center" class="TableFormCell"><input type="checkbox" name="option[]" /></td>'; echo '<td width="170px" align="center" class="TableFormCell">'.$row['uname'].'</td>'; echo '</tr>'; } I'm not sure what exactly $id[]=$rows['id'] does I know after the row, my option[] would become an array of option[1], option[2], option[3] for what power should be given, i've got no problem with that but on how to update the database i'm got no clue... for($i=0;$i<$count;$i++){ $sql1="UPDATE ninos SET power='$power' WHERE id='$option[$i]'"; $result1=mysql_query($sql1); } So Say i have 5 users, Aye, Bee, Cee, Dee, Eee with IDs of 1,2,3,4,5 how can i make it so that my script would run like $sql1="UPDATE ninos SET power = '$power' Where id='1','2','3','4','5'"; Please help, thanks.

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  • PHP PDO SQL Server Select statement not replacing question marks

    - by Metropolis
    Awhile ago I wrote a database class which uses PDO in order to connect to SQL Server databases and also to MySQL databases. It has always replaced the question marks fine when using it on the MySQL databases, but for the SQL Server database I had to create a work around which basically replaces the question marks manually. Here is the code for that. if($this->getPDODriver() == 'odbc' && !empty($values_a) && substr_count($query_s, "?") > 0) { $query_s = preg_replace(array_fill(0, substr_count($query_s, "?"), '/\?/'), $values_a, $query_s, 1); $values_a = NULL; } Now, I understand that this completely defeats the purpose of the question marks and PDO, but it has been working fine for me. What I would like to do now though, is find out why the question marks are not getting replaced in the first place, and remove this workaround. If I have a select statement like the following SELECT * FROM database WHERE value = ? That is what the query looks like when I go to prepare it, but when I display the query results, it is a blank array. Just remember, this class is working fine with MySQL, and it is working fine with the work around above. So I know it has something to do with the question marks.

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  • PHP Doctrine: Filter Table?

    - by ropstah
    I'm still not convinced after my previous question and some experience. Requirements: I don't want to use an SQL query everytime a filterBy() function is called and still be able to call -filterBy() on the returned table. Please find the comment @ ObjectsTable class: "How to instantiate another table and add records which match the filter criteria?" Usage: $globaltable = new ObjectsTable(); //globally accessible variable $globaltable->findAll(); //this call is made once at the beginning of the request $globaltable->filterBy('somefield', $someValue); //this function is used all over the place ObjectsTable class: class ObjectsTable extends Doctrine_Table { function filterBy($field, $value) { //How to instantiate another table and add records which match the criteria? } }

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  • PHP - Math - Round Number Function

    - by aSeptik
    Hi All guys! this time i have a math question for you! Assuming we have three numbers one is the Number of Votes the second is the Total Values and the last is the Units Ratings. units_ratings can be a number from 1 to 10; if ( total_values / units_ratings != number_of_votes ) { //do something for let the "number_of_votes" fit the division! } I ask this to you, cause i want know the best (fastest) way of achieve this! Thanks!

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  • Mysql IN clause, php array

    - by robert knobulous
    I know that this has been asked and answered before, but for the life of me I cannot find where I am going wrong. My code is below. $backa = array("1", "7", "8", "9", "12"); $backaa = implode(",", $backa); /* code to create connection object $wkHook */ $getOpt=$wkHook->prepare("select movementId, movementName from Movement where movementId IN ($backaa) order by movementName asc"); $getOpt->execute(); $getOpt->store_result($id, $name); Every time I run this I get one of two errors depending upon how I use the $backaa variable. More often than not I get a call to a non-object error indicating that $getOpt is not a proper Mysql query. I have tried every fashion of quoting, bracketing, etc for the $backaa variable but it's just not working for me. What obvious thing am I missing?

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