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  • problem with joomla, php and json

    - by sebastian
    hi, i have a problem with a joomla component. i'm, unsing php and json for some dynamic drop down boxes. here is the code:` jQuery( function () { //jQuery.ajaxSetup({error : function (a,b) {console.dir(a); console.dir(b);}}); jQuery("#util, #loc").change( function() { var locatie = jQuery("#loc").val(); var utilitate = jQuery("#util").val(); if ( (locatie!= '---') && (utilitate!='---') ) jQuery.getJSON( "index.php?option=com_calculator&opt=json_contor&format=raw", { locatie: locatie, utilitate: utilitate }, function (data) { var html = ""; if ( data.success == 'ok' ) for (var i in data.val) html += "<option name=den_contor value ='"+ i+"' >" + data.val[i]+ " </option>"; jQuery("#den_contor").html( html ) } ) }) }); the query works, but only on one PC. we have exactly the same xampp server, exactly the same files. on one pc it works, and on a online server and on my pc it doesn't. EDIT: i have three drop down boxes, the first is populated directly from the database, the second has 4 predefined values. and the third is populated depending on combination of the first two. i have a test site online. http://contor.redxart.com must be logged in to use Calculator in the menu. you can make an new account :) "Adaugare Index" is the part that isn't working any ideas? thanks, sebastian

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  • Error in computed Field of select Query

    - by Shehzad Bilal
    This Query is giving me an error of #1054 - Unknown column 'totalamount' in 'where clause' SELECT (amount1 + amount2) as totalamount FROM `Donation` WHERE totalamount > 1000 I know i can resolve this error by using group by clause and replace my where condition with having clause. But is there any other solution beside using having clause. If group by is the only solution then I want to know why I have to use group by clause even I havent use any aggregate function thanks.

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  • How do I replace NOT EXISTS with JOIN?

    - by YelizavetaYR
    I've got the following query: select distinct a.id, a.name from Employee a join Dependencies b on a.id = b.eid where not exists ( select * from Dependencies d where b.id = d.id and d.name = 'Apple' ) and exists ( select * from Dependencies c where b.id = c.id and c.name = 'Orange' ); I have two tables, relatively simple. The first Employee has an id column and a name column The second table Dependencies has 3 column, an id, an eid (employee id to link) and names (apple, orange etc). the data looks like this Employee table looks like this id | name ----------- 1 | Pat 2 | Tom 3 | Rob 4 | Sam Dependencies id | eid | Name -------------------- 1 | 1 | Orange 2 | 1 | Apple 3 | 2 | Strawberry 4 | 2 | Apple 5 | 3 | Orange 6 | 3 | Banana As you can see Pat has both Orange and Apple and he needs to be excluded and it has to be via joins and i can't seem to get it to work. Ultimately the data should only return Rob

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  • Get the count of A -> B and B->A without duplicates

    - by TomGasson
    I have a table like so: index|from | to ------------------ 1 | ABC | DEF 2 | ABC | GHI 3 | ABC | GHI 4 | ABC | JKL 5 | ABC | JKL 6 | ABC | JKL 7 | DEF | ABC 8 | DEF | GHI 9 | DEF | JKL 10 | GHI | ABC 11 | GHI | ABC 12 | GHI | ABC 13 | JKL | DEF And I need to count how the total times between the points (regardless of direction) to get the result: A | B | count ----------------- ABC | DEF | 2 ABC | GHI | 5 ABC | JKL | 3 DEF | GHI | 1 DEF | JKL | 2 So far I can get: SELECT `a`.`from` as `A`, `a`.`to` as `B`, (`a`.`count` + `b`.`count`) as `count` FROM (SELECT `from`, `to`, count(*) as `count` FROM `table` GROUP BY 1,2) `a` LEFT OUTER JOIN (SELECT `from`,`to`, count(*) as `count` FROM `table` GROUP BY 1,2) `b` ON `a`.`from` = `b`.`to` AND `a`.`to` = `b`.`from` But I'm unsure how to remove the A/B swapped duplicates.

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  • PHP Framework Benefits / Downfalls

    - by Lizard
    I have been a PHP developer for about 10 years now and until about a month ago I have never used a framework. The framework I am now using due to an existing codebase is cakePHP 1.2 I can see certain benefits of the frameworks with the basic helpers like default layouts. I can deffinately seen the benefits of MVC keeping the logic sperate etc. But the query building just seems to be bloated. Is this expected? Am I likely to be able to build better queries than the framework could build? I just feel I could get my apps running better without a framework. What are your thoughts?

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  • PHP - Drilling down Data and Looping with Loops

    - by stogdilla
    I'm currently having difficulty finding a way of making my loops work. I have a table of data with 15 minute values. I need the data to pull up in a few different increments $filters=Array('Yrs','Qtr','Day','60','30','15'); I think I have a way of finding out what I need to be able to drill down to but the issue I'm having is after the first loop to cycle through all the Outter most values (ex: the user says they want to display by Hours, each hour should be able to have a "+" that will then add a new div to display the half hour data, then each half hour data have a "+" to display the 15 minute data upon request. Now I can just program the number of outputs for each value (6 different outputs) just in-case... but isn't there a way I can make it do the drill down for each one in a loop? so I only have to code one output once and have it just check if there are any more intervals after it and check for those? I'm sure I'm just overlooking some very simple way of doing this but my brain isn't being clever today. Sorry in advance if this is a simple solution. I guess the best way I could think of it as a reply on a form. How you would check to see if it's a reply of a reply, and then if that reply has any replys...etc for output. Can anyone help or at least point me in the right direction? Or am I stuck coding each possible check? Thanks in advance!

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  • passing a scalar query result to coalesce

    - by Fakrudeen
    How can I pass the result from a scalar [single row, single value] query to coalesce? I am trying to pick the priority as (the biggest priority so far in the table) + 1. [0 if it is the first row.] create trigger priority_SuperRuleSamples before insert on SuperRuleSamples FOR EACH ROW SET NEW.Priority=coalesce(NEW.Priority, coalesce( select Priority from SuperRuleSamples order by Priority desc limit 1, -1 )+1 )

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  • problem in creating a php tree menu

    - by Mac Taylor
    hi mates im writing a tree menu for my categories in php and i wonder how can i code it correctly ! this is my table in database " |----topicid------topicname--------parent | |---- 1 ------ News -------- 0 | |---- 2 ------ sport -------- 1 | |---- 3 ------ games -------- 1 | |---- 4 ------ PES -------- 3 | so now for showing it like a tree i did try but not worked : $result = mysql_query("SELECT * FROM Topics ORDER BY topicid"); while ($row = mysql_fetchrow($result)) { $id = intval($row['topicid']); $title = filter($row['topicname'], "nohtml"); $parent = $row['parent'] ; if ($parent==0) { $menu_item .= "<li><span class='folder'><a title = \"$alt\" href=\"modules.php?name=News&amp;new_topic=$id\">$title</a></span></li>"; }else { $result = mysql_query("SELECT * FROM ".$prefix."_Topics where parent='$id' ORDER BY topicid"); while ($row = mysql_fetchrow($result)) { $id = intval($row['topicid']); $title = filter($row['topicname'], "nohtml"); $parent = $row['parent'] ; $menu_item .= " <ul><li><span class='file'><a title = \"$alt\" href=\"modules.php?name=News&amp;new_topic=$id\">$title</a></span></li></ul>"; } } i dont know how to solve this

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  • Trying to grab several random videos from database, but it just shows the same one all the time.

    - by Birk
    Hi guys, I'm trying to grab several random videos from my database, and have them show on a page. However, it just keeps on grabbing the same video rather than several different ones. So I end up with 5 of the same video rather than 5 different ones. Here's the grab random PHP code file... and after it is the template output file. //===================================================== // Random | Previous | Next //===================================================== $show['random'] = $db->quick_fetch( "SELECT file_id, title, title_seo, category_id, thumb FROM files WHERE files.category_id = '".$show['main']['category_id']."' AND files.verified=1 ORDER BY RAND() LIMIT 0,1; "); Here's the template CSS html thingy code I have this pasted 5 times to show 5 random videos <td valign="top" width="53%"><? $sql="select * from files ORDER BY rand() limit 0,5"; $res=@mysql_query($sql); $data=@mysql_result($res,0,'filename'); $id=@mysql_result($res,0,'file_id'); $title=@mysql_result($res,0,'title'); $title2=str_replace(" ", "-",$title); $path="{$siteurl}/media/{$file.random.file_id}/{$file.random.title_seo}/"; $img="{$siteurl}/thumbs/{$file.random.thumb}"; echo " {$file.random.title}"

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  • PHP:Wrong Login info does not redirect to the specific page

    - by sdr
    <?php include 'lib/db_conn.php'; $uid=$_REQUEST['uid']; $pass=$_REQUEST['pass']; if(($uid==NULL && $pass==NULL) ||($uid==NULL) ||($pass==NULL)) { header("location:index.php?msg=Fields can't be left blank.."); } $pass=md5($pass); $sql1="SELECT * FROM `tb_user` WHERE `email`='$uid' AND `pass`='$pass'"; $rs1=mysql_query($sql1) or die (mysql_error()); $row1=mysql_fetch_array($rs1) or die (mysql_error()); $email=$row1['email']; if($uid==$email) { session_start(); $_SESSION['id']=$row1['id']; header("location:home.php"); } else { header("location:index.php?msg=Wrong Credentials.."); } ?>

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  • Activetopics - Get max 5 topics per category

    - by Arjen
    Hey, I want to get the 5 latest active topics within several category's. Each topic has a subcatid and this subcatid relates to a catid. What I want is to get the 5 active topics within each catid. I'm trying to use the query below, but this isn't working at all: set @num := 0, @catid := 0; SELECT forum_posts.topicid, forum_topics.titel, forum_topics.sticky, forum_topics.gesloten, MAX(forum_cats.id) AS catid, MAX(forum_cats.titel) AS cattitel, MAX(forum_subcats.id) AS subcatid, MAX(forum_posts.id) AS maxid, DATE_FORMAT(MAX(forum_posts.datum), '%d-%m-%Y om %H:%i uur') AS datum, UNIX_TIMESTAMP(MAX(forum_posts.datum)) AS laatstereactieunix, (COUNT(forum_posts.id) - 1) AS reactieaantal, @num := IF(@catid = MAX(forum_cats.id), @num + 1, 1) AS row_number, @catid := MAX(forum_cats.id) AS dummy FROM forum_posts INNER JOIN forum_topics ON forum_topics.id = forum_posts.topicid INNER JOIN forum_subcats ON forum_subcats.id = forum_topics.subcat INNER JOIN forum_cats ON forum_cats.id = forum_subcats.cat WHERE forum_cats.id IN (1) AND forum_topics.gesloten != '1' GROUP BY forum_posts.topicid, forum_topics.titel, forum_topics.sticky, forum_topics.gesloten HAVING row_number <= 5 ORDER BY forum_cats.id ASC, MAX(forum_posts.datum) DESC When executing this code I get always the same number (1) for row_number, so this is not the result I want. Does anyone know how I can get this work? Thanks!

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  • Unknown Column?

    - by Kenny
    ok im trying to get mutual friends between these Two users, user1 and user92 This is the sql that is successful in displaying them SELECT IF(user_a = 1 OR user_a = 92, user_b, user_a) friend FROM friendship WHERE (user_a = 1 OR user_a = 92) OR (user_b = 1 OR user_b = 92) GROUP BY 1 HAVING COUNT(*) > 1 THis is how it looks friend 61 72 73 74 75 76 77 78 79 80 81 So now i want to select all users after the number 72, and i try to do it with this sql but its not working? It gives me the error, "unknown coulum name friend in where clause" SELECT IF(user_a = 1 OR user_a = 92, user_b, user_a) friend FROM friendship WHERE friend > 72 and (user_a = 1 OR user_a = 92) OR (user_b = 1 OR user_b = 92) GROUP BY 1 HAVING COUNT(*) > 1 what am i doing wrong? or what is the correct way?? thx

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  • WHERE id IN doesn't work in UPDATE

    - by Donator
    UPDATE statistics' SET money = money + '$money' WHERE member_id IN ((SELECT member_id FROM races WHERE l_id = '$mem_id'), $other_id) What's wrong with that? I want to retrieve all member_ids from races and also include to member_id $other_id. Without $other_id it works. By the way, it gives me "Subquery returns more than 1 row" error.

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  • Flexible forms and supporting database structure

    - by sunwukung
    I have been tasked with creating an application that allows administrators to alter the content of the user input form (i.e. add arbitrary fields) - the contents of which get stored in a database. Think Modx/Wordpress/Expression Engine template variables. The approach I've been looking at is implementing concrete tables where the specification is consistent (i.e. user profiles, user content etc) and some generic field data tables (i.e. text, boolean) to store non-specific values. Forms (and model fields) would be generated by first querying the tables and retrieving the relevant columns - although I've yet to think about how I would setup validation. I've taken a look at this problem, and it seems to be indicating an EAV type approach - which, from my brief research - looks like it could be a greater burden than the blessings it's flexibility would bring. I've read a couple of posts here, however, which suggest this is a dangerous route: How to design a generic database whose layout may change over time? Dynamic Database Schema I'd appreciate some advice on this matter if anyone has some to give regards SWK

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  • Zend Framework Relations vs. Table Select

    - by rtmilker
    Hey! I just want to know your guys opinion on using join tables within the zend framework. Of course you can use relations by defining a referenceMap and dependentTables and stuff, or using setIntegrityCheck(false) within a db select(). The setIntegrityCheck version seems a little bit dirty to me, but the other version is not very suitable for big querys and joining many tables... I'm a PHP developer for 5 years now and new to the zend framework and just want get a direction for my first project. Thanks!!!

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  • Save phone calls data in a DB?

    - by Alex
    How would you save this data on a database: An user can make phone calls (id, date, hour, duration, outcome). The "outcome" can be, for example, to recall the client on another day (so I have to save the date, the hour, etc of this "future" call). How would you manage this data on a db? At the moment i have only a "Call" table.

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  • how to join 3 relational tables

    - by orioncabbar
    Hello there, how to join 3 relational tables with the structure: t1 | id t2 | id | rating t3 | source_id | relation t3 stores the data of a field which t1 and t2 uses both. so source_id field can be t1's id or t2's id. input : t1 id output : t2 rating an example: **t1** id | --------- 42 | **t2** id | rating ------------- 37 | 9.2 **t3** id | source_id -------------- 42 | 1 37 | 1 26 | 2 23 | 1 what i want is to get 9.2 output with 42 input. can you do that in one sql query?

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  • Help me understand WebDAV and Autoversioning

    - by Malfist
    I just read the WebDAV Appendex in the O'Reilly Subversion book. I don't quite understand it. It talked about users being able to "mount" WebDAV directories (trees) and manipulate the files like they would normally and on saves the server would automagically create a new revision. The way it explained it, it sounded like it would work for any program, but then at the end of the appendix, it listed a series of programs that worked with WebDAV servers, which leads me to think that maybe it doesn't work like it originally described it. My question is this: How exactly do you interact with a WebDAV repository? Can I do this for example: Copy a file locally via ftp, edit it with notepad++, and then upload it via ftp to the server and have the server do a commit and create a new revision with the file I just edited and uploaded. Also, if that is possible, what happens if two people edit the file locally (on their machines) and uploaded two reversions to the server? With webDAV will I be able to replace Dreamweaver's "Oops, someone edited this before you" with simple ftp uploads and subversion conflict resolutions?

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  • Sort database entries via a dropdown list

    - by Lin
    Hello! I'm curious if anyone could possibly help me, because I can't find anything exactly related to it anywhere, and it's driving me nuts. I'd like to have a dropdown list on a page, that will give the visitor the option to sort all entries by year. I have entries from i.e. 2001, 2005, 2009, 2010. The years should be displayed in the dropdown, so the visitor can easily just select all entries dated 2001 if they want. The year for each entry is located in the one database table I have. In other words, I simply want a "sort by" dropdown that you can see on pretty much any shopping site nowadays. But with set years. Thanks in advance for any replies!

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