Search Results

Search found 18546 results on 742 pages for 'order of evaluation'.

Page 50/742 | < Previous Page | 46 47 48 49 50 51 52 53 54 55 56 57  | Next Page >

  • Limiting the number of queries returns in SQL Server 2008

    - by Jose Sotero Villegas III
    This is my query SELECT Fullname, rank, id_no, TIN, birthdate, hair, eyes, Blood, height, weight, marks, name, address FROM [******_DOMAIN\****_*****].*******view Problem is, source table has too many duplicates, how do I my limit query to the latest row on the database? I'm using SQL Server 2008. Thanks In advance My next problem is that the view shows me a birthdate string format of yyyymmdd, I need to change it to mm/dd/yyyy can please provide me a function? using the same string above?

    Read the article

  • Ordering the results of a Hibernate Criteria query by using information of the child entities of the

    - by pkainulainen
    I have got two entities Person and Book. Only one instance of a specific book is stored to the system (When a book is added, application checks if that book is already found before adding a new row to the database). Relevant source code of the entities is can be found below: @Entity @Table(name="persons") @SequenceGenerator(name="id_sequence", sequenceName="hibernate_sequence") public class Person extends BaseModel { @Id @Column(name = "id") @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "id_sequence") private Long id = null; @ManyToMany(targetEntity=Book.class) @JoinTable(name="persons_books", joinColumns = @JoinColumn( name="person_id"), inverseJoinColumns = @JoinColumn( name="book_id")) private List<Book> ownedBooks = new ArrayList<Book>(); } @Entity @Table(name="books") @SequenceGenerator(name="id_sequence", sequenceName="hibernate_sequence") public class Book extends BaseModel { @Id @Column(name = "id") @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "id_sequence") private Long id = null; @Column(name="name") private String name = null; } My problem is that I want to find persons, which are owning some of the books owned by a specific persons. The returned list of persons should be ordered by using following logic: The person owning most of the same books should be at the first of the list, second person of the the list does not own as many books as the first person, but more than the third person. The code of the method performing this query is added below: @Override public List<Person> searchPersonsWithSimilarBooks(Long[] bookIds) { Criteria similarPersonCriteria = this.getSession().createCriteria(Person.class); similarPersonCriteria.add(Restrictions.in("ownedBooks.id", bookIds)); //How to set the ordering? similarPersonCriteria.addOrder(null); return similarPersonCriteria.list(); } My question is that can this be done by using Hibernate? And if so, how it can be done? I know I could implement a Comparator, but I would prefer using Hibernate to solve this problem.

    Read the article

  • @OrderBy: Sorting references

    - by Sven Moschel
    We have the following entity structure: @Entity public class SecurityRole { private List<Account> accounts; // ManyToMany } @Entity public class Account { private Employee owner; // OneToOne } @Entity public class Employee { private String lastName; } A security role can have many accounts. A account always has an employee. On the GUI we show the security roles in an mastertable. In the detail table we show the accounts of the role. To display the employee information we show "account.getOwner().getLastName()"; How can we use the @OrderBy annotation with this model? Is this possible? The problem is that the Account entity has no employee information that we can sort.

    Read the article

  • Sort MySQL result set using comparison between 2 columns of same value type

    - by Kyobul
    Hello, I have a table containing last_updated_1 and last_updated_2 columns, used respectively for text and images update time on a post. I wish I could get a result set of 10 rows based on all time last updated records contained in the 2 columns, ex. row 1 = last_updated_1 record, row 2 = last_updated_2 record, row 3 = last_updated_1 record, etc. How could I compare inside a MySQL query the both columns values, to get unique & mixed result set ? Thank you in advance for your help

    Read the article

  • Identify words with ascending characters from text file

    - by user2914000
    I am having a fair amount of trouble trying to write a program that counts the amount of ascending words (words in which each character is larger than the previous character) in a text file. I have tried a few different methods to solve this but cannot seem to get it working. If anyone could help me revise the code to work properly it would be appreciated. The code will print about 5 of the words from the list of nearly 20000, but none considered are ascending (the file does have many ascending words) and it sometimes prints the same word twice. I am printing theWord to the console simply to see if the code works. import java.util.Scanner; import java.io.*; public class { public static void main (String [] args) throws FileNotFoundException{ String theWord; Scanner inputFile = new Scanner(new File("file.txt")); boolean ascending = true; int i = 1; while(inputFile.hasNextLine()){ theWord = inputFile.nextLine(); if(theWord.length() >= 2){ while(i < theWord.length() - 1){ if(theWord.charAt(i) <= theWord.charAt(i + 1)){ ascending = true; System.out.println("+ " + theWord); totalNum = totalNum + 1; } else{ ascending = false; System.out.println("= " + theWord); } i++; } } }

    Read the article

  • How does the Keyword Order in the domain name effects SEO?

    - by Sushil
    From the Google keyword research tool, I see "chuck norris jokes" has global 246,000 searches. And again searching "jokes chuck norris" has the same search result. But as see, order of keyword in search terms has, "hello how are you" and "how are you hello" has clearly different results. Now instead of search term (assuming "chuck norris jokes"), I was wondering, if I had to register chucknorrisjokes.com and jokeschucknorris.com, would it effect the ranking on the search result? Or would it be the same? As we see here, both the domains has the same keywords, just in different order. How would that effect? I hope what I am trying to say is clear.

    Read the article

  • What is the most effective order to learn SQL Server, LINQ, and Entity Framework?

    - by user1525474
    I am trying to get some advice on what order I should learn about SQL Server, LINQ, and Entity Framework to be able to better work with ASP.NET Webforms and MVC. From what I've been able to learn so far, many recommend learning LINQ or Entity Framework before learning SQL Server. It also appears that many companies are looking for people with knowledge in LINQ-to-SQL and Entity Framework without mentioning SQL Server. However, my understanding is that LINQ-to-SQL and Entity Framework translate code into SQL Server queries, making this a poor approach. Is there a correct or best order in which to learn these technologies?

    Read the article

  • Saving child collections with NHibernate

    - by Ben
    Hi, I am in the process or learning NHibernate so bare with me. I have an Order class and a Transaction class. Order has a one to many association with transaction. The transaction table in my database has a not null constraint on the OrderId foreign key. Order class: public class Order { public virtual Guid Id { get; set; } public virtual DateTime CreatedOn { get; set; } public virtual decimal Total { get; set; } public virtual ICollection<Transaction> Transactions { get; set; } public Order() { Transactions = new HashSet<Transaction>(); } } Order Mapping: <class name="Order" table="Orders"> <cache usage="read-write"/> <id name="Id"> <generator class="guid"/> </id> <property name="CreatedOn" type="datetime"/> <property name="Total" type="decimal"/> <set name="Transactions" table="Transactions" lazy="false" inverse="true"> <key column="OrderId"/> <one-to-many class="Transaction"/> </set> Transaction Class: public class Transaction { public virtual Guid Id { get; set; } public virtual DateTime ExecutedOn { get; set; } public virtual bool Success { get; set; } public virtual Order Order { get; set; } } Transaction Mapping: <class name="Transaction" table="Transactions"> <cache usage="read-write"/> <id name="Id" column="Id" type="Guid"> <generator class="guid"/> </id> <property name="ExecutedOn" type="datetime"/> <property name="Success" type="bool"/> <many-to-one name="Order" class="Order" column="OrderId" not-null="true"/> Really I don't want a bidirectional association. There is no need for my transaction objects to reference their order object directly (I just need to access the transactions of an order). However, I had to add this so that Order.Transactions is persisted to the database: Repository: public void Update(Order entity) { using (ISession session = NHibernateHelper.OpenSession()) { using (ITransaction transaction = session.BeginTransaction()) { session.Update(entity); foreach (var tx in entity.Transactions) { tx.Order = entity; session.SaveOrUpdate(tx); } transaction.Commit(); } } } My problem is that this will then issue an update for every transaction on the order collection (regardless of whether it has changed or not). What I was trying to get around was having to explicitly save the transaction before saving the order and instead just add the transactions to the order and then save the order: public void Can_add_transaction_to_existing_order() { var orderRepo = new OrderRepository(); var order = orderRepo.GetById(new Guid("aa3b5d04-c5c8-4ad9-9b3e-9ce73e488a9f")); Transaction tx = new Transaction(); tx.ExecutedOn = DateTime.Now; tx.Success = true; order.Transactions.Add(tx); orderRepo.Update(order); } Although I have found quite a few articles covering the set up of a one-to-many association, most of these discuss retrieving of data and not persisting back. Many thanks, Ben

    Read the article

  • SQL SERVER – Puzzle – Statistics are not Updated but are Created Once

    - by pinaldave
    After having excellent response to my quiz – Why SELECT * throws an error but SELECT COUNT(*) does not?I have decided to ask another puzzling question to all of you. I am running this test on SQL Server 2008 R2. Here is the quick scenario about my setup. Create Table Insert 1000 Records Check the Statistics Now insert 10 times more 10,000 indexes Check the Statistics – it will be NOT updated Note: Auto Update Statistics and Auto Create Statistics for database is TRUE Expected Result – Statistics should be updated – SQL SERVER – When are Statistics Updated – What triggers Statistics to Update Now the question is why the statistics are not updated? The common answer is – we can update the statistics ourselves using UPDATE STATISTICS TableName WITH FULLSCAN, ALL However, the solution I am looking is where statistics should be updated automatically based on algorithm mentioned here. Now the solution is to ____________________. Vinod Kumar is not allowed to take participate over here as he is the one who has helped me to build this puzzle. I will publish the solution on next week. Please leave a comment and if your comment consist valid answer, I will publish with due credit. Here is the script to reproduce the scenario which I mentioned. -- Execution Plans Difference -- Create Sample Database CREATE DATABASE SampleDB GO USE SampleDB GO -- Create Table CREATE TABLE ExecTable (ID INT, FirstName VARCHAR(100), LastName VARCHAR(100), City VARCHAR(100)) GO -- Insert One Thousand Records -- INSERT 1 INSERT INTO ExecTable (ID,FirstName,LastName,City) SELECT TOP 1000 ROW_NUMBER() OVER (ORDER BY a.name) RowID, 'Bob', CASE WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%2 = 1 THEN 'Smith' ELSE 'Brown' END, CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%20 = 1 THEN 'New York' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 5 THEN 'San Marino' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 3 THEN 'Los Angeles' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 7 THEN 'La Cinega' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 13 THEN 'San Diego' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 17 THEN 'Las Vegas' ELSE 'Houston' END FROM sys.all_objects a CROSS JOIN sys.all_objects b GO -- Display statistics of the table - none listed sp_helpstats N'ExecTable', 'ALL' GO -- Select Statement SELECT FirstName, LastName, City FROM ExecTable WHERE City  = 'New York' GO -- Display statistics of the table sp_helpstats N'ExecTable', 'ALL' GO -- Replace your Statistics over here -- NOTE: Replace your _WA_Sys with stats from above query DBCC SHOW_STATISTICS('ExecTable', _WA_Sys_00000004_7D78A4E7); GO -------------------------------------------------------------- -- Round 2 -- Insert Ten Thousand Records -- INSERT 2 INSERT INTO ExecTable (ID,FirstName,LastName,City) SELECT TOP 10000 ROW_NUMBER() OVER (ORDER BY a.name) RowID, 'Bob', CASE WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%2 = 1 THEN 'Smith' ELSE 'Brown' END, CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%20 = 1 THEN 'New York' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 5 THEN 'San Marino' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 3 THEN 'Los Angeles' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 7 THEN 'La Cinega' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 13 THEN 'San Diego' WHEN  ROW_NUMBER() OVER (ORDER BY a.name)%20 = 17 THEN 'Las Vegas' ELSE 'Houston' END FROM sys.all_objects a CROSS JOIN sys.all_objects b GO -- Select Statement SELECT FirstName, LastName, City FROM ExecTable WHERE City  = 'New York' GO -- Display statistics of the table sp_helpstats N'ExecTable', 'ALL' GO -- Replace your Statistics over here -- NOTE: Replace your _WA_Sys with stats from above query DBCC SHOW_STATISTICS('ExecTable', _WA_Sys_00000004_7D78A4E7); GO -- You will notice that Statistics are still updated with 1000 rows -- Clean up Database DROP TABLE ExecTable GO USE MASTER GO ALTER DATABASE SampleDB SET SINGLE_USER WITH ROLLBACK IMMEDIATE; GO DROP DATABASE SampleDB GO Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Index, SQL Performance, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: SQL Statistics, Statistics

    Read the article

  • Spring MVC managing multiple views with single controller

    - by Sudhir
    I am trying to implement order management module. There are different order types (approximately about 15). Each order has a seperate view. But the actions performed on UI are same irrespective of order type. Below is the structure of my DTO abstract class Order abstract class SecurityOrder extends Order abstract class TermDepositOrder extends Order ..... ..... ..... I am trying to implement a single controller capable of managing all views. Something similar to the one below: @Controller public class OrderController<F extends Order> { public F validate(F order) { } public F insert(F order) { } } I am not sure how spring mvc would be able to map request parameters properly to the order instance as it doesn't know which order instance to populate. Is it possible to achieve this with single controller or should I go with a controller for each order type and duplicate same code across all controllers?

    Read the article

  • Is my DFD accurate?

    - by Dummy Derp
    This is my first ever DFD that I made after my fair share of learning but I have no way of verifying whether it is correct or not. Although I have taken utmost care to make sure it is right, I may be wrong. Here is the scenario: Bebop Records is a mail-order company that distributes CDs and tapes at discount prices to record club members. When an order processing clerk receives an order form, he or she verifies that the sender is a club member by checking the Member file. If the sender is not a member, the clerk returns the order along with a membership application form. If the customer is a member, the clerk verifies the order item data by checking the Item file. Then the clerk enters the order data and saves it to the Daily Order file. The clerk also prints an invoice and shipping list for each order, which are forwarded to Order Fulfilment. And here is my diagram:

    Read the article

  • Please suggest me the ( Interaction model of view model) MVVM design in the simple scenario discusse

    - by Jack
    Data Layer I have an Order class as an entity. This Order entity is my model object. Order can be different types, let it be A B C D Also Order class may have common properties like Name, Time of creation, etc. Also based on the order type there are different fields that are not common. View Layer The view contains the following Main Menu ListView The Main Menu contains the drop down menu button which is used to create the order based on the type selected from the drop down. The drop down contains the Order types ( A ,B , C and D). There are different user control based on the order type. Like for example if user chooses to create an order of type A then different view with different inputs field is popped up. Hence, there are four user control for each order type. If user selects A option from the drop down then Order of type A is created and vica versa. Now below is the List View that contains the List of orders so far created by the user. To Edit any particular order user may double click the list view row. Based on the order type clicked by the user in the listview, the view of that order type opens in edit mode. For example if user selects an order type A from the list view then view for order type A open in edit mode. Please suggest me interaction model for view model's in the scenario discussed above. Please excume me if the query is very basic, since I am new new to MVVM and WPF ,

    Read the article

  • Is there a way to change the order of tabs in Foxit Reader?

    - by Harold
    In web browsers you can drag the tabs to change the order. But I can't do that in Foxit Reader (version 3.1.4.1125, using Windows Vista Home, Chinese Traditional) Example: I open 3 files: Page2.pdf Page3.pdf Page1.pdf which opens Foxit Reader with a tab for each file, in the order Page2.pdf Page3.pdf Page1.pdf Is there a way to change the order of the tabs to Page1.pdf Page2.pdf Page3.pdf ? This would really be helpful when you have many files open... TIA! Harold

    Read the article

  • SQL SERVER – Shrinking Database is Bad – Increases Fragmentation – Reduces Performance

    - by pinaldave
    Earlier, I had written two articles related to Shrinking Database. I wrote about why Shrinking Database is not good. SQL SERVER – SHRINKDATABASE For Every Database in the SQL Server SQL SERVER – What the Business Says Is Not What the Business Wants I received many comments on Why Database Shrinking is bad. Today we will go over a very interesting example that I have created for the same. Here are the quick steps of the example. Create a test database Create two tables and populate with data Check the size of both the tables Size of database is very low Check the Fragmentation of one table Fragmentation will be very low Truncate another table Check the size of the table Check the fragmentation of the one table Fragmentation will be very low SHRINK Database Check the size of the table Check the fragmentation of the one table Fragmentation will be very HIGH REBUILD index on one table Check the size of the table Size of database is very HIGH Check the fragmentation of the one table Fragmentation will be very low Here is the script for the same. USE MASTER GO CREATE DATABASE ShrinkIsBed GO USE ShrinkIsBed GO -- Name of the Database and Size SELECT name, (size*8) Size_KB FROM sys.database_files GO -- Create FirstTable CREATE TABLE FirstTable (ID INT, FirstName VARCHAR(100), LastName VARCHAR(100), City VARCHAR(100)) GO -- Create Clustered Index on ID CREATE CLUSTERED INDEX [IX_FirstTable_ID] ON FirstTable ( [ID] ASC ) ON [PRIMARY] GO -- Create SecondTable CREATE TABLE SecondTable (ID INT, FirstName VARCHAR(100), LastName VARCHAR(100), City VARCHAR(100)) GO -- Create Clustered Index on ID CREATE CLUSTERED INDEX [IX_SecondTable_ID] ON SecondTable ( [ID] ASC ) ON [PRIMARY] GO -- Insert One Hundred Thousand Records INSERT INTO FirstTable (ID,FirstName,LastName,City) SELECT TOP 100000 ROW_NUMBER() OVER (ORDER BY a.name) RowID, 'Bob', CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%2 = 1 THEN 'Smith' ELSE 'Brown' END, CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 1 THEN 'New York' WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 5 THEN 'San Marino' WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 3 THEN 'Los Angeles' ELSE 'Houston' END FROM sys.all_objects a CROSS JOIN sys.all_objects b GO -- Name of the Database and Size SELECT name, (size*8) Size_KB FROM sys.database_files GO -- Insert One Hundred Thousand Records INSERT INTO SecondTable (ID,FirstName,LastName,City) SELECT TOP 100000 ROW_NUMBER() OVER (ORDER BY a.name) RowID, 'Bob', CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%2 = 1 THEN 'Smith' ELSE 'Brown' END, CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 1 THEN 'New York' WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 5 THEN 'San Marino' WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 3 THEN 'Los Angeles' ELSE 'Houston' END FROM sys.all_objects a CROSS JOIN sys.all_objects b GO -- Name of the Database and Size SELECT name, (size*8) Size_KB FROM sys.database_files GO -- Check Fragmentations in the database SELECT avg_fragmentation_in_percent, fragment_count FROM sys.dm_db_index_physical_stats (DB_ID(), OBJECT_ID('SecondTable'), NULL, NULL, 'LIMITED') GO Let us check the table size and fragmentation. Now let us TRUNCATE the table and check the size and Fragmentation. USE MASTER GO CREATE DATABASE ShrinkIsBed GO USE ShrinkIsBed GO -- Name of the Database and Size SELECT name, (size*8) Size_KB FROM sys.database_files GO -- Create FirstTable CREATE TABLE FirstTable (ID INT, FirstName VARCHAR(100), LastName VARCHAR(100), City VARCHAR(100)) GO -- Create Clustered Index on ID CREATE CLUSTERED INDEX [IX_FirstTable_ID] ON FirstTable ( [ID] ASC ) ON [PRIMARY] GO -- Create SecondTable CREATE TABLE SecondTable (ID INT, FirstName VARCHAR(100), LastName VARCHAR(100), City VARCHAR(100)) GO -- Create Clustered Index on ID CREATE CLUSTERED INDEX [IX_SecondTable_ID] ON SecondTable ( [ID] ASC ) ON [PRIMARY] GO -- Insert One Hundred Thousand Records INSERT INTO FirstTable (ID,FirstName,LastName,City) SELECT TOP 100000 ROW_NUMBER() OVER (ORDER BY a.name) RowID, 'Bob', CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%2 = 1 THEN 'Smith' ELSE 'Brown' END, CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 1 THEN 'New York' WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 5 THEN 'San Marino' WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 3 THEN 'Los Angeles' ELSE 'Houston' END FROM sys.all_objects a CROSS JOIN sys.all_objects b GO -- Name of the Database and Size SELECT name, (size*8) Size_KB FROM sys.database_files GO -- Insert One Hundred Thousand Records INSERT INTO SecondTable (ID,FirstName,LastName,City) SELECT TOP 100000 ROW_NUMBER() OVER (ORDER BY a.name) RowID, 'Bob', CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%2 = 1 THEN 'Smith' ELSE 'Brown' END, CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 1 THEN 'New York' WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 5 THEN 'San Marino' WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 3 THEN 'Los Angeles' ELSE 'Houston' END FROM sys.all_objects a CROSS JOIN sys.all_objects b GO -- Name of the Database and Size SELECT name, (size*8) Size_KB FROM sys.database_files GO -- Check Fragmentations in the database SELECT avg_fragmentation_in_percent, fragment_count FROM sys.dm_db_index_physical_stats (DB_ID(), OBJECT_ID('SecondTable'), NULL, NULL, 'LIMITED') GO You can clearly see that after TRUNCATE, the size of the database is not reduced and it is still the same as before TRUNCATE operation. After the Shrinking database operation, we were able to reduce the size of the database. If you notice the fragmentation, it is considerably high. The major problem with the Shrink operation is that it increases fragmentation of the database to very high value. Higher fragmentation reduces the performance of the database as reading from that particular table becomes very expensive. One of the ways to reduce the fragmentation is to rebuild index on the database. Let us rebuild the index and observe fragmentation and database size. -- Rebuild Index on FirstTable ALTER INDEX IX_SecondTable_ID ON SecondTable REBUILD GO -- Name of the Database and Size SELECT name, (size*8) Size_KB FROM sys.database_files GO -- Check Fragmentations in the database SELECT avg_fragmentation_in_percent, fragment_count FROM sys.dm_db_index_physical_stats (DB_ID(), OBJECT_ID('SecondTable'), NULL, NULL, 'LIMITED') GO You can notice that after rebuilding, Fragmentation reduces to a very low value (almost same to original value); however the database size increases way higher than the original. Before rebuilding, the size of the database was 5 MB, and after rebuilding, it is around 20 MB. Regular rebuilding the index is rebuild in the same user database where the index is placed. This usually increases the size of the database. Look at irony of the Shrinking database. One person shrinks the database to gain space (thinking it will help performance), which leads to increase in fragmentation (reducing performance). To reduce the fragmentation, one rebuilds index, which leads to size of the database to increase way more than the original size of the database (before shrinking). Well, by Shrinking, one did not gain what he was looking for usually. Rebuild indexing is not the best suggestion as that will create database grow again. I have always remembered the excellent post from Paul Randal regarding Shrinking the database is bad. I suggest every one to read that for accuracy and interesting conversation. Let us run following script where we Shrink the database and REORGANIZE. -- Name of the Database and Size SELECT name, (size*8) Size_KB FROM sys.database_files GO -- Check Fragmentations in the database SELECT avg_fragmentation_in_percent, fragment_count FROM sys.dm_db_index_physical_stats (DB_ID(), OBJECT_ID('SecondTable'), NULL, NULL, 'LIMITED') GO -- Shrink the Database DBCC SHRINKDATABASE (ShrinkIsBed); GO -- Name of the Database and Size SELECT name, (size*8) Size_KB FROM sys.database_files GO -- Check Fragmentations in the database SELECT avg_fragmentation_in_percent, fragment_count FROM sys.dm_db_index_physical_stats (DB_ID(), OBJECT_ID('SecondTable'), NULL, NULL, 'LIMITED') GO -- Rebuild Index on FirstTable ALTER INDEX IX_SecondTable_ID ON SecondTable REORGANIZE GO -- Name of the Database and Size SELECT name, (size*8) Size_KB FROM sys.database_files GO -- Check Fragmentations in the database SELECT avg_fragmentation_in_percent, fragment_count FROM sys.dm_db_index_physical_stats (DB_ID(), OBJECT_ID('SecondTable'), NULL, NULL, 'LIMITED') GO You can see that REORGANIZE does not increase the size of the database or remove the fragmentation. Again, I no way suggest that REORGANIZE is the solution over here. This is purely observation using demo. Read the blog post of Paul Randal. Following script will clean up the database -- Clean up USE MASTER GO ALTER DATABASE ShrinkIsBed SET SINGLE_USER WITH ROLLBACK IMMEDIATE GO DROP DATABASE ShrinkIsBed GO There are few valid cases of the Shrinking database as well, but that is not covered in this blog post. We will cover that area some other time in future. Additionally, one can rebuild index in the tempdb as well, and we will also talk about the same in future. Brent has written a good summary blog post as well. Are you Shrinking your database? Well, when are you going to stop Shrinking it? Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Index, SQL Performance, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, SQLServer, T SQL, Technology

    Read the article

  • Order Unlocked iPhone 4S From Apple Online Store. $649, No Contract, Any Network.

    - by Gopinath
    Apple opened the flood gates of iPhone 4S! Now you can buy the unlocked iPhone 4S directly from Apple instead of buying them from grey market. The Apple US Online store has started accepting order for unlocked iPhone 4S and at the moment the expected shipping time is around 1 to 2 weeks. Price of the phones starts from $649 for 16GB and goes up to $849 for 64GB version. These unlocked phones are free from monthly contracts, works on any GSM network around the globe. Sorry CDMA networks, unlocked iPhone 4S is not yet ready for you! Its a good move from Apple. This helps people from staying away from multi-year contracts and also visitors returning from USA now can buy an original unlocked iPhone to use in their home countries. Buy iPhone 4S from Apple Online Store This article titled,Order Unlocked iPhone 4S From Apple Online Store. $649, No Contract, Any Network., was originally published at Tech Dreams. Grab our rss feed or fan us on Facebook to get updates from us.

    Read the article

  • How do you keep the order using SELECT WHERE IN()?

    - by Pepper
    Is there a way to keep the order when using SELECT WHERE IN()? For example, using the following query: SELECT id FROM data_table WHERE id IN(56,55,54,1,7); The results will come back using the default order by id. 1,7,54,55,56 When I want to keep the order used in the IN: 56,55,54,1,7 Is there a quick way to do this in mySQL or will I be forced to order it after in code. Thanks :)

    Read the article

  • Why call-by-value evaluation strategy is not Turing complete?

    - by Roman
    I'm reading an article about different evaluation strategies (I linked article in wiki, but I'm reading another one not in English). And it says that unlike to call-by-name and call-by-need strategies, call-by-value strategy is not Turing complete. Can anybody explain, please, why is it so? If it's possible, add an example pls.

    Read the article

  • Any way to avoid a filesort when order by is different to where clause?

    - by Julian
    I have an incredibly simple query (table type InnoDb) and EXPLAIN says that MySQL must do an extra pass to find out how to retrieve the rows in sorted order. SELECT * FROM `comments` WHERE (commentable_id = 1976) ORDER BY created_at desc LIMIT 0, 5 exact explain output: table select_type type extra possible_keys key key length ref rows comments simple ref using where; using filesort common_lookups common_lookups 5 const 89 commentable_id is indexed. Comments has nothing trick in it, just a content field. The manual suggests that if the order by is different to the where, there is no way filesort can be avoided. http://dev.mysql.com/doc/refman/5.0/en/order-by-optimization.html I also tried order by id as well as it's equivalent but makes no difference, even if I add id as an index (which I understand is not required as id is indexed implicitly in MySQL). thanks in advance for any ideas!

    Read the article

  • Are browsers permitted to render <li>s in any order?

    - by ctford
    As I understand the XML spec, the significance of the order of child elements is not guaranteed. XML parsers tend to keep child elements in the same order as they occur in the XML document, but they are under no obligation to do so. If that's so, then are browsers free to render the <li>s in an <ol> or an <ul> in a different order than they occur in the XHTML? Or is it specified in the XHTML spec somewhere that order has to be preserved? I realise that all major browsers will respect the order of my <li>s. I'm just interested in the academic question of whether or not they are technically obliged to.

    Read the article

  • Are browsers permitted to render <ol>s in any order?

    - by ctford
    As I understand the XML spec, the significance of the order of child elements is not guaranteed. XML parsers tend to keep child elements in the same order as they occur in the XML document, but they are under no obligation to do so. If that's so, then are browsers free to render the <li>s in an <ol> in a different order than they occur in the XHTML? Or is it specified in the XHTML spec somewhere that order has to be preserved? I realise that all major browsers will respect the order of my <li>s. I'm just interested in the academic question of whether or not they are technically obliged to.

    Read the article

  • Which order would you teach programming languages in, when teaching a newbie?

    - by blueberryfields
    If you had to design a study program, with a breadth-of-programming-languages requirement, which stated that the student should be exposed to all major concepts and methodologies that can be taught through (at the minimum) 6 programming languages, which programming languages would you choose to teach, and in which order? Breadth-of-programming-languages is based on programming language and theoretical concepts.

    Read the article

  • Microsoft SQL Server 2008 R2 Administration Cookbook - Book and eBook expected June 2011. Pre-order now!

    - by ssqa.net
    Over 85 practical recipes for administering a high-performance SQL Server 2008 R2 system. Book and eBook expected June 2011 . Pre-order now! Multi-format orders get free access on PacktLib , This practical cookbook will show you the advanced administration techniques for managing and administering a scalable and high-performance SQL Server 2008 R2 system. It contains over 85 practical, task-based, and immediately useable recipes covering a wide range of advanced administration techniques for administering...(read more)

    Read the article

  • Is it appropriate to try to control the order of finalization?

    - by Strilanc
    I'm writing a class which is roughly analogous to a CancellationToken, except it has a third state for "never going to be cancelled". At the moment I'm trying to decide what to do if the 'source' of the token is garbage collected without ever being set. It seems that, intuitively, the source should transition the associated token to the 'never cancelled' state when it is about to be collected. However, this could trigger callbacks who were only kept alive by their linkage from the token. That means what those callbacks reference might now in the process of finalization. Calling them would be bad. In order to "fix" this, I wrote this class: public sealed class GCRoot { private static readonly GCRoot MainRoot = new GCRoot(); private GCRoot _next; private GCRoot _prev; private object _value; private GCRoot() { this._next = this._prev = this; } private GCRoot(GCRoot prev, object value) { this._value = value; this._prev = prev; this._next = prev._next; _prev._next = this; _next._prev = this; } public static GCRoot Root(object value) { return new GCRoot(MainRoot, value); } public void Unroot() { lock (MainRoot) { _next._prev = _prev; _prev._next = _next; this._next = this._prev = this; } } } intending to use it like this: Source() { ... _root = GCRoot.Root(callbacks); } void TransitionToNeverCancelled() { _root.Unlink(); ... } ~Source() { TransitionToNeverCancelled(); } but now I'm troubled. This seems to open the possibility for memory leaks, without actually fixing all cases of sources in limbo. Like, if a source is closed over in one of its own callbacks, then it is rooted by the callback root and so can never be collected. Presumably I should just let my sources be collected without a peep. Or maybe not? Is it ever appropriate to try to control the order of finalization, or is it a giant warning sign?

    Read the article

  • How can I change the language order by command-line (or text editor)?

    - by KIAaze
    How can I change the language order by command-line (or text editor)? i.e. without using the graphical "gnome-language-selector". (Or is there a better GUI which allows you to select multiple language entries and move them all to another position directly, without having to do it one by one?) Alternatively: Where are the user-specific language settings stored? i.e. the /etc/default/locale for users.

    Read the article

  • ASP.NET MVC 2 RC2 Routing - How to clear low-level values when using ActionLink to refer to a higher

    - by Gary McGill
    [NOTE: I'm using ASP.NET MVC2 RC2.] I have URLs like this: /customer/123/order/456/item/index /customer/123/order/456/item/789/edit My routing table lists the most-specific routes first, so I've got: // customer/123/order/456/item/789/edit routes.MapRoute( "item", // Route name "customer/{customerId}/order/{orderId}/item/{itemId}/{action}", // URL with parameters new { controller = "Items", action = "Details" }, // Parameter defaults new { customerId = @"\d+", orderId = @"\d+", itemId = @"\d+" } // Constraints ); // customer/123/order/456/item/index routes.MapRoute( "items", // Route name "customer/{customerId}/order/{orderId}/item/{action}", // URL with parameters new { controller = "Items", action = "Index" }, // Parameter defaults new { customerId = @"\d+", orderId = @"\d+" } // Constraints ); When I'm in the "Edit" page, I want a link back up to the "Index" page. So, I use: ActionLink("Back to Index", "index") However, because there's an ambient order ID, this results in the URL: /Customer/123/Order/456/Item/789/Index ...whereas I want it to "forget" the order ID and just use: /Customer/123/Order/456/Item/Index I've tried overriding the order ID like so: ActionLink("Back to Index", "index", new { orderId=string.empty }) ...but that doesn't work. How can I persuade ActionLink to "forget" the order ID?

    Read the article

< Previous Page | 46 47 48 49 50 51 52 53 54 55 56 57  | Next Page >