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Search found 294 results on 12 pages for 'jonny boy'.

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  • In Java, does return trump finally?

    - by jonny five
    If I have a try/catch block with returns inside it, will the finally block be called? For example: try { something(); return success; } catch (Exception e) { return failure; } finally { System.out.println "i don't know if this will get printed out." } I know I can just type this in an see what happens (which is what I'm about to do, actually) but when I googled for answers nothing came up, so I figured I'd throw this up as a question. Thanks!

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  • How can I get node coordinates from a graph, using Perl?

    - by jonny
    Ok, I have a flowchart definition (basically, array of nodes and edges for each node). Now I want to calculate coordinates for every task in the flow, preferably hierarchycal style. I need something like Graph::Easy::Layout but I have no idea how to get nodes coordinates: I render nodes myself and I only want to retrieve box coordinates/size. Any suggestions? What I need is a CPAN module available even in Debian repository.

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  • generate image of basic figures with perl

    - by jonny
    I am using jalava library as a diagram drawing tool. It displays firgures as images in order to maintain compatibility with majority of browsers. When diagram block is being resized a request is being made and new gif image is generated and send to browser. What I need is generating image of basic blocks, like rounded rectangle, circle, diamond with specified parameters (height, width and color). I want to do all server-side; my server part is written on Perl.

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  • jQuery arrays - newbie needs a kick start

    - by Jonny Wood
    I've only really started using this site and alredy I am very impressed by the community here! This is my third question in less than three days. Hopefully I'll be able to start answering questions soon instead of just asking them! I'm fairly new to jQuery and can't find a decent tutorial on Arrays. I'd like to be able to create an array that targets several ID's on my page and performs the same effect for each. For example I have tabs set up with the following: $('.tabs div.tab').hide(); $('.tabs div:first').show(); $('.tabs ul li:first a').addClass('current'); $('.tabs ul li a').click(function(){ $('.tabs ul li a').removeClass('current'); $(this).addClass('current'); var currentTab = $(this).attr('href'); $('.tabs div.tab').hide(); $(currentTab).show(); return false; }); I've used the class .tag to target the tabs as there are several sets on the same page, but I've heard jQuery works much faster when targetting ID's How would I add an array to the above code to target 4 different ID's? I've looked at var myArray = new Array('#id1', 'id2', 'id3', 'id4'); And also var myValues = [ '#id1', 'id2', 'id3', 'id4' ]; Which is correct and how do I then use the array in the code for my tabs...?

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  • Orientation issue while presenting Modal ViewController

    - by Jacky Boy
    Current scenario: Right now I am showing a UIViewController using a segue with the style Modal and presentation Sheet. This Modal gets its superview bounds change, in order to have the dimensions I want, like this: - (void)viewWillLayoutSubviews { [super viewWillLayoutSubviews]; self.view.superview.bounds = WHBoundsRect; } The only allowed orientations are UIInterfaceOrientationLandscapeLeft and UIInterfaceOrientationLandscapeRight. Since the Modal has some TextFields and the keyboard would be over the Modal itself, I am changing its center so it moves a bit to the top. The problem: What I am noticing right now, is that I am unable to work with the Y coordinate. In order for it move vertically (remember it's on landscape) I need to work with the X. The problem is that when it's UIInterfaceOrientationLandscapeLeft I need to come with a negative X. And when it's UIInterfaceOrientationLandscapeRight I need to come with a positive X. So it seems that the X/Y Coordinate System is "glued" to the top left corner while in Portrait and when an orientation occurs, it's still there: What I have done So I have something like this: UIInterfaceOrientation orientation = [[UIApplication sharedApplication] statusBarOrientation]; NSInteger newX = 0.0f; if (orientation == UIInterfaceOrientationLandscapeLeft) { // Logic for calculating the negative X. } else { // Logic for calculating the positive X. } It works exactly like I want, but it seems a very fragile implementation. Am I missing something? Is this the expected behaviour?

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  • Partial class or "chained inheritance"

    - by Charlie boy
    Hi From my understanding partial classes are a bit frowned upon by professional developers, but I've come over a bit of an issue; I have made an implementation of the RichTextBox control that uses user32.dll calls for faster editing of large texts. That results in quite a bit of code. Then I added spellchecking capabilities to the control, this was made in another class inheriting RichTextBox control as well. That also makes up a bit of code. These two functionalities are quite separate but I would like them to be merged so that I can drop one control on my form that has both fast editing capabilities and spellchecking built in. I feel that simply adding the code form one class to the other would result in a too large code file, especially since there are two very distinct areas of functionality, so I seem to need another approach. Now to my question; To merge these two classes should I make the spellchecking RichTextBox inherit from the fast edit one, that in turn inherits RichTextBox? Or should I make the two classes partials of a single class and thus making them more “equal” so to speak? This is more of a question of OO principles and exercise on my part than me trying to reinvent the wheel, I know there are plenty of good text editing controls out there. But this is just a hobby for me and I just want to know how this kind of solution would be managed by a professional. Thanks!

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  • Use of 'super' keyword when accessing non-overridden superclass methods

    - by jonny
    I'm trying to get the hang of inheritance in Java and have learnt that when overriding methods (and hiding fields) in sub classes, they can still be accessed from the super class by using the 'super' keyword. What I want to know is, should the 'super' keyword be used for non-overridden methods? Is there any difference (for non-overridden methods / non-hidden fields)? I've put together an example below. public class Vehicle { public int tyreCost; public Vehicle(int tyreCost) { this.tyreCost = tyreCost; } public int getTyreCost() { return tyreCost; } } and public class Car extends Vehicle { public int wheelCount; public Vehicle(int tyreCost, int wheelCount) { super(tyreCost); this.wheelCount = wheelCount; } public int getTotalTyreReplacementCost() { return getTyreCost() * wheelCount; } } Specifically, given that getTyreCost() hasn't been overridden, should getTotalTyreReplacementCost() use getTyreCost(), or super.getTyreCost() ? I'm wondering whether super should be used in all instances where fields or methods of the superclass are accessed (to show in the code that you are accessing the superclass), or only in the overridden/hidden ones (so they stand out).

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  • designing classes and objects in .net for a restaurant assignment

    - by Dell Boy
    I have received an assignment at School for creating a Restaurant site. I have to use objects and classes (OOP) for my assignment. I have the foundations of the OOP in .net, but what I don't know is how can I design this assignment to be object-oriented. I don't know how to start it. The requirement is like this: The menu has to be saved in a database and retrieved from it. The menu is devided in appetizers, Salades, Main Meal, Pastas, Wines, Beverages, Extras, Do I create classes like this: Base Class: Menu Derived classes: Appetizers, Salades, Main meal, Pastas, wines, etc. If you have a good example about how to create classes from a Menu that will be great. You don't have to rely on the example I gave above. The menu can be anything. I can deside what the menu will contain. thanks a lot. I am waiting for some help. Please

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  • how to prevent myControl.g.cs from overwriting with wrong base class

    - by Jonny Cundall
    I've got two custom cursors for my app, MyCursor and MyOtherCursor, both of which were designed in xaml, and I added some behaviour in the xaml.cs for each of them. This behaviour was the same for both so I had them inherit from a base class to reduce code duplication. public partial class myCursor: CursorBase { public InterchangeCursor() { InitializeComponent(); } } public class CursorBase : UserControl { public virtual void MoveTo(Point pt) { this.SetValue(Canvas.LeftProperty, pt.X); this.SetValue(Canvas.TopProperty, pt.Y); } } my problem is that if I change something in the xaml for MyCursor, the MyCursor.g.cs file is regenerated, and instead of inheriting from CursorBase, the partial class in the g.cs inherits from System.Windows.Controls.UserControl. Since the other side of the partial class in the xaml.cs file still inherits CursorBase, a build error occurs. I'm finding it annoying fixing the g.cs file each time. Does anyone know how to prevent this happening?

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  • Image swaping with click on <tr>

    - by Jonny Sooter
    I've edited this piece of code from the Data Tables Plugin witch makes a tr click able and pops open another tr with details from the clicked tr. This piece of code is the event listener for opening and closing. When "details" are open the img should be images/details_close.png and they are closed the img should be images/details_open.png and have a swap occurring when it opens and closes when clicked. What is happening is there is no swap going on when its open or closed I still only get the "details_open.png". I don't knoe if I'm just not selecting the img tag properly or whats going on. Link to project: http://www2.kent.k12.wa.us/ksd/it/www/mobile/elementary.html $('#example tbody').on('click', 'td', function (e) { var myImage = $(this).find("img"); var nTr = $(this).parents('tr')[0]; if ( oTable.fnIsOpen(nTr) ) { /* This row is already open - close it */ myImage.src = "images/details_open.png"; oTable.fnClose( nTr ); } else { /* Open this row */ myImage.src = "images/details_close.png"; oTable.fnOpen( nTr, fnFormatDetails(oTable, nTr), 'details' ); } } );

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  • jQuery changing css on navigation when div # scrolls into view

    - by Jonny Wood
    I'm looking to recreate the effect used on this site: http://www.brizk.com/ The site uses one large page that scrolls down. As you scroll down and pass different sections the menu navigation on the left changes css class to "current" as the corresponding div comes into view. I presume this can be done with jQuery using $(window).height(); I'm fairly new to jQuery and what I want to write is something like this (in laymans terms): Get height of browser window – if div#content1 is 100px from top and/or 200px from bottom change menu a#link1 to '.current' – else remove .current from all menu a links ... and repeat for 4 different content divs. Can anyone point me in the right direction..? Thanks.

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  • Bitmap size exceeds VM budget after second load

    - by jonny
    This is driving me crazy. I have a game which has a bitmap as the background, this is big so I scale it down and this works fine. However when I navigate to another activity and then reload the game screen it crashes on drawing the background. I am calling recycle on all the bitmaps and setting them to null on onDestroy() but this doesn't help. Any ideas and if not how can I debug the memory to see at which step its growing. I looked at getting the heap but nothing of any size is on there really. Thanks.

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  • Help with database design

    - by Jonny
    Hey im new to database design and having trouble trying to figure this one out. I have two tables Team and Fixtures. Team has rows of football teams and Fixture has 2 of those football teams in each row (home and away team). I want to link team id to home_team and away_team but it doesnt allow me to. Please tell me how i can solve this. Here is an image of my tables/relationships http://i49.tinypic.com/288qwpg.jpg

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  • Use desktop widget to run corporate web application

    - by jonny
    So the question is simple: is it possible to set windows desktop to corporate application page (anybody remembers that active desktop thing?) and use it instead of browser (sic!). My thoughts: Windows 7: I can create giant full-screen widget that will show my page. Still have no idea if I will be able to navigate inside it though. Windows Vista: ???. I know there is still a side bar gadget that hosts a browser. Windows XP: create static html page with iframe pointing to corporate app home page. Problem: clicking links on page still opens default browser.

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  • C++: Short question regarding switch and break

    - by oh boy
    Example: switch( x ) { case y: if ( true ) { break; } cout << "Oops"; break; } If the switch statement selects y, will Oops be written to the standard output? - Is break in switch statements a dynamic keyword like continue which can be called under conditions or static like a closing bracket }?

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  • jQuery .hasClass method to omit effect

    - by Jonny Wood
    I've created a simple background effect for some tabs on a page but don't want that effect to fire if the tab has the class 'current'. I presume there is a way to do this using .hasClass Here's what I'm using for the effect: $('ul.htabs a').mouseover(function(){ $(this).stop().animate( {backgroundPosition:"(0 -810px)"}, {duration:150}, {easing: 'easeOutCubic'}) }).mouseout(function(){ $(this).stop().animate( {backgroundPosition:"(0 -806px)"}, {duration:150}, {easing: 'easeInCubic'}) });

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  • How to repair Java in Ubuntu after trying to switch to Java 6 using update-java-alternatives

    - by Kau-Boy
    I tried to switch from Java 5 to Java 6 using the "update-java-alternatives" command like explained on this page: https://help.ubuntu.com/community/Java But afterwards I get the following error when I tried to execute java: root@webserver:~# java Error occurred during initialization of VM Could not reserve enough space for object heap Could not create the Java virtual machine. I also tried to reinstall the java binaries using "apt-get" but I didn't succeed reinstalling it. I would like to post the "apt-get" errors, but unfortunately I don't know how to print out the error messages in English and not in German. My system is a Ubuntu 8.04 ROOT server. Here is the (Google translated) english text tring to install Java 6 again: root@server:~# apt-get install sun-java6-jdk Reading package lists ... Ready Dependency tree Reading state information ... Ready sun-java6-jdk is already the newest version. sun-java6-jdk set to manually installed. 0 upgraded, 0 newly installed, 0 to remove and 86 not upgraded. 1 not fully installed or removed. After this operation, 0B of additional disk space will be used. Set up a sun-java6-bin (6-03-0ubuntu2) ... Could not create the Java virtual machine. dpkg: error processing sun-java6-bin (- configure): Subprocess post-installation script returned error exit status 1 Errors were encountered while processing: sun-java6-bin E: Sub-process / usr / bin / dpkg returned an error code (1) I hope that this might help you helping me.

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  • rendering html to png (server-side)

    - by jonny
    Hi! I have a workflow model. Internet Explorer doesn't support some features required for model editing functionality (and regular user doesn't need it). I want a read-only preview of my model. Is it possible to server-side render my html to image?

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  • PHP-How to Pass Multiple Value In Form Field

    - by Tall boY
    hi i have a php based sorting method with drop down menu to sort no of rows, it is working fine. i have another sorting links to sort id & title, it is also working fine. but together they are not working fine. what happens is that when i sort(say by title) using links, result gets sorted by title, then if i sort rows using drop down menu rows get sorted but result gets back to default of id sort. sorting codes for id & tite is if ($orderby == 'title' && $sortby == 'asc') {echo " <li id='scurrent'><a href='?rpp=$rowsperpage&order=title&sort=asc'>title-asc:</a></li> ";} else {echo " <li><a href='?rpp=$rowsperpage&order=title&sort=asc'>title-asc:</a></li> ";} if ($orderby == 'title' && $sortby == 'desc') {echo " <li id='scurrent'><a href='?rpp=$rowsperpage&order=title&sort=desc'>title-desc:</a></li> ";} else {echo " <li><a href='?rpp=$rowsperpage&order=title&sort=desc'>title-desc:</a></li> ";} if ($orderby == 'id' && $sortby == 'asc') {echo " <li id='scurrent'><a href='?rpp=$rowsperpage&order=id&sort=asc'>id-asc:</a></li> ";} else {echo " <li><a href='?rpp=$rowsperpage&order=id&sort=asc'>id-asc:</a></li> ";} if ($orderby == 'id' && $sortby == 'desc') {echo " <li id='scurrent'><a href='?rpp=$rowsperpage&order=id&sort=desc'>id-desc:</a></li> ";} else {echo " <li><a href='?rpp=$rowsperpage&order=id&sort=desc'>id-desc:</a></li> ";} ?> sorting codes for rows is <form action="is-test.php" method="get"> <select name="rpp" onchange="this.form.submit()"> <option value="10" <?php if ($rowsperpage == 10) echo 'selected="selected"' ?>>10</option> <option value="20" <?php if ($rowsperpage == 20) echo 'selected="selected"' ?>>20</option> <option value="30" <?php if ($rowsperpage == 30) echo 'selected="selected"' ?>>30</option> </select> </form> this method passes only rows per page(rpp) into url. i want it to pass order, sort& rpp. is there a way around to pass multiple values in form fields like this. <form action="is-test.php" method="get"> <select name="rpp, order, sort" onchange="this.form.submit()"> <option value="10, $orderby, $sortby" <?php if ($rowsperpage == 10) echo 'selected="selected"' ?>>10</option> <option value="20, $orderby, $sortby" <?php if ($rowsperpage == 20) echo 'selected="selected"' ?>>20</option> <option value="30, $orderby, $sortby" <?php if ($rowsperpage == 30) echo 'selected="selected"' ?>>30</option> </select> </form> this may seem silly but it just to give you an idea of what i am trying to implement,(i am very new to php) please suggest any way to make this work. thanks

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