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  • Java: Calculate distance between a large number of locations and performance

    - by Ally
    I'm creating an application that will tell a user how far away a large number of points are from their current position. Each point has a longitude and latitude. I've read over this article http://www.movable-type.co.uk/scripts/latlong.html and seen this post http://stackoverflow.com/questions/837872/calculate-distance-in-meters-when-you-know-longitude-and-latitude-in-java There are a number of calculations (50-200) that need carried about. If speed is more important than the accuracy of these calculations, which one is best?

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  • Trouble with wireless driver on a Dell Latitude D830

    - by Kevin
    After uninstalling Dell's wireless utility I get a new hardware found dialog that can not find any driver for my wifi card on it's own. I'm running Windows XP Professional Service Pack 3, and I would like to use the default wifi handler since dell's utility does not work with my company's wireless switch. I did try downloading the recommend driver from the dell support site Network Adapter 2 Model Intel(R) PRO/Wireless 3945ABG Network Connection Description [12] Intel(R) PRO/Wireless 3945ABG Network Connection Status Connected

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  • Latitude XT2 Battery issue

    - by Multi_Mark
    I received the add-on battery yesterday and put it in side my new lattitude xt2 but it would not recognize the battery. the laptop simply flashed yellow and the battery itself when the white battery level indicator was pressed just flashed green i left it plugged in overnight and its still the same issue. it will not charge. i removed and re-inserted the battery several times to make sure the plug in was properly connected but still no luck. is there a trick to this? or some way i can make this work? or is it simply defective?

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  • Sort latitude and longitude coordinates into clockwise ordered quadrilateral

    - by Dave Jarvis
    Problem Users can provide up to four latitude and longitude coordinates, in any order. They do so with Google Maps. Using Google's Polygon API (v3), the coordinates they select should highlight the selected area between the four coordinates. Solutions and Searches http://www.geocodezip.com/map-markers_ConvexHull_Polygon.asp http://softsurfer.com/Archive/algorithm_0103/algorithm_0103.htm http://stackoverflow.com/questions/2374708/how-to-sort-points-in-a-google-maps-polygon-so-that-lines-do-not-cross http://stackoverflow.com/questions/242404/sort-four-points-in-clockwise-order http://en.literateprograms.org/Quickhull_%28Javascript%29 Graham's scan seems too complicated for four coordinates Sort the coordinates into two arrays (one by latitude, the other longitude) ... then? Jarvis March algorithm? Question How do you sort the coordinates in (counter-)clockwise order, using JavaScript? Code Here is what I have so far: // Ensures the markers are sorted: NW, NE, SE, SW function sortMarkers() { var ns = markers.slice( 0 ); var ew = markers.slice( 0 ); ew.sort( function( a, b ) { if( a.position.lat() < b.position.lat() ) { return -1; } else if( a.position.lat() > b.position.lat() ) { return 1; } return 0; }); ns.sort( function( a, b ) { if( a.position.lng() < b.position.lng() ) { return -1; } else if( a.position.lng() > b.position.lng() ) { return 1; } return 0; }); var nw; var ne; var se; var sw; if( ew.indexOf( ns[0] ) > 1 ) { nw = ns[0]; } else { ne = ns[0]; } if( ew.indexOf( ns[1] ) > 1 ) { nw = ns[1]; } else { ne = ns[1]; } if( ew.indexOf( ns[2] ) > 1 ) { sw = ns[2]; } else { se = ns[2]; } if( ew.indexOf( ns[3] ) > 1 ) { sw = ns[3]; } else { se = ns[3]; } markers[0] = nw; markers[1] = ne; markers[2] = se; markers[3] = sw; } What is a better approach? The recursive Convex Hull algorithm is overkill for four points in the data set. Thank you.

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  • Using Shapefile data to determine neighborhood for a longitude/latitude

    - by Kunal
    I'm trying to determine the neighborhood for a location, based on Zillow's freely published Shapefile data. I don't really know anything about the Shapefile format, and am having some trouble finding tutorials online -- but I basically want to take latitude/longitude pairs, and run it against the Shapefile data to determine the corresponding neighborhood(s). Can anyone point me in the right direction? Not even sure where to start. This is where I've grabbed the Shapefile files: http://www.zillow.com/howto/api/neighborhood-boundaries.htm

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  • Suggestions for Troubleshooting WIndows 7 lockups

    - by Craig L
    I've got a Dell Latitude E6500 that was working fine under Vista x64. I got one of the new Seagate 500GB Hybrid SSD/HD 2.5 drives and thought.. hmm.. let's try Win 7 x64 on it. Bottom line: It works great for hours and then it will hard lock. I don't mean BSOD (or whatever the Win7 equivalent is). I mean my screen is displaying a static image (if there is a clock displayed, it will be frozen at the time the lockup occurred) and the mouse and keyboard do not work. Control-Alt-Delete will not work. I have to hold down the power button to reboot. The event log records NOTHING at the time the lockup occurs. Obviously something is happening to the system to cause the lockup, but the default Windows 7 x64 doesn't log it. How can I log the things Windows doesn't normally log in Event Viewer ?

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  • Enter / Return key stops working

    - by andygrunt
    I have a Dell Latitude E5400 laptop running Windows 7. Everything runs fine on it for days then I suddenly notice the enter/return key is no longer working e.g. I could be writing an email, press enter for a new line but it doesn’t ‘register’ – so no new line. I thought it might be some dirt under the key perhaps so I tried running the Windows onscreen keyboard but the Enter key on that doesn’t work either. A reboot always fixes the problem but it’s a pain. Any ideas a) how to fix it and b) out of interest, is there some other key combination that I can use as an alternative to using the Enter key when I need to?

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  • Enter / Return key stops working

    - by andygrunt
    I have a Dell Latitude E5400 laptop running Windows 7. Everything runs fine on it for days then I suddenly notice the enter/return key is no longer working e.g. I could be writing an email, press enter for a new line but it doesn’t ‘register’ – so no new line. I thought it might be some dirt under the key perhaps so I tried running the Windows onscreen keyboard but the Enter key on that doesn’t work either. A reboot always fixes the problem but it’s a pain. Any ideas a) how to fix it and b) out of interest, is there some other key combination that I can use as an alternative to using the Enter key when I need to? UPDATE: Thanks to CarlF's suggestion, I tried exiting running programmes and found it seems to be a problem with PhraseExpress.

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  • Why Does My Laptop Freeze Up When Docked?

    - by Michael Haren
    I have a Dell Latitude D520. First with Windows XP and now with Windows 7, it completely freezes/locks up if I dock it while it's awake. If I hibernate/sleep, dock, then wake/resume, everything's fine. I installed the Dell Notebook System Software for Vista (No Win7 version available) and updated the bios to the latest version but the problem persists. As long as I remember to put this thing in standby before I dock it, it's extremely reliable--it survives my daily commute and heavy use and typically only reboots a few times a month. Any other ideas for things I can try?

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  • Fastest distance lookup given latitude/longitude?

    - by Ryan Detzel
    I currently have just under a million locations in a mysql database all with longitude and latitude information. With this I use another lat/lng to find the distance of certain places in the database but it's not as fast as I want it to be especially with 100+ hits a second. Is there a faster formula or possibly a faster system other than mysql for this? The formula I'm using is this. select name, ( 3959 * acos( cos( radians(42.290763) ) * cos( radians( locations.lat ) ) * cos( radians( locations.lng ) - radians(-71.35368) ) + sin( radians(42.290763) ) * sin( radians( locations.lat ) ) ) ) AS distance from locations where active = 1 HAVING distance < 10 ORDER BY distance;

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  • How to convert latitude or longitude to meters?

    - by Adam Taylor
    Hi, If I have a latitude or longitude reading in standard NMEA format is there an easy way / forumla to convert that reading to meters, which I can then implement in Java (J9)? Edit: Ok seems what I want to do is not possible /easily/, however what I really want to do is: Say I have a lat and long of a way point and a lat and long of a user is there an easy way to compare them to decide when to tell the user they are within a /reasonably/ close distance of the way point? I realise reasonable is subject but is this easily do-able or still overly maths-y? Thanks, Adam

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  • SQL 2003 Distance Latitude Longitude

    - by J.Hendrix
    I have a table full of Dealers along with their latitude and longitude. I am trying to determine the top n closest dealers to any given lat and lon. I already have the function to calculate distance between locations, but I want to do as few calculations as possible (my table can contain many thousands of entries). Currently I have to calculate the distance for each entry then sort them. Is there any way to sort before I do the calculation to improve performance? This question is good, but I will not always know my range. Should I just pick an arbitrarily high range then refine my results? I am thankful for any help the community can offer. declare @Lat real declare @lon real Set @lat = 41.05 Set @lon = -73.53 SELECT top 10 MemberID, Address1, City, State, Zip, Phone, Lat, Lon, (SELECT fun_DistanceLatLon] (@Lat,@lon,Lat,Lon)) as mDistance --Calculate distance FROM Dealers Order by (SELECT fun_DistanceLatLon] (@Lat,@lon,Lat,Lon))

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  • Fetch Latitude Longitude by passing postcodes to maps.google.com using Javascript

    - by Nirmal
    Hello All... I have Postcode in my large database, which contains values like SL5 9JH, LU1 3TQ etc. Now when I am pasting above postcode to maps.google.com it's pointing to a perfect location.. My requirement is like I want to pass post codes to maps.google.com and it should return a related latitude and longitude of that pointed location, that I want to store in my database. So, most probably there should be some javascript for that... If anybody have another idea regarding that please provide it.. Thanks in advance...

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  • iPhone: Turning latitude/longitude into "major cross-streets"

    - by Gloria
    Using the MKReverseGeocoder or GoogleAPI or MapKit... Is there a simple way to turn a latitude/longitude into "nearest major cross-streets"? A user might not have any idea where "12345 Pineapple" is located... so I want to show something like "Pineapple and Main"... or (larger, major roads) like "US-140 and Hwy 76". I don't really care what "major" is defined as... perhaps any road with higher speed limits... or more than 3 lanes... etc. I don't really care what "close by" is defines as... perhaps within 0-10 miles... or just "closest found".

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  • How to get the place name by latitude and longitude using openstreetmap in android

    - by Gaurav kumar
    In my app i am using osm rather than google map.I have latitude and longitude.So from here how i will query to get the city name from osm database..please help me. final String requestString = "http://nominatim.openstreetmap.org/reverse?format=json&lat=" + Double.toString(lat) + "&lon=" + Double.toString(lon) + "&zoom=18&addressdetails=1"; RequestBuilder builder = new RequestBuilder(RequestBuilder.GET, URL.encode(requestString)); try { @SuppressWarnings("unused") Request request = builder.sendRequest(null, new RequestCallback() { @Override public void onResponseReceived(Request request, Response response) { if (response.getStatusCode() == 200) { String city = ""; try { JSONValue json = JSONParser.parseStrict(response); JSONObject address = json.isObject().get("address").isObject(); final String quotes = "^\"|\"$"; if (address.get("city") != null) { city = address.get("city").toString().replaceAll(quotes, ""); } else if (address.get("village") != null) { city = address.get("village").toString().replaceAll(quotes, ""); } } catch (Exception e) { } } } }); } catch (Exception e1) { }

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  • Finding cities close to one another using longitude and latitude

    - by Jamie
    Each user in my db is associated to a city (with it's longitude and latitude) How would I go about finding out which cities are close to one another? i.e. in England, Cambridge is fairly close to London. So If I have a user who lives in Cambridge. Users close to them would be users living in close surrounding cities, such as London, Hertford etc. Any ideas how I could go about this? And also, how would I define what is close? i.e. in the UK close would be much closer than if it were in the US as the US is far more spread out. Ideas and suggestions. Also, do you know any services that provide this sort of functionality? Thanks

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  • Google maps in iPhone - city & State name by Longitude & Latitude

    - by sugar
    I have developed an application in which the data About Schools are stored in ASP.NET Web Server. The database has following values. =School Name = Longitude of School = Latitude of School. Now, I retrieve all the data in iPhone through web-service & NSURLRequest. Now, Following is my Problem. When user Clicks on a school ( in tableView ). Google map should be load - ( i can do that ) A pin should be dropped at the place - ( i can do that ) A pin title should be with City & State name - ( i can't do ) Thanks in advance for helping me.

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  • Storing high precision latitude/longitude numbers in iOS Core Data

    - by Bryan
    I'm trying to store Latitude/Longitudes in core data. These end up being anywhere from 6-20 digit precision. And for whatever reason, i had them as floats in Core Data, its rounding them and not giving me the exact values back. I tried "decimal" type, with no luck either. Are NSStrings my only other option? EDIT NSManagedObject: @interface Event : NSManagedObject { } @property (nonatomic, retain) NSDecimalNumber * dec; @property (nonatomic, retain) NSDate * timeStamp; @property (nonatomic, retain) NSNumber * flo; @property (nonatomic, retain) NSNumber * doub; Here's the code for a sample number that I store into core data: NSNumber *n = [NSDecimalNumber decimalNumberWithString:@"-97.12345678901234567890123456789"]; Code to access it again: NSNumber *n = [managedObject valueForKey:@"dec"]; NSNumber *f = [managedObject valueForKey:@"flo"]; NSNumber *d = [managedObject valueForKey:@"doub"]; Printed values: Printing description of n: -97.1234567890124 Printing description of f: <CFNumber 0x603f250 [0xfef3e0]>{value = -97.12345678901235146441, type = kCFNumberFloat64Type} Printing description of d: <CFNumber 0x6040310 [0xfef3e0]>{value = -97.12345678901235146441, type = kCFNumberFloat64Type}

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  • Calculating distance from latitude, longitude and height using a geocentric co-ordinate system

    - by Sarge
    I've implemented this method in Javascript and I'm roughly 2.5% out and I'd like to understand why. My input data is an array of points represented as latitude, longitude and the height above the WGS84 ellipsoid. These points are taken from data collected from a wrist-mounted GPS device during a marathon race. My algorithm was to convert each point to cartesian geocentric co-ordinates and then compute the Euclidean distance (c.f Pythagoras). Cartesian geocentric is also known as Earth Centred Earth Fixed. i.e. it's an X, Y, Z co-ordinate system which rotates with the earth. My test data was the data from a marathon and so the distance should be very close to 42.26km. However, the distance comes to about 43.4km. I've tried various approaches and nothing changes the result by more than a metre. e.g. I replaced the height data with data from the NASA SRTM mission, I've set the height to zero, etc. Using Google, I found two points in the literature where lat, lon, height had been transformed and my transformation algorithm is matching. What could explain this? Am I expecting too much from Javascript's double representation? (The X, Y, Z numbers are very big but the differences between two points is very small). My alternative is to move to computing the geodesic across the WGS84 ellipsoid using Vincenty's algorithm (or similar) and then calculating the Euclidean distance with the two heights but this seems inaccurate. Thanks in advance for your help!

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