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  • Is there an equivalent to C++'s "friend class" in Java?

    - by Ricket
    In C++ there is a concept of a "friend", which has access to a class's private variables and functions. So if you have: class Foo { friend class Bar; private: int x; } then any instance of the class Bar can modify any Foo instance's x member, despite it being private, because Bar is a friend of Foo. Now I have a situation in Java where this functionality would come in handy. There are three classes: Database, Modifier, Viewer. The Database is just a collection of variables (like a struct). Modifier should be "friends" with Database; that is, it should be able to read and write its variables directly. But Viewer should only be able to read Database's variables. How is this best implemented? Is there a good way to enforce Viewer's read-only access of Database?

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  • How to post on my friend's Facebook Wall using koala gem??

    - by Cody
    I am trying to post a message on my friend's Facebook wall using Koala Gem in my Web Application. I am trying using the following code @user.put_wall_post("Hey, Welcome to the Web Application!!!!",{:name => "Friend's Name"} ) I have also tried replacing the name of my friend with his Facebook Id, but it is of no help... @user.put_wall_post("Hey, Welcome to the Web Application!!!!",{:name => "10001010101010"} ) But, both the above methods post the message on my wall. What am I wrong with??

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  • SQL: How to select rows from a table while ignoring the duplicate field values?

    - by Maxxon
    How to select rows from a table while ignoring the duplicate field values? Here is an example: id user_id message 1 Adam "Adam is here." 2 Peter "Hi there this is Peter." 3 Peter "I am getting sick." 4 Josh "Oh, snap. I'm on a boat!" 5 Tom "This show is great." 6 Laura "Textmate rocks." What i want to achive is to select the recently active users from my db. Let's say i want to select the 5 recently active users. The problem is, that the following script selects Peter twice. mysql_query("SELECT * FROM messages ORDER BY id DESC LIMIT 5 "); What i want is to skip the row when it gets again to Peter, and select the next result, in our case Adam. So i don't want to show my visitors that the recently active users were Laura, Tom, Josh, Peter, and Peter again. That does not make any sense, instead i want to show them this way: Laura, Tom, Josh, Peter, (skipping Peter) and Adam. Is there an SQL command i can use for this problem?

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  • TechEd Video: The Largest Code Camp In the World ?!?

    Check out this short 2 minute video chat with ASP.NET MVP, Peter Kellner. Peter is the primary coordinator for the Silicon Valley Code Camp and claims that it is the largest in the world. DevExpress is happy to sponsor this 2-day event and I hope to attend it this year in October 2010. Watch the video to learn more about the Silicon Valley Code Camp and Peter Kellner: Links mentioned in the video: Silicon Valley Code Camp Peter Kellners Blog & Twitter Thanks Peter! Drop me a line...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • TechEd Video: The Largest Code Camp In the World ?!?

    Check out this short 2 minute video chat with ASP.NET MVP, Peter Kellner. Peter is the primary coordinator for the Silicon Valley Code Camp and claims that it is the largest in the world. DevExpress is happy to sponsor this 2-day event and I hope to attend it this year in October 2010. Watch the video to learn more about the Silicon Valley Code Camp and Peter Kellner: Links mentioned in the video: Silicon Valley Code Camp Peter Kellners Blog & Twitter Thanks Peter! Drop me a line...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • What is the simplest way to send a large batch of pictures to a distant friend or colleague?

    - by Notitze
    What is the simplest way to send a large batch of pictures to a friend, colleague or to a group? I know about social sites like Picasa or Facebook but not everyone in my group has an account, nor I want to make any of the pictures public. Uploading repeated batches won't do for this and definitely sending through email won't cut it. Also Ftp solutions are just too technical. Is there just a simple tool for this?

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  • UltraSurf not working, used to work on same network (and is working fine on friend's computer on same network)

    - by Kush
    I'm using UltraSurf (10.17), it used to work fine but now its not working on my computer (Windows 7) and the window keeps showing "Connecting Server..." and after sometime, it fails to establish the connection. While, its working perfectly on the friend's computer on the same network. Any help will be appreciated. (Please note that using Proxifier would be my last option if I can't get UltraSurf working anyway).

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  • Is it still true, to make cross broswer layouts for desktop browsers using table+css is easier then

    - by metal-gear-solid
    My one of web designer friend still making sites with table but he use css very nicely and I also use css nicely but with <div> and i face cross browser problem in layout more than my friend. and i given some reason to my friend about cons of <table>. read my whole discussion with friend? I - you site will be problematic with screen reader My friend - OK, but i never got any call from any client regarding this. I - you will devote more time to make any changes in layout, if changes comes from client My friend - I don't think so, but if it is then show me how can i save time with <div>? I - your sites will not work well with search engine. My friend - it's not true. I've made many site and no problem with any site or client regarding this I - layout is old way, non w3c and non standard way. My friend - what is old and what is new, Who is W3C i don't know, What is standard? Whatever i make works in all browsers, it's enough for me and my client will not pay for standard and W3C guidelines rules I - Your site will not work in mobile browsers My friend - No problem for me, my client don't care about mobile phone I - Your sites are not accessible? My Friend - What do u mean not accessible? Whatever i make works in all browsers. my any client never asked about accessibility I - You will not get more work in future, with table? My friend - OK, no problem when clients will not accept site with table then i will learn about div based layouts in future. My questions? Is it still true, to make cross browser layouts for desktop browsers using table+css is easier then div+css? What is the benefit for developer to use DIV+CSS layout in place of <table> layouts if client would not mind if i use ?

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  • Delete corrupted folder

    - by Peter Becich
    I am trying to delete a folder in my home directory; its name is completely garbled. In Nautilus, the garbled text is followed by 'Invalid Directory.' Deleting it with Nautilus stalls; I can't type in the garbled name in the terminal. peter@io_vbox:~$ ls -lbdR * ... drwxrwxr-x 3 peter peter 4096 Jul 28 15:19 \346>\3152\357+\332)\363*\356,\253-\277+H&\266\033z\v\373\366\340\340?\314\022\274P\262\003\260?\303p\326\342\351\214\374f\016X\036r)!.\026 ... Any ideas? Running 12.04; if it's of any importance, this is running in VirtualBox on a Macbook Air. It was installed through VirtualBox. I don't have any other signs of SSD failure that I've picked up on -- referring to this question: Random files (invalid encoding) appearing in home directory Thanks

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  • I lent my 3 USB modem to a friend because her Meteor USB modem had run out of credit.

    - by oddbyte7
    I lent my 3 USB modem to a friend because her Meteor USB modem had run out of credit. The 3 modem worked on her machine fine once the driver was installed. She bought Meteor credit a couple of days later, uninstalled the 3 driver and she only now seems to get on the Meteor server, when you try IE8 or Firefox you get the message “Page could not be found”. I uninstalled the Meteor driver and reinstalled…no change. The OS is Win_7 home edition. Any help would be much appreciated. Regards to all, oddbyte7.

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  • Why do I get the error "X is not a member of Y" even though X is a friend of Y?

    - by user1232138
    I am trying to write a binary tree. Why does the following code report error C2039, "'<<' : is not a member of 'btree<T'" even though the << operator has been declared as a friend function in the btree class? #include<iostream> using namespace std; template<class T> class btree { public: friend ostream& operator<<(ostream &,T); }; template<class T> ostream& btree<T>::operator<<(ostream &o,T s) { o<<s.i<<'\t'<<s.n; return o; }

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  • Why this friend function can't access a private member of the class?

    - by Alceu Costa
    I am getting the following error when I try to access bins private member of the GHistogram class from within the extractHistogram() implementation: error: 'QVector<double> MyNamespace::GHistogram::bins' is private error: within this context Where the 'within this context' error points to the extractHistogram() implementation. Does anyone knows what's wrong with my friend function declaration? Here's the code: namespace MyNamespace{ class GHistogram { public: GHistogram(qint32 numberOfBins); qint32 getNumberOfBins(); /** * Returns the frequency of the value i. */ double getValueAt(qint32 i); friend GHistogram * Gbdi::extractHistogram(GImage *image, qint32 numberOfBins); private: QVector<double> bins; }; GHistogram * extractHistogram(GImage * image, qint32 numberOfBins); }

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  • Group by SQL with count

    - by snorlaks
    Lets say we have got rows like that: MyTable ID Name Product 1 Adam x 2 Adam y 3 Adam z 4 Peter a 5 Peter b Using query like: Select Name, Count(Product) from MyTable group by Name results will be: Adam 3 Peter 2 But I would like results like: 1 Adam x 3 2 Adam y 3 3 Adam z 3 4 Peter a 2 5 Peter b 2 I hope Ypu know what I mean Could You help me with that query, thanks for help, Bye

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  • Setting an instanced class property overwrites the property in all instances.

    - by Peter Moore
    I have two instances of a class. Setting a property in the first instance will set it for the second instance too. Why? It shouldn't. The property is not a "prototype property". Check the code below, what happens to Peter Griffin? Two objects are created and given the name "Peter Griffin" and "Roger Moore" but the alert boxes will say "Peter Moore" and "Roger Moore". What happened to Peter Griffin? var BaseClass = function(){ this.name = ""; this.data = {}; this.data.lastname = ""; } var ExtendedClass = function(){ this.setName = function(fname, lname){ this.name = fname; this.data.lastname = lname; } this.hello = function(){ alert("Full name: " + this.name + " " + this.data.lastname); } } ExtendedClass.prototype = new BaseClass(); pilot = new ExtendedClass(); driver = new ExtendedClass(); pilot.setName("Peter", "Griffin"); driver.setName("Roger", "Moore"); pilot.hello(); // Full name: Peter Moore driver.hello(); // Full name: Roger Moore

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  • SQL SERVER – Solution – User Not Able to See Any User Created Object in Tables – Security and Permissions Issue

    - by pinaldave
    There is an old quote “A Picture is Worth a Thousand Words”. I believe this quote immensely. Quite often I get phone calls that something is not working if I can help. My reaction is in most of the cases, I need to know more, send me exact error or a screenshot. Until and unless I see the error or reproduce the scenario myself I prefer not to comment. Yesterday I got a similar phone call from an old friend, where he was not sure what is going on. Here is what he said. “When I try to connect to SQL Server, it lets me connect just fine as well let me open and explore the database. I noticed that I do not see any user created instances but when my colleague attempts to connect to the server, he is able to explore the database as well see all the user created tables and other objects. Can you help me fix it? “ My immediate reaction was he was facing security and permission issue. However, to make the same recommendation I suggested that he send me a screenshot of his own SSMS and his friend’s SSMS. After carefully looking at both the screenshots, I was very confident about the issue and we were able to resolve the issue. Let us reproduce the same scenario and many there is some learning for us. Issue: User not able to see user created objects First let us see the image of my friend’s SSMS screen. (Recreated on my machine) Now let us see my friend’s colleague SSMS screen. (Recreated on my machine) You can see that my friend could not see the user tables but his colleague was able to do the same for sure. Now I believed it was a permissions issue. Further to this I asked him to send me another image where I can see the various permissions of the user in the database. My friends screen My friends colleagues screen This indeed proved that my friend did not have access to the AdventureWorks database and because of the same he was not able to access the database. He did have public access which means he will have similar rights as guest access. However, their SQL Server had followed my earlier advise on having limited access for guest access, which means he was not able to see any user created objects. My next question was to validate what kind of access my friend’s colleague had. He replied that the colleague is the admin of the server. I suggested that if my friend was suppose to have admin access to the database, he should request of having admin access to his colleague. My friend promptly asked for the same to his colleague and on following screen he added him as an admin. You can do the same using following T-SQL script as well. USE [AdventureWorks2012] GO ALTER ROLE [db_owner] ADD MEMBER [testguest] GO Once my friend was admin he was able to access all the user objects just like he was expecting. Please note, this complete exercise was done on a development server. One should not play around with security on live or production server. Security is such an issue, which should be left with only senior administrator of the server. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Security, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Making one of a group of similar form fields required in CakePHP

    - by Pickledegg
    I have a bunch of name/email fields in my form like this: data[Friend][0][name] data[Friend][1][name] data[Friend][2][name] etc. and data[Friend][0][email] data[Friend][1][email] data[Friend][2][email] etc. I have a custom validation rule on each one that checks to see if the corresponding field is filled in. Ie. if data[Friend][2][name] then data[Friend][2][email] MUST be filled in. FYI, heres what one of the two rules look like: My form validation rule: ( I have an email validation too but that's irrelevant here) 'name' => array( 'checkEmail' => array( 'rule' => 'hasEmail', 'message' => 'You must fill in the name field', 'last' => true ) ) My custom rule code: function hasEmail($data){ $name = array_values($data); $name = $name[0]; if(strlen($name) == 0){ return empty($this->data['Friend']['email']); } return true; } I need to make it so that one of the pairs should be filled in as a minimum. It can be any as long as the indexes correspond. I can't figure a way, as if I set the form rule to be required or allowEmpty false, it fails on ALL empty fields. How can I check for the existence of 1 pair and if present, carry on? Also, I need to strip out all of the remaining empty [Friend] fields, so my saveAll() doesn't save a load of empty rows, but I think I can handle that part using extract in my controller. The main problem is this validation. Thanks.

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  • Can I do this in only one query ?

    - by Paté
    Merry christmas everyone, I Know my way around SQL but I'm having a hard time figuring this one out. First here are my tables (examples) User id name friend from //userid to //userid If user 1 is friend with user 10 then you a row with 1,10. User 1 cannot be friend with user 10 if user 10 is not friend with user 1 so you have 1,10 10,1 It may look weird but I need those two rows per relations. Now I'm trying to make a query to select the users that have the most mutual friend with a given user. For example User 1 is friend with user 10,9 and 7 and user 8 is friend with 10,9 and 7 too ,I want to suggest user 1 to invite him (like facebook). I want to get like the 10 first people with the most mutual friend. The output would be like User,NumOfMutualFriends I dont know if that can be done in a single query ? Thanks in advance for any help.

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  • sip.conf configuration file - add new line to each record

    - by Flukey
    I have a sip configuration file which looks like this: [1664] username=1664 mailbox=1664@8360 host=192.168.254.3 type=friend subscribemwi=no [1679] username=1679 mailbox=1679@8360 host=192.168.254.3 type=friend subscribemwi=no [1700] username=1700 mailbox=1700@8360 host=192.168.254.3 type=friend subscribemwi=no [1701] username=1701 mailbox=1701@8360 host=192.168.254.3 type=friend subscribemwi=no For each record I need to add another line (vmxten for each record) for example the above becomes: [1664] username=1664 mailbox=1664@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1664 [1679] username=1679 mailbox=1679@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1679 [1700] username=1700 mailbox=1700@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1700 [1701] username=1701 mailbox=1701@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1701 What would you say would be the quickest way to do this? there are hundreds of records in the file, therefore modifying all of the records by hand would take a long time. Would you use Regex? Would you use sed? I'm interested to know how you would approach the problem. Thanks

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  • PHP: How to find connections between users so I can create a closed friend circle?

    - by CuSS
    Hi all, First of all, I'm not trying to create a social network, facebook is big enough! (comic) I've chosen this question as example because it fits exactly on what I'm trying to do. Imagine that I have in MySQL a users table and a user_connections table with 'friend requests'. If so, it would be something like this: Users Table: userid username 1 John 2 Amalia 3 Stewie 4 Stuart 5 Ron 6 Harry 7 Joseph 8 Tiago 9 Anselmo 10 Maria User Connections Table: userid_request userid_accepted 2 3 7 2 3 4 7 8 5 6 4 5 8 9 4 7 9 10 6 1 10 7 1 2 Now I want to find circles between friends and create a structure array and put that circle on the database (none of the arrays can include the same friends that another has already). Return Example: // First Circle of Friends Circleid => 1 CircleStructure => Array( 1 => 2, 2 => 3, 3 => 4, 4 => 5, 5 => 6, 6 => 1, ) // Second Circle of Friends Circleid => 2 CircleStructure => Array( 7 => 8, 8 => 9, 9 => 10, 10 => 7, ) I'm trying to think of an algorithm to do that, but I think it will take a lot of processing time because it would randomly search the database until it 'closes' a circle. PS: The minimum structure length of a circle is 3 connections and the limit is 100 (so the daemon doesn't search the entire database) EDIT: I've think on something like this: function browse_user($userget='random',$users_history=array()){ $user = user::get($userget); $users_history[] = $user['userid']; $connections = user::connection::getByUser($user['userid']); foreach($connections as $connection){ $userid = ($connection['userid_request']!=$user['userid']) ? $connection['userid_request'] : $connection['userid_accepted']; // Start the circle array if(in_array($userid,$users_history)) return array($user['userid'] => $userid); $res = browse_user($userid, $users_history); if($res!==false){ // Continue the circle array return $res + array($user['userid'] => $userid); } } return false; } while(true){ $res = browse_user(); // Yuppy, friend circle found! if($res!==false){ user::circle::create($res); } // Start from scratch again! } The problem with this function is that it could search the entire database without finding the biggest circle, or the best match.

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  • How to give friend access to git repository without giving command line access?

    - by Jack Humphries
    I have some git repositories running on my server and I would like to give a friend read/write access to one. That's simple: I add him as a user, give him SSH access, and change the permissions to the repository folder. Everything works fine; I'm able to clone the git repository using Xcode and change things (ssh://www.example.com/repo.git). However, I do not want him to have command line access. If I recall correctly, Github does not give command line access to those who SSH in. I'm using Snow Leopard Server. Is this more of a server issue or a git issue? Do you have any idea where to begin? Setting the user's Login Shell to none (as opposed to /bin/bash) cuts off access to everything.

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  • Where can I collaborate with my friend on source code in real time?

    - by Carson Myers
    I mean, other than a conference room :) Using google docs, I can upload any kind of file and view it with other people, watch them edit it in real time, with a live chat happening in the same window. This is awesome. How can I do the same thing with source code? I'm looking for a web application where I can upload source files that will be displayed in some kind of editor, with syntax highlighting, and allow others to view it and edit it in real time. Preferably with a live chat also, but not necessary. Does anybody know where I can find this?

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  • How can I share files from my Windows 7 machine to my friend's Ubuntu machine?

    - by ProfKaos
    I run a Windows 7 Pro SP1 laptop as my home machine, and my housemate runs an Ubuntu 12.04.1.05 desktop. We share a WLAN. I would like to make certain locations and files available for him to read and maybe write. How can I go about this? Bearing in mind I have very little recent experience with modern Linux, and Ubuntu in particular. My first idea is to share a Windows folder with my Ubuntu VM under VMWare Player, then his Ubuntu machine can connect to my Unbuntu VM, and the two can use whatever magic Ubuntu uses to achieve file sharing. This requires my Ubuntu VM to be always running though, and that may not always be possible. I have also heard that Samba may have a feature to help here, but I know nothing about that. How can I share my Windows files with my mate's Ubuntu machine, preferably with a 1 to 1 connection, i.e. rather not using shim VM's

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