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  • Debugging XSLT with extension objects in Visual Studio 2010

    - by Alex Ciminian
    I'm currently working on a project that involves a lot of XSLT transformations and I really need a debugger (I have XSLTs that are 1000+ lines long and I didn't write them :-). The project is written in C# and makes use of extension objects: xslArg.AddExtensionObject("urn:<obj>", new <Obj>()); From my knowledge, in this situation Visual Studio is the only tool that can help me debug the transformations step-by-step. The static debugger is no use because of the extension objects (it throws an error when it reaches elements that reference their namespace). Fortunately, I've found this thread which gave me a starting point (at least I know it can be done). After searching MSDN, I found the criteria that makes stepping into the transform possible. They are listed here. In short: the XML and the XSLT must be loaded via a class that has the IXmlLineInfo interface (XmlReader & co.) the XML resolver used in the XSLTCompiledTransform constructor is file-based (XmlUriResolver should work). the stylesheet should be on the local machine or on the intranet (?) From what I can tell, I fit all these criteria, but it still doesn't work. The relevant code samples are posted below: // [...] xslTransform = new XslCompiledTransform(true); xslTransform.Load(XmlReader.Create(new StringReader(contents)), null, new BaseUriXmlResolver(xslLocalPath)); // [...] // I already had the xml loaded in an xmlDocument // so I have to convert to an XmlReader XmlTextReader r = new XmlTextReader(new StringReader(xmlDoc.OuterXml)); XsltArgumentList xslArg = new XsltArgumentList(); xslArg.AddExtensionObject("urn:[...]", new [...]()); xslTransform.Transform(r, xslArg, context.Response.Output); I really don't get what I'm doing wrong. I've checked the interfaces on both XmlReader objects and they implement the required one. Also, BaseUriXmlResolver inherits from XmlUriResolver and the stylesheet is stored locally. The screenshot below is what I get when stepping into the Transform function. First I can see the stylesheet code after stepping through the parameters (on template-match), I get this: If anyone has any idea why it doesn't work or has an alternative way of getting it to work I'd be much obliged :). Thanks, Alex

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  • XSLT: How to reverse output without sorting

    - by prometoys
    Hi, I have a list of items: a x c z and I want as output z c x a I have no order information in the file and I just want to reverse the lines. The last line in the source file should be first line in the output. How can I solve this problem with XSLT without sorting by number etc.

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  • Docbook-xslt chapter id matching

    - by Jerry Jacobs
    Dear all, I would like to write a xslt rule if it matches a certain chapter ID that it sets autolabel to zero on the section. in pseudo code: IF CHAPTER == LOGBOOK SECTION.AUTOLABEL = 0 ELSE SECTION.AUTOLABEL = 1 ENDIF But after reading the docbook xsl website and docbook xsl reference i'm still unable to figure out how to do it. Maybe someone can push me in the right direction, because i'm new in docbook and xls(t) Kind regards, Jerry

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  • XSLT: Splitting none continues Elements/Grouping continues Elements

    - by Gerald
    Hi! Need some help with this problem in implementing with Xslt, I had already implemented a java code of this one using sax parser but it is a troublesome due to customer request to change something... so we are doing it now using an XSLT with don't need to be compiled and deployed to a web server. I have an xml like the one below Example 1: <ShotRows> <ShotRow row="3" col="3" bit="1" position="1"/> <ShotRow row="3" col="4" bit="1" position="2"/> <ShotRow row="3" col="5" bit="1" position="3"/> <ShotRow row="3" col="6" bit="1" position="4"/> <ShotRow row="3" col="7" bit="1" position="5"/> <ShotRow row="3" col="8" bit="1" position="6"/> <ShotRow row="3" col="9" bit="1" position="7"/> <ShotRow row="3" col="10" bit="1" position="8"/> <ShotRow row="3" col="11" bit="1" position="9"/> </ShotRows> Output 1: <ShotRows> <ShotRow row="3" colStart="3" colEnd="11" /> </ShotRows> -- Be cause the col is continues from 3 to 11 Example 2: <ShotRows> <ShotRow row="3" col="3" bit="1" position="1"/> <ShotRow row="3" col="4" bit="1" position="2"/> <ShotRow row="3" col="6" bit="1" position="3"/> <ShotRow row="3" col="7" bit="1" position="4"/> <ShotRow row="3" col="8" bit="1" position="5"/> <ShotRow row="3" col="10" bit="1" position="6"/> <ShotRow row="3" col="11" bit="1" position="7"/> <ShotRow row="3" col="15" bit="1" position="8"/> <ShotRow row="3" col="19" bit="1" position="9"/> </ShotRows> Output 2: <ShotRows> <ShotRow row="3" colStart="3" colEnd="4" /> <ShotRow row="3" colStart="6" colEnd="8" /> <ShotRow row="3" colStart="10" colEnd="11" /> <ShotRow row="3" colStart="15" colEnd="15" /> <ShotRow row="3" colStart="19" colEnd="19" /> </ShotRows> -- Basic idea is to group any continues col into one element, like the col 3 to 4, col 6 to 8, col 10 to 11, col 15 is only one, and col 19 is only one. Thanks in advance. Sincerely, Gerald

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  • XSLT Document function returns empty result on Maven POM

    - by user328618
    Greetings! I want to extract some properties from different Maven POMs in a XSLT via the document function. The script itself works fine but the document function returns an empty result for the POM as long as I have the xmlns="http://maven.apache.org/POM/4.0.0" in the project tag. If I remove it, everything works fine. Any idea how the make this work while leaving the xmlns attribute where it belongs or why this doesn't work with the attribute in place? Here comes the relevant portion of my XSLT: <xsl:template match="abcs"> <xsl:variable name="artifactCoordinate" select="abc"/> <xsl:choose> <xsl:when test="document(concat($artifactCoordinate,'-pom.xml'))"> <abc> <ID><xsl:value-of select="$artifactCoordinate"/></ID> <xsl:copy-of select="document(concat($artifactCoordinate,'-pom.xml'))/project/properties"/> </abc> </xsl:when> <xsl:otherwise> <xsl:message terminate="yes"> Transformation failed: POM "<xsl:value-of select="concat($artifactCoordinate,'-pom.xml')"/>" doesn't exist. </xsl:message> </xsl:otherwise> </xsl:choose> And, for completeness, a POM extract with the "bad" attribute: <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd"> <modelVersion>4.0.0</modelVersion> <!-- ... --> <properties> <proalpha.version>[5.2a]</proalpha.version> <proalpha.openedge.version>[10.1B]</proalpha.openedge.version> <proalpha.optimierer.version>[1.1]</proalpha.optimierer.version> <proalpha.sonic.version>[7.6.1]</proalpha.sonic.version> </properties> </project>

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  • DataContractSerializer and XSLT not Serializing Class Properties

    - by Russ Clark
    I've written a simple Employee class that I'm trying to serialize to an XDocument and then use XSLT to transform the document to a page that displays both the properties (Name and ID) from the Employee class, and an html form with 2 radio buttons (Approve and Reject) and a submit button. Here is the Employee class: [Serializable, DataContract(Namespace="XSLT_MVC.Controllers/")] public class Employee { [DataMember] public string Name { get; set; } [DataMember] public int ID { get; set; } public Employee() { } public Employee(string name, int id) { Name = name; ID = id; } public XDocument GetDoc() { XDocument doc = new XDocument(); var serializer = new DataContractSerializer(typeof(Employee)); using (var writer = doc.CreateWriter()) { serializer.WriteObject(writer, this); writer.Close(); } return doc; } } And here is the XSLT file: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <html> <body> <xsl:value-of select="Employee/Name"/> <br /> <xsl:value-of select="Employee/ID"/> <br /> <form method="post" action="/Home/ProcessRequest?id={Employee/ID}"> <input id="Action" name="Action" type="radio" value="Approved"></input> Approved <br /> <input id="Action" name="Action" type="radio" value="Rejected"></input> Rejected <br /> <input type="submit" value="Submit"></input> </form> </body> </html> </xsl:template> </xsl:stylesheet> When I run this, all I get is the html form with the 2 radio buttons and the submit button, but not the properties from the Employee class. I saw a separate StackOverflow post that said I need to change the <xsl:template match="/"> to match on the namespace of my Employee class like this: <xsl:template match="/XSLT_MVC.Controllers"> but when I do that, now all I get are the Employee properties, and not the html form with the 2 radio buttons and the submit button. Does anyone know what needs to be done so that my transform will select and display both the Employee properties and the html form?

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  • Translating itunes affiliate rss via xslt

    - by jd
    I can't get this working for the life of me. Here is a snippet of the xml I get from an RSS feed from itunes affiliate. I want top print the values within tags but I cannot for some reason: <?xml version="1.0" encoding="utf-8"?> <feed xmlns:im="http://itunes.apple.com/rss" xmlns="http://www.w3.org/2005/Atom" xml:lang="en"> <id>http://ax.itunes.apple.com/WebObjects/MZStoreServices.woa/ws/RSS/toppaidapplications/sf=143441/limit=100/genre=6014/xml</id><title>iTunes Store: Top Paid Applications</title><updated>2010-03-24T15:36:42-07:00</updated><link rel="alternate" type="text/html" href="http://itunes.apple.com/WebObjects/MZStore.woa/wa/viewTop?id=25180&amp;popId=30"/><link rel="self" href="http://ax.itunes.apple.com/WebObjects/MZStoreServices.woa/ws/RSS/toppaidapplications/sf=143441/limit=100/genre=6014/xml"/><icon>http://phobos.apple.com/favicon.ico</icon><author><name>iTunes Store</name><uri>http://www.apple.com/itunes/</uri></author><rights>Copyright 2008 Apple Inc.</rights> <entry> <updated>date</updated> <id>someID</id> <title>a</title> <im:name>b</im:name> </entry> <entry> <updated>date2/updated> <id>someID2</id> <title>a2</title> <im:name>b2</im:name> </entry> </feed> If I try <xsl:apply-templates match="entry"/> it spits out the entire contents of file. If I use <xsl:call-template name="entry"> it will show only one entry and I have to use <xsl:value-of select="//*[local-name(.)='name']"/> to get name but that's a hack. I've used xslt before for xml without namespaces and xml that has proper parent child relationships but not like this RSS feed. Notice entry is not wrapped in entries or anything. Any help is appreciated. I want to use xslt because I want to alter the itunes link to go through my affiliate account - so something automated wouldn't work for me.

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  • XSLT: Whole table columns count.

    - by kalininew
    Good afternoon, gentlemen. Please help us solve the problem, I do not have enough brains to solve it by myself. There is a table, you must define "simple" it or "complicated". Table "simple" if each row contain only two column, otherwise it is "complicated" table. How to do this means xslt.

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  • Xslt external parameter

    - by enrico
    In my server side TransformerFactory tfactory = TransformerFactory.newInstance(); Transformer transformer = tfactory.newTransformer( new StreamSource("mytext.xsl")); transformer.setParameter("parametro","hope"); transformer.transform( new DOMSource(document), outputStream ); --mytext.xslt-- . . . . . . why the value of $parametro isn't "hope" in my html output? Thanks

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  • Dynamic Data Manipulation using XSLT from XML

    - by Imrul
    I am not working with XSLT not too long. I read that variable of XSLT can't be updated on the fly, so how can i do the following task. I want to sum up Purchase & Sales and put them into a variable, and make some decision according to these values. (For example, if Purchase is greater then sales then do something if not, do something else) <rows> <row> <col attr2="Purchase" >100.00</col> <col attr2="Sales" >100.00</col> </row> <row > <col attr2="Purchase" >19.16</col> <col attr2="Sales" >12.94</col> </row> <row > <col attr2="Purchase" >0.67</col> <col attr2="Sales" >2.74</col> </row> <row > <col attr2="Purchase" >71.95</col> <col attr2="Sales" >61.54</col> </row> <row > <col attr2="Purchase" >3.62</col> <col attr2="Sales" >14.72</col> </row> <row > <col attr2="Purchase">8.80</col> <col attr2="Sales">1.22</col> </row> <row > <col attr2="Purchase" >-4.28</col> <col attr2="Sales" >6.53</col> </row> </rows> if anyone knows, please help me.

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  • Sorting based on existing elements in xslt

    - by Teelo
    Hi , I want to sort in xslt based on existing set of pattern . Let me explain with the code: <Types> <Type> <Names> <Name>Ryan</Name> </Names> <Address>2344</Address> </Type> <Type> <Names> </Name>Timber</Name> </Names> <Address>1234</Address> </Type> <Type> <Names> </Name>Bryan</Name> </Names> <Address>34</Address> </Type> </Types> Right now I m just calling it and getting it like (all hyperlinks) Ryan Timber Bryan Now I don't want sorting on name but I have existing pattern how I want it to get displayed.Like Timber Bryan Ryan (Also I don't want to lose the url attached to my names earlier while doing this) I was thinking of putting earlier value in some array and sort based on the other array where I will store my existing pattern. But I am not sure how to achieve that.. My xslt looks like this now(there can be duplicate names also) <xsl:for-each select="/Types/Type/Names/Name/text()[generate-id()=generate-id(key('Name',.)[1])]"> <xsl:call-template name="typename"> </xsl:call-template> </xsl:for-each> <xsl:template name="typename"> <li> <a href="somelogicforurl"> <xsl:value-of select="."/> </a> </li> </xsl:template> I am using xsl 1.0

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  • XSLT, JSTL e JSF

    - by Paulo S.
    I have a xml file which I want to transform in a jsf code page. To do that I've created a xsl file. xml: <?xml version='1.0' encoding='ISO-8859-1'?> <questionario xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' xsi:noNamespaceSchemaLocation='Schema2.xsd'> <componente nome='input'> <id>input1</id> </componente> <componente nome='input'> <id>input2</id> </componente> </questionario> code: <%@ taglib uri="http://java.sun.com/jstl/core_rt" prefix="c" %> <%@ taglib uri="http://java.sun.com/jsp/jstl/xml" prefix="x" %> <c:set var="xml" value="${questionarioXSLBean.xml}"/> <c:set var="xsl"> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0" xmlns:f="http://java.sun.com/jsf/core" xmlns:h="http://java.sun.com/jsf/html" exclude-result-prefixes="f h"> <xsl:template match="/"> <xsl:for-each select="questionario/componente"> <xsl:if test="attribute::nome = 'input'"> <xsl:variable name="id"> <xsl:value-of select="id" /> </xsl:variable> <h:inputText id="{$id}"/> </xsl:if> </xsl:for-each> </xsl:template> </xsl:stylesheet> </c:set> <x:transform xml="${xml}" xslt="${xsl}" /> The problem is that nothing is shown in my screen because the generated code for <h:inputText id="input1"/> is <h:inputText id="input_1" xmlns:h="http://java.sun.com/jsf/html"/> how can I replace the xmlns:h="http://java.sun.com/jsf/html" or suppress it. Thanks! Update: Let me clarify what I want to do. I want to generate a jsf page dynamically depending on the attributes of a xml file, for instance, 2 input texts, 3 check boxes, etc. To make the transformation to jsf I thought in two approaches, one using jstl and another using xslt. The problem with the former is that I couldn't integrate jstl with jsf code (to set jsf components attributes using jstl variables) and with the last approach, I'm facing the problem described above.I wouldn't like to create components in java (UIComponents). Any suggestions?

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  • DataContractSerializer and XSLT

    - by Russ Clark
    I've got a simple Employee class that I'm trying to serialize to an XDocument and then use XSLT to transform the document to a page that displays both the properties (Name and ID) from the Employee class, and an html form with 2 radio buttons (Approve and Reject) and a submit button. Here is the Employee class: [Serializable, DataContract(Namespace="XSLT_MVC.Controllers/")] public class Employee { [DataMember] public string Name { get; set; } [DataMember] public int ID { get; set; } public Employee() { } public Employee(string name, int id) { Name = name; ID = id; } public XDocument GetDoc() { XDocument doc = new XDocument(); var serializer = new DataContractSerializer(typeof(Employee)); using (var writer = doc.CreateWriter()) { serializer.WriteObject(writer, this); writer.Close(); } return doc; } } And here is the XSLT file: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <html> <body> <xsl:value-of select="Employee/Name"/> <br /> <xsl:value-of select="Employee/ID"/> <br /> <form method="post" action="/Home/ProcessRequest?id={Employee/ID}"> <input id="Action" name="Action" type="radio" value="Approved"></input> Approved <br /> <input id="Action" name="Action" type="radio" value="Rejected"></input> Rejected <br /> <input type="submit" value="Submit"></input> </form> </body> </html> </xsl:template> </xsl:stylesheet> When I run this, all I get is the html form with the 2 radio buttons and the submit button, but not the properties from the Employee class. I saw a separate StackOverflow post that said I need to change the <xsl:template match="/"> to match on the namespace of my Employee class like this: <xsl:template match="/XSLT_MVC.Controllers">, but when I do that, now all I get are the Employee properties, and not the html form with the 2 radio buttons and the submit button. Does anyone know what needs to be done so that my transform will select and display both the Employee properties and the html form?

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  • basic operations for modifying a source document with XSLT

    - by SpliFF
    All the tutorials and examples I've found of XSLT processing seem to assume your destination will be a significantly different format/structure to your source and that you know the structure of the source in advance. I'm struggling with finding out how to perform simple "in-place" modifications to a HTML document without knowing anything else about its existing structure. Could somebody show me a clear example that, given an arbitrary unknown HTML source will: 1.) delete the classname 'foo' from all divs 2.) delete a node if its empty (ie <p></p>) 3.) delete a <p> node if its first child is <br> 4.) add newattr="newvalue" to all H1 5.) replace 'heading' in text nodes with 'title' 6.) wrap all <u> tags in <b> tags (ie, <u>foo</u> -> <b><u>foo</u></b>) 7.) output the transformed document without changing anything else The above examples are the primary types of transform I wish to accomplish. Understanding how to do the above will go a long way towards helping me build more complex transforms. To help clarify/test the examples here is a sample source and output, however I must reiterate that I want to work with arbitrary samples without rewriting the XSLT for each source: <!doctype html> <html> <body> <h1>heading</h1> <p></p> <p><br>line</p> <div class="foo bar"><u>baz</u></div> <p>untouched</p> </body> </html> output: <!doctype html> <html> <body> <h1 newattr="newvalue">title</h1> <div class="bar"><b><u>baz</u></b></div> <p>untouched</p> </body> </html>

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  • XSLT: Transform XML files tree

    - by Myniva
    I have the following file structure (XML files 'index.xml' in nested folders): index.xml foo/index.xml foo/sub/index.xml foo/.../index.xml bar/.../index.xml Now I have to transform each of this XML files with a given XSL stylesheet. The result should be the same folder structure (overwriting would be OK). What would be your approach to achieve this? My system: OS X 10.6, Saxon XSLT processor

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  • XSLT for-each loop for element collection

    - by brain_pusher
    Is it possible to make a for-each loop in XSLT not for a node set, but for my own collection of elements? For example, I split some string and have a string collection as a result. And I need to create a node for each item in the collection. I know that issue can be solved with a recursive template, but I want to know if it is possible to avoid a recursion.

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  • HTML encode on a XSLT

    - by Hugo Palma
    I would like to convert some value from a XML attribute into valid HTML with entities. So that for example the string "olá" from the XML would be transformed from the XSLT into "ol&#225;" I can't find any xsl function to do this. Any ideas ?

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