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  • Having a Link Only Appear If a Logged-In User Appears on a Dynamic List

    - by John
    Hello, For the function below, I would like the link <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> to only appear if the logged in user currently appears on editorlist.php. (I. e. if the loginid in the function corresponds to any of the usernames that currently appear in editorlist.php.) Appearing on editorlist.php is something that is dynamic. How can I do this? Thanks in advance, John function show_userbox() { // retrieve the session information $u = $_SESSION['username']; $uid = $_SESSION['loginid']; // display the user box echo '<div id="userbox"> <div class="username">'.$u.'</div> <div class="submit"><a href="http://www...com/.../submit.php">Submit an item.</a></div> <div class="changepassword"><a href="http://www...com/.../changepassword.php">Change Password</a></div> <div class="logout"><a href="http://www...com/.../logout.php">Logout</a></div> <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> </div>'; } On editorlist.php: $sqlStr = "SELECT l.loginid, l.username, l.created, DATEDIFF(NOW(), l.created) AS days, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments, COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore, DATEDIFF(NOW(), l.created) + COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore2 FROM login l LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM submission GROUP BY loginid ) s ON l.loginid = s.loginid LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM comment GROUP BY loginid ) c ON l.loginid = c.loginid GROUP BY l.loginid ORDER BY totalScore2 DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec1edit\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1edit1"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.stripslashes($row["username"]).'</a></td>'; echo '<td class="sitename1edit2">'.($row["countSubmissions"]).'</td>'; echo '<td class="sitename1edit2">'.($row["countComments"]).'</td>'; echo '<td class="sitename1edit2">'.($row["days"]).'</td>'; echo '<td class="sitename1edit2">'.($row["totalScore2"]).'</td>'; echo '</tr>'; } echo "</table>";

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  • L-Soft LISTSERV TCPGUI Interface for PHP Creation

    - by poolnoodl
    I'm trying to use LISTSERV's "API" in PHP. L-Soft calls this TCPGUI, and essentially, you can request data like over Telnet. To do this, I'm using PHP's TCP socket functions. I've seen this done in other languages but can't quite convert it to PHP. I can connect, I can change set ASCII or BINARY mode. But I can never quite craft the header packet the way I need to authenticate, so I'm thinking I'm messing up my conversion. C: http://www.lsoft.com/manuals/16.0/htmlhelp/advanced%20topics/TCPGUI.html#2334328 $origin = '[email protected]'; $pwd = 'password'; $host = "example.com"; $port = 2306; $email = "[email protected]"; $list = "mailinglist"; $command = "Query $list FOR $email"; $fp = stream_socket_client("tcp://$host:$port", $errno, $errstr, 30); $cmd = $command . " PW=" . $pwd; $len = strlen($cmd); $orglen = strlen($origin); $n = $len + $orglen + 1; $headerPacket[0] = "1"; $headerPacket[1] = "B"; $headerPacket[2] = "\r"; $headerPacket[3] = "\n"; $headerPacket[4] = ord($n / 256); $headerPacket[5] = ord($n + 255); $headerPacket[6] = ord($orglen); for ($i = 0; $i < $orglen; $i++) { $headerPacket[$i + 7] = ord($origin[$i]); } for ($i = 0; $i < $len; $i++) { $cmdPacket[$i] = ord($cmd[$i]); } fwrite($fp, implode($headerPacket)); while (!feof($fp)) { echo fgets($fp, 1024); } Any thoughts on where I'm going wrong? I'd much appreciate it if anyone could point me toward some code to do this, days of googling and searching here on SO has only lead me to examples in other languages. Of course, if you know C (or Java or Perl as linked below in my comment to bypass the spam filter), PHP, and socket programming fairly well, you could probably rewrite the whole of the code in an hour, maybe a few minutes. You'd have my eternal thanks for that.

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  • Table prefix for MySqlMembershipProvider

    - by choudeshell
    I have MySqlMembershipProvider working with Asp.Net MVC. My question is how can I configure the table prefix... so instead of 'my_aspnet_' prefix on the tables, I want this to be either none or defined by me. My web.config: <?xml version="1.0"?> <add name="ApplicationServices" connectionString="server=localhost;user id=root;Password=*********;database=sparkSources" providerName="MySql.Data.MySqlClient"/> <authentication mode="Forms"> <forms loginUrl="~/Account/LogOn" timeout="2880" /> </authentication> <membership defaultProvider="MySqlMembershipProvider"> <providers> <clear/> <add name="MySqlMembershipProvider" type="MySql.Web.Security.MySQLMembershipProvider, MySql.Web, Version=6.3.4.0, Culture=neutral, PublicKeyToken=c5687fc88969c44d" autogenerateschema="true" tablePrefix="ss" connectionStringName="ApplicationServices" enablePasswordRetrieval="false" enablePasswordReset="true" requiresQuestionAndAnswer="false" requiresUniqueEmail="false" passwordFormat="Hashed" maxInvalidPasswordAttempts="5" minRequiredPasswordLength="6" minRequiredNonalphanumericCharacters="0" passwordAttemptWindow="10" passwordStrengthRegularExpression="" applicationName="sparkSources" /> </providers> </membership> <profile> <providers> <clear/> <add name="AspNetSqlProfileProvider" type="System.Web.Profile.SqlProfileProvider" connectionStringName="ApplicationServices" applicationName="/" /> </providers> </profile> <roleManager enabled="false"> <providers> <clear/> <add name="AspNetSqlRoleProvider" type="System.Web.Security.SqlRoleProvider" connectionStringName="ApplicationServices" applicationName="/" /> <add name="AspNetWindowsTokenRoleProvider" type="System.Web.Security.WindowsTokenRoleProvider" applicationName="/" /> </providers> </roleManager> <pages> <namespaces> <add namespace="System.Web.Mvc" /> <add namespace="System.Web.Mvc.Ajax" /> <add namespace="System.Web.Mvc.Html" /> <add namespace="System.Web.Routing" /> </namespaces> </pages>

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  • Running OpenMPI on Windows XP

    - by iamweird
    Hi there. I'm trying to build a simple cluster based on Windows XP. I compiled OpenMPI-1.4.2 successfully, and tools like mpicc and ompi_info work too, but I can't get my mpirun working properly. The only output I can see is Z:\orterun --hostfile z:\hosts.txt -np 2 hostname [host0:04728] Failed to initialize COM library. Error code = -2147417850 [host0:04728] [[8946,0],0] ORTE_ERROR_LOG: Error in file ..\..\openmpi-1.4.2 \orte\mca\ess\hnp\ess_hnp_module.c at line 218 -------------------------------------------------------------------------- It looks like orte_init failed for some reason; your parallel process is likely to abort. There are many reasons that a parallel process can fail during orte_init; some of which are due to configuration or environment problems. This failure appears to be an internal failure; here's some additional information (which may only be relevant to an Open MPI developer): orte_plm_init failed -- Returned value Error (-1) instead of ORTE_SUCCESS -------------------------------------------------------------------------- [host0:04728] [[8946,0],0] ORTE_ERROR_LOG: Error in file ..\..\openmpi-1.4.2 \orte\runtime\orte_init.c at line 132 -------------------------------------------------------------------------- It looks like orte_init failed for some reason; your parallel process is likely to abort. There are many reasons that a parallel process can fail during orte_init; some of which are due to configuration or environment problems. This failure appears to be an internal failure; here's some additional information (which may only be relevant to an Open MPI developer): orte_ess_set_name failed -- Returned value Error (-1) instead of ORTE_SUCCESS -------------------------------------------------------------------------- [host0:04728] [[8946,0],0] ORTE_ERROR_LOG: Error in file ..\..\..\..\openmpi -1.4.2\orte\tools\orterun\orterun.c at line 543 Where z:\hosts.txt appears as follows: host0 host1 Z: is a shared network drive available to both host0 and host1. What my problem is and how do I fix it? Upd: Ok, this problem seems to be fixed. It seems to me that WideCap driver and/or software components causes this error to appear. A "clean" machine runs local task successfully. Anyway, I still cannot run a task within at least 2 machines, I'm getting following message: Z:\mpirun --hostfile z:\hosts.txt -np 2 hostname connecting to host1 username:cluster password:******** Save Credential?(Y/N) y [host0:04728] This feature hasn't been implemented yet. [host0:04728] Could not connect to namespace cimv2 on node host1. Error code =-2147024891 -------------------------------------------------------------------------- mpirun was unable to start the specified application as it encountered an error. More information may be available above. -------------------------------------------------------------------------- I googled a little and did all the things as described here: http://www.open-mpi.org/community/lists/users/2010/03/12355.php but I'm still getting the same error. Can anyone help me? Upd2: Error code -2147024891 might be WMI error WBEM_E_INVALID_PARAMETER (0x80041008) which occures when one of the parameters passed to the WMI call is not correct. Does this mean that the problem is in OpenMPI source code itself? Or maybe it's because of wrong/outdated wincred.h and credui.lib I used while building OpenMPI from the source code?

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  • NHibernate unable to create SessionFactory

    - by Tyler
    I'm having a bit of trouble setting up NHibernate, and I'm not too sure what the problem is exactly. I'm attempting to save a domain object to the database (Oracle 10g XE). However, I'm getting a TypeInitializationException while trying to create the ISessionFactory. Here is what my hibernate.cfg.xml looks like: <?xml version="1.0" encoding="utf-8"?> <hibernate-configuration xmlns="urn:nhibernate-configuration-2.2" > <session-factory name="MyProject.DataAccess"> <property name="connection.driver_class">NHibernate.Driver.OracleClientDriver</property> <property name="connection.connection_string"> User ID=myid;Password=mypassword;Data Source=localhost </property> <property name="show_sql">true</property> <property name="dialect">NHibernate.Dialect.OracleDialect</property> <property name="proxyfactory.factory_class">NHibernate.ByteCode.LinFu.ProxyFactoryFactory, NHibernate.ByteCode.LinFu</property> <mapping resource="MyProject/Domain/User.hbm.xml"/> </session-factory> </hibernate-configuration> I created a DAO which I will use to persist domain objects to the database. The DAO uses a HibernateUtil class that creates the SessionFactory. Both classes are in the DataAccess namespace along with the Hibernate configuration. This is where the exception is occuring. Here's that class: public class HibernateUtil { private static ISessionFactory SessionFactory = BuildSessionFactory(); private static ISessionFactory BuildSessionFactory() { try { // This seems to be where the problem occurs return new Configuration().Configure().BuildSessionFactory(); } catch (TypeInitializationException ex) { Console.WriteLine("Initial SessionFactory creation failed." + ex); throw new Exception("Unable to create SessionFactory."); } } public static ISessionFactory GetSessionFactory() { return SessionFactory; } } The DataAccess namespace references the NHibernate DLLs. This is virtually the same setup I've used with Hibernate in Java, so I'm not entirely sure what I'm doing wrong here. Any ideas? Edit The innermost exception is the following: "Could not find file 'C:\Users\Tyler\Documents\Visual Studio 2010\Projects\MyProject\MyProject\ConsoleApplication\bin\Debug\hibernate.cfg.xml'." ConsoleApplication contains the entry point where I've created a User object and am trying to persist it with my DAO. Why is it looking for the configuration file there? The actual persisting takes place in the DAO, which is in DataAccess. Also, when I add the configuration file to ConsoleApplication, it still does not find it.

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  • Haskell data serialization of some data implementing a common type class

    - by Evan
    Let's start with the following data A = A String deriving Show data B = B String deriving Show class X a where spooge :: a -> Q [ Some implementations of X for A and B ] Now let's say we have custom implementations of show and read, named show' and read' respectively which utilize Show as a serialization mechanism. I want show' and read' to have types show' :: X a => a -> String read' :: X a => String -> a So I can do things like f :: String -> [Q] f d = map (\x -> spooge $ read' x) d Where data could have been [show' (A "foo"), show' (B "bar")] In summary, I wanna serialize stuff of various types which share a common typeclass so I can call their separate implementations on the deserialized stuff automatically. Now, I realize you could write some template haskell which would generate a wrapper type, like data XWrap = AWrap A | BWrap B deriving (Show) and serialize the wrapped type which would guarantee that the type info would be stored with it, and that we'd be able to get ourselves back at least an XWrap... but is there a better way using haskell ninja-ery? EDIT Okay I need to be more application specific. This is an API. Users will define their As, and Bs and fs as they see fit. I don't ever want them hacking through the rest of the code updating their XWraps, or switches or anything. The most i'm willing to compromise is one list somewhere of all the A, B, etc. in some format. Why? Here's the application. A is "Download a file from an FTP server." B is "convert from flac to mp3". A contains username, password, port, etc. information. B contains file path information. A and B are Xs, and Xs shall be called "Tickets." Q is IO (). Spooge is runTicket. I want to read the tickets off into their relevant data types and then write generic code that will runTicket on the stuff read' from the stuff on disk. At some point I have to jam type information into the serialized data.

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  • Feedback on Optimizing C# NET Code Block

    - by Brett Powell
    I just spent quite a few hours reading up on TCP servers and my desired protocol I was trying to implement, and finally got everything working great. I noticed the code looks like absolute bollocks (is the the correct usage? Im not a brit) and would like some feedback on optimizing it, mostly for reuse and readability. The packet formats are always int, int, int, string, string. try { BinaryReader reader = new BinaryReader(clientStream); int packetsize = reader.ReadInt32(); int requestid = reader.ReadInt32(); int serverdata = reader.ReadInt32(); Console.WriteLine("Packet Size: {0} RequestID: {1} ServerData: {2}", packetsize, requestid, serverdata); List<byte> str = new List<byte>(); byte nextByte = reader.ReadByte(); while (nextByte != 0) { str.Add(nextByte); nextByte = reader.ReadByte(); } // Password Sent to be Authenticated string string1 = Encoding.UTF8.GetString(str.ToArray()); str.Clear(); nextByte = reader.ReadByte(); while (nextByte != 0) { str.Add(nextByte); nextByte = reader.ReadByte(); } // NULL string string string2 = Encoding.UTF8.GetString(str.ToArray()); Console.WriteLine("String1: {0} String2: {1}", string1, string2); // Reply to Authentication Request MemoryStream stream = new MemoryStream(); BinaryWriter writer = new BinaryWriter(stream); writer.Write((int)(1)); // Packet Size writer.Write((int)(requestid)); // Mirror RequestID if Authenticated, -1 if Failed byte[] buffer = stream.ToArray(); clientStream.Write(buffer, 0, buffer.Length); clientStream.Flush(); } I am going to be dealing with other packet types as well that are formatted the same (int/int/int/str/str), but different values. I could probably create a packet class, but this is a bit outside my scope of knowledge for how to apply it to this scenario. If it makes any difference, this is the Protocol I am implementing. http://developer.valvesoftware.com/wiki/Source_RCON_Protocol

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  • Losing session after Login - Java

    - by Patrick Villela
    I'm building an application that needs to login to a certain page and make a navigation. I can login, provided that the response contains a string that identifies it. But, when I navigate to the second page, I can't see the page as a logged user, only as anonymous. I'll provide my code. import java.net.*; import java.security.*; import java.security.cert.*; import javax.net.ssl.*; import java.io.*; import java.util.*; public class PostTest { static HttpsURLConnection conn = null; private static class DefaultTrustManager implements X509TrustManager { @Override public void checkClientTrusted(X509Certificate[] arg0, String arg1) throws CertificateException {} @Override public void checkServerTrusted(X509Certificate[] arg0, String arg1) throws CertificateException {} @Override public X509Certificate[] getAcceptedIssuers() { return null; } } public static void main(String[] args) { try { SSLContext ctx = SSLContext.getInstance("TLS"); ctx.init(new KeyManager[0], new TrustManager[] {new DefaultTrustManager()}, new SecureRandom()); SSLContext.setDefault(ctx); String data = URLEncoder.encode("txtUserName", "UTF-8") + "=" + URLEncoder.encode(/*username*/, "UTF-8"); data += "&" + URLEncoder.encode("txtPassword", "UTF-8") + "=" + URLEncoder.encode(/*password*/", "UTF-8"); data += "&" + URLEncoder.encode("envia", "UTF-8") + "=" + URLEncoder.encode("1", "UTF-8"); connectToSSL(/*login url*/); conn.setDoOutput(true); OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream()); wr.write(data); wr.flush(); BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); String line; String resposta = ""; while((line = rd.readLine()) != null) { resposta += line + "\n"; } System.out.println("valid login -> " + resposta.contains(/*string that assures me I'm looged in*/)); connectToSSL(/*first navigation page*/); rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); while((line = rd.readLine()) != null) { System.out.println(line); } } catch(Exception e) { e.printStackTrace(); } } private static void connectToSSL(String address) { try { URL url = new URL(address); conn = (HttpsURLConnection) url.openConnection(); conn.setHostnameVerifier(new HostnameVerifier() { @Override public boolean verify(String arg0, SSLSession arg1) { return true; } }); } catch(Exception ex) { ex.printStackTrace(); } } } Any further information, just ask. Thanks in advance.

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  • how to insert into database from stored procedure in log4net?

    - by Samreen
    I have to log thread context properties like this: string logFilePath = AppDomain.CurrentDomain.BaseDirectory + "log4netconfig.xml"; FileInfo finfo = new FileInfo(logFilePath); log4net.Config.XmlConfigurator.ConfigureAndWatch(finfo); ILog logger = LogManager.GetLogger("Exception.Logging"); log4net.ThreadContext.Properties["MESSAGE"] = exception.Message; log4net.ThreadContext.Properties["MODULE"] = "module1"; log4net.ThreadContext.Properties["COMPONENT"] = "component1"; logger.Debug("test"); and the configuration file is: <configuration> <configSections> <section name="log4net" type="log4net.Config.Log4NetConfigurationSectionHandler,Log4net"/> </configSections> <log4net> <logger name="Exception.Logging" level="Debug"> <appender-ref ref="AdoNetAppender"/> </logger> <appender name="AdoNetAppender" type="log4net.Appender.AdoNetAppender"> <connectionString value="Data Source=xe;User ID=test;Password=test;" /> <connectionType value="System.Data.OracleClient.OracleConnection, System.Data.OracleClient, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089" /> <bufferSize value="10000"/> <commandText value="Log_Exception_Pkg.Insert_Log" /> <commandType value="StoredProcedure" /> <parameter> <parameterName value="@p_Error_Message" /> <dbType value="String" /> <size value="255" /> <layout type="log4net.Layout.PatternLayout"> <conversionPattern value="%property{MESSAGE}"/> </layout> </parameter> <parameter> <parameterName value="@p_Module" /> <dbType value="String" /> <size value="225" /> <layout type="log4net.Layout.PatternLayout"> <conversionPattern value="%property{MODULE}"/> </layout> </parameter> <parameter> <parameterName value="@p_Component" /> <dbType value="String" /> <size value="225" /> <layout type="log4net.Layout.PatternLayout"> <conversionPattern value="%property{COMPONENT}"/> </layout> </parameter> </appender> </log4net> </configuration> But its not inserting them in the database. How can I get that to work?

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  • current_user.user_type_id = @employer ID

    - by sscirrus
    I am building a system with a User model (authenticated using AuthLogic) and three user types in three models: one of these models is Employer. Each of these three models has_many :users, :as = :authenticable. I start by having a new visitor to the site create their own 'User' record with username, password, which user type they are, etc. Upon creation, the user is sent to the 'new' action for one of the three models. So, if they tell us they are an employer, we redirect_to :controller = "employers, :action = "new". Question: When the employer has submitted, I want to set the current_user.user_type_id equal to the employer ID. This should be simple... but it's not working. # Employers Controller / new def new @employer = Employer.new 1.times {@employer.addresses.build} render :layout => 'forms' end # Employers Controller / create def create @employer = Employer.new(params[:employer]) if @employer.save if current_user.blank? redirect_to :controller => "users", :action => "new" else current_user.user_type_id = @employer.id current_user.user_type = "Employer" redirect_to :action => "home", :id => current_user.user_type_id end else render :action => "new" end end ------UPDATE------ Hi guys. In response: I am using this table structure because each of my three user type models have lots of different fields and each has different relationships to the other models, which is why I've avoided STI. By 1.times (@employer.addresses.build) I'm connecting the employer model to the address polymorphic table in one form, so I'm asking the controller to build a new address to go along with the new employer. Averell: you mentioned encapsulating... something in the model using a 'setter' method. I have no idea what you mean by this - could you please explain how this works (or direct me to an example elsewhere)? With tsdbrown's answer I have managed to create the behavior I want... if there's a more elegant way to accomplish the same thing I'd love to learn how. Thanks very much. Thanks to tsdbrown for answering the current_user.save problem!

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  • HttpWebRequest possibly slowing website

    - by Steven Smith
    Using Visual studio 2012, C#.net 4.5 , SQL Server 2008, Feefo, Nopcommerce Hey guys I have Recently implemented a new review service into a current site we have. When the change went live the first day all worked fine. Since then though the sending of sales to Feefo hasnt been working, There are no logs either of anything going wrong. In the OrderProcessingService.cs in Nop Commerce's Service, i call a HttpWebrequest when an order has been confirmed as completed. Here is the code. var email = HttpUtility.UrlEncode(order.Customer.Email.ToString()); var name = HttpUtility.UrlEncode(order.Customer.GetFullName().ToString()); var description = HttpUtility.UrlEncode(productVariant.ProductVariant.Product.MetaDescription != null ? productVariant.ProductVariant.Product.MetaDescription.ToString() : "product"); var orderRef = HttpUtility.UrlEncode(order.Id.ToString()); var productLink = HttpUtility.UrlEncode(string.Format("myurl/p/{0}/{1}", productVariant.ProductVariant.ProductId, productVariant.ProductVariant.Name.Replace(" ", "-"))); string itemRef = ""; try { itemRef = HttpUtility.UrlEncode(productVariant.ProductVariant.ProductId.ToString()); } catch { itemRef = "0"; } var url = string.Format("feefo Url", login, password,email,name,description,orderRef,productLink,itemRef); var request = (HttpWebRequest)WebRequest.Create(url); request.KeepAlive = false; request.Timeout = 5000; request.Proxy = null; using (var response = (HttpWebResponse)request.GetResponse()) { if (response.StatusDescription == "OK") { var stream = response.GetResponseStream(); if(stream != null) { using (var reader = new StreamReader(stream)) { var content = reader.ReadToEnd(); } } } } So as you can see its a simple webrequest that is processed on an order, and all product variants are sent to feefo. Now: this hasnt been happening all week since the 15th (day of the implementation) the site has been grinding to a halt recently. The stream and reader in the the var content is there for debugging. Im wondering does the code redflag anything to you that could relate to the process of website? Also note i have run some SQL statements to see if there is any deadlocks or large escalations, so far seems fine, Logs have also been fine just the usual logging of Bots. Any help would be much appreciated! EDIT: also note that this code is in a method that is called and wrapped in A try catch UPDATE: well forget about the "not sending", thats because i was just told my code was rolled back last week

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  • First record does not show in pagination script

    - by whitstone86
    This is my pagination script which extracts info for my TV guide project that I am working on. Currently I've been experimenting with different PHP/MySQL before it becomes a production site. This is my current script: <?php /*********************************** * PhpMyCoder Paginator * * Created By PhpMyCoder * * 2010 PhpMyCoder * * ------------------------------- * * You may use this code as long * * as this notice stays intact and * * the proper credit is given to * * the author. * ***********************************/ // set the default timezone to use. Available since PHP 5.1 putenv("TZ=US/Eastern") ?> <head> <title> Pagination Test - Created By PhpMyCoder</title> <style type="text/css"> #nav { font: normal 13px/14px Arial, Helvetica, sans-serif; margin: 2px 0; } #nav a { background: #EEE; border: 1px solid #DDD; color: #000080; padding: 1px 7px; text-decoration: none; } #nav strong { background: #000080; border: 1px solid #DDD; color: #FFF; font-weight: normal; padding: 1px 7px; } #nav span { background: #FFF; border: 1px solid #DDD; color: #999; padding: 1px 7px; } </style> </head> <?php //Require the file that contains the required classes include("pmcPagination.php"); //PhpMyCoder Paginator $paginator = new pmcPagination(20, "page"); //Connect to the database mysql_connect("localhost","root","PASSWORD"); //Select DB mysql_select_db("mytvguide"); //Select only results for today and future $result = mysql_query("SELECT programme, channel, airdate, expiration, episode, setreminder FROM lagunabeach where expiration >= now() order by airdate, 3 ASC LIMIT 0, 100;"); //You can also add reuslts to paginate here mysql_data_seek($queryresult,0) ; while($row = mysql_fetch_array($result)) { $paginator->add(new paginationData($row['programme'], $row['channel'], $row['airdate'], $row['expiration'], $row['episode'], $row['setreminder'])); } ?> <?php //Show the paginated results $paginator->paginate (); ?><? include("pca-footer1.php"); ?> <?php //Show the navigation $paginator->navigation(); ?> Despite me having two records for the programmes airing today, it only shows records from the second one onwards - the programme that airs at 8:35pm UK time GMT does not show, but the later 11:25pm UK time GMT one does show. How should I fix this? Above is my code if that is of any use! Thanks

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  • assign a model's attribute through association

    - by justcode
    I'm new to rails and working on a rails app and I'm stuck pondering this issue. I have three models class product < ActiveRecord::Base attr_accessible :name, :issn, :category validates_presence_of :name, :issn, :category validates_numericality_of :issn, :message => "has to be a number" has_many :user_products has_many :users, :through => :user_products end class UserProduct < ActiveRecord::Base attr_accessible :price, :category validates_presence_of :price, :category validates_numericality_of :price, :message = "has to be a number" belongs_to :user belongs_to :product end class user < ActiveRecord::Base # devise authentication here # Setup accessible (or protected) attributes for your model attr_accessible :email, :password, :password_confirmation, :remember_me has_many :user_products has_many :products, :through = :user_products end here is my new.html.erb <div class="MainBodyWrapper"> <div class="span8"> <div id="listBoxWrapper"> <fieldset> <%= form_for(@product, :html => { :class => "form-inline" }, :style => "margin-bottom: 60px" ) do |f| %> <div class="control-group"> <label class="control-label" for="name">name</label> <div class="controls"> <%= f.text_field :price, :class => 'input-xlarge input-name', :id => "name" %> </div> </div> <div class="listingButtons"> <button class="btn btn-info"></i>Add</button> <a class="btn">Upload Pictures (anytime)</a> </div> </fieldset> </div> </div> There are reasons why I want to setup the models this way. So the question is this: I want the user to enter the info for the product in the form but it also involves putting in the price of the product which exists in a different model/table (user_product) that is associated with product. How can I do this? You can see that my form_for uses @product. Any help will be appreciated.

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  • Cannot extend a class located in another file, PHP

    - by NightMICU
    I am trying to set up a class with commonly used tasks, such as preparing strings for input into a database and creating a PDO object. I would like to include this file in other class files and extend those classes to use the common class' code. However, when I place the common class in its own file and include it in the class it will be used in, I receive an error that states the second class cannot be found. For example, if the class name is foo and it is extending bar (the common class, located elsewhere), the error says that foo cannot be found. But if I place the code for class bar in the same file as foo, it works. Here are the classes in question - Common Class abstract class coreFunctions { protected $contentDB; public function __construct() { $this->contentDB = new PDO('mysql:host=localhost;dbname=db', 'username', 'password'); } public function cleanStr($string) { $cleansed = trim($string); $cleansed = stripslashes($cleansed); $cleansed = strip_tags($cleansed); return $cleansed; } } Code from individual class include $_SERVER['DOCUMENT_ROOT'] . '/includes/class.core-functions.php'; $mode = $_POST['mode']; if (isset($mode)) { $gallery = new gallery; switch ($mode) { case 'addAlbum': $gallery->addAlbum($_POST['hash'], $_POST['title'], $_POST['description']); } } class gallery extends coreFunctions { private function directoryPath($string) { $path = trim($string); $path = strtolower($path); $path = preg_replace('/[^ \pL \pN]/', '', $path); $path = preg_replace('[\s+]', '', $path); $path = substr($path, 0, 18); return $path; } public function addAlbum($hash, $title, $description) { $title = $this->cleanStr($title); $description = $this->cleanStr($description); $path = $this->directoryPath($title); if ($title && $description && $hash) { $addAlbum = $this->contentDB->prepare("INSERT INTO gallery_albums (albumHash, albumTitle, albumDescription, albumPath) VALUES (:hash, :title, :description, :path)"); $addAlbum->execute(array('hash' => $hash, 'title' => $title, 'description' => $description, 'path' => $path)); } } } The error when I try it this way is Fatal error: Class 'gallery' not found in /home/opheliad/public_html/admin/photo-gallery/includes/class.admin_photo-gallery.php on line 10

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  • join 03 table in the database codeIgniter

    - by python
    with my table. person_id serial NOT NULL, firstname character varying(30) NOT NULL, lastname character varying(30), email character varying(50), username character varying(20) NOT NULL, "password" character varying(100) NOT NULL, gender character varying(10), dob date, accesslevel smallint NOT NULL, company_id integer NOT NULL,//Reference to table company position_id integer NOT NULL,//Reference to table position company_id serial NOT NULL, company_name character varying(80) NOT NULL, description character varying(255), address character varying(100) NOT NULL, In my controller ........................ // load data $persons = $this->person_model->get_paged_list(10,0); // generate table data $this->load->library('table'); $this->table->set_empty("&nbsp;"); $this->table->set_heading('No', 'FirstName', 'LastName','E-mail','Company''Gender', 'Date of Birth', 'Actions'); foreach ($persons as $person){ $this->table->add_row(++$i, $person->firstname, $person->lastname, $person->email, $person->company_name, //HOW CAN I GOT THE POSITION TITLE ?, strtoupper($person->gender)=='M'? 'Male':'Female', date('d-m-Y',strtotime($person->dob)), } My model <?php class Person_Model extends Model { private $person= 'person'; function Person(){ parent::Model(); } function list_all(){ $this->db->order_by('person_id','asc'); return $this->db->get($person); } function count_all(){ return $this->db->count_all($this->person); } function get_paged_list($limit = 0, $offset = 0) { $this->db->limit($limit, $offset); $this->db->select("person.*, company.company_name as company"); $this->db->from('person'); $this->db->join('company','person.company_id = company.company_id','left'); //MY QUESTION:? CAN I JOIN MORE WITH TABLE POSITION? $query = $this->db->get(); return $query->result(); } function get_by_id($id){ $this->db->where('person_id', $id); return $this->db->get($this->person); } function save($person){ $this->db->insert($this->person, $person); return $this->db->insert_id(); } function update($id, $person){ $this->db->where('person_id', $id); $this->db->update($this->person, $person); } function delete($id){ $this->db->where('person_id', $id); $this->db->delete($this->person); } } ?>

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  • Authlogic Help! Registering a new user when currently logged-in as a user not working.

    - by looloobs
    Hi Just as a disclaimer I am new to rails and programming in general so apologize for misunderstanding something obvious. I have Authlogic with activation up and running. So for my site I would like my users who are logged in to be able to register other users. The new user would pick their login and password through the activation email, but the existing user needs to put them in by email, position and a couple other attributes. I want that to be done by the existing user. The problem I am running into, if I am logged in and then try and create a new user it just tries to update the existing user and doesn't create a new one. I am not sure if there is some way to fix this by having another session start??? If that is even right/possible I wouldn't know how to go about implementing it. I realize without knowing fully about my application it may be difficult to answer this, but does this even sound like the right way to go about this? Am I missing something here? Users Controller: class UsersController < ApplicationController before_filter :require_no_user, :only => [:new, :create] before_filter :require_user, :only => [:show, :edit, :update] def new @user = User.new end def create @user = User.new if @user.signup!(params) @user.deliver_activation_instructions! flash[:notice] = "Your account has been created. Please check your e-mail for your account activation instructions!" redirect_to profile_url else render :action => :new end end def show @user = @current_user end def edit @user = @current_user end def update @user = @current_user # makes our views "cleaner" and more consistent if @user.update_attributes(params[:user]) flash[:notice] = "Account updated!" redirect_to profile_url else render :action => :edit end end end My User_Session Controller: class UserSessionsController < ApplicationController before_filter :require_no_user, :only => [:new, :create] before_filter :require_user, :only => :destroy def new @user_session = UserSession.new end def create @user_session = UserSession.new(params[:user_session]) if @user_session.save flash[:notice] = "Login successful!" if @user_session.user.position == 'Battalion Commander' : redirect_to battalion_path(@user_session.user.battalion_id) else end else render :action => :new end end def destroy current_user_session.destroy flash[:notice] = "Logout successful!" redirect_back_or_default new_user_session_url end end

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  • Creating a mySQL query using PHP form dropdowns - If user ignores dropdown, do not filter by that pa

    - by user303043
    Hello, I am creating a simple MySQL query that will be built from the user selecting options from 2 dropdowns. The issue I am having is that I would like each drop down to default that if they do not actually choose an option, do not filter by that dropdown parameter. So, if they come in, and simply hit submit without choosing from a dropdown they should see everything. If they come in and pick from only one of the dropdowns, the query will basically ignore filtering by the other dropdown. I tried making <OPTION VALUE='any'>Choose but my query didn't know what to do with the 'any' and just shows no results. Here is my code. Thank you very much for whatever help you can provide. FORM <form method="POST" action="<?php echo $_SERVER['REQUEST_URI']; ?>"> <select name="GameType"> <OPTION VALUE='any'>Choose Game Type <option value="Game1">Option 1</option> <option value="Game2">Option 2</option> <option value="Game3">Option 3</option> </select> <select name="Instructor"> <OPTION VALUE='any'>Choose Instructor <option VALUE="InstructorA">Instructor A</option> <option value="InstructorB">Instructor B</option> <option value="InstructorC">Instructor C</option> </select> <input type='submit' value='Search Videos'> </form> MYSQL <?PHP connection stuff $db_handle = mysql_connect($server, $user_name, $password); $db_found = mysql_select_db($database, $db_handle); if ($db_found) { $SQL = "SELECT * FROM Videos WHERE GameType=\"{$_POST['GameType']}\" AND Instructor=\"{$_POST['Instructor']}\""; $result = mysql_query($SQL); while ($db_field = mysql_fetch_assoc($result)) { echo $db_field['ShortDescription'] . ", "; echo $db_field['LongDescription'] . ", "; echo $db_field['GameType'] . ", "; echo $db_field['NumberOfPlayers'] . ", "; echo $db_field['Instructor'] . ", "; echo $db_field['Stakes'] . ", "; echo $db_field['UserPermissionLevel'] . ", "; echo $db_field['DateCreated'] . "<BR>"; } mysql_close($db_handle); } else { print "Database NOT Found "; mysql_close($db_handle); } ?>

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  • An error occurred creating the form. See Exception.InnerException for details. The error is: Object

    - by Ben
    I get this error when attempting to debug my form, I cannot see where at all the error could be (also does not highlight where), anyone have any suggestions? An error occurred creating the form. See Exception.InnerException for details. The error is: Object reference not set to an instance of an object. Public Class Form1 Dim dateCrap As String = "Date:" Dim IPcrap As String = "Ip:" Dim pcCrap As String = "Computer:" Dim programCrap As String = "Program:" Dim textz As String = TextBox1.Text Dim sep() As String = {vbNewLine & vbNewLine} Dim sections() As String = Text.Split(sep, StringSplitOptions.None) Dim NewArray() As String = TextBox1.Text.Split(vbNewLine) Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click For i = 0 To sections.Count - 1 TextBox2.Text = sections(i) Dim text2 As String = TextBox2.Text Dim sep2() As String = {vbNewLine & vbNewLine} Dim sections2() As String = Text.Split(sep, StringSplitOptions.None) Dim FTPinfo() As String = TextBox2.Text.Split(vbNewLine) Dim clsRequest As System.Net.FtpWebRequest = _ DirectCast(System.Net.WebRequest.Create(sections2(0).Replace("Url/Host:", "")), System.Net.FtpWebRequest) clsRequest.Credentials = New System.Net.NetworkCredential(sections2(1).Replace("Login:", ""), (sections2(2).Replace("Password:", ""))) clsRequest.Method = System.Net.WebRequestMethods.Ftp.UploadFile ' read in file... Dim bFile() As Byte = System.IO.File.ReadAllBytes(txtShellDir.Text) ' upload file... Dim clsStream As System.IO.Stream = clsRequest.GetRequestStream() clsStream.Write(bFile, 0, bFile.Length) clsStream.Close() clsStream.Dispose() Next End Sub Private Sub Button3_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button3.Click ListBox1.Items.Clear() Dim fdlg As OpenFileDialog = New OpenFileDialog() fdlg.Title = "Browse for the FTP List you wish to use." fdlg.InitialDirectory = Application.ExecutablePath fdlg.Filter = "All files (*.txt)|*.txt|txt files (*.txt)|*.txt" fdlg.FilterIndex = 2 fdlg.RestoreDirectory = True If fdlg.ShowDialog() = DialogResult.OK Then 'ListBox1.Items.AddRange(Split(My.Computer.FileSystem.ReadAllText(fdlg.FileName), vbNewLine)) TextBox1.Text = My.Computer.FileSystem.ReadAllText(fdlg.FileName) End If Dim tmp() As String = TextBox1.Text.Split(CChar(vbNewLine)) For Each line As String In tmp If line.Length > 1 Then TextBox1.AppendText(line & vbNewLine) End If Next TextBox1.Text = TextBox1.Text.Replace(" ", "") TextBox1.Text = TextBox1.Text.Replace("----------------------------------------------------------", vbNewLine) For Each item As String In NewArray ListBox1.Items.Add(item) Next Try For i = 0 To ListBox1.Items.Count - 1 If ListBox1.Items(i).Contains(dateCrap) Then ListBox1.Items.RemoveAt(i) End If Next Catch ex As Exception End Try Try For i = 0 To ListBox1.Items.Count - 1 If ListBox1.Items(i).Contains(IPcrap) Then ListBox1.Items.RemoveAt(i) End If Next Catch ex As Exception End Try Try For i = 0 To ListBox1.Items.Count - 1 If ListBox1.Items(i).Contains(pcCrap) Then ListBox1.Items.RemoveAt(i) End If Next Catch ex As Exception End Try Try For i = 0 To ListBox1.Items.Count - 1 If ListBox1.Items(i).Contains(programCrap) Then ListBox1.Items.RemoveAt(i) End If Next Catch ex As Exception End Try TextBox1.Text = "" For Each thing As Object In ListBox1.Items TextBox1.AppendText(thing.ToString & vbNewLine) Next End Sub Private Sub Button4_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) For i = 0 To ListBox1.SelectedItems.Count - 1 TextBox1.Text = TextBox1.Text & ListBox1.Items.Item(i).ToString() & vbNewLine Next End Sub End Class

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  • Rails nested form for belongs_to

    - by user1232533
    I'm new to rails and have some troubles with creating a nested form. My models: class User < ActiveRecord::Base belongs_to :company accepts_nested_attributes_for :company, :reject_if => :all_blank end class Company < ActiveRecord::Base has_many :users end Now i would like to create a new company from the user sign_up page (i use Devise btw) by given only a company name. And have a relation between the new User and new Company. In the console i can create a company for a existing User like this: @company = User.first.build_company(:name => "name of company") @company.save That works, but i can't make this happen for a new user, in my new user sign_up form i tried this (i know its wrong by creating a new User fist but im trying to get something working here..): <%= simple_form_for(resource, :as => resource_name, :html => { :class => 'form-horizontal' }, :url => registration_path(resource_name)) do |f| %> <%= f.error_notification %> <div class="inputs"> <% @user = User.new company = @user.build_company() %> <% f.fields_for company do |builder| %> <%= builder.input :name, :required => true, :autofocus => true %> <% end %> <%= f.input :email, :required => true, :autofocus => true %> <%= f.input :password, :required => true %> <%= f.input :password_confirmation, :required => true %> </div> <div class="form-actions"> <%= f.button :submit, :class => 'btn-primary', :value => 'Sign up' %> </div> I did my best to google for a solution/ example.. found some nested form examples but it's just not clear to me how to do this. Really hope somebody can help me with this. Any help on this would be appreciated. Thanks in advance! Greets, Daniel

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  • Criticise/Recommendations for my code

    - by aLk
    Before i go any further it would be nice to know if there is any major design flaws in my program so far. Is there anything worth changing before i continue? Model package model; import java.sql.*; import java.util.*; public class MovieDatabase { @SuppressWarnings({ "rawtypes", "unchecked" }) public List queryMovies() throws SQLException { Connection connection = null; java.sql.Statement statement = null; ResultSet rs = null; List results = new ArrayList(); try { DriverManager.registerDriver(new com.mysql.jdbc.Driver()); connection = DriverManager.getConnection("jdbc:mysql://localhost:3306/test", "root", "password"); statement = connection.createStatement(); String query = "SELECT * FROM movie"; rs = statement.executeQuery(query); while(rs.next()) { MovieBean bean = new MovieBean(); bean.setMovieId(rs.getInt(1)); bean.setTitle(rs.getString(2)); bean.setYear(rs.getInt(3)); bean.setRating(rs.getInt(4)); results.add(bean); } } catch(SQLException e) { } return results; } } Servlet public class Service extends HttpServlet { @SuppressWarnings("rawtypes") protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.setContentType("text/html"); PrintWriter out = response.getWriter(); out.println("Movies!"); MovieDatabase movies = new MovieDatabase(); try { List results = movies.queryMovies(); Iterator it = results.iterator(); while(it.hasNext()) { MovieBean movie = new MovieBean(); movie = (MovieBean)it.next(); out.println(movie.getYear()); } } catch(SQLException e) { } } } Bean package model; @SuppressWarnings("serial") public class MovieBean implements java.io.Serializable { protected int movieid; protected int rating; protected int year; protected String title; public MovieBean() { } public void setMovieId(int movieidVal) { movieid = movieidVal; } public void setRating(int ratingVal) { rating = ratingVal; } public void setYear(int yearVal) { year = yearVal; } public void setTitle(String titleVal) { title = titleVal; } public int getMovieId() { return movieid; } public int getRating() { return rating; } public int getYear() { return year; } public String getTitle() { return title; } }

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  • pdo connection scope

    - by Scarface
    Hey guys I have a connection class I found for pdo. I am calling the connection method on the page that the file is included on. The problem is that within functions the $conn variable is not defined even though I stated the method was public (bare with me I am very new to OOP), and I was wondering if anyone had an elegant solution other then using global in every function. Any suggestions are greatly appreciated. CONNECTION class PDOConnectionFactory{ // receives the connection public $con = null; // swich database? public $dbType = "mysql"; // connection parameters // when it will not be necessary leaves blank only with the double quotations marks "" public $host = "localhost"; public $user = "user"; public $senha = "password"; public $db = "database"; // arrow the persistence of the connection public $persistent = false; // new PDOConnectionFactory( true ) <--- persistent connection // new PDOConnectionFactory() <--- no persistent connection public function PDOConnectionFactory( $persistent=false ){ // it verifies the persistence of the connection if( $persistent != false){ $this->persistent = true; } } public function getConnection(){ try{ // it carries through the connection $this->con = new PDO($this->dbType.":host=".$this->host.";dbname=".$this->db, $this->user, $this->senha, array( PDO::ATTR_PERSISTENT => $this->persistent ) ); // carried through successfully, it returns connected return $this->con; // in case that an error occurs, it returns the error; }catch ( PDOException $ex ){ echo "We are currently experiencing technical difficulties. We have a bunch of monkies working really hard to fix the problem. Check back soon: ".$ex->getMessage(); } } // close connection public function Close(){ if( $this->con != null ) $this->con = null; } } PAGE USED ON include("includes/connection.php"); $db = new PDOConnectionFactory(); $conn = $db->getConnection(); function test(){ try{ $sql = 'SELECT * FROM topic'; $stmt = $conn->prepare($sql); $result=$stmt->execute(); } catch(PDOException $e){ echo $e->getMessage(); } } test();

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  • PHP problems when transfering code from Windows to OS X

    - by Makka95
    I have recently bought a new MacBook Pro. Before I had my MacBook Pro I was working on a website on my desktop computer. And now I want to transfer this code to my new MacBook Pro. The problem is that when I transfered the code (I put it on Dropbox and simply downloaded it on my MacBook Pro) I started to see lots of error messages in my PHP code. The error message I”m receiving is: Warning: Cannot modify header information - headers already sent by (output started at /some/file.php:1) in /some/file.php on line 23 I have done some research on this and it seems that this error is most frequently caused by a new line, simple whitespace or any output before the <?php sign. I have looked through all the places where I have cookies that are being sent in the HTTP request and also where I'm using the header() function. I haven’t detected any output or whitespace that possibly could interfere and cause this problem. Noteworthy is that the error always says that the output is started at line 1. Which got me thinking if there is some kind of coding differences in the way that the Mac OS X and Windows operating systems handle new lines or white spaces? Or could the Dropbox transfer messed something up? The code on one of the sites(login.php) which produces the error: <?php include "mysql_database.php"; login(); $id = $_SESSION['Loggedin']; setcookie("login", $id, (time()+60*60*24*30)); header('Location: ' . $_SERVER['HTTP_REFERER']); ?> login function: function login() { $connection = connecttodatabase(); $pass = ""; $user = ""; $query = ""; if (isset($_POST['user']) && $_POST['user'] != null) { $user = $_POST['user']; if (isset($_POST['pass']) && $_POST['pass'] != null) { $pass = md5($_POST['pass']); $query = "SELECT ID FROM Anvandare WHERE Nickname='$user' AND Password ='$pass'"; } } if ($query != "") { $id = $connection->query($query); $id = mysqli_fetch_assoc($id); $id = $id['ID']; $_SESSION['Loggedin'] = $id; } closeconnection($connection); } Complete error: Warning: Cannot modify header information - headers already sent by (output started at /Users/name/GitHub/website/login.php:1) in /Users/namn/GitHub/website/login.php on line 9

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  • Please Describe Your Struggles with Minimizing Use of Global Variables

    - by MetaHyperBolic
    Most of the programs I write are relatively flowchartable processes, with a defined start and hoped-for end. The problems themselves can be complex but do not readily lean towards central use of objects and event-driven programming. Often, I am simply churning through great varied batches of text data to produce different text data. Only occasionally do I need to create a class: As an example, to track warnings, errors, and debugging message, I created a class (Problems) with one instantiation (myErr), which I believe to be an example of the Singleton design pattern. As a further factor, my colleagues are more old school (procedural) than I and are unacquainted with object-oriented programming, so I am loath to create things they could not puzzle through. And yet I hear, again and again, how even the Singleton design pattern is really an anti-pattern and ought to be avoided because Global Variables Are Bad. Minor functions need few arguments passed to them and have no need to know of configuration (unchanging) or program state (changing) -- I agree. However, the functions in the middle of the chain, which primarily control program flow, have a need for a large number of configuration variables and some program state variables. I believe passing a dozen or more arguments along to a function is a "solution," but hardly an attractive one. I could, of course, cram variables into a single hash/dict/associative array, but that seems like cheating. For instance, connecting to the Active Directory to make a new account, I need such configuration variables as an administrative username, password, a target OU, some default groups, a domain, etc. I would have to pass those arguments down through a variety of functions which would not even use them, merely shuffle them off down through a chain which would eventually lead to the function that actually needs them. I would at least declare the configuration variables to be constant, to protect them, but my language of choice these days (Python) provides no simple manner to do this, though recipes do exist as workarounds. Numerous Stack Overflow questions have hit on the why? of the badness and the requisite shunning, but do not often mention tips on living with this quasi-religious restriction. How have you resolved, or at least made peace with, the issue of global variables and program state? Where have you made compromises? What have your tricks been, aside from shoving around flocks of arguments to functions?

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  • Converting my lightweight MySQL DB wrapper into MySQLi. Pesky Problems

    - by Chaplin
    Here is the original code: http://pastebin.com/DNxtmApY. I'm not that interested in prepared statements at the moment, I just want this wrapper updating to MySQLi so once MySQL becomes depreciated I haven't got to update a billion websites. Here is my attempt at converting to MySQLi. <? $database_host = "127.0.0.1"; $database_user = "user"; $database_pass = "pass"; $database_name = "name"; $db = new database($database_host, $database_user, $database_pass, $database_name); class database { var $link, $result; function database($host, $user, $pass, $db) { $this->link = mysqli_connect($host, $user, $pass, $db) or $this->error(); mysqli_select_db($db, $this->link) or $this->error(); } function query($query) { $this->result = mysqli_query($query, $this->link) or $this->error(); $this->_query_count++; return $this->result; } function countRows($result = "") { if ( empty( $result ) ) $result = $this->result; return mysqli_num_rows($result); } function fetch($result = "") { if ( empty( $result ) ) $result = $this->result; return mysqli_fetch_array($result); } function fetch_num($result = "") { if ( empty( $result ) ) $result = $this->result; return mysqli_fetch_array($result, mysqli_NUM); } function fetch_assoc($result = "") { if ( empty( $result ) ) $result = $this->result; return mysqli_fetch_array($result, mysqli_ASSOC); } function escape($str) { return mysqli_real_escape_string($str); } function error() { if ( $_GET["debug"] == 1 ){ die(mysqi_error()); } else { echo "Error in db code"; } } } function sanitize($data) { //apply stripslashes if magic_quotes_gpc is enabled if(get_magic_quotes_gpc()) $data = stripslashes($data); // a mysqli connection is required before using this function $data = trim(mysqli_real_escape_string($data)); return $data; } However it chucks all sorts of errors: Warning: mysql_query(): Access denied for user 'www-data'@'localhost' (using password: NO) in /home/count/Workspace/lib/classes/user.php on line 7 Warning: mysql_query(): A link to the server could not be established in /home/count/Workspace/lib/classes/user.php on line 7 Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /home/count/Workspace/lib/classes/user.php on line 8 Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, object given in /home/count/Workspace/lib/classes/database.php on line 31

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  • Get return values from a stored procedure in c# (login process)

    - by Jin
    Hi all, I am trying to use a Stored Procedure which takes two parameters (login, pw) and returns the user info. If I execute the SP manually, I get Session_UID User_Group_Name Sys_User_Name ------------------------------------ -------------------------------------------------- - NULL Administrators NTMSAdmin No rows affected. (1 row(s) returned) @RETURN_VALUE = 0 Finished running [dbo].[p_SYS_Login]. But with the code below, I only get the return value. do you know how to get the other values shown above like Session_UID, User_Group_Name, and Sys_User_Name ? if you see the commented part below code. I tried to add some output parameters but it doesn't work with incorrect number of parameters error. string strConnection = Settings.Default.ConnectionString; using (SqlConnection conn = new SqlConnection(strConnection)) { using (SqlCommand cmd = new SqlCommand()) { SqlDataReader rdr = null; cmd.Connection = conn; cmd.CommandText = "p_SYS_Login"; //cmd.CommandText = "p_sys_Select_User_Group"; cmd.CommandType = CommandType.StoredProcedure; SqlParameter paramReturnValue = new SqlParameter(); paramReturnValue.ParameterName = "@RETURN_VALUE"; paramReturnValue.SqlDbType = SqlDbType.Int; paramReturnValue.SourceColumn = null; paramReturnValue.Direction = ParameterDirection.ReturnValue; //SqlParameter paramGroupName = new SqlParameter("@User_Group_Name", SqlDbType.VarChar, 50); //paramGroupName.Direction = ParameterDirection.Output; //SqlParameter paramUserName = new SqlParameter("@Sys_User_Name", SqlDbType.VarChar, 50); //paramUserName.Direction = ParameterDirection.Output; cmd.Parameters.Add(paramReturnValue); //cmd.Parameters.Add(paramGroupName); //cmd.Parameters.Add(paramUserName); cmd.Parameters.AddWithValue("@Sys_Login", textUserID.Text); cmd.Parameters.AddWithValue("@Sys_Password", textPassword.Text); try { conn.Open(); object result = cmd.ExecuteNonQuery(); int returnValue = (int)cmd.Parameters["@RETURN_VALUE"].Value; if (returnValue == 0) { Hide(); Program.MapForm.Show(); } else if (returnValue == 1) { MessageBox.Show("The username or password you entered is incorrect", "NTMS Login", MessageBoxButtons.OK, MessageBoxIcon.Warning); } else if (returnValue == 2) { MessageBox.Show("This account is disabled", "NTMS Login", MessageBoxButtons.OK, MessageBoxIcon.Warning); } else { MessageBox.Show("Database error. Please contact administrator", "NTMS Login", MessageBoxButtons.OK, MessageBoxIcon.Warning); } } catch (Exception ex) { string message = ex.Message; string caption = "MAVIS Exception"; MessageBoxButtons buttons = MessageBoxButtons.OK; MessageBox.Show( message, caption, buttons, MessageBoxIcon.Warning, MessageBoxDefaultButton.Button1); } } } Thanks for your help.

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