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  • How can I solve this SAT direct corner intersection edge case?

    - by ssb
    I have a working SAT implementation, but I am running into a problem where direct collisions at a corner do not work for tiled surfaces. That is, it clips on the surface when going in a certain direction because it gets hung up on one of the tiles, and so, for example, if I walk across a floor while holding both down and left, the player will stop when meeting the next shape because the player will be colliding with the right side rather than with the top of the floor tile. This illustration shows what I mean: The top block will translate right first and then up. I have checked here and here which are helpful, but this does not address what I should do in a situation where I don't have a tile-based world. My usage of the term "tile" before isn't really accurate since what I'm doing here is manually placing square obstacles next to each other, not assigning them spots on a grid. What can I do to fix this?

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  • AABB vs OBB Collision Resolution jitter on corners

    - by patt4179
    I've implemented a collision library for a character who is an AABB and am resolving collisions between AABB vs AABB and AABB vs OBB. I wanted slopes for certain sections, so I've toyed around with using several OBBs to make one, and it's working great except for one glaring issue; The collision resolution on the corner of an OBB makes the player's AABB jitter up and down constantly. I've tried a few things I've thought of, but I just can't wrap my head around what's going on exactly. Here's a video of what's happening as well as my code: Here's the function to get the collision resolution (I'm likely not doing this the right way, so this may be where the issue lies): public Vector2 GetCollisionResolveAmount(RectangleCollisionObject resolvedObject, OrientedRectangleCollisionObject b) { Vector2 overlap = Vector2.Zero; LineSegment edge = GetOrientedRectangleEdge(b, 0); if (!SeparatingAxisForRectangle(edge, resolvedObject)) { LineSegment rEdgeA = new LineSegment(), rEdgeB = new LineSegment(); Range axisRange = new Range(), rEdgeARange = new Range(), rEdgeBRange = new Range(), rProjection = new Range(); Vector2 n = edge.PointA - edge.PointB; rEdgeA.PointA = RectangleCorner(resolvedObject, 0); rEdgeA.PointB = RectangleCorner(resolvedObject, 1); rEdgeB.PointA = RectangleCorner(resolvedObject, 2); rEdgeB.PointB = RectangleCorner(resolvedObject, 3); rEdgeARange = ProjectLineSegment(rEdgeA, n); rEdgeBRange = ProjectLineSegment(rEdgeB, n); rProjection = GetRangeHull(rEdgeARange, rEdgeBRange); axisRange = ProjectLineSegment(edge, n); float axisMid = (axisRange.Maximum + axisRange.Minimum) / 2; float projectionMid = (rProjection.Maximum + rProjection.Minimum) / 2; if (projectionMid > axisMid) { overlap.X = axisRange.Maximum - rProjection.Minimum; } else { overlap.X = rProjection.Maximum - axisRange.Minimum; overlap.X = -overlap.X; } } edge = GetOrientedRectangleEdge(b, 1); if (!SeparatingAxisForRectangle(edge, resolvedObject)) { LineSegment rEdgeA = new LineSegment(), rEdgeB = new LineSegment(); Range axisRange = new Range(), rEdgeARange = new Range(), rEdgeBRange = new Range(), rProjection = new Range(); Vector2 n = edge.PointA - edge.PointB; rEdgeA.PointA = RectangleCorner(resolvedObject, 0); rEdgeA.PointB = RectangleCorner(resolvedObject, 1); rEdgeB.PointA = RectangleCorner(resolvedObject, 2); rEdgeB.PointB = RectangleCorner(resolvedObject, 3); rEdgeARange = ProjectLineSegment(rEdgeA, n); rEdgeBRange = ProjectLineSegment(rEdgeB, n); rProjection = GetRangeHull(rEdgeARange, rEdgeBRange); axisRange = ProjectLineSegment(edge, n); float axisMid = (axisRange.Maximum + axisRange.Minimum) / 2; float projectionMid = (rProjection.Maximum + rProjection.Minimum) / 2; if (projectionMid > axisMid) { overlap.Y = axisRange.Maximum - rProjection.Minimum; overlap.Y = -overlap.Y; } else { overlap.Y = rProjection.Maximum - axisRange.Minimum; } } return overlap; } And here is what I'm doing to resolve it right now: if (collisionDetection.OrientedRectangleAndRectangleCollide(obb, player.PlayerCollision)) { var resolveAmount = collisionDetection.GetCollisionResolveAmount(player.PlayerCollision, obb); if (Math.Abs(resolveAmount.Y) < Math.Abs(resolveAmount.X)) { var roundedAmount = (float)Math.Floor(resolveAmount.Y); player.PlayerCollision._position.Y -= roundedAmount; } else if (Math.Abs(resolveAmount.Y) <= 30.0f) //Catch cases where the player should be able to step over the top of something { var roundedAmount = (float)Math.Floor(resolveAmount.Y); player.PlayerCollision._position.Y -= roundedAmount; } else { var roundedAmount = (float)Math.Floor(resolveAmount.X); player.PlayerCollision._position.X -= roundedAmount; } } Can anyone see what might be the issue here, or has anyone experienced this before that knows a possible solution? I've tried for a few days to figure this out on my own, but I'm just stumped.

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  • How can I get accurate collision resolution on the corners of rectangles?

    - by ssb
    I have a working collision system implemented, and it's based on minimum translation vectors. This works fine in most cases except when the minimum translation vector is not actually in the direction of the collision. For example: When a rectangle is on the far edge on any side of another rectangle, a force can be applied, in this example down, the pushes one rectangle into the other, particularly a static object like a wall or a floor. As in the picture, the collision is coming from above, but because it's on the very edge, it translates to the left instead of back up. I've searched for a while to find an approach but everything I can find deals with general corner collisions where my problem is only in this one limited case. Any suggestions?

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  • TGA loader: reverse y-axis

    - by aVoX
    I've written a TGA image loader in Java which is working perfectly for files created with GIMP as long as they are saved with the option origin set to Top Left (Note: Actually TGA files are meant to be stored upside down - Bottom Left in GIMP). My problem is that I want my image loader to be capable of reading all different kinds of TGA, so my question is: How do I flip the image upside down? Note that I store all image data inside a one-dimensional byte array, because OpenGL (glTexImage2D to be specific) requires it that way. Thanks in advance.

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  • Z axis trouble with glTranslatef(...) - LWJGL

    - by Zarkopafilis
    Here is the code: private static boolean up = true , down = false , left = false , right = false, reset = false, in = false , out = false; public void start() { try { Display.setDisplayMode(new DisplayMode(800,600)); Display.create(); } catch (LWJGLException e) { e.printStackTrace(); System.exit(0); } GL11.glMatrixMode(GL11.GL_PROJECTION); GL11.glLoadIdentity(); GL11.glOrtho(0, 800, 0, 600, 0.00001f, 1000); GL11.glMatrixMode(GL11.GL_MODELVIEW); Keyboard.enableRepeatEvents(true); while (!Display.isCloseRequested()) { GL11.glClear(GL11.GL_COLOR_BUFFER_BIT); input(); if(up){ GL11.glTranslatef(0,0.1f,0); } if(down){ GL11.glTranslatef(0,-0.1f,0); } if(left){ GL11.glTranslatef(-0.1f,0,0); } if(right){ GL11.glTranslatef(0.1f,0,0); } if(in){ GL11.glTranslatef(0, 0, 1f); } if(out){ GL11.glTranslatef(0, 0, -1f); } if(reset){ GL11.glLoadIdentity(); } GL11.glBegin(GL11.GL_QUADS); GL11.glColor3f(255, 255, 255); GL11.glVertex3f(800/2, 600/2, 0); GL11.glVertex3f(800/2 + 200, 600/2, 0); GL11.glVertex3f(800/2 + 200, 600/2 + 200, 0); GL11.glVertex3f(800/2, 600/2 + 200, 0); GL11.glColor3f(0, 255, 0); GL11.glVertex3f(800/2, 600/2, 1); GL11.glVertex3f(800/2 + 200, 600/2, 1); GL11.glVertex3f(800/2 + 200, 600/2 + 200, 1); GL11.glVertex3f(800/2, 600/2 + 200, 1); GL11.glEnd(); Display.update(); } Display.destroy(); } public static void main(String[] argv){ new main().start(); } public void input(){ up = false; down = false; left = false; right = false; reset = false; in = false; out = false; if(Keyboard.isKeyDown(Keyboard.KEY_SPACE)){ reset = true; } if(Keyboard.isKeyDown(Keyboard.KEY_W)){ up = true; } if(Keyboard.isKeyDown(Keyboard.KEY_S)){ down = true; } if(Keyboard.isKeyDown(Keyboard.KEY_A)){ left = true; } if(Keyboard.isKeyDown(Keyboard.KEY_D)){ right = true; } if(Keyboard.isKeyDown(Keyboard.KEY_Q)){ in = true; } if(Keyboard.isKeyDown(Keyboard.KEY_E)){ out = true; } } As you can see I am creating 2 quads , a white one at z 0 and a green one at z 1. WASD keys function correctly. Also when I hit SPACEBAR the white quad is being shown. If I then press E , I can see the green quad. But if I press Q afterwards , I dont see the white one again!(Space Works everytime). Also if I render the green one at Z = -1 everything works perfectly BUT you may need up to 3 key presses Q/E to see the other quad. Why is that happening?

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  • Why do we use the Pythagorean theorem in game physics?

    - by Starkers
    I've recently learned that we use Pythagorean theorem a lot in our physics calculations and I'm afraid I don't really get the point. Here's an example from a book to make sure an object doesn't travel faster than a MAXIMUM_VELOCITY constant in the horizontal plane: MAXIMUM_VELOCITY = <any number>; SQUARED_MAXIMUM_VELOCITY = MAXIMUM_VELOCITY * MAXIMUM_VELOCITY; function animate(){ var squared_horizontal_velocity = (x_velocity * x_velocity) + (z_velocity * z_velocity); if( squared_horizontal_velocity <= SQUARED_MAXIMUM_VELOCITY ){ scalar = squared_horizontal_velocity / SQUARED_MAXIMUM_VELOCITY; x_velocity = x_velocity / scalar; z_velocity = x_velocity / scalar; } } Let's try this with some numbers: An object is attempting to move 5 units in x and 5 units in z. It should only be able to move 5 units horizontally in total! MAXIMUM_VELOCITY = 5; SQUARED_MAXIMUM_VELOCITY = 5 * 5; SQUARED_MAXIMUM_VELOCITY = 25; function animate(){ var x_velocity = 5; var z_velocity = 5; var squared_horizontal_velocity = (x_velocity * x_velocity) + (z_velocity * z_velocity); var squared_horizontal_velocity = 5 * 5 + 5 * 5; var squared_horizontal_velocity = 25 + 25; var squared_horizontal_velocity = 50; // if( squared_horizontal_velocity <= SQUARED_MAXIMUM_VELOCITY ){ if( 50 <= 25 ){ scalar = squared_horizontal_velocity / SQUARED_MAXIMUM_VELOCITY; scalar = 50 / 25; scalar = 2.0; x_velocity = x_velocity / scalar; x_velocity = 5 / 2.0; x_velocity = 2.5; z_velocity = z_velocity / scalar; z_velocity = 5 / 2.0; z_velocity = 2.5; // new_horizontal_velocity = x_velocity + z_velocity // new_horizontal_velocity = 2.5 + 2.5 // new_horizontal_velocity = 5 } } Now this works well, but we can do the same thing without Pythagoras: MAXIMUM_VELOCITY = 5; function animate(){ var x_velocity = 5; var z_velocity = 5; var horizontal_velocity = x_velocity + z_velocity; var horizontal_velocity = 5 + 5; var horizontal_velocity = 10; // if( horizontal_velocity >= MAXIMUM_VELOCITY ){ if( 10 >= 5 ){ scalar = horizontal_velocity / MAXIMUM_VELOCITY; scalar = 10 / 5; scalar = 2.0; x_velocity = x_velocity / scalar; x_velocity = 5 / 2.0; x_velocity = 2.5; z_velocity = z_velocity / scalar; z_velocity = 5 / 2.0; z_velocity = 2.5; // new_horizontal_velocity = x_velocity + z_velocity // new_horizontal_velocity = 2.5 + 2.5 // new_horizontal_velocity = 5 } } Benefits of doing it without Pythagoras: Less lines Within those lines, it's easier to read what's going on ...and it takes less time to compute, as there are less multiplications Seems to me like computers and humans get a better deal without Pythagorean theorem! However, I'm sure I'm wrong as I've seen Pythagoras' theorem in a number of reputable places, so I'd like someone to explain me the benefit of using Pythagorean theorem to a maths newbie. Does this have anything to do with unit vectors? To me a unit vector is when we normalize a vector and turn it into a fraction. We do this by dividing the vector by a larger constant. I'm not sure what constant it is. The total size of the graph? Anyway, because it's a fraction, I take it, a unit vector is basically a graph that can fit inside a 3D grid with the x-axis running from -1 to 1, z-axis running from -1 to 1, and the y-axis running from -1 to 1. That's literally everything I know about unit vectors... not much :P And I fail to see their usefulness. Also, we're not really creating a unit vector in the above examples. Should I be determining the scalar like this: // a mathematical work-around of my own invention. There may be a cleverer way to do this! I've also made up my own terms such as 'divisive_scalar' so don't bother googling var divisive_scalar = (squared_horizontal_velocity / SQUARED_MAXIMUM_VELOCITY); var divisive_scalar = ( 50 / 25 ); var divisive_scalar = 2; var multiplicative_scalar = (divisive_scalar / (2*divisive_scalar)); var multiplicative_scalar = (2 / (2*2)); var multiplicative_scalar = (2 / 4); var multiplicative_scalar = 0.5; x_velocity = x_velocity * multiplicative_scalar x_velocity = 5 * 0.5 x_velocity = 2.5 Again, I can't see why this is better, but it's more "unit-vector-y" because the multiplicative_scalar is a unit_vector? As you can see, I use words such as "unit-vector-y" so I'm really not a maths whiz! Also aware that unit vectors might have nothing to do with Pythagorean theorem so ignore all of this if I'm barking up the wrong tree. I'm a very visual person (3D modeller and concept artist by trade!) and I find diagrams and graphs really, really helpful so as many as humanely possible please!

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  • Flex chart axis title blinking on resize

    - by Anoop
    I am having a chart with titles for horizontal and vertical axis. the verticalAxisTitleAlignment property of the vertical axis renderer is set to vertical. The application is a portal sort of thing and this chart is placed inside a small window. on click of the window am resizing the parent of the chart. but at that time the title of the axis is blinking and it provides a feeling that the resizing is not smooth. I dont understand why this happens? does the tile renders each time when the component is maximized? is there any way to stop that? Thanks in Advance, Cheers, PK This is the code am using to draw the title : <mx:horizontalAxis> <mx:LinearAxis id="haxis" title="Share" interval="5"/> </mx:horizontalAxis> <mx:verticalAxis> <mx:LinearAxis id="vaxis" title="{'Aided'+ '\n'+ ' awareness'}" interval="5"/> </mx:verticalAxis> <mx:horizontalAxisRenderers> <mx:AxisRenderer axis="{haxis}" axisStroke="{axisStroke}" tickPlacement="none"/> </mx:horizontalAxisRenderers> <mx:verticalAxisRenderers> <mx:AxisRenderer axis="{vaxis}" axisStroke="{axisStroke}" verticalAxisTitleAlignment="vertical" tickPlacement="none"/> </mx:verticalAxisRenderers>

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  • JFreeChart - Axis label positioning

    - by sardaukar
    I want the label of one of my axis to be two words, each aligned to the beginning and end of said axis - I've been doing this by inserting spaces in the Axis label, but it's a crappy solution. Is there a way to align label text for a JFreeChart chart? Thanks for any replies!

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  • Problem with y-axis in Matlab Diagram

    - by Claus
    Hi, I am drawing a simple bar diagram in Matlab. The problem is, that the value at x = 0 lets the y-axis disappear partially. Is there a way to bring the y-axis to the front instead of hiding between the y-value for x=0? Is there any option I can make sure the y-axis is always in the front? Many thanks, Claus

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  • How to rotate 3D axis(XYZ) using Yaw,Pitch,Roll angles in Opengl

    - by user3639338
    I am working Pose estimation with capturing from camera with Opencv. Now I had three angle(Yaw,Pitch,Roll) from each frame(Head) using my code.How to rotate 3D axis(XYZ) those three angle using opengl ? I draw 3D axis using opengl. I have Problem with rotate this axis for returning each frame(Head) using VideoCapture camera input from my code.I cant rotate continuously using returning three angle my code.

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  • matlab: figure size, same axis size

    - by Art
    I have a figure with fixed size, like that: hFig = figure(1); set(hFig, 'Position', [200 200 500 500]) But the thing is, that I want to have my AXIS with fixed size (i want them to be a square), not (necessary) the whole figure... - see image attached, Y axis is a bit longer than X axis (of course longer in a meaning of display... X and Y axis range is set to the same value). How to adjust it? Thanks!

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  • Y-axis in MATLAB bar plot is hidden.

    - by Claus
    I am drawing a simple bar diagram in MATLAB. The problem is, that the value at x = 0 lets the y-axis disappear partially. Is there a way to bring the y-axis to the front instead of hiding between the y-value for x=0? Is there any option I can make sure the y-axis is always in the front?

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  • Where does the tomcat axis file server-config.wsdd come from?

    - by David Sykes
    Part of our system provides a web service through apache tomcat, the service is referenced in the server-config.wsdd file. Unfortunately nobody can remember how it got in there. The apache set up has changed, and I need to update the system for the new configuration. What magic keywords can I google for to help me work out how and why it got into the existing server-config.wsdd, and how it might fit into the new server-config.wsdd

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  • Gnuplot axis scale units

    - by Kami
    I have the following data in a log file: 1270719764.323778250 926 vm-mystery1 1073744528 0 1 1270719764.323815250 926 vm-mystery1 1073746080 0 1 1270719764.323842250 926 vm-mystery1 1075968992 0 1 The first column is a UNIX date that I want to use for my x-axis in a gnuplot graph. My graph looks ugly because the first unit in the x-axis is 1.27072e+09. I would like to have the x-axis looks like the following : x axis [(first row date - first row date) ; (last row date - first row date)] displaying ticks in mili seconds. How to do this ?

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  • CorePlot - Set y-Axis range to include all data points

    - by zdestiny
    I have implemented a CorePlot graph in my iOS application, however I am unable to dynamically size the y-Axis based on the data points in the set. Some datasets range from 10-50, while others would range from 400-500. In both cases, I would like to have y-origin (0) visible. I have tried using the scaletofitplots method: [graph.defaultPlotSpace scaleToFitPlots:[graph allPlots]]; but this has no effect on the graphs, they still show the default Y-Axis range of 0 to 1. The only way that I can change the y-Axis is to do it manually via this: graph.defaultPlotSpace.yRange = [CPTPlotRange plotRangeWithLocation:CPTDecimalFromFloat(0.0f)) length:CPTDecimalFromFloat(500.0f)]; however this doesn't work well for graphs with smaller ranges (10-50), as you can imagine. Is there any method to retrieve the highest y-value from my dataset so that I can manually set the maximum y-Axis to that value? Or is there a better alternative?

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  • Transform only one axis to log10 scale with ggplot2

    - by daroczig
    I have the following problem: I would like to visualize a discrete and a continuous variable on a boxplot in which the latter has a few extreme high values. This makes the boxplot meaningless (the points and even the "body" of the chart is too small), that is why I would like to show this on a log10 scale. I am aware that I could leave out the extreme values from the visualization, but I am not intended to. Let's see a simple example with diamonds data: m <- ggplot(diamonds, aes(y = price, x = color)) The problem is not serious here, but I hope you could imagine why I would like to see the values at a log10 scale. Let's try it: m + geom_boxplot() + coord_trans(y = "log10") As you can see the y axis is log10 scaled and looks fine but there is a problem with the x axis, which makes the plot very strange. The problem do not occur with scale_log, but this is not an option for me, as I cannot use a custom formatter this way. E.g.: m + geom_boxplot() + scale_y_log10() My question: does anyone know a solution to plot the boxplot with log10 scale on y axis which labels could be freely formatted with a formatter function like in this thread? Editing the question to help answerers based on answers and comments: What I am really after: one log10 transformed axis (y) with not scientific labels. I would like to label it like dollar (formatter=dollar) or any custom format. If I try @hadley's suggestion I get the following warnings: > m + geom_boxplot() + scale_y_log10(formatter=dollar) Warning messages: 1: In max(x) : no non-missing arguments to max; returning -Inf 2: In max(x) : no non-missing arguments to max; returning -Inf 3: In max(x) : no non-missing arguments to max; returning -Inf With an unchanged y axis labels:

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  • How can I get jcifs to play nicely with apache axis

    - by Ben Hammond
    I need to connect Apache Axis 1.4 to a Webservice that uses NTLM authentication to restrict access to its operations. I'm expecting to use Samba Jcifs to handle the NTLM handshake. I found http://hc.apache.org/httpcomponents-client/ntlm.html which gives me fantastic directions for how to wire up HttpClient 4.0 with jcifs. Trouble is, Axis wants to use Http Client 3.0 and the two apis look very different. There are 2 possibilities that I can see Write an object for Axis that lets it plug into HttpClient 4. Figure out how to wire HttpClient 3.0 up with Samba Jcifs. Number 1. looks non-trivial, but possible Number 2. I cannot find any encouraging messages on the web describing how to do this. My question is: has anyone successfully connected samba jcifs with HttpClient 3.0 ? Has anyone already created an Axis HttpSender object that works with HttpClient 4 ? Is there some better alternative that I have not considered?

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  • [MATH]Project an axis to a plane

    - by Robert
    how do i project the X axis to a plane if the plane is defined by three points? see pic here: http://129.25.16.135:2080/v6.5/books/usb/graphics/iconventions-local-surfaces.png The default local 1-direction is the projection of the global x-axis onto the surface. If the global x-axis is within 0.1° of being normal to the surface, the local 1-direction is the projection of the global z-axis onto the surface. let's suppose that these points are: t1 = [-0.362879991531372, 0.357021987438202, -0.373737007379532] t2 = [-0.383525013923645, 0.371621012687683, -0.383549988269806] t3 = [-0.383534014225006, 0.34629300236702, -0.38544899225235] is the vector [0.78280971952246, -0.0307519963686645, 0.411184845614438] correct answer in this case? i've calculated the angle between the surf and x (1,0,0) is ~28°. and can you give the entire procedure for the calculation, because i'm just puzzled.

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  • Existing function to slice pandas object by axis number

    - by Zero
    Pandas has the following indexers: Object Type Indexers Series s.loc[indexer] DataFrame df.loc[row_indexer,column_indexer] Panel p.loc[item_indexer,major_indexer,minor_indexer] I would like to be able to index dynamically by axis, for example: df = pd.DataFrame(data=0, index=['row1', 'row2', 'row3'], columns=['col1', 'col2', col3']) df.index(['row1', 'row3'], axis=0) # index by rows df.index(['col1', 'col2'], axis=1) # index by columns Is there a built-in function that does this?

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  • xrandr fails when 3rd monitor has higher resolution

    - by Pi3cH
    I tried many combinations with xrandr command under lubuntu 12.04 to setup my three monitors DVI (DELL 1) left detected as HDMI1 HDMI (LG E2290) middle detected as HDMI2 VGA (DELL 2) right detected as VGA1 I can get the display with fix 1280x1024 on all the monitors. But once I setup 1280x1024 + 1920x1080 + 1280x1024, I get blank screen on all the monitors. Sometimes it throws crts fail error instead of blanking out. Anyone have similar issues? any solutions/workarounds? P.S. I can setup two monitors using 1280x1280 and 1920x1080 P.S.S. HDMI2 required at least 1920x1080 to display sharp picture. Outputs (it seems graphic card supports up to 8192x8192): xrandr Screen 0: minimum 320 x 200, current 3840 x 1024, maximum 8192 x 8192 VGA1 connected 1280x1024+2560+0 (normal left inverted right x axis y axis) 338mm x 270mm 1280x1024 60.0*+ 75.0 1152x864 75.0 1024x768 75.1 60.0 800x600 75.0 60.3 640x480 75.0 60.0 720x400 70.1 HDMI1 connected 1280x1024+0+0 (normal left inverted right x axis y axis) 376mm x 301mm 1280x1024 60.0*+ 75.0 1152x864 75.0 1024x768 75.1 60.0 800x600 75.0 60.3 640x480 75.0 60.0 720x400 70.1 HDMI2 connected 1280x1024+1280+0 (normal left inverted right x axis y axis) 477mm x 268mm 1920x1080 60.0 + 1680x1050 60.0 1280x1024 75.0 60.0* 1152x864 75.0 1024x768 75.1 60.0 800x600 75.0 60.3 640x480 75.0 60.0 720x400 70.1 DP1 disconnected (normal left inverted right x axis y axis) DP2 disconnected (normal left inverted right x axis y axis) 3 CRTs (0,1 VGA, 0,1,2 for other HDMI) xrandr --verbose VGA1 connected 1280x1024+2560+0 (0x47) normal (normal left inverted right x axis y axis) 338mm x 270mm Identifier: 0x42 Timestamp: 51324 Subpixel: unknown Gamma: 1.0:1.0:1.0 Brightness: 1.0 Clones: CRTC: 0 CRTCs: 0 1 ... HDMI1 connected 1280x1024+0+0 (0x47) normal (normal left inverted right x axis y axis) 376mm x 301mm Identifier: 0x43 Timestamp: 51324 Subpixel: unknown Gamma: 1.0:1.0:1.0 Brightness: 1.0 Clones: CRTC: 1 CRTCs: 0 1 2 ... HDMI2 connected 1280x1024+1280+0 (0x47) normal (normal left inverted right x axis y axis) 477mm x 268mm Identifier: 0x44 Timestamp: 51324 Subpixel: unknown Gamma: 1.0:1.0:1.0 Brightness: 1.0 Clones: CRTC: 2 CRTCs: 0 1 2 Below command fails: xrandr --output VGA1 --auto --output HDMI2 --auto --left-of VGA1 --output HDMI1 --auto --left-of HDMI2 Below command passes: xrandr --output VGA1 --auto --output HDMI2 --mode 1280x1024 --rate 60.0 --left-of VGA1 --output HDMI1 --auto --left-of HDMI2 Graphic card VGA compatible controller: Intel Corporation Ivy Bridge Graphics Controller (rev 09)

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  • Excel 2007: Using a time to set XY chart axis scaling like in 2003

    - by CookieOfFortune
    In Excel 2003, when you created a XY chart using time as an axis, you could set the scaling of these axes by typing in the date. In Excel 2007, you have to use the decimal version of the time (eg. How many days since some arbitrary earlier date). I was wondering if there was a way to avoid having to make such a calculation? A developer posted on a blog that this issue would be fixed in a future release, but all versions of Excel 2007 I have tried have not resolved this issue. The relevant quote: Those of you familiar with this technique of converting time to a decimal may recall that Excel 2003 allowed you to enter a date and time like “1/1/07 11:00 AM” directly in the axis option min/max fields and Excel would calculate the appropriate decimal representation. This currently does not work in Excel 2007 but will be fixed in a subsequent release.

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  • Using a time to set XY chart axis scaling like in 2003

    - by CookieOfFortune
    In Excel 2003, when you created a XY chart using time as an axis, you could set the scaling of these axes by typing in the date. In Excel 2007, you have to use the decimal version of the time (eg. How many days since some arbitrary earlier date). I was wondering if there was a way to avoid having to make such a calculation? A developer posted on a blog that this issue would be fixed in a future release, but all versions of Excel 2007 I have tried have not resolved this issue. The relevant quote: Those of you familiar with this technique of converting time to a decimal may recall that Excel 2003 allowed you to enter a date and time like “1/1/07 11:00 AM” directly in the axis option min/max fields and Excel would calculate the appropriate decimal representation. This currently does not work in Excel 2007 but will be fixed in a subsequent release.

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  • Excel axis problem

    - by itid
    I am graphing the height above sea level obtained by GPS at 12 measuring stations, which are distributed along a straight line but NOT equidistantly. Excel does a nice job of creating a suitable Y axis. But, it insists on placing the 12 stations equidistantly along the X axis. Consequently, the line graph does not represent the true cross section of the terrain. It is only true at the stations themselves. Surely there must be a way that I can enter the actual distances between the stations into a column, and get Excel to read from that column and space the values accordingly? It is such a basic mapping procedure for geologists and many others. Thanks

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