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  • How do I access abstract private data from derived class without friend or 'getter' functions in C++?

    - by John
    So, I am caught up in a dilemma right now. How am I suppose to access a pure abstract base class private member variable from a derived class? I have heard from a friend that it is possible to access it through the base constructor, but he didn't explain. How is it possible? There are some inherited classes from base class. Is there any way to gain access to the private variables ? class Base_button { private: bool is_vis; Rect rButton; public: // Constructors Base_button(); Base_button( const Point &corner, double height, double width ); // Destructor virtual ~ Base_button(); // Accessors virtual void draw() const = 0; bool clicked( const Point &click ) const; bool is_visible() const; // Mutators virtual void show(); virtual void hide(); void move( const Point &loc ); }; class Button : public Base_button { private: Message mButton; public: // Constructors Button(); Button( const Point &corner, const string &label ); // Acessors virtual void draw() const; // Mutators virtual void show(); virtual void hide(); }; I want to be able access Rect and bool in the base class from the subclass

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  • org.hibernate.NonUniqueObjectException Within GWT application using hibernate through gilead

    - by molleman
    Hello Guys, i am working on a project for college that uses GWT,Hibernate and Gilead. Basically for the moment users should be able to add friends and remove them. also a user can see if his or her friends are online or not. my trouble is that when i add a friend that is already related to another friend i get this error org.hibernate.NonUniqueObjectException: a different object with the same identifier value was already associated with the session: [com.example.client.YFUser#4] i have a service class public class TestServiceImpl extends PersistentRemoteService implements TestService { this is my service class for my gwt application. my toruble is here with my implmentation class of my serivce in this method that is called when a user presses add friend button on the client-side public void addYFUserFriend(String userName){ //this retrieves the current user YFUser user = (YFUser)getSession().getAttribute(SESSION_USER); Session session = com.example.server.HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); YFUser friend = (YFUser) session.createQuery("select u FROM YFUser u where u.username = :username").setParameter("username", userName).uniqueResult(); System.out.println("user " + friend.getUsername() + " Found"); user.getFriends().add(friend); friend.getBefriended().add(user); session.update(user); session.update(friend); session.getTransaction().commit(); } a scenerio : user1 adds user2 as a friend. this works fine. then user3 adds user2 and the exeception is thrown. any ideas why and where my logic is going wrong Ok so i have changed my code, and i have removed all the getCurrentASession() calls and replaced with openSession() call which are closed at the appropiate point, now the error i am getting is com.google.gwt.user.server.rpc.UnexpectedException: Service method 'public abstract void com.example.client.TestService.addYFUserFriend(java.lang.String)' threw an unexpected exception: org.hibernate.NonUniqueResultException: query did not return a unique result: 3

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  • What Can I Do To One Of My Team Number (Good Friend As Well) Who Lost His Passion.

    - by skyflyer
    It seems this question is not program related, but there are lot of similar questions. So please bear with me! By the way, I am programmer and my team is also charging a software project. And SO is the only place which solved me lot of thorny troubles!THANK YOU GUYS! I joined my company with him years ago. At that time he was quite passionate on his job which is a front-end development. He gave us lot of useful suggestions concerning his work like design. And I believed he was a smart guy. I believe he still is smart too by the way. One years later, however, he seemed lost his passion and fooling around every day, did not care about his work any more and produced poorwork. Even worse he literally stopped learning new skills and honing his work related skills. For me it is horrible, we got to keep abreast with new technology development, otherwise we will be throw out. Since we were just coworkers, I did not care about it too much except mentioned my thoughts several times. But last month, we resembled a new group and assigned very important project. And I am the team leader, sadly! My boss gave me lot of support and expectation as well. I did a pretty good job before and I am very optimism to our future. But as a team, if my team does not work hard, we will be doomed to failure no matter how hard I work and push. In order to revitalize his passion, I tried couple of ways like talking to him about my concern and my boss's angry. I offered his new task which is quite new to him. I even persuaded my boss to give him new incentive package. But all of them knocked wall. His reaction was just he did not care. Even worse he did not want to talk about his situation. I want to be hard on him, but since we are friends and coworkers, I really can not see it will work. Even it works, I can not so quickly change my self from friend and coworker into manager. As a novice in management, I am really overwhelmed! I do not want get him fired, we are friends and I do not see him fired as my team number. What can I do? Thank you guys!

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  • Deadlock Analysis in NetBeans 8

    - by Geertjan
    Lock contention profiling is very important in multi-core environments. Lock contention occurs when a thread tries to acquire a lock while another thread is holding it, forcing it to wait. Lock contentions result in deadlocks. Multi-core environments have even more threads to deal with, causing an increased likelihood of lock contentions. In NetBeans 8, the NetBeans Profiler has new support for displaying detailed information about lock contention, i.e., the relationship between the threads that are locked. After all, whenever there's a deadlock, in any aspect of interaction, e.g., a political deadlock, it helps to be able to point to the responsible party or, at least, the order in which events happened resulting in the deadlock. As an example, let's take the handy Deadlock sample code from the Java Tutorial and look at the tools in NetBeans IDE for identifying and analyzing the code. The description of the deadlock is nice: Alphonse and Gaston are friends, and great believers in courtesy. A strict rule of courtesy is that when you bow to a friend, you must remain bowed until your friend has a chance to return the bow. Unfortunately, this rule does not account for the possibility that two friends might bow to each other at the same time. To help identify who bowed first or, at least, the order in which bowing took place, right-click the file and choose "Profile File". In the Profile Task Manager, make the choices below: When you have clicked Run, the Threads window shows the two threads are blocked, i.e., the red "Monitor" lines tell you that the related threads are blocked while trying to enter a synchronized method or block: But which thread is holding the lock? Which one is blocked by the other? The above visualization does not answer these questions. New in NetBeans 8 is that you can analyze the deadlock in the new Lock Contention window to determine which of the threads is responsible for the lock: Here is the code that simulates the lock, very slightly tweaked at the end, where I use "setName" on the threads, so that it's even easier to analyze the threads in the relevant NetBeans tools. Also, I converted the anonymous inner Runnables to lambda expressions. package org.demo; public class Deadlock { static class Friend { private final String name; public Friend(String name) { this.name = name; } public String getName() { return this.name; } public synchronized void bow(Friend bower) { System.out.format("%s: %s" + " has bowed to me!%n", this.name, bower.getName()); bower.bowBack(this); } public synchronized void bowBack(Friend bower) { System.out.format("%s: %s" + " has bowed back to me!%n", this.name, bower.getName()); } } public static void main(String[] args) { final Friend alphonse = new Friend("Alphonse"); final Friend gaston = new Friend("Gaston"); Thread t1 = new Thread(() -> { alphonse.bow(gaston); }); t1.setName("Alphonse bows to Gaston"); t1.start(); Thread t2 = new Thread(() -> { gaston.bow(alphonse); }); t2.setName("Gaston bows to Alphonse"); t2.start(); } } In the above code, it's extremely likely that both threads will block when they attempt to invoke bowBack. Neither block will ever end, because each thread is waiting for the other to exit bow. Note: As you can see, it really helps to use "Thread.setName", everywhere, wherever you're creating a Thread in your code, since the tools in the IDE become a lot more meaningful when you've defined the name of the thread because otherwise the Profiler will be forced to use thread names like "thread-5" and "thread-6", i.e., based on the order of the threads, which is kind of meaningless. (Normally, except in a simple demo scenario like the above, you're not starting the threads in the same class, so you have no idea at all what "thread-5" and "thread-6" mean because you don't know the order in which the threads were started.) Slightly more compact: Thread t1 = new Thread(() -> { alphonse.bow(gaston); },"Alphonse bows to Gaston"); t1.start(); Thread t2 = new Thread(() -> { gaston.bow(alphonse); },"Gaston bows to Alphonse"); t2.start();

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  • Inviting friends in facebook application

    - by Ahmy
    I have a facebook application that is published at facebook platform and i used facebook API to invite friends and i have succeeded in creating invitation form but the problem is that when u invite friend and send invitation and the invitation request sent to the user and the user accept it this friend appears again in the friend list that can be invited again For example : i have friend in my friend list named X and when i send invitation to him the invitation is sent and and X accept the invitation and when i try to send invitation again the friend X appears again in the list that i can select from to send invitation this means that may i send an invitation to this user (X) and he is already playing the game i need to know how to fix this problem so friends appear in the friend list (for invitation )only friends that not use the application. My application at the following link My Game application visit it and see the problem exactly after inviting friends they will appear again is this normal in any game application? thanks in advance for any reply

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  • Postfix mail server: can't connect via POP/IMAP

    - by MelkerOVan
    I've followed this guide on setting up a mail server on my dedicated server. I've been able to send mails from the php application I'm using and the linux commandline (using telnet, php, etc). The problem is that I cannot connect to the server via IMAP/POP which I've setup using Courier. I've tried using thunderbird but it complains that the username or password is wrong. I doubt it is the username/password but I don't know how to trouble shoot this. Edit: Here's the messages in mail.log: Jan 9 22:43:38 mail authdaemond: received auth request, service=imap, authtype=login Jan 9 22:43:38 mail authdaemond: authmysql: trying this module Jan 9 22:43:38 mail authdaemond: SQL query: SELECT id, crypt, "", uid, gid, home, "", "", name, "" FROM users WHERE id = '[email protected]' AND (enabled=1) Jan 9 22:43:38 mail authdaemond: password matches successfully Jan 9 22:43:38 mail authdaemond: authmysql: sysusername=<null>, sysuserid=5000, sysgroupid=5000, homedir=/var/spool/mail/virtual, [email protected], fullname=peter, maildir=<null>, quota=<null>, options=<null> Jan 9 22:43:38 mail authdaemond: authmysql: clearpasswd=<null>, passwd=6SrBcYq65l8QU Jan 9 22:43:38 mail authdaemond: Authenticated: sysusername=<null>, sysuserid=5000, sysgroupid=5000, homedir=/var/spool/mail/virtual, [email protected], fullname=peter, maildir=<null>, quota=<null>, options=<null> Jan 9 22:43:38 mail authdaemond: Authenticated: clearpasswd=peter, passwd=6SrBcYq65l8QU Jan 9 22:43:38 mail imapd: chdir Maildir: No such file or directory

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  • Mail server: can't connect via POP/IMAP

    - by MelkerOVan
    I've followed this guide on setting up a mail server on my dedicated server. I've been able to send mails from the php application I'm using and the linux commandline (using telnet, php, etc). The problem is that I cannot connect to the server via IMAP/POP which I've setup using Courier. I've tried using thunderbird but it complains that the username or password is wrong. I doubt it is the username/password but I don't know how to trouble shoot this. Edit: Here's the messages in mail.log: Jan 9 22:43:38 mail authdaemond: received auth request, service=imap, authtype=login Jan 9 22:43:38 mail authdaemond: authmysql: trying this module Jan 9 22:43:38 mail authdaemond: SQL query: SELECT id, crypt, "", uid, gid, home, "", "", name, "" FROM users WHERE id = '[email protected]' AND (enabled=1) Jan 9 22:43:38 mail authdaemond: password matches successfully Jan 9 22:43:38 mail authdaemond: authmysql: sysusername=<null>, sysuserid=5000, sysgroupid=5000, homedir=/var/spool/mail/virtual, [email protected], fullname=peter, maildir=<null>, quota=<null>, options=<null> Jan 9 22:43:38 mail authdaemond: authmysql: clearpasswd=<null>, passwd=password Jan 9 22:43:38 mail authdaemond: Authenticated: sysusername=<null>, sysuserid=5000, sysgroupid=5000, homedir=/var/spool/mail/virtual, [email protected], fullname=peter, maildir=<null>, quota=<null>, options=<null> Jan 9 22:43:38 mail authdaemond: Authenticated: clearpasswd=peter, passwd=password Jan 9 22:43:38 mail imapd: chdir Maildir: No such file or directory

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  • how do i search from php file ?

    - by Tum Bin
    Dear Friends, im totally new in php. Just learning. I got 2 Assingment with php and html. Assignment 01: I have to mansion some pplz name and all of them some friends name. and I have to print common friend if there have common friend. Bt there have a prob that I got also msg which dnt have any common friend like “Rana has 0 friends in common with Roni.” I want to stop this and how can i? Assignment 02: I made a html form to search a person from that php file. Like: when I will search for Rana php form will b open and and print : Rana have 4 friends and he has a common friend with Nandini and Mamun. when I will search for Tanmoy the page will be open and print: Tonmoy is Rana’s friend who have 4 friend and common friends with Nandini and Mamun. for this I have to use the function “post/get/request” Plz plz plzzzzzzzzzz help me! Here im posting my codes; <?php # Function: finfCommon function findCommon($current, $arr) { $cUser = $arr[$current]; unset($arr[$current]); foreach ($arr As $user => $friends) { $common = array(); $total = array(); foreach ($friends As $friend) { if (in_array($friend, $cUser)) { $common[] = $friend; } } $total = count($common); $add = ($total != 1) ? 's' : ''; $final[] = "<i>{$current} has {$total} friend{$add} in common with {$user}.</i>"; } return implode('<br />', $final); } # Array of users and friends $Friends = array( "Rana" => array("Pothik", "Zaman", "Tanmoy", "Ishita"), "Nandini" => array("Bonna", "Shakib", "Kamal", "Minhaj", "Ishita"), "Roni" => array("Akbar", "Anwar", "Khakan", "Pavel"), "Liton" => array("Mahadi", "Pavel"), "Mamun" => array("Meheli", "Tarek", "Zaman") ); # Creating the output value $output = "<ul>"; foreach ($Friends As $user => $friends) { $total = count($friends); $common = findCommon($user, $Friends); $output .= "<li><u>{$user} has {$total} friends.</u><br /><strong>Friends:</strong>"; if (is_array($friends) && !empty($friends[0])) { $output .= "<ul>"; foreach ($friends As $friend) { $output .= "<li>{$friend}</li>"; } $output .= "</ul>"; } $output .= "{$common}<br /><br /></li>"; } $output .= "</ul>"; # Printing the output value print $output; ?>

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  • ExpandoObject (dynamics) my greatest friend or my new greatest foe?

    - by WeNeedAnswers
    Yes I know that it shouldn't be abused and that C# is primariy used as a static language. But seriously folks if you could just dirty up some code, in the python style, or create some dynamic do hicky, would you? My mind is working overtime on this having spent a while loving the dynamics of python, is c# going over to the dark side through the back door? Is the argument for static typing a dead one with this obvious addition? Is the argument for less Unit testing a bit silly when we are all grown ups? Or has the addition of dynamics ruined a strongly static typed and well designed language?

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  • Rails: show some examples of code from controllers, models and views

    - by Totty
    Hy, my controller example: class FriendsController < ApplicationController before_filter :authorize, :except => [:friends] ############## ############## ## REQUESTS ## ############## ############## ################## # GET MY FRIENDS # ################## # Get my friends. def friends @friends = @my_profile.friends.paginate({:page => params[:page], :per_page => 3}) @profile = @my_profile end ################### # REMOVED FRIENDS # ################### # Get my deleted friends. def removed_friends @removed_friends = @my_profile.friends('removed_friends', params[:page]) end ################### # PENDING FRIENDS # ################### # Friend requests made by other profiles to me. def pending_friends @pending_friends = @my_profile.friends('pending_friends', params[:page]) end ############################ # REJECTED PENDING FRIENDS # ############################ # Rejected friend requests made by other profiles to me. def rejected_pending_friends @rejected_pending_friends = @my_profile.friends('rejected_pending_friends', params[:page]) end ##################### # REQUESTED FRIENDS # ##################### # The friend requests I've sent to others profiles. def requested_friends @requested_friends = @my_profile.friends('requested_friends', params[:page]) end ############################# # DELETED REQUESTED FRIENDS # ############################# # The requests I've sent to others # profiles and then canceled. def deleted_requested_friends @deleted_requested_friends = @my_profile.friends('deleted_requested_friends', params[:page]) end ############# ############# ## ACTIONS ## ############# ############# ########################## # ADD FRIENDSHIP REQUEST # ########################## # Add a friendship request. def add_friendship_request friendship = @my_profile.add_friendship_request(params[:profile_id]) render :json => friendship end ############################# # REMOVE FRIENDSHIP REQUEST # ############################# # Removes a friendship request I've done. def remove_friendship_request friendship = @my_profile.remove_friendship_request(params[:profile_id]) render :json => friendship end ###################### # PROCESS FRIENDSHIP # ###################### # Process friendship: accept or reject a friend. # This will make a new friend or # will make a new rejected pending friend. def process_friendship friendship = @my_profile.process_friendship(params[:profile_id].to_i, params[:accepted].to_i) render :json => friendship end ################### # REMOVE A FRIEND # ################### # Remove a friend from my friends by id. def remove_friend friendship = @my_profile.remove_friend(params[:profile_id]) render :json => friendship end end

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  • Binding, Prefixes and generated HTML

    - by Vman
    MVC newbie question re binders. Supposing I have two strongly typed partial actions that happen to have a model attributes with the same name, and are rendered in the same containing page i.e.: Class Friend {string Name {get; set ;} DateTime DOB {get; set ;}} Class Foe {string Name {get; set ;} string ReasonForDislike {get; set ;}} Both partials will have a line: <%= Html.TextBoxFor(model => model.Name) %> And associated controller actions: public ActionResult SaveFriend(Friend friend) public ActionResult SaveFoe(Foe foe) My problem is that both will render on my containing page with the same id (of course, bad for lots of reasons). I’m aware of the [Bind] attribute that allows me add a prefix, resulting in code: public ActionResult SaveFriend([Bind(Prefix = “friend”)] Friend friend) <%= Html.TextBox("friend.Name", Model. Name) %> //Boo, no TextBoxFor :( But this still doesn’t cut it. I can just about tolerate the loss of the strongly typed TextBoxFor helpers but I’ve yet to get clientside validation to work with prefixes: I’ve tried: <%= Html.ValidationMessage("friend.Name") %> ...and every other variant I can think of. I seem to need the model to be aware of the prefix in both directions but bind only applies when mapping the inbound request. It seems (to me) a common scenario but I’m struggling to find examples out there. What am I missing! Thanks in advance.

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  • A friend told me Python is garbage, I'm taking web design classes in the Spring and I have a textbook on C++. What should I do? [on hold]

    - by user107165
    I dont know if I should start digging into Python beforehand just to get acquanited with programming and "whet my appetite" or if I should work on the C++ book... Python definitely has more resources around town and I like the beginner friendly approach that seems to go along with every site that appeals to it. Or should I just wait for my assignments that start in 4 months? Any tips for an aspiring programmer?

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  • Is this simple XOR encrypted communication absolutely secure?

    - by user3123061
    Say Alice have 4GB USB flash memory and Peter also have 4GB USB flash memory. They once meet and save on both of memories two files named alice_to_peter.key (2GB) and peter_to_alice.key (2GB) which is randomly generated bits. Then they never meet again and communicate electronicaly. Alice also maintains variable called alice_pointer and Peter maintains variable called peter_pointer which is both initially set to zero. Then when Alice needs to send message to Peter they do: encrypted_message_to_peter[n] = message_to_peter[n] XOR alice_to_peter.key[alice_pointer + n] Where n i n-th byte of message. Then alice_pointer is attached at begining of the encrypted message and (alice_pointer + encrypted message) is sent to Peter and then alice_pointer is incremented by length of message (and for maximum security can be used part of key erased) Peter receives encrypted_message, reads alice_pointer stored at beginning of message and do this: message_to_peter[n] = encrypted_message_to_peter[n] XOR alice_to_peter.key[alice_pointer + n] And for maximum security after reading of message also erases used part of key. - EDIT: In fact this step with this simple algorithm (without integrity check and authentication) decreases security, see Paulo Ebermann post below. When Peter needs to send message to Alice they do analogical steps with peter_to_alice.key and with peter_pointer. With this trivial schema they can send for next 50 years each day 2GB / (50 * 365) = cca 115kB of encrypted data in both directions. If they need more data to send, they simple use larger memory for keys for example with today 2TB harddiscs (1TB keys) is possible to exchange next 50years 60MB/day ! (thats practicaly lots of data for example with using compression its more than hour of high quality voice communication) It Seems to me there is no way for attacker to read encrypted message without keys even if they have infinitely fast computer. because even with infinitely fast computer with brute force they get ever possible message that can fit to length of message, but this is astronomical amount of messages and attacker dont know which of them is actual message. I am right? Is this communication schema really absolutely secure? And if its secure, has this communication method its own name? (I mean XOR encryption is well-known, but whats name of this concrete practical application with use large memories at both communication sides for keys? I am humbly expecting that this application has been invented someone before me :-) ) Note: If its absolutely secure then its amazing because with today low cost large memories it is practicaly much cheeper way of secure communication than expensive quantum cryptography and with equivalent security! EDIT: I think it will be more and more practical in future with lower a lower cost of memories. It can solve secure communication forever. Today you have no certainty if someone succesfuly atack to existing ciphers one year later and make its often expensive implementations unsecure. In many cases before comunication exist step where communicating sides meets personaly, thats time to generate large keys. I think its perfect for military communication for example for communication with submarines which can have installed harddrive with large keys and military central can have harddrive for each submarine they have. It can be also practical in everyday life for example for control your bank account because when you create your account you meet with bank etc.

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  • error in auth.log but can login; LDAP/PAM

    - by Peter
    I have a server running OpenLDAP. When I start a ssh-session I can log in without problems, but an error appears in the logs. This only happens when I log in with a LDAP account (so not with a system account such as root). Any help to eliminate these errors would be much appreciated. The relevant piece from /var/log/auth.log sshd[6235]: pam_unix(sshd:auth): authentication failure; logname= uid=0 euid=0 tty=ssh ruser= rhost=example.com user=peter sshd[6235]: Accepted password for peter from 192.168.1.2 port 2441 ssh2 sshd[6235]: pam_unix(sshd:session): session opened for user peter by (uid=0) pam common-session session [default=1] pam_permit.so session required pam_unix.so session optional pam_ldap.so session required pam_mkhomedir.so skel=/etc/skel umask=0022 session required pam_limits.so session required pam_unix.so session optional pam_ldap.so pam common-auth auth [success=1 default=ignore] pam_ldap.so auth required pam_unix.so nullok_secure use_first_pass auth required pam_permit.so session required pam_mkhomedir.so skel=/etc/skel umask=0022 silent auth sufficient pam_unix.so nullok_secure use_first_pass auth requisite pam_succeed_if.so uid >= 1000 quiet auth sufficient pam_ldap.so use_first_pass auth required pam_deny.so pam common-account account [success=2 new_authtok_reqd=done default=ignore] pam_ldap.so account [success=1 default=ignore] pam_unix.so account required pam_unix.so account sufficient pam_succeed_if.so uid < 1000 quiet account [default=bad success=ok user_unknown=ignore] pam_ldap.so account required pam_permit.so account sufficient pam_ldap.so account sufficient pam_unix.so

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  • Silverlight Cream for June 21, 2011 -- #1110

    - by Dave Campbell
    In this Issue: Colin Eberhardt, Kunal Chowdhury(-2-), Peter Kuhn(-2-, -3-), Mike Gold, WindowsPhoneGeek, Nigel Sampson, Paul Sheriff, Dhananjay Kumar, and Erno de Weerd. Above the Fold: Silverlight: "Silverlight Debug Helper" Peter Kuhn3 WP7: "Metro In Motion #8 – AutoCompleteBox Reveal Animation" Colin Eberhardt Shoutouts: Check out the Top 5 from my friends at SilverlightShow from last week: SilverlightShow for June 13 - 19, 2011 From SilverlightCream.com: Metro In Motion #8 – AutoCompleteBox Reveal Animation Colin Eberhardt found yet another 'Metro In Motion' to duplicate... this one is the auto-complete effect seen in the WP7 email client... check out the video on the post! Windows Phone 7 (Mango) Tutorial - 16 - How to Create a WP7 Alarm Application? Kunal Chowdhury has a couple more of his Mango tutorials up... number 16 (!) is on creating an Alarm app using scheduled tasks. Windows Phone 7 (Mango) Tutorial - 17 - How to Create a WP7 Reminder Application? Kunal Chowdhury's latest is number 17 in the Mango series and he's discussing the Reminder class which is part of the Scheduler namespace. Silverlight Debug Helper Peter Kuhn has deployed a new version of his "Silverlight Debug Helper"... this time he's added support for FireFox and Chrome. Getting ready for the Windows Phone 7 Exam 70-599 (Part 3) Peter Kuhn also has Part 3 of his series posted at SilverlightShow on getting ready for the WP7 exam. XNA for Silverlight developers: Part 13 - Mango (2) Finally, Peter Kuhn's latest XNA for Silverlight developers tutorial is up at SilverlightShow and is the 2nd Mango post for game devs. Detecting Altitude using the WP7 Phone WindowsPhoneGeek apparently turned the reigns of his blog over to Mike Gold for this post about Altitude detection on the WP7. Windows Phone Mango: Getting Started with MVVM in 10 Minutes If you're out there and still haven't gotten your head around MVVM, or want to take another look at why you're beating yourself up doing it [ :) ]... WindowsPhoneGeek has a quick write-up on MVVM and WP7.1 apps Creating app promotional videos Nigel Sampson details how he uses Expression Encoder to produce the app videos he has on his blog for his WP7* apps. Sort Data in Windows Phone using Collection View Source Paul Sheriff's latest post is up, and is another WP7 post. This time on how to sort the data you consume by using a CollectionViewSource object in XAML and not write any code! Viewing Flickr Images on Windows 7.1 Phone or Mango Phone Dhananjay Kumar has a tutorial up for WP7.1 showing how to use the Flickr REST service to display images on your device. Windows Phone 7: Drawing graphics for your application with Inkscape – Part II: Icons Part 2 of Erno de Weerd's Trilogy on Drawing graphics for your WP7* apps in Inkscape is up... this tutorial is all about icons... good stuff! Stay in the 'Light! Twitter SilverlightNews | Twitter WynApse | WynApse.com | Tagged Posts | SilverlightCream Join me @ SilverlightCream | Phoenix Silverlight User Group Technorati Tags: Silverlight    Silverlight 3    Silverlight 4    Windows Phone MIX10

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  • Devoxx UK JCP & Adopt-a-JSR activities

    - by Heather VanCura
    Devoxx UK starts this week!  The JCP Program is organizing many activities throughout the conference, including some tables in the Hackergarten area on 12-13 June.  Topics include Java EE, Data Grids, Java SE 8 (Lambdas and Date & Time API), Money & Currency API and OpenJDK.  We will have two book signings by Richard Warburton and Peter Pilgrim during the Hackergarten - free signed copy of their books at these times - first come, first served (limited quantities available).  Thursday night is the party and the Birds of a Feather (BoF) sessions - come with your favorite questions and topics related to the JCP, Adopt-a-JSR and Adopt OpenJDK Programs!  See below for the schedule of activities; I will fill in details for each session tomorrow.    Thursday 12 June 10:20 - 12:50 Java EE -- Arun Gupta 13:30-17:00 Lambdas/Date & Time API --Richard Warburton & Raoul-Gabriel Urma (also a book signing with Richard Warburon during the afternoon break) 14:30-17:30 Data Grids - Peter Lawrey 14:30-18:00 Money & Currency -- Anatole Tresch 18:45 Adopt OpenJDK BoF session (Java EE BoF runs concurrently) 19:45 JCP & Adopt-a-JSR BoF session Friday 13 June 10:20-13:00 OpenJDK -- Mani Sarkar  10:20- 14:30 Money & Currency -- Anatole Tresch 10:20 - 13:00 Java EE -- Peter Pilgrim 13:00-13:30 Peter Pilgrim Java EE 7 Book signing sponsored by JCP @ lunch time 13:30 - 15:30 JCP.Next/JSR 364 -- Heather VanCura

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  • View Script Over SSH?

    - by user74781
    A friend, using a remote machine, ran a script that SSHed to my machine, and ran the following python script that resides on my machine: while (1): ....print "hello world" (this script simply prints 'hello world' continuously). I am now logged in to my machine. How can I see the output of the script my friend was running? if it helps, I can 'spot' the script my friend is using: me@home:~$ ps aux | grep justprint.py **friend 7494 12.8 0.3 7260 3300 ? Ss 17:24 0:06 python TEST_AREA/justprint.py** friend 7640 0.0 0.0 3320 800 pts/3 S+ 17:25 0:00 grep --color=auto just what steps should I take in order to view the "hello world" messages on my screen?

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  • iOS: game with facebook challenges

    - by nazz_areno
    I created a game for iPad and I want to challenge my facebook friends. I follow the iOS tutorial in "facebook dev docs", with the "Smash game", but it doesn't explain how to challenge a friend directly to a game. I will explain with an example: I want to start a new match and I want challenge a friend on facebook. Then I send him a request to install the app and when I detect that its app is installed I send him a request to play vs me. Then, when I finish the match I sent him my result and my friend do the same thing. But if I and my friend don't finish the match it is not possible to send another challenge. This scenario is not explained by facebook sdk. Is it necessary to use another instrument to do this situation?

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  • Delegates: A Practical Understanding

    - by samerpaul
    It's been a while since I have written on this blog, and I'm planning on reviving it this summer, since I have more time to do so again.I've also recently started working on the iPhone platform, so I haven't been as busy in .NET as before.In either case, today's blog post applies to both C# and Objective-C, because it's more about a practical understanding of delegates than it is about code. When I was learning coding, I felt like delegates was one of the hardest things to conceptually understand, and a lot of books don't really do a good job (in my opinion) of explaining it. So here's my stab at it.A Real Life Example of DelegatesLet's say there are three of you. You, your friend, and your brother. You're each in a different room in your house so you can't hear each other, even if you shout. 1)You are playing a computer game2) Friend is building a puzzle3) Brother is nappingNow, you three are going to stay in your room but you want to be informed if anything interesting is happening to the one of you. Let's say you (playing the computer game) want to know when your brother wakes up.You could keep walking to the room, checking to see if he's napping, and then walking back to your room. But that would waste a lot of time / resources, and what if you miss when he's awake before he goes back to sleep? That would be bad.Instead, you hand him a 2-way radio that works between your room and his room. And you inform him that when he wakes up, he should press a button on the radio and say "I'm awake". You are going to be listening to that radio, waiting for him to say he's awake. This, in essence, is how a delegate works.You're creating an "object" (the radio) that allows you to listen in on an event you specify. You don't want him to send any other messages to you right now, except when he wakes up. And you want to know immediately when he does, so you can go over to his room and say hi. (the methods that are called when a delegate event fires). You're also currently specifying that only you are listening on his radio.Let's say you want your friend to come into the room at the same time as you, and do something else entirely, like fluff your brother's pillow. You will then give him an identical radio, that also hooks into your brother's radio, and inform him to wait and listen for the "i'm awake" signal.Then, when your brother wakes up, he says "I'm awake!" and both you and your friend walk into the room. You say hi, and your friend fluffs the pillow, then you both exit.Later, if you decide you don't care to say hi anymore, you turn off your radio. Now, you have no idea when your brother is awake or not, because you aren't listening anymore.So again, you are each classes in this example, and each of you have your own methods. You're playing a computer game (PlayComputerGame()), your friend is building a puzzle (BuildPuzzle()) and your brother is napping (Napping()). You create a delegate (ImAwake) that you set your brother to do, when he wakes up. You listen in on that delegate (giving yourself a radio and turning it on), and when you receive the message, you fire a new method called SayHi()). Your friend is also wired up to the same delegate (using an identical radio) and fires the method FluffPillow().Hopefully this makes sense, and helps shed some light on how delegates operate. Let me know! Feel free to drop me a line at Twitter (preferred method of contact) here: samerabousalbi

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  • Tweeple some general questions about twitter

    - by Peter
    1) If I tweet to someone who is not my friend/follower does he receive my tweets? What if I select 'protect my tweets' option in my profile? 2) Can someone who is not my friend/follower send me a tweet? What if I select 'protect my tweets' option in my profile?

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  • uploading image & getting back from database

    - by Anup Prakash
    Putting a set of code which is pushing image to database and fetching back from database: <!-- <?php error_reporting(0); // Connect to database $errmsg = ""; if (! @mysql_connect("localhost","root","")) { $errmsg = "Cannot connect to database"; } @mysql_select_db("test"); $q = <<<CREATE create table image ( pid int primary key not null auto_increment, title text, imgdata longblob, friend text) CREATE; @mysql_query($q); // Insert any new image into database if (isset($_POST['submit'])) { move_uploaded_file($_FILES['imagefile']['tmp_name'],"latest.img"); $instr = fopen("latest.img","rb"); $image = addslashes(fread($instr,filesize("latest.img"))); if (strlen($instr) < 149000) { $image_query="insert into image (title, imgdata,friend) values (\"". $_REQUEST['title']. "\", \"". $image. "\",'".$_REQUEST['friend']."')"; mysql_query ($image_query) or die("query error"); } else { $errmsg = "Too large!"; } $resultbytes=''; // Find out about latest image $query = "select * from image where pid=1"; $result = @mysql_query("$query"); $resultrow = @mysql_fetch_assoc($result); $gotten = @mysql_query("select * from image order by pid desc limit 1"); if ($row = @mysql_fetch_assoc($gotten)) { $title = htmlspecialchars($row[title]); $bytes = $row[imgdata]; $resultbytes = $row[imgdata]; $friend=$row[friend]; } else { $errmsg = "There is no image in the database yet"; $title = "no database image available"; // Put up a picture of our training centre $instr = fopen("../wellimg/ctco.jpg","rb"); $bytes = fread($instr,filesize("../wellimg/ctco.jpg")); } if ($resultbytes!='') { echo $resultbytes; } } ?> <html> <head> <title>Upload an image to a database</title> </head> <body bgcolor="#FFFF66"> <form enctype="multipart/form-data" name="file_upload" method="post"> <center> <div id="image" align="center"> <h2>Heres the latest picture</h2> <font color=red><?php echo $errmsg; ?></font> <b><?php echo $title ?></center> </div> <hr> <h2>Please upload a new picture and title</h2> <table align="center"> <tr> <td>Select image to upload: </td> <td><input type="file" name="imagefile"></td> </tr> <tr> <td>Enter the title for picture: </td> <td><input type="text" name="title"></td> </tr> <tr> <td>Enter your friend's name:</td> <td><input type="text" name="friend"></td> </tr> <tr> <td><input type="submit" name="submit" value="submit"></td> <td></td> </tr> </table> </form> </body> </html> --> Above set of code has one problem. The problem is whenever i pressing the "submit" button. It is just displaying the image on a page. But it is leaving all the html codes. even any new line message after the // Printing image on browser echo $resultbytes; //************************// So, for this i put this set of code in html tag: This is other sample code: <!-- <?php error_reporting(0); // Connect to database $errmsg = ""; if (! @mysql_connect("localhost","root","")) { $errmsg = "Cannot connect to database"; } @mysql_select_db("test"); $q = <<<CREATE create table image ( pid int primary key not null auto_increment, title text, imgdata longblob, friend text) CREATE; @mysql_query($q); // Insert any new image into database if (isset($_POST['submit'])) { move_uploaded_file($_FILES['imagefile']['tmp_name'],"latest.img"); $instr = fopen("latest.img","rb"); $image = addslashes(fread($instr,filesize("latest.img"))); if (strlen($instr) < 149000) { $image_query="insert into image (title, imgdata,friend) values (\"". $_REQUEST['title']. "\", \"". $image. "\",'".$_REQUEST['friend']."')"; mysql_query ($image_query) or die("query error"); } else { $errmsg = "Too large!"; } $resultbytes=''; // Find out about latest image $query = "select * from image where pid=1"; $result = @mysql_query("$query"); $resultrow = @mysql_fetch_assoc($result); $gotten = @mysql_query("select * from image order by pid desc limit 1"); if ($row = @mysql_fetch_assoc($gotten)) { $title = htmlspecialchars($row[title]); $bytes = $row[imgdata]; $resultbytes = $row[imgdata]; $friend=$row[friend]; } else { $errmsg = "There is no image in the database yet"; $title = "no database image available"; // Put up a picture of our training centre $instr = fopen("../wellimg/ctco.jpg","rb"); $bytes = fread($instr,filesize("../wellimg/ctco.jpg")); } } ?> <html> <head> <title>Upload an image to a database</title> </head> <body bgcolor="#FFFF66"> <form enctype="multipart/form-data" name="file_upload" method="post"> <center> <div id="image" align="center"> <h2>Heres the latest picture</h2> <?php if ($resultbytes!='') { // Printing image on browser echo $resultbytes; } ?> <font color=red><?php echo $errmsg; ?></font> <b><?php echo $title ?></center> </div> <hr> <h2>Please upload a new picture and title</h2> <table align="center"> <tr> <td>Select image to upload: </td> <td><input type="file" name="imagefile"></td> </tr> <tr> <td>Enter the title for picture: </td> <td><input type="text" name="title"></td> </tr> <tr> <td>Enter your friend's name:</td> <td><input type="text" name="friend"></td> </tr> <tr> <td><input type="submit" name="submit" value="submit"></td> <td></td> </tr> </table> </form> </body> </html> --> ** But in this It is showing the image in format of special charaters and digits. 1) So, Please help me to print the image with some HTML code. So that i can print it in my form to display the image. 2) Is there any way to convert the database image into real image, so that i can store it into my hard-disk and call it from tag? Please help me.

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  • android custom dialog imageButton onclicklistener

    - by Asaf Nevo
    this is my custom dialog class: package com.WhosAround.Dialogs; import com.WhosAround.AppVariables; import com.WhosAround.R; import com.WhosAround.AsyncTasks.LoadUserStatus; import com.WhosAround.Facebook.FacebookUser; import android.app.Dialog; import android.content.Context; import android.graphics.drawable.Drawable; import android.view.MotionEvent; import android.view.View; import android.widget.ImageButton; import android.widget.ImageView; import android.widget.TextView; public class MenuFriend extends Dialog{ private FacebookUser friend; private AppVariables app; public MenuFriend(Context context, FacebookUser friend) { super(context, android.R.style.Theme_Translucent_NoTitleBar); this.app = (AppVariables) context.getApplicationContext(); this.friend = friend; } public void setDialog(String userName, Drawable userProfilePicture) { setContentView(R.layout.menu_friend); setCancelable(true); setCanceledOnTouchOutside(true); TextView name = (TextView) findViewById(R.id.menu_user_name); TextView status = (TextView) findViewById(R.id.menu_user_status); ImageView profilePicture = (ImageView) findViewById(R.id.menu_profile_picture); ImageButton closeButton = (ImageButton) findViewById(R.id.menu_close); name.setText(userName); profilePicture.setImageDrawable(userProfilePicture); if (friend.getStatus() != null) status.setText(friend.getStatus()); else new LoadUserStatus(app, friend, status).execute(0); closeButton.setOnClickListener(new OnClickListener() { @Override public void onClick(View v) { dismiss(); } }) } } for some reason eclipse tells me the following errors on closeButton imageButton: The method setOnClickListener(View.OnClickListener) in the type View is not applicable for the arguments (new DialogInterface.OnClickListener(){}) The type new DialogInterface.OnClickListener(){} must implement the inherited abstract method DialogInterface.OnClickListener.onClick(DialogInterface, int) The method onClick(View) of type new DialogInterface.OnClickListener(){} must override or implement a supertype method why is that ?

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  • Get client IP address

    - by Peter Larsson
    Up until now, I have used convuluted approaches to get the current user client IP-address. This weekend I browsed Books Online for SQL Server 2008 R2 (November CTP) and found this new cool function! SELECT  CONNECTIONPROPERTY('net_transport') AS net_transport,         CONNECTIONPROPERTY('protocol_type') AS protocol_type,         CONNECTIONPROPERTY('auth_scheme') AS auth_scheme,         CONNECTIONPROPERTY('local_net_address') AS local_net_address,         CONNECTIONPROPERTY('local_tcp_port') AS local_tcp_port,         CONNECTIONPROPERTY('client_net_address') AS client_net_address  //Peter

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  • GNU Smalltalk package

    - by Peter
    I've installed the GNU Smalltalk package and can get to the SmallTalk command line with the command 'gst'. However, I can't start the visual gst browser using the command: $ gst-browser When I try, this is what I get: peter@peredur:~$ gst-browser Object: CFunctionDescriptor new: 1 "<0x40488720>" error: Invalid C call-out gdk_colormap_get_type SystemExceptions.CInterfaceError(Smalltalk.Exception)>>signal (ExcHandling.st:254) SystemExceptions.CInterfaceError class(Smalltalk.Exception class)>>signal: (ExcHandling.st:161) Smalltalk.CFunctionDescriptor(Smalltalk.CCallable)>>callInto: (CCallable.st:165) GdkColormap class>>getType (GTK.star#VFS.ZipFile/Funcs.st:1) optimized [] in GLib class>>registerAllTypes (GTK.star#VFS.ZipFile/GtkDecl.st:78) Smalltalk.OrderedCollection>>do: (OrderColl.st:68) GLib class>>registerAllTypes (GTK.star#VFS.ZipFile/GtkDecl.st:78) Smalltalk.UndefinedObject>>executeStatements (GTK.star#VFS.ZipFile/GtkImpl.st:1078) Object: CFunctionDescriptor new: 1 "<0x404a7c28>" error: Invalid C call-out gtk_window_new SystemExceptions.CInterfaceError(Exception)>>signal (ExcHandling.st:254) SystemExceptions.CInterfaceError class(Exception class)>>signal: (ExcHandling.st:161) CFunctionDescriptor(CCallable)>>callInto: (CCallable.st:165) GTK.GtkWindow class>>new: (GTK.star#VFS.ZipFile/Funcs.st:1) VisualGST.GtkDebugger(VisualGST.GtkMainWindow)>>initialize (VisualGST.star#VFS.ZipFile/GtkMainWindow.st:131) VisualGST.GtkDebugger class(VisualGST.GtkMainWindow class)>>openSized: (VisualGST.star#VFS.ZipFile/GtkMainWindow.st:19) [] in VisualGST.GtkDebugger class>>open: (VisualGST.star#VFS.ZipFile/Debugger/GtkDebugger.st:16) [] in BlockClosure>>forkDebugger (DebugTools.star#VFS.ZipFile/DebugTools.st:380) [] in Process>>onBlock:at:suspend: (Process.st:392) BlockClosure>>on:do: (BlkClosure.st:193) [] in Process>>onBlock:at:suspend: (Process.st:393) BlockClosure>>ensure: (BlkClosure.st:269) [] in Process>>onBlock:at:suspend: (Process.st:370) [] in BlockClosure>>asContext: (BlkClosure.st:179) BlockContext class>>fromClosure:parent: (BlkContext.st:68) Everything hangs at this point until I hit ^C, after which, I get: Object: CFunctionDescriptor new: 1 "<0x404a7c28>" error: Invalid C call-out gtk_window_new SystemExceptions.CInterfaceError(Exception)>>signal (ExcHandling.st:254) SystemExceptions.CInterfaceError class(Exception class)>>signal: (ExcHandling.st:161) CFunctionDescriptor(CCallable)>>callInto: (CCallable.st:165) GTK.GtkWindow class>>new: (GTK.star#VFS.ZipFile/Funcs.st:1) VisualGST.GtkDebugger(VisualGST.GtkMainWindow)>>initialize (VisualGST.star#VFS.ZipFile/GtkMainWindow.st:131) VisualGST.GtkDebugger class(VisualGST.GtkMainWindow class)>>openSized: (VisualGST.star#VFS.ZipFile/GtkMainWindow.st:19) [] in VisualGST.GtkDebugger class>>open: (VisualGST.star#VFS.ZipFile/Debugger/GtkDebugger.st:16) [] in BlockClosure>>forkDebugger (DebugTools.star#VFS.ZipFile/DebugTools.st:380) [] in Process>>onBlock:at:suspend: (Process.st:392) BlockClosure>>on:do: (BlkClosure.st:193) [] in Process>>onBlock:at:suspend: (Process.st:393) BlockClosure>>ensure: (BlkClosure.st:269) [] in Process>>onBlock:at:suspend: (Process.st:370) [] in BlockClosure>>asContext: (BlkClosure.st:179) BlockContext class>>fromClosure:parent: (BlkContext.st:68) peter@peredur:~$ Is there a problem with this package?

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