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  • Question About Abstract Classes?

    - by IbrarMumtaz
    URL: Link (1) According to this wesbite .. you cannot implement Abstract classes but derive from them. This makes sense and I have read this many times. Like an interface, you cannot implement an instance of an abstract class, however you can implement methods, fields, and properties in the abstract class that can be used by the child class. But on MSDN URL: TextWriter CLass on MSDN TextWriter is an abstract class but it has two constructors defined ... and according to the MS 70-536 book, the following statement is valid: TextWriter tw = new File.CreateText("myFile.Txt") The static file class and it's CreateText method is fine by me as I have studied it on MSDN but can somebody explain this little contradiction I have found? Surely I am not the first? Why is instantaion of base abstract classes possible????

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  • PrintingPermissionLevel, SafePrinting, and restrictions

    - by Steve Cooper
    There is a PrintingPermission attribute in the framework which takes a PrintingPermissionLevel enumeration with one of these values; NoPrinting: Prevents access to printers. NoPrinting is a subset of SafePrinting. SafePrinting: Provides printing only from a restricted dialog box. SafePrinting is a subset of DefaultPrinting. DefaultPrinting: Provides printing programmatically to the default printer, along with safe printing through semirestricted dialog box. DefaultPrinting is a subset of AllPrinting. AllPrinting: Provides full access to all printers. The documentation is really sparse, and I wondered if anyone can tell me more about the SafePrinting option. What does the documentation mean when it says "Provides printing only from a restricted dialog box." I have no idea what this means. Can anyone shed any light? This subject is touched in the MS certification 70-505: TS: Microsoft .NET Framework 3.5, Windows Forms Application Development and so I'm keen to find out more.

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  • WebCenter Implementation Specialist Exam Preparation Webcasts: WebCenter Content And WebCenter Portal

    - by swalker
    Oracle PartnerNetwork would like to invite you to Refresh Courses for WebCenter Content and WebCenter Portal, to help partners to prepare for the WebCenter Implementation Specialist EXAMS. This is a 3 hours intensive refresher partner-only training session, providing attendees with an overview of WebCenter Content and WebCenter Portal functions and related topics. After the refresher part you will be able to take the relevant Implementation Specialist EXAM depending on your personal focus. NOTE: This is only suitable for experienced WebCenter Content or WebCenter Portal practitioners Who should attend? Partner Consultants who want to become an Oracle WebCenter Content or a WebCenter Portal Certified Implementation Specialist or both, that will help them to differentiate themselves in front of customers and support their Companies to become Specialized. Webcast Details: Date Topic Speaker Web Call Details Intercall Details December 14th WebCenter Content Refresh Course Markus Neubauer, Silbury WebCenter Content Specialized Partner Join Webcast Dial-in numbers: CC/SP: 1579222/9221 Time: 12:00 -15:00 CET Break around 13:30 Conference ID/Key: 9249533/1412 Date Topic Speaker Web Call Details Intercall Details January 10th WebCenter Portal Refresh Course Yannick Ongena, InfoMentum WebCenter Portal Specialized Partner Join Webcast Dial-in numbers: CC/SP: 1579222/9221 Time: 12:00 -15:00 CET Break around 13:30 Conference ID/Key: 9249375/1001 Date Topic Speaker Web Call Details Intercall Details February 22nd WebCenter Content Refresh Course Markus Neubauer, Silbury WebCenter Content Specialized Partner Join Webcast Dial-in numbers: CC/SP: 1579222/9221 Time: 12:00 -15:00 CET Break around 13:30 Conference ID/Key: 9249541/2202 Date Topic Speaker Web Call Details Intercall Details March 13th WebCenter Portal Refresh Course Yannick Ongena, InfoMentum WebCenter Portal Specialized Partner Join Webcast Dial-in numbers: CC/SP: 1579222/9221 Time: 12:00 -15:00 CET Break around 13:30 Conference ID/Key: 9249549/1303 Local dial-in numbers can be found here . Next Steps: After the Webcast you will receive the Training material and FREE Vouchers to book and take the: Oracle ECM 11g Certified Implementation Specialist EXAM Oracle WebCenter 11g Essentials EXAM Booking with Voucher can be done on www.pearsonvue.com. Note: FREE Vouchers will be send after attending the webcast.

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  • INVITATION: WEBCENTER IMPLEMENTATION SPECIALIST EXAM PREPARATION WEBCASTS

    - by mseika
    Oracle Partner Network would like to invite you to Refresh Courses for WebCenter Content and WebCenter Portal, to help partners to prepare for the WebCenter Implementation Specialist EXAMS. This is a 3 hours intensive refresher partner-only training session, providing attendees with an overview of WebCenter Content and WebCenter Portal functions and related topics. After the refresher part you will be able to take the relevant Implementation Specialist EXAM depending on your personal focus.NOTE: This is only suitable for experienced WebCenter Content or WebCenter Portal practitioners Who should attend? Partner Consultants who want to become an Oracle WebCenter Content or a WebCenter Portal Certified Implementation Specialist or both, that will help them to differentiate themselves in front of customers and support their Companies to become Specialized. Webcast Details: Date Topic Speaker Web Call Details Intercall Details December 14th WebCenter Content Refresh Course Markus Neubauer, Silbury WebCenter Content Specialized Partner Join Webcast Dial-in numbers: CC/SP: 1579222/9221 Time: 12:00 -15:00 CET Break around 13:30 Conference ID/Key: 9249533/1412 Date Topic Speaker Web Call Details Intercall Details January 10th WebCenter Portal Refresh Course Yannick Ongena, InfoMentum WebCenter Portal Specialized Partner Join Webcast Dial-in numbers: CC/SP: 1579222/9221 Time: 12:00 -15:00 CET Break around 13:30 Conference ID/Key: 9249375/1001 Date Topic Speaker Web Call Details Intercall Details February 22nd WebCenter Content Refresh Course Markus Neubauer, Silbury WebCenter Content Specialized Partner Join Webcast Dial-in numbers: CC/SP: 1579222/9221 Time: 12:00 -15:00 CET Break around 13:30 Conference ID/Key: 9249541/2202 Date Topic Speaker Web Call Details Intercall Details March 13th WebCenter Portal Refresh Course Yannick Ongena, InfoMentum WebCenter Portal Specialized Partner Join Webcast Dial-in numbers: CC/SP: 1579222/9221 Time: 12:00 -15:00 CET Break around 13:30 Conference ID/Key: 9249549/1303 Local dial-in numbers can be found here . Next Steps: After the Webcast you will receive the Training material and FREE Vouchers to book and take the: Oracle ECM 11g Certified Implementation Specialist EXAM Oracle WebCenter 11g Essentials EXAM Booking with Voucher can be done on www.pearsonvue.com. Note: FREE Vouchers will be send after attending the webcast.  

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  • Implementation Specialist OPN Exam for OBI Suite 11g is Now LIVE

    - by Mike.Hallett(at)Oracle-BI&EPM
    The OPN specialisation Exam for implementation consultants of OBI Suite 11g is now live and ready for all partners.  You can now update your specialisation certification to the latest product version 11g for OBI: until recently, the accreditation had examined skills for OBI 10g. For more details see Oracle Business Intelligence Foundation Suite 11g Essentials (1Z1-591) where you can apply for this Oracle Implementation Specialist credential. This exam is primarily intended for consultants that are skilled in implementing solutions based on Oracle Business Intelligence Foundation Suite 11g. The certification covers skills such as: installing OBIEE, building the BI Server metadata repository, building BI dashboards, constructing ad hoc queries, defining security settings and configuring and managing cache files. The exam targets the intermediate-level implementation team member. Up-to-date training and field experience are recommended.   Also Note the New OPN on-line Sales & Pre-sales Assessment Tests are available @ Oracle Business Intelligence Foundation Suite 11g Sales Specialist Oracle Business Intelligence Foundation Suite 11g PreSales Specialist Oracle Business Intelligence Foundation Suite 11g Support Specialist FREE Certification Testing at OpenWorld ·       Are you attending OPN Exchange @ OpenWorld ? Then join us at OPN Specialist Test Fest! October 1st - 4th 2012, Marriott Marquis Hotel :  Pre-register here now!   For More Information OPN Certified Specialist exams OPN Certified Specialist FAQ Enablement 2.0 Get Specialized!

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  • How can the AssemblyName class be used for existing Assembly's?

    - by IbrarMumtaz
    This is another exam related question. I want to know how can I use the AssemblyName class to represent an existing assembly that already exists on disk??? I am talking about from the perspective of using the AppDomain's instance method .Load(), that takes an AssemblyName object as a parameter. I know what MSDN has to say about what the .Load() method was designed for but that aside, I still want to know how to use it !!!

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  • How can the AssemblyName class be used for existing Assemblies?

    - by IbrarMumtaz
    This is another exam related question. I want to know how can I use the AssemblyName class to represent an existing assembly that already exists on disk??? I am talking about from the perspective of using the AppDomain's instance method .Load(), that takes an AssemblyName object as a parameter. I know what MSDN has to say about what the .Load() method was designed for but that aside, I still want to know how to use it !!!

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  • Michael Crump&rsquo;s notes for 70-563 PRO &ndash; Designing and Developing Windows Applications usi

    - by mbcrump
    TIME TO GO PRO! This is my notes for 70-563 PRO – Designing and Developing Windows Applications using .NET Framework 3.5 I created it using several resources (various certification web sites, msdn, official ms 70-548 book). The reason that I created this review is because a) I am taking the exam. b) MS did not create a book for this exam. Use the(MS 70-548)book. c) To make sure I am familiar with each before the exam. I hope that it provides a good start for your own notes. I hope that someone finds this useful. At least, it will give you a starting point of what to expect to know on the PRO exam. Also, for those wondering, the PRO exam does contains very little code. It is basically all theory. 1. Validation Controls – How to prevent users from entering invalid data on forms. (MaskedTextBox control and RegEx) 2. ServiceController – used to start and control the behavior of existing services. 3. User Feedback (know winforms Status Bar, Tool Tips, Color, Error Provider, Context-Sensitive and Accessibility) 4. Specific (derived) exceptions must be handled before general (base class) exceptions. By moving the exception handling for the base type Exception to after exception handling of ArgumentNullException, all ArgumentNullException thrown by the Helper method will be caught and logged correctly. 5. A heartbeat method is a method exposed by a Web service that allows external applications to check on the status of the service. 6. New users must master key tasks quickly. Giving these tasks context and appropriate detail will help. However, advanced users will demand quicker paths. Shortcuts, accelerators, or toolbar buttons will speed things along for the advanced user. 7. MSBuild uses project files to instruct the build engine what to build and how to build it. MSBuild project files are XML files that adhere to the MSBuild XML schema. The MSBuild project files contain complete file, build action, and dependency information for each individual projects. 8. Evaluating whether or not to fix a bug involves a triage process. You must identify the bug's impact, set the priority, categorize it, and assign a developer. Many times the person doing the triage work will assign the bug to a developer for further investigation. In fact, the workflow for the bug work item inside of Team System supports this step. Developers are often asked to assess the impact of a given bug. This assessment helps the person doing the triage make a decision on how to proceed. When assessing the impact of a bug, you should consider time and resources to fix it, bug risk, and impacts of the bug. 9. In large projects it is generally impossible and unfeasible to fix all bugs because of the impact on schedule and budget. 10. Code reviews should be conducted by a technical lead or a technical peer. 11. Testing Applications 12. WCF Services – application state 13. SQL Server 2005 / 2008 Express Edition – reliable storage of data / Microsoft SQL Server 3.5 Compact Database– used for client computers to retrieve and save data from a shared location. 14. SQL Server 2008 Compact Edition – used for minimum possible memory and can synchronize data with a corporate SQL Server 2008 Database. Supports offline user and minimum dependency on external components. 15. MDI and SDI Forms (specifically IsMDIContainer) 16. GUID – in the case of data warehousing, it is important to define unique keys. 17. Encrypting / Security Data 18. Understanding of Isolated Storage/Proper location to store items 19. LINQ to SQL 20. Multithreaded access 21. ADO.NET Entity Framework model 22. Marshal.ReleaseComObject 23. Common User Interface Layout (ComboBox, ListBox, Listview, MaskedTextBox, TextBox, RichTextBox, SplitContainer, TableLayoutPanel, TabControl) 24. DataSets Class - http://msdn.microsoft.com/en-us/library/system.data.dataset%28VS.71%29.aspx 25. SQL Server 2008 Reporting Services (SSRS) 26. SystemIcons.Shield (Vista UAC) 27. Leverging stored procedures to perform data manipulation for a database schema that can change. 28. DataContext 29. Microsoft Windows Installer Packages, ClickOnce(bootstrapping features), XCopy. 30. Client Application Services – will authenticate users by using the same data source as a ASP.NET web application. 31. SQL Server 2008 Caching 32. StringBuilder 33. Accessibility Guidelines for Windows Applications http://msdn.microsoft.com/en-us/library/ms228004.aspx 34. Logging erros 35. Testing performance related issues. 36. Role Based Security, GenericIdentity and GenericPrincipal 37. System.Net.CookieContainer will store session data for webapps (see isolated storage for winforms) 38. .NET CLR Profiler tool will identify objects that cause performance issues. 39. ADO.NET Synchronization (SyncGroup) 40. Globalization - CultureInfo 41. IDisposable Interface- reports on several questions relating to this. 42. Adding timestamps to determine whether data has changed or not. 43. Converting applications to .NET Framework 3.5 44. MicrosoftReportViewer 45. Composite Controls 46. Windows Vista KNOWN folders. 47. Microsoft Sync Framework 48. TypeConverter -Provides a unified way of converting types of values to other types, as well as for accessing standard values and sub properties. http://msdn.microsoft.com/en-us/library/system.componentmodel.typeconverter.aspx 49. Concurrency control mechanisms The main categories of concurrency control mechanisms are: Optimistic - Delay the checking of whether a transaction meets the isolation rules (e.g., serializability and recoverability) until its end, without blocking any of its (read, write) operations, and then abort a transaction, if the desired rules are violated. Pessimistic - Block operations of a transaction, if they may cause violation of the rules. Semi-optimistic - Block operations in some situations, and do not block in other situations, while delaying rules checking to transaction's end, as done with optimistic. 50. AutoResetEvent 51. Microsoft Messaging Queue (MSMQ) 4.0 52. Bulk imports 53. KeyDown event of controls 54. WPF UI components 55. UI process layer 56. GAC (installing, removing and queuing) 57. Use a local database cache to reduce the network bandwidth used by applications. 58. Sound can easily be annoying and distracting to users, so use it judiciously. Always give users the option to turn sound off. Because a user might have sound off, never convey important information through sound alone.

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  • Invitation: WebCenter Implementation Specialist Exam Preparation Webcasts

    - by rituchhibber
    Oracle Partner Network would like to invite you to Refresh Courses for WebCenter Content and WebCenter Portal, to help partners to prepare for the WebCenter Implementation Specialist EXAMS.This is a 3 hours intensive refresher partner-only training session, providing attendees with an overview of WebCenter Content and WebCenter Portal functions and related topics. After the refresher part you will be able to take the relevant Implementation Specialist EXAM depending on your personal focus. NOTE: This is only suitable for experienced WebCenter Content or WebCenter Portal practitioners Who should attend?Partner Consultants who want to become an Oracle WebCenter Content or a WebCenter Portal Certified Implementation Specialist or both, that will help them to differentiate themselves in front of customers and support their Companies to become Specialized. Webcast Details: Date Topic Speaker  Web Call Details  Intercall Details  December 14th WebCenter Content RefreshCourse Markus Neubauer, SilburyWebCenter Content Specialized Partner Join Webcast Dial-in numbers:CC/SP: 1579222/9221 Time: 12:00 -15:00 CET Break around 13:30 Conference ID/Key: 9249533/1412 Date Topic Speaker Web Call Details Intercall Details January 10th                  WebCenter Portal    Refresh Course                   Yannick Ongena, InfoMentumWebCenter Portal Specialized Partner                     Join Webcast Dial-in numbers:CC/SP: 1579222/9221 Time: 12:00 -15:00 CET Break around 13:30 Conference ID/Key: 9249375/1001 Date Topic Speaker Web Call Details Intercall Details February 22nd                WebCenter Content  RefreshCourse Markus Neubauer, SilburyWebCenter Content Specialized Partner    Join Webcast Dial-in numbers:CC/SP: 1579222/9221 Time: 12:00 -15:00 CET Break around13:30 Conference ID/Key: 9249541/2202 Date Topic Speaker Web Call Details Intercall Details  March 13th                WebCenter Portal   Refresh     Course      Yannick Ongena, InfoMentumWebCenter Portal Specialized Partner    Join Webcast Dial-in numbers:CC/SP: 1579222/9221 Time: 12:00 -15:00 CET Break around 13:30 Conference ID/Key: 9249549/1303 Local dial-in numbers can be found here . Next Steps:After the Webcast you will receive the Training material and FREE Vouchers to book and take the: Oracle ECM 11g Certified Implementation Specialist EXAM Oracle WebCenter 11g Essentials EXAM Booking with Voucher can be done on www.pearsonvue.com. Note: FREE Vouchers will be send after attending the webcast.

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  • Oracle Linux 6 Implementation Essentials Certification Exam Now Available

    - by Antoinette O'Sullivan
    Get proof of your linux system administration skills by taking the Oracle Linux 6 Implementation Essentials Certification exam. This certification is available to all candidates. Oracle Partner Members earning this certification will be recognized as OPN Certified Specialists. This certification takes under 3 hours, asking you between 120-150 questions on areas including: Introduction to Oracle Linux Installing Oracle Linux 6 Linux Boot Process Oracle Linux System Configuration and Process Management Oracle Linux Package Management Ksplice Zero Downtime Updates Automate Tasks and System Logging User and Group Administration Oracle Linux File Sytems and Storage Administration Network Administration Oracle Linux System Monitoring and Troubleshooting Oracle Certifications are among the most sought after badges of credibility for expertise in the Information Technology marketplace. See Benefits of Oracle Certification for more information. To prepare for this exam, you can take the Oracle Linux System Administration training.

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  • New Exam in Beta Testing: Oracle Fusion CRM - Sales 2014 Implementation Essentials

    - by Richard Lefebvre
    Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 This new exam is designed for individuals who possess a strong foundation and expertise in implementing Oracle Sales Cloud solutions. Request your free exam voucher now! /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Times New Roman","serif";}

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  • This program runs but not correctly; the numbers aren't right.

    - by user320950
    this program runs but not correctly numbers arent right, i read numbers from a file and then when i am using them in the program they are not right.:brief decription of what i am trying to do can someone tell me if something doesnt look right. this is what i have to do: write a program that determines the grade dispersal for 100 students You are to read the exam scores into three arrays, one array for each exam. You must then calculate how many students scored A’s (90 or above), B’s (80 or above), C’s (70 or above), D’s (60 or above), and F’s (less than 60). Do this for each exam and write the distribution to the screen. // basic file operations #include <iostream> #include <fstream> using namespace std; int read_file_in_array(double exam[100][3]); double calculate_total(double exam1[], double exam2[], double exam3[]); // function that calcualates grades to see how many 90,80,70,60 //void display_totals(); double exam[100][3]; int main() { double go,go2,go3; double exam[100][3],exam1[100],exam2[100],exam3[100]; go=read_file_in_array(exam); go2=calculate_total(exam1,exam2,exam3); //go3=display_totals(); cout << go,go2,go3; return 0; } /* int display_totals() { int grade_total; grade_total=calculate_total(exam1,exam2,exam3); return 0; } */ double calculate_total(double exam1[],double exam2[],double exam3[]) { int calc_tot,above90=0, above80=0, above70=0, above60=0,i,j, fail=0; double exam[100][3]; calc_tot=read_file_in_array(exam); for(i=0;i<100;i++) { for (j=0; j<3; j++) { exam1[i]=exam[100][0]; exam2[i]=exam[100][1]; exam3[i]=exam[100][2]; if(exam[i][j] <=90 && exam[i][j] >=100) { above90++; { if(exam[i][j] <=80 && exam[i][j] >=89) { above80++; { if(exam[i][j] <=70 && exam[i][j] >=79) { above70++; { if(exam[i][j] <=60 && exam[i][j] >=69) { above60++; { if(exam[i][j] >=59) { fail++; } } } } } } } } } } } return 0; } int read_file_in_array(double exam[100][3]) { ifstream infile; int exam1[100]; int exam2[100]; int exam3[100]; infile.open("grades.txt");// file containing numbers in 3 columns if(infile.fail()) // checks to see if file opended { cout << "error" << endl; } int num, i=0,j=0; while(!infile.eof()) // reads file to end of line { for(i=0;i<100;i++) // array numbers less than 100 { for(j=0;j<3;j++) // while reading get 1st array or element infile >> exam[i][j]; infile >> exam[i][j]; infile >> exam[i][j]; cout << exam[i][j] << endl; { if (! (infile >> exam[i][j]) ) cout << exam[i][j] << endl; } exam[i][j]=exam1[i]; exam[i][j]=exam2[i]; exam[i][j]=exam3[i]; } infile.close(); } return 0; }

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  • this program runs but not correctly:brief decription of what i am trying to do can someone tell me i

    - by user320950
    this is what i have to do: write a program that determines the grade dispersal for 100 students You are to read the exam scores into three arrays, one array for each exam. You must then calculate how many students scored A’s (90 or above), B’s (80 or above), C’s (70 or above), D’s (60 or above), and F’s (less than 60). Do this for each exam and write the distribution to the screen. // basic file operations #include <iostream> #include <fstream> using namespace std; int read_file_in_array(double exam[100][3]); double calculate_total(double exam1[], double exam2[], double exam3[]); // function that calcualates grades to see how many 90,80,70,60 //void display_totals(); double exam[100][3]; int main() { double go,go2,go3; double exam[100][3],exam1[100],exam2[100],exam3[100]; go=read_file_in_array(exam); go2=calculate_total(exam1,exam2,exam3); //go3=display_totals(); cout << go,go2,go3; return 0; } /* int display_totals() { int grade_total; grade_total=calculate_total(exam1,exam2,exam3); return 0; } */ double calculate_total(double exam1[],double exam2[],double exam3[]) { int calc_tot,above90=0, above80=0, above70=0, above60=0,i,j, fail=0; double exam[100][3]; calc_tot=read_file_in_array(exam); for(i=0;i<100;i++) { for (j=0; j<3; j++) { exam1[i]=exam[100][0]; exam2[i]=exam[100][1]; exam3[i]=exam[100][2]; if(exam[i][j] <=90 && exam[i][j] >=100) { above90++; { if(exam[i][j] <=80 && exam[i][j] >=89) { above80++; { if(exam[i][j] <=70 && exam[i][j] >=79) { above70++; { if(exam[i][j] <=60 && exam[i][j] >=69) { above60++; { if(exam[i][j] >=59) { fail++; } } } } } } } } } } } return 0; } int read_file_in_array(double exam[100][3]) { ifstream infile; int exam1[100]; int exam2[100]; int exam3[100]; infile.open("grades.txt");// file containing numbers in 3 columns if(infile.fail()) // checks to see if file opended { cout << "error" << endl; } int num, i=0,j=0; while(!infile.eof()) // reads file to end of line { for(i=0;i<100;i++) // array numbers less than 100 { for(j=0;j<3;j++) // while reading get 1st array or element infile >> exam[i][j]; infile >> exam[i][j]; infile >> exam[i][j]; cout << exam[i][j] << endl; { if (! (infile >> exam[i][j]) ) cout << exam[i][j] << endl; } exam[i][j]=exam1[i]; exam[i][j]=exam2[i]; exam[i][j]=exam3[i]; } infile.close(); } return 0; }

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  • this program runs but not correctly numbers arent right, i read numbers from a file and then when i

    - by user320950
    this is what i have to do: write a program that determines the grade dispersal for 100 students You are to read the exam scores into three arrays, one array for each exam. You must then calculate how many students scored A’s (90 or above), B’s (80 or above), C’s (70 or above), D’s (60 or above), and F’s (less than 60). Do this for each exam and write the distribution to the screen. // basic file operations #include <iostream> #include <fstream> using namespace std; int read_file_in_array(double exam[100][3]); double calculate_total(double exam1[], double exam2[], double exam3[]); // function that calcualates grades to see how many 90,80,70,60 //void display_totals(); double exam[100][3]; int main() { double go,go2,go3; double exam[100][3],exam1[100],exam2[100],exam3[100]; go=read_file_in_array(exam); go2=calculate_total(exam1,exam2,exam3); //go3=display_totals(); cout << go,go2,go3; return 0; } /* int display_totals() { int grade_total; grade_total=calculate_total(exam1,exam2,exam3); return 0; } */ double calculate_total(double exam1[],double exam2[],double exam3[]) { int calc_tot,above90=0, above80=0, above70=0, above60=0,i,j, fail=0; double exam[100][3]; calc_tot=read_file_in_array(exam); for(i=0;i<100;i++) { for (j=0; j<3; j++) { exam1[i]=exam[100][0]; exam2[i]=exam[100][1]; exam3[i]=exam[100][2]; if(exam[i][j] <=90 && exam[i][j] >=100) { above90++; { if(exam[i][j] <=80 && exam[i][j] >=89) { above80++; { if(exam[i][j] <=70 && exam[i][j] >=79) { above70++; { if(exam[i][j] <=60 && exam[i][j] >=69) { above60++; { if(exam[i][j] >=59) { fail++; } } } } } } } } } } } return 0; } int read_file_in_array(double exam[100][3]) { ifstream infile; int exam1[100]; int exam2[100]; int exam3[100]; infile.open("grades.txt");// file containing numbers in 3 columns if(infile.fail()) // checks to see if file opended { cout << "error" << endl; } int num, i=0,j=0; while(!infile.eof()) // reads file to end of line { for(i=0;i<100;i++) // array numbers less than 100 { for(j=0;j<3;j++) // while reading get 1st array or element infile >> exam[i][j]; infile >> exam[i][j]; infile >> exam[i][j]; cout << exam[i][j] << endl; { if (! (infile >> exam[i][j]) ) cout << exam[i][j] << endl; } exam[i][j]=exam1[i]; exam[i][j]=exam2[i]; exam[i][j]=exam3[i]; } infile.close(); } return 0; }

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  • TechEd 2012: Windows Phone Exam Cram

    - by Tim Murphy
    Usually speakers take offence if you wear headphones in their talk.  For the exam cram session it was a requirement.  This was because it was a cubical walled room with an open top next to a study hall. While no-one was going to come out of this session ready to take a test, I am glad that I took the time to attend it.  There was a fair amount of material that you should know already if you have ever taken a certification test before.  This was packed around a mix of key concepts and some tidbits that marked where some of the pitfalls are for this particular test.  The biggest warning was that the test is based on Windows Phone 7.0 and not Mango meaning that you have to be careful that you don’t answer a question in the wrong context. I would suggest if you have a chance to take attend a free session grab it.  It is a good break from the other hard core talks and will get your mind into a mode for getting your next certification.  Good luck. del.icio.us Tags: TechEd,TechEd 2012,Windows Phone,Exam Cram,Certification

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  • A Question about .net Rfc2898DeriveBytes class?

    - by IbrarMumtaz
    What is the difference in this class? as posed to just using Encoding.ASCII.GetBytes(string object); I have had relative success with either approach, the former is a more long winded approach where as the latter is simple and to the point. Both seem to allow you to do the same thing eventually but I am struggling to the see the point in using the former over the latter. The basic concept I have been able to grasp is that you can convert string passwords into byte arrays to be used for e.g a symmetric encryption class, AesManaged. Via the RFC class but you get to use SaltValues and password when creating your rfc object. I assume its more secure but still thats an uneducated guess at best ! Also that it allows you to return byte arrays of a certain size, well something like that. heres a few examples to show you where I am coming from? byte[] myPassinBytes = Encoding.ASCII.GetBytes("some password"); or string password = "P@%5w0r]>"; byte[] saltArray = Encoding.ASCII.GetBytes("this is my salt"); Rfc2898DeriveBytes rfcKey = new Rfc2898DeriveBytes(password, saltArray); The 'rfcKey' object can now be used towards setting up the the .Key or .IV properties on a Symmetric Encryption Algorithm class. ie. RijndaelManaged rj = new RijndaelManaged (); rj.Key = rfcKey.Getbytes(rj.KeySize / 8); rj.IV = rfcKey.Getbytes(rj.Blocksize / 8); 'rj' should be ready to go ! The confusing part ... so rather than using the 'rfcKey' object can I not just use my 'myPassInBytes' array to help set-up my 'rj' object???? I have tried doing this in VS2008 and the immediate answer is NO ! but have you guys got a better educated answer as to why the RFC class is used over the other alternative I have mentioned above and why????

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  • Geek City: Preparing for the SQL Server Master Exam

    - by Kalen Delaney
    I was amazed at the results when I just did a search of SQLBlog, and realized no one had really blogged here about the changes to the Microsoft Certified Master (MCM) program. Greg Low described the MCM program when he decided to pursue the MCM at the end of 2008, but two years later, at the end of 2010, Microsoft completely changed the requirements. Microsoft published the new requirements here . The three week intensive course is no longer required, but that doesn't mean you can just buy an exam...(read more)

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  • Introducing Exam Preparation Seminars on iPad

    - by Brandye Barrington
    Oracle University announced last week, the availability of the new Oracle Training On Demand app for iPad. This means that Oracle Certification's Exam Preparation Seminars, which are in the Training On Demand format are conveniently available for viewing on your iPad. The app is supplemental to the Web browser version. Features include: Access to your Oracle Training On Demand course titles High-quality video playback Video download and offline playback Interactive Table of Contents Course search Ability to search and preview available courses The app is available for free on the Apple App Store.

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  • YouGrade - Silverlight Multimedia Exam Suite

    A multimedia exam suite built on Silverlight and Youtube...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Why would 70-persistent-net.rules have no effect?

    - by Wes Felter
    I've got a saucy server with a lot of NICs and they end up with weird names like "rename19". I know interface names can be changed by modifying the /etc/udev/rules.d/70-persistent-net.rules file. The first clue that something is wrong is that that file did not exist even though it's supposed to be created automatically. So I decided to write my own based on advice from Linux From Scratch: ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:06:00.0", NAME="eth0" ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:06:00.1", NAME="eth1" ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:06:00.2", NAME="eth2" ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:06:00.3", NAME="eth3" ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:0c:00.0", NAME="mezz0" ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:0c:00.1", NAME="mezz1" ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:1b:00.0", NAME="slot1a" ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:1b:00.1", NAME="slot1b" ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:20:00.0", NAME="slot2a" ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:20:00.1", NAME="slot2b" ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:11:00.0", NAME="slot3a" ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:11:00.1", NAME="slot3b" ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:8b:00.0", NAME="slot4a" ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:8b:00.1", NAME="slot4b" ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:90:00.0", NAME="slot5a" ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:90:00.1", NAME="slot5b" ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:95:00.0", NAME="slot6a" ACTION=="add", SUBSYSTEM=="net", BUS=="pci", KERNELS=="0000:95:00.1", NAME="slot6b" (I'm matching on PCI IDs instead of MAC addresses because I have multiple identical machines that I want to apply this configuration to.) After rebooting, nothing has changed. It's like these rules aren't even being read. There's not much going on in dmesg either: $ dmesg | grep udev [ 3.196629] systemd-udevd[323]: starting version 204 [ 6.719140] systemd-udevd[550]: starting version 204 [ 38.695050] init: udev-fallback-graphics main process (1658) terminated with status 1

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  • SQL SERVER – SQL in Sixty Seconds – 5 Videos from Joes 2 Pros Series – SQL Exam Prep Series 70-433

    - by pinaldave
    Joes 2 Pros SQL Server Learning series is indeed fun. Joes 2 Pros series is written for beginners and who wants to build expertise for SQL Server programming and development from fundamental. In the beginning of the series author Rick Morelan is not shy to explain the simplest concept of how to open SQL Server Management Studio. Honestly the book starts with that much basic but as it progresses further Rick discussing about various advanced concepts from query tuning to Core Architecture. This five part series is written with keeping SQL Server Exam 70-433. Instead of just focusing on what will be there in exam, this series is focusing on learning the important concepts thoroughly. This book no way take short cut to explain any concepts and at times, will go beyond the topic at length. The best part is that all the books has many companion videos explaining the concepts and videos. Every Wednesday I like to post a video which explains something in quick few seconds. Today we will go over five videos which I posted in my earlier posts related to Joes 2 Pros series. Introduction to XML Data Type Methods – SQL in Sixty Seconds #015 The XML data type was first introduced with SQL Server 2005. This data type continues with SQL Server 2008 where expanded XML features are available, most notably is the power of the XQuery language to analyze and query the values contained in your XML instance. There are five XML data type methods available in SQL Server 2008: query() – Used to extract XML fragments from an XML data type. value() – Used to extract a single value from an XML document. exist() – Used to determine if a specified node exists. Returns 1 if yes and 0 if no. modify() – Updates XML data in an XML data type. node() – Shreds XML data into multiple rows (not covered in this blog post). [Detailed Blog Post] | [Quiz with Answer] Introduction to SQL Error Actions – SQL in Sixty Seconds #014 Most people believe that when SQL Server encounters an error severity level 11 or higher the remaining SQL statements will not get executed. In addition, people also believe that if any error severity level of 11 or higher is hit inside an explicit transaction, then the whole statement will fail as a unit. While both of these beliefs are true 99% of the time, they are not true in all cases. It is these outlying cases that frequently cause unexpected results in your SQL code. To understand how to achieve consistent results you need to know the four ways SQL Error Actions can react to error severity levels 11-16: Statement Termination – The statement with the procedure fails but the code keeps on running to the next statement. Transactions are not affected. Scope Abortion – The current procedure, function or batch is aborted and the next calling scope keeps running. That is, if Stored Procedure A calls B and C, and B fails, then nothing in B runs but A continues to call C. @@Error is set but the procedure does not have a return value. Batch Termination – The entire client call is terminated. XACT_ABORT – (ON = The entire client call is terminated.) or (OFF = SQL Server will choose how to handle all errors.) [Detailed Blog Post] | [Quiz with Answer] Introduction to Basics of a Query Hint – SQL in Sixty Seconds #013 Query hints specify that the indicated hints should be used throughout the query. Query hints affect all operators in the statement and are implemented using the OPTION clause. Cautionary Note: Because the SQL Server Query Optimizer typically selects the best execution plan for a query, it is highly recommended that hints be used as a last resort for experienced developers and database administrators to achieve the desired results. [Detailed Blog Post] | [Quiz with Answer] Introduction to Hierarchical Query – SQL in Sixty Seconds #012 A CTE can be thought of as a temporary result set and are similar to a derived table in that it is not stored as an object and lasts only for the duration of the query. A CTE is generally considered to be more readable than a derived table and does not require the extra effort of declaring a Temp Table while providing the same benefits to the user. However; a CTE is more powerful than a derived table as it can also be self-referencing, or even referenced multiple times in the same query. A recursive CTE requires four elements in order to work properly: Anchor query (runs once and the results ‘seed’ the Recursive query) Recursive query (runs multiple times and is the criteria for the remaining results) UNION ALL statement to bind the Anchor and Recursive queries together. INNER JOIN statement to bind the Recursive query to the results of the CTE. [Detailed Blog Post] | [Quiz with Answer] Introduction to SQL Server Security – SQL in Sixty Seconds #011 Let’s get some basic definitions down first. Take the workplace example where “Tom” needs “Read” access to the “Financial Folder”. What are the Securable, Principal, and Permissions from that last sentence? A Securable is a resource that someone might want to access (like the Financial Folder). A Principal is anything that might want to gain access to the securable (like Tom). A Permission is the level of access a principal has to a securable (like Read). [Detailed Blog Post] | [Quiz with Answer] Please leave a comment explain which one was your favorite video as that will help me understand what works and what needs improvement. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology, Video

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  • Unable to access Windows share

    - by mbnoimi
    I've installed Alfresco 4.2.d under Ubuntu 12.04 LTS; Everything done fine except I can't access it from Windows share although I got the link from Alfresco explorer which is: file:///%5C%5CECSA%5CAlfresco%5CSites%5Cswsdp%5CdocumentLibrary%5CAgency%20Files%5CImages%5Ccoins.JPG I tried to access it from: \\ECSA but I failed too so I made a ping (192.168.0.70 is server IP) then I got: C:\Users\user>ping 192.168.0.70 Pinging 192.168.0.70 with 32 bytes of data: Reply from 192.168.0.70: bytes=32 time<1ms TTL=64 Reply from 192.168.0.70: bytes=32 time<1ms TTL=64 Reply from 192.168.0.70: bytes=32 time<1ms TTL=64 Reply from 192.168.0.70: bytes=32 time<1ms TTL=64 Ping statistics for 192.168.0.70: Packets: Sent = 4, Received = 4, Lost = 0 (0% loss), Approximate round trip times in milli-seconds: Minimum = 0ms, Maximum = 0ms, Average = 0ms C:\Users\user>ping ECSA Ping request could not find host ECSA. Please check the name and try C:\Users\user> Some logs of what's going on: C:\Users\user>net view ECSA System error 1707 has occurred. The network address is invalid. C:\Users\user>nbtstat -a 192.168.0.70 Local Area Connection: Node IpAddress: [192.168.0.84] Scope Id: [] NetBIOS Remote Machine Name Table Name Type Status --------------------------------------------- ECSA <20> UNIQUE Registered ECSA <00> UNIQUE Registered WORKGROUP <00> GROUP Registered MAC Address = 00-00-00-00-00-00 C:\Users\user> CIFS Server Configuration in file-servers.properties ### CIFS Server Configuration - file-servers.properties ### cifs.enabled=true cifs.serverName=${localname}A cifs.domain= cifs.broadcast=255.255.255.255 cifs.bindto=192.168.0.70 cifs.ipv6.enabled=false cifs.hostannounce=true cifs.disableNIO=false cifs.disableNativeCode=false cifs.sessionTimeout=900 cifs.maximumVirtualCircuitsPerSession=16 cifs.tcpipSMB.port=445 cifs.netBIOSSMB.sessionPort=139 cifs.netBIOSSMB.namePort=137 cifs.netBIOSSMB.datagramPort=138 cifs.WINS.autoDetectEnabled=true cifs.WINS.primary=192.168.0.70 cifs.WINS.secondary=192.168.0.1 cifs.sessionDebug= cifs.pseudoFiles.enabled=true cifs.pseudoFiles.explorerURL.enabled=true cifs.pseudoFiles.explorerURL.fileName=__Alfresco.url cifs.pseudoFiles.shareURL.enabled=false cifs.pseudoFiles.shareURL.fileName=__Share.url How can I fix this issue?

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  • DL380 G7: Not able to access ILO on DL380 via ssh from a client

    - by user117140
    I have problem where I can't access my ILO(ssh to ILO IP) thru client which is in different network.I am able to ping ILO IP thru this clinet but ssh access is not possible. Is it possible to have ssh to ILO IP from a client which is in different network? FYI, from the same client I can do ssh to server application IP but ssh to this server ILO IP is not possible. Kindly help? Some more info added: ILO IP address is 10.247.172.70 and its VLAN is different than Client VLAN. Client IP address is 10.247.167.80. ping to ILO IP from this client is possible but not ssh. I can do ssh to ILO IP if I try to do it from the server(hostname:node1) having ILO port or from the other node of this cluster itself,So ssh login is enabled. [root@node1 ~]$ssh -v 10.247.173.70 OpenSSH_4.3p2, OpenSSL 0.9.8e-fips-rhel5 01 Jul 2008 debug1: Reading configuration data /etc/ssh/ssh_config debug1: Applying options for * debug1: Connecting to 10.247.173.70 [10.247.173.70] port 22. [root@node1 ~]$ping 10.247.173.70 PING 10.247.173.70 (10.247.173.70) 56(84) bytes of data. 64 bytes from 10.247.173.70: icmp_seq=1 ttl=254 time=0.283 ms 64 bytes from 10.247.173.70: icmp_seq=2 ttl=254 time=0.344 ms 64 bytes from 10.247.173.70: icmp_seq=3 ttl=254 time=0.324 ms 64 bytes from 10.247.173.70: icmp_seq=4 ttl=254 time=0.367 ms

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  • wireless clients not getting correct dhcp addresses

    - by szeli
    I apologise first if this is a stupid problem. I'm new to Cisco networking. I need some help with an existing configuration done by my vendor. Environment: 1. Core switch - Catalyst 6509e vlans configured: a. vlan 50 (wired clients) 10.0.50.x/24 interface IP 10.0.50.20 b. vlan 70 (wireless clients) 10.0.70.x/24 interface IP 10.0.70.20 c. vlan 192 (guest clients) 192.168.1.x/24 interface IP 192.168.1.20 d. trunk port for WLC native vlan 70 allowed vlan 50, 70, 192 2. Cisco 4402 WLC interfaces a. management untagged IP 10.0.70.10 b. ap-manager untagged IP 10.0.70.11 c. service-port n/a IP 192.168.10.1 d. virtual n/a IP 1.1.1.1 e. guestwlan vlan192 IP 192.168.1.100 3. Cisco AIR-LAP1142N-S-K9 LAP01 (WLAN local, interface: management) IP 10.0.70.21/24 GW 10.0.70.20 DHCP server 10.0.50.10 (scope 10.0.70.101 to 200) LAP02 (WLAN guest, interface: guestwlan) IP 192.168.1.21/24 GW 192.168.1.20 DHCP server 192.168.1.10 (scope 192.168.1.101 to 200) here's the problem, wireless clients connected to WLAN guest keep getting DHCP leases from WLAN local 10.0.50.10 (scope 10.0.70.101 to 200) can anyone please help? thanks!

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