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  • Spring noHandlerFound

    - by Justin
    I am trying to set up my Spring MVC testing environment. But I always get this noHandlerFound error: Aug 21, 2014 4:43:25 PM org.springframework.web.servlet.DispatcherServlet noHandlerFound WARNING: No mapping found for HTTP request with URI [/restful/firstPage] in DispatcherServlet with name 'spring' Aug 21, 2014 4:47:21 PM org.springframework.web.servlet.DispatcherServlet noHandlerFound WARNING: No mapping found for HTTP request with URI [/restful/firstPage2] in DispatcherServlet with name 'spring' Aug 21, 2014 5:10:27 PM org.springframework.web.servlet.DispatcherServlet noHandlerFound WARNING: No mapping found for HTTP request with URI [/restful/index.html] in DispatcherServlet with name 'spring' I already searched for solution, but none can fix my problem. My spring mvc version: 3.1.3.RELEASE This is my web.xml: <servlet> <servlet-name>spring</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>spring</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> <context-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/applicationContext.xml </param-value> </context-param> this is my spring-servlet.xml: <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver" p:prefix="/WEB-INF/jsp/" p:suffix=".jsp" /> this is my applicationContext.xml: <context:annotation-config /> <context:component-scan base-package="test.spring" /> <mvc:annotation-driven /> <mvc:resources mapping="/index.html" location="/index.html" /> <mvc:view-controller path="/firstPage" /> This is my Controller: package test.spring; .... @Controller @RequestMapping("/") public class FirstController { @RequestMapping(value = "firstPage2", method = RequestMethod.GET) public String showFirstPage(Map<String,Object> model){ return "firstPage"; } } My server is tomcat 7, there is no error and warning when it is deployed. I also tried this with no luck: <mvc:default-servlet-handler/> Before I start Spring MVC, I can access index.html

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  • struts2-json-plugin not retrieving json data from action class for Struts-JQuery-Plugin grid

    - by thebravedave
    Hello, Im having an issue getting json working with the struts-jquery-plugin-2.1.0 I have included the struts2-json-plugin-2.1.8.1 in my classpath as well. Im sure that I have my struts-jquery-plugin configured correctly because the grid loads, but doesnt load the data its supposed to get from the action class that has been json'ized. The documentation with the json plugin and the struts-jquery plugin leaves ALOT of gaps that I cant even find with examples/tutorials, so I come to the community at stackoverflow. My action class has a property called gridModel thats a List with a basic POJO called Customer. Customer is a pojo with one property, id. I have a factory that supplies the populated List to the actions List property which i mentioned called gridModel. Heres how i set up my struts.xml file: <constant name="struts.devMode" value="true"/> <constant name="struts.objectFactory" value="guice"/> <package name="org.webhop.ywdc" namespace="/" extends="struts-default,json-default"> <result-types> <result-type name="json" class="com.googlecode.jsonplugin.JSONResult"> </result-type> </result-types> <action name="login" class="org.webhop.ywdc.LoginAction" > <result type="json"></result> <result name="success" type="dispatcher">/pages/uiTags/Success.jsp</result> <result name="error" type="redirect">/pages/uiTags/Login.jsp</result> <interceptor-ref name="cookie"> <param name="cookiesName">JSESSIONID</param> </interceptor-ref> </action> <action name="logout" class="org.webhop.ywdc.LogoutAction" > <result name="success" type="redirect">/pages/uiTags/Login.jsp</result> </action> </package> In the struts.xml file i set the and in my action i listed in the action configuration. Heres my jsp page that the action loads: <%@ taglib prefix="s" uri="/struts-tags" % <%@ taglib prefix="sj" uri="/struts-jquery-tags"% <%@ taglib prefix="sjg" uri="/struts-jquery-grid-tags"% <%@ page language="java" contentType="text/html" import="java.util.*"% Welcome, you have logged in! <s:url id="remoteurl" action="login"/> <sjg:grid id="gridtable" caption="Customer Examples" dataType="json" href="%{remoteurl}" pager="false" gridModel="gridModel" > <sjg:gridColumn name="id" key="true" index="id" title="ID" formatter="integer" sortable="false"/> </sjg:grid> Welcome, you have logged in. <br /> <b>Session Time: </b><%=new Date(session.getLastAccessedTime())%> <h2>Password:<s:property value="password"/></h2> <h2>userId:<s:property value="userId"/></h2> <br /> <a href="<%= request.getContextPath() %>/logout.action">Logout</a><br /><br /> ID: <s:property value="id"/> session id: <s:property value="JSESSIONID"/> </body> Im not really sure how to tell what json the json plugin is creating from the action class. If i did know how i could tell if it wasnt formed properly. As far as I know if I specificy in my action configuration in struts.xml, that the grid, which is set to read json and knows to look for "gridModel" will then automatically load the json to the grid, but its not. Heres my action class: public class LoginAction extends ActionSupport { public String JSESSIONID; public int id; private String userId; private String password; public Members member; public List<Customer> gridModel; public String execute() { Cookie cookie = new Cookie("ywdcsid", password); cookie.setMaxAge(3600); HttpServletResponse response = ServletActionContext.getResponse(); response.addCookie(cookie); HttpServletRequest request = ServletActionContext.getRequest(); Cookie[] ckey = request.getCookies(); for(Cookie c: ckey) { System.out.println(c.getName() + "/cookie_name + " + c.getValue() + "/cookie_value"); } Map requestParameters = ActionContext.getContext().getParameters();//getParameters(); String[] testString = (String[])requestParameters.get("password"); String passwordString = testString[0]; String[] usernameArray = (String[])requestParameters.get("userId"); String usernameString = usernameArray[0]; Injector injector = Guice.createInjector(new GuiceModule()); HibernateConnection connection = injector.getInstance(HibernateConnection.class); AuthenticationServices currentService = injector.getInstance(AuthenticationServices.class); currentService.setConnection(connection); currentService.setInjector(injector); member = currentService.getMemberByUsernamePassword(usernameString, passwordString); userId = member.getUsername(); password = member.getPassword(); CustomerFactory customerFactory = new CustomerFactory(); gridModel = customerFactory.getCustomers(); if(member == null) { return ERROR; } else { id = member.getId(); Map session = ActionContext.getContext().getSession(); session.put(usernameString, member); return SUCCESS; } } public String logout() throws Exception { Map session = ActionContext.getContext().getSession(); session.remove("logged-in"); return SUCCESS; } public List<Customer> getGridModel() { return gridModel; } public void setGridModel(List<Customer> gridModel) { this.gridModel = gridModel; } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } public String getUserId() { return userId; } public void setUserId(String userId) { this.userId = userId; } public String getJSESSIONID() { return JSESSIONID; } public void setJSESSIONID(String jsessionid) { JSESSIONID = jsessionid; } } Please help me with this problem. You will make my week, as this is a major bottleneck for me :( thanks so much, thebravedave

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  • Parsing nested JSON objects with JSON Framework for Objective-C

    - by Sheehan Alam
    I have the following JSON object: { "response": { "status": 200 }, "messages": [ { "message": { "user": "value" "pass": "value", "url": "value" } ] } } I am using JSON-Framework (also tried JSON Touch) to parse through this and create a dictionary. I want to access the "message" block and pull out the "user", "pass" and "url" values. In Obj-C I have the following code: // Create new SBJSON parser object SBJSON *parser = [[SBJSON alloc] init]; // Prepare URL request to download statuses from Twitter NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:myURL]]; // Perform request and get JSON back as a NSData object NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil]; // Get JSON as a NSString from NSData response NSString *json_string = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding]; //Print contents of json-string NSArray *statuses = [parser objectWithString:json_string error:nil]; NSLog(@"Array Contents: %@", [statuses valueForKey:@"messages"]); NSLog(@"Array Count: %d", [statuses count]); NSDictionary *results = [json_string JSONValue]; NSArray *tweets = [[results objectForKey:@"messages"] objectForKey:@"message"]; for (NSDictionary *tweet in tweets) { NSString *url = [tweet objectForKey:@"url"]; NSLog(@"url is: %@",url); } I can pull out "messages" and see all of the "message" blocks, but I am unable to parse deeper and pull out the "user", "pass", and "url".

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  • Problem with Json Date format when calling cross-domain proxy

    - by Christo Fur
    I am using a proxy service to allow my client side javascript to talk to a service on another domain The proxy is a simple ashx file with simply gets the request and forwards it onto the service on the other domain : using (var sr = new System.IO.StreamReader(context.Request.InputStream)) { requestData = sr.ReadToEnd(); } string data = HttpUtility.UrlDecode(requestData); using (var client = new WebClient()) { client.BaseAddress = serviceUrl; client.Headers.Add("Content-Type", "application/json"); response = client.UploadString(new Uri(webserviceUrl), data); } The client javascript calling this proxy looks like this function TestMethod() { $.ajax({ type: "POST", url: "/custommodules/configuratorproxyservice.ashx?m=TestMethod", contentType: "application/json; charset=utf-8", data: JSON.parse('{"testObj":{"Name":"jo","Ref":"jones","LastModified":"\/Date(-62135596800000+0000)\/"}}'), dataType: "json", success: AjaxSucceeded, error: AjaxFailed }); function AjaxSucceeded(result) { alert(result); } function AjaxFailed(result) { alert(result.status + ' - ' + result.statusText); } } This works fine until I have to pass a date. At which point I get a Bad Request error when the proxy tries to call the service I did have this working at one point but have now lost it. Have tried using JSON.Parse on the object before sending. and JSON.Stringify, but no joy anyone got any ideas what I am missing

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  • What UI Library(widgets) are you using in your Spring MVC or Spring Web Flow Project [closed]

    - by techsjs2012
    What UI Library(widgets) are you using in your Spring MVC or Spring Web Flow Project I am working on a number of projects with Spring MVC and Spring Web Flow and we started to use Dojo(dijit) widgets for the UI Library. I would like to hear from other projects if anyone knows of anything better or what are you using?? My screens looks like the one below.. the layouts are easy but I need hightlighting, tooltips and more...

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  • Integrating JSF with Spring

    - by Abel Morelos
    I haven't implemented any code, I'm still working the overall architecture for a new application and this going to be the first time I use JSF+Spring. I need to put web services in front of the Spring service beans (business logic tier) since these beans could be accessed by other applications besides the presentation tier. While defining the different layers or tiers for the application, I feel unsure about how to integrate JSF (the presentation tier) with Spring (the business tier in this application). I'm considering to define some sort of common tier or service tier in order to provide the glue code for JSF and Spring, but before that I want to hear from others what have they done or if they have used other frameworks to help with the glue code for this scenario (I already checked Spring MVC/Spring Faces, but I'm not sure if that's what I need since I'm thinking of this application more like JSF-centric than Spring-centric, but maybe you could help me about considering another approach). Thanks in advance.

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  • XML ou JSON? (pt-BR)

    - by srecosta
    Depende.Alguns de nós sentem a necessidade de escolher uma nova técnica / tecnologia em detrimento da que estava antes, como uma negação de identidade ou como se tudo que é novo viesse para substituir o que já existe. Chega a parecer, como foi dito num dos episódios de “This Developer’s Life”, que temos de esquecer algo para termos espaço para novos conteúdos. Que temos de abrir mão.Não é bem assim que as coisas funcionam. Eu vejo os colegas abraçando o ASP.NET MVC e condenando o ASP.NET WebForms como o anticristo. E tenho observado a mesma tendência com o uso do JSON para APIs ao invés de XML, como se o XML não servisse mais para nada. Já vi, inclusive, módulos sendo reescritos para trabalhar com JSON, só porque “JSON é melhor” ™.O post continua no meu blog: http://www.srecosta.com/2012/11/22/xml-ou-json/Grande abraço,Eduardo Costa

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  • Quick Hint: Formatting JSON for Debugging

    - by Aligned
    Originally posted on: http://geekswithblogs.net/Aligned/archive/2013/06/25/quick-hint-formatting-json-for-debugging.aspxI needed a way to quickly format JSON that I copied from the Network view in Google Chrome Developer Tools. A co-worker pointed me to the Notepad++ (or use Chocolatey to install Notepad++) plugin JSMin. Now all I have to do is copy the JSON into Notepad++ and Alt + Ctrl + M and I can see it easily.

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  • How to convert datatable to json string using json.net?

    - by Pandiya Chendur
    How to convert datatable to json using json.net? Any suggestion... I ve downloaded the necessary binaries... Which class should i use to get the conversion of my datatable to json? Thus far used this method to get json string by passing my datatable... public string GetJSONString(DataTable table) { StringBuilder headStrBuilder = new StringBuilder(table.Columns.Count * 5); //pre-allocate some space, default is 16 bytes for (int i = 0; i < table.Columns.Count; i++) { headStrBuilder.AppendFormat("\"{0}\" : \"{0}{1}¾\",", table.Columns[i].Caption, i); } headStrBuilder.Remove(headStrBuilder.Length - 1, 1); // trim away last , StringBuilder sb = new StringBuilder(table.Rows.Count * 5); //pre-allocate some space sb.Append("{\""); sb.Append(table.TableName); sb.Append("\" : ["); for (int i = 0; i < table.Rows.Count; i++) { string tempStr = headStrBuilder.ToString(); sb.Append("{"); for (int j = 0; j < table.Columns.Count; j++) { table.Rows[i][j] = table.Rows[i][j].ToString().Replace("'", ""); tempStr = tempStr.Replace(table.Columns[j] + j.ToString() + "¾", table.Rows[i][j].ToString()); } sb.Append(tempStr + "},"); } sb.Remove(sb.Length - 1, 1); // trim last , sb.Append("]}"); return sb.ToString(); } Now i thought of using json.net but dont know where to get started....

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  • Decode sparse json array to php array

    - by Isaac Sutherland
    I can create a sparse php array (or map) using the command: $myarray = array(10=>'hi','test20'=>'howdy'); I want to serialize/deserialize this as JSON. I can serialize it using the command: $json = json_encode($myarray); which results in the string {"10":"hi","test20":"howdy"}. However, when I deserialize this and cast it to an array using the command: $mynewarray = (array)json_decode($json); I seem to lose any mappings with keys which were not valid php identifiers. That is, mynewarray has mapping 'test20'=>'howdy', but not 10=>'hi' nor '10'=>'hi'. Is there a way to preserve the numerical keys in a php map when converting to and back from json using the standard json_encode / json_decode functions?

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  • Spring ResourceServlet throws too many open files exception in jetty and tomcat under linux

    - by atomsfat
    I was running the petclinic example that was created with spring roo, also I test booking-mvc example that comes whit spring webflow 2.0.9 and the same happens, this is when I reload the main page many times. If I remove the lines from both examples there is no error. < spring:theme code="styleSheet" var="theme_css"/> <spring:url value="/${theme_css}" var="theme_css_url"/> <spring:url value="/resources/dojo/dojo.js" var="dojo_url"/> <spring:url value="/resources/dijit/themes/tundra/tundra.css" var="tundra_url"/> <spring:url value="/resources/spring/Spring.js" var="spring_url"/> <spring:url value="/resources/spring/Spring-Dojo.js" var="spring_dojo_url"/> <spring:url value="/static/images/favicon.ico" var="favicon" /> <link rel="stylesheet" type="text/css" media="screen" href="${theme_css_url}"><!-- //required for FF3 and Opera --></link> <link rel="stylesheet" type="text/css" href="${tundra_url}"><!-- //required for FF3 and Opera --></link> <link rel="SHORTCUT ICON" href="${favicon}" /> <script src="${dojo_url}" type="text/javascript" ><!-- //required for FF3 and Opera --></script> <script src="${spring_url}" type="text/javascript"><!-- //required for FF3 and Opera --></script> <script src="${spring_dojo_url}" type="text/javascript"><!-- //required for FF3 and Opera --></script> <script language="JavaScript" type="text/javascript">dojo.require("dojo.parser");</script> So I can deduce that this is something related with this servlet <servlet> <servlet-name>Resource Servlet</servlet-name> <servlet-class>org.springframework.js.resource.ResourceServlet</servlet-class> </servlet> <!-- Map all /resources requests to the Resource Servlet for handling --> <servlet-mapping> <servlet-name>Resource Servlet</servlet-name> <url-pattern>/resources/*</url-pattern> </servlet-mapping> Running the example injetty 6.1.10, tomcat 1.6, in fedora 12 with java 1.6.20, make errors. but in aix and websphere no errors, and tomcat 1.6 and windows no errors, I think that this is something related with linux. STACKTRACE 2010-05-21 12:53:07.733::WARN: Nested in org.springframework.web.util.NestedServletException: Request processing failed; nested exception is org.apache.tiles.impl.CannotRenderException: ServletException including path '/WEB-INF/layouts/default.jspx'.: org.apache.tiles.impl.CannotRenderException: ServletException including path '/WEB-INF/layouts/default.jspx'. at org.apache.tiles.impl.BasicTilesContainer.render(BasicTilesContainer.java:691) at org.apache.tiles.impl.BasicTilesContainer.render(BasicTilesContainer.java:643) at org.apache.tiles.impl.BasicTilesContainer.render(BasicTilesContainer.java:626) at org.apache.tiles.impl.BasicTilesContainer.render(BasicTilesContainer.java:322) at org.springframework.web.servlet.view.tiles2.TilesView.renderMergedOutputModel(TilesView.java:100) at org.springframework.web.servlet.view.AbstractView.render(AbstractView.java:250) at org.springframework.web.servlet.DispatcherServlet.render(DispatcherServlet.java:1060) at org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:798) at org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:716) at org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:647) at org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:552) at javax.servlet.http.HttpServlet.service(HttpServlet.java:707) at javax.servlet.http.HttpServlet.service(HttpServlet.java:820) at org.mortbay.jetty.servlet.ServletHolder.handle(ServletHolder.java:487) at org.mortbay.jetty.servlet.ServletHandler.handle(ServletHandler.java:362) at org.mortbay.jetty.security.SecurityHandler.handle(SecurityHandler.java:216) at org.mortbay.jetty.servlet.SessionHandler.handle(SessionHandler.java:181) at org.mortbay.jetty.handler.ContextHandler.handle(ContextHandler.java:726) at org.mortbay.jetty.webapp.WebAppContext.handle(WebAppContext.java:405) at org.mortbay.jetty.servlet.Dispatcher.forward(Dispatcher.java:285) at org.mortbay.jetty.servlet.Dispatcher.error(Dispatcher.java:135) at org.mortbay.jetty.servlet.ErrorPageErrorHandler.handle(ErrorPageErrorHandler.java:121) at org.mortbay.jetty.Response.sendError(Response.java:274) at org.mortbay.jetty.servlet.ServletHandler.handle(ServletHandler.java:429) at org.mortbay.jetty.security.SecurityHandler.handle(SecurityHandler.java:216) at org.mortbay.jetty.servlet.SessionHandler.handle(SessionHandler.java:181) at org.mortbay.jetty.handler.ContextHandler.handle(ContextHandler.java:726) at org.mortbay.jetty.webapp.WebAppContext.handle(WebAppContext.java:405) at org.mortbay.jetty.handler.ContextHandlerCollection.handle(ContextHandlerCollection.java:206) at org.mortbay.jetty.handler.HandlerCollection.handle(HandlerCollection.java:114) at org.mortbay.jetty.handler.HandlerWrapper.handle(HandlerWrapper.java:152) at org.mortbay.jetty.Server.handle(Server.java:324) at org.mortbay.jetty.HttpConnection.handleRequest(HttpConnection.java:505) at org.mortbay.jetty.HttpConnection$RequestHandler.headerComplete(HttpConnection.java:829) at org.mortbay.jetty.HttpParser.parseNext(HttpParser.java:514) at org.mortbay.jetty.HttpParser.parseAvailable(HttpParser.java:211) at org.mortbay.jetty.HttpConnection.handle(HttpConnection.java:380) at org.mortbay.io.nio.SelectChannelEndPoint.run(SelectChannelEndPoint.java:395) at org.mortbay.thread.QueuedThreadPool$PoolThread.run(QueuedThreadPool.java:488) Caused by: org.apache.tiles.util.TilesIOException: ServletException including path '/WEB-INF/layouts/default.jspx'. at org.apache.tiles.servlet.context.ServletUtil.wrapServletException(ServletUtil.java:232) at org.apache.tiles.servlet.context.ServletTilesRequestContext.forward(ServletTilesRequestContext.java:243) at org.apache.tiles.servlet.context.ServletTilesRequestContext.dispatch(ServletTilesRequestContext.java:222) at org.apache.tiles.renderer.impl.TemplateAttributeRenderer.write(TemplateAttributeRenderer.java:44) at org.apache.tiles.renderer.impl.AbstractBaseAttributeRenderer.render(AbstractBaseAttributeRenderer.java:103) at org.apache.tiles.impl.BasicTilesContainer.render(BasicTilesContainer.java:669) at org.apache.tiles.impl.BasicTilesContainer.render(BasicTilesContainer.java:689) ... 38 more Caused by: java.io.FileNotFoundException: /home/tsalazar/Workspace/test/roo_clinic/src/main/webapp/WEB-INF/web.xml (Too many open files) at java.io.FileInputStream.open(Native Method) at java.io.FileInputStream.<init>(FileInputStream.java:106) at java.io.FileInputStream.<init>(FileInputStream.java:66) at sun.net.www.protocol.file.FileURLConnection.connect(FileURLConnection.java:70) at sun.net.www.protocol.file.FileURLConnection.getInputStream(FileURLConnection.java:161) at java.net.URL.openStream(URL.java:1010) at org.apache.jasper.compiler.JspConfig.processWebDotXml(JspConfig.java:114) at org.apache.jasper.compiler.JspConfig.init(JspConfig.java:295) at org.apache.jasper.compiler.JspConfig.findJspProperty(JspConfig.java:360) at org.apache.jasper.compiler.Compiler.generateJava(Compiler.java:141) at org.apache.jasper.compiler.Compiler.compile(Compiler.java:409) at org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:592) at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:344) at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:470) at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:364) at javax.servlet.http.HttpServlet.service(HttpServlet.java:820) at org.mortbay.jetty.servlet.ServletHolder.handle(ServletHolder.java:487) at org.mortbay.jetty.servlet.ServletHandler.handle(ServletHandler.java:362) at org.mortbay.jetty.security.SecurityHandler.handle(SecurityHandler.java:216) at org.mortbay.jetty.servlet.SessionHandler.handle(SessionHandler.java:181) at org.mortbay.jetty.handler.ContextHandler.handle(ContextHandler.java:726) at org.mortbay.jetty.webapp.WebAppContext.handle(WebAppContext.java:405) at org.mortbay.jetty.servlet.Dispatcher.forward(Dispatcher.java:285) at org.mortbay.jetty.servlet.Dispatcher.forward(Dispatcher.java:126) at org.apache.tiles.servlet.context.ServletTilesRequestContext.forward(ServletTilesRequestContext.java:241) ... 43 more

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  • Serializing Python bytestrings to JSON, preserving ordinal character values

    - by Doctor J
    I have some binary data produced as base-256 bytestrings in Python (2.x). I need to read these into JavaScript, preserving the ordinal value of each byte (char) in the string. If you'll allow me to mix languages, I want to encode a string s in Python such that ord(s[i]) == s.charCodeAt(i) after I've read it back into JavaScript. The cleanest way to do this seems to be to serialize my Python strings to JSON. However, json.dump doesn't like my bytestrings, despite fiddling with the ensure_ascii and encoding parameters. Is there a way to encode bytestrings to Unicode strings that preserves ordinal character values? Otherwise I think I need to encode the characters above the ASCII range into JSON-style \u1234 escapes; but a codec like this does not seem to be among Python's codecs. Is there an easy way to serialize Python bytestrings to JSON, preserving char values, or do I need to write my own encoder?

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  • Receive JSON payload with ZEND framework and / or PHP

    - by kent3800
    I'm receiving a JSON payload from a webservice at my site's internal webpage at /asset/setjob. The following is the JSON payload being posted to /asset/setjob: [{"job": {"source_filename": "beer-drinking-pig.mpg", "current_step": "waiting_for_file", "encoding_profile_id": "nil", "resolution": "nil", "status_url": "http://example.com/api/v1/jobs/1.json", "id": 1, "bitrate": "nil", "current_status": "waiting for file", "current_progress": "nil", "remote_id": "my-own-remote-id"}}] This payload posts one time to this page. The page is not meant for viewing but parsing the JSON object for the id and current_status so that I can insert it into a database. I'm using Zend framework. HOW DO I receive this payload in Zend? Do I $_GET['json']? $_POST['job']? None of these seem to work. I essentially need to assign this payload to a php variable so that I can then manipulate it. I've tried: $jsonStrGet = var_dump($_GET); $jsonStrPost = var_dump($_POST); And I've tried: $response = $this-getResponse(); $body = $response-getBody(); Blockquote Any help would be much appreciated! Thanks.

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  • JSON Returning Null in PHP

    - by kira423
    Here is the two scripts I have Script 1: if(sha1($json+$secret) == $_POST['signature']) { $conversion_id = md5(($obj['amount'])); echo "OK"; echo $conversion_id; mysql_query("INSERT INTO completed (`id`,`uid`,`completedid`) VALUES ('','".$obj['uid']."','".$conversion_id."')"); } else { } ?> Script 2: <? $json = $_POST['payload']; $secret = "78f12668216b562a79d46b170dc59f695070e532"; $obj = json_decode($json); if(sha1($json+$secret) == $_POST['signature']) { print "OK"; } else { } ?> The problem here is that it is returning all NULL values. I am not an expert with JSON so I have no idea what is going on here. I really have no way of testing it because the information is coming from an outside website sending information such as this: { payload: { uid: "900af657a65e", amount: 50, adjusted_amount: 25 }, signature: "4dd0f5da77ecaf88628967bbd91d9506" } The site allows me to test the script, but because json_decode is providing NULL values it will not get through the signature block. Is there a way I can test it myself? Or is there a simple error in this script that I may have just looked over?

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  • How do I use a custom authentication mechanism for a Java web application with Spring Security?

    - by Adam
    Hi, I'm working on a project to convert an existing Java web application to use Spring Web MVC. As a part of this I will migrate the existing log-on/log-off mechanism to use Spring Security. The idea at this stage is to replicate the existing functionality and replace only the web layer, leaving the service classes and objects in place. The required functionality is simple. Access is controlled to URLs and to access certain pages the user must log on. Authentication is performed with a simple username and password along with an extra static piece of information that comes from the login page. There is no notion of a role: once a user has logged on they have access to all of the pages. Behind the scenes, the service layer has a class with a simple authentication method: doAuthenticate(String username, String password, String info) throws ServiceException An exception is thrown if the login fails. I'd like to leave this existing service object that does the authentication intact but to "plug it into" the Spring Security mechanism. Can somebody suggest the best approach to take for this please? Naturally, I'd like to take the path of least resistance and leave the work where possible to Spring... Thanks in advance, Adam.

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  • Parse JSON in C#

    - by Ender
    I'm trying to parse some JSON data from the Google AJAX Search API. I have this URL and I'd like to break it down so that the results are displayed. I've currently written this code, but I'm pretty lost in regards of what to do next, although there are a number of examples out there with simplified JSON strings. Being new to C# and .NET in general I've struggled to get a genuine text output for my ASP.NET page so I've been recommended to give JSON.NET a try. Could anyone point me in the right direction to just simply writing some code that'll take in JSON from the Google AJAX Search API and print it out to the screen? EDIT: I think I've made some progress in regards to getting some code working using DataContractJsonSerializer. Here is the code I have so far. Any advice on whether this is close to working and/or how I would output my results in a clean format? EDIT 2: I've followed the advice from Dreas Grech and the StackOverflowException has gone. However, now I am getting no output. Any ideas on where to go next? EDIT 3: ALL FIXED! All results are working fine. Thank you again Dreas Grech! using System; using System.Data; using System.Configuration; using System.Web; using System.Web.Security; using System.Web.UI; using System.Web.UI.WebControls; using System.Web.UI.WebControls.WebParts; using System.Web.UI.HtmlControls; using System.ServiceModel.Web; using System.Runtime.Serialization; using System.Runtime.Serialization.Json; using System.IO; using System.Text; public partial class _Default : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { GoogleSearchResults g1 = new GoogleSearchResults(); const string json = @"{""responseData"": {""results"":[{""GsearchResultClass"":""GwebSearch"",""unescapedUrl"":""http://www.cheese.com/"",""url"":""http://www.cheese.com/"",""visibleUrl"":""www.cheese.com"",""cacheUrl"":""http://www.google.com/search?q\u003dcache:bkg1gwNt8u4J:www.cheese.com"",""title"":""\u003cb\u003eCHEESE\u003c/b\u003e.COM - All about \u003cb\u003echeese\u003c/b\u003e!."",""titleNoFormatting"":""CHEESE.COM - All about cheese!."",""content"":""\u003cb\u003eCheese\u003c/b\u003e - everything you want to know about it. Search \u003cb\u003echeese\u003c/b\u003e by name, by types of milk, by textures and by countries.""},{""GsearchResultClass"":""GwebSearch"",""unescapedUrl"":""http://en.wikipedia.org/wiki/Cheese"",""url"":""http://en.wikipedia.org/wiki/Cheese"",""visibleUrl"":""en.wikipedia.org"",""cacheUrl"":""http://www.google.com/search?q\u003dcache:n9icdgMlCXIJ:en.wikipedia.org"",""title"":""\u003cb\u003eCheese\u003c/b\u003e - Wikipedia, the free encyclopedia"",""titleNoFormatting"":""Cheese - Wikipedia, the free encyclopedia"",""content"":""\u003cb\u003eCheese\u003c/b\u003e is a food consisting of proteins and fat from milk, usually the milk of cows, buffalo, goats, or sheep. It is produced by coagulation of the milk \u003cb\u003e...\u003c/b\u003e""},{""GsearchResultClass"":""GwebSearch"",""unescapedUrl"":""http://www.ilovecheese.com/"",""url"":""http://www.ilovecheese.com/"",""visibleUrl"":""www.ilovecheese.com"",""cacheUrl"":""http://www.google.com/search?q\u003dcache:GBhRR8ytMhQJ:www.ilovecheese.com"",""title"":""I Love \u003cb\u003eCheese\u003c/b\u003e!, Homepage"",""titleNoFormatting"":""I Love Cheese!, Homepage"",""content"":""The American Dairy Association\u0026#39;s official site includes recipes and information on nutrition and storage of \u003cb\u003echeese\u003c/b\u003e.""},{""GsearchResultClass"":""GwebSearch"",""unescapedUrl"":""http://www.gnome.org/projects/cheese/"",""url"":""http://www.g

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  • JSON Formatting with Jersey, Jackson, & json.org/java Parser using Curl Command

    - by socal_javaguy
    Using Java 6, Tomcat 7, Jersey 1.15, Jackson 2.0.6 (from FasterXml maven repo), & www.json.org parser, I am trying to pretty print the JSON String so it will look indented by the curl -X GET command line. I created a simple web service which has the following architecture: My POJOs (model classes): Family.java import javax.xml.bind.annotation.XmlRootElement; @XmlRootElement public class Family { private String father; private String mother; private List<Children> children; // Getter & Setters } Children.java import javax.xml.bind.annotation.XmlRootElement; @XmlRootElement public class Children { private String name; private String age; private String gender; // Getters & Setters } Using a Utility Class, I decided to hard code the POJOs as follows: public class FamilyUtil { public static Family getFamily() { Family family = new Family(); family.setFather("Joe"); family.setMother("Jennifer"); Children child = new Children(); child.setName("Jimmy"); child.setAge("12"); child.setGender("male"); List<Children> children = new ArrayList<Children>(); children.add(child); family.setChildren(children); return family; } } My web service: import java.io.IOException; import javax.ws.rs.GET; import javax.ws.rs.Path; import javax.ws.rs.PathParam; import javax.ws.rs.Produces; import javax.ws.rs.core.MediaType; import org.codehaus.jackson.JsonGenerationException; import org.codehaus.jackson.map.JsonMappingException; import org.codehaus.jackson.map.ObjectMapper; import org.codehaus.jettison.json.JSONException; import org.json.JSONObject; import org.json.JSONTokener; import com.myapp.controller.myappController; import com.myapp.resource.output.HostingSegmentOutput; import com.myapp.util.FamilyUtil; @Path("") public class MyWebService { @GET @Produces(MediaType.APPLICATION_JSON) public static String getFamily() throws IOException, JsonGenerationException, JsonMappingException, JSONException, org.json.JSONException { ObjectMapper mapper = new ObjectMapper(); String uglyJsonString = mapper.writeValueAsString(FamilyUtil.getFamily()); System.out.println(uglyJsonString); JSONTokener tokener = new JSONTokener(uglyJsonString); JSONObject finalResult = new JSONObject(tokener); return finalResult.toString(4); } } When I run this using: curl -X GET http://localhost:8080/mywebservice I get this in my Eclipse's console: {"father":"Joe","mother":"Jennifer","children":[{"name":"Jimmy","age":"12","gender":"male"}]} But from the curl command on the command line (this response is more important): "{\n \"mother\": \"Jennifer\",\n \"children\": [{\n \"age\": \"12\",\n \"name\": \"Jimmy\",\n \"gender\": \"male\"\n }],\n \"father\": \"Joe\"\n}" This is adding newline escape sequences and placing double quotes (but not indenting like it should it does have 4 spaces after the new line but its all in one line). Would appreciate it if someone could point me in the right direction.

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  • 404 with spring 3

    - by markjason72
    hi I am going through my first lessons with spring 3.I created a dynamic web app in eclipse with the following structure. spring3mvc \src\my.spring.HelloWorldController.java \WebContent | |-----WEB-INF\jsp\hello.jsp |-----index.jsp |-----web.xml |-----WEB-INF\spring-servlet.xml |-----WEB-INF\lib\...*.jar files I created the spring-servlet.xml as below <context:component-scan base-package="my.spring" /> <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" /> <property name="prefix" value="/WEB-INF/jsp/" /> <property name="suffix" value=".jsp" /> </bean> and coded the controller package my.spring; import org.springframework.stereotype.Controller; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.servlet.ModelAndView; @Controller public class HelloWorldController { @RequestMapping("/hello") public ModelAndView helloWorld() { String message = "Hello World, Spring 3.0!"; return new ModelAndView("hello", "message", message); } } index.jsp has a link to hello view <html> <body> <a href="hello.html">Say Hello</a> </body> </html> finally in hello.jsp I have put <html> <body> ${message} </body> </html> My web.xml has <display-name>Spring3MVC</display-name> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> <servlet> <servlet-name>spring</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>spring</servlet-name> <url-pattern>*.html</url-pattern> </servlet-mapping> When I run the app on Tomcat6 server( thru eclipse),I can see the index page at http://localhost:8080/Spring3MVC/ .It displays the link to hello page.When I click on it(http://localhost:8080/Spring3MVC/hello.html),I get a 404 error. message /Spring3MVC/hello.html description The requested resource (/Spring3MVC/hello.html) is not available. Any idea how I can solve this? thanks mark.

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  • Calling a REST Based JSON Endpoint with HTTP POST and WCF

    - by Wallym
    Note: I always forget this stuff, so I'm putting it my blog to help me remember it.Calling a JSON REST based service with some params isn't that hard.  I have an endpoint that has this interface:        [WebInvoke(UriTemplate = "/Login",             Method="POST",             BodyStyle = WebMessageBodyStyle.Wrapped,            RequestFormat = WebMessageFormat.Json,            ResponseFormat = WebMessageFormat.Json )]        [OperationContract]        bool Login(LoginData ld); The LoginData class is defined like this:    [DataContract]    public class LoginData    {        [DataMember]        public string UserName { get; set; }        [DataMember]        public string PassWord { get; set; }        [DataMember]        public string AppKey { get; set; }    } Now that you see my method to call to login as well as the class that is passed for the login, the body of the login request looks like this:{ "ld" : {  "UserName":"testuser", "PassWord":"ackkkk", "AppKey":"blah" } } The header (in Fiddler), looks like this:User-Agent: FiddlerHost: hostnameContent-Length: 76Content-Type: application/json And finally, my url to POST against is:http://www.something.com/...../someservice.svc/LoginAnd there you have it, calling a WCF JSON Endpoint thru REST (and HTTP POST)

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  • Design considerations on JSON schema for scalars with a consistent attachment property

    - by casperOne
    I'm trying to create a JSON schema for the results of doing statistical analysis based on disparate pieces of data. The current schema I have looks something like this: { // Basic key information. video : "http://www.youtube.com/watch?v=7uwfjpfK0jo", start : "00:00:00", end : null, // For results of analysis, to be populated: // *** This is where it gets interesting *** analysis : { game : { value: "Super Street Fighter 4: Arcade Edition Ver. 2012", confidence: 0.9725 } teams : [ { player : { value : "Desk", confidence: 0.95, } characters : [ { value : "Hakan", confidence: 0.80 } ] } ] } } The issue is the tuples that are used to store a value and the confidence related to that value (i.e. { value : "some value", confidence : 0.85 }), populated after the results of the analysis. This leads to a creep of this tuple for every value. Take a fully-fleshed out value from the characters array: { name : { value : "Hakan", confidence: 0.80 } ultra : { value: 1, confidence: 0.90 } } As the structures that represent the values become more and more detailed (and more analysis is done on them to try and determine the confidence behind that analysis), the nesting of the tuples adds great deal of noise to the overall structure, considering that the final result (when verified) will be: { name : "Hakan", ultra : 1 } (And recall that this is just a nested value) In .NET (in which I'll be using to work with this data), I'd have a little helper like this: public class UnknownValue<T> { T Value { get; set; } double? Confidence { get; set; } } Which I'd then use like so: public class Character { public UnknownValue<Character> Name { get; set; } } While the same as the JSON representation in code, it doesn't have the same creep because I don't have to redefine the tuple every time and property accessors hide the appearance of creep. Of course, this is an apples-to-oranges comparison, the above is code while the JSON is data. Is there a more formalized/cleaner/best practice way of containing the creep of these tuples in JSON, or is the approach above an accepted approach for the type of data I'm trying to store (and I'm just perceiving it the wrong way)? Note, this is being represented in JSON because this will ultimately go in a document database (something like RavenDB or elasticsearch). I'm not concerned about being able to serialize into the object above, because I can always use data transfer objects to facilitate getting data into/out of my underlying data store.

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  • How to get around the Circular Reference issue with JSON and Entity

    - by DanScan
    I have been experimenting with creating a website that leverages MVC with JSON for my presentation layer and Entity framework for data model/database. My Issue comes into play with serializing my Model objects into JSON. I am using the code first method to create my database. When doing the code first method a one to many relationship (parent/child) requires the child to have a reference back to the parent. (Example code my be a typo but you get the picture) class parent { public List<child> Children{get;set;} public int Id{get;set;} } class child { public int ParentId{get;set;} [ForeignKey("ParentId")] public parent MyParent{get;set;} public string name{get;set;} } When returning a "parent" object via a JsonResult a circular reference error is thrown because "child" has a property of class parent. I have tried the ScriptIgnore attribute but I lose the ability to look at the child objects. I will need to display information in a parent child view at some point. I have tried to make base classes for both parent and child that do not have a circular reference. Unfortunately when I attempt to send the baseParent and baseChild these are read by the JSON Parser as their derived classes (I am pretty sure this concept is escaping me). Base.baseParent basep = (Base.baseParent)parent; return Json(basep, JsonRequestBehavior.AllowGet); The one solution I have come up with is to create "View" Models. I create simple versions of the database models that do not include the reference to the parent class. These view models each have method to return the Database Version and a constructor that takes the database model as a parameter (viewmodel.name = databasemodel.name). This method seems forced although it works. NOTE:I am posting here because I think this is more discussion worthy. I could leverage a different design pattern to over come this issue or it could be as simple as using a different attribute on my model. In my searching I have not seen a good method to overcome this problem. My end goal would be to have a nice MVC application that heavily leverages JSON for communicating with the server and displaying data. While maintaining a consistant model across layers (or as best as I can come up with).

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  • json-framework: EXC_BAD_ACCESS on stringWithObject

    - by Vegar
    UPDATE: I found that the reason for the previous error was an error in the documentation. The method should be named proxyForJson, not jsonProxyObject... But I'm still stuck, though. I now get an EXC_BAD_ACCESS error inside stringWithObject some where. Any clues? UPDATE 2: My proxyForJson implementation is a cut-n-paste from then documentation: - (id)proxyForJson { return [NSDictionary dictionaryWithObjectsAndKeys: Navn, @"Navn", Adresse, @"Adresse", Alder, @"Alder", nil]; } Trying to make json serialization work for my custom objective-c class. As I understand the documentation, json-framework can serialize custom objects, if they implement the jsonProxyObject method. So I have this class: @interface MyObject : NSObject { NSString *Name; NSString *Addresse; NSInteger Age; } @property (nonatomic, retain) NSString *Name; @property (nonatomic, retain) NSString *Addresse; @property (nonatomic, assign) NSInteger Age; - (id)jsonProxyObject; @end And I try to serialize an array with some instances in it: [json stringWithObject:list error:&error]; But all I get is he following error: "JSON serialisation not supported for MyObject" I guess the jsonWriter can't find my jsonProxyObject method for some reason, buy why? Regards.

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  • How to get JSON code into MYSQL database?

    - by the_boy_za
    I've created this form with a jQuery autocomplete function. The selected brand from the autocomplete list needs to get sent to a PHP file using $.ajax function. My code doesn't seem to work but i can't find the error. I don't know why the data isn't getting inserted into MYSQL database. Here is my code: JQUERY: $(document).ready(function() { $("#autocomplete").autocomplete({ minLength: 2 }); $("#autocomplete").autocomplete({ source: ["Adidas", "Airforce", "Alpha Industries", "Asics", "Bikkemberg", "Birkenstock", "Bjorn Borg", "Brunotti", "Calvin Klein", "Cars Jeans", "Chanel", "Chasin", "Diesel", "Dior", "DKNY", "Dolce & Gabbana"] }); $("#add-brand").click(function() { var merk = $("#autocomplete").val(); $("#selected-brands").append(" <a class=\"deletemerk\" href=\"#\">" + merk + "</a>"); //Add your parameters here var param = JSON.stringify({ Brand: merk }); $.ajax({ type: "POST", async: true, url: "scripttohandlejson.php", contentType: "application/json", data: param, dataType: "json", success: function (good){ //handle success alert(good) }, failure: function (bad){ //handle any errors alert(bad) } }); return false; }); }); PHP FILE: scripttohandlejson.php <?PHP $getcontent = json_decode($json, true); $getcontent->{'Brand'}; $vraag ="INSERT INTO kijken (merk) VALUES ='$getcontent' "; $voerin = mysql_query($vraag) or die("couldnt put into db"); <?

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  • Fastest way to parse big json android

    - by jem88
    I've a doubt that doesn't let me sleep! :D I'm currently working with big json files, with many levels. I parse these object using the 'default' android way, so I read the response with a ByteArrayOutputStream, get a string and create a JSONObject from the string. All fine here. Now, I've to parse the content of the json to get the objects of my interest, and I really can't find a better way that parse it manually, like this: String status = jsonObject.getString("status"); Boolean isLogged = jsonObject.getBoolean("is_logged"); ArrayList<Genre> genresList = new ArrayList<Genre>(); // Get jsonObject with genres JSONObject jObjGenres = jsonObject.getJSONObject("genres"); // Instantiate an iterator on jsonObject keys Iterator<?> keys = jObjGenres.keys(); // Iterate on keys while( keys.hasNext() ) { String key = (String) keys.next(); JSONObject jObjGenre = jObjGenres.getJSONObject(key); // Create genre object Genre genre = new Genre( jObjGenre.getInt("id_genre"), jObjGenre.getString("string"), jObjGenre.getString("icon") ); genresList.add(genre); } // Get languages list JSONObject jObjLanguages = jsonObject.getJSONObject("languages"); Iterator jLangKey = jObjLanguages.keys(); List<Language> langList = new ArrayList<Language>(); while (jLangKey.hasNext()) { // Iterate on jlangKey obj String key = (String) jLangKey.next(); JSONObject jCurrentLang = (JSONObject) jObjLanguages.get(key); Language lang = new Language( jCurrentLang.getString("id_lang"), jCurrentLang.getString("name"), jCurrentLang.getString("code"), jCurrentLang.getString("active").equals("1") ); langList.add(lang); } I think this is really ugly, frustrating, timewaster, and fragile. I've seen parser like json-smart and Gson... but seems difficult to parse a json with many levels, and get the objects! But I guess that must be a better way... Any idea? Every suggestion will be really appreciated. Thanks in advance!

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