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  • Custom property editors do not work for request parameters in Spring MVC?

    - by dvd
    Hello, I'm trying to create a multiaction web controller using Spring annotations. This controller will be responsible for adding and removing user profiles and preparing reference data for the jsp page. @Controller public class ManageProfilesController { @InitBinder public void initBinder(WebDataBinder binder) { binder.registerCustomEditor(UserAccount.class,"account", new UserAccountPropertyEditor(userManager)); binder.registerCustomEditor(Profile.class, "profile", new ProfilePropertyEditor(profileManager)); logger.info("Editors registered"); } @RequestMapping("remove") public void up( @RequestParam("account") UserAccount account, @RequestParam("profile") Profile profile) { ... } @RequestMapping("") public ModelAndView defaultView(@RequestParam("account") UserAccount account) { logger.info("Default view handling"); ModelAndView mav = new ModelAndView(); logger.info(account.getLogin()); mav.addObject("account", account); mav.addObject("profiles", profileManager.getProfiles()); mav.setViewName(view); return mav; } ... } Here is the part of my webContext.xml file: <context:component-scan base-package="ru.mirea.rea.webapp.controllers" /> <context:annotation-config/> <bean class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping"> <property name="mappings"> <value> ... /home/users/manageProfiles=users.manageProfilesController </value> </property> </bean> <bean id="users.manageProfilesController" class="ru.mirea.rea.webapp.controllers.users.ManageProfilesController"> <property name="view" value="home\users\manageProfiles"/> </bean> <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter" /> However, when i open the mapped url, i get exception: java.lang.IllegalArgumentException: Cannot convert value of type [java.lang.String] to required type [ru.mirea.rea.model.UserAccount]: no matching editors or conversion strategy found I use spring 2.5.6 and plan to move to the Spring 3.0 in some not very distant future. However, according to this JIRA https://jira.springsource.org/browse/SPR-4182 it should be possible already in spring 2.5.1. The debug shows that the InitBinder method is correctly called. What am i doing wrong?

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  • Python read multiline JSON

    - by Paul W
    I have been trying to use JSON to store settings for a program. I can't seem to get Python 2.6 's JSON Decoder to decode multi-line JSON strings... Here is example input: .settings file: """ {\ 'user':'username',\ 'password':'passwd',\ }\ """ I have tried a couple other syntaxes for this file, which I will specify below (with the traceback they cause). My python code for reading the file in is import json settings_text = open(".settings", "r").read() settings = json.loads(settings_text) The Traceback for this is: Traceback (most recent call last): File "json_test.py", line 4, in <module> print json.loads(text) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/json/__init__.py", line 307, in loads return _default_decoder.decode(s) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/json/decoder.py", line 322, in decode raise ValueError(errmsg("Extra data", s, end, len(s))) ValueError: Extra data: line 1 column 2 - line 7 column 1 (char 2 - 41) I assume the "Extra data" is the triple-quote. Here are the other syntaxes I have tried for the .settings file, with their respective Tracebacks: "{\ 'user':'username',\ 'pass':'passwd'\ }" Traceback (most recent call last): File "json_test.py", line 4, in <module> print json.loads(text) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/json/__init__.py", line 307, in loads return _default_decoder.decode(s) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/json/decoder.py", line 319, in decode obj, end = self.raw_decode(s, idx=_w(s, 0).end()) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/json/decoder.py", line 336, in raw_decode obj, end = self._scanner.iterscan(s, **kw).next() File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/json/scanner.py", line 55, in iterscan rval, next_pos = action(m, context) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/json/decoder.py", line 155, in JSONString return scanstring(match.string, match.end(), encoding, strict) ValueError: Invalid \escape: line 1 column 2 (char 2) '{\ "user":"username",\ "pass":"passwd",\ }' Traceback (most recent call last): File "json_test.py", line 4, in <module> print json.loads(text) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/json/__init__.py", line 307, in loads return _default_decoder.decode(s) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/json/decoder.py", line 319, in decode obj, end = self.raw_decode(s, idx=_w(s, 0).end()) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/json/decoder.py", line 338, in raw_decode raise ValueError("No JSON object could be decoded") ValueError: No JSON object could be decoded If I put the settings all on one line, it decodes fine.

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  • Json.Net CustomSerialization

    - by BonyT
    I am serializing a collection of objects that contains a dictionary called dynamic properties. The default Json emitted looks like this: [{"dynamicProperties":{"WatchId":7771,"Issues":0,"WatchType":"x","Location":"Equinix Source","Name":"PI_5570_5580"}}, {"dynamicProperties":{"WatchId":7769,"Issues":0,"WatchType":"x","Location":"Equinix Source","Name":"PI_5570_5574"}}, {"dynamicProperties":{"WatchId":7767,"Issues":0,"WatchType":"x","Location":"Equinix Source","Name":"PI_5570_5572"}}, {"dynamicProperties":{"WatchId":7765,"Issues":0,"WatchType":"y","Location":"Equinix Source","Name":"highlight_SM"}}, {"dynamicProperties":{"WatchId":8432,"Issues":0,"WatchType":"y","Location":"Test Devices","Name":"Cisco1700PI"}}] I'd like to produce Json that looks like this: [{"WatchId":7771,"Issues":0,"WatchType":"x","Location":"Equinix Source","Name":"PI_5570_5580"}, {"WatchId":7769,"Issues":0,"WatchType":"x","Location":"Equinix Source","Name":"PI_5570_5574"}, {"WatchId":7767,"Issues":0,"WatchType":"x","Location":"Equinix Source","Name":"PI_5570_5572"}, {"WatchId":7765,"Issues":0,"WatchType":"y","Location":"Equinix Source","Name":"highlight_SM"}, {"WatchId":8432,"Issues":0,"WatchType":"y","Location":"Test Devices","Name":"Cisco1700PI"}] From reading the Json.Net documentation it looks like I could build a CustomContractResolver for my class, but I cannot find any details on how to go about this... Can anyone shed any light on the direction I should be looking in?

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  • Spring import runs hibernate persistence twice

    - by Jaanus
    I have 2 spring configurations : spring-servlet.xml spring-security.xml needed to add this line to security: <beans:import resource="spring-servlet.xml"/> Now hibernate is ran twice, this is log screenshot : my web.xml: <servlet> <servlet-name>spring</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>spring</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> <listener> <listener-class> org.springframework.web.context.ContextLoaderListener </listener-class> </listener> <context-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/spring-security.xml </param-value> </context-param>

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  • Struts or Spring MVC or Struts & Spring?

    - by Shaw
    I need some information to understand design decision: Is Struts a better choice than Spring MVC? I hear about Strus-Spring-Hibernae combo - Is struts used at MVC layer because its a matured framework than when compared to Spring MVC? Any one used this combination for projects or aware of issues?

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  • Spring security oauth2 provider to secure non-spring api

    - by user1241320
    I'm trying to set up an oauth 2.0 provider that should "secure" our restful api using spring-security-oauth. Being a 'spring fan' i thought it could be the quicker solution. main point is this restful thingie is not a spring based webapp. boss says the oauth provider should be a separate application, but i'm starting to doubt that. (got this impression by reading spring-security-oauth) i'm also new here so haven't really got my hands into this other (jersey-powered) restul api (core of our business). any help/hint will be much appreciated.

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  • Logging in JSON Effect on Performance

    - by Pius
    I see more and more articles about logging in JSON. You can also find one on NodeJS blog. Why does everyone like it so much? I can only see more operations getting involved: A couple new objects being created. Stringifying objects, which either involves calculating string length or multiple string allocations. GCing all the crap that was created. Is there any test on performance when using JSON logging and regular string logging? Do people use JSON (for logging) in enterprise projects?

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  • JSON encoding on RTL languages

    - by Lev
    Hi, I'm using JSON to integrate open flash chart to my web page. When I have a Right to Left language string which contains more the one word the JSON encodes it backwards (For example: "Hello world" is encoded as "world hello"). The string is extracted from a database, there for can be of any language. How do I force the correct encoding of Right to Left language without ruining other languages? Thanks

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  • Is JSON.stringify() reliable for serializing JSON objects?

    - by Colin
    I need to send full objects from Javascript to PHP. It seemed pretty obvious to do JSON.stringify() and then json_decode() on the PHP end, but will this allow for strings with ":" and ","? Do I need to run an escape() function on big user input strings that may cause an issue? What would that escape function be? I don't think escape works for my purposes. Are there any downsides to JSON.stringify() I need to know about? Thanks

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  • JSON Rpc libraries for use with .NET

    - by Deeptechtons
    I am looking into JSON RPC libraries for .net that are free to use in commercial applications. Up until now i just seem to have found JROCK. What other libraries, architecture have i got similar to JRock for .NET 2.0 What is the difference between a [WebMethod] in asmx web-service returning a instance of a class and a JSON Rpc method as in the JRock website page. Do i have any usability benefits, performance benefits or any benefits of using one over the other

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  • Upgrading dojo in Spring-js from 1.3 to 1.4

    - by peirix
    We have a project where we're using Spring-js. With it comes Spring-dojo and the full dojo package. But in the current version of Spring-js (2.0.9), it's using dojo 1.3. Is there a way to upgrade manually to dojo 1.4? Or even a new Spring-js.jar-file that can be donwloaded that uses dojo 1.4?

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  • What's wrong with my JSON?

    - by Ronald
    Anybody out there notice anything wrong with this JSON? It validates at JSONLint.com, but neither Chrome nor Firefox's native JSON parse functions will properly parse it. Any ideas? { "result": "{\"players\":[{\"name\":\"User 522\",\"turn\":true,\"score\":0},{\"name\":\"User 925\",\"turn\":false,\"score\":5}],\"enableControls\":false}", "error": "null", "id": "7" }

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  • JSON parsing using JSON.net

    - by vbNewbie
    I am accessing the facebook api and using the json.net library (newtonsoft.json.net) I declare a Jobject to parse the content and look for the specific elements and get their values. Everything works fine for the first few but then I get this unexplained nullexception error " (Object reference not set to an instance of an object) Now I took a look at the declaration but cannot see how to change it. Any help appreciated: Dim jobj as JObject = JObject.Parse(responseData) Dim message as string = string.empty message = jobj("message").tostring The error occurs at the last line above.

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  • Spring 3 learning curve

    - by Lucian Enache
    I'm coming from a Struts background and I was considering learning the Spring framework. How long would it usually take to get familiarity with Spring Core and Spring MVC modules, keeping in mind that I come from a Struts 1 background ? Beside those two modules are there any other modules that I should focus on ? I know that the time is relative given that everyone has a different learning curve.

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  • Long polling using Spring MVC 3.2M1

    - by Dangling Piyush
    I want to implement Long polling Using Spring 3.2 DeferredResult. I got only this tutorial available on internet Long Polling with Spring MVC. It's a good tutorial but I could not understand it fully because I am pretty new to Spring MVC. So if anyone could explain me how to use DeferredResult for implenting long polling efficiently (server-side code) I would be grateful. I have posted this question before on Stack Overflow but got zero response so I thought of reposting it here again.

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  • How can I return json from my WCF rest service (.NET 4), using Json.Net, without it being a string,

    - by Samuel Meacham
    The DataContractJsonSerializer is unable to handle many scenarios that Json.Net handles just fine when properly configured (specifically, cycles). A service method can either return a specific object type (in this case a DTO), in which case the DataContractJsonSerializer will be used, or I can have the method return a string, and do the serialization myself with Json.Net. The problem is that when I return a json string as opposed to an object, the json that is sent to the client is wrapped in quotes. Using DataContractJsonSerializer, returning a specific object type, the response is: {"Message":"Hello World"} Using Json.Net to return a json string, the response is: "{\"Message\":\"Hello World\"}" I do not want to have to eval() or JSON.parse() the result on the client, which is what I would have to do if the json comes back as a string, wrapped in quotes. I realize that the behavior is correct; it's just not what I want/need. I need the raw json; the behavior when the service method's return type is an object, not a string. So, how can I have my method return an object type, but not use the DataContractJsonSerializer? How can I tell it to use the Json.Net serializer instead? Or, is there someway to directly write to the response stream? So I can just return the raw json myself? Without the wrapping quotes? Here is my contrived example, for reference: [DataContract] public class SimpleMessage { [DataMember] public string Message { get; set; } } [ServiceContract] [AspNetCompatibilityRequirements(RequirementsMode = AspNetCompatibilityRequirementsMode.Allowed)] [ServiceBehavior(InstanceContextMode = InstanceContextMode.Single)] public class PersonService { // uses DataContractJsonSerializer // returns {"Message":"Hello World"} [WebGet(UriTemplate = "helloObject")] public SimpleMessage SayHelloObject() { return new SimpleMessage("Hello World"); } // uses Json.Net serialization, to return a json string // returns "{\"Message\":\"Hello World\"}" [WebGet(UriTemplate = "helloString")] public string SayHelloString() { SimpleMessage message = new SimpleMessage() { Message = "Hello World" }; string json = JsonConvert.Serialize(message); return json; } // I need a mix of the two. Return an object type, but use the Json.Net serializer. }

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  • Deserialize json with json.net c#

    - by 76mel
    Hi, am new to Json so a little green. I have a Rest Based Service that returns a json string; {"treeNode":[{"id":"U-2905","pid":"R","userId":"2905"}, {"id":"U-2905","pid":"R","userId":"2905"}]} I have been playing with the Json.net and trying to Deserialize the string into Objects etc. I wrote an extention method to help. public static T DeserializeFromJSON<T>(this Stream jsonStream, Type objectType) { T result; using (StreamReader reader = new StreamReader(jsonStream)) { JsonSerializer serializer = new JsonSerializer(); try { result = (T)serializer.Deserialize(reader, objectType); } catch (Exception e) { throw; } } return result; } I was expecting an array of treeNode[] objects. But its seems that I can only deserialize correctly if treeNode[] property of another object. public class treeNode { public string id { get; set; } public string pid { get; set; } public string userId { get; set; } } I there a way to to just get an straight array from the deserialization ? Cheers

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  • Create JSON From C# using json Library

    Create JSON From C# using json library available at codeplex...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Mapping to a JSON method with url-pattern

    - by Brian
    I'm creating a Spring MVC application that will have a controller with 'RequestMapping'-annotated methods, including a JSON method. It currently has static content that resides in webapps/static, and the app itself resides in webapps/myapp. I assume that Catalina's default servlet is handling the static content, and my *.htm url-pattern in web.xml is returning the request for my JSP page, but I haven't been able to get the JSON method to be called. How do I write the url-pattern in the servlet mapping to do so? Using /* has not worked; it prevents the app from being accessed at all. Is there anything else to be aware of? EDIT: The url-pattern '/' appears to allow the JSON request through, because a 406 error is returned. What then would need to be modified to allow JSON to be returned?

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  • Json.NET - How to serialize a class using custom resolver

    - by Mendy
    I want to serialize this class: public class CarDisplay { public string Name { get; set; } public string Brand { get; set; } public string Year { get; set; } public PictureDisplay[] Pictures { get; set; } } public class PictureDisplay { public int Id { get; set; } public string SecretKey { get; set; } public string AltText { get; set; } } To this Json test: { Name: "Name value", Brand: "Brand value", Year: "Year value", Pictures: ["url1", "url2", "url3"] } Note that each Car have an pictures array with only url string, instead of all the properties that Picture class have. I know that Json.NET have the notion of Custom Resolver, but I don't sure exactly how to use it.

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  • Returning control codes as JSON to a jquery ajax json call

    - by Graham
    I want to know if it is possible to return ascii control codes in JSON format from classic ASP to a jQuery ajax call. This is my jQuery call: $.ajax({ url: "/jsontest.asp", type: "POST", cache: false, dataType: "json", complete: function(data) { var o = $.parseJSON(data.responseText.toString()); }, error: function(data1, data2) { alert("There has been an error - please try again"); } }); This is my called page: {"val1":123,"val2","abcdef"} The above works fine, but if I change my called page to include ascii character 31 (1F) like so: {"val1":123,"val2","abc\x1Fdef"} then I get the alert in my error function. Can this be done, and if so, how please. Note: I'm using jQuery 1.7.1 and both IIS 6 and IIS 7 I have tried: \x1f, %1f, and \u001f

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