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  • JPQL / SQL: How to select * from a table with group by on a single column?

    - by DavidD
    I would like to select every column of a table, but want to have distinct values on a single attribute of my rows (City in the example). I don't want extra columns like counts or anything, just a limited number of results, and it seems like it is not possible to directly LIMIT results in a JPQL query. Original table: ID | Name | City --------------------------- 1 | John | NY 2 | Maria | LA 3 | John | LA 4 | Albert | NY Wanted result, if I do the distinct on the City: ID | Name | City --------------------------- 1 | John | NY 2 | Maria | LA What is the best way to do that? Thank you for your help.

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  • C - array count, strtok, etc

    - by Pedro
    Hi... i have a little problem on my code... HI open a txt that have this: LEI;7671;Maria Albertina da silva;[email protected]; 9;8;12;9;12;11;6;15;7;11; LTCGM;6567;Artur Pereira Ribeiro;[email protected]; 6;13;14;12;11;16;14; LEI;7701;Ana Maria Carvalho;[email protected]; 8;13;11;7;14;12;11;16;14; LEI, LTCGM are the college; 7671, 6567, 7701 is student number; Maria, Artur e Ana are the students name; [email protected], ...@gmail are emails from students; the first number of every line is the total of classes that students have; after that is students school notes; example: College: LEI Number: 7671 Name: Maria Albertina da Silva email: [email protected] total of classes: 9 Classe Notes: 8 12 9 12 11 6 15 7 11. My code: typedef struct aluno{ char sigla[5];//college char numero[80];//number char nome[80];//student name char email[20];//email int total_notas;// total of classes char tot_not[40]; // total classes char notas[20];// classe notes int nota; //class notes char situacao[80]; //situation (aproved or disaproved) }ALUNO; void ordena(ALUNO*alunos, int tam)//bubble sort { int i=0; int j=0; char temp[100]; for( i=0;i<tam;i++) for(j=0;j<tam-1;j++) if(strcmp( alunos[i].sigla[j], alunos[i].sigla[j+1])>0){ strcpy(temp, alunos[i].sigla[j]); strcpy(alunos[i].sigla[j],alunos[i].sigla[j+1]); strcpy(alunos[i].sigla[j+1], temp); } } void xml(ALUNO*alunos, int tam){ FILE *fp; char linha[60];//line int soma, max, min, count;//biggest note and lowest note and students per course count float media; //media of notes fp=fopen("example.txt","r"); if(fp==NULL){ exit(1); } else{ while(!(feof(fp))){ soma=0; media=0; max=0; min=0; count=0; fgets(linha,60,fp); if(linha[0]=='L'){ if(ap_dados=strtok(linha,";")){ strcpy(alunos[i].sigla,ap_dados);//copy to struct // i need to call bubble sort here, but i don't know how printf("College: %s\n",alunos[i].sigla); if(ap_dados=strtok(NULL,";")){ strcpy(alunos[i].numero,ap_dados);//copy to struct printf("number: %s\n",alunos[i].numero); if(ap_dados=strtok(NULL,";")){ strcpy(alunos[i].nome, ap_dados);//copy to struct printf("name: %s\n",alunos[i].nome); if(ap_dados=strtok(NULL,";")){ strcpy(alunos[i].email, ap_dados);//copy to struct printf("email: %s\n",alunos[i].email); } } } }i++; } if(isdigit(linha[0])){ if(info_notas=strtok(linha,";")){ strcpy(alunos[i].tot_not,info_notas); alunos[i].total_notas=atoi(alunos[i].tot_not);//total classes for(z=0;z<=alunos[i].total_notas;z++){ if(info_notas=strtok(NULL,";")){ strcpy(alunos[i].notas,info_notas); alunos[i].nota=atoi(alunos[i].notas); // student class notes } soma=soma + alunos[i].nota; media=soma/alunos[i].total_notas;//doesn't work if(alunos[i].nota>max){ max=alunos[i].nota;;//doesn't work } else{ if(min<alunos[i].nota){ min=alunos[i].nota;;//doesn't work } } //now i need to count the numbers of students in the same college, but doesn't work /*If(strcmp(alunos[i].sigla, alunos[i+1].sigla)=0){ count ++; printf("%d\n", count); here for LEI should appear 2 students and for LTCGM appear 1, don't work }*/ //Now i need to see if student is aproved or disaproved // Student is disaproved if he gets 3 notes under 10, how can i do that? } printf("media %d\n",media); //media printf("Nota maxima %d\n",max);// biggest note printf("Nota minima %d\n",min); //lowest note }i++; } } } fclose(fp); } int main(int argc, char *argv[]){ ALUNO alunos; FILE *fp; int tam; fp=fopen(nomeFicheiro,"r"); alunos = (ALUNO*) calloc (tam, sizeof(ALUNO)); xml(alunos,nomeFicheiro, tam); system("PAUSE"); return 0; }

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  • Alternative to FTP

    - by maria
    I need an easy to use alternative to FTP. I need to store docs and photos but clients need to be able to access easily (need to be able to both upload and download). Inexpenisve or free would be great. Help!

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  • Regex for hyperlink and hypen problem

    - by Maria
    I am trying to find links in user entered text and convert them to link automatically. I am using current Regex as following, which good to find hyperlinks from text. Regex regexResolveUrl = new Regex("((http://|www\\.)([A-Z0-9.-:]{1,})\\.[0-9A-Z?;~&#=\\-_\\./]{2,})", RegexOptions.Compiled | RegexOptions.IgnoreCase); It is working good for almost all links so far i came across but it is giving problem when i want to detect links with hypen. i.e. www.abc-xyz.com will not work, with above regex, can anyone help me with this?

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  • C programming XML

    - by Pedro
    Hello, Do you imagine that I have the following txt: /* Licenciaturas na ESTG-IPVC 2009 – v1.1*/ - Info, 3 dados, ;; - disciplinas, ;;[;] LEI;7671;Maria Albertina da silva;[email protected]; 9;8;12;9;12;11;6;15;7;11; LTCGM;6567;Artur Pereira Ribeiro;[email protected]; 6;13;14;12;11;16;14; LEI;7701;Ana Maria Carvalho;[email protected]; 8;13;11;7;14;12;11;16;14; How can I make a C program that convert txt to XML. thanks

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  • How to add a another value to a key in python

    - by Nanowatt
    First I'm sorry this might be a dumb question but I'm trying to self learn python and I can't find the answer to my question. I want to make a phonebook and I need to add an email to an already existing name. That name has already a phone number attached. I have this first code: phonebook = {} phonebook ['ana'] = '12345' phonebook ['maria']= '23456' , '[email protected]' def add_contact(): name = raw_input ("Please enter a name:") number = raw_input ("Please enter a number:") phonebook[name] = number Then I wanted to add an email to the name "ana" for example: ana: 12345, [email protected]. I created this code but instead of addend a new value (the email), it just changes the old one, removing the number: def add_email(): name = raw_input("Please enter a name:") email = raw_input("Please enter an email:") phonebook[name] = email I tried .append() too but it didn't work. Can you help me? And I'm sorry if the code is bad, I'm just trying to learn and I'm a bit noob yet :)

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  • Ajaxrequest with Wicket but multiple possilbe model values

    - by Markus Maria Miedaner
    Hi, I'm new to wicket and stuck with the following problem: I have a table with 5 rows. Each row contains 7 cells. Each cell has a unique value. Once a cell is clicked, its unqiue value should be posted to the server. I would like to register only one ajaxfallbacklink (or similar) on the table and adjust the value of the model to the unique value of cell that has been clicked. Any ideas?

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  • SelectDateWidget in Django Admin?

    - by Maria
    Can i change default AdminDateWidget to SelectDateWidget in my models? How can i do this? I try: class RespondentAdmin(admin.ModelAdmin): formfield_overrides = { models.DateField: {'widget': SelectDateWidget}, } but it doesn't work

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  • File processing-Haskell

    - by Martinas Maria
    How can I implement in haskell the following: I receive an input file from the command line. This input file contains words separated with tabs,new lines and spaces.I have two replace this elements(tabs,new lines and spaces) with comma(,) .Observation:more newlines,tabs,spaces will be replaced with a single comma.The result has to be write in a new file(output.txt). Please help me with this.My haskell skills are very scarse. This is what I have so far: processFile::String->String processFile [] =[] processFile input =input process :: String -> IO String process fileName = do text <- readFile fileName return (processFile text) main :: IO () main = do n <- process "input.txt" print n In processFile function I should process the text from the input file. I'm stuck..Please help.

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  • Using a Hash table

    - by Maria Attard
    I have 2 lists in my program one that store objects of type student and another one which stores objects of type marks. I have 3 methods one that inputs the details of the students, one that inputs the marks and one to view student details and their marks. My question is how I can use a hash table to get the Id of a student and then use it to input the marks and then how to retrieve both the student details and their marks altogether. Please help me if you can.

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  • Remove duplicates in a String [] list f#

    - by Jose Maria de la Torre
    I need some noob help... I have a String[] list (a list that each element is a Array of strings) I wish to remove all duplicates in the list. But to see if they are duplicates I need to see the fist element in the array. what I have tried is let NotDuplicated = Duplicated.[0] |> Seq.distinct let NotDuplicated = Duplicated |> Seq.distinctBy id but nothing is working... can you guys please help me.. thanks!!

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  • Constructing a tree using Python

    - by stealthspy
    I am trying to implement a unranked boolean retrieval. For this, I need to construct a tree and perform a DFS to retrieve documents. I have the leaf nodes but I am having difficulty to construct the tree. Eg: query = OR ( AND (maria sharapova) tennis) Result: OR | | AND tennis | | maria sharapova I traverse the tree using DFS and calculate the boolean equivalent of certain document ids to identify the required document from the corpus. Can someone help me with the design of this using python? I have parsed the query and retrieved the leaf nodes for now.

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  • Parner Webcast - Innovations in Products Program

    - by Richard Lefebvre
    We are pleased to invite you to join the Innovations in Products –webcast. Innovations in Products will present Oracle Applications' Product's new functions and features including sales positioning. The key objectives of these webcasts are to inspire System Integrator's implementation personnel to conduct successful after sales in their Customer projects. Innovations in Products will be presented on the 1st Monday of each quarter after the billable day (4:00 to 5:00 PM CET). The webcast is intended for System Integrator's Implementation Certified Specialists but Innovations in Products is open for other interested Oracle Applications system Integrator's personnel as well. At first, two Oracle representatives will discuss Oracle's contribution to Partners. Then you will see product breakout session followed by Q&A with Oracle Experts. Each session will last for maximum 1 hour. A Q&A document covering all questions and answers will be made available after the webcast. What are the Benefits for partners? Find out how Innovations in Products helps you to improve your after sales Discover new functions and features so you can enrich your Customers's solution Learn more about Oracle Applications products, especially sales positioning Hear crucial questions raised by colleague alike, learn from their interest Engage and present your questions to subject experts Be inspired of the richness of Oracle Application portfolio – for your and your customer’s benefit Note: Should you already be familiar with a specific Product, then choose another one. Doing so you would expand your knowledge of the overall Applications portfolio. Some presentations contain product demonstration, although these presentations are not intended to be extremely detailed technical presentations. Note: At the latter part of this email you have also 17 links into the recent Applications Products presentations and 6 links into the Public Sector Value Proposition presentations that were presented in Innovations in Industries -program. Product breakout sessions: Topics Speaker To Register Fusion Applications Technology and Extensibility: A next-generation platform that adapts to client needs. Matthew Johnson, Sr. Director, SCM Product Development, EMEA CLICK HERE Fusion Applications - Transforming your Back-Office Accounting Function: Changing how people work in back office functions to drive value add Liam Nolan, Director, ERP Product Development, EMEA CLICK HERE Fusion HCM & Talent Overview & Extensibility: A more in-depth look into a personalized HCM solution Synco Jonkeren, Vice-President HCM Product Development & Management, EMEA CLICK HERE Fusion HCM Compensation Planning: Compensate To Compete Rosie Warner, Director, HCM Sales Development CLICK HERE Enterprise PLM for the Product Value Chain: Oracle Enterprise PLM offers Industry specific solutions that cover the Product Value Chain Ulf Köster, Sales Development Leader Enterprise PLM, Oracle Western Europe CLICK HERE Oracle's Asset Management and Maintenance Solution: What you need to know to successfully implement Oracle Asset Management solutions within Oracle Installed Base Philip Carey, Asset Management and Maintenance Solution Specialist CLICK HERE For more details please visit Innovations in Products and other breakout sessions on OPN page. Delivery Format Innovations in Products –program is a series of FREE prerecorded Applications product presentations followed by Q&A. It will be delivered over the Web. Participants have the opportunity to submit questions during the web cast via chat and subject matter experts will provide verbal answers live. Innovations in Products consists of several parallel prerecorded product breakout sessions, each lasting for max. 1 hour. At first, two Oracle representatives will discuss Oracle’s contribution to Partners. Then you’ll see the product breakout sessions followed by Q&A with Oracle Experts. A Q&A document covering all questions and answers will be made available after the webcast. You can also see Innovations in Products afterwards as its content will be available online for the next 6-12 months. The next Innovations in Products web casts will be presented as follows: July 2nd 2012 October 1st 2012 January 14th 2013 April 8th 2013. Note: Depending on local network bandwidth please allow some seconds time the presentations to download. You might want to refresh your screen by pressing F5. Duration Maximum 1 hour For further information please contact me Markku Rouhiainen. Recent Innovations in Products presentations Applications Products presented on April the 2nd, 2012 Speaker To Register Fusion CRM: Effective, Efficient and Easy James Penfold , Senior Director, Applications Product Development and Product Management CLICK HERE Fusion HCM: Talent management overview performance, goals, talent review Jaime Losantos Viñolas, Director, HCM Sales Development CLICK HERE Distributed Order Management - Fusion SCM Solution Vikram K Singla, Business Development Director, Supply Chain Management Applications, UK CLICK HERE Oracle Transportation Management Dominic Regan, Senior Director Oracle Transportation Management EMEA CLICK HERE Oracle Value Chain Planning: Demantra Sales & Operation Planning and Demantra Demand Management Lionel Albert, Senior Director Value Chain Planning, EMEA CLICK HERE Oracle CX (Customer Experience) - formerly CEM: Powering Great Customer Experiences Maria Ramirez , CRM Presales Consultant, EPC CLICK HERE EPM 11.1.2.2 Overview Nicholas Cox , EMEA Sales Development Director - Enterprise Performance Management CLICK HERE Oracle Hyperion Profitability and Cost Management, 11.1.2.1 Daniela Lazar , Senior EPM Sales Consultant, EPC CLICK HERE January the 16th 2012 Speaker To Register CRM / ATG: Best-in-Class CRM & Commerce Maria Ramirez , Associate CRM Presales Consultant, EPC CLICK HERE CRM / Automate Business Rules for Maximum Efficiency with OPA (Oracle Policy Automation) Marco Nilo, Associate CRM Presales Consultant, EPC CLICK HERE CRM / InQuira Toby Baker, Principal Sales Consultant, CRM Product Specialist Team CLICK HERE EPM / Business Intelligence Foundation Suite – Sales and Product Updates Liviu Nitescu, Senior BI Sales Consultant, EPC CLICK HERE EPM / Hyperion Planning 11.1.2.1 - Sales & Product Updates Andreea Voinea, EPM Sales Consultant, EPC CLICK HERE ERP / JDE EnterpriseOne Fulfillment Management Overview Mirela Andreea Nasta , ERP Presales Consultant, EPC CLICK HERE ERP / Spotlights on iExpenses Elena Nita ,ERP Presales Consultant, EPC CLICK HERE MDM / Master Data Management Martin Boyd , Senior Director Product Strategy CLICK HERE Product break through session Fusion Applications Human Capital Management Rosie Warner , Director, HCM Sales Development CLICK HERE Recent Innovations in Industries Value Proposition presentations January the 16th 2012 Speaker To Register Process Modernisation Iemke Idsingh Public Sector Solutions Director CLICK HERE Shared Services Ann Smith Business Development Director, Shared Services CLICK HERE Strengthening Financial Discipline Whilst Delivering Cashable Savings Philippa Headley UK Sales Development Director Public Sector - EPM Solutions CLICK HERE Social Welfare Industry Solutions Christian Wernberg-Tougaard Industry Director - Social Welfare CLICK HERE Police Industry Solutions Jeff Penrose Solution Sales Director CLICK HERE Tax and Revenue Management Industry Solutions Andre van der Post Global Director - Tax Solutions and Strategy CLICK HERE  

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  • Unlock the full potential of Oracle Retail with Oracle Retail Consulting

    - by user801960
    In this video, Maria Porretta, Engagement Director, introduces Oracle Retail Consulting which supports Oracle Retail customers by unlocking the potential of the software solutions they are utilising. Oracle Retail Consulting comprises of a global team of over 300 consultants, 70 of which are EMEA based. 90% of the team have a retail background in either IT or business, ensuring true industry expertise and maximum business benefit. Oracle Retail Consulting offers two primary streams of service; design authority which looks at analysis and design to ensure a guided process through to implementation, and delivery ownership which runs throughout the implementation process. Further information is available on our website regarding Oracle Retail Consulting.

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  • Arrow ECS: VAD mit Weitblick

    - by A&C Redaktion
    Die Arrow ECS unterstützt Oracle Partner dabei, sich dauerhaft erfolgreich zu etablieren. Als Value Added Distributor, kurz VAD, für das Oracle Soft- und Hardware Portfolio bietet Arrow wertvolle Mehrwertdienstleistungen für Partner an, etwa in den Bereichen Consulting, Vertrieb und Produktmarketing. Der Vorteil: Die Partner können sich voll auf ihr Kerngeschäft konzentrieren. Wie die Zusammenarbeit genau funktioniert, erklären Martin Wilhelm, Manager Business Unit Enterprise Solutions, Herbert Varga vom Product Management und die Sales-Expertin für Oracle Produkte, Maria Keller, im Video. Arrow ECS steht für kompetente und zuverlässige Zusammenarbeit mit dem Partner und wurde bereits mehrfach zum Oracle Global Value Added Distributor des Jahres gekürt

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  • Arrow ECS: VAD mit Weitblick

    - by A&C Redaktion
    Die Arrow ECS unterstützt Oracle Partner dabei, sich dauerhaft erfolgreich zu etablieren. Als Value Added Distributor, kurz VAD, für das Oracle Soft- und Hardware Portfolio bietet Arrow wertvolle Mehrwertdienstleistungen für Partner an, etwa in den Bereichen Consulting, Vertrieb und Produktmarketing. Der Vorteil: Die Partner können sich voll auf ihr Kerngeschäft konzentrieren. Wie die Zusammenarbeit genau funktioniert, erklären Martin Wilhelm, Manager Business Unit Enterprise Solutions, Herbert Varga vom Product Management und die Sales-Expertin für Oracle Produkte, Maria Keller, im Video. Arrow ECS steht für kompetente und zuverlässige Zusammenarbeit mit dem Partner und wurde bereits mehrfach zum Oracle Global Value Added Distributor des Jahres gekürt

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  • All day optimizer event....

    - by noreply(at)blogger.com (Thomas Kyte)
    I've recently taken over some of the responsibilities of Maria Colgan (also known as the "optimizer lady") so she can move onto supporting our new In Memory Database features (note her new twitter handle for that: https://twitter.com/db_inmemory ).To that end, I have two one day Optimizer classes scheduled this year (and more to follow next year!).  The first one will be Wednesday November 20th in Northern California.  You can find details for that here: http://www.nocoug.org/ .The next one will be 5,500 miles (about 8,800 km) away in the UK - in Manchester.  That'll take place immediately following the UKOUG technical conference taking place the first week of December on December 5th.  You can see all of the details for that here: http://www.ukoug.org/events/tom-kyte-seminar-2013/I know I'll be doing one in Belgrade early next year, probably the first week in April. Stay tuned for details on that and for more to come.

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  • Catching multiple exceptions on the client is robust and easy

    - by Alexander Kuznetsov
    Maria Zakourdaev has just demonstrated that if our T-SQL throws multiple exceptions, ERROR_MESSAGE() in TRY..CATCH block will only expose one. When we handle errors in C#, we have a very easy access to all errors. The following procedure throws two exceptions: CREATE PROCEDURE dbo.ThrowsTwoExceptions AS BEGIN ; RAISERROR ( 'Error 1' , 16 , 1 ) ; RAISERROR ( 'Error 2' , 16 , 1 ) ; END ; GO EXEC dbo.ThrowsTwoExceptions ; Both exceptions are shown by SSMS: Msg 50000 , LEVEL 16 , State 1 , PROCEDURE...(read more)

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  • monkey patching time.time() in python

    - by user84584
    Hello guys, I've an application where, for testing, I need to replace the time.time() call with a specific timestamp, I've done that in the past using ruby (code available here: http://github.com/zemariamm/Back-to-Future/blob/master/back_to_future.rb ) However I do not know how to do this using Python. Any hints ? Cheers, Ze Maria

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  • Efficient method of getting all plist arrays into one array?

    - by cannyboy
    If I have a plist which is structured like this: Root Array Item 0 Dictionary City String New York People Array Item 0 String Steve Item 1 String Paul Item 2 String Fabio Item 3 String David Item 4 String Penny Item 1 Dictionary City String London People Array Item 0 String Linda Item 1 String Rachel Item 2 String Jessica Item 3 String Lou Item 2 Dictionary City String Barcelona People Array Item 0 String Edward Item 1 String Juan Item 2 String Maria Then what is the most efficient way of getting all the names of the people into one big NSArray?

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