Search Results

Search found 19090 results on 764 pages for 'greatest n per group'.

Page 50/764 | < Previous Page | 46 47 48 49 50 51 52 53 54 55 56 57  | Next Page >

  • Website access per client and each client having multiple users Sample Application

    - by windson
    I'm interested in building a web application in .NET that is scalable to multiple Clients and each and every Client has users associated with them. Suppose that my website is xyz.com and I have 3 clients "abc", "klm", "pqr" and I want to give access to features of xyz.com under the link as follows www.xyz.com/abc www.xyz.com/klm www.xyz.com/pqr and Client abc has N users and I want to set 3 roles for every client's user role. Is there any sample application in .NET that support this kind of website access per client having multiple users? And If I use ASP.NET Membership will that be a suitable membership solution or Do I need to opt for any other type of Membership defined by my own or already available in open source market for .NET. Edit: All the clients will have same functionality. I would like to build a generic model for www.xyz.com/{whatever} so that in future if a new client want to register with me he/she just have to give client name and up on adding client name all the features avaiable to exising clients will be applicable.

    Read the article

  • RSS feed per tag

    - by niaher
    Hi. Suppose stackoverflow.com wanted to have an RSS feed per each tag. They would probably have requests like stackoverflow.com/rss?tag=aspnet to return appropriate RSS feeds. This is the easy part. Now when the user requested stackoverflow.com/rss?tag=aspnet he would see some XML. Instead it would be better to show a page where user can choose which RSS reader he wants to subscribe with (just like feedburner.com). My question is: is there any ready-made code (html+javascript) that I can copy-paste to create such a subscription page? Basically I want to copy feedburner.com's subscription page onto my own site. PS - I would be happy using feedburner.com, but it would require me to create a feed for each tag manually, which is impractical.

    Read the article

  • Cache bandwidth per tick for modern CPUs

    - by osgx
    Hello What is a speed of cache accessing for modern CPUs? How many bytes can be read or written from memory every processor clock tick by Intel P4, Core2, Corei7, AMD? Please, answer with both theoretical (width of ld/sd unit with its throughput in uOPs/tick) and practical numbers (even memcpy speed tests, or STREAM benchmark), if any. PS it is question, related to maximal rate of load/store instructions in assembler. There can be theoretical rate of loading (all Instructions Per Tick are widest loads), but processor can give only part of such, a practical limit of loading.

    Read the article

  • Table per subclass inheritance relationship: How to query against the Parent class without loading a

    - by Arthur Ronald F D Garcia
    Suppose a Table per subclass inheritance relationship which can be described bellow (From wikibooks.org - see here) Notice Parent class is not abstract @Entity @Inheritance(strategy=InheritanceType.JOINED) public class Project { @Id private long id; // Other properties } @Entity @Table(name="LARGEPROJECT") public class LargeProject extends Project { private BigDecimal budget; } @Entity @Table(name="SMALLPROJECT") public class SmallProject extends Project { } I have a scenario where i just need to retrieve the Parent class. Because of performance issues, What should i do to run a HQL query in order to retrieve the Parent class and just the Parent class without loading any subclass ???

    Read the article

  • Java - Confused by the one class per file rule

    - by Mark
    The one class per file rule in Java has me a bit confused. I writing an Android app and trying to implement the accepted answer to this question: Common class for AsyncTask in Android? which calls for an interface definition which class A implements and class B accepts as an argument to its constructor. So I need an A.java and a B.java, but where does the interface go? Does it need a separate java file itself? Do I have to define it inside both A and B? If not how to import it? Also I will have about 10 different AsyncTask classes, but I don't want to bother creating a new file for each one. What would you recommend? Is there a way to put all 10 classes in one file? Or should I create a big if/then block inside the class and pass an argument telling it which of the 10 different tasks I want it to do?

    Read the article

  • Getting the most recent entry per group in a select statement

    - by TheObserver
    I have 3 tables to join to get table1.code, table1.series, table2.entry_date, table3.title1 and I'm trying to get the most recent non null table3.title1 grouped by table1.code and table1.series. select table1.code, table1.series, max(table2.entry_date), table3.Title1 from table3 INNER JOIN table2 ON table3.ID = table2.ID INNER JOIN table1 ON table2.source_code = table1.code where table3.Title1 is not NULL group by table1.code, table1.series, table3.Title1 seems to give me all entries with a non null title1 instead of the most recent one. How should I structure the query to just pick the newest version of Title1 per code & series?

    Read the article

  • Count number of messages per user

    - by Pr0no
    Consider the following tables: users messages ----------------- ----------------------- user_id messages msg_id user_id content ----------------- ----------------------- 1 0 1 1 foo 2 0 2 1 bar 3 0 3 1 foobar 4 3 baz 5 3 bar I want to count the number of messages per user and insert the outcome into users.messages, like this: users ----------------- user_id messages ----------------- 1 3 2 0 3 2 I could use PHP to perform this operation, pseudo: foreach ($user_id in users) { $count = select count(msg_id) from messages where user_id = $user_id update users set messages = $count } But this is probably very inefficient as compared to one query executed in MySQL directly: UPDATE users SET messages = ( SELECT COUNT(msg_id) FROM messages ) But I'm sure this is not a proper query. Therefore, any help would be appreciated :-)

    Read the article

  • The Scala way to use one actor per socket connection

    - by Stefan
    I am wondering how it is possible to avoid one socket connection pr. thread in Scala. I have thought a lot about it, but I always end up with some code which is listening for incoming data for each client connection. The problem is that I want to develop an application which should simultanously handle perhaps a couple of thousand connections. However I will of course not want to create a thread for each connection because of the lack of scalability and context switching. What would be the "right" way to do this. In my world it should be possible to have one actor for each connection without the need to block one thread per actor.

    Read the article

  • Why does Java ArrayList use per-element casting instead of per-array casting?

    - by user1111929
    What happens inside Java's ArrayList<T> (and probably many other classes) is that there is an internal Object[] array = new Object[n];, to which T Objects are written. Whenever an element is read from it, a cast return (T) array[i]; is done. So, a cast on every single read. I wonder why this is done. To me, it seems like they're just doing unnecessary casts. Wouldn't it be more logical and also slightly faster to just create a T[] array = (T[]) new Object[n]; and then just return array[i]; without cast? This is only one cast per array creation, which is usually far less than the number of reads. Why is their method to be preferred? I fail to see why my idea isn't strictly better?

    Read the article

  • West Palm Beach Developers&rsquo; Group Celebrates its Fifth Anniversary as a Member of INETA

    - by Sam Abraham
    Earlier this week marked our fifth anniversary as an INETA group, a fact that we had forgotten but thankfully INETA remembered. In celebrating our membership, INETA sent us a certificate recognizing our membership which we will be sharing with our members at our upcoming meeting. It‘s been a great two-year tenure for me as group co-coordinator working with Venkat Subramanian who had been involved with the group since its inception. Moving into the future we hope to grow both group membership and leadership. We continue to strive to bring added value to our membership which can only happen with your ideas, feedback and involvement in our community-driven group. Our next almost sold-out meeting will be taking place on 8/28/2012 6:30PM (Register at: http://www.fladotnet.com/Reg.aspx?EventID=607) . Will Strohl, DotNetNuke’s Technical Evangelist will be presenting to us an overview on getting started with DNN’s latest 6.2 version all while taking us on a deep dive into its built-in social networking integration features. There is still time to register, but don’t procrastinate! Our September meeting will feature Jonas Stawski, Microsoft MVP sharing with us on SignalR while October will bring us the much anticipated visit by our Microsoft Developer Evangelist Joe Healy who will be talking to us about the latest with Windows 8. Joe will be also presenting in Miami the next day after our event in case you miss his West Palm appearance. We look forward to meeting you at our upcoming meetings. All the best --Sam Abraham

    Read the article

  • How big can my SharePoint 2010 installation be?

    - by Sahil Malik
    Ad:: SharePoint 2007 Training in .NET 3.5 technologies (more information). 3 years ago, I had published “How big can my SharePoint 2007 installation be?” Well, SharePoint 2010 has significant under the covers improvements. So, how big can your SharePoint 2010 installation be? There are three kinds of limits you should know about Hard limits that cannot be exceeded by design. Configurable that are, well configurable – but the default values are set for a pretty good reason, so if you need to tweak, plan and understand before you tweak. Soft limits, you can exceed them, but it is not recommended that you do. Before you read any of the limits, read these two important disclaimers - 1. The limit depends on what you’re doing. So, don’t take the below as gospel, the reality depends on your situation. 2. There are many additional considerations in planning your SharePoint solution scalability and performance, besides just the below. So with those in mind, here goes.   Hard Limits - Zones per web app 5 RBS NAS performance Time to first byte of any response from NAS must be less than 20 milliseconds List row size 8000 bytes driven by how SP stores list items internally Max file size 2GB (default is 50MB, configurable). RBS does not increase this limit. Search metadata properties 10,000 per item crawled (pretty damn high, you’ll never need to worry about it). Max # of concurrent in-memory enterprise content types 5000 per web server, per tenant Max # of external system connections 500 per web server PerformancePoint services using Excel services as a datasource No single query can fetch more than 1 million excel cells Office Web Apps Renders One doc per second, per CPU core, per Application server, limited to a maximum of 8 cores.   Configurable Limits - Row Size Limit 6, configurable via SPWebApplication.MaxListItemRowStorage property List view lookup 8 join operations per query Max number of list items that a single operation can process at one time in normal hours 5000 Configurable via SPWebApplication.MaxItemsPerThrottledOperation   Also you get a warning at 3000, which is configurable via SPWebApplication.MaxItemsPerThrottledOperationWarningLevel   In addition, throttle overrides can be requested, throttle overrides can be disabled, and time windows can be set when throttle is disabled. Max number of list items for administrators that a single operation can process at one time in normal hours 20000 Configurable via SPWebApplication.MaxItemsPerThrottledOperationOverride Enumerating subsites 2000 Word and Powerpoint co-authoring simultaneous editors 10 (Hard limit is 99). # of webparts on a page 25 Search Crawl DBs per search service app 10 Items per crawl db 25 million Search Keywords 200 per site collection. There is a max limit of 5000, which can then be modified by editing the web.config/client.config. Concurrent # of workflows on a content db 15. Workflows running in the timer service are not counted in this limit. Further workflows are queued. Can be configured via the Set-SPFarmConfig powershell commandlet. Number of events picked by the workflow timer job and delivered to workflows 100. You can increase this limit by running additional instances of the workflow timer service. Visio services file size 50MB Visio web drawing recalculation timeout 120 seconds Configurable via – Powershell commandlet Set-SPVisioPerformance Visio services minimum and maximum cache age for data connected diagrams 0 to 24 hours. Default is 60 minutes. Configurable via – Powershell commandlet Set-SPVisioPerformance   Soft Limits - Content Databases 300 per web app Application Pools 10 per web server Managed Paths 20 per web app Content Database Size 200GB per Content DB Size of 1 site collection 100GB # of sites in a site collection 250,000 Documents in a library 30 Million, with nesting. Depends heavily on type and usage and size of documents. Items 30 million. Depends heavily on usage of items. SPGroups one SPUser can be in 5000 Users in a site collection 2 million, depends on UI, nesting, containers and underlying user store AD Principals in a SPGroup 5000 SPGroups in a site collection 10000 Search Service Instances 20 Indexed Items in Search 100 million Crawl Log entries 100 million Search Alerts 1 million per search application Search Crawled Properties 1/2 million URL removals in search 100 removals per operation User Profiles 2 million per service application Social Tags 500 million per social database Comment on the article ....

    Read the article

  • Post SQL 2008 R2 Launch Thurs 15th London - UK SQL Server User Group is having a Social Event @ the

    - by tonyrogerson
    The UK SQL Server User Group is organising a Social event for SQL and SQL Server professionals, the event will be held after the SQL Server 2008 R2 launch event and is a short walk from that venue. See site for more information: http://sqlserverfaq.com/events/222/Social-for-SQL-and-SQL-Server-professionals-SQL-quiz-meet-your-peers-ask-the-group-Q-A.aspx We are putting some light bites on, if you are coming then do let us know through the site. Neil Hambly who is the London UK SQL Server User Group...(read more)

    Read the article

  • What is the greatest design flaw you have faced in any programming language?

    - by Anto
    All programming languages are having their design flaws simply because not a single language can be perfect, just as with most (all?) other things. That aside, which design fault in a programming language has annoyed you the most through your history as a programmer? Note that if a language is "bad" just because it isn't designed for a specific thing isn't a design flaw, but a feature of design, so don't list such annoyances of languages. If a language is illsuited for what it is designed for, that is of course a flaw in the design. Implementation specific things and under the hood things do not count either.

    Read the article

  • Oracle E-Business Supply Chain Suite Release 12.1.2: Latest & Greatest!

    - by [email protected]
    This week we hosted one of several planned orientation and training sessions for the ASR/ASM sales community.  The purpose of the session was to orient our contact center and marketing associates with the 'hotpoints' of the latest release and to provide a few 'snippets' for the scheduled 'call-down' to the installed base.  Oracle EBS Release 12.1.2 contains some of the most powerful supply chain applications technology available to the industrial, commercial and public sector communities.  They should all be taking advantage of this great capability to drive margins, control costs and achieve compliance.   In today's changing business landscape, organizations need competitive advantage and we see that R12 provides this capability according to our customers leveraging the upgrade.

    Read the article

  • Queyring container with Linq + group by ?

    - by Prix
    public class ItemList { public int GuID { get; set; } public int ItemID { get; set; } public string Name { get; set; } public entityType Status { get; set; } public class Waypoint { public int Zone { get; set; } public int SubID { get; set; } public int Heading { get; set; } public float PosX { get; set; } public float PosY { get; set; } public float PosZ { get; set; } } public List<Waypoint> Routes = new List<Waypoint>(); } I have a list of items using the above class and now I need to group it by ItemID and join the first entry of Routes of each iqual ItemID. So for example, let's say on my list I have: GUID ItemID ListOfRoutes 1 23 first entry only 2 23 first entry only 3 23 first entry only 4 23 first entry only 5 23 first entry only 6 23 first entry only 7 23 first entry only Means I have to group entries 1 to 7 as 1 Item with all the Routes entries. So I would have one ItemID 23 with 7 Routes on it where those routes are the first element of that given GUID Routes List. My question is if it is possible using LINQ to make a statment to do something like that this: var query = from ItemList entry in myList where status.Contains(entry.Status) group entry by entry.ItemID into result select new { items = new { ID = entry.ItemID, Name = entry.Name }, routes = from ItemList m in entry group m.Routes.FirstOrDefault() by n.NpcID into m2 }; So basicly I would have list of unique IDS information with a inner list of all the first entry of each GUID route that had the same ItemID. <<< UPDATE: This would be an example of public List<ItemList> myList = new List<ItemList>(); data: GUID ItemID ListOfRoutes 1 20 Routes[1] 2 20 Routes[2] 3 20 Routes[3] 4 20 Routes[4] 5 20 Routes[5] 6 55 Routes[6] 7 55 Routes[7] 8 55 Routes[8] 9 1 Routes[9] 10 1 Routes[10] As you can see GUID is unique, ItemID can reapeat it self. Each GUID has a Routes list and all routes list have a minimum of 1 entry and above. Routes example. Routes[1] have: Entry Zone SubID Heading PosX PosY PosZ 1 1200 0 100 1029.32 837.21 29.10 2 1200 0 120 1129.32 537.21 29.10 3 1200 0 180 1229.32 137.21 29.10 4 1200 0 360 1329.32 437.21 29.10 5 1200 0 100 1429.32 637.21 29.10 Routes[2] have: Entry Zone SubID Heading PosX PosY PosZ 1 100 0 10 129.32 437.21 29.10 So what I want to do is a list of all entries I have on myList grouped by ItemID maintainning the fields ItemID and Name ... and a new field or item that will have all the first elements of Routes of those GUIDs. For example ItemID 20 would produce the follow result: ItemID, Name, ListOfRoutes This ItemID ListOfRoutes would contain Routes[1] first entry: Entry Zone SubID Heading PosX PosY PosZ 1 1200 0 100 1029.32 837.21 29.10 Routes[2] first entry: Entry Zone SubID Heading PosX PosY PosZ 1 100 0 10 129.32 437.21 29.10 Routes[3], Routes[4], Routes[5] first entries. Example of how myList is feeded: ItemList newItem = new ItemList(); newItem.GUID = GUID; newItem.ItemID = ItemID; newItem.Name = Name; newItem.Status = Status; // Item location ItemList.Waypoint itemLocation = new ItemList.Waypoint(); itemLocation.SubID = SubID; itemLocation.Zone = Zone; itemLocation.Heading = convertHeading(Heading); itemLocation.PosX = PosX; itemLocation.PosY = PosY; itemLocation.PosZ = PosZ; itemLocation.Rest = Rest; newItem.Routes.Add(itemLocation); myList.Add(newItem);

    Read the article

  • Efficient representation of Hierarchies in Hibernate.

    - by Alison G
    I'm having some trouble representing an object hierarchy in Hibernate. I've searched around, and haven't managed to find any examples doing this or similar - you have my apologies if this is a common question. I have two types which I'd like to persist using Hibernate: Groups and Items. * Groups are identified uniquely by a combination of their name and their parent. * The groups are arranged in a number of trees, such that every Group has zero or one parent Group. * Each Item can be a member of zero or more Groups. Ideally, I'd like a bi-directional relationship allowing me to get: * all Groups that an Item is a member of * all Items that are a member of a particular Group or its descendants. I also need to be able to traverse the Group tree from the top in order to display it on the UI. The basic object structure would ideally look like this: class Group { ... /** @return all items in this group and its descendants */ Set<Item> getAllItems() { ... } /** @return all direct children of this group */ Set<Group> getChildren() { ... } ... } class Item { ... /** @return all groups that this Item is a direct member of */ Set<Group> getGroups() { ... } ... } Originally, I had just made a simple bi-directional many-to-many relationship between Items and Groups, such that fetching all items in a group hierarchy required recursion down the tree, and fetching groups for an Item was a simple getter, i.e.: class Group { ... private Set<Item> items; private Set<Group> children; ... /** @return all items in this group and its descendants */ Set<Item> getAllItems() { Set<Item> allItems = new HashSet<Item>(); allItems.addAll(this.items); for(Group child : this.getChildren()) { allItems.addAll(child.getAllItems()); } return allItems; } /** @return all direct children of this group */ Set<Group> getChildren() { return this.children; } ... } class Item { ... private Set<Group> groups; /** @return all groups that this Item is a direct member of */ Set<Group> getGroups() { return this.groups; } ... } However, this resulted in multiple database requests to fetch the Items in a Group with many descendants, or for retrieving the entire Group tree to display in the UI. This seems very inefficient, especially with deeper, larger group trees. Is there a better or standard way of representing this relationship in Hibernate? Am I doing anything obviously wrong or stupid? My only other thought so far was this: Replace the group's id, parent and name fields with a unique "path" String which specifies the whole ancestry of a group, e.g.: /rootGroup /rootGroup/aChild /rootGroup/aChild/aGrandChild The join table between Groups and Items would then contain group_path and item_id. This immediately solves the two issues I was suffering previously: 1. The entire group hierarchy can be fetched from the database in a single query and reconstructed in-memory. 2. To retrieve all Items in a group or its descendants, we can select from group_item where group_path='N' or group_path like 'N/%' However, this seems to defeat the point of using Hibernate. All thoughts welcome!

    Read the article

  • Facebook Invalid OAuth access token signature trying to post an attachment to group wall from PHP

    - by Volodymyr B
    I am an administrator (manager role) of a Facebook Group. I created an app, and stored its id and secret. I want my app to be able to post something on the Facebook group's feed. But when I attempt to post, I get the error 190 Invalid OAuth access token signature, even though I able to successfully obtain the access_token with publish_stream and offline_access scopes. It has the form of NNNNNNNNNNNNNNN|XXXXXXXXXXXXXXXXXXXXXXXXXXX, where N is a number (15) and X is a letter or a number (27). What should I do more to get this accomplished? Here is the code I am using: public static function postToFB($message, $image, $link) { //Get App Token $token = self::getFacebookToken(); // Create FB Object Instance $facebook = new Facebook(array( 'appId' => self::fb_appid, 'secret' => self::fb_secret, 'cookie' => true )); //$token = $facebook->getAccessToken(); //Try to Publish on wall or catch the Facebook exception try { $attachment = array('access_token' => $token, 'message' => $message, 'picture' => $image, 'link' => $link, //'name' => '', //'caption' => '', 'description' => 'More...', //'actions' => array(array('name' => 'Action Text', 'link' => 'http://apps.facebook.com/xxxxxx/')) ); $result = $facebook->api('/'.self::fb_groupid.'/feed/', 'post', $attachment); } catch (FacebookApiException $e) { //If the post is not published, print error details echo '<pre>'; print_r($e); echo '</pre>'; } } Code which returns the token //Function to Get Access Token public static function getFacebookToken($appid = self::fb_appid, $appsecret = self::fb_secret) { $args = array( 'grant_type' => 'client_credentials', 'client_id' => $appid, 'client_secret' => $appsecret, 'redirect_uri' => 'https://www.facebook.com/connect/login_success.html', 'scope' => 'publish_stream,offline_access' ); $ch = curl_init(); $url = 'https://graph.facebook.com/oauth/access_token'; curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_HEADER, false); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_POST, true); curl_setopt($ch, CURLOPT_POSTFIELDS, $args); try { $data = curl_exec($ch); } catch (Exception $exc) { error_log($exc->getMessage()); } return json_encode($data); } If I uncomment $token = $facebook->getAccessToken(); in the posting code, it gives me yet another error (#200) The user hasn't authorized the application to perform this action. The token I get using developers.facebook.com/tools/explorer/ is of another form, much longer and with it I am able to post to the group page feed. How do I do it without copy/paste from Graph API Explorer and how do I post as a group instead of posting as a user? Thanks.

    Read the article

  • Listing issue, GROUP mysql

    - by SethCodes
    Here is a mock-up example of Mysql table: | ID | Country | City | ________________________________ | 1 | Sweden | Stockholm | | 2 | Sweden | Stockholm | | 3 | Sweden | Lund | | 4 | Sweden | Lund | | 5 | Germany | Berlin | | 6 | Germany | Berlin | | 7 | Germany | Hamburg | | 8 | Germany | Hamburg | Notice how both rows Country and city have repeated values inside them. Using GROUP BY country, city in my PDO query, the values will not repeat while in loop. Here is PDO for this: $query = "SELECT id, city, country FROM table GROUP BY country, city"; $stmt = $db->query($query); while($row = $stmt->fetch(PDO::FETCH_ASSOC)) : The above code will result in an output like this (some editing in-between). GROUP BY works but the country repeats: Sweden - Stockholm Sweden - Lund Germany - Berlin Germany - Hamburg Using bootstrap collapse and above code, I separate the country from the city with a simple drop down collopase. Here is code: <li> <a data-toggle="collapse" data-target="#<?= $row['id']; ?>" href="search.php?country=<?= $row['country']; ?>"> <?= $row['country']; ?> </a> <div id ="<?= $row['id']; ?>" class="collapse in"> //collapse div here <a href="search.php?city=<?= $row['city']; ?>"> <?= $row['city']; ?><br></a> </div> //end </li> It then looks something like this (once collapse is initiated): Sweden > Stockholm Sweden > Lund Germany >Berlin Germany >Hamburg Here is where I face the problem. The above lists the values Sweden and Germany 2 times. I want Sweden and Germany to only list one time, and the cities listed below, so the desired look is to be this: Sweden // Lists one time > Stockholm > Lund Germany // Lists one time >Berlin >Hamburg I have tried using DISTINCT, GROUP_CONTACT and other methods, yet none get my desired output (above). Suggestions? Below is my current full code in action: <? $query = "SELECT id, city, country FROM table GROUP BY country, city"; $stmt = $db->query($query); while($row = $stmt->fetch(PDO::FETCH_ASSOC)) : ?> <li> <a data-toggle="collapse" data-target="#<?= $row['id']; ?>" href="search.php?country=<?= $row['country']; ?>"> <?= $row['country']; ?> </a> <div id ="<?= $row['id']; ?>" class="collapse in"> //collapse div here <a href="search.php?city=<?= $row['city']; ?>"> <?= $row['city']; ?><br></a> </div> //end </li> <? endwhile ?>

    Read the article

  • SQL - Count grouped entries and then get the max values grouped by date

    - by Marcus
    hello, I am out of any logic how to write the right sql statment. I've got a sqlite table holding every played track in a row with played date/time Now I will count the plays of all artists, grouped by day and then find the artist with the max playcount per day. I used this Query SELECT COUNT(ARTISTID) AS artistcount, ARTIST AS artistname,strftime('%Y-%m-%d', playtime) AS day_played FROM playcount GROUP BY artistname to get this result "93"|"The Skygreen Leopards"|"2010-06-16" "2" |"Arcade Fire" |"2010-06-15" "2" |"Dead Kennedys" |"2010-06-15" "2" |"Wolf People" |"2010-06-15" "3" |"16 Horsepower" |"2010-06-15" "3" |"Alela Diane" |"2010-06-15" "46"|"Motorama" |"2010-06-15" "1" |"Ariel Pink's Haunted" |"2010-06-14" I tried then to query this virtual table but I always get false results in artistname. SELECT MAX(artistcount), artistname , day_played FROM ( SELECT COUNT(ARTISTID) AS artistcount, ARTIST AS artistname,strftime('%Y-%m-%d', playtime) AS day_played FROM playcount GROUP BY artistname ) GROUP BY strftime('%Y-%m-%d',day_played) result in this "93"|"lilium" |"2010-06-16" "46"|"Wolf People"|"2010-06-15" "30"|"of Montreal"|"2010-06-14" but the artist name is false. I think through the grouping by day, it just use the last artist, or so. I tested stuff like INNER JOIN or GROUP BY ... HAVING in trial and error, I read examples of similar issues but always get lost in columnnames and stuff (I am a bit burned out) I hope someone can give me a hint. thanks m

    Read the article

  • SQL query to count and list the different counties per zip code

    - by Chris
    I have a sql server 2005 table called ZipCode, which has all the US ZIPs in it. For each entry, it lists the zip, county, city, state, and several other details. Some zipcodes span multiple cities and some even span multiple counties. As a result, some zipcodes appear many times in the table. I am trying to query the table to see which zipcodes go across multiple counties. This is what I have so far: select zipcode, count(zipcode) as total, county, state from zipcode group by zipcode, county, state order by zipcode Of 19248 records in the result set, here are the first several records returned: zipcode total county state 00501 2 SUFFOLK NY 00544 2 SUFFOLK NY 00801 3 SAINT THOMAS VI 00802 3 SAINT THOMAS VI 00803 3 SAINT THOMAS VI 00804 3 SAINT THOMAS VI 00805 1 SAINT THOMAS VI 00820 2 SAINT CROIX VI 00821 1 SAINT CROIX VI 00822 1 SAINT CROIX VI 00823 2 SAINT CROIX VI 00824 2 SAINT CROIX VI In this particular example, each zip with a total of two or more happens to be in the table more than once, and it's because the "cityaliasname" (not shown) or some other column differs. But I just want to know which zips are in there more than once because the county column differs. I searched before posting this and I found many questions about counting records but I could not figure out how to apply them to my problem. Please forgive me if there is already a question whose answer applies to this question.

    Read the article

  • Wix create non advertised shortcut for all users / per machine

    - by mcdon
    In WIX, how do you create a non advertised shortcut in the allusers profile? So far I've only been able to accomplish this with advertised shortcuts. I prefer advertised shortcuts because you can go to the shortcut's properties and use "find target". In the tutorials I've seen use a registry value for the keypath of a shortcut. The problem is they use HKCU as the root. When HKCU is used, and another user uninstalls the program (since it's installed for all users) the registry key is left behind. When I use HKMU as the root I get an ICE57 error, but the key is removed when another user uninstalls the program. I seem to be pushed towards using HKCU though HKMU seems to behave correctly (per-user vs all-users). When I try to create the non advertised shortcut I get various ICE error such as ICE38, ICE43, or ICE 57. Most articles I've seen recommend "just ignore the ice errors". There must be a way to create the non advertised shortcuts, without creating ICE errors. Please post sample code for a working example.

    Read the article

  • LaTeX: bibliography per chapter.

    - by YuppieNetworking
    Hello all, I am helping a colleague with his PhD thesis and we need to present the bibliography at the end of each chapter. The question is: does anyone have a minimal working example for this case using latex+bibtex? The current document structure that we use is the following: main.tex chap1.tex chap2.tex ... chapn.tex biblio.bib Where main.tex contains packages, document declarations, macros and \includes for each chapter. biblio.bib is the only bibtex file (I think is easier to have all citations in one place). We have searched and tried with different latex packages, reading and following their documentation. Specifically, bibitems and chapterbib. bibitems successfully generates bu*.aux files, but when running bibtex for each one of them, an error occurs since there is no \bibdata element in the .aux file. chapterbib also generates a .aux file, but bibtex finishes with an error caused by using multiple \bibliography{file} in the .tex files (one per chapter). Some coworkers suggested using a separate bibtex file for each chapter, which could be a problem of maintenance in the future when citing the same publications in different chapters. We will like to continue having this document structure, if possible. So, if anyone could shed some light to this problem, we will appreciate it. Thanks.

    Read the article

  • Checkstyle: cannot summarise issues per author ?

    - by David Michel
    Hi all, I'm trying to use checkstyle for a java project but I can't seem to get it working properly: While it apparently runs smoothly, the html report doesn't give any info per authors as it should, i.e. the authors table is empty. The thing is I don't know how checkstyle identify an author. Does it look at the java doc tag @author ? at the class level or at the method level ? The ant task I used is below: <taskdef resource="checkstyletask.properties" classpath="${libs.dir}/checkstyle-all-5.0.jar"/> <target name="checkstyle" description="Generates a report of code convention violations."> <mkdir dir="${checkstyle.dir}"/> <checkstyle config="${util.dir}/checkstyle/sun_checks.xml" failureProperty="checkstyle.failure" failOnViolation="false"> <formatter type="xml" tofile="${checkstyle.dir}/checkstyle_report.xml"/> <fileset dir="${src.dir}" includes="**/*.java"/> </checkstyle> <xslt in="${checkstyle.dir}/checkstyle_report.xml" out="${checkstyle.dir}/checkstyle_report.html" style="${util.dir}/checkstyle/checkstyle-author.xsl"/> </target> Many thanks for your help David

    Read the article

  • NHibernate Session per Call in WCF - How to Rollback

    - by Corey Coogan
    I've implemented some components to use WCF with both an IoC Container (StructureMap) and the Session per Call pattern. The NHibernate stuff is most taken from here: http://realfiction.net/Content/Entry/133. It seems to be OK, but I want to open a transaction with each call and commit at the end, rather than just Flush() which how its being done in the article. Here's where I am running into some problems and could use some advice. I haven't figured out a good way to rollback. I realize I can check the CommunicationState and if there's an exception, rollback, like so: public void Detach(InstanceContext owner) { if (Session != null) { try { if(owner.State == CommunicationState.Faulted) RollbackTransaction(); else CommitTransaction(); } finally { Session.Dispose(); } } } void CommitTransaction() { if(Session.Transaction != null && Session.Transaction.IsActive) Session.Transaction.Commit(); } void RollbackTransaction() { if (Session.Transaction != null && Session.Transaction.IsActive) Session.Transaction.Rollback(); } However, I almost never return a faulted state from a service call. I would typically handle the exception and return an appropriate indicator on my response object and rollback the transaction myself. The only way I can think of handling this would be to inject not only repositories into my WCF services, but also an ISession so I can rollback and handle the way I want. That doesn't sit well with me and seems kind of leaky. Anyone else handling the same problem?

    Read the article

  • NHibernate: how to handle entity-based validation using session-per-request pattern, without control

    - by Seth Petry-Johnson
    What is the best way to do entity-based validation (each entity class has an IsValid() method that validates its internal members) in ASP.NET MVC, with a "session-per-request" model, where the controller has zero (or limited) knowledge of the ISession? Here's the pattern I'm using: Get an entity by ID, using an IFooRepository that wraps the current NH session. This returns a connected entity instance. Load the entity with potentially invalid data, coming from the form post. Validate the entity by callings its IsValid() method. If valid, call IFooRepository.Save(entity). Otherwise, display error message. The session is currently opened when the request begins and flushed when the request ends. Since my entity is connected to a session, flushing the session attempts to save the changes even if the object is invalid. What's the best way to keep validation logic in the entity class, limit controller knowledge of NH, and avoid saving invalid changes at the end of a request? Option 1: Explicitly evict on validation failure, implicitly flush: if the validation fails, I could manually evict the invalid object in the action method. If successful, I do nothing and the session is automatically flushed. Con: error prone and counter-intuitive ("I didn't call .Save(), why are my invalid changes being saved anyways?") Option 2: Explicitly flush, do nothing by default: By default I can dispose of the session on request end, only flushing if the controller indicates success. I'd probably create a SaveChanges() method in my base controller that sets a flag indicating success, and then query this flag when closing the session at request end. Pro: More intuitive to troubleshoot if dev forgets this step [relative to option 1] Con: I have to call IRepository.Save(entity)' and SaveChanges(). Option 3: Always work with disconnected objects: I could modify my repositories to return disconnected/transient objects, and modify the Repo.Save() method to re-attach them. Pro: Most intuitive, given that controllers don't know about NH. Con: Does this defeat many of the benefits I'd get from NH?

    Read the article

< Previous Page | 46 47 48 49 50 51 52 53 54 55 56 57  | Next Page >