mysql table - Page 496 - Developer IT

how to add an ajax jQuery code, that return a row from php file [DB] and then change the value of input text?

- by Nisreen KH

//this is a code in php which is fetch a record from database <?php include("dbconn.inc"); $data=mysql_query("SELECT `subtitle`, `mian-title`, `page_num`, `note_path`, `flash_path` FROM `main-page` WHERE `page_num` =".$r." LIMIT 1"); echo $data; if (mysql_num_rows($data) == 0) { echo "No rows found, nothing to print so am exiting"; exit; } while ($row = mysql_fetch_assoc($data)) { echo $row['page_num']; } include("close.php"); ?> //and this is a code in html <form method="post" action="data.php"> <input name="Button1" type="submit" value="<<" /> <input name="test" style="width: 31px; height: 23px" type="text" /> // this is a value of page_num in DB. <input name="Button2" type="submit" value=">>" > </form> //i want to add an ajax code to retrieve the record from php code, and then change the input values depends on returned data ,and also to prevent refreshing the page always!!

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Difficults on sql query

- by João Madureira Pires

I have the following tables: TableA (id, tableB_id, tableC_id) TableB (id, expirationDate) TableC (id, expirationDate) I want to retrieve all the results from TableA ordered by tableB.expirationDate and tableC.expirationDate. thanks

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Does the MySQLdb module support prepared statements ?

- by planetp

Does MySQLdb support server-side prepared statements? I can't figure this out from its manual.

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Programmatically creating linked tables in access

- by newtoaccess

Hi all, We need to find a way to programatically *link all the tables* in a SQL Server database to an access db. We will be invoking this access database from a program that uses .net/SQL Server 2008. While invoking the application we would like to add the linked tables so that the users can just run the reports/modules from access without having to worry about linking the tables. Is there a way we can do this? Thanks!

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How to check with PHP does a SQL database already have

- by Dan Horvat

I've tried to find the answer to this question but none of the answers fit. I have two databases, one has 15.000.000 entries and I want to extract the necessary data and store it in a much smaller database with around 33.000 entries. Both databases are open at the same time. Or at least they should be. While having the big database open and extracting the entries from it, is it possible to check whether the value already exists in the smaller database? I just need some generic way which checks that.

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insert data using sqlite issue on iphone ( not reflecting on table)

- by prajakta

i can insert my data but i cant show them on my table view ..i did [tableview reload data] but of no success here is my code -(void)gButtonTapped:(id)sender { NSLog(@"right nav bar button is hit%@ ",storePaths); //[self readAnimalsFromDatabase2]; appDelegate = (DatabaseTestAppDelegate *)[[UIApplication sharedApplication] delegate]; sqlite3 *database; sqlite3_stmt *compiled_statement1; if(sqlite3_open([storePaths UTF8String], &database) == SQLITE_OK) { //const char *sqlStatement = NSString *newQuery = [NSString stringWithFormat:@"insert into cat_tbl (cat_id,names,imgs) values ('12','test1','r.png')"]; // NSString *newQuery = [NSString stringWithFormat:@"select * from list_tbl"]; const char *sql = [newQuery cStringUsingEncoding:NSASCIIStringEncoding]; NSLog(@"update query is %@",newQuery); if(sqlite3_prepare_v2(database, sql, -1, &compiled_statement1, NULL) == SQLITE_OK) { int result = sqlite3_step(compiled_statement1); sqlite3_reset(compiled_statement1); NSLog(@"result %d", result); if(result != SQLITE_ERROR) { int lastInsertId = sqlite3_last_insert_rowid(database); NSLog(@"x %d", lastInsertId); } } } sqlite3_finalize(compiled_statement1); sqlite3_close(database); [tabelView reloadData];// this is also not working }

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Selecting Date Range on a PHP form and displaying results from MySQL database

- by Sarah HSL

This may be something simple but I cant understand why this wouldn't work.. I have a php form where you can select a date range from drop downs. I've given the field names day, month year, and day1, month1, year1. When clicking submit it takes you to a second php form. Here is the code for second form: <?php $username="***"; $password="***"; $database="****"; mysql_connect('localhost',$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $day = $_GET['day']; $month = $_GET['month']; $year = $_GET['year']; $day1 = $_GET['day1']; $month1 = $_GET['month1']; $year1 = $_GET['year1']; $date1 = "$year-$month-$day"; $date2 = "$year1-$month1-$day1"; $query = "SELECT * FROM main_stock WHERE curr_timestamp BETWEEN '$date1' AND '$date2'"; $result=mysql_query($query); $num=mysql_num_rows($result); ?> <table border="1" cellspacing="2" cellpadding="2"> <tr> <td>Product Description</td> <td>Category</td> <td>Master Category</td> <td>Barcode</td> <td>Status</td> <td>TimeStamp</td> <td>New Own</td> <td>Serial No.</td> </tr> <?php $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"product_desc"); $f2=mysql_result($result,$i,"category"); $f3=mysql_result($result,$i,"mastercategory"); $f4=mysql_result($result,$i,"barcode"); $f5=mysql_result($result,$i,"status"); $f6=mysql_result($result,$i,"curr_timestamp"); $f7=mysql_result($result,$i,"newown"); $f8=mysql_result($result,$i,"serial"); ?> <tr> <td><?php echo $f1; ?></td> <td><?php echo $f2; ?></td> <td><?php echo $f3; ?></td> <td><?php echo $f4; ?></td> <td><?php echo $f5; ?></td> <td><?php echo $f6; ?></td> <td><?php echo $f7; ?></td> <td><?php echo $f8; ?></td> </tr> <?php $i++; } $num_rows = mysql_num_rows($result); echo "$num_rows Rows\n"; mysql_close(); ?> Is there any reason this wouldn't work? I'm not sure where I am going wrong. It displays results when there is another option as well as the date such as 'status' but when this is taken out and I just want to display all the results between the date range it doesn't work.. This works: <?php $username="+++"; $password="+++"; $database="+++"; mysql_connect('localhost',$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $day = $_GET['day']; $month = $_GET['month']; $year = $_GET['year']; $day1 = $_GET['day1']; $month1 = $_GET['month1']; $year1 = $_GET['year1']; $status = $_GET['status']; $date1 = "$year-$month-$day"; $date2 = "$year1-$month1-$day1"; $query = "SELECT * FROM main_stock WHERE status = '$status' AND curr_timestamp BETWEEN '$date1' AND '$date2'"; $result=mysql_query($query); $num=mysql_num_rows($result); ?> <table border="1" cellspacing="2" cellpadding="2"> <tr> <td>Product Description</td> <td>Category</td> <td>Master Category</td> <td>Barcode</td> <td>Status</td> <td>TimeStamp</td> <td>New Own</td> <td>Serial No.</td> </tr> <?php $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"product_desc"); $f2=mysql_result($result,$i,"category"); $f3=mysql_result($result,$i,"mastercategory"); $f4=mysql_result($result,$i,"barcode"); $f5=mysql_result($result,$i,"status"); $f6=mysql_result($result,$i,"curr_timestamp"); $f7=mysql_result($result,$i,"newown"); $f8=mysql_result($result,$i,"serial"); ?> <tr> <td><?php echo $f1; ?></td> <td><?php echo $f2; ?></td> <td><?php echo $f3; ?></td> <td><?php echo $f4; ?></td> <td><?php echo $f5; ?></td> <td><?php echo $f6; ?></td> <td><?php echo $f7; ?></td> <td><?php echo $f8; ?></td> </tr> <?php $i++; } $num_rows = mysql_num_rows($result); echo "$num_rows Rows\n"; mysql_close(); ?> But when the 'status' field is taken out (and obviously the serial drop down in the first form) it stops working...

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Can I convert Innodb with foreign directly into mysiam?

- by Joe

I want to convert the db with innodb tables into myisam, all of them. How can I do these? there are some foreign keys exist among tables. how can I make this in the best way?

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Return a result in the original page.

- by Josh

When the user submit his data, I take him to a different page where plenty of calculations are made, then I redirect him to the original page with a simple : <?php header("Location:http://mysite.com/index.php"); The problem is I need all the variables and results to be show in this page, but they are obviously stored in the other one, so I need your help please :) ! Thank you for reading this !

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Stretching across 2 rows in Table Layout

- by Will03uk

How do I stretch across 2 columns in the Table Layout. I have 2 rows with a label and edit text on 1 row and I want to have a single button stretch across the whole second row. <?xml version="1.0" encoding="utf-8"?> <TableLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_height="fill_parent" android:layout_width="fill_parent" android:background="#000000" android:stretchColumns="1"> <TableRow> <TextView android:text = "Name: " /> <EditText android:id = "@+id/txtAddName" android:gravity = "right" android:layout_width = "fill_parent" /> </TableRow> <TableRow> <TextView android:text = "Phone: " /> <EditText android:id = "@+id/txtAddPhone" android:gravity = "right" android:layout_width = "fill_parent" /> </TableRow> <TableRow> <Button android:id = "@+id/btnAdd" android:text = "Add Entrie" android:layout_width = "fill_parent" /> </TableRow> <TableRow> <Button android:id = "@+id/btnShow" android:text = "Show all Entries" android:layout_width = "fill_parent" /> </TableRow> <TableRow> <Button android:id = "@+id/btnDelete" android:text = "Delete all Entries" android:layout_width = "fill_parent" /> </TableRow> </TableLayout>

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Using array instead of lots of db queries in PHP

- by Tural Teyyuboglu

My function looks like that. It works but does lots of work (recursively calls itself and does lots of db queries.). There must be another way to do same thing but with array (with one query). I can't figure out how to modify this function to get it work with array. Please help. function genMenu($parent, $level, $menu, $utype) { global $db; $stmt=$db->prepare("select id, name FROM navigation WHERE parent = ? AND menu=? AND user_type=?") or die($db->error); $stmt->bind_param("iii", $parent, $menu, $utype) or die($stmt->error); $stmt->execute() or die($stmt->error); $stmt->store_result(); /* bind variables to prepared statement */ $stmt->bind_result($id, $name) or die($stmt->error); if ($level > 0 && $stmt->num_rows > 0) { echo "\n<ul>\n"; } while ($stmt->fetch()) { echo "<li>"; echo '<a href="?page=' . $id . '">' . $name . '</a>'; //display this level's children genMenu($id, $level+1, $menu, $utype); echo "</li>\n\n"; } if ($level > 0 && $stmt->num_rows > 0) { echo "</ul>\n"; } $stmt->close(); }

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Efficient way to combine results of two database queries.

- by ensnare

I have two tables on different servers, and I'd like some help finding an efficient way to combine and match the datasets. Here's an example: From server 1, which holds our stories, I perform a query like: query = """SELECT author_id, title, text FROM stories ORDER BY timestamp_created DESC LIMIT 10 """ results = DB.getAll(query) for i in range(len(results)): #Build a string of author_ids, e.g. '1314,4134,2624,2342' But, I'd like to fetch some info about each author_id from server 2: query = """SELECT id, avatar_url FROM members WHERE id IN (%s) """ values = (uid_list) results = DB.getAll(query, values) Now I need some way to combine these two queries so I have a dict that has the story as well as avatar_url and member_id. If this data were on one server, it would be a simple join that would look like: SELECT * FROM members, stories WHERE members.id = stories.author_id But since we store the data on multiple servers, this is not possible. What is the most efficient way to do this? Thanks.

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How to set binary data using setBlob() in C++ connector

- by Paul

I know this has been asked before, and I tried to implement the solution, but I just get exception errors when I call ps-executeUpdate(). Has anyone got an explicit example?

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Determine week number based on starting date

- by kreetiv

I need help to create a function to determine the week number based on these 2 parameters: Starting date Specified date For example, if I specify April 7, 2010 as the starting date & passed April 20, 2010 as the date to lookup, I would like the function to return WEEK 2. Another example, if I set March 6, 2010 as starting date and looked up April 5, 2010 then it should return WEEK 6. I appreciate your time and help.

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How to select last row of mysql_query?

- by sergdev

It is possible to select last row selected by mysql_query in php without iterating using mysql_fetch_row from first row till last? If so, what should I use?

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How do I make all the finders on the model ignorecase?

- by Glex

I have a model with several attributes, among them title and artist. The case of title and artist should be ignored in all the Active Record finders. Basically, if title or artist are present in the :conditions (or dynamically i.e. find_all_by_artist), then the WHERE artist = :artist should become WHERE UPPER(artist) = UPPER(:artist) or something along these lines. Is there a way of doing it with Rails?

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Jquery Autocomplete after space press

- by Limpep

I am having an issue with my auto-complete feature such as when a user presses the space button the auto-complete doesn't show up again. Here is my code script type="text/javascript"> function lookup(inputString) { if(inputString.length == 0) { // Hide the suggestion box. $('#suggestions').hide(); } else { $.post("autocomplete.php", { queryString: ""+inputString+"" }, function(data){ if(data.length >0) { $('#suggestions').show(); $('#autoSuggestionsList').html(data); } }); } } // lookup function fill(thisValue) { $('#tag').val(thisValue); setTimeout("$('#suggestions').hide();", 200); } here my php code <?php require_once('config.php'); $db = new mysqli(DB_HOST, DB_USER, DB_PASSWORD,DB_DATABASE); if(!$db) { // Show error if we cannot connect. echo 'ERROR: Could not connect to the database.'; } else { // Is there a posted query string? if(isset($_POST['queryString'])) { $queryString = $db->real_escape_string($_POST['queryString']); // Is the string length greater than 0? if(strlen($queryString) >0) { // Run the query: We use LIKE '$queryString%' // The percentage sign is a wild-card, in my example of countries it works like this... // $queryString = 'Uni'; // Returned data = 'United States, United Kindom'; $query = $db->query("SELECT name FROM tag WHERE name LIKE '$queryString%' ORDER BY name LIMIT 10"); if($query) { // While there are results loop through them - fetching an Object (i like PHP5 btw!). while ($result = $query ->fetch_object()) { // Format the results, im using <li> for the list, you can change it. // The onClick function fills the textbox with the result. echo '<li onClick="fill(\''.$result->name.'\');">'.$result->name.'</li>'; } } else { echo 'ERROR: There was a problem with the query.'; } } else { // Dont do anything. } // There is a queryString. } else { echo 'There should be no direct access to this script!'; } } ? Any help would be great, thanks.

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SQL query INSERT not working inserting values into my DB.

- by Aiden Ryan

Hello, I'm trying to insert registration data into a database but my php code isn't inserting the values into the DB although I'm not getting any errors either, can someone help me? this is the code i'm currently using: $connect = mysql_connect("localhost","myusername","mypassword"); mysql_select_db("application"); $queryreg = mysql_query('INSERT INTO users("username","password","email","date") VALUES("$username","$password","$email","$date")'); die ("You Have Been Registered."); I just need to add the username password email and date into the fields i have specified but it won't work, please someone help!

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Combining two queries on same table

- by user1830856

I've looked through several previous questions but I am struggling to apply the solutions to my specific example. I am having trouble combining query 1 and query 2. My query originally returned (amongst other details) the values "SpentTotal" and "UnderSpent" for all members/users for the current month. My issue has been adding two additional columns to this original quert that will return JUST these two columns (Spent and Overspent) but for the previous months data Original Query #1: set @BPlanKey = '##CURRENTMONTH##' EXECUTE @RC = Minimum_UpdateForPeriod @BPlanKey SELECT cm.clubaccountnumber, bp.Description , msh.PeriodMinObligation, msh.SpentTotal, msh.UnderSpent, msh.OverSpent, msh.BilledDate, msh.PeriodStartDate, msh.PeriodEndDate, msh.OverSpent FROM MinimumSpendHistory msh INNER JOIN BillPlanMinimums bpm ON msh.BillingPeriodKey = @BPlanKey and bpm.BillPlanMinimumKey = msh.BillPlanMinimumKey INNER JOIN BillPlans bp ON bp.BillPlanKey = bpm.BillPlanKey INNER JOIN ClubMembers cm ON cm.parentmemberkey is null and cm.ClubMemberKey = msh.ClubMemberKey order by cm.clubaccountnumber asc, msh.BilledDate asc Query #2, query of all columns for PREVIOUS month, but I only need two (spent and over spent), added to the query from above, joined on the customer number: set @BPlanKeyLastMo = '##PREVMONTH##' EXECUTE @RCLastMo = Minimum_UpdateForPeriod @BPlanKeyLastMo SELECT cm.clubaccountnumber, bp.Description , msh.PeriodMinObligation, msh.SpentTotal, msh.UnderSpent, msh.OverSpent, msh.BilledDate, msh.PeriodStartDate, msh.PeriodEndDate, msh.OverSpent FROM MinimumSpendHistory msh INNER JOIN BillPlanMinimums bpm ON msh.BillingPeriodKey = @BPlanKeyLastMo and bpm.BillPlanMinimumKey = msh.BillPlanMinimumKey INNER JOIN BillPlans bp ON bp.BillPlanKey = bpm.BillPlanKey INNER JOIN ClubMembers cm ON cm.parentmemberkey is null and cm.ClubMemberKey = msh.ClubMemberKey order by cm.clubaccountnumber asc, msh.BilledDate asc Big thank you to any and all that are willing to lend their help and time. Cheers! AJ CREATE TABLE MinimumSpendHistory( [MinimumSpendHistoryKey] [uniqueidentifier] NOT NULL, [BillPlanMinimumKey] [uniqueidentifier] NOT NULL, [ClubMemberKey] [uniqueidentifier] NOT NULL, [BillingPeriodKey] [uniqueidentifier] NOT NULL, [PeriodStartDate] [datetime] NOT NULL, [PeriodEndDate] [datetime] NOT NULL, [PeriodMinObligation] [money] NOT NULL, [SpentTotal] [money] NOT NULL, [CurrentSpent] [money] NOT NULL, [OverSpent] [money] NULL, [UnderSpent] [money] NULL, [BilledAmount] [money] NOT NULL, [BilledDate] [datetime] NOT NULL, [PriorPeriodMinimum] [money] NULL, [IsCommitted] [bit] NOT NULL, [IsCalculated] [bit] NOT NULL, [BillPeriodMinimumKey] [uniqueidentifier] NOT NULL, [CarryForwardCounter] [smallint] NULL, [YTDSpent] [money] NOT NULL, [PeriodToAccumulateCounter] [int] NULL, [StartDate] [datetime] NOT NULL,

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Select multi-select form from array

- by Budove

Here's the issue. I have a database column called pymnt_meth_pref, which contains a comma separated string of payment methods chosen from a multiselect form. <td>Payment Methods Used: <input type="checkbox" name="pyment_meth_pref[]" value="Cash">I can pay with cash. <input type="checkbox" name="pyment_meth_pref[]" value="Check">I can pay by check. <input type="checkbox" name="pyment_meth_pref[]" value="Credit Card">I can pay by credit card. <input type="checkbox" name="pyment_meth_pref[]" value="Paypal">I can pay with Paypal. </td> This array is posted to a variable and turned into a comma separated string if (isset($_POST['pyment_meth_pref'])) $pymntmethpref = implode(", ", $_POST['pyment_meth_pref']); if (isset($_POST['pyment_meth_acc'])) $pymntmethacc = implode(", ", $_POST['pyment_meth_acc']); This is then inserted into the database as a comma separated string. What I would like to do, is take this string and apply the values to the original form when the user goes back to the form as 'pre-selected' checkboxes, indicated that the user has already selected those values previously, and keeping those values in the database if they choose to edit any other information in the form. I'm assuming this would need to be done with javascript but if there is a way to do it with PHP I'd rather do it that way.

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need an sql query

- by CKeven

I currently have two tables: 1. car(plate_number, brand, cid) 2. borrow(StartDate, endDate, brand, id) I want to write a query to get all available brand and count of available cars for each brand

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add array element to row returned from sql query

- by bert

I want to add an additional value into an array before passing it to json_encode function, but I can't get the syntax right. $result = db_query($query); // $row is a database query result resource while ($row = db_fetch_object($result)) { $stack[] = $row; // I am trying to 'inject' array element here $stack[]['x'] = "test"; } echo json_encode($stack);

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How to get regex split from other var

- by Dean

Hi, $dbLink = mysql_connect('localhost', 'root', 't'); mysql_select_db('pc_spec', $dbLink); $html = file_get_contents('http://localhost/pc_spec/scrape.php?q=amd+955'); echo $html; $html = strip_tags($html); $price = ereg("\$.{6}", $html); $html = mysql_real_escape_string($html); $price = mysql_real_escape_string($price); $insert = mysql_query("INSERT INTO parts(part, price) values('$html','$price')") or var_dump(mysql_error()); How can I get $price to match $.{6} and insert this value (eg. $111.11) into a database and remove it from $html? Do I need to use explode? Thanks

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Translate SQL statement into named_scope?

- by keruilin

How can I translate this SQL into a named_scope? Also, I want the total comments param to be passed through a lambda. "select users., count() as total_comments from users, comments where (users.id = comments.user_id) and (comments.public_comment = 1) and (comments.aasm_state = 'posted') and (comments.forum_user_id is null) group by users.id having total_comments 25"

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how can we change the value by using radio buttons

- by magna

I am making a website in Adobe Dreamweaver with php. In the site there’s a 3 buttons for selecting payment method that will act as the continue button. What I want is when the user checks a radio buttons (I agree button), it will be add with that amount and display with previous amount.. there is three buttons which has the corresponding values(amount in pounds).. plz check my website http://www.spsmobile.co.uk in this linkgo to mobile phone unlocking and after add the cart click make payment it will go to next page there is a delivery mail details.. for that delivery mail details only am asking.. here i mentioned code: <input id="radio-1" type="radio" name="rmr" value="1"> <label for="radio-1">£3</label> <input id="radio-2" type="radio" name="rmr" value="2"> <label for="radio-2">£5.5</label> <input id="radio-3" type="radio" name="rmr" value="4"> <label for="radio-3">£10</label> <div class="total-text" style="font-size:36px">£10</div> var total = parseInt($("div.total-text").text().substring(1), 10); $("input[name='rmr']").bind('change', function() { var amount = 0; switch (this.value) { case "1": amount = 3; break; case "2": amount = 5.5; break; case "4": amount = 10; break; } $("div.total-text").text("£" + (total + amount)); }); but there is no change , my previous amount did not add with that. while am clicking previous amount only displayed on browser.. i need when i cliks radio button the value should change correspondingly.. where i did that mistake...plz give me some idea and what should i do..is there any need for storing db.. thanks in adv

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- by Nisreen KH

- by João Madureira Pires

- by planetp

- by newtoaccess

- by Dan Horvat

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- by Sarah HSL

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- by Josh

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- by Tural Teyyuboglu

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