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Search found 806 results on 33 pages for 'latitude'.

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  • Is there an algorithm for determining how much daylight there is?

    - by Pharaun
    Is there a function/algorithm that allows me to input the latitude and the approximate orbital position of the earth in so that I can determine how long the sun is up? IE during the winter it would show that the sun is only up a few hours in the far north hemisphere. I did some basic Google search and didn't find much so I was thinking that I might have to do some trigonometry that would allow me to calculate how much the earth is inclined or not toward the sun then use that information along with the latitude to figure out how much sunshine a site would be getting.

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  • Add kilometers to a map point

    - by proveyourselfthom
    Good morning. I would like to know how do I add kilometers to a map point (latitude / longitude). For example: The city Jaraguá do Sul is in latitude -26.462049, longitude -49.059448. I want to add 100 kilometers up, down, and on the sides. I want to do a square and get the new points. How do I do that? I tried it: <?php $distance = 100; $earthRadius = 6371; $lat1 = -26.4853239150483; $lon1 = -49.075927734375; $bearing = 0; $lat2 = asin(sin($lat1) * cos($distance / $earthRadius) + cos($lat1) * sin($distance / $earthRadius) * cos($bearing)); $lon2 = $lon1 + atan2(sin($bearing) * sin($distance / $earthRadius) * cos($lat1), cos($distance / $earthRadius) - sin($lat1) * sin($lat2)); echo 'LAT: ' . $lat2 . '<br >'; echo 'LNG: ' . $lon2; ?> But it's returning wrong cordinates. Thank you! Thank you very much.

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  • How to use MySQL geospatial extensions with spherical geometries

    - by Joshua
    Hi Everyone, I would like to store thousands of latitude/longitude points in a MySQL db. I was successful at setting up the tables and adding the data using the geospatial extensions where the column 'coord' is a Point(lat, lng). Problem: I want to quickly find the 'N' closest entries to latitude 'X' degrees and longitude 'Y' degrees. Since the Distance() function has not yet been implemented, I used GLength() function to calculate the distance between (X,Y) and each of the entries, sorting by ascending distance, and limiting to 'N' results. The problem is that this is not calculating shortest distance with spherical geometry. Which means if Y = 179.9 degrees, the list of closest entries will only include longitudes of starting at 179.9 and decreasing even though closer entries exist with longitudes increasing from -179.9. How does one typically handle the discontinuity in longitude when working with spherical geometries in databases? There has to be an easy solution to this, but I must just be searching for the wrong thing because I have not found anything helpful. Should I just forget the GLength() function and create my own function for calculating angular separation? If I do this, will it still be fast and take advantage of the geospatial extensions? Thanks! josh UPDATE: This is exactly what I am describing above. However, it is only for SQL Server. Apparently SQL Server has a Geometry and Geography datatypes. The geography does exactly what I need. Is there something similar in MySQL?

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  • Get points from a Gdirections route

    - by Twan
    Hi, I'm trying to get a collection of points (latitude,longitude) between 2 adresses. The points needs to be on a valid tracfic route. I currently use Gdirections to create a route between 2 adresses. Is there a method to get somepoints allong this route? To me it seems impossible... thx in advance!

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  • Why is shrink_to_fit non-binding?

    - by Roger Pate
    The C++0x FCD states in 23.3.6.2 vector capacity: void shrink_to_fit(); Remarks: shrink_to_fit is a non-binding request to reduce capacity() to size(). [Note: The request is non-binding to allow latitude for implementation-specific optimizations. —end note] Why is it non-binding, and what optimizations are intended to be allowed?

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  • Using PHP to extract data from an ATOM feed and using it reverse lookup coordinates to an actual add

    - by gbhall
    Basically I have a public feed: http://www.google.com/latitude/apps/badge/api?user=-1671995934285587708&type=atom If you go to my Google Profile you can see it says: "Gareth is in 6 Seaside Gardens, Mullaloo WA 6027, Australia (1 minute ago)" google.com/profiles/Gareth.B.Hall How can I, using PHP, display my location on a website the same way it's displayed on my Google Profile? Thanks

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  • geo-indexing: efficiently calculating proximity based on latitude/longitude

    - by AnC
    My simple web app (WSGI, Python) supports text queries to find items in the database. Now I'd like to extend this to allow for queries like "find all items within 1 mile of {lat,long}". Of course that's a complex job if efficiency is a concern, so I'm thinking of a dedicated external module that does indexing for geo-coordinates - sort of like Lucene would for text. I assume a generic component like this already exists, but haven't been able to find anything so far. Any help would be greatly appreciated.

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  • Dell 36400 Display issue - "doubling up" intermittently

    - by alex
    I've got a Dell E6400 It's suddenly developed an intermittent fault with the display Every now and again, it seems to boot up with "double vision" By that I mean, its split horizontally, with each half showing the same thing, but with low resolution, and looks grainy - if that makes sense (I will try to get a couple of pictures if I can) I haven't changed any hardware or anything. I have re-built windows, to see if that fixed the problem, it didn't. I've upgraded the BIOS to see if that would help, still same problem. I'm out of ideas :-(

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  • Need a list of all countries in the world, with a longitude and latitude coordinate

    - by ptrn
    I need a list of all the countries in the world, with one lat/long coordinate for the country. I had a look at GeoNames, but all I can seem to find are lists that have the countries as well as cities in the same list. I guess I can just parse it and filter out the countries, but I was hoping to avoid that. Basically, what I need; Country name - Lat/long coordinate (some sort of center of the country) It doesn't need to say anything about continent, but I wouldn't mind if it did. _L

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  • Dell E6400 Display issue - "doubling up" intermittently

    - by alex
    I've got a Dell E6400 It's suddenly developed an intermittent fault with the display Every now and again, it seems to boot up with "double vision" By that I mean, its split horizontally, with each half showing the same thing, but with low resolution, and looks grainy - if that makes sense (I will try to get a couple of pictures if I can) I haven't changed any hardware or anything. I have re-built windows, to see if that fixed the problem, it didn't. I've upgraded the BIOS to see if that would help, still same problem. I'm out of ideas :-(

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  • Dell D630 - Touchpad does not move the mouse cursor

    - by Dean McKenzie
    Windows XP - Dell D630 - Synaptics Touch Pad driver installed. The system tray icon that shows the movement of your finger on the touchpad registeres movement. The scroll feature of the touchpad works on any window with a scroll bar. The double click works even. But it never actually moves the cursor on the screen. An external mouse works with out problems, and I've replaced the palm-rest/touchpad and it continues to happen. The touch stick in the middle of the keyboard works without problems. Does anyone have any ideas?

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  • Radius of multiple latitude/longitude points

    - by zekial
    I have a program that takes as input an array of lat/long points. I need to perform a check on that array to ensure that all of the points are within a certain radius. So, for example, the maximum radius I will allow is 100 miles. Given an array of lat/long (coming from a MySQL database, could be 10 points could be 10000) I need to figure out if they will all fit in a circle with radius of 100 miles. Kinda stumped on how to approach this. Any help would be greatly appreciated.

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  • Latitude & longitude coordinates of Australian states/territories for database using Google Maps

    - by RMW
    Hi, We have a database which has location-based search using Google Maps API. However searching by state or territory in Australia is problematic because Google Maps locates these at the centre of the states and most population centres in Australia are on the coast. We need to hand code in the latitudes and longitudes so that when someone searches for the state 'NSW', for example, the database returns relevant results. Does anyone know where to find a list of the coordinates for the boundaries of Australian states & territories to code into the database? This will save our busy programmer a lot of time. Thanks in advance.

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  • Mapview getLatitudeSpan and getLongitudeSpan not working

    - by janfsd
    Hi! Sometimes when trying to get the Latitude span or Longitude span of a mapview with getLatitudeSpan() and getLongitudeSpan() I get 0 and 360*1E6 respectively. This doesn't happen always but it is a problem, has anybody got this problem? Any workarounds? I tried using getProjection() too but I get the same problem. Here is the piece of code: MapView mapView = (MapView) findViewById(R.id.mapview); int lat = mapView.getLatitudeSpan(); // sometimes returns 0 int long = mapView.getLongitudeSpan(); // sometimes returns 360*1E6

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  • Converting an equation into a way java script can interpret it

    - by GeorgeTaylor
    So I have this code that is meant to do this equation: (1 / 15) * arccos(-tan(L) * tan(23.44 * sin(360 * (D + 284) / 365))) and for testing purposes alert it! But for some reason it returns "NaN". I've probably done something really stupid :P var now = new Date(); var start = new Date(now.getFullYear(), 0, 0); var diff = now - start; var oneDay = 1000 * 60 * 60 * 24; var d = Math.floor(diff / oneDay); var lat = position.coords.latitude; var long = position.coords.longitude; var tanlat = Math.atan(lat); var tantwentythree = Math.tan(23.44); var dayplus = d + 284; var sinday = Math.sin(360 * dayplus); var arccos = Math.acos(tanlat); var start = 1 / 15; var equation = start * arccos * tantwentythree * sinday / 365; alert(equation);

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