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  • Select distinct... in fulltext search

    - by lam3r4370
    <?php session_start(); $user =$_GET['user']; $conn = mysql_connect("localhost","...","..."); mysql_select_db("..."); $sql= "SELECT filter FROM userfilter WHERE user='$user'"; $mksql = mysql_query($sql); while($row =mysql_fetch_assoc($mksql)) { $filter=$row['filter']; $sql2 = "SELECT DISTINCT * FROM rss WHERE MATCH(content,title) AGAINST ('$filter')"; $mksql2 = mysql_query($sql2) or die(mysql_error()); while($rows=mysql_fetch_assoc($mksql2)) { echo ..... } ?> If I have two rows content that contains the $filter ,it outputs me that content but it's repeating. For example: title|content asd |This is a sample content ,number one das |This is a sample content ,number two .... And if my keywords are "sample" and "number" ,it outputs me twice the title and the content.How to prevent that?

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  • How to retrieve column total when rows are paginated?

    - by Rick
    Hey guys I have a column "price" in a table and I used a pagination script to generate the data displayed. Now the pagination is working perfectly however I am trying to have a final row in my HTML table to show the total of all the price. So I wrote a script to do just that with a foreach loop and it sort of works where it does give me the total of all the price summed up together however it is the sum of all the rows, even the ones that are on following pages. How can I retrieve just the sum of the rows displayed within the pagination? Thank you! Here is the query.. SELECT purchase_log.id, purchase_log.date_purchased, purchase_log.total_cost, purchase_log.payment_status, cart_contents.product_name, members.first_name, members.last_name, members.email FROM purchase_log LEFT JOIN cart_contents ON purchase_log.id = cart_contents.purchase_id LEFT JOIN members ON purchase_log.member_id = members.id GROUP BY id ORDER BY id DESC LIMIT 0,30";

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  • Codeigniter database update

    - by Carry All
    The table is like this and I want to update DecryptionDate by specify ArchiveID and RecipientID this is my code $this->load->database(); $date = date("Y-m-d H:i:s"); $data = array('DecryptionDate' => $date); $array = array('ArchiveID'=>$archiveID.'','RecipientID'=>$userID.''); $this->db->where($array); $this->db->update('log', $data); if ($this->db->affected_rows() > 0) { echo "SUCCESS"; } else { echo "FAIL"; } my problem is I can update the data only when $archiveID is 911 and $userID is test01 but the program fail to update when $archiveID is 911 and $userID is test02

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  • How to select latest change done in the given Table structure?

    - by OM The Eternity
    I have a Table structure as id, trackid, table_name, operation, oldvalue, newvalue, field, changedonetime Now if I have 3 rows for the same "trackid" same "field", then how can i select the latest out of the three? i.e. for e.g.: id = 100 trackid = 152 table_name = jos_menu operation= UPDATE oldvalue = IPL newvalue = IPLcccc field = name live = 0 changedonetime = 2010-04-30 17:54:39 and id = 101 trackid = 152 table_name = jos_menu operation= UPDATE oldvalue = IPLcccc newvalue = IPL2222 field = name live = 0 changedonetime = 2010-04-30 18:54:39 As u can see above the secind entry is the latest change, Now what query I shoud use to get the only one and Latest row out of many such rows...

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  • jQuery: Sorting hierarchical data?

    - by Industrial
    Hi everybody, I have tried for some time to work out a way of sorting nested categories with jQuery. I failed to build my own plugin to do this, so I tried to find something that were available already. Tried a few hours now with this one, http://www.jordivila.net/code/js/jquery/ui-widgetTreeList_inheritance/widgetTreeListSample.aspx and cant get it to work. What are the alternatives of creating a jQuery / jQuery UI script that handles sorting children and parent categories in a way that can be combined with a AJAX PHP backend to handle the actual sorting in the database? Thanks!

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  • PHP getting blank pages after submit a form + signal Segmentation fault (11)

    - by Ole Media
    I few days ago I update my macbook pro to snow leopard, and since then some php files are not showing. This is what happens: I created a php form, when going to 'http://localhost/webform.php' I can see the form just fine. Then, once I submit the form, I just get a blank page. I enable error and warnings reporting under php.ini to make sure I'm not missing something, but still I'm not getting anything, just the blank page. Then I checked under apache log files, and what I notice is that every time I submit the form I see the following line coming up under the apache logs: [Wed Apr 07 21:40:28 2010] [notice] child pid 70223 exit signal Segmentation fault (11) I'm clueless on this one. Any ideas on how to fix it?

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  • Is the time cost constant when bulk inserting data into an indexed table?

    - by SiLent SoNG
    I have created an archive table which will store data for selecting only. Daily there will be a program to transfer a batch of records into the archive table. There are several columns which are indexed; while others are not. I am concerned with time cost per batch insertion: - 1st batch insertion: N1 - 2nd batch insertion: N2 - 3rd batch insertion: N3 The question is: will N1, N2, and N3 roughly be the same, or N3 N2 N1? That is, will the time cost be a constant or incremental, with existence of several indexes? All indexes are non-clustered. The archive table structure is this: create table document ( doc_id int unsigned primary key, owner_id int, -- indexed title smalltext, country char(2), year year(4), time datetime, key ix_owner(owner_id) }

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  • query excuting problem

    - by srini-r85
    hi, i tried to execute following query in php script. $db_selected = mysql_select_db("lumiinc1_sndemo1", $con); if ($db_selected) { echo "database connected"; } else { die ("Can\'t use db : " . mysql_error()); } $sql = "INSERT INTO `markers` ( `name`, `address`, `lat`, `lng`, `id` ) SELECT `name`, `street`, `latitude`, `longitude`, `lid` FROM `location` WHERE NOT EXISTS ( SELECT * FROM `markers` WHERE `location`.`lid` = `markers`.`id` )"; $result = mysql_query($sql); if ($result) { echo "Query executed OK"; } else { die("Invalid query: " . mysql_error()); } script does not show any error.also query executed.but i didn't get my expected result.at the same i try this query in phpmyAdmin i got my expected result. i dont know the cause of this problem. plz any one find the problem . thanks

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  • How to name uploaded files in php to prevent them from being overwritten?

    - by user156814
    I'm trying to add user submitted articles to my website, (only for admins). With each article comes an option to upload up to 3 images. My database is set up like this Articles id user_id title body date_added last_edited Photos id (auto_increment) article_id First I save the article in the database, then I upload the photo (temporarily) then I create a new photo record in the database saving the article_id. Then I rename the uploaded photo to be the same as the primary key of the photo record, and to be a png. $filename = $photo->id . '.png'; I figured this would be a good way to prevent files form being overwritten. This seems flawed to me. Any suggestions on how I should save my records and photos? Thanks

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  • storing image_id after uploading image in article table

    - by Bader
    According to this question i successed to create upload image , but now i need to store the image_id to another table called articles , i do not know if this is correct , but i tried to select the image_id from table image like this $select_image=mysql_query("select image_id from image where image_name = $fileName") or die(mysql_error()); and fetch the result to my article insert query like this $fetch=mysql_fetch_array($select_image); $qeuery=mysql_query("insert into articles (article_name,article_category,article_subcategory,article_body,article_summary,article_tags,article_photo,article_timedate) values ('$article_title','$CategoryID','$ProductID','$article_body','$article_summary','$fetch[image_id]','$time')") or die ('Error, Query Faild'.mysql_error()); is this correct ? the mysql_error keeps saying " Unknown column 'Penguins.jpg' in 'where clause'"

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  • PHP Multiple User Login Form - Navigation to Different Pages Based on Login Credentials

    - by Zulu Irminger
    I am trying to create a login page that will send the user to a different index.php page based on their login credentials. For example, should a user with the "IT Technician" role log in, they will be sent to "index.php", and if a user with the "Student" role log in, they will be sent to the "student/index.php" page. I can't see what's wrong with my code, but it's not working... I'm getting the "wrong login credentials" message every time I press the login button. My code for the user login page is here: <?php session_start(); if (isset($_SESSION["manager"])) { header("location: http://www.zuluirminger.com/SchoolAdmin/index.php"); exit(); } ?> <?php if (isset($_POST["username"]) && isset($_POST["password"]) && isset($_POST["role"])) { $manager = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["username"]); $password = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["password"]); $role = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["role"]); include "adminscripts/connect_to_mysql.php"; $sql = mysql_query("SELECT id FROM Users WHERE username='$manager' AND password='$password' AND role='$role' LIMIT 1"); $existCount = mysql_num_rows($sql); if (($existCount == 1) && ($role == 'IT Technician')) { while ($row = mysql_fetch_array($sql)) { $id = $row["id"]; } $_SESSION["id"] = $id; $_SESSION["manager"] = $manager; $_SESSION["password"] = $password; $_SESSION["role"] = $role; header("location: http://www.zuluirminger.com/SchoolAdmin/index.php"); } else { echo 'Your login details were incorrect. Please try again <a href="http://www.zuluirminger.com/SchoolAdmin/index.php">here</a>'; exit(); } } ?> <?php if (isset($_POST["username"]) && isset($_POST["password"]) && isset($_POST["role"])) { $manager = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["username"]); $password = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["password"]); $role = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["role"]); include "adminscripts/connect_to_mysql.php"; $sql = mysql_query("SELECT id FROM Users WHERE username='$manager' AND password='$password' AND role='$role' LIMIT 1"); $existCount = mysql_num_rows($sql); if (($existCount == 1) && ($role == 'Student')) { while ($row = mysql_fetch_array($sql)) { $id = $row["id"]; } $_SESSION["id"] = $id; $_SESSION["manager"] = $manager; $_SESSION["password"] = $password; $_SESSION["role"] = $role; header("location: http://www.zuluirminger.com/SchoolAdmin/student/index.php"); } else { echo 'Your login details were incorrect. Please try again <a href="http://www.zuluirminger.com/SchoolAdmin/index.php">here</a>'; exit(); } } ?> And the form that the data is pulled from is shown here: <form id="LoginForm" name="LoginForm" method="post" action="http://www.zuluirminger.com/SchoolAdmin/user_login.php"> User Name:<br /> <input type="text" name="username" id="username" size="50" /><br /> <br /> Password:<br /> <input type="password" name="password" id="password" size="50" /><br /> <br /> Log in as: <select name="role" id="role"> <option value="">...</option> <option value="Head">Head</option> <option value="Deputy Head">Deputy Head</option> <option value="IT Technician">IT Technician</option> <option value="Pastoral Care">Pastoral Care</option> <option value="Bursar">Bursar</option> <option value="Secretary">Secretary</option> <option value="Housemaster">Housemaster</option> <option value="Teacher">Teacher</option> <option value="Tutor">Tutor</option> <option value="Sanatorium Staff">Sanatorium Staff</option> <option value="Kitchen Staff">Kitchen Staff</option> <option value="Parent">Parent</option> <option value="Student">Student</option> </select><br /> <br /> <input type="submit" name = "button" id="button" value="Log In" onclick="javascript:return validateLoginForm();" /> </h3> </form> Once logged in (and should the correct page be loaded, the validation code I have at the top of the script looks like this: <?php session_start(); if (!isset($_SESSION["manager"])) { header("location: http://www.zuluirminger.com/SchoolAdmin/user_login.php"); exit(); } $managerID = preg_replace('#[^0-9]#i', '', $_SESSION["id"]); $manager = preg_replace('#[^A-Za-z0-9]#i', '', $_SESSION["manager"]); $password = preg_replace('#[^A-Za-z0-9]#i', '', $_SESSION["password"]); $role = preg_replace('#[^A-Za-z0-9]#i', '', $_SESSION["role"]); include "adminscripts/connect_to_mysql.php"; $sql = mysql_query("SELECT id FROM Users WHERE username='$manager' AND password='$password' AND role='$role' LIMIT 1"); $existCount = mysql_num_rows($sql); if ($existCount == 0) { header("location: http://www.zuluirminger.com/SchoolAdmin/index.php"); exit(); } ?> Just so you're aware, the database table has the following fields: id, username, password and role. Any help would be greatly appreciated! Many thanks, Zulu

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  • Passing dynamic string in hyperlink as parameter in jsp

    - by user3660263
    I am trying to pass a dynamic string builder variable in jsp I am generating a string through code. String Builder variable has some value but i am not able to pass it in at run time.It doesn't get the value. CODE FOR VARIABLE <% StringBuilder sb=new StringBuilder(""); if(request.getAttribute("Brand")!=null) { String Brand[]=(String[])request.getAttribute("Brand"); for(String brand:Brand) { sb.append("Brand="); sb.append(brand); sb.append("&&"); } } if(request.getAttribute("Flavour")!=null) { String Flavour[]=(String[])request.getAttribute("Flavour"); for(String flavour:Flavour) { sb.append(flavour); sb.append("&&"); } sb.trimToSize(); pageContext.setAttribute("sb", sb); } out.print("this is string"+sb); %> CODE FOR HYPERLINK <a href="Filter_Products?${sb}page=${currentPage + 1}" style="color: white;text-decoration: none;">Next</a></td>

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  • Query multiple currencies

    - by TiuTalk
    I need store multiple currencies on my database... Here's the problem: Example Tables: [ Products ] id (INT, PK) name (VARCHAR) price (DECIMAL) currency (INT, FK) [ Currencies ] id (INT, PK) name (VARCHAR) conversion (DECIMAL) # To U$ I'll store the product price with the currency selected by the user... Later I need to search the products using a price interval like "Search products with price from U$ 50 to U$ 100" and I need the system convert these values "on the fly" to run the SQL Query and filter the products. And I really don't know how to make this query... :/

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  • What applications is Python optimal for?

    - by Alan
    I'm already a professional J2EE developer by day, and Rails developer by night. I'm planning on adding Python to my list of skills. I'm already convinced a language is just a tool, so I'm not interested in a religious war. I agree with the Pragmatic Programmers that learning one language/year is a good thing for your professional development So, in your considered opinion, what kinds of applications does Python hit the sweet spot? And why? What advantages does it have, and why do these advantages outweigh the costs in adopting Python? ADD: I also plan on learning a pure functional language like Scheme.

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  • Concatinating Multiple Rows in SQL

    - by Dave C
    Hello, I have a table structure that looks like this: ID String ----------- 1 A 1 Test 1 String 2 Dear 2 Person I need the final output to look like this: ID FullString -------------------- 1 A, Test, String 2 Dear, Person I am really lost on how to approach this... I looked on a couple examples online but they seemed to be VERY complex... this seems like it should be a real easy problem to solve in sql. Thank you for all assistance!

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  • JOIN (SELECT DISTINCT [..] substitute

    - by FRKT
    Hello, I'd like to find a substitute for using SELECT DISTINCT in a derived table. Let's say I have three tables: CREATE TABLE `trades` ( `tradeID` int(11) unsigned NOT NULL AUTO_INCREMENT, `employeeID` int(11) unsigned NOT NULL, `corporationID` int(11) unsigned NOT NULL, `profit` int(11) NOT NULL, KEY `tradeID` (`tradeID`), KEY `employeeID` (`employeeID`), KEY `corporationID` (`corporationID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 CREATE TABLE `corporations` ( `corporationID` int(11) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, PRIMARY KEY (`corporationID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 CREATE TABLE `employees` ( `employeeID` int(11) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, PRIMARY KEY (`employeeID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 Let's say I'd like to find out how much profit a specific employee has generated. Simple: SELECT SUM(profit) FROM trades JOIN employees ON trades.employeeID = employees.employeeID AND employees.employeeID = 1; It gets trickier if I'd like to query how much revenue a specific corporation has, however. I cannot simply replicate the aforementioned query, because two or more employees from the same company might be involved in the same trade. This query should do the trick: SELECT SUM(profit) FROM trades JOIN (SELECT DISTINCT tradeID FROM trades WHERE trades.corporationID = 1) ... unfortunately, DISTINCT JOINs seem crazy ineffective. Is there any alternative I can use to determine how much revenue a corporation has, taking into account that a corporation might be listed several times with the same tradeID?

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  • Printing All Entries in A PHP Table

    - by mgunawan
    I'm trying to insert a php excerpt with SQL (I understand this is outdated, but am trying to grasp the syntax first) into my HTML page, and I've got the following table: ID Name Element1 Element2 0 John John's 1st John's 2nd 1 Bill Bill's 1st Bill's 2nd 2 Steve Steven's 1st Steve's 2nd I'm trying to get the for loop that will essentially print out the following in my html page Name: Name where ID=0 Element1: Element1 where ID=0 Element2: Element2 where ID=0 Name: Name where ID=1 Element1: Element1 where ID=1 Element2: Element2 where ID=1 and so forth. Basically, I am trying to make this process automated so that whenever a new record is added into the table, the HTML page will automatically update with a new "profile". Thank you for your help!

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  • Syncing a table records with a Service response frequently

    - by Karthik Dheeraj
    I am requesting data from a service whose response in stored in a database.First, I have an empty table, whenever I make my very first request the records from the service comes to my database table. from now, whenever I make second request, the service will provide me some records which may be same as my first response, may be new records, may be updated records etc. my query is to how to update my table with respect to the responses coming from the service during my second request on-wards? so that Unchanged records will remain same, New records will be added, updated records will be updated.Do I need to write any stored procedure on my DB or any workaround ?what might be the scenario if I use Nomysql DB's like mongo DB ? Thanks In Advance.

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  • Scalable way of doing self join with many to many table

    - by johnathan
    I have a table structure like the following: user id name profile_stat id name profile_stat_value id name user_profile user_id profile_stat_id profile_stat_value_id My question is: How do I evaluate a query where I want to find all users with profile_stat_id and profile_stat_value_id for many stats? I've tried doing an inner self join, but that quickly gets crazy when searching for many stats. I've also tried doing a count on the actual user_profile table, and that's much better, but still slow. Is there some magic I'm missing? I have about 10 million rows in the user_profile table and want the query to take no longer than a few seconds. Is that possible?

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  • Define keys in temporary table creation

    - by imperium2335
    How do I define the keys for a temporary table that is being created from a SELECT statement? I have: CREATE temporary TABLE _temp_unique_parts_trading engine=memory AS (SELECT parts_trading.enquiryref, sellingcurrency, jobs.id AS jobID FROM parts_trading, jobs WHERE jobs.enquiryref = parts_trading.enquiryref GROUP BY parts_trading.enquiryref) But where do I define the keys?

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  • How to use SQL - INSERT...ON DUPLICATE KEY UPDATE?

    - by Probocop
    Hi, I have a script which captures tweets and puts them into a database. I will be running the script on a cronjob and then displaying the tweets on my site from the database to prevent hitting the limit on the twitter API. So I don't want to have duplicate tweets in my database, I understand I can use 'INSERT...ON DUPLICATE KEY UPDATE' to achieve this, but I don't quite understand how to use it. My database structure is as follows. Table - Hash id (auto_increment) tweet user user_url And currently my SQL to insert is as follows: $tweet = $clean_content[0]; $user_url = $clean_uri[0]; $user = $clean_name[0]; $query='INSERT INTO hash (tweet, user, user_url) VALUES ("'.$tweet.'", "'.$user.'", "'.$user_url.'")'; mysql_query($query); How would I correctly use 'INSERT...ON DUPLICATE KEY UPDATE' to insert only if it doesn't exist, and update if it does? Thanks

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