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  • Break the object body

    - by Siddharth
    In my game, I want to break the object body creating slicing effect. After research I found that I have to use ray casting but I don't know how to use it. If some one know how to break the physics body then please provide information to me. EDIT : I don't have any logic how to do that in andengine. Only I have some link to do slicing http://www.emanueleferonato.com/2012/03/05/breaking-objects-with-box2d-the-realistic-way/ Yes I have to slice physics body into two parts. My physics body have 2d objects.

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  • How to redirect page

    - by sharun
    Hi i created one java application in which i tried to open my company's standard login page and i planned to redirect the link to open my own design page. Standard login page is displayed, instead of going to my own design page as usual its going to mail page. After sign out the mail page i'm gettting my own design page. But my need is, when i sign in the standard login page it should diplay my own design page. Is it possible? Please Help me. And this is code that i followed import java.io.IOException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.google.appengine.api.users.UserService; import com.google.appengine.api.users.UserServiceFactory; import com.google.appengine.api.users.User; public class New extends HttpServlet { /** * */ private static final long serialVersionUID = 1L; public void doPost(HttpServletRequest req, HttpServletResponse resp) throws IOException { resp.setHeader("Cache-Control", "no-store, no-cache, must-revalidate"); resp.setContentType("text/html"); UserService userService = UserServiceFactory.getUserService(); User user = userService.getCurrentUser(); if (user != null) { if(user.getEmail().equals("[email protected]")) { resp.getWriter().println("done"); resp.sendRedirect("/login.jsp"); } else { resp.getWriter().println("Hello, " + user.getNickname()+"<br>"); resp.getWriter().println("Thanks for your interest. But this application is still not available to everybody."); resp.getWriter().println("<a href="+UserServiceFactory.getUserService().createLogoutURL(userService.createLoginURL(req.getRequestURI()))+">Log out</a>"); } } else { resp.sendRedirect(userService.createLoginURL("http://mail.yyy.edu.in")); } } } Thanks in advance Regards Sharun.

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  • Web page from the terminal

    - by juanpablo
    Hi, I use snow leopard. how I can send a html page to web browser from the terminal? example: if I am in $HOME dir, where exist myPage.html, I can send this page for see in web browser with a command ? Many thanks.

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  • value was "" blank when refreshing the page manually

    - by crisgomez
    Hi, I have a problem regarding the maintaining of value when page was refresh.I assign a value into a hidden control using javascript below: function displaytab(tabID) { var tabId = document.getElementById("ctl00_MainContent_tabId"); switch (tabID) { case 1: tabId.value=1; break; case 2: tabId.value=2; break; case 3: tabId.value=3; break; default: tabId.value=0; break; } but when i refresh the page the value was ("") blank. Is there any way how to resolved this issue? or what is the best way to do this?

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  • access dropdown control from the master page to the content page using asp.net

    - by Isha Jain
    i have a master page and the content pages in the master page i have the textbox and dropdown the value in the dropdown may vary according to the content pages e.g for one content page the dropdown may contain branchname, city, address and let for other content page under same master page the dropdown may have values like Contactnumber, EmailID, ........... ......... etc..... so please help me to how can i bind that dropdown from my content page thanks.

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  • android webview returns blank page when load dynamic html page

    - by user2962555
    I am trying to click one button to load a page into a div block dynamically. To test it, I try to append a list item with text "abc" into the loaded page. However, I always get a blank page. load function works fine because if I try to load a static page, it works. Following is my main html page code. <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, initial-scale=1"> <title>LoadPageTest</title> <link rel="stylesheet" href="http://fonts.googleapis.com/css?family=Open+Sans:300,400,700"> <link rel="stylesheet" href="./css/customizedstyle.css"> <link rel="stylesheet" href="./css/themes/default/jquery.mobile-1.4.3.min.css"> <link rel="stylesheet" href="./css/jqm-demos.css"> <script src="./js/jquery.js"></script> <script scr="./js/customizedjs.js"></script> <script src="./js/jquery.mobile-1.4.3.min.js"></script> <script> $( document ).on( "pagecreate", "#demo-page", function() { $( document ).on( "swipeleft swiperight", "#demo-page", function( e ) { if ( $( ".ui-page-active" ).jqmData( "panel" ) !== "open" ) { if ( e.type === "swipeleft" ) { $( "#right-panel" ).panel( "open" ); } } }); }); </script> <style type="text/css"> body { overflow:hidden; } </style> </head> <body style= "overflow:hidden" scrolling="no"> <style type="text/css"> body { overflow:hidden; } </style> <div data-role="page" id="main-page" style= "overflow:hidden" scrolling="no"> <div role="main" class="ui-content" id ="maindiv" style= "overflow: auto"> Will load diff pages here. </div><!-- /content --> <div data-role="panel" id="left-panel" data-theme="b"> <ul data-role="listview" data-icon="false" id="menu"> <li> <a href="#" id = "btnA" data-rel="close">Go Page A <img src="./images/icona.png" class="ui-li-thumb"/> </li> <li> <a href="#" id = "btnB" data-rel="close">Go Page B <img src="./images/iconb.png" class="ui-li-thumb"/> </li> </ul> </div><!-- /panel --> <script type="text/javascript"> $("#btnA").on("click", function(){ $("#maindiv").empty(); $("#maindiv").load("pageA.html"); }); $("#btnB").on("click", function(){ $("#maindiv").empty(); $("#maindiv").load("pageB.html"); }); </script> </div><!-- /page --> </body> </html> Next is code for the page I try to load dynamically. <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, initial-scale=1"> <title>Page should be loaded</title> <link rel="stylesheet" href="http://fonts.googleapis.com/css?family=Open+Sans:300,400,700"> <link rel="stylesheet" href="./css/customizedstyle.css"> <link rel="stylesheet" href="./css/themes/default/jquery.mobile-1.4.3.min.css"> <link rel="stylesheet" href="./css/jqm-demos.css"> <script src="./js/jquery.js"></script> <script scr="./js/customizedjs.js"></script> <script src="./js/jquery.mobile-1.4.3.min.js"></script> <script> $(document).on('pagebeforeshow', function () { $('#postlist').append('<li> abc </li>'); $('#postlist').listview('refresh'); }); </script> </head> <body > <div data-role="page" id="posthome"> <div data-role = "content"> <ul data-role='listview' id = "postlist"> </ul> </div> </div> </body> </html> I doubt if it is because my javascript in the page doesn't work, cause the swipe js code in the main page seems not work either. Is that possible? I have enabled javascript in the onCreate() function of the activity file as below. protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_message); new LongRunningGetIO().execute(); mWebView = (WebView) findViewById(R.id.webview); mWebView.setWebViewClient(new AppClient()); mWebView.setVerticalScrollBarEnabled(false); mWebView.getSettings().setJavaScriptEnabled(true); mWebView.getSettings().setDomStorageEnabled(true); mWebView.loadUrl("file:///android_asset/index.html"); } I noticed there is a warning for statement to enable javascript "Using setJavaScriptEnabled can introduce XSS vulnerabilities into you application, review carefully". Will that maybe the reason? Then, I added @SuppressLint("SetJavaScriptEnabled") on top of the activity. The warning is gone, but the js code in pages seem still not work.

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  • What do I put in my Ruby (JRuby) code to break into the debugger?

    - by Daryl Spitzer
    I'm familiarizing myself with some JRuby code, and I'd like to be able to place a breakpoint in the code and run (as usual) from the command-line, having it break into the debugger when it gets to that point. Is there something I can put in my code to force JRuby to break into the debugger? I've tried running jruby -r debug foo.rb (instead of the usual jruby foo.rb), and then setting a breakpoint with b bar.py:98, and then continuing. But the debugger stops every time there's an exception, and there seem to be a lot of them before it gets to the line of code I'm interested in. I'd like to be able to put the "break-into-debugger" line(s) in my code and run jruby foo.rb and have the first place the debugger stops be at that line. (i.e. I'm looking for the Ruby/JRuby equivalent of import pdb;pdb.set_trace() in Python.)

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  • Will small random dynamic snippets break caching

    - by Saif Bechan
    I am busy writing a WordPress plugin. Now most users have cache plugins installed, they cache the pages. I know also some webservers as nginx have php caching and whatnot. There are also things like memcached. Now I have to admit I do not know exactly how they work, if anyone have some good links on how they work I would be glad. Some links where it's explained simple, not to technical. Now the question. My plugin displays different statistics on posts, they are always different, will this break the caching of the page. To take is a step further, sometimes the statistics of the post needs updating, and there is a small javascript snippet added to the page. Now will these two action result in the page not caching, or am I ok.

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  • Why make the login page to a single page application a separate page?

    - by ryanzec
    I am wondering why it seems to be popular to have the login page of a SPA be a separate page that is not page of the SPA (as in loaded and send data through ajax requests)? I only thing I can think of is security but I can't think a specific security reason. I mean the only thing that come to mind is that if your login page in part of the SPA, it sends the username/password through ajax which can be seen by such tools like firebug or web inspector however even if you send it as a normal POST request, there are other tools that can easily capture this data (like fiddler, httpscoop, etc...). Is there something I am missing?

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  • how to open HTML page stored on client machine from aspx page.

    - by shania
    Hi, I m developing asp.net application in which I m opening HTML page that is stored on client machine on that page I have a link which will open aspx page on server, On that aspx page I have a button that will open another html page stored on client machine. Since I m new to web development Plz help me and suggest me some solutions for this ASAP. Thanks....

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  • Should you disable page file with SSD?

    - by Pyrolistical
    I've been reading http://serverfault.com/questions/23621/any-benefit-or-detriment-from-removing-a-pagefile-on-an-8gb-ram-machine, and it has a lot of great information. But assuming you have more than enough ram, I think page file should be disabled on SSD to extend the life time. I know you would lose the core dump on crash, but not many people need that information. From my understand without a page file as you reach the limit of your ram that might trigger thrashing on disk. But for SSDs there is no concept of thrashing, reads are fast. What do you guys think?

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  • Dynamically created controls and the ASP.NET page lifecycle

    - by Dirk
    I'm working on an ASP.NET project in which the vast majority of the forms are generated dynamically at run time (form definitions are stored in a DB for customizability). Therefore, I have to dynamically create and add my controls to the Page every time OnLoad fires, regardless of IsPostBack. This has been working just fine and .NET takes care of managing ViewState for these controls. protected override void OnLoad(EventArgs e) { base.OnLoad(e); RenderDynamicControls() } private void RenderDynamicControls(){ //1. call service layer to retrieve form definition //2. create and add controls to page container } I have a new requirement in which if a user clicks on a given button (this button is created at design time) the page should be re-rendered in a slightly different way. So in addition to the code that executes in OnLoad (i.e. RenderDynamicControls()), I have this code: protected void MyButton_Click(object sender, EventArgs e) { RenderDynamicControlsALittleDifferently() } private void RenderDynamicControlsALittleDifferently() (){ //1. clear all controls from the page container added in RenderDynamicControls() //2. call service layer to retrieve form definition //3. create and add controls to page container } My question is, is this really the only way to accomplish what I'm after? It seems beyond hacky to effectively render the form twice simply to respond to a button click. I gather from my research that this is simply how the page-lifecycle works in ASP.NET: Namely, that OnLoad must fire on every Postback before child events are invoked. Still, it's worthwhile to check with the SO community before having to drink the kool-aid. On a related note, once I get this feature completed, I'm planning on throwing an UpdatePanel on the page to perform the page updates via Ajax. Any code/advice that make that transition easier would be much appreciated. Thanks

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  • one page filter results in new page in javascript

    - by Jake
    I have links set up on one page and the relationship between the links is a parent child relationship. (For example: Parent: All, Children: Software; Hardware) These links of course lead the user to a new page that shows the results from a table that is populated. Currently these links are all Similar destinations, but just a filter in the url. But the problem is that there is a javascript filter on the page that gives the user to choose between All, Software, or Hardware. Understand basically that if the url is still reading that there on the software page but they just filtered on the page to be Hardware that doesn't look good IMO. So what I was trying to do was make the links on the inital page all go the the exact same destination and somehow still know on the new page which link was clicked and run the javascript filter from knowing which link was clicked on that page. Is there a way to found that out from javascript? I guess a way to pass that value to the new page and retrieving it in javascript without showing it in the url so I can filter the table for the user based on that value?

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  • Rails paginate array items one-by-one instead of page-by-page

    - by hnovick
    Hi Guys, I have a group of assets, let's call them "practitioners". I'm displaying these practitioners in the header of a calendar interface. There are 7 columns to the calendar. 7 columns = 7 practitioners per view/page. Right now: if the first page shows you practitioners 1-7, when you go the next page you will see practitioners 8-15, next page 16-23, etc. etc. i am wondering how to page the practitioners so that if the first page shows you practitioners 1-7, the next page will show you practitioners 2-8, then 3-9, etc. etc. i would greatly appreciate any help you can offer. here is the rails code i am working with. best regards, harris novick # get the default sort order sort_order = RESOURCE_SORT_ORDER # if we've been given asset ids, start our list with them unless params[:asset_ids].blank? params[:asset_ids] = params[:asset_ids].values unless params[:asset_ids].is_a?(Array) sort_order = "#{params[:asset_ids].collect{|id| "service_provider_resources.id = #{id} DESC"}.join(",")}, #{sort_order}" end @asset_set = @provider.active_resources(:include => {:active_services => :latest_approved_version}).paginate( :per_page => RESOURCES_IN_DAY_VIEW, :page => params[:page], :order => sort_order )

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  • [php] Firefox refreshes page 1, even after redirection to page 2

    - by Znarkus
    Hi! This is a quite weird and annoying problem, which is reproduced with the script below. Say we have two pages: script.php and script.php?second. Page 1 creates some database entries and redirects to page 2. On page 2, the user is presented with an editor for said entries. If page 1 for some reason crashes on the first try, and prints some error message, a strange thing will happend. If we refresh page 1 (and this time it redirects fine), every consecutive refresh (of page 2) will actually refresh page 1 and again redirect to page 2. In the above example this would create new database entries for every refresh, which is the problem I want to circumvent by redirecting to page 2. <?php header('Content-type: text/plain'); session_start(); if (!isset($_GET['second'])) { $_SESSION['counter'] = isset($_SESSION['counter']) ? $_SESSION['counter'] + 1 : 1; /*$_SESSION['counter'] = 0; exit('asd');*/ header("Location: {$_SERVER['PHP_SELF']}?second", true, 303); exit; } echo "Counter: {$_SESSION['counter']}"; To try the above complete script, first run it with the commented code intact, then by enabling the commented code. I've tried 301, 302 and 303 redirections. Does someone know why this is happening?

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  • How can I replicate Google Page Speed's lossless image compression as part of my workflow?

    - by Keefer
    I love that Google's Page Speed is able to losslessly compress a lot of my images, but I'd love to make it part of my workflow, prior to uploading a site and making it live. Is there anything I can run locally to give me the same lossless compression? I currently export images from Export For Web from Photoshop, and use a little application called PNGCrusher to reduce file size of PNGs. I'd love to find a faster way though than saving out and replacing the individual images from Page Speed's results.

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  • Can a site recover by itself after dropping google page rank for 404 errors?

    - by Jeff
    Recently redid a website and changed the directory / URL structure. I did some .htaccess redirects for the main landing pages - however when reviewing web master tools received 404 errors for the rest of the changed URLs and noticed that Google dropped my site from the #1 position to around the 5th page. I corrected all the 404s by providing redirects in the .htaccess, resubmitted the site map and tested the google crawl bot. Will my page regain its rank by itself - or am I going to have to put some time into like I originally did?

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  • How do I break out of a loop in Scala?

    - by TiansHUo
    For Problem 4 of Project Euler How do I break out a loop? var largest=0 for(i<-999 to 1 by -1) { for (j<-i to 1 by -1) { val product=i*j if (largest>product) // I want to break out here else if(product.toString=product.toString.reverse) largest=largest max product } } And does anyone know how to turn nested for loops into tail recursion?

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  • AJAX get data from large HTML page as the large HTML page loads

    - by Ed
    Not entirely sure whether this has a name but basically I have a large HTML page that is generated from results in a db. So viewing the HTML page (which is a report) in a browser directly does not display all contents immediately but displays what it has and additional HTML is added as the results from the DB are retrieved... Is there a way I can make an AJAX request to this HTML page and as opposed to waiting until the whole page (report) is ready, I can start processing the response as the HTML report is loaded? Or is there another way of doing it? Atm I make my AJAX response it just sits there for a minute or two until the HTML page is complete... If context is of any use: The HTML report is generated by a Java servlet and the page making the AJAX call is a JSP page. Unfortunately I can't very easily break the report up because it is generated by BIRT (Eclipse reporting extension). Thanks in advance.

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  • OS X home, end, page up, page down movement keys and cursor focus

    - by Gerald Kaszuba
    When using the home, end, page up and page down movement keys in a text editor, the cursor stays in the same spot, even though the window has moved elsewhere. I know that you can use the option modifier to move the cursor along, but is there a way to move the cursor where your window has moved to (without using the mouse)? Another alternative would be to make these movement keys always behave as if the option modifier key is already pressed. Is this possible?

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