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  • Looping through all attributes of a XML element in XSLT

    - by TheGNUGuy
    Hey everyone, I am trying to use <xsl:for-each select="@*"> to grab all the attributes of a given element but when i do that my <xsl:choose> statement doesn't execute. Here is the element that I'm working with: <textBox id="Airfare" value="" label="text 1"/> Here is the XSLT template I'm using: <xsl:template match="textBox"> <div> <xsl:choose> <xsl:when test="@label"> <xsl:value-of select="@label"/> </xsl:when> <xsl:otherwise> <xsl:text>No Label Defined</xsl:text> </xsl:otherwise> </xsl:choose> <xsl:element name="input"> <xsl:attribute name="type">text</xsl:attribute> <xsl:for-each select="@*"> <xsl:choose> <xsl:when test="@id"> <xsl:attribute name="name">form_<xsl:value-of select="@id"/></xsl:attribute> <xsl:attribute name="id">form_<xsl:value-of select="@id"/></xsl:attribute> </xsl:when> <xsl:when test="@label"> </xsl:when> <xsl:otherwise> <xsl:copy-of select="current()"/> </xsl:otherwise> </xsl:choose> </xsl:for-each> </xsl:element> </div> And when I generate the HTML using PHP I get this: <div>text 1<input type="text" id="Airfare" value="" label="text 1"></div> As you can see it didn't add form_ to the id attribute it didn't generate a name attribute and it didn't skip over the label attribute. Thanks for your help!

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  • Get current node's local-name in XSL

    - by green67
    Here's the structure of my XML <FileRoot> <UserSet1> <User> <FirstName></FirstName> <LastName></LastName> </User> <User> <FirstName></FirstName> <LastName></LastName> </User> ... </UserSet1> <InactiveUsers> <User> <FirstName></FirstName> <LastName></LastName> </User> <User> <FirstName></FirstName> <LastName></LastName> </User> ... </InactiveUsers> </FileRoot> In my XSL template <xsl:template match="/*/*"> <File> <xsl attribute name="Name"> <xsl:value-of select="local-name(/*/*)"/> </xsl:attribute> </File> </xsl> After transforming, for both UserSet1 and InactiveUsers, gave me "UserSet1". The expected results should be "UserSet1" for UserSet1, and "InactiveUsers" for InactiveUsers. How do I correctly retrieve the value? Thanks

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  • xsltproc killed, out of memory

    - by David Parks
    I'm trying to split up a 13GB xml file into small ~50MB xml files with this XSLT style sheet. But this process kills xsltproc after I see it taking up over 1.7GB of memory (that's the total on the system). Is there any way to deal with huge XML files with xsltproc? Can I change my style sheet? Or should I use a different processor? Or am I just S.O.L.? <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" xmlns:exsl="http://exslt.org/common" extension-element-prefixes="exsl" xmlns:fn="http://www.w3.org/2005/xpath-functions"> <xsl:output method="xml" indent="yes"/> <xsl:strip-space elements="*"/> <xsl:param name="block-size" select="75000"/> <xsl:template match="/"> <xsl:copy> <xsl:apply-templates select="mysqldump/database/table_data/row[position() mod $block-size = 1]" /> </xsl:copy> </xsl:template> <xsl:template match="row"> <exsl:document href="chunk-{position()}.xml"> <add> <xsl:for-each select=". | following-sibling::row[position() &lt; $block-size]" > <doc> <xsl:for-each select="field"> <field> <xsl:attribute name="name"><xsl:value-of select="./@name"/></xsl:attribute> <xsl:value-of select="."/> </field> <xsl:text>&#xa;</xsl:text> </xsl:for-each> </doc> </xsl:for-each> </add> </exsl:document> </xsl:template>

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  • How to Generate XML from Database

    - by Nisarg Mehta
    Hi , I am fetching data from two tables CARRIER_IFTA ,IFTA_NAME. My Select Query is like below.. SELECT t1.IFTA_LICENSE_NUMBER,t1.IFTA_BASE_STATE,t2.NAME_TYPE,t2.NAME from CARRIER_IFTA t1 inner join IFTA_NAME t2 on t1.IFTA_LICENSE_NUMBER=t2.IFTA_LICENSE_NUMBER My Data is coming in this way... IFTA_LICENSE_NUMBER IFTA_BASE_STATE NAME_TYPE NAME -------------------------------------------------------- 630908333 US LG XYZ 630908333 US MG PQR 730908344 US LG ABC Now using XSLT I want to generate XML like this <T0019> <IFTA_ACCOUNT> <IFTA_LICENSE_NUMBER>630908333</IFTA_LICENSE_NUMBER> <IFTA_BASE_STATE>US</IFTA_BASE_STATE> <IFTA_NAME> <NAME_TYPE>LG<NAME_TYPE> <NAME>XYZ</NAME> </IFTA_NAME> <IFTA_NAME> <NAME_TYPE>MG<NAME_TYPE> <NAME>PQR</NAME> <IFTA_NAME> </IFTA_ACCOUNT> <IFTA_ACCOUNT> <IFTA_LICENSE_NUMBER>730908344</IFTA_LICENSE_NUMBER> <IFTA_BASE_STATE>US</IFTA_BASE_STATE> <IFTA_NAME> <NAME_TYPE>LG<NAME_TYPE> <NAME>ABC</NAME> </IFTA_NAME> </IFTA_ACCOUNT> </T0019> i have used below xslt but it is not giveng me desire result ... <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:template match="/ROWSET"> <xsl:element name="T0019"> <xsl:apply-templates select="IFTAACCOUNT"/> </xsl:element> </xsl:template> <xsl:template match="IFTAACCOUNT"> <xsl:element name="IFTAACCOUNT"> <xsl:apply-templates select="IFTA_CARRIER_ID_NUMBER"/> </xsl:element> </xsl:template> <xsl:template match="IFTA_LICENSE_NUMBER"> <xsl:element name="IFTA_LICENSE_NUMBER"> <xsl:apply-templates /> </xsl:element> </xsl:template> <xsl:template match="IFTA_BASE_STATE"> <xsl:element name="IFTA_BASE_STATE"> <xsl:apply-templates /> </xsl:element> </xsl:template> <xsl:template match="IRP_NAME"> <IRP_NAME> <xsl:apply-templates select="NAME"/> <xsl:apply-templates select="NAME_TYPE"/> </IRP_NAME> </xsl:template> <xsl:template match="NAME"> <xsl:element name="NAME"> <xsl:value-of select="." /> </xsl:element> </xsl:template> <xsl:template match="NAME_TYPE"> <xsl:element name="NAME_TYPE"> <xsl:apply-templates /> </xsl:element> </xsl:template> </xsl:stylesheet> but it is not giving desire result ... Please help me ... Thanks in Advance...

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  • Generate XML from Database using XSLT

    - by Nisarg Mehta
    Hi , I am fetching data from two tables CARRIER_IFTA ,IFTA_NAME. My Select Query is like below.. SELECT t1.IFTA_LICENSE_NUMBER,t1.IFTA_BASE_STATE,t2.NAME_TYPE,t2.NAME from CARRIER_IFTA t1 inner join IFTA_NAME t2 on t1.IFTA_LICENSE_NUMBER=t2.IFTA_LICENSE_NUMBER My Data is coming in this way... IFTA_LICENSE_NUMBER IFTA_BASE_STATE NAME_TYPE NAME -------------------------------------------------------- 630908333 US LG XYZ 630908333 US MG PQR 730908344 US LG ABC Now using XSLT I want to generate XML like this <T0019> <IFTA_ACCOUNT> <IFTA_LICENSE_NUMBER>630908333</IFTA_LICENSE_NUMBER> <IFTA_BASE_STATE>US</IFTA_BASE_STATE> <IFTA_NAME> <NAME_TYPE>LG<NAME_TYPE> <NAME>XYZ</NAME> </IFTA_NAME> <IFTA_NAME> <NAME_TYPE>MG<NAME_TYPE> <NAME>PQR</NAME> <IFTA_NAME> </IFTA_ACCOUNT> <IFTA_ACCOUNT> <IFTA_LICENSE_NUMBER>730908344</IFTA_LICENSE_NUMBER> <IFTA_BASE_STATE>US</IFTA_BASE_STATE> <IFTA_NAME> <NAME_TYPE>LG<NAME_TYPE> <NAME>ABC</NAME> </IFTA_NAME> </IFTA_ACCOUNT> </T0019> i have used below xslt but it is not giveng me desire result ... <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:template match="/ROWSET"> <xsl:element name="T0019"> <xsl:apply-templates select="IFTAACCOUNT"/> </xsl:element> </xsl:template> <xsl:template match="IFTAACCOUNT"> <xsl:element name="IFTAACCOUNT"> <xsl:apply-templates select="IFTA_CARRIER_ID_NUMBER"/> </xsl:element> </xsl:template> <xsl:template match="IFTA_LICENSE_NUMBER"> <xsl:element name="IFTA_LICENSE_NUMBER"> <xsl:apply-templates /> </xsl:element> </xsl:template> <xsl:template match="IFTA_BASE_STATE"> <xsl:element name="IFTA_BASE_STATE"> <xsl:apply-templates /> </xsl:element> </xsl:template> <xsl:template match="IRP_NAME"> <IRP_NAME> <xsl:apply-templates select="NAME"/> <xsl:apply-templates select="NAME_TYPE"/> </IRP_NAME> </xsl:template> <xsl:template match="NAME"> <xsl:element name="NAME"> <xsl:value-of select="." /> </xsl:element> </xsl:template> <xsl:template match="NAME_TYPE"> <xsl:element name="NAME_TYPE"> <xsl:apply-templates /> </xsl:element> </xsl:template> </xsl:stylesheet> but it is not giving desire result ... Please help me ... Thanks in Advance...

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  • Emphasized text in docbook, fo, pdf out put.

    - by Mica
    I am trying to emphasize a character of some static text to render into the footer of my pdf, but can't figure out the right combination of tags in my xsl. How can I accomplish this? Example: <!-- Footer content --> <xsl:template name="footer.content"> <xsl:param name="pageclass" select="''"/> <xsl:param name="sequence" select="''"/> <xsl:param name="position" select="''"/> <xsl:param name="gentext-key" select="''"/> <fo:block> <xsl:choose> ... <xsl:when test="$sequence = 'odd' and $position = 'left'"> <xsl:text>&#x00A9;<emphasis>My</emphasis>Company</xsl:text> </xsl:when> ... </xsl:choose> </fo:block> </xsl:template> This example generates an error in xsltproc. Help!

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  • XSL check param length

    - by AdRock
    I need to check if a param has got a value in it and if it has then do this line otherwise do this line. I've got it working whereas I don't get errors but it's not taking the right branch Here is the template which holds the html in the XSL stylesheet <xsl:call-template name="volunteer_role"> <xsl:with-param name="volrole" select="volunteer/roles" /> </xsl:call-template> and here is the template where there is a choice whether to take this brancg or that brach depending if the param is empty <xsl:template name="volunteer_role"> <xsl:param name="volrole" select="'Not Available'" /> <div class="small bold">ROLES:</div> <div class="large"> <xsl:choose> <xsl:when test="string-length($volrole)!=0"> <xsl:value-of select="$volrole" /> </xsl:when> <xsl:otherwise> <xsl:text> </xsl:text> </xsl:otherwise> </xsl:choose> </div> </xsl:template>

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  • How do I check for the existence of an external file with XSL?

    - by LOlliffe
    I've found a lot of examples that reference Java and C for this, but how do I, or can I, check for the existence of an external file with XSL. First, I realize that this is only a snippet, but it's part of a huge stylesheet, so I'm hoping it's enough to show my issue. <!-- Use this template for Received SMSs --> <xsl:template name="ReceivedSMS"> <!-- Set/Declare "SMSname" variable (local, evaluates per instance) --> <xsl:variable name="SMSname"> <xsl:value-of select=" following-sibling::Name"/> </xsl:variable> <fo:table font-family="Arial Unicode MS" font-size="8pt" text-align="start"> <fo:table-column column-width=".75in"/> <fo:table-column column-width="6.75in"/> <fo:table-body> <fo:table-row> <!-- Cell contains "speakers" icon --> <fo:table-cell display-align="after"> <fo:block text-align="start"> <fo:external-graphic src="../images/{$SMSname}.jpg" content-height="0.6in"/> What I'd like to do, is put in an "if" statement, surronding the {$SMSname}.jpg line. That is: <fo:block text-align="start"> <xsl:if test="exists( the external file {$SMSname}.jpg)"> <fo:external-graphic src="../images/{$SMSname}.jpg" content-height="0.6in"/> </xsl:if> <xsl:if test="not(exists( the external file {$SMSname}.jpg))"> <fo:external-graphic src="../images/unknown.jpg" content-height="0.6in"/> </xsl:if> </fo:block> Because of "grouping", etc., I'm using XSLT 2.0. I hope that this is something that can be done. I hope even more that it's something simple. As always, thanks in advance for any help. LO

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  • Recoverable error while running XSL

    - by Kate
    XSL: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ve="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:o="urn:schemas-microsoft-com:office:office" xmlns:r="http://schemas.openxmlformats.org/officeDocument/2006/relationships" xmlns:m="http://schemas.openxmlformats.org/officeDocument/2006/math" xmlns:v="urn:schemas-microsoft-com:vml" xmlns:wp="http://schemas.openxmlformats.org/drawingml/2006/wordprocessingDrawing" xmlns:w10="urn:schemas-microsoft-com:office:word" xmlns:w="http://schemas.openxmlformats.org/wordprocessingml/2006/main" xmlns:wne="http://schemas.microsoft.com/office/word/2006/wordml" exclude-result-prefixes="wp wne w10 w ve o r m v" version="2.0"> <xsl:output method="text"/> <xsl:param name="styleName"/> <xsl:template match="w:p"> <xsl:apply-templates/><xsl:text>&#10;</xsl:text> </xsl:template> <xsl:template match="w:r[not ((parent::w:hyperlink[@w:anchor[matches(.,concat('^(',$styleName,')')),'i']]))]"> <xsl:value-of select="replace(., '.', '&#xFF00;')"/> </xsl:template> </xsl:stylesheet> While processing the above XSL, I am getting the below error, Recoverable Error: Recoverable error on line 11 FORG0006: An error occurred matching pattern {w:r[not ((parent::w:hyperlink[@w:anchor[matches(.,concat('^(',$styleName,')')),'i']]))]}: Effective boolean value is not defined for a sequence of two or more items starting with a boolean Please Help. I am not able to figure out this.

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  • placing the matched 2 different child elements xml values in a single line from xslt2.0

    - by Girikumar Mathivanan
    I have the below input xml, <GSKProductHierarchy> <GlobalBusinessIdentifier>ZGB001</GlobalBusinessIdentifier> <Hierarchy> <Material>335165140779</Material> <Level1>02</Level1> <Level2>02AQ</Level2> <Level3>02AQ006</Level3> <Level4>02AQ006309</Level4> <Level5>02AQ006309</Level5> <Level6>02AQ006309</Level6> <Level7>02AQ006309</Level7> <Level8>02AQ006309</Level8> </Hierarchy> <Hierarchy> <Material>335165140780</Material> <Level1>02</Level1> <Level2>02AQ</Level2> <Level3>02AQ006</Level3> <Level4>02AQ006309</Level4> <Level5>02AQ006309</Level5> <Level6>02AQ006309</Level6> <Level7>02AQ006309</Level7> <Level8>02AQ006310</Level8> </Hierarchy> <Texts> <ProductHierarchy>02AQ006310</ProductHierarchy> <Language>A</Language> <Description>CREAM</Description> </Texts> <Texts> <ProductHierarchy>02AQ006309</ProductHierarchy> <Language>B</Language> <Description>CREAM</Description> </Texts> as per the requirement, xsl should check the matched value of GSKProductHierarchy/Hierarchy/Level8 in the GSKProductHierarchy/Texts/ProductHierarchy elements...and its should result as below flat file. 335165140779|02|02AQ|02AQ006|02AQ006309|02AQ006309|02AQ006309|02AQ006309|02AQ006309|02AQ006309|A|CREAM| 335165140780|02|02AQ|02AQ006|02AQ006309|02AQ006309|02AQ006309|02AQ006309|02AQ006310|02AQ006310|B|CREAM| Right now I have the below xslt, <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:exsl="http://exslt.org/common" xmlns:set="http://exslt.org/sets" xmlns:str="http://exslt.org/strings" xmlns:java="http://xml.apache.org/xslt/java" xmlns:saxon="http://saxon.sf.net/" exclude-result-prefixes="exsl set str java saxon"> <xsl:output method="text" indent="yes"/> <xsl:variable name="VarPipe" select="'|'"/> <xsl:variable name="VarBreak" select="'&#xa;'"/> <xsl:template match="/"> <xsl:for-each select="GSKProductHierarchy/Hierarchy"> <xsl:variable name="currentIndex" select="position()"/> <xsl:variable name="Level8" select="Level8"/> <xsl:variable name="ProductHierarchy" select="../Texts[$currentIndex]/ProductHierarchy"/> <xsl:if test="$Level8=$ProductHierarchy"> <xsl:value-of select="Material"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level1"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level2"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level3"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level4"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level5"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level6"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level7"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level8"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="../Texts[$currentIndex]/ProductHierarchy"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="../Texts[$currentIndex]/Language"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="../Texts[$currentIndex]/Description"/> <xsl:value-of select="$VarPipe"/> <xsl:if test="not(position() = last())"> <xsl:value-of select="$VarBreak"/> </xsl:if> </xsl:if> </xsl:for-each> </xsl:template> can anyone please suggest what function should i need to use to get the desired result. Regards, Giri

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  • how to get child nodes in xsl

    - by ppp
    here my code- <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="ArrayOfLinkEntity" name="bindLink"> <ul> <xsl:for-each select="LinkEntity[ParentLinkId=0]"> <li> <xsl:variable name="linkId" select="LinkId"/> <xsl:variable name="child" select="count(/ArrayOfLinkEntity/LinkEntity[ParentLinkId=$linkId])"/> <xsl:value-of select="$child"/> <xsl:choose> <xsl:when test="($child &gt; 0)"> <a href="#" data-flexmenu="flexmenu1" onclick="javascript:setPageLinkId({$linkId});"> <xsl:value-of select="LinkTitle"/> <img src="../images/down.gif" border="0"/> </a> </xsl:when> <xsl:otherwise > <a href="#" onclick="javascript:setPageLinkId({$linkId});"> <xsl:value-of select="LinkTitle"/> </a> </xsl:otherwise> </xsl:choose> </li> </xsl:for-each> </ul> </xsl:template> </xsl:stylesheet> but I am getting $child=0 always.but there exists children. my xml structure- <ArrayOfLinkEntity xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <LinkEntity> <EntityId>00000000-0000-0000-0000-000000000000</EntityId> <LinkId>1</LinkId> <SequenceNo>1</SequenceNo> <ParentLinkId>0</ParentLinkId> <LinkTitle>Home</LinkTitle> <SubLink /> </LinkEntity> ... </ArrayOfLinkEntity> What should I do? Please suggest.

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  • XSL file handling through javascript

    - by Zaid Iqbal
    i want to handle my xsl file through my javascript code. I made my XSL file but i want to dynamically change my XSL file at run time.As in add more attributes in header or data. My javascript code as follow` <script> function loadXMLDoc(dname) { if (window.XMLHttpRequest) { xhttp=new XMLHttpRequest(); } else { xhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xhttp.open("GET",dname,false); xhttp.send(""); return xhttp.responseXML; } function displayResult() { xml=loadXMLDoc("cdcatalog.xml"); xsl=loadXMLDoc("cdcatalog.xsl"); // code for IE if (window.ActiveXObject) { ex=xml.transformNode(xsl); document.getElementById("example").innerHTML=ex; } // code for Mozilla, Firefox, Opera, etc. else if (document.implementation && document.implementation.createDocument) { xsltProcessor=new XSLTProcessor(); xsltProcessor.importStylesheet(xsl); resultDocument = xsltProcessor.transformToFragment(xml,document); document.getElementById("example").appendChild(resultDocument); } } </script> My XSL file code: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <html> <body> <h2>My CD Collection</h2> <table border="1"> <tr bgcolor="#9acd32"> <th align="left">Title</th> <th align="left">Artist</th> <th align="left">Country</th> </tr> <xsl:for-each select="catalog/cd"> <tr> <td><xsl:value-of select="title" /></td> <td><xsl:value-of select="artist" /></td> <td><xsl:value-of select="country" /></td> </tr> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet> `

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  • How to convert XML to a HTML table using XSL for-each

    - by Meeeee
    I am trying to convert some XML with XSL, to make the output look better and more readable for other users. I have some XML along the lines of: <G> <OE> <example1>Sample 1</example1> <example2>Sample 2</example2> <var name="name1"> <integer>1</integer> </var> </OE> </G> I want to get all the details from it and display it in a table so I use the following XSL code: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:template match="/"> <html> <body> <h2>Heading</h2> <table border="1"> <tr bgcolor="#3399FF"> <th>Example 1</th> <th>Example 2</th> <th>Var name</th> <th>Int</th> </tr> <xsl:for-each select="G/OE"> <xsl:for-each select="var"> <tr> <td> <xsl:value-of select="Example 1" /> </td> <td> <xsl:value-of select="Example 2" /> </td> <td> <xsl:value-of select="@name" /> </td> <td> <xsl:value-of select="integer" /> </td> </tr> </xsl:for-each> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet> I know that the following XSL won't work properly. I want the output to be: Sample 1, Sample 2, name1, 1 - in a table format. My problem is I don't know how to do this. In the above XSL code it will only retrieve var and integer. If I only use the top <xsl:for-each>, then only the first two are retrieved. I have tried moving the 2nd <xsl:for-each> after the first to have been selected, so between: <td><xsl:value-of select="Example 2"/></td> and <td><xsl:value-of select="@name"/></td> I get an error. Is there any way to solve this problem? Thanks for the help.

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  • Issue with XSL for website sitemap XML

    - by Lucifer
    Hi The XSL for a website sitemap is not working as expected. The URL elements are not being looped through? Please can you take a look: XML: http://www.telephonesystems.co.uk/sitemap.xml XSL: http://www.telephonesystems.co.uk/css/sitemap.xsl Thanks

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  • i have code below where i need to develop the xsl-fo file using loop

    - by karthick
    <?xml version="1.0" encoding="iso-8859-1"?> <!--<!DOCTYPE svg PUBLIC "-//W3C//DTD SVG 1.1//EN" "http://www.w3.org/Graphics/SVG/1.1/DTD/svg11.dtd">--> <!-- Generator: Arbortext IsoDraw 7.0 --> <?xml-stylesheet type="text/xsl" href="file:///C:/Documents%20and%20Settings/Admin/Desktop/Info%20Tech/task--2/taskbaba.xsl"?> <svg width="100%" height="100%" viewBox="0 0 214.819 278.002"> <g id="Catalog"> <text transform="matrix(0.984 0 0 0.93 183.515 265.271)" stroke="none" fill="#000000" font-family="'Helvetica'" font-size="3.174"/> <text transform="matrix(0.994 0 0 0.93 7.235 265.3)" stroke="none" fill="#000000" font-family="'Helvetica'" font-size="3.174">087156-8-</text> <text transform="matrix(0.995 0 0 0.93 21.708 265.357)" stroke="none" fill="#000000" font-family="'Helvetica'" font-size="3.174" font-weight="bold">AB</text> <text x="103.292" y="265.298" stroke="none" fill="#000000" font-family="'Helvetica'" font-size="3.174">P. 1/1</text> <g id="IC_TextBlock.1"> <g> <text transform="matrix(0.994 0 0 0.93 192.812 8.076)" stroke="none" fill="#000000" font-family="'Helvetica'" font-size="4.586" font-weight="bold">Fittings</text> <text transform="matrix(0.994 0 0 0.93 188.492 13.323)" stroke="none" fill="#000000" font-family="'Helvetica'" font-size="4.586" font-weight="bold">Raccords</text> <text transform="matrix(0.994 0 0 0.93 183.431 18.571)" stroke="none" fill="#000000" font-family="'Helvetica'" font-size="4.586" font-weight="bold">Conexiones</text> </g> </g> </svg>

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  • Link XSL Style Sheet to XForms generated XML document

    - by iHeartGreek
    Hi! Through XForms, I generate an XML document. I need this XML document to be transformed by a specific XSL. How do I link the XSL to the XML through XForms? Example of link: <?xml-stylesheet type="text/xsl" href="test.xsl"?> (The XML doc gets regenerated every time the XForms submits to it.. so I cannot hardcode the link in the XML doc, in needs to be done through the XForms) Thanks!

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  • Get subdomain of XML page from XSL

    - by fudgey
    I am working with a guild hosting site that provides an XML/XSL transformation widget where all I need to do is enter the URL for the XML and XSL and it does the rest. I have written an XSL transform to display a World of Warcraft armory page: Here is an example XML page (view source to see it) of the group I'm trying to help now. So, the user is entering their own XML page url (which has an eu subdomain in this case, but it is not within the XML itself). So when I make links to the character url, I need to add the entire url <a target="_blank" href="http://eu.wowarmory.com/character-sheet.xml?{@url}"> <xsl:value-of select="@name"/> </a> But I can't just set the domain to eu since there are multiple regions. Here are the possibilities: us = www, europe = eu, korea = kr, china = cn and taiwan = tw. Here is a snippet of the XML which shows the url parameters: <character achPoints="4275" classId="3" genderId="0" level="80" name="Virtex" raceId="4" rank="2" url="r=Drek%27Thar&amp;cn=Virtex"/> I guess I could just have the user add a small bit of HTML with their region in another part of their page, something like <div id="region">eu</div>, but I'm trying to make this work without any extra coding on their part. Edit: Ok, my question explicitly stated: How do I get the URL subdomain using XSL?

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  • How to use an expression in xsl:include elment in an XSLT processing

    - by addinquy
    I need to include an XSLT that exists in 2 variants, depending on a param value. However, it's seems to be not possible to write an expression in the href attribute of the xsl:include element. My last trial looks like that: < xsl:param name="ml-fmt" select="mono"/ ... < xsl:include href="{$ml-fmt}/format.xsl"/ The XSLT engine used is Saxon 9.2.0.6 Have anybody an idea about how I could do something close to that ?

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  • XSL - How to tell if element is last in series

    - by Chris
    I have an XSL template that is called (below). What I would like to do is be able to tell if I am the last Unit being called. <xsl:template match="Unit[@DeviceType = 'Node']"> <!-- Am I the last Unit in this section of xml? --> <div class="unitchild"> Node: #<xsl:value-of select="@id"/> </div> </xsl:template> Example XML <Unit DeviceType="QueueMonitor" Master="1" Status="alive" id="7"> <arbitarytags /> <Unit DeviceType="Node" Master="0" Status="alive" id="8"/> <Unit DeviceType="Node" Master="0" Status="alive" id="88"/> </Unit>

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  • Square Brackets in XSL-FO

    - by Igman
    I am attempting to create a list in XSL-FO using a square bracket. I have been able to get it working using the standard unicode bullet character (&#8226;) but I just can't seem to get it working for square brackets. I have tried using &#9632;, but that does not seem to work. It is important that i can get the square bullets working because I am matching an existing file format.Any help in getting this working would be greatly appreciated.

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  • Rotate text in XSL-FO

    - by Shekar_XSL
    Hi, I am generating the xsl-fo document for my XML content and then passing this content to one of the third party DLL that will generate the PDF. I have a requirement to display a test in 45 degrees angle. How to achive this? Thanks

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