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  • How to do this in a smart way

    - by Azzyh
    Hello SO. My websystem im coding with now is integrated from the originally phpBB system. With this i mean when you log on my websystem, you have actually logged into the forum from the login page. Now i came to the "log out" part, and i want to make it smart. Right now its a simply link with logout: <a href="<?php echo BASEDIR; ?>../../ucp.php?mode=logout&sid=<? echo $user->data['session_id']; ?>" style="margin-left: 14px; font-size: 10px;">- Log Out</a> As you see in the link it refers to the forum´s ucp.php?mode=logout, and you need to have the SID variable in it in order to log out right.. anyway.. I want to do this log out part in a smart way, i mean, not so you land on the forum´s "you have now been logged out", i want something maybe like run this page in background when you click, and then it refreshes the current page your on. Or should it be smarter just try to modify the phpbb file ucp.php? I think its hard coded, and not the way I am coding, so thats why i find it abit tricky. Thank you for your answers and examples on how this could be done, in a smart way..

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  • Amazon EC2 + SSL Godaddy are not routing properly in HTTPS

    - by azngunit81
    I have an Amazon EC2 + SSL just installed on GoDaddy. I have successfully managed to install it and get the green https on the main domain https://www.example.com however it doesn't any https://www.example.com/something but the route works under http://www.example.com I am using an .htacess file for some rewrite. Options -MultiViews RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^ index.php [L] the Ec2 instance is ubuntu if that helps in anyway.

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  • Send email from webpage without postback/refresh

    - by jb
    Hi all. Long time reader, first time writer. Quick query i hope someone can help me with. I have a webpage (php, javascript) which has a small contact form for a user to fill in and email us. Not a problem in itself, i have a working form already. Nothing noteworthy, just a form posting to a php page which sends an email. <form id="myform" name="myform" method="post" action="Mailer.php"> So user fills in form, hits submit and the page changes to mailer.php and they find their way back to where they were. What I want instead is for the to stay on the same page when submit is pushed. The form div to update itself to just say 'message sent' or something. I just want to avoid a full page refresh. Much like how on say facebook, commenting on a status only updates that div. Hope that is phrased clearly enough. Cheers all,

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  • jQuery and MySQL

    - by Wayne
    I have taken a jQuery script which would remove divs on a click, but I want to implement deleting records of a MySQL database. In the delete.php: <?php $photo_id = $_POST['id']; $sql = "DELETE FROM photos WHERE id = '" . $photo_id . "'"; $result = mysql_query($sql) or die(mysql_error()); ?> The jQuery script: $(document).ready(function() { $('#load').hide(); }); $(function() { $(".delete").click(function() { $('#load').fadeIn(); var commentContainer = $(this).parent(); var id = $(this).attr("id"); var string = 'id='+ id ; $.ajax({ type: "POST", url: "delete.php", data: string, cache: false, success: function(){ commentContainer.slideUp('slow', function() {$("#photo-" + id).remove();}); $('#load').fadeOut(); } }); return false; }); }); The div goes away when I click on it, but then after I refresh the page, it appears again... How do I get it to delete it from the database? Thanks :) EDIT: Woopsie... forgot to add the db.php to it, so it works now .<

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  • Getting Response From Jquery JSON

    - by Howdy_McGee
    I'm having trouble getting a response from my php jquery / json / ajax. I keep combining all these different tutorials together but I still can't seem to pull it all together since no one tutorial follow what I'm trying to do. Right now I'm trying to pass two arrays (since there's no easy way to pass associative arrays) to my jquery ajax function and just alert it out. Here's my code: PHP $names = array('john doe', 'jane doe'); $ids = array('123', '223'); $data['names'] = $names; $data['ids'] = $ids; echo json_encode($data); Jquery function getList(){ $.ajax({ type: "GET", url: 'test.php', data: "", complete: function(data){ var test = jQuery.parseJSON(data); alert(test.names[0]); alert("here"); } }, "json"); } getList(); In my html file all I'm really calling is my javascript file for debugging purposes. I know i'm returning an object but I'm getting an error with null values in my names section, and i'm not sure why. What am I missing? My PHP file returns {"names":["john doe","jane doe"],"ids":["123","223"]} It seems to be just ending here Uncaught TypeError: Cannot read property '0' of undefined so my sub0 is killing me.

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  • Disabling Text field with Javascript when value in drop down box is from mysql

    - by SteveJ313
    Hi I have a simple script in HTML, using a dropdown menu. When the value 1 is selected, the user can write in the text field, if value 2 is selected, it disables the text field. However, i changed the values of the dropdown menu, so that one value was from a mysql table(using PHP) and the other remained 'option value='1''. Yet now neither text field is disabled. Below is the code. `<script type="text/javascript"> function findselected() { if (document.form.selmenu.value == <?php echo $id; ?>) { document.form.txtField.disabled=true; // return false; // not sure this line is needed } else { document.form.txtField.disabled=false; // return false; // not sure this line is needed } } ` And the PHP section if(mysql_num_rows($SQL) == 1) { echo "<select name='selmenu' onChange='findselected()'>"; echo "<label>TCA_Subject</label>"; while ($row=mysql_fetch_array($SQL)) { echo "<option value='$id'>$thing</option>"; echo "<option value='2'>Choice 2</option>"; } } echo "<option value=$userid>'Choice 1'</option>"; ?> <option value='2'>Choice 2</option>"; </select> I have tried taking the second option value out of the loop, putting it into html, editing the variable in the javascript function. There is not a fault with the PHP as it is retrieving the right results and displaying it, yet the text field doesnt become disabled. Does anyone know of a possible solution? Thanks

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  • why does my <br> not work ?

    - by Vince
    I am returning a PHP array back to a JQuery call for appending into a div called "name-data". I want my array to be listed vertically, so I concatenate a br tag in the PHP however, when it gets to the HTML page the br is not being rendered, it just comes out as text. I have tried the various forms of br all without luck. I am new to JQuery - What am I doing wrong ? Many Thanks ! PHP: $result = mysqli_query($con,"SELECT FirstName FROM customer limit 5"); while($row = mysqli_fetch_array($result)) { echo $row['FirstName']."<br />"; } JQuery: $('input#name-submit').on('click',function(){ var name = $('input#name').val(); if($.trim(name) !=''){ $.post('search.php',{name:name}, function(data){ $('div#name-data').text(data); }); } }); HTML Name:<input type="text" id="name"> <input type="submit" id="name-submit" value="grab"> <div id="name-data"> </div>

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  • Upload .txt and keep formating

    - by s2xi
    I have been trying to upload a .txt to my server via a simple php script I made. Everything seems to uploaded correctly, if I open the .txt in Dreamweaver I can see all the formatting is still in tact with spaces and paragraph breaks. The problem I have is when I try to open that file with PHP and import the contents onto my site. I'm not using an editor right now, just a simple div where the contents are echoed. I don't have much experience with uploading/downloading using PHP. Am I not using a command to handle the file contents and keep the initial formatting? In the end I want the user to upload a file, and have PHP read the file and extract certain elements from it based on the number of spaces between paragraph breaks and such. I was able to actually echo the .txt using URLENCODE() which kept the formatting and made all my spaces +'s. Thats the closes I got, but the original file isn't uploaded in the format so I can't do a count for +'s and select x characters after the last +. Hmmm, if someone knows of a script already available that can do this or similar to with me just tweaking that would be awesome.

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  • Minimizing server load in case of many XMLHttpRequest calls

    - by user1888975
    I am making a website where users are to like some articles. Whenever the like button is clicked I am sending a XMLHttpRequest to the server to run a file called like_clicked.php along with the get data of article id and user id. This file takes article id and user id and updates the sql database and also adds a node in an xml file related to the user. This is the first time I am doing something for mass usage. I am worried about the server load when too many users call the like_clicked.php file. Please help me, if this method is ok. I am also thinking of an alternative in case the above method fails. I am thinking of making many like_clicked files (namely like_clicked1.php, like_clicked2.php ... ) to minimize load on a single i-node. Is there a method to detect that it is better to call the next like_clicked file. Here we would need to detect how many calls per unit time are coming for the particular file. How do we handle this? Thanks in advance.

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  • Failed to load url in Dom Document?

    - by Lakhan
    im trying to get latitude and longtitude from google map by giving address. But its giving error.when i directly copy url to browser url bar.its giving correct result.If anybody know the answer .Plz reply. Thanx in advance Here is my code. <?php $key = '[AIzaSyAoPgQlfKsBKQcBGB01cl8KmiPee3SmpU0]'; $opt = array ( 'address' => urlencode('Kolkata,India, ON') , 'output' => 'xml' ); $url = 'http://maps.google.com/maps/geo?q='.$opt['address'].'&output='.$opt['output'].'&oe=utf8&key='.$key; $dom = new DOMDocument(); $dom->load($url); $xpath = new DomXPath($dom); $xpath->registerNamespace('ge', 'http://earth.google.com/kml/2.0'); $statusCode = $xpath->query('//ge:Status/ge:code'); if ($statusCode->item(0)->nodeValue == '200') { $pointStr = $xpath->query('//ge:coordinates'); $point = explode(",", $pointStr->item(0)->nodeValue); $lat = $point[1]; $lon = $point[0]; echo '<pre>'; echo 'Lat: '.$lat.', Lon: '.$lon; echo '</pre>'; } ?> Following error has occured: Warning: DOMDocument::load(http://maps.google.com/maps/geo? q=Kolkata%252CIndia%252C%2BON&output=xml&oe=utf8&key=%5BAIzaSyAoPgQlfKsBKQcBGB01cl8KmiPee3SmpU0%5D) [domdocument.load]: failed to open stream: HTTP request failed! HTTP/1.0 400 Bad Request in C:\xampp\htdocs\draw\draw.php on line 19 Warning: DOMDocument::load() [domdocument.load]: I/O warning : failed to load external entity "http://maps.google.com/maps/geo?q=Kolkata%252CIndia%252C%2BON&output=xml&oe=utf8&key=%5BAIzaSyAoPgQlfKsBKQcBGB01cl8KmiPee3SmpU0%5D" in C:\xampp\htdocs\draw\draw.php on line 19 Notice: Trying to get property of non-object in C:\xampp\htdocs\draw\draw.php on line 26

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  • jquery form extension ajax

    - by Craig Wilson
    http://www.malsup.com/jquery/form/#html I have multiple forms on a single page. They all use the same class "myForm". Using the above extension I can get them to successfully process and POST to ajax-process.php <script> // wait for the DOM to be loaded $(document).ready(function() { // bind 'myForm' and provide a simple callback function $('.myForm').ajaxForm(function() { alert("Thank you for your comment!"); }); }); </script> I'm having an issue however with the response. I need to get the comment that the user submitted to be displayed in the respective div that it was submitted from. I can either set this as a hidden field in the form, or as text in the ajax-process.php file. I can't work out how to get the response from ajax-process.php into something I can work with in the script, if I run the following it appends to all the forms (obviously). The only way I can think to do it is to repeat the script using individual DIV ID's instead of a single class. However there must be a way of updating the div that the ajax-process.php returns! // prepare the form when the DOM is ready $(document).ready(function() { // bind form using ajaxForm $('.myForm').ajaxForm({ // target identifies the element(s) to update with the server response target: '.myDiv', // success identifies the function to invoke when the server response // has been received; here we apply a fade-in effect to the new content success: function() { $('.myDiv').fadeIn('slow'); } }); }); Any suggestions?!

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  • MySQL connection attempt works fine in 5.2.9 but not in 5.3.0 - Help?

    - by Rich
    Hi, I'm having trouble making a secondary MySQL connection (to a separate, external DB) in my code. It works fine in PHP 5.2.9 but fails to connect in PHP 5.3.0. I'm aware of (at least some) of the changes needed to make successful MySQL connections in the newer version of PHP, and have succeeded before, so I'm not sure why it isn't working this time. I already have a db connection open to a local database. This function below is then used to make an additional connection to a separate, remote directory. The included config file simply contains the external database details (host, user, pass and name). I have checked and it is being included correctly. function connectDP() { global $dpConnection; include("secondary_db_config.php); $dpConnection = mysql_connect($dp_dbHost, $dp_dbUser, $dp_dbPass, true) or DIE("ERROR: Unable to connect to Deployment Platform"); mysql_select_db($dp_dbName, $dpConnection) or DIE("ERROR 006: Unable to select Deployment Platform Database"); } I then attempt to make this new connection simply by calling this function externally: connectDP(); But when loading the page (in 5.3.0), I get the message: ERROR: Unable to connect to Deployment Platform I'm using the optional new_link flag boolean as the fourth argument in the mysql_connect() function and it's still not working. I've been wracking my brain this morning trying to figure out why this connection doesn't work (while I've done something very similar elsewhere to a separate second database that does work). Any help would be appreciated. Thanks! Rich

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  • Fatal error: Allowed memory size exhausted...

    - by Nano HE
    HI, I upload my php testing script to online vps server just now. The script used to parse a big size XML file(about 4M, 7000Lines). But my IE explorer show the online error message below. Fatal error: Allowed memory size of 16777216 bytes exhausted (tried to allocate 77 bytes) in /var/www/test/result/index.php on line 26 I am sure I already tested the php script on localhost successfully. Is there any configuration need be enable/modify on my VPS? Such as php.ini or some setting for apache server? I just verified there are about 200M memory usage are avaliable for my VPS. How can I fix this? ...... function startElementHandler ($parser,$name,$attrib){ global $usercount; global $userdata; global $state; // Line #26; //Debug //print "name is: ".$name."\n"; switch ($name) { case $name=="_ID" : { $userdata[$usercount]["first"] = $attrib["FIRST"]; $userdata[$usercount]["last"] = $attrib["LAST"]; $userdata[$usercount]["nick"] = $attrib["NICK"]; $userdata[$usercount]["title"] = $attrib["TITLE"]; break; } ...... default : {$state=$name;break;} } }

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  • Processing data from an AJAX request

    - by Josh K
    I have a PHP API I'm working with that outputs everything as JSON. I need to call one of the API methods and parse it out using an AJAX request. I am using jQuery (though it shouldn't matter). When I make the request it errors out with a "parsererror" as the textStatus and a "Syntax Error: invalid label" when I make the request. Simplified code: $.ajax ({ type: "POST", url: "http://mydomain.com/api/get/userlist/"+mid, dataType: "json", dataFilter: function(data, type) { /* Here we assume and pray */ users = eval(data); alert(users[1].id); }, success: function(data, textStatus, XMLHttpRequest) { alert(data.length); // Should be an array, yet is undefined. }, error: function(XMLHttpRequest, textStatus, errorThrown) { alert(textStatus); alert(errorThrown); }, complete: function(XMLHttpRequest, textStatus) { alert("Done"); } }); If I leave off the eval(data) then everything works fine. Well, except for data still being undefined in success. Note that I'm taking an array of objects in PHP and then passing them out through json_encode. Would that make any difference? There has been no progress made on this. I'm willing to throw more code up if someone believes they can help. Here is the PHP side of things private function _get_user_colors($id) { $u = new User(); $u->get_where(array('id' => $id)); $bar = array(); $bar['user'] = $u->stored; foreach($user->colors as $color) { $bar['colors'][] = $color; } echo(json_encode($bar)); } I have had zero issues using this with other PHP based scripts. I don't know why Javascript would take issue with it.

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  • JQuery/AJAX: Loading external DIVs using dynamic content

    - by ticallian
    I need to create a page that will load divs from an external page using Jquery and AJAX. I have come across a few good tutorials, but they are all based on static content, my links and content are generated by PHP. The main tutorial I am basing my code on is from: http://yensdesign.com/2008/12/how-to-load-content-via-ajax-in-jquery/ The exact function i need is as follows: Main page contains a permanent div listing some links containing a parameter. Upon click, link passes parameter to external page. External page filters recordset against parameter and populates div with results. The new div contains a new set of links with new parameters. The external div is loaded underneath the main pages first div. Process can then be repeated creating a chain of divs under each other. The last div in the chain will then direct to a new page collating all the previously used querystrings. I can handle all of the PHP work with populating the divs on the main and external pages. It's the JQuery and AJAX part i'm struggling with. $(document).ready(function(){ var sections = $('a[id^=link_]'); // Link that passes parameter to external page var content = $('div[id^=content_]'); // Where external div is loaded to sections.click(function(){ //load selected section switch(this.id){ case "div01": content.load("external.php?param=1 #section_div01"); break; case "div02": content.load("external.php?param=2 #section_div02"); break; } }); The problem I am having is getting JQuery to pass the dynamically generated parameters to the external page and then retrieve the new div. I can currently only do this with static links (As above).

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  • MySql backup (MySqldump questions)

    - by Camran
    I have a vps with ubuntu 9 server. I need to backup my MySql database. Can MySql make backups automatically? If so, how? If not, how should I do it then? The website is a classifieds website (PHP, MySql etc) Thanks

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  • [Zend Framework] Forms and success output

    - by rasouza
    Well, It's a beginer's question but I really don't know what is the best way. I have a basic CRUD (Create, Retrieve, Update and Delete) in my project and I'd like to output some message if succeded or not in a div inside the same page. So, basically, I have a form which action is setted to the same page and I have a div #statusDiv below this same form which I'd like to output something like Register included with success. What is the best way for doing this? Set a flag in the controller $this->view->flagStatus = 'message' then call it in the view? Just to make it more clear. It's my code: //IndexController.php indexAction() ... //Check if there's submitted data if ($this->getRequest()->isPost()) { ... $registries->insert($data); $this->view->flagStatus = 'message'; $this->_redirect('/'); } Then my view: .... <?php if ($this->flagStatus) { ?> <div id="divStatus" class="success span-5" style="display: none;"> <?php echo $this->flagStatus; ?> </div> <?php } ?> ....

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  • How much traffic per month would my site need? [closed]

    - by camran
    HOW MANY GB OF TRAFFIC IS REQUIRED PER MONTH? Any way to calculate this? Webhosting companies have a limit when ordering, so I need to know... A classifieds website using PHP and MYSQL. MYSQL has around 500thousand records. Not much graphics. Pretty advanced search feautures. How much traffic would I need do you think? Thanks

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  • Trigger alert when database entries are added, not when they are removed

    - by Jeremy
    I have a jQuery script running that makes a periodic AJAX call using the following code. var a = moment(); var dayOfMonth = a.format("MMM Do"); var timeSubmitted = a.format("h:mm a"); var count_cases = -1; var count_claimed = -1; setInterval(function(){ //check if new lead was added to the db $.ajax({ type : "POST", url : "inc/new_lead_alerts_process.php", dataType: 'json', cache: false, success : function(response){ $.getJSON("inc/new_lead_alerts_process.php", function(data) { if (count_cases != -1 && count_cases != data.count) { window.location = "new_lead_alerts.php?id="+data.id; } count_cases = data.count; }); } }); This is the PHP that runs with each call: $count = mysql_fetch_array(mysql_query("SELECT count(*) as count FROM leads")); $client_id = mysql_fetch_array(mysql_query("SELECT id, client_id FROM leads ORDER BY id DESC LIMIT 1")); echo json_encode(array("count" => $count['count'], "id" => $client_id['id'], "client_id" => $client_id['client_id'])); I need to change the code so that the alert only triggers when a new entry is added to the database, not when an existing entry is removed. As it stands, the alert fires on both events. Any help is greatly appreciated.

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  • Display error message at top of form

    - by moustafa
    Hello, I'm trying to get the following error to show when some once presses the submit button and has not filled in the required field/s. My PHP code is. <?php require_once("includes/database.php"); require_once("includes/functions.php"); if(isset($_POST['full_name'])) { $required = array('full_name','user_name','email','pwd','pwd2'); $missing = array(); $validation = array( 'full_name' => 'Please provide your full name', 'user_name' => 'Please provide your username', 'email' => 'Please provide your valid email address', 'pwd' => 'Please provide your password', 'pwd2' => 'Please confirm your password', 'userdup' => 'Username already registered', 'emaildup' => 'Email address already registered', 'mismatch' => 'Passwords do not match' ); //Sanitise and clean function $full_name = escape($_POST['full_name']); $user_name = escape($_POST['user_name']); $email = escape($_POST['email']); $pwd = escape($_POST['pwd']); $pwd2 = escape($_POST['pwd2']); foreach($_POST as $key => $value) { $value = trim($value); if(empty($value) && in_array($key,$required)) { array_push($missing,$key); } else { ${$key} = escape($value); } }

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  • autoreload webpage on new release

    - by user3726562
    I have a website in PHP which is completely ajax-based. There is an index.php, but a part from it, all the other page are never rendered directly into the browser. Instead, all the post and get request are done tfrom javascript through ajax. So basically, if you go to /contact.php you will not see anything. All the pages are rendered inside index.php. So, there are a lot of people that use this page that are not very good in using the web. Asking them to "refresh" the page makes them to wonder what we are talking about. Unfortunately. The biggest issue happens when we do a new release. Especially the javascript code (but not only) can be the old one in a client's webpage as they maybe havent refreshed the page for some week (lol). S I do an svn-update and the new code is on the server. I just refresh my page and see the new features. However, the poor guys that dont really know how to make a refresh, will not see anything. I have added a big button on the page with the text "refresh". Which makes a location.reload. Hopefully this can help a few of them. But my question is: how to "force" the browser to reload itself when a new svn-version has been released? Hopefully in a simple way, without needing some node.js, javascript timer or stuff like that. It is also quite important to not refresh the page when the user is doing something with the page (maybe writing a mail in the UI, and then suddenly the page get refreshed: not so good).

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  • AJAX Uploading - Not waiting for response before continuing

    - by waxical
    I'm using Blueimp's jQuery Uploader (very good it is too btw) and an S3 handler to upload files and then transfer them to S3 via the S3 API (from the PHP SDK). It works. The problem is, on large files (1GB) it can take anything up to a a few minutes to transfer (via create-object) onto S3. The PHP file that does this is hung-up until this process is complete. The problem is, the uploader (which utilises the jQuery Ajax method) seems to give up waiting and start again everytime. I have thought this was related to PHP INI 'max_input_time' or such, as it seemed to wait around 60 seconds, though this now appears to vary. I have upped the max_input_time in PHP INI and others related - but no further. I've also considered (the more likely) that JS, either in the script or the jQuery method has a timeout. The developer (blueimp) has said there's no such timeout in the front-end script, nor have I seen any and though 'timeout' is referenced in the jQuery Ajax method options, it seems to affect the entire time it uploads rather than the wait for a response - so that's not much use. Any help or guidance gratefully received.

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  • Detect if Download is Complete

    - by user604138
    I have a very simple and standard PHP force download script. How do I check if/when the download has completed in order to notify the user on the clientside? I don't even need to show the progress in real time, I am only interested in the very specific event: "when the download completes". Based on my research, it seems like it would have to be determined from the serverside as there is noondownloadready event and I don't think it is possible to intercept browser events. So it seems that my best bet would be to compare bytes sent to total bytes with some sort of clientside/severside interaction. How would I go about checking the bytes sent from the server for a PHP forced download? is there some sort of global PHP variable that store these data that I can ping with AJAX? <?php header("Content-Type: video/x-msvideo"); header("Content-Disposition: attachment; filename=\"".basename($realpath)."\";"); ... $chunksize = 1 * (1024 * 1024); // how many bytes per chunk if ($size > $chunksize) { $handle = fopen($realpath, 'rb'); $buffer = ''; while (!feof($handle)) { $buffer = fread($handle, $chunksize); echo $buffer; ob_flush(); flush(); } fclose($handle); } else { readfile($realpath); } exit(); ?> The reason I need this: For the project I am working on, it is required that after the download starts, the page redirects to (or displays) a "please wait while the download completes" page. Then, once it is complete, it should redirect to (or display) a "Your download is complete, thank you" page. I am open to other ideas that would achieve the same result.

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  • permissions on upload folder not working

    - by Camran
    I have a php script which uploads images to a folder. I have these permissions on the upload folder: drwxrwxr-- 4 user user 4096 2010-06-02 16:20 temp_images Shouldn't these permissions be enough for files to be uploaded to the folder? But this doesn't work. It only works when I set the permissions to 777. "user" is added to the www-data group, still no luck. Any ideas why?

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